f(x, y) = x2 i xy j x2 y2 = 4 (a) find the work done by the force field on a particle that moves once around the circle oriented in the clockwise direction.

Answers

Answer 1

The work done by the force field on a particle moving around a circle in a clockwise direction can be found by parametrizing the curve of the circle and evaluating the line integral of the force field along the curve.

The curve is given as

x² + y² = 4,

which is the equation for a circle of radius 2 centered at the origin. A parameterization for this curve can be found by letting x = 2cos(t) and y = 2sin(t), where t is the parameter that ranges from 0 to 2π as the particle moves around the circle once in a clockwise direction.

Using the parameterization, we can calculate the work done by the force field

F(x,y) = x² i + xy j

along the circle using the line integral:

∫(C) F(x,y) · dr = ∫(0 to 2π) F(2cos(t), 2sin(t)) · (-2sin(t) i + 2cos(t) j) dt

= ∫(0 to 2π) [4cos²(t) (-2sin(t)) + 4cos(t)sin(t) (2cos(t))] dt

= ∫(0 to 2π) [-8cos²(t)sin(t) + 8cos(t)sin(t)cos(t)] dt

= ∫(0 to 2π) [-4sin(t)cos²(t) + 4cos(t)sin(t)cos(t)] dt

= ∫(0 to 2π) [2sin(2t)cos(t)] dt

= [sin²(t)](from 0 to 2π) = 0

Therefore, the work done by the force field on a particle that moves once around the circle oriented in the clockwise direction is 0.

The work done by the force field on a particle that moves once around the circle oriented in the clockwise direction is 0.

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Related Questions

"Please include all relevant working out as detailed as possible
and all relevant diagram to find the answer. Much appreciated! I
will upvote! Thank you so much"
Find total response of the system (transient+steady state). Do not solve for coefficients. Determine the frequency of applied force at which resonance will occur? M = 20 kg F, = 90 N Given: -6 rad/s M

Answers

Given the following information:Mass of the system, m = 20 kg.Damping coefficient, b = 6 Ns/m.Force, F = 90 N.Frequency of applied force, f = ?Applied force angular frequency, w = 6 rad/s.Forced vibration equation:F(t) = F0 sin(wt)where F0 = 90 N and w = 6 rad/s.Under the action of the force F, the mass m will oscillate.The equation of motion for the mass-spring-damper system is given by:$$\mathrm{m\frac{d^{2}x}{dt^{2}}} + \mathrm{b\frac{dx}{dt}} + \mathrm{kx = F_{0}sin(\omega t)}$$where k is the spring constant.x(0) = 0 and x'(0) = 0.As we have the damping coefficient (b), we can calculate the damping ratio (ζ) and natural frequency (ωn) of the system.Damping ratio:$$\mathrm{\zeta = \frac{b}{2\sqrt{km}}}$$where k is the spring constant and m is the mass of the system.Natural frequency:$$\mathrm{\omega_{n} = \sqrt{\frac{k}{m}}}$$where k is the spring constant and m is the mass of the system.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$At resonance, the amplitude of the system will be maximum when forced by a sinusoidal force of frequency equal to the resonant frequency.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$$$\mathrm{\omega_{d} = \sqrt{(6.57)^{2}-(-2.88)^{2}} = 6.98 rad/s}$$Hence, the frequency of applied force at which resonance will occur is 6.98 rad/s.

The frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.

To determine the frequency of the applied force at which resonance will occur, resonance happens when the frequency of the applied force matches the natural frequency of the system. The natural frequency can be determined using the formula:

ωn = √(K / M),

where ωn is the natural frequency, K is the spring constant, and M is the mass of the system.

Substituting the given values of K = 400 N/m and M = 20 kg into the equation, we can calculate the natural frequency ωn.

ωn = √(400 N/m / 20 kg) = √(20 rad/s²) = 2√5 rad/s.

Therefore, the frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.

The correct question is given as,

M= 20kg

Fo = 90 N

ω = 6 rad/s

K = 400 N/m

C = 125 Ns/m

Determine the frequency of applied force at which resonance will occur?

