For flow of a liquid metal through a circular tube, the velocity and temperature profiles at a particular axial location may be approximated as being uniform and parabolic, respectively. That is, u(r) = C, and TO-T, = C11-(r/ro)2], where Ci and C2 are constants. what is the value of the Nusselt number Nup at this location?

Answers

Answer 1

Answer:

Nup = 8

Explanation:

u(r) = C1 and T(r) = T(s) = C2 [ 1 - r/ro)^2 ]

The temperature and velocity particles at a particular axial location is Uniform and parabolic

The Nusset Number Nup at this location can be obtained by first determining/calculating for the convection coefficient = \(h = \frac{q^I s}{TsTn}\)

Therefore the mean temperature is calculated as follows

attached is the detailed solution and free body diagram

For Flow Of A Liquid Metal Through A Circular Tube, The Velocity And Temperature Profiles At A Particular
For Flow Of A Liquid Metal Through A Circular Tube, The Velocity And Temperature Profiles At A Particular

Related Questions

The coefficient of static friction for both wedge surfaces is μw=0.4 and that between the 27-kg concrete block and the β=20° incline is μg=0.7.

If the wedge has an angle of 5° determine the minimum value of the force P2, parallel to the fixed surface on the left, required to begin moving the block up the incline.

Answers

Assuming  the wedge has an angle of 5°.The minimum value of the force P that is required to begin moving the block up the incline is: 322.84 N.

Minimum value of force P

First step

Using this formula to find the weight of the block

W=mg

W=27×9.81

W=264.87 N

Second step

Angles of friction ∅A and ∅B

∅A=tan^-1(μA)

∅A=tan^-1(0.70)

∅A=34.99°

∅B=tan^-1(μB)

∅B=tan^-1(0.40)

∅B=21.80°

Third step

Equate the sum of forces in m-direction to 0 in order to find the reaction force at B.

∑fm=0

W sin (∅A+20°)  + RB cos (∅B+∅A)=0

264.87 sin(34.99°+20°) + RB cos (21.80°+34.99°)=0

216.94+0.5477Rb=0

RB=216.94/0.5477

RB=396.09 N

Fourth step

Equate the sum of forces in x-direction to 0 in order to find force Rc.

∑fx=0

RB cos (∅B) - RC cos (∅B+ 5°)=0

396.09 cos(21.80°) - RC cos (21.80°+5°)=0

RC=396.09 cos(21.80°)/cos(26.80°)

RC=412.02 N

Last step

Equate the sum of forces in y-direction to 0 in order to find force P required to move the block up the incline.

∑fy=0

RB sin (∅B) + RC sin (∅B)-P=0

P=Rb sin (∅B) + RC sin (5°+∅B)

P=396.09 sin(21.80°) +412.02sin (5°+21.80°)

P=322.84 N

Inconclusion the minimum value of the force P that is required to begin moving the block up the incline is: 322.84 N.

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10.0 kmol of a 40.0 mol% methanol and 60.0 mol% water mixture is processed in a normal batch distillation system with a still pot that acts as an equilibrium stage and a column with two equilibrium stages (total of three equilibrium contacts). The column has a total condenser, and reflux is a saturated liquid. The column is operated with a varying reflux ratio so that xD is held constant. We desire a final still-pot concentration of 8.0 mol% methanol, and distillate should be 84.0 mol% methanol. Pressure is 1 atm, and CMO is valid.

Required:
a. What initial external reflux ratio, LD, must be used?
b. What final external reflux ratio must be used?
c. How much distillate product is withdrawn, and what is the value of Wfinal?

Answers

Answer:

[a]. 0.49.

[2]. 0.536

[c]. 4.15 kmol; 5.84 kmol.

Explanation:

Without mincing words let's dive straight into the solution to the question above.

                                                            [a].

The initial external reflux ratio, LD that must be used = [(0.85 - 0.57)/ 0.85 - 0]/ [ 1 - (0.85 - 0.57)/ 0.85 - 0].

The initial external reflux ratio, LD that must be used = 0.329/ 1- 0.329 = 0.49.

                                                             [b].

The final external reflux ratio that must be used = [ 0.85 - 0.13/ 0.85 - 0]/ [ 1 - 0.85 - 0.13/ 0.85 - 0].

Hence, the final external reflux ratio that must be used =0.847/ 1 - 0.847 = 5.536.

                                                              [c].

The amount of distillate product that is withdrawn:

4 = 0.85 H(t) + 0.8 - 0.08.

