. find the electric flux through the surface of a rectangular gaussian surface with a charge of 3.1 c. placed at it'scenter. the ends of the box are squares whose sides are 4.0 cm. the length is 8.0 cm.

Answers

Answer 1

The electric flux through the surface of the rectangular Gaussian surface is 3.05 x 10^6 N m^2 / C.

What is the electric flux through the surface?

To find the electric flux through the surface of the rectangular Gaussian surface, we need to use Gauss's law:

Ф(E) = E * A * cos(θ)

where;

Ф(E) is the electric flux through the surface, E is the electric field, A is the area of the surface, and θ is the angle between the electric field and the surface normal.

In this case, the charge is located at the center of the rectangular Gaussian surface, and the ends of the box are squares with sides of 4.0 cm. The length of the box is 8.0 cm.

To apply Gauss's law, we need to choose a closed surface that encloses the charge. Since the charge is at the center of the rectangular box, we can choose the box itself as the closed surface.

The area of the rectangular box is:

A = 2 * (4.0 cm)^2 + 2 * (8.0 cm) * (4.0 cm) = 96.0 cm^2

The electric field at any point on the surface of the box will be radial, pointing directly outward from the charge.

Thus, the angle between the electric field and the surface normal is 0 degrees, and cos(θ) = 1.

Using Coulomb's law, the electric field due to a point charge q at a distance r is given by:

E = k * q / r^2

where;

k is Coulomb's constant (8.99 x 10^9 N m^2 / C^2).

In this case, the distance between the charge and any point on the surface of the box is the same, and is given by:

r = √[(4.0 cm / 2)^2 + (8.0 cm / 2)^2 + (4.0 cm / 2)^2]

r = 5.6569 cm

Thus, the electric field due to the charge at any point on the surface of the box is:

E = (8.99 x 10^9 N m^2 / C^2) * (3.1 x 10^-6 C) / (5.6569 cm)^2

E  = 3.18 x 10^4 N/C

Therefore, the electric flux through the surface of the rectangular Gaussian surface is:

Ф(E) = E * A * cos(θ)

Ф(E) = (3.18 x 10^4 N/C) * (96.0 cm^2) * 1

Ф(E) = 3.05 x 10^6 N m^2 / C

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Related Questions

angle of reflection

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The angle of reflection equals the angle of Incidence

Explanation:

The Law Of Reflection

trình bày những hiểu biết cơ bản về năng lượng

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Answer:

I don't understand your language

Please help with this question

Please help with this question

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Answer:

I believe the answer is 5718.75. Respond if it is wrong please.

Explanation:

I used a calculator.

simple but not plagiarized answer for "what is forces and motion?"​

Answers

FORCE-physical power or strength possessed by a living being:
He used all his force in opening the window.

MOTION-the action or process of moving or of changing place or position; movement.

An OP AMP has CMRR = 100 dB and open-loop gain =250000.

Determine the common mode gain ACM

Answers

Answer:

ACM = 2.5

Explanation:

The common mode rejection ratio, is a parameter that is used to measure the ability of an Operational-Amplifier, to reject or eliminate the noises of same polarity. The common mode rejection ratio is given by the following formula:

CMMR = AV/ACM

for the value of CMMR in deciBels (dB), the formula becomes:

CMMR = 20 log(AV/ACM)

where,

CMMR = Common Mode Rejection Ratio = 100 dB

AV = Open Loop Gain = 250000

ACM = Common Mode Gain = ?

Therefore,

100  = 20 log (250000/ACM)

100/20 = log (250000/ACM)

10⁵ = 250000/ACM

ACM = 250000/10⁵

ACM = 2.5

If the same force is applied to each of these balls, which one will have the LEAST
acceleration
A
m 1.0 kg
B
m=7.3 kg 1
С
m=0.75 kg
D
m=0.5 kg

Answers

Answer:

d is the awnser

Explanation:

MABY?!??

3. Consider the motion of the object whose velocity-time graph is given
in the diagram. What is the net displacement of the object between times
t = 0 and t = 2?
Velocity-time graph
8
(m/s)
8
12 16
16 m
2 m
8 m
56 m

3. Consider the motion of the object whose velocity-time graph is givenin the diagram. What is the net

Answers

Answer:

16 m.

Explanation:

From the question given above, we obtained the following data:

Initial velocity (u) = 0 m/s

Final velocity (v) = 8 m/s

Initial time (t1) = 0 sec

Final time (t2) = 2 secs

Net Displacement (ΔD) =?

Velocity is defined as the rate of change of the displacement of an object with time. Mathematically, it is expressed as:

Change in velocity (Δv) = change in displacement (ΔD) / change in time (Δt)

Δv = ΔD / Δt

Next we shall determine the change in velocity and time. This is illustrated below below:

Initial velocity (u) = 0 m/s

Final velocity (v) = 8 m/s

Change in velocity (Δv) =?

