Answer:
1.000153 T
Explanation:
The energy change ΔE = hc(1/λb - 1/λa)
= 6.626069 ✕ 10⁻³⁴ J · s 2.997925 × 10⁸ m/s(1/6.544750 × 10⁻⁷ m - 1/6.544550 × 10⁻⁷ m)
= 19.864457907 × 10⁻²⁶(1527942.2438 - 1527988.9374) = 19.864457907 × 10⁻²⁶(-46.6936)
= 927.543052 × 10⁻²⁶
= -9.275431× 10⁻²⁴ J.
This energy change ΔE = 2μBB. So the magnetic field, B is
B = ΔE/2μB where μB = 9.274009 ✕ 10⁻²⁴ J/T
B = -9.275431× 10⁻²⁴ J/9.274009 ✕ 10⁻²⁴ J/T = -1.000153 T
The magnitude of the magnetic field B = 1.000153 T
Which law of thermodynamics does each of the following scenarios violate (if any)?
A machine that can turn 1000J of heat directly into 1000J of electricity
1.
The first law of thermodynamics
2.
The second law of thermodynamics
3.
The third law of thermodynamics
4.
It is allowed
Answer: The scenario violates the second law of thermodynamics.
Explanation: The second law states that heat cannot be converted into work without some loss of usable energy, and that the amount of usable energy in a closed system will always decrease over time. Therefore, the machine described in the scenario cannot exist because it would violate the second law by converting all of the heat into electricity without any loss of usable energy.
What best describes the speed of light waves in solids, liquids, and gases?
The speed is fastest in solids.
The speed is fastest in liquids.
The speed is fastest in gases.
The speed is the same in all matter.
Answer: It’s fastest in gases. Letter C !
Explanation:
Answer:
its c
Explanation:
Now slowly begin to raise the temperature. At approximately what temperature would a heated material (metal, wood, etc.) begin to give off visible light at a deep red color?Note: This will be the temperature where your spectrum first begins to come off of the wavelength axis in the visible region, and so is giving off a small amount of red light.
A. 500 K (440 Fahrenheit)
B. 1050 K (1430 Fahrenheit)
C. 1800 K (2780 Fahrenheit)
D. 2500 K (4040 Fahrenheit)
Answer:
Explanation:
We shall apply Wien's displacement law which is as follows .
λ T = b where λ is wavelength of light that is coming out of hot body to maximum extent .
Putting the value of temperature given and b
λ x 500 = 2898 μmK
λ = 5.796 μm = 5796 nm
For temp 1050 K
λ = 2760 nm
For temp 1800 K
λ = 1610 nm
For temp 2500 K
λ = 1159.2 nm
The visible range starts from 740 nm .
Hence we can expect that some amount of visible light may emerge at the temperature of 2500K because the wavelength that we have calculated above gives the value of peak wavelength of a spectrum of light coming out of hot body .
A 12.7 L box is filled with 6.0 moles of Argon gas and cooled to a temperature of 210 K. What is the pressure?
Answer:
Gases are easily compressed. We can see evidence of this in Table 1 in Thermal Expansion of Solids and Liquids, where you will note that gases have the largest coefficients of volume expansion. The large coefficients mean that gases expand and contract very rapidly with temperature changes. In addition, you will note that most gases expand at the same rate, or have the same β. This raises the question as to why gases should all act in nearly the same way, when liquids and solids have widely varying expansion rates.
Explanation:
Q4. (a) An acre-foot is the volume of water that would cover 1 acre of flat land to a depth of 1
foot. How many gallons are in 1 acre-foot?
Answer:
326,000
Explanation:
One acre-foot equals about 326,000 gallons, or enough water to cover an acre of land, about the size of a football field, one foot deep. An average California household uses between one-half and one acre-foot of water per year for indoor and outdoor use.
8. (-/2 Points]
DETAILS
OBINPHYS8 3.Q.017.
