Find the LCM for 24 and 30 using the cake method

Answer:

It depends on what that number is but -4+29 is equal to 29-4; making the answer to -4+29=5.

Step-by-step explanation:

Answer:

Trapezoid

Step-by-step explanation:

The two-dimensional shapes could be the cross-section of a cube sliced by a plane in any direction is square and triangle. Option B is correct.

When a 2 dimensional plane figure at any angle is intersected, a solid object, a cross-section is formed. The shape of this cross-section is based on the type of plane, its angle of intersect and type of solid.

Now, when a cube sliced by a plane in any direction, the following cross section is formed-

Thus, the two-dimensional shapes could be the cross-section of a cube sliced by a plane in any direction is square and triangle. Option B is correct.

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Answer:

\(1 \dfrac{1}{4} \ liters\)

Step-by-step explanation:

Given that:

Claire uses 2 liters of paint to cover 1 3/5 doors

Then in order for her to paint 1 door, She will need:

2 L = 1 3/5 door

x L = 1 door

\(x (L) = \dfrac{2 L \times 1 door }{ 1 \dfrac{3}{5} \ door}\)

\(x (L) = \dfrac{2 L }{ 1 \dfrac{3}{5} }\)

\(x (L) = \dfrac{2 L }{ \dfrac{8}{5} }\)

\(x (L) = \dfrac{2 L\times 5 }{ 8 }\)

\(x (L) = \dfrac{10 \ L }{ 8 }\)

\(x(L) =1 \dfrac{1}{4} \ L\)

Answer:

Length is 10

Width is 8

Step-by-step explanation:

The formula for the perimeter of a rectangle is:

\(P=2l+2w\)

We are told that the length l is 2 more than twice the width w. In other words:

\(l=2+2w\)

Also, we are given that the perimeter is 28. Therefore:

\(P=2l+2w\\28=2(2+2w)+2w\)

Distribute:

\(28=4+4w+2w\)

Combine like terms:

\(28=4+6w\)

Subtract 4 from both sides:

\(6w=24\)

Divide by 6:

\(w=4\)

So, the width is 4.

And the length is 2 more than twice the width. Thus:

\(l=2+2(4)\\l=2+8=10\)

The length is 10.

And we are done :)

Answer:

The answer is A) All four sides are equal. The simplest radical form for each side is √40.

Step-by-step explanation:

If X is plotted on 6 on the y-axis, then X is located at the point (2, 6), since W is plotted on 2 on the x-axis, W is located at the point (2, 2).

Since we know that XW is one side of the square, we can find the other three vertices of the square using the fact that all sides of a square are equal in length and perpendicular to each other.

To find the third vertex, we can use the fact that Z is plotted at (4, -2) and is perpendicular to XW. Since XW has a length of 4 (the difference in y-coordinates between X and W), we know that the length of ZY must also be 4. To find the coordinates of Y, we can move 4 units up from the y-coordinate of Z (which is -2), giving us a y-coordinate of 2. Since ZY is perpendicular to XW, we know that the x-coordinate of Y must be the same as the x-coordinate of Z (which is 4). Therefore, the coordinates of Y are (4, 2).

To find the fourth vertex, we can use the fact that all sides of the square are equal in length. Since XW has a length of 4, we know that ZY must also have a length of 4. Therefore, the fourth vertex must be located 4 units to the right of Y and 4 units up from X. This gives us a fourth vertex with coordinates of (6, 6).

Therefore, the vertices of the square are W(2, 2), X(2, 6), Y(4, 2), and Z(4, -2).

To check that the sides of the square are perpendicular to each other, we can calculate the slopes of the sides.

The slope of XW is:

m_XW = (6 - 2) / (2 - 2) = undefined

The slope of ZY is:

m_ZY = (2 - (-2)) / (4 - 4) = undefined

Since both slopes are undefined (the lines are vertical), the sides are perpendicular to each other.

To check that the sides of the square are equal in length, we can use the distance formula:

XW = sqrt((6 - 2)^2 + (2 - 2)^2) = sqrt(16) = 4

ZY = sqrt((2 - (-2))^2 + (4 - 4)^2) = sqrt(16) = 4

Since both sides have the same length of 4, all sides of the square are equal in length.

