explain why it is important to keep the weight over the pulley constant ( Newton 's second law)​

Answers

Answer 1

Newton's second law of motion states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. In other words, the larger the net force acting on an object, the greater its acceleration, and the larger the object's mass, the smaller its acceleration for a given force.

Why  is it important to keep the weight over the pulley constant?

When a weight is placed over a pulley, the net force acting on it is equal to the weight of the object, and the acceleration of the object depends on its mass. However, if the weight over the pulley is not constant, the net force acting on the object changes, which affects its acceleration.

For example, if the weight over the pulley increases, the net force acting on the object also increases, and the object's acceleration increases. Conversely, if the weight over the pulley decreases, the net force acting on the object decreases, and the object's acceleration decreases.

Keeping the weight over the pulley constant ensures that the net force acting on the object remains constant, which allows for accurate and predictable calculations of the object's acceleration. This is especially important in scientific and engineering applications where precise measurements and calculations are necessary.

Therefore, it is important to keep the weight over the pulley constant to ensure that Newton's second law of motion can be applied accurately and consistently.

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Related Questions

At what velocity will a 300.W motor pull a mass if it applies a force of 13.9N?
4170m/s
286m/s
21.6m/s
0.0463m/s

Answers

To answer this question, we need to use the formula that relates force, mass, and acceleration: F=ma. We can rearrange this formula to solve for acceleration: a=F/m.

In this case, we are given that the force applied by the motor is 13.9N, and we need to find the velocity at which it will pull a mass. We are not given the mass directly, but we can calculate it using the power of the motor (300W) and the velocity we are trying to find.

Power is defined as the rate at which work is done, or P=W/t, where W is the work done and t is the time it takes to do that work. In this case, we can assume that the work done is moving the mass a certain distance, and we can use the velocity to calculate the time it takes to do that work. So, we have:

P=Fv

where P=300W, F=13.9N, and v is the velocity we want to find. Rearranging this equation gives:

v=P/F

Now we can substitute in the values for P and F to get:

v=300/13.9

v≈21.6 m/s

So, at a velocity of 21.6 m/s, a 300.W motor applying a force of 13.9N can pull a mass.

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a pilot performs an evasive maneuver by diving vertically at 330 m/s . if he can withstand an acceleration of 9.0 g 's without blacking out, at what altitude must he begin to pull out of the dive to avoid crashing into the sea?

Answers

12100 m is altitude must he begin to pull out of the dive to avoid crashing into the sea

Data given us that,

Velocity = 330 m/s

Acceleration = 9.0g s

centripetal acceleration

a=v^2/r

r=v^2/a

v = velocity

r = altitude

a = acceleration

Put the value

r=108900/9

r=12100 m

Gravity has an impact on how the missile moves vertically. As a result, the vertical component of the starting speed will be 0 at the highest altitude point. The projectile will slow down as it ascends to its highest point, come to a complete halt, and then begin its free fall plummet to the ground.

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bill nye makes an ""extraordinary claim"" that an inflated red balloon will move forward in an accelerating car. does it work? what is the explanation?

Answers

The explanation about "red balloon will move forward in an accelerating car"  is given below:

What is acceleration ?

Acceleration is a vector quantity that describes the rate at which an object changes its velocity. It is the rate at which the velocity of an object changes in magnitude or direction, or both. In other words, it tells us how quickly an object is speeding up or slowing down. Acceleration has units of meter per second squared (m/s²) and its direction is the same as the direction of the change in velocity.

Bill Nye's claim that an inflated red balloon will move forward in an accelerating car.

And it can be understood through the principles of motion.

When a car is accelerating, its velocity changes, and this creates a force called the "inertial force" that acts in the opposite direction of the acceleration. This force is also referred to as the "fictitious force" or the "centrifugal force."

Hence, the inflated red balloon does move forward in an accelerating car.

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explain why the different thermal conductivities of metal and plastic are important in the design of the bowl.

explain why the different thermal conductivities of metal and plastic are important in the design of

Answers

Answer:

metal conducts heat faster than wood. which means the metal conducted heat away from your hand (or whatever it is) faster than wood.