A spring is stretched by an initial amount from its relaxed state. If the spring is then stretched by five times that amount from its relaxed state,
by what factor does the amount of mechanical energy stored in the spring change?
PE final
PE initial
The amount of mechanical energy stored in the spring changes by a factor of 25.
Energy stored in an elastic spring
The energy stored in an elastic spring is given as;
E = ¹/₂kx²
The energy stored in an elastic spring is directly proportional to the square of the extension of the spring.
when the spring is stretched by 5 times greater, the energy stored in the spring is calculated as;
E = ¹/₂k(5x)²
E = ¹/₂k(25x²)
E = 25(¹/₂kx²)
Thus, the amount of mechanical energy stored in the spring changes by a factor of 25.
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An airbys A380 airliner lands at 30 m/s. Partially loaded, its mass is 480000 kg. The engines apply reverse thrust for 12s to slow the plane to 25 m/s.How much thrust did the engines apply?
To determine the thrust applied by the engines, we can use Newton's second law of motion, which states that force (thrust) is equal to mass times acceleration. In this case, we need to calculate the force required to decelerate the plane from 30 m/s to 25 m/s in 12 seconds.
First, we calculate the change in velocity (∆v):
\(\displaystyle\sf \Delta v=25\,m/s-30\,m/s=-5\,m/s\)
Next, we calculate the acceleration (∆a) using the formula:
\(\displaystyle\sf \Delta a=\frac{\Delta v}{\Delta t}\)
where ∆t is the change in time, which is 12 seconds in this case.
\(\displaystyle\sf \Delta a=\frac{-5\,m/s}{12\,s}\)
Now, we can determine the force (thrust) applied by the engines using Newton's second law:
\(\displaystyle\sf F=m\cdot a\)
where m is the mass of the airplane, which is 480000 kg.
\(\displaystyle\sf F=480000\,kg\cdot \left(\frac{-5\,m/s}{12\,s}\right)\)
Calculating the result:
\(\displaystyle\sf F=-200000\,N\)
Therefore, the engines applied a thrust of -200000 Newtons (N) to decelerate the plane. The negative sign indicates that the thrust is in the opposite direction of the motion.
Three cylindrical wires, 1, 2, and 3 are made of the same materialand have resistances R1, R2, and R3, respectively. Wires 1 and 2 have the same lengthbut diameter of wire 2 is twice that of wire 1. Wires 2 and 3 have the same diameterbut length of wire 3is twice that of wire 2.
1. Rank the wires according to their resistances, greatest first.
A. R1> R2> R3R1
B. R1> R3> R2R2
C. R2> R1> R3R3
D. R2> R3> R1
E. R3> R1> R2
F. R3> R2> R1Q2.
2. If same voltage is applied across each of the wires, which one will dissipate heat at the highest rate
Answer:
1) R₁ > R₃ > R₂ correct B , 2) the wire that dissipates the most is wire 2
Explanation:
1) The resistance of a wire is given by the expression
R = \(\rho \ \frac{l}{A}\)
where ρ is the resistivity of the material, l the length of the wire and A the area of the wire
The area is given by
A = π r² = π d² / 4
we substitute
R = (ρ 4 /π) \(\frac{l}{d^2}\)
the amount in parentheses is constant for this case
let's analyze the situation presented, to find the resistance of each wire
* indicate l₁ = l₂ and d₂ = 2 d₁
the resistance of wire 1 is
R₁ = (ρ 4 /π) \(\frac{l_1}{d_1^2}\)
the resistance of wire 2 is
