Factorise:a(a-2)-b(b-2)

FALSE. Symmetric algorithms support confidentiality, but they do not inherently support authentication and non-repudiation.

Symmetric algorithms are encryption algorithms that use the same key for both encryption and decryption. Their primary purpose is to ensure confidentiality by keeping data secure from unauthorized access. However, symmetric algorithms do not provide built-in mechanisms for authentication and non-repudiation.

Authentication involves verifying the identity of a communicating party to ensure that the message comes from a trusted source. Non-repudiation, on the other hand, ensures that the sender cannot deny sending a message.

To achieve authentication and non-repudiation, additional mechanisms such as digital signatures and asymmetric encryption algorithms are typically used. Asymmetric algorithms, also known as public-key algorithms, employ a pair of keys (public and private) for encryption and decryption, enabling authentication and non-repudiation.

So, while symmetric algorithms can provide confidentiality, they do not directly support authentication and non-repudiation without the use of additional mechanisms.

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The two unit vectors are (2/5 +√5/10, 3/10 + 2√5/15) and (2/5 -√5/10, 3/10 - 2√5/15).

Given that, Angle = 60°, v = 8, 6

Consider unit vector a = (x, y)

x² + y² = 1 …. (1)

Now apply the dot product of unit vector with v

a.v = |a||v|cos Ø

a.v = √ (x² + y²) √ (8² + 6²) cos 60º

8x + 6y = 1 × 10 × ½

So we get,

8x + 6y = 5 …. (2)

y = (5 - 8x) / 6

Substituting the value of y in equation (1)

x² + y² = 1

x² + [(5 - 8x)/6]² = 1

x² + 25/36 + 16x²/9 - 20x/9 = 1

25x²/9 - 20x/9 = 11/36

So we get,

4 × (25x² - 20x) = 11

100x² - 80x = 11

100x² - 80x - 11 = 0

Now solve the quadratic equation,

x = { 2/5 ± √5/10}

Substituting the value of x in equation (2)

y = 3/10 ± 2√5/15

Therefore, the two unit vectors are (2/5 +√5/10, 3/10 + 2√5/15) and (2/5 -√5/10, 3/10 - 2√5/15).

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a)

The perimeter is given by

b)

Then we simplify by summing similar terms we obtain that the expression of the perimeter is

\(12>-2(y-4)\\\\\implies -\dfrac{12}2 <y-4~~~;[\text{Dividing by a negative number, so reverse the inequality.}]\\\\\implies -6<y-4\\\\\implies -6+4<y\\\\\implies -2<y\\\\\implies y>-2\\\\\text{Interval,}~ (-2,\infty)\)

Answer:

(3,-2)

Step-by-step explanation:

See attached image.

80% шанс получить хороший насос Конрад

The mean, also known as the average, is a measure of central tendency in statistics. It is calculated by adding up a set of numbers and then dividing by the total number of values.

Based on the information provided, we need to determine the mean number of text messages sent per day by the students in the local high school. Here's a step-by-step explanation:

1. The study surveyed a random sample of 146 students.
2. The mean number of text messages found in this sample is 185 messages per day.
3. Since this sample is representative of the entire high school population, we can infer that the mean number of text messages sent per day by all students in the high school is approximately 185 messages.

In conclusion, the study determined that the mean number of text messages sent per day by students in the local high school is approximately 185 messages.

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Answer:

\((c - 5)f = - 2x - 3 \\ f = \frac{ - 2x - 3}{c - 5} \\ f = - \frac{2x + 3}{c - 5} \)

Answer:

- \(\frac{3}{2}\)

Step-by-step explanation:

the slope m between the 2 points is a measure of the rate of change

calculate m using the slope formula

m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)

with (x₁, y₁ ) = (2, 12 ) and (x₂, y₂ ) = (6, 6 )

m = \(\frac{6-12}{6-2}\) = \(\frac{-6}{4}\) = - \(\frac{3}{2}\) ← rate of change

The difference after the subtraction is: 2a³ +  10a² - 5a - 4

A polynomial is an expression which has one or more of its variables with a power of at least 2 degrees. It can be expressed in form of a term.

Therefore, a polynomial equation is a means of expressing an expression with terms and on variable with a degree of 2 or more.

To find the difference by subtracting the polynomials, we have:

4a³ + 6a² - 11a - 3 - (2a³ - 4a² - 6a + 1) = 4a³ + 6a² - 11a - 3 - 2a³ + 4a² + 6a - 1

collecting like terms,

4a³ - 2a³ +  6a² + 4a²  - 11a + 6a - 3 - 1 = 2a³ +  10a² - 5a - 4

Therefore, the difference by subtracting the two polynomials is:

2a³ +  10a² - 5a - 4

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Answer:

2

Step-by-step explanation:

5 1/2:2 3/4 reduces is a 2:1 ratio

Answer:

13 i think

Step-by-step explanation:

Answer:

The ratio of 51:9 in it's simplest form is 17:3.