Explanation:

just because they feel warm/cold doesn't always mean that it is warm/cold. if they both were sitting at room temp for a long time, then both will eventually reach the temp of the room. even though they are the same temp the metal will feel colder than the wood because of the thermal conductivity of the metal compared to the wood.

The different thermal conductivities of metal and plastic are important in the design of the bowl is metal conducts heat faster than Plastic. which means the metal conducted heat away from your hand (or whatever it is) faster than Plastic.

What is thermal conductivity?

Thermal conductivity can be defined as the degree to which heat is transmitted through the cross-section of the unit of an object, where the temperature exits directly across the surface.

What is electrical and thermal conductivity?

Electrical conductivity is a measure of how much energy (moving charge) can pass through objects under the influence of a used electric field. Thermal conductivity measures how heat (heat moving energy) can pass through objects below temperature differences.

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A civil engineer is to design a road curve at an 88.3 m radius to carry racing cars traveling at 21 m/s. µ = 0.13 (of the car thin) At what angle θ should it be banked for maximum control of the racing car? The coefficient of friction of the surface is 0.13 and the acceleration due to gravity is 9.8 m/s2.

Answers

The road curve should be banked at an angle of 8.67 degrees for maximum control of the racing car.

The angle θ at which the road curve should be banked for maximum control of the racing car can be found using the formula for centripetal force and the frictional force equation.

The centripetal force equation is Fc = mv^2/r,

where Fc is the centripetal force,

m is the mass of the car,

v is the velocity of the car,

and r is the radius of the curve.

The frictional force equation is Ff = μmg,

where Ff is the frictional force,

μ is the coefficient of friction,

m is the mass of the car,

and g is the acceleration due to gravity.

For maximum control, the centripetal force and the frictional force should be equal, so we can set the two equations equal to each other and solve for θ:

mv^2/r = μmg

v^2/r = μg

tanθ = v^2/(rμg)

θ = tan^-1(v^2/(rμg))

Plugging in the given values for v, r, μ, and g, we get:

θ = tan^-1((21 m/s)^2/(88.3 m * 0.13 * 9.8 m/s^2))

θ = 8.67 degrees

Therefore, the road curve should be banked at an angle of 8.67 degrees for maximum control of the racing car.

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Which types of interactions are negligible at standard temperature and pressure?

Answers

Explanation: a reduction in genetic diversity and discomfort for animals that have very exaggerated characteristics.

What is the range of an arrow shot horizontally at 85.3 m/s if it is initially 1.50 m above the ground?

range of arrow =

Answers

Answer:

47.2m

Explanation:

Engineers are using computer models to study train collisions to design safer train cars. They start by modeling an elastic collision between two train cars traveling towards each other. Car 1 is traveling north at 20 m/s and has a mass of 12,745 kg. Car 2 is traveling south at 15 m/s and has a mass of 4,125 kg. After the collision, car 1 has a final velocity of 3 m/s north. What is the final velocity of car 2?

Engineers are using computer models to study train collisions to design safer train cars. They start

Answers

The final velocity of car 2 is 67.5248. The momentum is conserved in the given problem,

What is the law of conservation of momentum?

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

The given data in the problem is;

(m₁) is the mass of 1st car=  12,745 kg.

(u₁) is the initial velocity of 1st car= 20 m/s

(m₂) is the mass of 2nd car = 4125 kg

(u₂) is the initial velocity of 2nd car = 15 m/s

(v₁) is the velocity after the collision of 1st car = 3 m/s

The final velocity of car 2,v₂=?

According to the law of conservation of momentum;

Momentum before collision =Momentum after collision

\(\rm m_1u_1 + m_2u_2 = m_1v_1 + m_2v_2 \\\\ 12745 \times 20 +4125 \times 15 = 12745 \times 3 + 4125 \times v_2 \\\\ v_2 = 67.52 \ m/sec\)

Hence, the final velocity of car 2 is 67.5248.