R₂ = (ρ 4 /π) \frac{l_2}{d_2^2}
R₂ = (ρ 4 /π) \(\frac{l_1}{ (2 d_1)^2}\)
R₂ = (ρ 4 /π ) \(\frac{l_1}{d_1^2}\) ¼
R₂ = ¼ R₁
* indicate that d₂ = d₃ and l₃ = 2 l₂
R2 = (ρ 4 /π) \(\frac{l_2}{d_2^2}\)
the resistance of wire 3 is substituting the indicated condition
R3 = (ρ 4 /π 2) \frac{l_3}{d_3^2}
R3 = (ρ 4 /π) \(\frac{2 \ l_2}{d_2}\)
R3 = 2 R₂
let's write the relations obtained
R₁ = (ρ 4 /π) \(\frac{I_1}{ d_1^2}\)
R₂ = ¼ R₁
R₃ = 2 R₂
let's write everything as a function of R1
R₁ =(ρ 4 /π) \(\frac{l_1}{d_1^2}\)
R₂ = ¼ R₁
R₃ = ½ R₁
the resistance of the wire in decreasing order is
R₁ > R₃ > R₂
2) The power dissipated by a wire is
P = V I
the voltage is
V = I R
I = V / R
substituting
P = V² / R
therefore the power dissipated by each wire is
wire 1
P₁ = V² / R₁
wire 2
P₂ = V² / R₂
P₂ = \(\frac{V^2}{ \frac{1}{4} R_1}\)
P₂ = 4 P₁
wire 3
P₃ = V² / R₃
P₃ = \(\frac{V^2}{ \frac{1}{2} R_1}\)
P₃ = 2 P₁
Therefore, the wire that dissipates the most is wire 2
In a symphony a single violin produces 25.0 dB sound intensity, if the conductor desires a robust
sound intensity of 70.0 dB from violin section, how many violin players does he employ?
He has to employ 31623 violin players.
What is intensity of sound in dB?The SI unit for sound intensity is W/m^2, although considering how humans hear sounds, the decibel (dB) scale of sound intensity is more useful. The logarithm of the intensity of a sound, as opposed to the intensity of a sound directly, is a better indicator of how human ears perceive sound.
Ten decibels (dB) are equal to every factor of ten in intensity.
For this case, a 70.0 dB sound is 45 dB louder than a 60 dB sound, 4.5 factors of 10 (10^4.5) as intense.
Hence, if a single violin produces 25.0 dB sound intensity, to produce a robust sound intensity of 70.0 dB from violin section, he has to employ 10^4.5 = 31623 violin players.
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A 1.3 KG blocks flies along a frictionless surface at 1.0 M/S.a2 block sliding at a faster 5.0 M/S collides with the first from behind and sticks to it. The final velocity of the combine blocks is 2.0 M/S. What was the mass of the second block?
the initial momentum of the system of block m1 and block m2 is
Pi= m1v1 + m2v2
the final momentum of the combine blocks is
Pf= (m1+m2)V
according to the law of convervation of momentum
Pi = Pf
m1v1 + m2v2 = (m1+m2)V
1.3 × 1 + 5m2 = 1.3 × 2 + 2m2
m2= 1.3/3 kg
If a 15-ohm resistor is connected in parallel with a 30 ohm-resistor, the equivalent resistance is?
Answer:
Explanation:
in parallel combination equivalent resistence =
1/R=1/R1 + 1/R2
1/2=1/15+1/30
1/2=1*2+1*1/30
1/R=3/30
R*3=30*1
R=30/3
R=10 ohm
Explanation:
Equilibrium resistance=1/R1 +1/R2
\( = \frac{1}{15} + \frac{1}{30} \\ = \frac{2 + 1}{30} \\ \frac{1}{r} = \frac{3}{30} \\ resistance \: = \frac{30}{3} \\ = 10 \: ohms\)
As you walk to class with a constant speed of 1.90 m/s, you are moving in a direction that is 13.8 degrees north of east.
A.) how much time does it take to change your displacement by 16.0 m East?
B.) how much time does it take to change your displacement by 26.0 m North?
(a) The time it takes for you to change your displacement by 16 m east is 8.67 s.
(b) The time it takes for you to change your displacement by 26 m north is 35.3 s.