The only equilibrium point for this population system is f = 0, r = 0. the given system of differential equations represents the population dynamics of foxes and rabbits:

df/dt = 5f - 9r

dr/dt = 3f - 4r

to analyze the behavior of the population, we can examine the equilibrium points by setting both Derivative equal to zero:

5f - 9r = 0

3f - 4r = 0

we can solve this system of equations to find the equilibrium points.

from the first equation:

5f = 9r

f = (9/5)r

substituting this into the second equation:

3(9/5)r - 4r = 0

(27/5)r - (20/5)r = 0

(7/5)r = 0

r = 0

so one equilibrium point is f = 0, r = 0.

now, if we consider f ≠ 0, we can divide the first equation by f and rearrange it:

5 - (9/5)(r/f) = 0

(9/5)(r/f) = 5

(r/f) = (5/9)

substituting this into the second equation:

3f - 4(5/9)f = 0

3f - (20/9)f = 0

(7/9)f = 0

f = 0

so the other equilibrium point is f = 0, r = 0.

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Answer:

C.  The value of f (4) is 60, and it represents the number of hours of work remaining for the month after working for 4 days

Step-by-step explanation:

So 5 time 4 equals 20...!

80 minus 20= 60

The value of f (4) is 60, and it represents the number of hours of work remaining for the month after working for 4 days, which is the correct answer would be option (C).

A numerical expression is algebraic information stated in the form of numbers and variables that are unknown. Information can is used to generate numerical expressions.

A student works 80 hours per month and plans to work 5 hours each day, but only on days when work is planned. After working for d days, the function / (d) - 80 — 5d shows the number of hours of work remaining for the month.

⇒ f (d) = 80 - 5d ....(i)

According to option (C),

Substitute the value of d = 4 in equation (i),

⇒ f (4) = 80 - 5(4)

⇒ f (4) = 80 - 20

⇒ f (4) = 60

Thus, the value of f (4) is 60, and it represents the number of hours of work remaining for the month after working for 4 days

Hence, the correct answer would be option (C).

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8. \(10x+5\)

11. \(x^{4}-x^{3}+x\)

14. This is a monomial

17. \(-2x^3\)

The sound intensity level should be decreased by 2 dB to carry the studio into consistency with the rules.

A decrease of 2 dB can be accomplished by one or the other by closing down a portion of the machines (since the sound intensity level declines by 6 dB for each splitting of the sound power) or by introducing sound-sealing materials.

Thus, to carry the studio consistent with the rules, 16 machines would need to be closed down.

It's vital to follow well-being and security rules in the working environment to guarantee the prosperity of representatives and forestall hearing harm. Decreasing the number of machines or introducing soundproofing materials can bring the studio into consistency.

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a) The linear equation represents the charge for transporting x tons.

b) c(x) = 1.07*x

c) c(d(x)) is the tax applied to what we get with d(x).

e) The cost is $1,277.35

a) First we are given the linear function:

d(x) = 85*x + 95

This represents the fixed charge of $95 plus the $85 per ton, so that linear equation represents the charge for transporting x tons.

b) Remember that if we have a quantity A, and it increases by 7%, then just multiply it by 1.07

Then if the cost is x dollars, the cost + tax equation is:

c(x)=  1.07*x

c) Equations like:

C(d(x) ) will give us the tax + cost applied to d(x), which is what the company charges for x tons.

d) If there is no tax to the delivery fee, then the total charge equation is:

f(x) = 1.07*85*x + 95

(the 1.07 not applied to the delivery fee).

If you transport 13 tons of salt, then x = 13

f(13) =  1.07*85*13 + 95 = 1,277.35

The total cost for 13 tons of salt is $1,277.35

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Answer:

QUienn quieres ser mi ami

Step-by-step explanation:

xd

The percentage of measurements in a data set that are above and below each of the following percentiles are 68%, 95% and 99.7%.

We need to calculate the percentage of the measurements contained in each of the following intervals:

According to the empirical rule, approximately 68% of the measurements in a normally distributed data set will fall within one standard deviation of the mean. Therefore, approximately 68% of the measurements will fall within the interval (mean - s, mean + s).

Similarly, approximately 95% of the measurements in a normally distributed data set will fall within two standard deviations of the mean. Therefore, approximately 95% of the measurements will fall within the interval (mean - 2s, mean + 2s).

Likewise, approximately 99.7% of the measurements in a normally distributed data set will fall within three standard deviations of the mean. Therefore, approximately 99.7% of the measurements will fall within the interval (mean - 3s, mean + 3s).

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Answer:

The greatest height the bird reached was 26 feet

At 5 seconds the bird was going down.