H(t) = 4.15 kmol, and the value of Wfinal = 5.84 kmol.

how many types of lavatory there is?

Answers

Answer:

there are generally two types of toilet bowl types- round and elongated.

When we talk about toilet type, we mean the basic method that the toilet uses to flush and dispose of waste. From there, you will choose the best style and flushing technology that fits your overall design. Let's look at the three main toilet types: gravity-feed, pressure-assisted, double-cyclone, and waterless. Hope this helps :))

G A wheel-tractor scraper is operating on a level grade. Assume no power derating is required for equipment condition, altitude, temperature, and so on. Disregarding traction limitations, what is the maximum value of rolling resistance (in pounds per ton) over which a loaded scraper can maintain a speed of 11 mph

Answers

The maximum value of rolling resistance over which a loaded scraper can maintain in a speed of 11 mph is 275 lb/ton

What is a maximum rolling resistance?

The maximum rolling resistance is the maximum rolling friction that can cause the motion of a body or a substance to resist the force when rolled on a flat surface.

Using Rimpull Performance Chart for wheel-tractor scraper;

For 11 mph speed, the required total resistance is ≅ 25%Grade resistance = 0%

The total resistance = (gross+rolling) resistance

25% = 0% - rolling resistance

rolling resistance = 25%

The maximum rolling resistance = rolling resistance percentage × speed

The maximum rolling resistance \(\mathbf{=25\% ( \dfrac{11 \ lb/ton}{1 \% \ resistance})}\)

The maximum rolling resistance = 275 lb/ton

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By default, the smb.conf file shares all printers and home directories for recognized Windows users.
True or false?

Answers

The statement "By default, the smb.conf file shares all printers and home directories for recognized Windows users" is FALSE.

The smb.conf file is the main configuration file for the Samba server which allows the Linux system to act as a server for the Windows systems on a network. It is located in the /etc/samba directory. This file stores various parameters that configure the different shares available on the system to the clients.

In a default configuration, the smb.conf file does not share all printers and home directories for recognized Windows users. Rather, it specifies settings that allow users to access specific directories, printers, and resources. In other words, it's up to the system administrator to configure Samba to share printers and directories on the system.

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An M14 3 2 hex-head bolt with a nut is used to clamp together two 15-mm steel plates. (a)
Determine a suitable length for the bolt, rounded up to the nearest 5 mm. (b) Determine the
bolt stiffness. (c) Determine the stiffness of the members

Answers

(a) Rounding up to the nearest 5 mm gives a final bolt length of 45 mm.

(b) The stiffness of the bolt is approximately \(5.9 * 10^8\) N/m.

(c) The stiffness of each member (i.e., each steel plate) is approximately \(3.0 * 10^8\) N/m.

(a) To determine a suitable length for the bolt, we need to consider the thickness of the two steel plates and the length required for the threaded portion of the bolt to engage with the nut.

According to standard specifications, the length of engagement for a hex-head bolt should be at least equal to the diameter of the bolt. Therefore, the length of the bolt should be at least 14 mm (the diameter of an M14 bolt).

The combined thickness of the two steel plates is 30 mm (2 x 15 mm), so we need to add this to the length of the bolt. Therefore, a suitable length for the bolt would be:

14 mm (minimum length for engagement) + 30 mm (thickness of plates) = 44 mm

(b) The stiffness of the bolt can be calculated using the formula:

k = (π x d^3 x E) / (4 x L)

where k is the stiffness, d is the diameter of the bolt, E is the Young's modulus of the material (assumed to be 200 GPa for steel), and L is the length of the bolt.

For an M14 bolt, the diameter is 14 mm, and the length is 45 mm (as calculated in part a). Plugging in these values gives:

k = (π x 14^3 x 200 x 10^9) / (4 x 45 x 10^-3) = 5.9 x 10^8 N/m

(c) The stiffness of each member (i.e., each steel plate) can be calculated using the formula:

k = (E x A) / L

where k is the stiffness, E is the Young's modulus of the material, A is the cross-sectional area of the member, and L is the length of the member.

For a steel plate with a thickness of 15 mm, the cross-sectional area can be calculated as:

A = 15 mm x 15 mm = 225 mm^2 = 0.000225 m^2

Assuming a Young's modulus of 200 GPa, the stiffness of each steel plate can be calculated as:

k = (200 x 10^9 Pa x 0.000225 m^2) / 0.15 m = 3.0 x 10^8 N/m

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A Piper Cub airplane has a gross weight of 1700 lb, a cruising speed of 114 mph, and a wing area of 178 ft^2. Determine the lift coefficient of this airplane for these conditions.