What is the time of motion?(a) The time it takes for you to change your displacement by 16 m east is calculated as follows;
s = vt + ¹/₂at²
where;
v is the initial velocityt is the time of motiona is the acceleration = 0 (because velocity is constant)16 = 1.9 x cos(13.8)t
16 = 1.845t
t = 16/1.845
t = 8.67 s
(b) The time it takes for you to change your displacement by 26 m north is calculated as follows;
16 = 1.9 x sin(13.8)t
16 = 0.453t
t = 16/0.453
t = 35.3 s
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Convert the binary numbers into decimal number 1010102
\(\\ \sf\longmapsto (101010)_2\)
\(\\ \sf\longmapsto 0\times 2^0+1\times 2^1+0\times 2^2+1\times 2^3+0\times 2^4+1\times 2^5\)
\(\\ \sf\longmapsto 2+8+32\)
\(\\ \sf\longmapsto (42)_{10}\)
Particle is thrown in upward direction with initial velocity of 60m/s. Find average speed & average velocity after 10 seconds. Take g= 10 ms-2
The particle's average speed after 10 seconds is 110 m/s, and its average velocity is zero.
When a particle is thrown upwards, its initial velocity is in the upward direction and its acceleration is in the downward direction due to gravity. The acceleration due to gravity is approximately 10 m/s² near the surface of the Earth. Therefore, the particle's velocity decreases at a rate of 10 m/s² until it reaches its highest point, where its velocity is zero. After that, the particle's velocity becomes negative and it starts to fall back to the ground.
To find the particle's average speed after 10 seconds, we need to calculate the total distance traveled by the particle in 10 seconds. The formula to calculate the distance traveled by a particle under constant acceleration is:
distance = initial velocity * time + (1/2) * acceleration * time²
Substituting the given values, we get:
distance = 60 m/s * 10 s + (1/2) * 10 m/s² * (10 s)²
distance = 600 m + 500 m
distance = 1100 m
Therefore, the average speed of the particle after 10 seconds is:
average speed = total distance / total time
average speed = 1100 m / 10 s
average speed = 110 m/s
To find the particle's average velocity after 10 seconds, we need to calculate the displacement of the particle in 10 seconds. Displacement is the change in position of the particle, which is equal to the difference between its final and initial positions. Since the particle is thrown upwards and then falls back to the ground, its displacement after 10 seconds is zero. Therefore, the average velocity of the particle after 10 seconds is also zero.
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Find the acceleration due to gravity on planet Fergie which has a mass of 6.23 * 10^23 kg and a radius of 5.79* 10^7 m
Answer:
The acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.
Explanation:
We want to find the acceleration due to gravity on the planet Fregie. Let it be g m/s^2.
Now, the acceleration due to gravity is defined through the following equation:
\(mg = GMm/R^2\)
where m is the mass of an object on the surface of the planet, M is the mass of the planet, R is the radius of the planet, and G is the universal Gravitational constant.
Subsituting values for M = 6.23*10^23, R = 5.79*10^7, G = 6.67*10^(-11), we get
g = 0.0123 m/s^2.
Thus the acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.
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What is net force?
A. The sum of all the forces acting on an object
B. The difference between the largest and smallest forces acting on
an object
C. The largest force acting on an object
D. The smallest force acting on an object
Answer:
A. The sum of all the forces acting on an object.
A 0.18 kg baseball moving at +21.80 m/s is slowed to a stop by a catcher who exerts a constant force of -360 N.
How long does it take this force to stop the ball?
___s
How far does the ball travel before stopping?
___m
Answer:
hey so this website called quiz-let helps you it will give u the answer for every question i use it sometimes when im confused on a test.
It takes 0 seconds for the catcher to stop the ball and the ball travels 0 meters before stopping.
What is force?To find the time it takes for the catcher to stop the ball, you can use the equation:
time = distance / velocity
In this case, the distance is zero (since the ball is stopped) and the velocity is 21.80 m/s. Plugging these values into the equation gives us:
time = 0 / 21.80
time = 0 s
So, it takes 0 seconds for the catcher to stop the ball.