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could you help with question 5. Your solutions to the word problems in volving Newton's Laws should have the following features:Each solution should begin with one or more free body diagrams with a sign convention.The solution process should follow the GRASP process.Formulae should always be used in a three-step process: formula with letter variables, substitution of values, and then the answer.Answers should be expressed with the correct number of significant digits and with the direction if required.

could you help with question 5. Your solutions to the word problems in volving Newton's Laws should have

Answers

ANSWER:

(a) 20 m/s^2

(b) 250 m

STEP-BY-STEP EXPLANATION:

Given:

Mass (m) = 250 g = 0.25 kg

Force (F) = 20 N

Frictional force (Ff) = 15 N

(a)

The net force on the block is:

\(\begin{gathered} F_{net}=F-F_f \\ F_{net}=20-15 \\ F_{net}=5\text{ N} \end{gathered}\)

We know that:

\(\begin{gathered} F=m\cdot a \\ \text{ We replacing} \\ 5=0.25\cdot a \\ a=\frac{5}{0.25} \\ a=20\text{ m/s}^2 \end{gathered}\)

(b)

We can calculate the partial distance from the following equation:

initial velocity (u) = 0 (start from rest)

\(\begin{gathered} s=ut+\frac{1}{2}at^2 \\ \text{ we replacing} \\ s=0\cdot5+\frac{1}{2}\cdot20\cdot5^2 \\ s=250\text{ m} \end{gathered}\)

what is measurement​

Answers

Answer:

the size, length, or amount of something, as established by measuring.

Explanation:

intermediate level a 30 micro f capacitor is connected to a 9 v battery calculate the charge on the capicot

Answers

When a 30 micro of capacitor is attached to the a 9 v battery at its intermediate level, the equation states that 2.7μC is the charges on the capacitor.

What is the basic principle of a capacitor?

A capacitor operates on the basis that capacitance of the a conductor exhibits rise when a grounding conductor is introduced near it. As a result, the capacitance has parallel plates that are spaced apart from one another and facing in opposing directions.

What is a capacitor used for?

Two conductors that are separated from one another and positioned close to one another make up a capacitor, a electrical energy storage device. A parallel-plate capacitor is a simple example with one such storage device.

Briefing:

If we rearrange the previous formula to account for C=30F and V=9v in our issue, we can calculate the charge held in the capacitor:

             Q=CV

                =(30μF) (9v)

                =2.7μC

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A projectile i launched horizontally on a table that it 40 cm high. The projectile land 10 m away. What i the horizontal
velocity of the projectile a it leave the launcher?

Answers

The horizontal velocity of the projectile it leaves the launcher is 0.283 m/s.

The horizontal speed of a projectile is regular, and there's a vertical acceleration because of gravity; its cost is 9.8 m/s/s, down, The vertical speed of a projectile changes via nine.8 m/s every second, The horizontal motion of a projectile is impartial to its vertical movement.

Projectile motion is a form of motion experienced with the aid of an object or particle that is projected in a gravitational field, such as from Earth's floor, and movements alongside a curved route below the action of gravity best.

Projectile motion is the movement of an object thrown (projected) into the air. After the initial force that launches the item, it most effectively reports the pressure of gravity. The object is known as a projectile, and its route is called its trajectory.

Calculation:-

Horizontal distance = 40 cm

                          = 0.4 m

height of table = 10 m

Let vertical velocity is 0.

S = ut +1/2 at²

10 = 0 + 0.5 × 10 t²

t² = 10/5

t    = 1.414 sec.

At the same time, it will take to cover a horizontal distance of 0.4 m.

Velocity = distance/time

                = 0.4/1,414

                  = 0.283 m/s

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A highway speed limit is posted as 90 km/hr. Is this average speed or instantaneous speed? Explain your answer.

Answers

Answer: instantaneous speed.

Explanation: A highway speed limit posted as 90km/hr would be the instantaneous speed because it’s just the speed for that moment.

What type of device is a refrigerator?
A. A heat pump that uses work to move heat
B. A heat pump that uses heat to do work
C. A heat engine that uses work to move heat
D. A heat engine that uses heat to do work

Answers

A heat pump that uses work to move heat

For the vectors A and B in Fig. E1.22, use a scale drawing to find the magnitude and direction of (a) the vector sum A + B and (b) the vector difference A − B. Use your answers to find the magnitude and direction of (c) − A − B and (d) B − A. (See also Exercise1.29

Answers

To find the vector B - A, draw the vector A with its tail at the origin and draw the vector -A with its tail at the head of vector B. The vector B - A is then the vector drawn from the origin to the head of vector -A.

