explain why you would expect that the Hneutzn for HBr reacting with KOH and the Hneutzn for HNO3 reacting with NaOH to be identical

Answer:

12.23moles in 1000cm3

Explanation:

Mass=moles×molermass

538=44xY

Y=538÷44

Y=12.23moles in 1000cm3

A food chain refers to the order of events in an ecosystem, where one living organisms eats another organisms and later that organism is consumed by another larger organism. It also explains the feeding pattern.

The food chain is a linear sequence of organisms where the nutrients and energy is transferred from one organism to the other. It begins with the producer and ends with decomposer.

The producers in a food chain consists of all autotrophs like phytoplankton, algae and green plants. It is the producers which utilize the energy from the sun to produce food.

Thus the correct option is B.

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In Newton's second law, unbalanced or net forces cause an object to accelerate.

Newton's second law of motion states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. It can be expressed as F = m × a

Where:

F is the net force acting on the object,

m is the mass of the object,

a is the acceleration produced in the object.

This law describes the relationship between force, mass, and acceleration. The greater the force applied to an object, the greater its acceleration. The greater its mass, the smaller its acceleration for the same force.

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Answer: Thus the volume of the balloon at this altitude is 419 L

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\(\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\)

where,

\(P_1\) = initial pressure of gas = 751 mm Hg

\(P_2\) = final pressure of gas = 495 mm Hg

\(V_1\) = initial volume of gas = 340 L

\(V_2\) = final volume of gas = ?

\(T_1\) = initial temperature of gas = \(30^oC=273+30=303K\)

\(T_2\) = final temperature of gas = \(-27^oC=273-27=246K\)

Now put all the given values in the above equation, we get:

\(\frac{751\times 340}{303}=\frac{495\times V_2}{246}\)

\(V_2=419L\)

Thus the volume of the balloon at this altitude is 419 L

Answer:

0.77 M

Explanation:

Molarity is the concentration of a solution per liter

C= concentration

n= number of moles

V= volume of solution

The formula we will use is C= n/V

C= n/V

C= (1.93 mol NaCl)/(2.5 L of solution)

C= 0.772 mol/L

Since this concentration is given in moles per liters of a solution, this concentration is also the molarity.

C= 0.772 mol/L

*Include two significant digits in final answer*

M= 0.77 M

Answer:

a. pH = 2.52

b. pH = 8.67

c. pH = 12.83

Explanation:

The equation of the titration between the benzoic acid and NaOH is:

C₆H₅CO₂H + OH⁻ ⇄ C₆H₅CO₂⁻ + H₂O    (1)

a. To find the pH after the addition of 20.0 mL of NaOH we need to find the number of moles of C₆H₅CO₂H and NaOH:

\( \eta_{NaOH} = C*V = 0.250 M*0.020 L = 5.00 \cdot 10^{-3} moles \)

\( \eta_{C_{6}H_{5}CO_{2}H}i = C*V = 0.300 M*0.050 L = 0.015 moles \)  

From the reaction between the benzoic acid and NaOH we have the following number of moles of benzoic acid remaining:

\(\eta_{C_{6}H_{5}CO_{2}H} = \eta_{C_{6}H_{5}CO_{2}H}i - \eta_{NaOH} = 0.015 moles - 5.00 \cdot 10^{-3} moles = 0.01 moles\)

The concentration of benzoic acid is:

\( C = \frac{\eta}{V} = \frac{0.01 moles}{(0.020 + 0.050) L} = 0.14 M \)

Now, from the dissociation equilibrium of benzoic acid we have:

C₆H₅CO₂H + H₂O ⇄ C₆H₅CO₂⁻ + H₃O⁺  

0.14 - x                            x                x

\( Ka = \frac{[C_{6}H_{5}CO_{2}^{-}][H_{3}O^{+}]}{[C_{6}H_{5}CO_{2}H]} \)

\( Ka = \frac{x*x}{0.14 - x} \)

\( 6.5 \cdot 10^{-5}*(0.14 - x) - x^{2} = 0 \)   (2)  

By solving equation (2) for x we have:          

x = 0.0030 = [C₆H₅CO₂⁻] = [H₃O⁺]

Finally, the pH is:

\( pH = -log([H_{3}O^{+}]) = -log (0.0030) = 2.52 \)

b. At the equivalence point, the benzoic acid has been converted to its conjugate base for the reaction with NaOH so, the equilibrium equation is:

C₆H₅CO₂⁻ + H₂O  ⇄  C₆H₅CO₂H + OH⁻     (3)

The number of moles of C₆H₅CO₂⁻ is:

\( \eta_{C_{6}H_{5}CO_{2}^{-}} = \eta_{C_{6}H_{5}CO_{2}H}i = 0.015 moles \)

The volume of NaOH added is:

\( V = \frac{\eta}{C} = \frac{0.015 moles}{0.250 M} = 0.060 L \)

The concentration of C₆H₅CO₂⁻ is:

\( C = \frac{\eta}{V} = \frac{0.015 moles}{(0.060 L + 0.050 L)} = 0.14 M \)

From the equilibrium of equation (3) we have:

C₆H₅CO₂⁻ + H₂O  ⇄  C₆H₅CO₂H + OH⁻  

0.14 - x                              x               x

\(Kb = \frac{[C_{6}H_{5}CO_{2}H][OH^{-}]}{[C_{6}H_{5}CO_{2}^{-}]}\)

\( (\frac{Kw}{Ka})*(0.14 - x) - x^{2} = 0 \)

\( (\frac{1.00 \cdot 10^{-14}}{6.5 \cdot 10^{-5}})*(0.14 - x) - x^{2} = 0 \)

By solving the equation above for x, we have:

x = 4.64x10⁻⁶ = [C₆H₅CO₂H] = [OH⁻]

The pH is:

\( pOH = -log[OH^{-}] = -log(4.64 \cdot 10^{-6}) = 5.33 \)

\( pH = 14 - pOH = 14 - 5.33 = 8.67 \)

c. To find the pH after the addition of 100 mL of NaOH we need to find the number of moles of NaOH:

\( \eta_{NaOH}i = C*V = 0.250 M*0.100 L = 0.025 moles \)

From the reaction between the benzoic acid and NaOH we have the following number of moles remaining:                              

\( \eta_{NaOH} = \eta_{NaOH}i - \eta_{C_{6}H_{5}CO_{2}H} = 0.025 moles - 0.015 moles = 0.010 moles \)                          

The concentration of NaOH is:

\( C = \frac{\eta}{V} = \frac{0.010 moles}{0.100 L + 0.050 L} = 0.067 M \)

Therefore, the pH is given by this excess of NaOH:         

\( pOH = -log([OH^{-}]) = -log(0.067) = 1.17 \)

\( pH = 14 - pOH = 12.83 \)

I hope it helps you!    

Answer:

A.It forms a boundary that controls what enters and leaves the cell.

Explanation:

i took the test on k12

The carbon in Compound 3 matches the carbon in Compound 4a with an asterisk is C2. Therefore, option B is correct.

Alpha-cadinol is a cadinane sesquiterpenoid that has a hydroxy group at position 10. It acts as a fungicide and a plant metabolite.

This compound is synthesized in two main steps. In the first step, compound 1 undergoes nucleophilic addition to compound 2. Then, the product compound 3 formed will undergo intramolecular aldol condensation. This cyclic product further undergoes dehydration and forms two isomers compound 4a and compound 4b. The compound 4a only is converted to alpha-cadinol.

In the conversion of compound 3 to compound 4a, carbon 2 containing acidic hydrogen will deprotonate and attack the carbonyl of the 5-carbon ring. Therefore, the asterisk is carbon 2.

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The Sun rotates at different rates at different latitudes on the Sun

The sun revolves around its axis like a ball in motion. One cycle of the sun takes approximately 27 days. But the sun rotates at various rates in various parts. The sun's equator rotates more quickly than its poles. Differential rotation is the name given to this phenomena.

The depth of the sun also affects how quickly it rotates, with the core regions rotating more slowly than the outer regions.

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Missing parts;

Which statement about the Sun's rotation is TRUE?

The Sun rotates only at the equator, where the sunspots are found; the rest of the Sun does not rotate

Only the atmosphere of the Sun rotates, not the main body of the Sun

The Sun rotates at different rates at different latitudes on the Sun

The Sun rotates once a day

The Sun does not rotate; only planets rotate

The ratio of neutrons to protons, or the N/Z ratio, plays a crucial role in determining a nucleus' stability. The range of N/Z ratios in which nuclei are stable is generally referred to as the belt of stability.

If the forces between the constituents of the nucleus are equal, an atom is stable. If these forces are out of balance or if the nucleus has an excessive amount of internal energy, an atom is unstable (radioactive).

Z = 104 for Rutherfordium, element 104. The isotopes 261Rf and 262Rf, having masses of 261 and 262, respectively, have the longest half-lives. Accordingly, N/Z ratios are:

261Rf: N/Z = (261-104)/157 = 1.08

262Rf: N/Z = (262-104)/158 = 1.09

These N/Z ratios are a little bit higher than the average belt of stability values, which are about 1.0 for heavy nuclei. These isotopes are thought to be reasonably stable because they are close enough.