Therefore, the answer is option A) All four sides are equal. The simplest radical form for each side is √40.

Hope this helped, if it's wrong I'm sorry! If you need more help, ask me! :]

210

Step-by-step explanation:

225/50 = 4.5(5)

5x2=10

220-10=210

Answer:

96

Step-by-step explanation: 40 percent is 64 so just subtract that from 160

Expreion have a quotient of 6 is 0. 48 ÷ 0. 08.

What is quotient?

In mathematics, the quotient is the result of performing division operations on two integers. It is essentially the outcome of the division procedure. In arithmetic division, the terms divisor, dividend, quotient, and remainder are employed in four different ways.Division is one of the four basic operations of arithmetic, the ways that numbers are combined to make new numbers. The other operations are addition, subtraction, and multiplication.

0. 48 ÷ 0. 8

=0.06

The solution for Long Division of \($\frac{4.8}{8}$\) is 0.6

The solution for Long Division of \($\frac{0.48}{0.08}$\) is 6.

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y=14x+32

since she can only bake 14 pies per week and she already has 32 pies done

Answer:

you will have 88 pies for the competition and y=14x+32

Step-by-step explanation:

The relation R is not transitive because the statement ∀x∀y∀z.R(x, y) is not sufficient to establish transitivity. Transitivity requires that if R(x, y) and R(y, z) are true, then R(x, z) must also be true for all x, y, and z. However, the given statement only asserts the existence of a relation between x and y, without specifying any relationship between y and z. Therefore, we cannot conclude that R is transitive based on the given condition.

Transitivity is a property of relations that states if there is a relation between two elements and another relation between the second element and a third element, then there must be a relation between the first and third elements. In the case of relation A(x, y) defined in the question, A is true if and only if the sets x and y have the same size (denoted by |x| = |y|).

To check transitivity, we need to examine whether the given condition ∀x∀y∀z.R(x, y) implies transitivity. However, the statement ∀x∀y∀z.R(x, y) simply asserts the existence of a relation between any elements x and y, without specifying any relationship between y and z. In other words, it does not guarantee that if there is a relation between x and y, and a relation between y and z, there will be a relation between x and z.

To illustrate this, consider the following counterexample: Let x = {1, 2}, y = {3, 4}, and z = {5, 6}. Here, |x| = |y| and |y| = |z|, satisfying the condition of relation A. However, there is no relation between x and z since |x| ≠ |z|. Therefore, the given condition does not establish transitivity for relation A.

In conclusion, the relation A(x, y) defined in the question is not transitive based on the given condition. Additional conditions or constraints would be required to ensure transitivity.

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Answer:

f(-3)=3(-3²-5)+1

=3(9-5)+1

=3(4)+1

=12+1

=13

Answer:

f(-3) = -32 for f(x) = 3(2x - 5) + 1

f(-3) = 13 for f(x) = 3(x^2 - 5) + 1

Step-by-step explanation:

f(x) = 3 (2x - 5) + 1

f(-3) = 3 (2(-3) - 5) + 1

f(-3) = 3( -6 - 5 ) + 1

f(-3) = 3( -11 ) + 1

f(-3) = -33 + 1

f(-3) = -32

_________

f(x) = 3(x^2 - 5) + 1

f(-3) = 3((-3)^2 - 5) + 1

f(-3) = 3(9 - 5) + 1

f(-3) = 3(4) + 1

f(-3) = 12 + 1

f(-3) = 13

Part A: Student B's work does not provide a proper verification of the identity.

Part B: Neither Student A nor Student B properly verified the given identity.

Part A:

Upon reviewing Student A's work, it becomes evident that they did not verify the identity properly. Student A's work does not follow the logical steps required to prove the given identity. They seem to have made errors in manipulating the trigonometric functions, resulting in an incorrect conclusion. Therefore, Student A's verification is incorrect.

Part B:

Student A's work did not successfully prove the given identity, so we cannot identify any identities used in their verification. However, we can discuss two identities that could potentially be used to prove the given identity.