Change in velocity (Δv) = v – u

Change in velocity (Δv) = 8 – 0

Change in velocity (Δv) = 8 m/s

Initial time (t1) = 0 sec

Final time (t2) = 2 secs

change in time (Δt) =?

change in time (Δt) = t2 – t1

change in time (Δt) = 2 – 0

change in time (Δt) = 2 secs.

Finally, we shall determine the net displacement of the object as follow:

Change in velocity (Δv) = 8 m/s

change in time (Δt) = 2 secs.

Net Displacement (ΔD) =?

Δv = ΔD / Δt

8 = ΔD/2

Cross multiply

ΔD = 8 × 2

ΔD = 16 m

Therefore, the net displacement of the object is 16 m.

how much work is done when a mass of 3kg (weighing 30N) is lifted vertically through 6m?​

Answers

Answer:

180 J is the answer to how much work is done when a mass of 3kg is lifted vertically through 6 m

To calculate the amount of work done when a mass is lifted vertically through a certain distance, we can use the formula:

Work = Force * Distance

In this case, the mass is 3kg, which weighs 30N, and it is lifted vertically through a distance of 6m. Plugging these values into the formula, we get:

Work = 30N * 6m

= 180 Joules

Therefore, the amount of work done when the mass is lifted vertically through 6m is 180 Joules.

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A ray in glass is incident onto a water-glass interface. The angle of incidence equals 0.75 times the critical angle for that interface. The index of refraction for water is 1.33 and for glass is 1.78. What is the angle that the refracted ray in the water makes with the normal?
52 degrees
42 degrees
48 degrees
63 degrees

Answers

42 is the right oneeee!!!!!!!

g initial angular velocity of 39.1 rad/s. It starts to slow down uniformly and comes to rest, making 76.8 revolutions during the process. a) What is its angular acceleration (in rad/s2 )

Answers

Answer:

Approximately \(-1.58\; \rm rad \cdot s^{-2}\).

Explanation:

This question suggests that the rotation of this object slows down "uniformly". Therefore, the angular acceleration of this object should be constant and smaller than zero.

This question does not provide any information about the time required for the rotation of this object to come to a stop. In linear motions with a constant acceleration, there's an SUVAT equation that does not involve time:

\(v^2 - u^2 = 2\, a\, x\),

where

\(v\) is the final velocity of the moving object, \(u\) is the initial velocity of the moving object,\(a\) is the (linear) acceleration of the moving object, and\(x\) is the (linear) displacement of the object while its velocity changed from \(u\) to \(v\).

The angular analogue of that equation will be:

\((\omega(\text{final}))^2 - (\omega(\text{initial}))^2 = 2\, \alpha\, \theta\), where

\(\omega(\text{final})\) and \(\omega(\text{initial})\) are the initial and final angular velocity of the rotating object,\(\alpha\) is the angular acceleration of the moving object, and\(\theta\) is the angular displacement of the object while its angular velocity changed from \(\omega(\text{initial})\) to \(\omega(\text{final})\).

For this object:

\(\omega(\text{final}) = 0\; \rm rad\cdot s^{-1}\), whereas\(\omega(\text{initial}) = 39.1\; \rm rad\cdot s^{-1}\).

The question is asking for an angular acceleration with the unit \(\rm rad \cdot s^{-1}\). However, the angular displacement from the question is described with the number of revolutions. Convert that to radians:

\(\begin{aligned}\theta &= 76.8\; \rm \text{revolution} \\ &= 76.8\;\text{revolution} \times 2\pi\; \rm rad \cdot \text{revolution}^{-1} \\ &= 153.6\pi\; \rm rad\end{aligned}\).

Rearrange the equation \((\omega(\text{final}))^2 - (\omega(\text{initial}))^2 = 2\, \alpha\, \theta\) and solve for \(\alpha\):

\(\begin{aligned}\alpha &= \frac{(\omega(\text{final}))^2 - (\omega(\text{initial}))^2}{2\, \theta} \\ &= \frac{-\left(39.1\; \rm rad \cdot s^{-1}\right)^2}{2\times 153.6\pi\; \rm rad} \approx -1.58\; \rm rad \cdot s^{-1}\end{aligned}\).

when wind encounters a wind turbine that produces energy, wind speed on the downside of the blades is

Answers

It is slowed
Can I get Brainliest

Which model below describes the processes of Gamma radiation?
A
B.
C.
D.

Which model below describes the processes of Gamma radiation?AB.C.D.