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when driving at 55 mph how many feet do you need to stop

Answers

The distance required to stop a vehicle depends on various factors, including reaction time, road conditions, vehicle weight, and braking efficiency. However, a commonly used estimate for the average stopping distance of a vehicle traveling at 55 mph is around 240 feet.

To calculate this estimate, we consider the total stopping distance, which comprises two components: the thinking distance and the braking distance. The thinking distance is the distance traveled during the driver's reaction time, typically assumed to be around 1.5 seconds. During this time, the vehicle continues to move at its initial speed. The braking distance is the distance traveled from the moment the brakes are applied until the vehicle comes to a complete stop.

While the average stopping distance at 55 mph is estimated to be around 240 feet, it is important to note that actual stopping distances can vary based on the factors mentioned earlier. It is always crucial to maintain a safe following distance and be aware of road conditions to ensure a proper stopping distance.

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a metal block measures 10cm×2cm×2cm. What is its volume? How many blocks each 2cm×2cm×2cm have the same total volume?

Answers

40cm³ is  volume of a metal block measures 10cm×2cm×2cm and 5 blocks have the same total volume.

volume=l×b×h

volume=10cm×2cm×2cm= 40cm³

volume=l×b×h

volume= 2cm×2cm×2cm=8cm³

blocks have the same total volume= 40cm³/8cm³= 5

The space occupied inside an object's borders in three dimensions is referred to as its volume. It is sometimes referred to as the object's capacity. Finding an object's volume can help us calculate the quantity needed to fill it, such as the volume of water needed to fill a bottle, aquarium, or water tank.

A sphere is the most basic and typical form of a three-dimensional shape. We see spheres on a regular basis in the form of balls, globes, ornamental lights, oranges, etc.

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If a car starting from rest accelerates at 1 m/s2 for 2 minutes, how far will the car have traveled in kilometers?

Answers

Answer:

60 m/s

Explanation:

acceleration: 1/2 m/s2

time: 2 minutes

there are 60 seconds in one minute so

60sec x 2 min = 120 sec

1/2 in decimal form is 0.5 so 0.5 x 120sec= 60m/s

How much electrical energy is used by a 75 W laptop that is operating for 12
minutes?
O A. 27,000 J
B. 108,000 J
C. 900 J
O D. 54,000 J

Answers

Answer:

54,000 J

Explanation:

Given,

Power ( P ) = 75 W

Time ( t ) = 12 minutes

To find : Electrical energy ( E ) = ?

t = 12 minutes

= 12 x 60

t = 720 seconds

Formula : -

E = Pt

E = 75 x 720

E = 54,000 J

Therefore,

54,000 J is the electrical energy is used by a 75 W laptop that is operating for 12 minutes.

Sunspots are dark areas on the surface of the Sun. They mark strong magnetic fields, and more sunspots indicate that the Sun is more active and is releasing more energy. The following graph presents the average daily number of sunspots from 1900 through 1944. Each data point is the average for one month.
Notice the series of peaks and troughs in the graph. The time from one minimum (trough) to the next is called a Solar Cycle. Solar Cycles can be anywhere from 9 to 14 years long.

What can be predicted with the most certainty from this graph?
A.
The next minimum in the graph will be in 1953.
B.
The average daily number of sunspots will peak in 1949.
C.
The average daily number of sunspots in 1949 will be 80.
D.
The average daily number of sunspots will increase throughout 1945.

Answers

Answer:

D

Explanation:

study island. first answer is wrong

The average daily number of sunspots will increase throughout 1945. therefore the correct answer is option D.

What is a solar system?

It is a system in which the sun's gravitational attraction causes all the planets and celestial bodies to revolve around it.

As specified in the issue statement On the surface of the Sun are spots known as sunspots. Increased sunspots imply that the Sun is more active and is producing more energy since they are a sign of strong magnetic fields.

The average daily number of sunspots from 1900 to 1944 is shown in the graph below. The average for each data point is for one month.