What is Vector?

In physics, vectors are often used to represent physical quantities such as velocity, force, and acceleration. They are typically represented graphically as arrows, with the length of the arrow representing the magnitude of the vector and the direction of the arrow representing the direction of the vector. Vectors can be added and subtracted to find the resulting vector, and they can also be multiplied by scalars (real numbers) to change their magnitude.

Without the provided figure, it is difficult to provide a specific answer. However, in general, to find the vector sum A + B, draw the vector A with its tail at the origin of the coordinate system and draw the vector. The vector sum A + B is then the vector drawn from the origin to the head of vector B.

To find the vector difference A - B, draw the vector A with its tail at the origin and draw the vector -B with its tail at the head of vector A. The vector difference A - B is then the vector drawn from the origin to the head of vector -B.

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Read each of the phrases below. Put the phrases in the correct order to show the path of blood flow in the circulatory system starting with the blood traveling from the lungs.

____ blood picks up waste products such as carbon dioxide
____ carries oxygen and nutrients to the body cells
____ moves to right ventricle and to lungs
____ blood travels from the lungs to the left atrium
____ returns to right atrium

Answers

Answer:

blood picks up waste products such as carbon dioxide

returns to right atrium

moves to right ventricle and to lungs

blood travels from the lungs to the left atrium

carries oxygen and nutrients to the body cells

Explanation:

In the circulatory system, the blood carries the carbon dioxide to the right atrium of the heart through superior vena cava, then it move to right ventricle through tricuspid valve. The blood move to lungs following pulmonary artery and from lungs blood travels to the left atrium. From left atrium blood moves to the rest of the body through aorta and carries oxygen and nutrients to the whole body cells through.

Hence, the correct order is as follows:

blood picks up waste products such as carbon dioxide

returns to right atrium

moves to right ventricle and to lungs

blood travels from the lungs to the left atrium

carries oxygen and nutrients to the body cells

Can someone please help a struggling physics student?

A Physics student is running an experiment to test the kinematic equations that she learned over the week. She is throwing a ball with an initial velocity of +12.0 m/s in the vertical direction. Assume that the ball is thrown from the ground (i.e., neglect the student's height)

a) What is the maximum height the ball will reach in the air? Express your answer in m

What is the the velocity of the ball when it hits the ground? Express your answer in m/s.

Later that day, the student decided to repeat the experiment. This time, the weather was a little rough outside and there was a strong wind blowing in the horizontal direction (see figure). As a result of the wind, the horizontal component of the ball's velocity is + 2.3 m/s throughout the time it is in air (pointing to the right).

b) Assuming that the student throws the ball with the same initial upwards velocity as in part a), what will be the maximum height that the ball with reach in the presence of wind? Express your answer in m.

What is the magnitude of the velocity of the ball when it hits the ground? Express your answer in m/s

What is the direction of the velocity of the ball when it hits the ground? Express your answer in terms of the angle (in degrees ) of the ball's velocity with respect to the horizontal direction (see figure).

Can someone please help a struggling physics student?A Physics student is running an experiment to test

Answers

Part A:

What is the maximum height the ball will reach in the air?

Kinematics equation used:

\(v_f^2=v_i^2+2ad\), where \(v_f\) is final velocity, \(v_i\) is initial velocity, \(a\) is acceleration, and \(d\) is distance travelled. From SI units, velocity should be in \(m/s\), acceleration should be in \(m/s^2\), and distance should be in \(m\)

We're given that the initial velocity is 12.0 m/s in the y-direction. At the maximum height, the vertical velocity of the ball will be 0 m/s, otherwise it would not be at maximum height. This is our final velocity.

The only acceleration in the system is acceleration due to gravity, which is approximately \(9.8\:\mathrm{ m/s^2}\). However, the acceleration is acting down, whereas the ball is moving up. To express its direction, acceleration should be plugged in as \(-9.8\:\mathrm{m/s^2}\). We have three variables, and we are solving for the fourth, which is distance travelled. This will be the maximum height of the ball.