Answers

Solution :

As the plane is flying in the air, the force of weight is pulling the plane down. This force must be equal to the force of lift which is generated from the plane's translation true the air. Therefore, the next condition must be satisfied.

\($F_W= L $\)  ................. (i)

The lift force of the plane is given by :

\($L=C_V \frac{\rho}{2} V^2 A$\)

Since the weight force of the plane is given, from the condition (i), we also know the intensity of the lift force.

Therefore, we transform the lift force expression to derive the lift coefficient formula:

\($C_L=\frac{2L}{\rho V^2 A}$\)

\($C_L=\frac{2 \times 1700}{2.38 \times 10^{-3 }\times (167.2)^2 \times 178} $\)

\($C_L = 0.287$\)

box with a central step now consider a box of length 3 nm where the right half of the potential is vright = ℏ 2 mel2 1.5 nm ≤ x ≤ 3 nm. We want to find the ground state wavefunction. We first write the left hand side of the wavefunction as Asin(k
1

x) and the right hand side of the wavefunction as Bsin(k
2

(L−x)). What is the relationship between k
1

and k
2

?

Answers

The relationship between k1 and k2 is determined by applying the boundary conditions at the step potential in the box of length 3 nm.

We can use numerical methods to solve for k1/k2 given the value of vright and other parameters of the problem. The resulting relationship between k1 and k2 will depend on the specific values of these parameters, and will determine the shape of the ground state wavefunction in the box with a central step potential.

The derivative of the wavefunction must also be continuous at x=1.5 nm. This can be expressed as k1Acos(k1*1.5) = k2Bcos(k2*(3-1.5)). We can use these two equations to solve for the relationship between k1 and k2. First, we divide the second equation by the first equation to eliminate the unknowns A and B: k1/k2 = cos(k2*(3-1.5))/cos(k1*1.5).

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How many watts are consumed in a circuit having a power factor of 0. 2 if the input is 100 vac at 4 amperes?.

Answers

The watts that are consumed is 80 watts.

What power factor?

The term power factor has to do with the measure of the efficiency of the use of energy. Recall that power is defined as the rate of doing work. The magnitude of the power factor shows the extent to which the power is used.

Now, to obtain the watts are consumed in a circuit having a power factor of 0. 2 if the input is 100 vac at 4 amperes we have;  V × I × PF = 100V × 4A × 0.2 = 80 watts.

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A horizontal force P is applied to a 130 kN box resting on a 33 incline. The line of action of P passes through the center of gravity of the box. The box is 5m wide x 5m tall, and the coefficient of static friction between the box and the surface is u=0.15. Determine the smallest magnitude of the force P that will cause the box to slip or tip first. Specify what will happen first, slipping or tipping.

A horizontal force P is applied to a 130 kN box resting on a 33 incline. The line of action of P passes

Answers

Answer:

SECTION LEARNING OBJECTIVES

By the end of this section, you will be able to do the following:

Distinguish between static friction and kinetic friction

Solve problems involving inclined planes

Section Key Terms

kinetic friction static friction

Static Friction and Kinetic Friction

Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.

There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.

Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.

Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.

are trains cool because if they are then my dad didn't beat me

Answers

Answer:

I think trains are pretty awesome. There's a train in japan that levitates slightly and runs on magnetism. Pretty amazing. It's super fast too

A triangular plate with a base 5 ft and altitude 3 ft is submerged vertically in water. If the base is in the surface of water, find the force against onr side of the plate. Express the hydrostatic force against one side of the plate as an integral and evaluate it. (Recall that the weight density of water is 62.5 lb/ft3.)

Answers

Answer:

Hydrostatic force = 41168 N

Explanation:

Complete question

A triangular plate with a base 5 ft and altitude 3 ft is submerged vertically in water  so that the top is 4 ft below the surface. If the base is in the surface of water, find the force against onr side of the plate. Express the hydrostatic force against one side of the plate as an integral and evaluate it. (Recall that the weight density of water is 62.5 lb/ft3.)

Let "x" be the side length submerged in water.