The graph's sequence of peaks and valleys should be noted. A solar cycle is the period of time from one minimum (trough) to the next. Solar cycles can last from nine to fourteen years.

Thus, The average daily number of sunspots will increase throughout 1945, therefore the correct answer is option D.

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part a. A 10 Kg object is pulled by a force of 60 N at an angle of 30°. As it moves on, it is resisted by a force of friction of 2 N, as shown by the diagram below. Determine the normal force F normal
part b. A 10 Kg object is pulled by a force of 60 N at an angle of 30°. As it moves on, it is resisted by a force of friction of 2 N, as shown by the diagram below. determine the acceleration.

part a. A 10 Kg object is pulled by a force of 60 N at an angle of 30. As it moves on, it is resisted

Answers

Answer:

What cell organelle makes turgor pressure in a plant cell

possible? Describe the role of this organelle in this process.

Explanation:

pls help dude

(D) âv = at where a = F/m. So we have âv = 10^-14 à 10^-9 ÷ 10^-30 = 10^(-14 + -9 - (-30))
The speed of the electron after it has accelerated for the 10-9 second is most nearly
(A) 10^1 m/s (B) 10^3 m/s (C) 10^5 m/s (D) 10^7 m/s (E) 10^9 m/s

Answers

The speed of the electron, after it has accelerated for 10^-9 seconds, is 10^5 m/s. The correct option is C.

Acceleration is the rate at which an object changes its velocity with respect to time. It is a vector quantity, which means it has both magnitude and direction. Mathematically, acceleration is defined as the change in velocity divided by the time taken for that change to occur.

Given:

Acceleration of the electron, a = F/m = 10^-14 N / 9.1 x 10^-31 kg = 1.0989 x 10^17 m/s^2

Time for which electron is accelerated, t = 10^-9 s

Using the equation, âv = at, where âv is the change in velocity, we get:

âv = at = 1.0989 x 10^17 m/s^2 x 10^-9 s = 1.0989 x 10^8 m/s

Therefore, the speed of the electron after it has accelerated for the 10^-9 second is approximately 10^8 m/s, which is closest to option (C) 10^5 m/s.

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PLEASE HELP ASAP! WILL GIVE BRANLIEST! Pay attention to what happens to the things around you as you go about your day. Describe three examples of Newton’s third law in action. In your examples describe the action and the equal and opposite reaction.

Answers

Answer:

jumping, pulling a elastic band, bouncing a ball

Explanation:

when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air.

When we pull an elastic band, it automatically returns to its original position. The more you pull the more force it generates. This is the same when you pull or compress a spring. The action (applied force) is stored as energy and is released as a reaction with an equal and opposite force

A ball is able to bounce because of the reaction from the ground. If there was no reaction then the ball would not bounce but rather stick to the ground.

Why would you wanna know a cure for all sickness.?

Answers

Answer:

because if someone close to u gets sick you would know how to cure it

Atomic particles are often characterized by their kinetic energy in m ev. what is the speed of an 8.7 m ev proton?

Answers

The speed of an 8.7m ev proton is v = 4.1 x 107 m/s.

What is kinetic energy?

Kinetic energy is defined as the energy that is produced by an object due to its motion. When an object is set to acceleration, there is a definite need to apply certain forces. The application of force needs work, and after the work is done, the energy gets transferred to the object making it move at a constant velocity.

Kinetic energy is directly proportional to the mass of the object and to the square of its velocity:

  k = 1/2 mv2

  m = 1.7 x 10-27 Kg

  v = √2k/m

  v = √(2x8.7x106x16x10-19 )/1.7x10-27

  v = 4.1 x 107 m/s

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At a certain distance from a point charge, the potential and electric-field magnitude due to that charge is 4.98 V and 12.0 V/m, respectively. (Take the potential to be zero at infinity.)
a) What is the distance to the point charge?
b) What is the magnitude of the charge?
c) Is the electric field directed toward or away from the point charge?