Z = 109 for Meitnerium, element 109. The isotopes 278Mt and 282Mt, with masses of 278 and 282, respectively, have the longest half-lives. Accordingly, N/Z ratios are:

278Mt: N/Z

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Answer:

no they do not

Explanation:

Answer:

It's just...Hair grown there...i guess it just grows as a male humans would

Explanation:

hope this helps.

Answer:

A) share electrons

Explanation:

In Ionic bonding is the complete transfer of valence electron between atoms

The reaction is given by

\(\\ \rm\Rrightarrow {}^{127}_{56}Ba\longrightarrow {}^{0}_{+1}\beta+{}^{127}_{55}Cs\)

Barium goes underneath beta decay to form Ceaseum

\(\sf {}^{127}_{56}Ba\longrightarrow {}^0_{1}\beta+{}^{127}_{55}Cs\)

Remember

Answer:

predator

Explanation:

Wolves, arctic foxes, and snowy owls are predators in the tundra.

The chemical elements involved are; hydrogen, fluorine, boron and lithium

There are two hydrogen atoms, five fluorine atoms, one boron atom and one lithium atom.

Chemical compounds are represented symbolically by chemical formulas, which reveal the types and amounts of atoms that make up the compound. It is a succinct approach to explain a substance's makeup.

The components of a compound are identified in a chemical formula by their corresponding chemical symbols, which are typically derived from their English or Latin names. The number of atoms of each element in a single compound molecule is indicated by the subscripts that follow each element.

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Answer:

Yes, wind and temperature are responsible for the spreading of fire.

Explanation:

Chemistry play a key role in the chemical reaction that is occurring in the wildfires because chemistry is the study of chemicals and in wildfires, the reaction of chemicals is responsible for the occurring and spreading of fire. Yes, wind currents and temperature has a great influence  on the fire spreading in the forests. The fire occurs in the forest is due to temperature while its spreading happens due to wind. Placing water on the fire does not help extinguish the fire because the the fire particles can be transmitted for a fair distance by wind.

The combined gas law equation is:

(P1 * V1) / (T1) = (P2 * V2) / (T2)

The volume of the gas at 30 °C is approximately 760.67 mL.

To determine the volume of the gas at 30 °C, we can use the combined gas law equation, which relates the initial and final conditions of temperature and volume for a gas.

The combined gas law equation is:

(P1 * V1) / (T1) = (P2 * V2) / (T2)

Where:

P1 and P2 are the initial and final pressures, respectively

V1 and V2 are the initial and final volumes, respectively

T1 and T2 are the initial and final temperatures in Kelvin, respectively

We need to convert the temperatures from Celsius to Kelvin by adding 273.15 to each value.

Given:

V1 = 550 mL

T1 = -55 °C = 218.15 K

T2 = 30 °C = 303.15 K

Assuming the pressure remains constant, we can rearrange the equation to solve for V2:

V2 = (P1 * V1 * T2) / (P2 * T1)

Since the pressure is not specified in the problem, we can assume it remains constant, allowing us to cancel out the pressure terms. Thus, the final equation becomes:

V2 = (V1 * T2) / T1

Plugging in the given values:

V2 = (550 mL * 303.15 K) / 218.15 K

Simplifying the calculation, we find:

V2 ≈ 760.67 mL

Therefore, the volume of the gas at 30 °C is approximately 760.67 mL.

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answer and explanation

this is and example of an exotherm reaction where energy is released

D is the correct option

Here are the answers for A and B.

Answer:

(a) 80% are metals.

(b) (1.) Metals are malleable and ductile. (2.) Metals are dense.

Explanation:

(a) If you look at the picture, there are faint lines dividing the circle into ten parts. Metals take up 8 sections and non-metals take up 2. This means that the number of metals on the periodic table takes up 80% and non-metals take up 20%.

(b) There are many physical properties of metals, but two of them are that metals are malleable & ductile (these relate to how metal can be shaped) and that metals are dense (density = mass ÷ volume).

Answer:

Explanation:

The reaction only takes place if the reactants are in contact, then the surface exposed is very important because as the exposed surface of the reactants increases, the reaction velocity also increases. If the lumps are not broken up, a big amount of baking soda would be only available to react after the surrounding soda has already reacted.