To find the distance the ball travels before stopping, you can use the equation:
distance = 1/2 * acceleration * time^2
In this case, the acceleration is the force applied to the ball divided by the mass of the ball, or (-360 N) / (0.18 kg) = -2000 m/s^2. The time is the time it takes the ball to stop, which we just found to be 0 s. Plugging these values into the equation gives us:
distance = 1/2 * (-2000 m/s^2) * (0 s)^2
distance = 0 m
So, the ball travels 0 meters before stopping.
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A 1.2 kg object hanging from a spring of force constant 300 N/m oscillates with a maximum speed of 30 cm/s. (a) What is its maximum displacement? When the object is at its maximum displacement, find (b) the total energy of the system, and (c) the gravitational potential energy. (Choose potential energy as zero when the object is in equilibrium).
The maximum displacement = 0.0189 m
The Total energy of the system = 1.188 J
The Gravitational potential energy = 0.22 J
Let m be = Mass of the object = 1.2 kg
As given K = Spring Constant of the spring = 300 N/m
Let v denote = Maximum speed with which the body oscillates = 30 cm/s
Let 'x' be the maximum displacement of the body
x²= mv²/k=1.2* 0.3 /300= 0.0189
Total energy= kinteric energy+potential energy =kx²/2 + mv²/2
=1.188J
The Gravitational potential energy of the system is
E=Mgx=1.2*9.8*0.0189
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The 1.2 kg object's maximum displacement when it is suspended from a spring with a 300 N/m force constant oscillates at a maximum speed of 30 cm/s. This displacement is equal to 0.0189 m.
How to calculate displacement and energy?When the object is displaced to its maximum, the system's total energy is 1.188 J.
The energy of gravity is equal to 0.22 J.
Allow m to be equal to 1.2 kg, the object's mass.
K = Spring as stated. Springs have a constant of 300 N/m.
the body can oscillate at a maximum speed of 30 cm/s (let v signify this).
Suppose that "x" represents the body's largest displacement.
x²= mv²/k=1.2* 0.3 /300= 0.0189
Total energy = interstellar energy + potential energy = kx2/2 + mv2/2
=1.188J
According to the system's gravitational potential energy,
E=Mgx=1.2*9.8*0.0189
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How has Physics improved
or affected our society?
By supplying the fundamental knowledge required to create new instruments and techniques for medical use, physics enhances our quality of life
From can openers, light bulbs, and mobile phones to muscles, lungs, and brains; from paintings, piccolos, and pirouettes to cameras, vehicles, and cathedrals; from earthquakes, tsunamis, and storms to quarks, DNA, and black holes, physics aids us in understanding the workings of the world around us.
The science of physics is the most fundamental and has many applications in contemporary technology. Because it makes it possible for smartphones, computers, televisions, watches, and many other modern technologies to function automatically, physics is crucial to modern technology.
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Are we within Earth's Roche limit?
Answer:
Yes
Explanation:
Within the Earths Roche is our mass and body.
A 2 kg object has a kinetic energy of 64 J. What is its momentum?
Take into account that the momentum is given by:
\(p=mv\)where m is the mass and v the speed of motion.
In order to calculate p it is necessary to find the value of v. Use the following expression for the kinetic energy:
\(K=\frac{1}{2}mv^2\)In this case, you have:
K = 64J
m = 2 kg
Solve for v and replace the previous values:
\(\begin{gathered} v=\sqrt{\frac{2K}{m}} \\ v=\sqrt[]{\frac{2(64J)}{2\operatorname{kg}}}=8\frac{m}{s} \end{gathered}\)Now, replace the value of v and m to find the momentum:
\(p=(2kg)(8\frac{m}{s})=16\operatorname{kg}\cdot\frac{m}{s}\)Hence, the momentum is 16 kg*m/s
PLEASE HELP!
I don't even know what Science is I'm so dumb lol XD
Answer:
C
Explanation:
Sled A has more potential energy because it's mass is 100 kg, and it is higher up than Sled B. The more high up the sled is and the lighter it is, the faster it gets, it creates more and more potential energy.