Step-by-step explanation:

Step-by-step explanation:

We know that,

\( ➟\sf \: fv \: of \: annuity \: = p( \frac{(1 + r) {}^{n} - 1}{r} )\)

where,

FV of annuity = $35,450

P = monthly payment,

r = rate of interest = 5.5% annually = \( \frac{5.5}{12}%\)

n = number period = 20 years = 240 months

Putting all the values,

\( \sf35450 = p( \frac{(1 + \frac{0.055}{12} ) {}^{240} - 1}{ \frac{0.055}{12} } )\)

\( \sf \: p = \frac{35450}{( \frac{(1 + \frac{0.055}{12} ) {}^{240} - 1}{ \frac{0.055}{12} } )}\)

\( \sf \: p \: = \: \$81.36\)

Therefore, they should deposit $81.38 monthly.

If x = \(t^3\) - t and y = \(\sqrt{3t + 1}\), then dy/dx is 3/8 at t = 1.

To find dy/dx at t=1, we need to first find dx/dt and dy/dt, and then use the chain rule.
1. Find dx/dt:
x = \(t^3\) - t
Differentiate with respect to t:
dx/dt = \(3t^2\) - 1
2. Find dy/dt:
y = sqrt(3t + 1)
Differentiate with respect to t:
dy/dt = 1/2 * \((3t + 1)^{(-1/2)}\) * 3
dy/dt = 3/(2 * \(\sqrt{(3t + 1)}\))
3. Use the chain rule to find dy/dx:
dy/dx = (dy/dt) / (dx/dt)
4. Plug in the values at t = 1:
dx/dt (t=1) = \(3(1)^2\) - 1 = 2
dy/dt (t=1) = 3/(2 * \(\sqrt{(3(1) + 1)}\)) = 3/4
5. Calculate dy/dx at t = 1:
dy/dx = (3/4) / 2 = 3/8
So, the answer is 3/8.

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The categorical variables goes in gf_facet_grid().

Based on a characteristic, a categorical variable value can be classified into a countable number of different categories. You can apply categories to a categorical variable, but there is no inherent order to the categories.

The most typical graph for displaying frequency distributions is a histogram. It closely resembles a bar chart.

You use it to split up histograms. Usually, the facets are described by an unnamed formula argument. We usually use this to show categorical variables.

eg) gf_histogram(~ Thumb, data = Fingers) %>%

gf_facet_grid(. ~ Sex)

So, we can say that categorical variables goes in gf_facet_grid().

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Answer:

∠1 = 48

∠2 = 132

∠4 - 132

Step-by-step explanation:

∠3 and ∠1 are vertical angles

vertical angles are congruent ( equal to each other )

So if ∠3 = 48° then ∠1 also = 48°

∠3 and ∠4 are supplementary angles

supplementary angles add up to equal 180°

Hence, ∠3 + ∠4 = 180

48 + ∠4 = 180

180 - 48 = 132

Hence, ∠4 = 132

∠4 and ∠2 are vertical angles

Like stated previously vertical angles are congruent

Hence, ∠2 = 132

The PDF describes the rate at which probability is accumulating around a given point, while the CDF gives the probability that the random variable takes on a value less than or equal to a given value.

The probability density function (PDF) and cumulative distribution function (CDF) are two different ways of representing the same information about a probability distribution.

The PDF gives the probability density of a continuous random variable at a particular point in its domain. In other words, the PDF gives the rate at which the probability is accumulating around a given point. The area under the PDF curve between two points represents the probability of the random variable taking on a value between those two points.

On the other hand, the CDF gives the probability that a random variable is less than or equal to a given value. The CDF is the integral of the PDF from negative infinity up to that value.

Therefore, the CDF and PDF are related by integration: The CDF is the integral of the PDF, and the PDF is the derivative of the CDF.

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The given question is incomplete, the complete question is:

What is the relationship between the cumulative distribution function and the probability density function?

The null hypothesis for the data will be 21.62 and the alternate hypothesis is 2.02 for the p-value for the data is 0.2253 .

The charge at which anything happens is referred to as the velocity at which it happens.

The required details for mean rate :

(a) H0: µ = 21.62

Ha: µ ≠ 21.62

(b) t = -1.231

p-value = 0.2253

(c) Stop rejecting H0 right now. No longer significantly different from the domestic water tariff in Tulsa, the suggested household water charge per five CCF for the entire USA.

(d) H0: µ = 21.62

Ha: µ ≠ 21.62

t = -1.231

check statistic ≥ 2.020

Don't dismiss H0 any longer. The suggested five CCF residential water charge for the entirety of the USA is no longer significantly different from the five CCF residential water tariff in Tulsa.

The P-value is higher at 0.05, the level of significance. The impact in this instance is negligible. The attempt to reject the null hypothesis failed.

The conclusion is that there is insufficient statistical support to determine whether other American cities have a different mortality rate than Tulsa.

The crucial values for t at this level of significance are t=2.019.

Given that the statistic t = -1.15 is inside the acceptance range in this case, the null hypothesis is not disproved.

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