Then

w(x)/base = (4+3-x)/altitude

w(x)/5 = (4+3-x)/3

w(x) = 5* (7-x)/3

Hydrostatic force = 62.5 integration of  x * 4 * (10-x)/3 with limits from 4 to 7

HF = integration of 40x - 4x^2/3

HF = 20x^2 - 4x^3/9 with limit 4 to 7

HF = (20*7^2 - 4*7^(3/9))- (20*4^2 - 4*4^(3/9))

HF = 658.69 N *62.5 = 41168 N

be expensed. Required: Conceptual Connection: Classify each cost as part of the overhaul or as an expense. New pump motor Repacking of bearings (performed monthly) New impeller (rotating component of a pump) Painting of pump housing (performed annually) Replacement of pump foundation New wiring (needed every 5 years) Installation labor, motor Installation labor, impeller Installation labor, wiring Paint labor (performed annually) Placement of fence around pump* (

A requirement of the Occupational Safety and Health Administration that will add to maintenance costs over the remaining life of the pump.)

Answers

The classification of each cost as part of an overhaul or as an expense depends on the nature of the cost and its purpose in maintaining or restoring the pump's functionality and efficiency.

To classify each cost as part of the overhaul or as an expense, we need to understand the difference between these two concepts.

An overhaul typically refers to a major repair or restoration of an asset, aimed at restoring it to its original or optimal condition. Overhauls are usually planned and performed periodically to extend the life and efficiency of the asset. On the other hand, expenses are costs incurred in the regular maintenance, operation, or replacement of components to keep the asset functioning properly.

Based on this understanding, let's classify each cost mentioned:

1. New pump motor: This cost would be classified as part of an overhaul if it involves replacing a worn-out or inefficient motor to restore the pump's functionality and efficiency. If it is a regular replacement due to wear and tear, it would be classified as an expense.

2. Repacking of bearings (performed monthly): This cost would generally be classified as an expense since it is part of regular maintenance to ensure smooth operation and prevent bearing failure.

3. New impeller (rotating component of a pump): Similar to the pump motor, if replacing the impeller is part of a planned overhaul to restore the pump's performance, it would be classified as an overhaul. If it is a routine replacement due to wear, it would be considered an expense.

4. Painting of pump housing (performed annually): This cost is typically an expense as it is part of routine maintenance and preservation of the pump housing to prevent corrosion and extend its lifespan.

5. Replacement of pump foundation: This cost is likely to be classified as an overhaul expense since it involves major work on the pump's infrastructure and would aim to restore or improve the foundation's stability.

6. New wiring (needed every 5 years): If the replacement of wiring is part of a planned overhaul to upgrade the pump's electrical system, it would be classified as an overhaul. Otherwise, if it is a regular replacement based on a predefined schedule, it would be an expense.

7. Installation labor (motor, impeller, wiring): The labor costs for installing new components would generally be considered part of the overhaul cost since they are directly associated with the restoration or replacement of major parts.

8. Paint labor (performed annually): Similar to the painting cost, the labor required for annual paint maintenance would be classified as an expense since it is part of routine upkeep.

9. Placement of fence around the pump: This cost would be classified as an expense, specifically a compliance expense, as it is necessary to meet the requirements of the Occupational Safety and Health Administration (OSHA) and ensure safety. It does not directly relate to the overhaul or restoration of the pump.

In summary, overhaul costs aim to restore the pump's original condition or improve its performance, while expenses cover regular maintenance, replacements, or compliance-related expenses.

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A pipe 120 mm diameter carries water with a head of 3 m. the pipe descends 12 m in altitude and reduces to 80 mm diameter, the pressure head at this point is 13 m. Determine the velocity in the small pipe and the rate of discharge (in L/s)? Take the density is 1000 kg/m³.​

Answers

To solve this problem, we can apply the principles of fluid mechanics and Bernoulli's equation.

Given:
- Diameter of the first pipe (D1): 120 mm = 0.12 m
- Diameter of the second pipe (D2): 80 mm = 0.08 m
- Head at the first pipe (H1): 3 m
- Altitude change (Δh): 12 m
- Head at the second pipe (H2): 13 m
- Density of water (ρ): 1000 kg/m³

Step 1: Calculate the velocities in the pipes using Bernoulli's equation.
Applying Bernoulli's equation between the two points in each pipe:
For the first pipe:
P1/ρ + V1²/2g + H1 = constant (1)

For the second pipe:
P2/ρ + V2²/2g + H2 = constant (2)

Since the pipes are open to the atmosphere, we can assume P1 = P2 = atmospheric pressure (approximately).