Answers

It is decided that there is no potential at infinity. V for a point charge, on the other hand, drops with distance, but E for a point charge, on the other hand, decreases with distance squared: E= Fq = kQr2.

How does the electric field change when the charge intensity rises?

Electric field strength is measured by its magnitude. For instance, if the electric field of a charge Q is of magnitude E, then the electric field of a charge 2*Q would be of magnitude 2*E. The size of the electric field grows together with the amount or quantity of the electric charge.

The vector numbers electric force and electric field (they have magnitude and direction). An excellent simplification, electric potential turns out to be a scalar variable (magnitude alone).

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According to Coulomb's law, the point charge is 0.307 meters away, and its magnitude is \(Q = 1.7 \times 10^{-10}C\).

(c) the point charge is kept distant from the electric field.

Coulomb's Law:

Let us consider the point charge Q, the electric field (E) and potential difference (V) due to this charge at a distance r is given by:

\(E=k \frac{Q}{r^2}\)and

\(V = k \frac{Q}{r}\)

where k is Coulomb's constant

E = \(\frac{v}{r}\)

\(r = \frac{v}{E}\)

(a) from the data provided in the question

r = \(\frac{4.98}{ 16.2}\) m

r = 0.307 m

(b) now the charge can ve calculated as follows:

\(V = k \frac{Q}{r}\)

Q= V r / k

\(Q = 1.7 \times 10^{-10}C\)

(c) Since the charge is positive the electric field is directed away from the point charge, the electric field is directed away from the point charge

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What value of resistor R gives the circuit in the figure a time constant of 22 μs ?

Answers

The value of resistor R that gives the circuit in the figure a time constant of 22 μs is 220 Ω.

The circuit that is in the figure is shown below:Given that time constant (RC) = 22 μs. To find the value of resistor R, we need to use the formula for the time constant:

RC = τ, where R is the resistance and C is the capacitance of the circuit.

Rearranging the above formula, we get:R = τ / C

Where τ is the time constant and C is the capacitance of the circuit.

From the figure, the capacitance is given as 0.1 μF

.Substituting the values of τ and C in the above formula, we get:

R = (22 × 10⁻⁶ s) / (0.1 × 10⁻⁶ F)

R = 220 Ω

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In typical game play situation, (with no overtime), when is a game over?
A. When both teams score
B. When there is a tie
C. When the time runs out
D. When the referee decides the game is over

Answers

C) When the time runs out (usually in sports such as soccer, but i don’t know what sport you’re referring to)

Answer:

C

Explanation:

Got it right on the test :)

Please mark brainliest!! <3

In typical game play situation, (with no overtime), when is a game over?A. When both teams scoreB. When

How do stairs reduce the
amount of effort needed to
get work done?
A. They require a large force over a long
distance.
B. They require a small force over a long
distance.
C. They require a large force over a short
time.

Answers

It’s B. Require a small force over a long distance

A student is investigating inertia and acceleration. The data the student collects is shown in the table.
Force (N) Mass (kg) Acceleration (m/s²)
10
10
20
20
1
2
1
2
b
Oc
Od
Assuming the force acting on the objects is constant, which claim about inertia and acceleration is supported by the data?
0.1
0.2
Next Page
0.05
0.1
An object with a lower mass has less inertia which causes it to speed up less quickly.
An object with a higher mass has more inertia which causes it to speed up less quickly.
An object with a higher mass has less inertia which causes it to speed up more quickly.
An object with a lower mass has more inertia which causes it to speed up more quickly.
Back

A student is investigating inertia and acceleration. The data the student collects is shown in the table.Force

Answers

Assuming the force acting on the objects is constant, a claim about inertia and acceleration which is supported by the data include the following: B. An object with a higher mass has more inertia which causes it to speed up less quickly.

What is Newton's First Law (Inertia)?

Newton's First Law of Motion is also referred to as Law of Inertia and it states that an object in motion would continue in its state of motion at continuous velocity (same speed and direction) or if at rest, it will remain at rest unless it is acted upon by an external force.

