First answer is brainlyist 50points

Olivia could have used a combination of a rotation and a translation to move ABCDE onto A"B"C"D"E".

Angelica's transformed figure will not match A"B"C"D"E" because reflecting ABCDE over the y-axis will change the order of the letters in the figure.

No, Michael is not correct.

Translating ABCDE diagonally by 8 units up and 10 units right will move each point in ABCDE the same distance horizontally and vertically, which will change the shape of the figure.

In order to match A"B"C"D"E", the transformation must preserve the order of the letters and the angles between the segments.

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An arrangement of more than one repeating shape with no spaces or overlapping between shapes is a semi-regular tessellation

Given data ,

Let the semi-regular tessellation be represented as A

Now , the value of A is

A semi-regular tessellation is a tiling of the plane by two or more regular polygons in such a way that every vertex has the same configuration of polygons in the same order

Therefore , an arrangement of more than one repeating shape with no spaces or overlapping between shapes

Hence , the semi-regular tessellation is solved

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Egbert must deposit $19,602.52 as a lump sum in order to have $40,000 in the fund at the end of 10 years.

To calculate the required lump sum deposit, we can use the formula for compound interest:

A = P\((1+r/n)^{nt}\)

Where:

A = the future value (desired amount in the fund) = $40,000

P = the initial principal (lump sum deposit we need to find)

r = the annual interest rate in decimal form = 7% = 0.07

n = the number of compounding periods per year = 4 (quarterly compounding)

t = the number of years = 10

Plugging in these values, the formula becomes:

$40,000 = P\((1+(0.07/4)^{(4*10)}\)

Simplifying further:

$40,000 = P\((1.0175)^{40}\)

Now we can solve for P by dividing both sides of the equation by

P = $40,000 /\((1.0175)^{40}\)

Using a calculator to evaluate the expression, we find:

P ≈ $19,602.52

Therefore, Egbert must deposit approximately $19,602.52 as a lump sum in order to have $40,000 in the fund at the end of 10 years.

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Answer:

212 degrees Fahrenheit (100 degrees Celsius)

Step-by-step explanation:

not really sure how to do this stuff

Answer:

The 99% confidence interval for the population mean reduction in anxiety was (1.2, 8.6).

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 27 - 1 = 26

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 26 degrees of freedom(y-axis) and a confidence level of \(1 - \frac{1 - 0.99}{2} = 0.995\). So we have T = 2.7787.

The margin of error is:

\(M = T\frac{s}{\sqrt{n}} = 2.7787\frac{6.9}{\sqrt{27}} = 3.7\)

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 4.9 - 3.7 = 1.2.

The upper end of the interval is the sample mean added to M. So it is 4.9 + 3.7 = 8.6.

The 99% confidence interval for the population mean reduction in anxiety was (1.2, 8.6).

We have proved that the Newton-Raphson iteration formula for solving the equation\(x^k e^x = 0\) is given by \(x_{n+1} = (k - 1) x_n + x_n^2 / k + x_n.\)

To prove that the Newton-Raphson method for solving the equation \(x^k e^x = 0\), where k is a constant, is given by the formula

\(x_{n+1} = (k - 1) x_n + x_n^2 / k + x_n,\)

we can start by considering the iterative process of the Newton-Raphson method.

Given an initial guess \(x_n\), we want to find a better approximation \(x_{n+1}\)that is closer to the root of the equation \(x^k e^x = 0.\)

The Newton-Raphson method involves the following steps:

Calculate the function value \(f(x_n) = x_n^k e^x_n\) and its derivative \(f'(x_n) = k x_n^(k-1) e^x_n.\)

Find the next approximation x_{n+1} by using the formula:

\(x_{n+1} = x_n - f(x_n) / f'(x_n)\)

Let's apply these steps to our equation \(x^k e^x = 0\):

Calculate the function value and its derivative:

\(f(x_n) = x_n^k e^x_n\\f'(x_n) = k x_n^(k-1) e^x_n\)

Find the next approximation x_{n+1} using the formula:

\(x_{n+1} = x_n - f(x_n) / f'(x_n)\)

Substituting the function value and its derivative:

\(x_{n+1} = x_n - (x_n^k e^x_n) / (k x_n^(k-1) e^x_n)\\= x_n - (x_n^k / k)\)

Simplifying the expression by combining like terms:

\(x_{n+1} = x_n - (x_n^k / k)\\= x_n - x_n^k / k\\= (k - 1) x_n + x_n^2 / k + x_n\)

Therefore, we have proved that the Newton-Raphson iteration formula for solving the equation\(x^k e^x = 0\) is given by \(x_{n+1} = (k - 1) x_n + x_n^2 / k + x_n.\)

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When we have two similar figures their corresponding sides or angles are pairs of matching angles or sides.