ANSWER

1-Butyne

STEP-BY-STEP EXPLANATION:

To name the below structure, we need to consider the following

0. The number of carbon atoms present in the structure

1. The type of bond and the location

According to the structure given, we have four carbon atoms

These four carbon atoms mean Butane according to the alkane family

We have a tripple bond in between the first and second carbon atom

Since we have a tripple bond, the -ane in butane will be changed to -yne

Hence, the name of the structure is 1-Butyne

Answer:

3.18 (w/w) %

Explanation:

In the problem, you can find mass of NaClO knowing the reaction of NaClO with Na₂S₂O₃ is:

NaClO + 2Na₂S₂O₃ + H₂O → NaCl + Na₂S₄O₆ +2NaOH + NaCl

Where 1 mole of NaClO reacts with 2 moles of Na₂S₂O₃

Moles of thiosulfate in the titration are:

0.0101L ₓ (0.042mol / L) = 4.242x10⁻⁴ moles of Na₂S₂O₃

Thus, moles of NaClO in the initial solution are:

4.242x10⁻⁴ moles of Na₂S₂O₃ ₓ (1mol NaClO / 2 mol Na₂S₂O₃) = 2.121x10⁻⁴ moles NaClO

As molar mass of NaClO is 74.44g/mol, mass of 2.121x10⁻⁴ moles are:

2.121x10⁻⁴ moles ₓ (74.44g / mol) = 0.0158g of NaClO

As mass of bleach is 0.496g, mass percent is:

0.0158g NaClO / 0.496g bleach ₓ 100 =

From the solution that we have in the question;

The equilibrium constant, denoted as K, is a value that quantitatively represents the ratio of the concentrations of products to reactants at equilibrium in a chemical reaction.

It is a fundamental concept in chemical equilibrium.

The value of the equilibrium constant provides valuable information about the position of equilibrium and the relative concentrations of species involved in a chemical reaction.

Kc = [X] [Y]/[XY]

\(0.25 = (0.1 + x)^2/(0.5 - x)\)

\(0.25(0.5 - x) = (0.1 + x)^2\)

\(0.125 - 0.25x =0.01 + 0.2x + x^2\\ x^2 + 0.45x - 0.115 = 0\)

x = 0.18 M

The equilibrium amount of X and Y=  0.28 M and the equilibrium concentration of XY = 0.32 M

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Based on the answer to the question that we have;

The ratio of the product to reactant concentrations in a chemical reaction at equilibrium is represented quantitatively by the equilibrium constant, abbreviated as K.

It is a cornerstone of the theory of chemical equilibrium.

A chemical reaction's equilibrium position and the relative concentrations of the species involved can both be learned from the equilibrium constant's value.

Kc = [X][Y]/[XY]

\(0.25 = (0.1 + x)^2/(0.5 - x)\\0.25(0.5 - x) = (0.1 +x)^2\\0.125 - 0.25x = 0.01 +0.2x +x^2\\= 0.18 M\)

The equilibrium concentration of;

XY =0.5 - 0.18

=0.32 M

Then the equilibrium amount of

X and Y is

0.1 + 0.18= 0.28 M.

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The usual enthalpy change for the 200g/7.68 mol of ethyne reaction is C2H6g C2H2g Plus 2H2g - 2,388.5kJ.

The quantity of heat released or absorbed during a reaction occurring at constant pressure is known as the enthalpy change.

H stands for "enthalpy change," Hf for "system final enthalpy" (i.e., the enthalpy of the byproducts of the system in equilibrium in a chemical reaction), and Hi for "system initial enthalpy" (i.e., the entropy for the reactants in a chemical reaction).

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Answer:

What is meant by activated complex?

The state of the particles that is in between the reactants and products is called the activated complex. An activated complex is an unstable arrangement of atoms that exists momentarily at the peak of the activation energy barrier.

source:Gogle

In exactly 1 mol Hg₂(NO₃)₂ , there are 2 mol Hg, 2 mol N and 6 mol O.

Since the molecular formula of Hg₂(NO₃)₂ shows that for every mole of the substance, we have 2 moles of Hg, 2 moles of N and 6 moles of O.

So, in exactly 1 mol Hg₂(NO₃)₂ , there are 2 mol Hg, 2 mol N and 6 mol O.

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The equation can be balanced by using options C and E

To balance a chemical reaction equation, you need to ensure that the number of atoms of each element is the same on both sides of the equation. Balancing the equation is important because it follows the law of conservation of mass, which states that matter cannot be created or destroyed in a chemical reaction.

Start balancing with elements that appear in the fewest compounds: Begin balancing the equation by adjusting elements that appear in the fewest compounds first.

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