This ultimately implies that, the amount of net force keeping a physical object moving at a constant speed and in a specific direction is always equal to zero (0) newton in accordance with Newton's First Law of Motion.

In this context, we can reasonably infer and logically deduce that a physical object that has a higher mass would have more inertia, which causes it to either experience a slower motion or speed up less quickly.

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Answer: its c

Explanation: i took the test


A rock thrown to the right with an initial horizontal velocity of 4 m/s lands after 5
seconds. What horizontal distance has the rock traveled?

Answers

Answer:

20m

Explanation:

Using the equation s=d/t and re arranging it to solve for distance, d=St, where d=distance, s=speed, ant t=time, we can plug in known variables.

d=4*5

d=20m

there is a distance of 20m traveled

The horizontal distance traveled by the rock is 20 m

For horizontal motion, we use the formula below

⇒ Formula

s = vt.................... equation 1

⇒ Where

S = horizontal distance traveled by the rockv = velocity of the rockt = time

From the question,

⇒ Given:

v = 4 m/st = 5 seconds

⇒ Substitute these values into equation 1

s = 4×5s = 20 m

Hence, The horizontal distance traveled by the rock is 20 m

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5. The temperature of air in a foundry increases when molten metals cool and solidify. Suppose 4.5 x 10^7 J energy is added to the surrounding air by the solidifying metal. The air's temperature increases by 55°C and the air has a specific heat capacity of 1.0 × 10 J/kg °C. What is the mass of the heated air?

Answers

The mass of the heated air is 2475000 kg.

What is specific heat capacity?

The heat capacity of a sample of a substance is equal to the mass of the sample divided by the specific heat capacity of the substance (symbol c) in thermodynamics.

Informally, it is the quantity of heat that must be added to one unit of a substance's mass in order to raise its temperature by one unit.

The specific heat capacity of air =  1.0 × 10³ J/kg °C.

Hence, the mass of the heated air is =

( 4.5 x 10⁷ × 55) ÷ ( 1.0 × 10³ ) kg

= 2475000 kg.

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How does the flux of light from an isotropic source depend on the distance r from the source?
A. r 2
B. r -2
C. r -1
D. r 1
E. r 1/2
F. none of the above

Answers

The flux of light from an isotropic source depend on the distance r from the source by  r-2.

What is isotropic source?

An isotropic source is a source of radiation or sound that emits energy in all directions equally. This type of source is usually assumed to have uniform power density in all directions, making it a simplifying assumption when analyzing a system. Examples include a point source in free space, such as a light bulb, or a sound source in a room.

The flux of light from an isotropic source (a source that radiates uniformly in all directions) decreases as the inverse square of the distance from the source. This means that the flux of light from the source decreases according to the equation F = 1/r2, where F is the flux of light, and r is the distance from the source. Therefore, the flux of light from an isotropic source decreases with the distance r from the source according to the equation F = r-2.

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A stiff wire 41.0 cm long is bent at a right angle in the middle. One section lies along the z axis and the other is along the line y = 2x in the xy plane. A current of 23.5 A flows in the wire-down the z axis and out the line in the xy plane. The wire passes through a uniform magnetic field given by B = (0.318i) T. Determine the magnitude and direction of the total force on the wire.

Answers

The magnitude of the total force on the wire is 0.968 N and it is directed along the negative y axis.

What is force?

A force is a pull or push upon an object resulting from the object's interaction with another object. Forces can cause an object to change its motion or velocity.

In this case, the wire is experiencing a magnetic force due to the current in the wire and a magnetic field acting on it. To calculate the magnitude and direction of the total force on the wire, we can use the right-hand rule for magnetic forces. According to this rule, if the thumb of the right hand points in the direction of the current, and the fingers point in the direction of the magnetic field, then the palm will point in the direction of the force.

Let's begin by determining the magnitude of the magnetic force on each section of the wire.