Hope this helps!
Three charges are at the vertices of a triangle ABC where AB = AC = 5cm and
\(q = 1.0 \times {10}^{ - 7} c\)
Find the force acting on the Charge at A.
The Force acting on charge A will be 0.036N.
What is Coulomb's law ?Coulomb's law is the force of attraction or repulsion acting on straight line is directly proportional to the charge place on that line and inversly proportional to the square of seperation between them.
F= kq1q2/r²
where F is the electrostatic force ,q are the point charges , K is coulomb constant , r is seperation between the charges.
Value of Coulomb's constant is 8.98×10⁹Nm²/C².
In the question ,we have given the sides of the triangle ,we can consider them as seperation also ,
r=5cm = 5×10-²m
the charge is 10-⁷C.
F= 9×10⁹×1×10-¹⁴/25×10-⁴
F= 0.036N
So, the force acting on Charge A is
0.036 N.
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Unless specifically stated otherwise, you may assume the speed of sound for all the scenarios below is 350 m/s.2.A traffic cop uses a sonar gun to check for speeding cars. The sonar gun emits a sound wave with a frequency of 35,000 Hz. The sonar waves are reflected by the oncoming cars and are read by the gun’s receiver. For one car coming towards the traffic cop, the sonar gun reads a frequency of 37,700 Hz. How fast is the oncoming car moving?
We have the following data:
fo: frequency observed; fo = 37700 Hz
fs: actual frequency emitted; fs = 35000 Hz
vo: velocity of observer; vo = 0 m/s
v: velocity of sound; v = 350 m/s
We need to solve for the velocity of the car, so let's call that vs.
Doppler effect equation:
fo/fs = (v+vo)/(v+vs)
Now let's substitute all the variables we know:
37700/35000 = (350+0)/(350+vs)
Let's isolate vs:
350+vs = 35000(350)/37700
vs = 35000(350)/37700 - 350
vs = -25.066 m/s
Since velocity of the car is negative in relation to the cop, this means the car is approaching the cop. Its speed is |vs| = 25.066 m/s
what is the main cause of the seasons
If a wave has a frequency of say 10 Hz, that means something is oscillating times per second. What is this property that is oscillating for light, described by its frequency?
The property that is oscillating would be the electric and magnetic fields.
Oscillating properties of lightFor light, the property that is oscillating or vibrating at a particular frequency is the electric and magnetic fields.
Light is an electromagnetic wave, which means that it consists of oscillating electric and magnetic fields that are perpendicular to each other and to the direction of wave propagation.
The frequency of the wave corresponds to the number of complete oscillations of the electric and magnetic fields that occur per second, and is measured in hertz (Hz).
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A pingpong ball has 2 kg/s of momentum when
thrown 8 m/s. Find the mass of the ball.
Answer:
0.25 kg
Explanation:
p = mv
2 = m(8)
2/8 = m(8)/8 *cancels
m = 1/4 OR 0.25 kg
Given the Coulomb's formula F= ke q1*q2/r^2 where ke= (9.0 * 10^9 N m^2/c^2)
F is the force between charges in Newton, Qr and Q2 are the respective two charges in Coulombs, and r is the distance in meters. Calculate the distance between two charges of 20μc and 18μC if the force between the two charges is 2.8x10^4 N
The distance between two charges is 1.075 cm.
Distance between the chargesThe distance between the charges is calculated using Coulomb's law as shown below;
F = kq1q2/r²
Fr² = kq1q2
r² = kq1q2/F
r = √( kq1q2/F)
where;
r is the distance between the chargesF is the force of attractionr = √( 9 x 10⁹ x 20 x 10⁻⁶ x 18 x 10⁻⁶/2.8 x 10⁴)
r = 0.01075 m
r = 1.075 cm
Thus, the distance between two charges is 1.075 cm.
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motorcycle accelerate
A 1.35 kg block is pulled across a flat, frictionless floor with a 3.07 n force at 32.0 above horizontal. What is the acceleration of the block