Reciprocal Identity:

One possible identity that could be used is the reciprocal identity of cotangent and cosecant:

cosec(x) = 1/sin(x)

cot(x) = 1/tan(x)

Pythagorean Identity:

Another relevant identity is the Pythagorean identity:

sin²(x) + cos²(x) = 1

These identities could be applied in the process of verifying the given identity (cot x)(cos x) = csc x − sin x. However, it is important to note that the exact steps and techniques used to prove the identity may vary depending on the approach taken.

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Given data:Width of flume (B) = 3 mDepth of flume (D) = 1.5 mChezy’s constant (C) = 0.013Slope of the bed (S) = 0.0025We know that,Q = (1/C) * A * R^(2/3) * S^(1/2)

Where,Q = Discharge of rectangular flumeA = Area of cross-sectionR = Hydraulic radiusS = Slope of the bedCalculation:Area of cross-section, A = B * D = 3 * 1.5 = 4.5 m²Wetted perimeter, P = B + 2 * D = 3 + 2 * 1.5 = 6 mHydraulic radius,

R = A / P = 4.5 / 6 = 0.75 mSubstituting the given values,Q = (1 / 0.013) * 4.5 * 0.75^(2/3) * 0.0025^(1/2)Q = 0.796 m³/sBoundary shear stress, τo = ρ * g * R * Sρ = Density of water = 1000 kg/m³g = Acceleration due to gravity = 9.81 m/s²Substituting the given values,τo = 1000 * 9.81 * 0.75 * 0.0025τo = 18.23 N/m²

The discharge of a rectangular flume 3 m wide and 1.5 m deep on a slope of 0.0025 is 0.796 m³/s and the boundary shear stress is 18.23 N/m².

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Answer:

l = 194999.45

Step-by-step explanation:

I'm going to assume that you meant 3.14 by 3,14.

336,765 = 3.14 × 0.55 × (l + 0.55)

336,765 ÷ (3.14 × 0.55) = l + 0.55

(336,765 ÷ (3.14 × 0.55)) - 0.55 = l

l = 194999.45

Federal fund loan denominations: $750,000, $3,000,000, $9,000,000, $12,000,000.

Properties of federal funds: Interbank loan volume < $100 billion, loan maturity of 1-7 days, enables lending/borrowing at the discount rate, most transactions are not for $5 million or more.

Typical federal fund loan denominations:

- $750,000 (not checked)

- $3,000,000 (not checked)

- $9,000,000 (not checked)

- $12,000,000 (not checked)

Properties of federal funds:

- The interbank loan volume outstanding is less than $100 billion. (checked)

- Most loan transactions have a maturity of 1 to 7 days. (checked)

- The federal funds market enables depository institutions to lend or borrow short-term funds from each other at the discount rate. (checked)

- Most loan transactions are for $5 million or more. (not checked)

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To determine the probability that a random sample of 400 U.S. adults will provide a sample proportion within 0.09 of the population proportion, we can use the concept of margin of error and the Central Limit Theorem.

The Central Limit Theorem states that the distribution of sample proportions approaches a normal distribution as the sample size increases, given that the sample size is sufficiently large (typically n ≥ 30). In this case, our sample size is 400, which is large enough.

To find the margin of error, we can use the formula: E = Z * sqrt(p * (1 - p) / n), where E is the margin of error, Z is the Z-score corresponding to the desired level of confidence, p is the population proportion, and n is the sample size.

In this problem, we are given the margin of error as 0.09. Unfortunately, we don't have enough information to determine the exact Z-score or the population proportion (p). However, we can still analyze the given answer choices: 99.968%, 0.032%, 16%, and 84%.

Considering that our margin of error is 0.09 and our sample size is sufficiently large, it's highly likely that the sample proportion will fall within this range. Thus, the correct answer should be the highest probability among the given choices, which is 99.968%.

In conclusion, the probability that a random sample of 400 U.S. adults will provide a sample proportion within 0.09 of the population proportion is approximately 99.968%.

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The probability that the mean of the sample would differ from the population mean by less than 43 points is approximately 0.7597 or 0.7600 (rounded to four decimal places).

Given that the standard deviation of the scores on a skill evaluation test is 320 points with a mean of 1434 points. And we have a sample of size n = 338.