Magnetic force on the section of the wire that lies along the z-axis:

Magnetic force on the section of the wire that lies along the line y = 2x in the xy plane:

Now, we need to calculate the total force on the wire by adding up the forces on each section of the wire. Since the forces are at right angles to each other, we can use the Pythagorean theorem to find the magnitude of the total force.

Ftotal² = Fz² + Fy²Ftotal² = (0.288 N)² + (0.792 N)²F

total = 0.849 N

Now, we need to find the direction of the total force. According to the right-hand rule for magnetic forces, the force on the section of the wire that lies along the line y = 2x in the xy plane is directed along the negative y-axis. Therefore, the total force on the wire is also directed along the negative y-axis.

Thus, the magnitude of the total force on the wire is 0.849 N, and it is directed along the negative y-axis.

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what will you do to determine the right quantity of the materials needed​

Answers

Answer:

Analyse the material required to build the instrument gauge and then keep a buffer stock of 1%

Explanation:

The right quantity to buy differs for every material. There are some materials which are very expensive and are very less used than buffer stock for such materials cannot be purchased. Usually the buffer is to be on the safe side from the shortage of the material. The buffer stock kept is around 1 to 2% for metal materials.

Calculate the gravitational potential energy of a 9.2 kg mass on the surface of the Earth.

Answers

The gravitational potential energy of a 9.2 kg mass on the surface of the Earth is equal to zero.

What is gravitational potential energy?

Gravitational potential energy can be defined as the energy exhibited by an object because of a change in its position in a gravitational field.

The gravitational potential energy of two interacting masses is given by

\(U=-G\frac{mM}{R}\)

where m & M are the masses, R is the distance between the masses, and G is the gravitational constant.

The gravitational potential energy of a body at height h can be given by:

\(U = mgh,\)            where m is the mass of the object.

Given, the mass of the object, m= 9.2 Kg

The height from the surface = 0

The gravitational potential energy, U = mgh = 0

Therefore,  the gravitational potential energy of a mass on the surface of the Earth is zero.

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a proton and an electron are released from rest at the midpoint between the plates of a charged parallel plate capacitor. except for these particles, nothing else is between the plates. ignore the attraction between the proton and the electron, and decide which particle strikes a capacitor plate first. why?

Answers

There are no other particles between the plates besides these ones. Choose which particle impacts a capacitor plate first, disregarding the electron's attraction to the proton. At the plate first is the electron.

An electron is a negatively charged subatomic particle that can exist either free or bound to an atom. An atom has three main types of particles: protons, neutrons, and the electron that is attached to them.

An electron's negative charge is balanced out by the positive charge of a proton. When an atom has an equal number of protons and electrons, it is considered to be neutral. The electron differs from the other particles in a number of ways. They are much less massive, exist outside of the nucleus, and exhibit both wave- and particle-like characteristics. Since an electron is a fundamental particle

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Watt-hours is a measure of energy, just like kilowatt-hours. how can you convert this to joules? (hint: break this down into basic units and determine the required conversion factors.)

Answers

Watt-hours and kilowatt-hours are both measures of energy. To convert watt-hours to joules, we need to break down the units and use the appropriate conversion factors.

1 watt-hour is equal to 3600 joules. This conversion factor comes from the fact that power is equal to energy divided by time, and 1 watt is equal to 1 joule per second. Since there are 3600 seconds in an hour, we multiply the power in watts by the number of seconds in an hour to get the energy in joules.

To convert kilowatt-hours to joules, we first convert kilowatts to watts. 1 kilowatt is equal to 1000 watts. Then, we multiply the power in watts by the number of seconds in an hour (3600 seconds) to get the energy in joules.

Here are the conversion steps:

1. For watt-hours to joules:
  - Multiply the watt-hours by 3600 to get the energy in joules.

2. For kilowatt-hours to joules:
  - Multiply the kilowatt-hours by 1000 to convert to watts.
  - Multiply the result by 3600 to get the energy in joules.

Remember to always label your final answer with the correct units.