Let's separate both triangles

ΔFHJ and ΔKHG

If we rotate any of both, then we will observe the similarity of the triangles:

Then, we have that the corresponding sides are (same colored):

And the corresponding angles are:

(same colored)

Then,

ANSWER:

Corresponding sides:

HF ≅ HK

JH ≅ GH

FJ ≅ KG

Corresponding angles:

∡H ≅ ∡H

∡J ≅ ∡G

∡F ≅ ∡K

Answer:

This is a case of direct variation. Hence,

210/1=x/2

x=420

since 2 pandas eat it each day hence

420/7

=60

60 pounds is the answer.(sure)

Step-by-step explanation:

Hope it helps you.

Answer: 60 pounds

Step-by-step explanation:

210 pounds a week

Divide by 7 days (a week)

Equals 30 pounds a day/ per panda

There is 2 pandas so 30 pounds times 2 equals 60 pounds

Answer:

1,560mi/h

Step-by-step explanation:

390 miles in 15 minutes

X miles in 60 minutes

(Cross multiplication)

(390*60)/15 = 1560

Answer:

40m^2    152.6m^2

Step-by-step explanation:

Answer:\(10n^{2}\)+180

Step-by-step explanation:

a. The answer is: The fewest number of multibase blocks required to represent 20 longs in base seven is 2 flats.

b. The answer is: The fewest number of multibase blocks required to represent 10 longs in base three is 3 flats and 1 unit.

a. To represent 20 longs in base seven, we need to find the fewest number of multibase blocks required.

In base seven, we have the following conversions:

1 long = 1 unit

1 flat = 10 units

1 block = 10 flats

To represent 20 longs, we can use 2 flats (each flat representing 10 units) and 0 units since there are no remaining units.

So, the fewest number of multibase blocks required would be 2 flats.

Therefore, the answer is: The fewest number of multibase blocks required to represent 20 longs in base seven is 2 flats.

b. To represent 10 longs in base three, we need to find the fewest number of multibase blocks required.

In base three, we have the following conversions:

1 long = 1 unit

1 flat = 3 units

1 block = 3 flats

To represent 10 longs, we can use 3 flats (each flat representing 3 units) and 1 unit since there is one remaining unit.

So, the fewest number of multibase blocks required would be 3 flats and 1 unit.

Therefore, the answer is: The fewest number of multibase blocks required to represent 10 longs in base three is 3 flats and 1 unit.

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Answer:

10x+16

Step-by-step explanation:

4x-1+6x+2+15

10x-1+2+15

10x+16

Answer:

Step-by-step explanation:

\(\sf 14=-6+2\left(2x+4\right)\)

\(\sf -6+2\left(2x+4\right)=14\)

\(\sf -6+2\left(2x+4\right)+6=14+\)

\(\sf 2\left(2x+4\right)=2\)

\(\sf \frac{2\left(2x+4\right)}{2}=\frac{20}{2}\)

\(\sf 2x+4=10\)

\(\sf 2x+4-4=10-4\)

\(\sf 2x=6\)

\(\sf \frac{2x}{2}=\frac{6}{2}\)

\(\sf x=3\)

To find the limit of a convergent sequence, we can simply take the limit as n approaches infinity. Let's calculate the limits for each of the given sequences:

A. \(\sf\:\lim_{n \to \infty} \frac{5n}{n+7} \\\)

To find the limit, we divide the leading terms by n:

\(\sf\:\lim_{n \to \infty} \frac{5n/n}{(n+7)/n} = \frac{5}{1} = 5 \\\)

Therefore, the limit of the sequence A is 5.

B. \(\sf\:\lim_{n \to \infty} \frac{4-7n}{8+n} \\\)

Again, divide the leading terms by n:

\(\sf\:\lim_{n \to \infty} \frac{4/n - 7}{8/n + 1} = \frac{0 - 7}{0 + 1} = -7 \\\)

So, the limit of sequence B is -7.

C. \(\sf:\lim_{n \to \infty} \frac{8n - 500\sqrt{n}}{2n + 800\sqrt{n}} \\\)

Divide the leading terms by n:

\(\sf\:\lim_{n \to \infty} \frac{8 - 500\sqrt{n}/n}{2 + 800\sqrt{n}/n} \\\)

As n approaches infinity, the terms involving \(\sf\:\sqrt{n}/n \\\) tend to 0:

\(\sf\:\lim_{n \to \infty} \frac{8 - 500(0)}{2 + 800(0)} = \frac{8}{2} = 4 \\\)

Therefore, the limit of sequence C is 4.