Simplifying equation (1):
V1²/2g + H1 = constant (3)

Simplifying equation (2):
V2²/2g + H2 = constant (4)

Step 2: Solve for the velocities V1 and V2.
Using equation (3) for the first pipe:
V1²/2g + 3 = constant (5)

Using equation (4) for the second pipe:
V2²/2g + 13 = constant (6)

Step 3: Solve for the velocities V1 and V2.
Since the constants in equations (5) and (6) are the same (as it is a continuous flow), we can equate the two equations:

V1²/2g + 3 = V2²/2g + 13

V1²/2g - V2²/2g = 10

(V1² - V2²)/(2g) = 10

V1² - V2² = 20g

V1² = V2² + 20g (equation 7)

Step 4: Convert the diameter to radius for each pipe.
r1 = D1/2 = 0.12/2 = 0.06 m
r2 = D2/2 = 0.08/2 = 0.04 m

Step 5: Calculate the rate of discharge (Q) using the continuity equation.
The continuity equation states that the product of the cross-sectional area (A) and the velocity (V) is constant in a flowing fluid.

Q1 = Q2 (since it is a continuous flow)

A1V1 = A2V2

πr1²V1 = πr2²V2

(r1²V1)/(r2²) = V2

Step 6: Calculate the velocity in the smaller pipe (V2).
Substitute the values in equation (7):

V1² = V2² + 20g

(V1²r2²)/(r1²) = V2²

(0.06²V2²)/(0.04²) = V2²

V2² = (0.06²V1²)/(0.04²) [Substitute V1² = 2g(3) from equation (5)]

V2² = (0.06² × 2g × 3)/(0.04²)

V2² = 0.27g

V2 = √(0.27g)

Step 7: Calculate the rate of discharge (Q) in L/s.

12. You need to be at the lift controls whenever the lift is in motion A) True B)False

Answers

the answer to that would be a) true

How did inventors like lee deforest and edwin howard armstrong fund their initial research and development ventures into radio technologies?.

Answers

The creation of a "supersonic heterodyne" radio receiver circuit, later abbreviated to "superheterodyne," was Armstrong's greatest achievement during this time. This circuit, which is still widely used today, increased the sensitivity and selectivity of radio receivers.

When was the radio invented by Edwin Armstrong?

1933

The superheterodyne circuit, which he developed in 1918, is a very selective method of capturing, converting, and significantly amplification relatively weak, high frequency electromagnetic waves. His greatest accomplishment, wide-band frequency modulation, or FM radio, was created in 1933.

Following this achievement, the Patent Office approved de Forest's two patents for the ultra-audion and the regenerative circuit. He subsequently filed a lawsuit against Armstrong for violating his ultra-audion patents. The Pennsylvanian court ruled in de Forest's favor.

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1. What is the difference between suspension bridge and cable-stayed bridge?

2. Describe the purpose behind extreme event I limit state?


3. What is the position of the Design Tandem that induce a maximum moment in simple-span bridges?


4. List three factors that affect live load distribution in bridge systems

Answers

1. A suspension bridge is supported by large main cables, from which smaller cables suspend the deck, while a cable-stayed bridge has towers that support the deck directly with cables attached to the towers. 2. The purpose of the extreme event I limit state is to assess the structural integrity of a system or infrastructure under extreme loading conditions, such as earthquakes, hurricanes, or other severe environmental events, ensuring they can withstand and safely endure these extreme forces. 3. The position of the Design Tandem that induces a maximum moment in simple-span bridges is typically located at the quarter span from the support, where the bending moment is the highest due to the concentrated load. 4. Three factors that affect live load distribution in bridge systems are Load configuration, Bridge stiffness and Bridge geometry.

These cables are supported by tall towers or pylons, and the load is primarily transferred to the anchorages. In contrast, a cable-stayed bridge has cables that are connected directly from the towers or pylons to the bridge deck.

The cables are arranged in a fan-like pattern and support the load by transferring it directly to the towers or pylons.

The purpose behind this limit state is to ensure the safety, functionality, and durability of the structure even under extreme conditions. By accounting for these extreme events, engineers can design structures that have the necessary strength, resilience, and robustness to withstand such scenarios, protecting both human life and property.

This configuration leads to the highest bending moment in the bridge structure, as the load is concentrated at the location where the structure is most vulnerable to bending stresses. By considering the maximum moment induced by the Design Tandem, engineers can design the bridge to withstand the associated load effects and ensure its structural integrity.

1. Load configuration: The arrangement and distribution of live loads, such as vehicles, on the bridge influence how the load is distributed across the bridge structure.

2. Bridge stiffness: The stiffness and flexibility of the bridge components impact how the load is transferred and distributed throughout the bridge system.

3. Bridge geometry: The shape, span length, and alignment of the bridge play a role in load distribution, as these factors affect the distribution of forces and moments within the bridge structure.