We need to find the probability that the mean of the sample would differ from the population mean by less than 43 points.

The standard error of the mean is given by:

SE = σ/√n

where σ is the population standard deviation and n is the sample size.

Substituting the given values, we get:

SE = 320/√338

SE ≈ 17.398

To find the probability, we need to standardize the sample mean using the standard error as follows:

Z = (X - μ) / SE

where X is the sample mean, μ is the population mean, and SE is the standard error of the mean.

Substituting the given values, we get:

Z = (1434 - 1434) / 17.398

Z = 0

Since the mean difference is 0, we can find the probability of a difference less than 43 points by finding the probability that Z lies between -43/17.398 and 43/17.398.

Using a standard normal distribution table or calculator, we find that this probability is approximately 0.7597.

Therefore, the probability that the mean of the sample would differ from the population mean by less than 43 points is approximately 0.7597 or 0.7600 (rounded to four decimal places).

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Answer:

B

Step-by-step explanation:

rate of change and slope have the same meaning; to only know the slope of a line isn't enough, you need also at least one point or intercept

4.1715 cm is the tenth-value layer. So, none of the given options (7.61 cm, 2.78 cm, 3.89 cm, 9.21 cm) matches the calculated value of the tenth-value layer.

Here, we have,

To determine the tenth-value layer, we need to find the thickness of the absorber required to reduce the intensity of the beam to one-tenth (10%) of its original value.

Given that the thickness of the absorber is 1.5 cm and 36.45% of the beam is attenuated, we can set up the following equation:

(1 - 36.45%)ⁿ = 10%

Here, 'n' represents the number of layers of absorber required to reach the tenth-value layer. Since we're looking for the thickness of the tenth-value layer, we need to solve for 'n' in the equation.

Let's calculate 'n':

(1 - 0.3645)ⁿ = 0.1

0.6355ⁿ = 0.1

Taking the natural logarithm (ln) of both sides:

n * ln(0.6355) = ln(0.1)

n = ln(0.1) / ln(0.6355)

Using a calculator, we find that n ≈ 2.781

Now, we can determine the thickness of the tenth-value layer by multiplying 'n' by the thickness of each absorber layer:

Tenth-value layer thickness = n * 1.5 cm

Tenth-value layer thickness ≈ 2.781 * 1.5 cm

Calculating this, we find that the approximate thickness of the tenth-value layer is 4.1715 cm.

Therefore, none of the given options (7.61 cm, 2.78 cm, 3.89 cm, 9.21 cm) matches the calculated value of the tenth-value layer, which is approximately 4.1715 cm.

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One personal example of a measurement I use routinely is converting weight from pounds (U.S. customary units) to kilograms (metric units). Let's say I have a weight of 150 pounds and I want to convert it to kilograms.

Start with the given weight in pounds: 150 pounds.

To convert pounds to kilograms, we need to use the conversion factor 1 pound = 0.45359237 kilograms.

Multiply the given weight in pounds by the conversion factor:

150 pounds * 0.45359237 kilograms/pound = 68.0388555 kilograms.

Round the converted weight to an appropriate number of decimal places, if necessary. In this case, let's round it to two decimal places.

The final converted weight is approximately 68.04 kilograms.

So, the weight of 150 pounds is approximately 68.04 kilograms.

Note: It's important to use the correct conversion factor when converting between U.S. customary units and metric units.

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The Mean will decrease by 20% and the mode or median may or may not have any impact.

Each style of the candle will cost 20% less if the candle store is having a 20% off deal.

The mean, median, and mode cost per kind of candle will be impacted in the following ways assuming that each candle has a distinct price:

Mean: There will be a 20% decrease in the mean cost of each type of candle. This is so that a lower mean cost per kind of candle may be achieved. The mean is the sum of all prices divided by the total number of candles, thus if each price is decreased by 20%, the sum of prices will also be decreased by 20%.

Median: The sale may or may not have an impact on the median price for each type of candle. This is true because the median, which represents the middle value in a group of data, will not change if the order of the prices is not affected by the sale price.

The median, however, could change to a different number if the sale price results in a change in the ranking of the values.