Answers

Answer:

C

Explanation:

A horse has a kinetic energy of 29/400 J. If the horse has a mass of 300 kg.
what is the horse's speed?
OA. 98 m/s
OB. 33.1 m/s
O C. 14 m/s
OD. 9.9 m/s

Answers

OB. 33.1 m/s

To calculate the horse's speed, you can use the formula for kinetic energy:

KE = (1/2)mv^2

where m is the mass of the horse and v is its velocity. Rearranging the formula to solve for velocity:

v = √(2KE/m)

Plugging in the given values:

v = √(2 * 29/400 J / 300 kg) = √(58/300 kg m^2/s^2) = √(0.194 m^2/s^2) = 33.1 m/s

Please helpppppppppp!!!!!!!!!!!

Please helpppppppppp!!!!!!!!!!!

Answers

37N is the answer.

Also pls mark me brianliest!!

USATESTPREP

‎Examine the image here showing the different characteristics of the components of the electromagnetic spectrum. Ultraviolet light is often used to sterilize water in a water treatment facility. Which characteristics of ultraviolet light allow it to sterilize water? Select ALL that apply.

A) It is not visible, so pathogens cannot detect its presence.
B) It has low enough energy to be safe to humans but harmful to pathogens.
C) Its energy level is high enough to cause ionizing damage to DNA and molecules.
D) It has wavelengths too large to cause molecular changes to the molecules of water.
E) Its wavelengths are small enough to interact with bacteria and viruses, which can be pathogenic in the water.

USATESTPREPExamine the image here showing the different characteristics of the components of the electromagnetic

Answers

Answer:

C, D, and E

Explanation:

Answer:it’s C, D, E

Explanation:


What is Energy in physics?

Answers

Answer:

Energy, in physics, the capacity for doing work. It may exist in potential, kinetic, thermal, electrical, chemical, nuclear, or other various forms. There are, moreover, heat and work—i.e., energy in the process of transfer from one body to another.

Explanation:

Hope this helps!

What is the momentum of 100 kg running at 4m/s north?

Answers

The momentum is known as mass x velocity then u should say that it will be 400 kg m/s

Mr. Rossi's car, stopped at the traffic lights, is hit by that of Mr. Bianchi. Then later in court, claims that he was traveling at 50 km / h, but Mr. Rossi
tthinks that mr. Bianchi was going much faster. After the collision the two cars got stuck and from the tracks on the asphalt it was possible to establish that, immediately after the collision, they were traveling at 30 km / h. Mr. Bianchi drove a car with a mass of 800 kg and Rossi a car with a mass of 1400 kg.
Does Bianchi tell the truth?

show explanation ​

Answers

Answer:

i need this too

Explanation:

the planets eccentricity in order least to greatest​

Answers

Answer:

Orbital Eccentricity

Planet Orbital Eccentricity

(Point in Orbit Closest to Sun)

measured in AU's

Mercury 0.206

Venus 0.007

Earth 0.017

Mars 0.093

Jupiter 0.048

Saturn 0.056

Uranus 0.047

Neptune 0.009

Pluto 0.248

Explanation:

link to information:

https://www.enchantedlearning.com/subjects/astronomy/glossary/Eccentricity.shtml

A train slows down as it rounds a sharp horizontal turn, going from 86.0 km/h to 56.0 km/h in the 18.0 s that it takes to round the bend. The radius of the curve is 160 m. Compute the acceleration at the moment the train speed reaches 56.0 km/h. Assume the train continues to slow down at this time at the same rate.

Answers

Answer:

The acceleration of the train is 1.581 m/s² inward.

Explanation:

Given;

initial velocity of the train, u = 86.0 km/h = 23.889 m/s

final velocity of the train, v = 56.0 km/h = 15.556 m/s

change in time, Δt = 18 s

The total acceleration of particles moving along a curved path is given as vector sum of the tangential acceleration and radial acceleration

\(a = \sqrt{a_t^2 + a_r^2}\)

where;

\(a_t\) is the tangential acceleration

\(a_r\) is radial acceleration

\(a_t = \frac{v-u}{t} \\a_t = \frac{15.556-23.889}{18} \\\\a_t = -0.463 \ m/s^2 \\\\a_t = 0.463 \ m/s^2 \ \ (inward)\)

\(a_r = \frac{v^2}{r} \\\\a_r = \frac{15.556^2}{160} \\\\a_r = 1.512 \ m/s^2\)

\(a = \sqrt{a_t^2 + a_r^2} \\\\a = \sqrt{(-0.463)^2+(1.512)^2} \\\\a = \sqrt{2.5005} \\\\a = 1.581 \ m/s^2\)

Therefore, the acceleration at the moment the train speed reaches 56.0 km/h is 1.581 m/s² inward.

If in the figure below, the friction between the block and the incline is negligible, (a) how much must the object on the right weigh if the 200-N block is to remain at rest? Ans: 115 N (b) if the system remains at rest when F= 220 N. What are the magnitude and direction of the friction force on the 200-N block? Ans: 105 N down the incline 200 N Fw 35.0⁰​

Answers

The magnitude of the acceleration and its direction however depends on the resultant force.