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Which of the following early works features a swaggering superhero? a. Ode to Aphrodite b. Gilgamesh c. The Iliad.

Answers

The correct answer is b. Gilgamesh. Gilgamesh is an ancient epic poem from Mesopotamia, dating back to the 3rd millennium BCE. It features the legendary hero Gilgamesh, who is depicted as a swaggering and powerful figure. The poem follows Gilgamesh on his adventures and quests, showcasing his heroic and larger-than-life persona.

Option a. Ode to Aphrodite is a reference to a poem by the ancient Greek poet Sappho, which is known for its themes of love and desire.

Option c. The Iliad is an ancient Greek epic poem attributed to Homer. While it does contain heroic characters and battles, it does not specifically feature a swaggering superhero character like Gilgamesh.

Therefore, the correct answer is b. Gilgamesh.

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why do u have to have certain limits for questions

Answers

Answer:

ok

Explanation:

An equipment catalog boasts that a pressure transducer system comes in 31/2-digit (e. G. , 19. 99) or 41/2- digit (e. G. , 19. 999) displays. The 41/2-digit model costs substantially more.


Both units are otherwise identical.


The specifications list the uncertainties for three elemental errors:


Linearity error: 0. 15% FSO

Hysteresis error: 0. 20% FSO

Sensitivity error: 0. 25% FSO

For a full-scale output (FSO) of 20 kPa, select a readout based on appropriate uncertainty calculations.


Explain

Answers

To select the appropriate readout based on the given uncertainties, we need to calculate the maximum potential error for each type of error and compare it with the resolution of the display.

1. Linearity error: The linearity error is specified as 0.15% FSO (Full-Scale Output). To calculate the maximum potential error due to linearity, we multiply the FSO by the specified percentage: 0.15% of 20 kPa = 0.0015 * 20 kPa = 0.03 kPa.

2. Hysteresis error: The hysteresis error is specified as 0.20% FSO. Similar to the linearity error, we calculate the maximum potential error due to hysteresis: 0.20% of 20 kPa = 0.002 * 20 kPa = 0.04 kPa.

3. Sensitivity error: The sensitivity error is specified as 0.25% FSO. Again, we calculate the maximum potential error due to sensitivity: 0.25% of 20 kPa = 0.0025 * 20 kPa = 0.05 kPa.

Now, we compare these maximum potential errors with the resolution of the two display options:

3½-digit display: This display can show values up to 19.99. The resolution is 0.01 kPa (since it's a 31/2-digit display).4½-digit display: This display can show values up to 19.999. The resolution is 0.001 kPa (since it's a 41/2-digit display).

Considering the calculated maximum potential errors, we can determine the appropriate readout:

For the linearity and hysteresis errors (0.03 kPa and 0.04 kPa, respectively), both are greater than the resolution of the 3½-digit display (0.01 kPa). Therefore, the 3½-digit display cannot adequately represent these errors, and we should choose the 4½-digit display.For the sensitivity error (0.05 kPa), it is smaller than the resolution of the 4½-digit display (0.001 kPa). Hence, the 4½-digit display is capable of representing this error accurately.

Based on these calculations, it is recommended to choose the 4½-digit display for this pressure transducer system. It can effectively represent all three elemental errors with its higher resolution and provide a more accurate readout.

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determine the number of branches and nodes in the given circuit. the number of nodes present in the given circuit is . the number of branches present in the given circuit is .

Answers

The number of nodes present in the given circuit is the number of points where two or more components are connected together.

The number of branches present in the given circuit is the number of individual paths between the nodes.

To further elaborate on the topic, nodes and branches are essential components of an electrical circuit, as they are essential for the flow of current throughout the circuit. Nodes represent the points in a circuit where two or more components are connected together, while branches represent the individual paths that the current can take between the nodes.

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Which one of the follow techniques can be used when welding steels with poor weldability? a Use low heat input to increase the weld cooling rates b Use high hydrogen flux ingredients c Preheat the base material to reduce the weld cooling rates d Keep the grease and oil at the welding zone

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The technique that can be used when welding steels with poor weldability is preheat the base material to reduce the weld cooling rates (option c)

Weldability refers to the ability of a material to be welded under certain conditions without producing defects, such as cracks or porosity, in the weld zone. Steels with poor weldability can be difficult to weld without producing defects, and often require special techniques to ensure a successful weld.

Preheating the base material is a common technique used when welding steels with poor weldability. By heating the base material before welding, the cooling rate of the weld zone can be reduced, which can help prevent the formation of cracks and other defects.