To summarize:

A. The limit of sequence A is 5.

B. The limit of sequence B is -7.

C. The limit of sequence C is 4.

Option A would add up to 85 cents: 3 quarters and 10 pennies.

Each of four equal or corresponding parts into which something is or can be divided is known as quarter.

The value of a quarter is 25 cents, so three quarters will have a value of 75 cents.

Now, we need to add coins that will make up the remaining 10 cents. If we add 9 pennies or 10 pennies, the total value would be:

75 cents + 9 cents = 84 cents

75 cents + 10 cents = 85 cents

So, option A would add up to 85 cents: 3 quarters and 10 pennies.

Option B, C, and D would not add up to 85 cents as they do not give a total value of 85 cents.

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B, C, and E are the products equivalent to 1/6

We have been given five different products and we have to find out which of them are equivalent to 1/6. So,

Here we observe that the product of B, C, and E after solving them is equivalent to 1/6 whereas, the product of A and D is 1/12 and -1/18 respectively.

Hence, We get that the product for the numbers

Which are Options B, C, and E equivalent to 1/6

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Answer:

one quart is about 0.95 liters, so its about 2.84 liters after dividing because you want to see how many times that 3 quarts can go into liters

Step-by-step explanation:

mr clean

Answer:

The cooler holds 2.85 liters.

Step-by-step explanation:

Convertion: 1 quart = 0.95 liters

3 × 0.95

= 2.85 Liters

Answer:

6.25 miles per hour

Step-by-step explanation:

Answer:

see below

Step-by-step explanation:

-2> x ≥ -7    can be written as   -7 ≤ x < -2

Answer:

L = ½ × pedestal × tall

L = ½ × ( 10 × 10 ) × ( 10 × 10 )

L = ½ × 100 × 100

L = 100/2 × 100

L = 10.000/2

L = 10.000 ÷ 2

L = 5.000 Cm³

Answer:

I never learned that sorry ‍♀️

Step-by-step explanation:

you should have to give more points for this answer

Answer:

B

Step-by-step explanation:

2/3 is the opposite of -2/3...

Hope this helps!

Answer:

0.33=0.33

Step-by-step explanation:

it is answer 0.33=0.33

Answer:

Step-by-step explanation:

1. (4x5) is 20

2. (4x 2) is 8

3. 20 plus 8 is 28

4. 28= 4x (5+n)

5. isolate n by dividing 4 on both sides= 28/4= 4+n

6. subtract 4 on both sides to get 7-4=n

7. n=3

The equation of the sinusoid function is:

3 Sin πx + 2.

Let's analyze the given options to find the correct equation:

a. 3 Cos πx + 2:

This option is a cosine function with a vertical shift of 2, but it does not have the correct amplitude or period. Therefore, it is not the correct equation.

b. 3 Sin x: This option is a sine function with the correct amplitude, but it does not have the correct vertical shift or period. Therefore, it is not the correct equation.

c. 3 Sin πx + 2: This option is a sine function with the correct amplitude and vertical shift. Let's check if it has the correct period:

To determine if the period is correct, we need to calculate the x-values when the function repeats itself.

In this case, we need to find x-values such that sin(πx) = 0, since the function will reach its maximum and minimum points again at those x-values.

sin(πx) = 0 when πx = 0, π, 2π, 3π, ...

Solving for x, we have:

πx = 0 ⟹ x = 0

πx = π ⟹ x = 1

πx = 2π ⟹ x = 2

πx = 3π ⟹ x = 3

From this, we can see that the function repeats itself every integer value of x, which matches the given information.

Therefore, option (c) is the correct equation: 3 Sin πx + 2.

Option (d) 3 Cos x does not have the correct vertical shift or period, so it is not the correct equation.

Hence, the equation of the sinusoid function is:

3 Sin πx + 2.

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There are 4 significant figures in the measurement 1.050 (Option d)

What are significant figures?

Significant figures are the number of digits that add to the correctness of a value, frequently a measurement. The first non-zero digit is where we start counting significant figures. We can determine how many significant figures in a given numbers by counting the number of digits that are significant to indicate the quantity or value of something.

How the measurement 1.050 has 4 significant figures?

Since the quantity 1.050 starts with 1, that is a non-zero digit, we start counting the significant figures starting from this digit. Thus, 1 is the first significant digit here. 0, 5, and 0 are the second, third, and fourth significant digit respectively.

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Answer:

option D

Step-by-step explanation:

just took the test

Answer:

Neither perpendicular or parallel

Step-by-step explanation:

here is it on a graph. They do not intersect and aren't the same distance apart