What is the resultant force?

In a system of forces, the resultant force is the force that has the same effect in magnitude and direction as all the forces acting together.

In an inclined plane, the friction, weight and applied force all act together on the object. The magnitude of the acceleration and its direction however depends on the resultant force.

This question is incomplete as the diagrams are missing hence the numerical values can not be computed.

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Luis wants to compare the density of three solid objects that are different shapes and sizes. What information does he need to make the comparison?

Answers

Answer:

u need to make sure that comparison is = to shapes and then find the shapes sizes and add them

Which of the following is the BEST explanation for why oceans have two different types of currents?

Answers

Answer:

sddww

Explanation:

szsswa

A man with 60 years to live wants to visit a distant Galaxy which is 160,000 light years away. What must be his constant speed?

Answers

The man's constant speed is 2.99 x 10⁸ m/s.

What is speed of light?

The speed with which the light ray travels in a medium with negative pressure or in vacuum.

This speed is the greatest speed in the universe. No matter can have speed greater than the speed of light in vacuum.

Given is a man with 60 years to live wants to visit a distant Galaxy which is 160,000 light years away.

If a man travels with the speed of light, he needs 160000 years to reach the galaxy, but visits in 60 years.

According to the relativistic theory,

160000 = 60 /√[1 - (v² /c²)]

where v is constant speed need to find and c is the speed of light in vacuum = 3 x 10⁸ m/s

Substitute into the formula, we get

160000 =  60 /√[1 - (v² /(3 x 10⁸)²) ]

Simplifying further

v² /c² = (1 - 1.406 x 10⁻⁷ )

Then,

v/c = 0.999

v = 0.999 x 3 x 10⁸ m/s

v = 2.99 x 10⁸ m/s

Thus, the constant speed of the  man is 2.99 x 10⁸ m/s.

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Which has more mass electron or ion?

Answers

an ion has more mass than an electron

who discovered Absolute Temperature​

Answers

Answer: William Thomson, better known as Lord Kelvin

William Thomson aka Lord Kelvin

A boat sails for 24 km pointed in the direction [40° S of WI. A constant current moves the boat 8 km [30° W of N]. If the trip takes 3 hours, find the boats resultant velocity


Please brainliest, really need it!!!

Answers

The resultant velocity of the boat is 7.5 km/h.

What is the resultant displacement of the boat?

The resultant displacement of the boat is calculated as follows;

Sum of the vertical displacement of the boat is calculated as;

∑Fy = -24 km sin(50)  + 8 km sin(60)

∑Fy = -11.5 km

Sum of the horizontal displacement of the boat is calculated as;

∑Fx = -24 km cos(50)  - 8 km cos(60)

∑Fx = -19.4 km

The resultant displacement is calculated as follows;

d = √ (-11.5² + 19.4²)

d = 22.55 km

The resultant velocity of the boat is calculated as follows;

v = ( 22.55 km ) / ( 3 hrs )

v = 7.5 km/h

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Taylor and Savannah are doing the Period of a Pendulum Lab. They observe that a pendulum makes exactly 10 complete back and forth cycles of motion in 21.8 seconds. Determine the period of the pendulum.

Answers

Answer:

the answer is 2

Explanation:

when you solve for this equation it wont make sense but I'm making you read this because I ain't ever seen 2 best friends.

3. A boulder drops in the water and creates a wave with a period of 2 s/cycle and a wavelength of
.75 m/cycle. How fast is the wave moving?

Answers

Answer:

The wave moves with a velocity of 37.5 m/s

Explanation:

We know that the speed of a wave is given by:

V = f*λ

Where f is the frequency (the inverse of the period)

Then:

f = 1/T

And we know that T = 2 s/cycle

f = 1/(2 s/cycle) = (1/2) cycle/s

And λ is the wavelength, we know that:

λ = 75m/cycle.

Then the speed of the wave is:

v = ( (1/2) cycle/s)*(75m/cycle) = (75/2) m/s = 37.5 m/s

two vectors undergo vector addition. vector a has a magnitude of 217 units and points to the north. vector b has a magnitude of 156 units and points to the west. what is the direction of the resultant vector? (the angle)

Answers

Explanation:

Given that,

The magnitude of vector A = 217 units to north

The magnitude of vector B = 156 units to west

Let R is the resultant. So,

\(R=\sqrt{217^2+156^2} \\\\R=267.25\ \text{units}\)

Let \(\theta\) is the direction of the resultant vector. So,

\(\tan\theta=\dfrac{y}{x}\\\\\tan\theta=\dfrac{217}{156}\\\\\theta=\tan^{-1}\left(\dfrac{217}{156}\right)\\\\\theta=54.28^{\circ}\)

Hence, this is the required solution.

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