Preheating also helps to ensure that the material being welded is at a consistent temperature throughout the welding process, which can improve the quality of the weld.

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Question 1 of 10
Which type of cloud is made up of both liquid water droplets and ice crystals?
• A. Cirrostratus
• B. Stratus
• C. Cirrus
• D. Cumulonimbus
SUBMIT

Answers

Answer:

[D] Cumulonimbus

Explanation:

When the top of a cumulus reaches above, the water droplets are transformed into ice crystals and it loses its clear, sharp outline. It transformed into ice crystals because when it reaches it height the place is cold. As well as at this stage the cloud has become a cumulonimbus. And thus, the type of cloud is made up of both Liquid water droplets and ice crystals are called Cumulonimbus.

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Answer:

D. Cumulonimbus

Explanation:

A vehicle has resistances to control the blower motor speed. This is an example of a ________ electrical circuit

Answers

Answer:

force

Explanation:

A vehicle has resistances to control the blower motor speed. This is an example of a series electrical circuit.

What is electrical circuit?

An electrical circuit is a system that allows an electric current to flow between different components and devices.

It is typically made up of a power source, conductors or wires to carry current, and loads or devices that use electrical energy.

Depending on the application and desired outcome, the components and devices can be arranged in various configurations.

A series electrical circuit is illustrated here. A series circuit connects all components in a row so that the current flowing through each component is the same and there is only one path for the current to take.

The circuit's resistances cause a voltage drop, which controls the speed of the blower motor.

Thus, the answer is series circuit.

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The rate or speed at which work is performed is called what?
Select one:


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Answer:

What are you talking about? pls explain and then maybe I can help.

A fair cubical die is thrown four times. use the binomial probability formula to calculate the probability of at least two 3's.

Answers

By using the binomial probability formula, the probability of at least two 3's is equal to 0.1319.

How to calculate the probability of at least two 3's?

Since the fair cubical die is thrown four times, the number of times is given by n = 4 and the probability of 3's is P = 1/6.

Mathematically, the binomial probability formula is given by:

\(P(X \geq x) =\sum^{n}_{r=x} ^nC_r (p)^r (q)^{(n-r)}\\\\P(X \geq 2) = \; ^4C_2 (\frac{1}{6} )^2 (\frac{5}{6} )^{(4-2)} + ^4C_3 (\frac{1}{6} )^3 (\frac{5}{6} )^{(4-3)} + ^4C_4 (\frac{1}{6} )^4 (\frac{5}{6} )^{(4-4)}\\\\P(X \geq 2) = 6 \times \frac{1}{36} \times \frac{25}{36} + 4 \times \frac{1}{216} \times \frac{5}{36} + 1 \times \frac{1}{1296} \times 1\\\\P(X \geq 2) = \frac{150}{1296} + \frac{20}{1296}+ \frac{1}{1296}\)

P(X ≥ 2) = 19/144

P(X ≥ 2) = 0.1319.

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a tensile specimen with a 12mm initial diameter and 50mm gage length reaches maximum load at 90KN and fractures at 70KN

the minimum diameter at fracture is 10mm

determine the engineering stress at maximum load and the true fracture stress.

Answers

Answer:

i) 796.18 N/mm^2

ii) 1111.11 N/mm^2

Explanation:

Initial diameter ( D ) = 12 mm

Gage Length = 50 mm

maximum load ( P ) = 90 KN

Fractures at =  70 KN

minimum diameter at fracture = 10mm

Calculate the engineering stress at Maximum load and the True fracture stress

i) Engineering stress at maximum load = P/ A

= P / \(\pi \frac{D^2}{4}\)  = 90 * 10^3 / ( 3.14 * 12^2 ) / 4

= 90,000 / 113.04 = 796.18 N/mm^2

ii) True Fracture stress =  P/A

= 90 * 10^3 / ( 3.24 * 10^2) / 4

= 90000 / 81  =  1111.11 N/mm^2

Based on the case, which of the following are reasons why Boeing continues to expand internationally?
Multiple Choice
access to financial capital
availability of supplies and new markets
new markets
availability of supplies

Answers

Availability of supplies and new markets are reasons why Boeing continues to expand internationally.

What is Boeing?

The Boeing Company is a global multinational American company that develops, produces, and markets aircraft, helicopters, rockets, satellites, telecommunications gear, and missiles. Additional services offered by the business include leasing and product support.

According to 2020 revenue, Boeing ranks third among the world's largest defence contractors. It is also the largest exporter from the United States in terms of dollar volume. Boeing is one of the biggest aerospace manufacturers in the world.