Mode: The sale may or may not have an impact on the average price for each type of candle. This is true because the mode—the value that appears the most frequently in a set of data—remains same if the sale price does not alter the frequency of the prices.

The mode, however, can change to a different value if the selling price results in a change in the frequency of the prices.

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Answer:

A

Step-by-step explanation:

It's not listed.

By the way if you look up "Desmos Graphing Calculator" you can click on the website and put in equations and it'll graph it for you. That way you can see if the answer is right or not

To find the expected value (E(X)), variance (Var(X)), expected value of 4X-5 (E(4X-5)), and variance of 3X+2 (Var(3X+2)) for the given probability mass function p of the discrete random variable X', we can use the following formulas:

Expected Value (E(X)):

E(X) = Σ (X * p(X))

Variance (Var(X)):

Var(X) = Σ ((X - E(X))^2 * p(X))

Expected Value of 4X-5 (E(4X-5)):

E(4X-5) = 4 * E(X) - 5

Variance of 3X+2 (Var(3X+2)):

Var(3X+2) = 9 * Var(X)

Given the probability mass function p for X':

X' p(X')

-5 0.1

-4 0.3

1 0.25

3 0.2

6 0.15

Now let's calculate each value step by step:

Expected Value (E(X)):

E(X) = (-5 * 0.1) + (-4 * 0.3) + (1 * 0.25) + (3 * 0.2) + (6 * 0.15)

E(X) = -0.5 - 1.2 + 0.25 + 0.6 + 0.9

E(X) = 0.45

Variance (Var(X)):

Var(X) = ((-5 - 0.45)^2 * 0.1) + ((-4 - 0.45)^2 * 0.3) + ((1 - 0.45)^2 * 0.25) + ((3 - 0.45)^2 * 0.2) + ((6 - 0.45)^2 * 0.15)

Var(X) = 14.8025 * 0.1 + 9.2025 * 0.3 + 0.3025 * 0.25 + 2.9025 * 0.2 + 28.1025 * 0.15

Var(X) = 1.48025 + 2.76075 + 0.075625 + 0.5805 + 4.215375

Var(X) = 9.1125

Expected Value of 4X-5 (E(4X-5)):

E(4X-5) = 4 * E(X) - 5

E(4X-5) = 4 * 0.45 - 5

E(4X-5) = 1.8 - 5

E(4X-5) = -3.2

Variance of 3X+2 (Var(3X+2)):

Var(3X+2) = 9 * Var(X)

Var(3X+2) = 9 * 9.1125

Var(3X+2) = 82.0125

Therefore, we have found:

E(X) = 0.45

Var(X) = 9.1125

E(4X-5) = -3.2

Var(3X+2) = 82.0125

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Answer: 121°

Step-by-step explanation:

The measure of angle B will be \(121^0\) .

Angle is formed by two rays lie in the plane that contains the rays.

We have,

\(m \angle A =(6x-19)^0\)

Now,

Linear pair angles are those angles whose sum is \(180^0\) .

i.e.

\(m \angle A + m \angle B=180^0\)

So,

\((6x-19)^0 +(11x-22)^0 =180^0\)

Now,

\(17x-41=180\)

\(17x=221\)

\(x=13\)

So,

\(m\angle B=(11x-22)^0\)

Putting value of x;

\(m\angle B=(11*13-22)^0\)

\(m\angle B=(121)^0\)

So, measure of angle B is \(121^0\).

Hence, we can say that the measure of angle B will be \(121^0\) .

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The histograms typically are used to display continuous measures.

There are different types of charts: histogram, line chart, pie chart, and others.

The histogram is a type of chart used as a tool that provides a way to assess the distribution of data. From this type of chart, a set of data are previously tabulated and divided into classes. In the other words, the histogram is applied to summarize discrete or continuous measures, so it becomes more easily the understand the used data. There are many websites and software that allow the plot of this type of chart.

From the explanation, it is possible to identify the histograms typically are used to display continuous measures.

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To compute a basis of the eigen space corresponding to eigen value -2, we need to find the null space of the matrix A + 2I, where A is the 3x3 matrix and I is the identity matrix.