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what is the relationship between harmonics and resonance frequency in a piano

Answers

Fundamental and Harmonics
Most vibrating objects have more than one resonant frequency and those used in musical instruments typically vibrate at harmonics of the fundamental. A harmonic is defined as an integer (whole number) multiple of the fundamental frequency.

There is direct relationship between harmonics and resonance frequency.

A harmonic is a wave with a frequency that is a positive integer multiple of the frequency of the original wave whereas, resonance frequency is the frequency at which the oscillation reaches to its maximum point. The lowest resonant frequency is known as the fundamental, while on the other hand, the higher resonant frequencies are called overtones. All resonant frequencies are multiples of the fundamental, and are called harmonics. So we can conclude that there is a direct relationship between harmonics and resonance frequency.

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On that same 30. °C day, you blow the same whistle with a frequency of
3.5x10^4 Hz. What is the wavelength of the sound?

Answers

The sound would have a wavelength of about  9.8 * 10^-3 m.

What is the wavelength?

The wavelength is a characteristic of a wave that describes the distance between two successive points in the wave that are in phase, or the distance over which the wave's shape repeats. It is typically denoted by the Greek letter lambda (λ) and is measured in meters (m) or other units of length.

Given that the speed of sound in air is 343 m/s

v= λf

λ = v/f

λ =  343 m/s/3.5x10^4 Hz

λ =  9.8 * 10^-3 m

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The rate of change of momentum?

Answers

Answer:

Answer in below and plz mark me as brainlist plz

Explanation:

The rate of change of momentum =tm(v−u) Rate of change of momentum = force applied. Force∝tm(v−u) Velocity is the rate of change of displacement and acceleration is the rate of change of velocity. Impulse is a change in momentum

The rate of change of momentum =tm(v−u) Rate of change of momentum = force applied. Force∝tm(v−u) Velocity is the rate of change of displacement and acceleration is the rate of change of velocity. Impulse is a change in momentum

A 2 kg watermelon is dropped from a roof and has a speed of 5 m/s just before it hits the ground. How much kinetic energy does the watermelon have at this moment?

Answers

Answer:

25J

Explanation:

Given parameters:

Mass of the watermelon  = 2kg

Speed before touching the ground  = 5m/s

Unknown:

Kinetic energy  = ?

Solution:

To solve this problem, we must understand that kinetic energy is the energy possessed by a body in motion.

    K.E  = \(\frac{1}{2}\)  m v²

m is the mass

v is the velocity

Now, insert the parameters and solve;

      K.E  =  \(\frac{1}{2}\)  x 2  x  5² = 25J

Emilio pushes a 100 kg freshman with 200 N of force. How much is the freshman accelerated?

Answers

Explanation:

F = MA

200 = 100 * A

A = 200/100

A = 2m/sec^2

hope it helps you

a 62.3 kg base runner begins his slide into second base while moving at a speed of 4.05 m/s. he slides so that his speed is zero just as he reaches the base. the acceleration of gravity is 9.8 m/s 2 . what is the magnitude of the mechanical energy lost due to friction acting on the runner? answer in units of j.

Answers

The magnitude of the mechanical energy lost due to friction acting on the runner is:  528.7 J

The mechanical energy lost due to friction acting on the runner can be calculated using the work-energy principle, which states that the net work done on an object is equal to its change in kinetic energy:

W_net = ΔK

where W_net is the net work done on the object, and ΔK is the change in its kinetic energy.

At the start of the slide, the runner has a kinetic energy of:

K₁ = (1/2)mv² = (1/2)(62.3 kg)(4.05 m/s)² = 528.7 J

At the end of the slide, the runner has a kinetic energy of zero.

Therefore, the change in kinetic energy of the runner is:

ΔK = K_final - K_initial = 0 - 528.7 J = -528.7 J

Since the runner comes to rest due to the force of friction acting on him, the net work done on him is negative. Thus, the magnitude of the mechanical energy lost is:

|W_friction| = |W_net| = |-528.7 J| = 528.7 J

Learn more about mechanical energy here:

https://brainly.com/question/24443465

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