The Dow Jones Industrial Average counts Boeing stock as a component. Delaware serves as Boeing's corporate home. In Seattle, Washington, on July 15, 1916, William Boeing established Boeing. At the beginning of August 1997, Boeing and McDonnell Douglas merged to form the current corporation.

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A list of 30 exam scores is: 31, 70, 92, 5, 47, 88, 81, 73, 51, 76, 80, 90, 55, 23, 43,98,36,87,22,61, 19,69,26,82,89,99, 71,59,49,64 Write a computer program that determines how many grades are between 0 and 19, between 20 and 39, between 40 and 59, between 60 and 79, and between 80 and 100. The results are displayed in the following form: Grades between 0 and 19: 2 students Grades between 20 and 39: 4 students Grades between 40 and 59: 6 students and so on. (Hint: use the command fprintf to display the results.)

Answers

To write a computer program that determines how many grades are between 0 and 19, between 20 and 39, between 40 and 59, between 60 and 79, and between 80 and 100 and display the results using the command fprintf we will follow the steps given below:

Step 1: Create a list of exam scores.

Step 2: Initialize 5 variables to 0 for each grade range

Step 3: Create a for loop that will iterate through each score in the list.

Step 4: For each score, use conditional statements to check which grade range it falls into and increment the corresponding variable for that range by 1.

Step 5: Use the command fprintf to display the results in the required format. Below is the program that will implement the above steps:```
scores = [31, 70, 92, 5, 47, 88, 81, 73, 51, 76, 80, 90, 55, 23, 43,98,36,87,22,61, 19,69,26,82,89,99, 71,59,49,64]
range1 = 0
range2 = 0
range3 = 0
range4 = 0
range5 = 0
for score in scores:
   if score >= 0 and score <= 19:
       range1 += 1
   elif score >= 20 and score <= 39:
       range2 += 1
   elif score >= 40 and score <= 59:
       range3 += 1
   elif score >= 60 and score <= 79:
       range4 += 1
   elif score >= 80 and score <= 100:
       range5 += 1
fprintf('Grades between 0 and 19: %d students\n', range1)
fprintf('Grades between 20 and 39: %d students\n', range2)
fprintf('Grades between 40 and 59: %d students\n', range3)
fprintf('Grades between 60 and 79: %d students\n', range4)
fprintf('Grades between 80 and 100: %d students\n', range5)

```The above program will print the number of students in each grade range in the required format.

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Given an array of strings, return the count of the number of strings with the given length.
wordsCount(["a", "bb", "b", "ccc"], 1) → 2
wordsCount(["a", "bb", "b", "ccc"], 3) → 1
wordsCount(["a", "bb", "b", "ccc"], 4) → 0

Answers

The problem requires counting the number of strings in an array that have a given length. To solve this problem, we can iterate through the array of strings and check the length of each string against the target length. If the length matches, we can increment a counter variable.

Here's an implementation of the solution in Python:

def wordsCount(words, length):

   count = 0

   for word in words:

       if len(word) == length:

           count += 1

   return count

In this solution, we first initialize a counter variable count to zero. Then, we loop through each element in the words array and check if its length is equal to the target length. If the length matches, we increment the count variable. Finally, we return the count value.

In the input array ["a", "bb", "b", "ccc"] and target length 1, the function will count the number of strings with length 1, which is 2. Similarly, for target length 3, the function will return 1. And for target length 4, the function will return 0.

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The underlined section of the RNA is designed to match a specific target DNA sequence.5'-GGCGGAGCGGUUCUUGGCAGGUUUUAGAGCUAGAAAUAGC-3'Review the partial gene sequence reshown below. It contains a target DNA sequence that matches the guide RNA above. Highlight the one PAM sequence in the top (5 to 3) strand that is next to this target DNA sequence. (The sequence upstream, toward the 5 end, of this PAM should match the underlined sequence in the guide RNA, which makes the opposite DNA strand complementary to the underlined sequence. Remember that Us in RNA are equivalent to Ts in DNA.)5'-GCACGGCGGAGCGGTTCTTGGCAGCGGCCGCACGATCTCGTTGCCGCCGG-3'3'-CGTGCCGCCTCGCCAAGAACCGTCGCCGGCGTGCTAGAGCAACGGCGGCC-5'Step 2: BindingOnce Cas9 binds to the correct PAM, the guide RNA binds to the complement of the target DNA sequence.Write down the guide RNA sequence that binds to the DNA, and the DNA sequence that it binds to (the complement of the target DNA). 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