The null space will give us the basis vectors of the eigen space

To find the eigen space corresponding to the eigen value -2, we start by constructing the matrix A + 2I, where A is the given 3x3 matrix and I is the 3x3 identity matrix. Next, we solve the homogeneous system of linear equations (A + 2I)x = 0, where x is a vector. The solutions to this system form the null space of the matrix A + 2I.

By finding a basis for this null space, we can obtain the basis vectors of the eigen space corresponding to the eigen value -2.

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Answer:

x = 1, y = 3

Step-by-step explanation:

Given the 2 equations

y = 2x + 1 → (1)

y = - x + 4 → (2)

Substitute y = 2x + 1 into (2)

2x + 1 = - x + 4 ( add x to both sides )

3x + 1 = 4 ( subtract 1 from both sides )

3x = 3 ( divide both sides by 3 )

x = 1

Substitute x = 1 into (1) and evaluate for y

y = 2(1) + 1 = 2 + 1 = 3

Then solution is x = 1, y = 3

As of December 31, 20XX, the balance sheet shows that the ending balance of raw materials is $76,000, the ending balance of work-in-process inventory is $52,600, and the ending balance of finished goods is $52,600.

In order to solve this problem, we need to follow a few steps. The steps are as follows:

1. Calculate the raw material transferred to work in process by multiplying the raw material purchases with the percentage transferred to the work in process.

2. Calculate the cost of goods manufactured (COGM) by adding the costs of raw material transferred to the work in process, direct labor, and overhead, and then subtracting the total depreciation.

3. Calculate the cost of goods sold (COGS) by multiplying the cost of goods manufactured with the percentage of finished goods that is sold.

4. Calculate the ending balance of raw materials by subtracting the COGM from the sum of raw material purchases and the beginning balance of raw materials.

5. Calculate the ending balance of work-in-process inventory by subtracting the COGS from the COGM.

6. Calculate the ending balance of finished goods by subtracting the COGS from the sum of the beginning balance of finished goods and the cost of goods manufactured.

Now, let's use the above method to solve the given problem.

Balance sheet for raw material purchases, transferred to work in process, direct labor, overhead, total depreciation, inventory production, and SG&A are given.

- Raw material purchases: $100,000

- Percentage of raw material purchases transferred to work in process: 50%

- Direct labor: $200,000

- Overhead: $300,000

- Total depreciation: $30,000, of which 80% is for inventory production and 20% for SG&A

- Work in process completed: 70%

- Finished goods that is sold: 90%

As of December 31, 20XX, we need to calculate how much raw materials are left on the balance sheet, how much work-in-process inventory is left on the balance sheet, and how much finished goods are left on the balance sheet. The problem is solved below.

1. Calculate the raw material transferred to work in process:

  Raw material transferred to work in process = 50% of $100,000

  = 0.50 × $100,000

  = $50,000

2. Calculate the cost of goods manufactured (COGM):

  Raw material purchases transferred to work in process = $50,000

  Direct labor = $200,000

  Overhead = $300,000

  Total depreciation = $30,000, of which 80% is for inventory production and 20% for SG&A

  COGM = ($50,000 + $200,000 + $300,000) - (80% × $30,000)

       = $50,000 + $200,000 + $300,000 - $24,000

       = $526,000

3. Calculate the cost of goods sold (COGS):

  COGS = 90% × $526,000

       = 0.90 × $526,000

       = $473,400

4. Calculate the ending balance of raw materials:

  Beginning balance of raw materials = $0

  Raw material purchases = $100,000

  Raw material transferred to work in process = $50,000

  COGM = $526,000

  Ending balance of raw materials = ($100,000 + $0) - $526,000 + $50,000

                              = $76,000

5. Calculate the ending balance of work-in-process inventory:

  Beginning balance of work-in-process inventory = $0

  COGM = $526,000

  COGS = $473,400

  Ending balance of work-in-process inventory = $526,000 - $473,400 + $0

                                             = $52,600

6. Calculate the ending balance of finished goods:

  Beginning balance of finished goods = $0

  COGM = $526,000

  COGS = $473,400

  Ending balance of finished goods = ($0 + $526,000) - $473,400

                                  = $52,600

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