Substitute \(v_i=12\), \(v_f=0\), \(a=-9.8\) to solve for \(d\):

\(0^2=12^2+2(-9.8)(d),\\0=144-19.6d,\\-19.6d=-144,\\d=\frac{-144}{-19.6}=7.34693877551\approx \boxed{7.35\text{ m}}\)

What is the velocity of the ball when it hits the ground?

This question tests a physics concept rather than a physics formula. The vertical velocity of the ball when it hits the ground is equal in magnitude but opposite in direction to the ball's initial vertical velocity. This is because the ball spends equal time travelling to its max height as it does travelling from max height to the ground (ball is accelerating from initial velocity to 0 and then from 0 to some velocity over the same distance and time). Since the ball has an initial vertical velocity of +12.0 m/s, its velocity when it hits the ground will be \(\boxed{-12.0\text{ m/s}}\). (The negative sign represents the direction. Because velocity is a vector, it is required.)

Part B:

**Since my initial answer exceeds the character limit, I've attached the first question to Part B as an image. Please refer to the attached image for the answer and explanation to the first question of Part B. Apologies for the inconvenience.**

What is the direction of the velocity of the ball when it hits the ground? Express your answer in terms of the angle (in degrees ) of the ball's velocity with respect to the horizontal direction (see figure).

This question uses a similar concept as the second question of Part A. The vertical velocity of the ball at launch is equal in magnitude but opposite in direction to the ball's final velocity. The horizontal component is equal in both magnitude and direction throughout the entire launch, since there are no horizontal forces acting on the system. Therefore, the angle below the horizontal of the ball's velocity when it hits the ground is equal to the angle of the ball to the horizontal at launch.

To find this, we need to use basic trigonometry for a right triangle. In any right triangle, the tangent/tan of an angle is equal to its opposite side divided by its adjacent side.

Let the angle to the horizontal at launch be \(\theta\). The angle's opposite side is represented by the vertical velocity at launch (12.0 m/s) and the angle's adjacent side is represented by the horizontal velocity at launch (2.3 m/s). Therefore, we have the following equation:

\(\tan \theta=\frac{12.0\text{m/s}}{2.3\text{ m/s}}\)

Take the inverse tangent of both sides:

\(\arctan (\tan \theta)=\arctan (\frac{12.0}{2.3})\)

Simplify using \(\arctan(\tan \theta)=\theta \text{ for }\theta \in (-90^{\circ}, 90^{\circ})\):

\(\theta=\arctan(\frac{12.3}{2.3}),\\\theta =79.14989537\approx \boxed{79.15^{\circ}}\)

We can express our answer by saying that the direction of the velocity of the ball when it hits the ground is \(\boxed{\text{approximately }79.15^{\circ} \text{ below the horizontal}}\) or \(\boxed{\text{approximately }-79.15^{\circ} \text{ to the horizontal}}\).

Can someone please help a struggling physics student?A Physics student is running an experiment to test

What is the intensity of a sound wave?

Answers

Acoustic power, also known as sound intensity, is defined as the power transmitted by a sound wave per unit area in a direction perpendicular to that area.

More on sound wave

A sound wave is a type of energy that propagates in a medium by adiabatic charging and discharging. Important quantities for describing sound waves are sound pressure, particle velocity, particle displacement, and sound intensity.

Sound waves can be classified into three categories:

Longitudinal waves, mechanical waves, pressure waves.

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how much does it cost to light six 100w light bulbs for six hours if the price of electrical energy is $0.09/kwh?

Answers

It will cost 0.324 Dollars to light six 100w light bulbs for six hours if the price of electrical energy is $0.09/ kwh.

kwh is commercial unit of electric energy. 1 unit= 1 kwh.

When 100 w power device is run for 1 hour, the amount of electrical energy consumed is 1 kwh.

We will find total units of electrical energy consumed in the given question.

energy consumed by 6 bulbs = 6×100= 600 w( joules per second).

The value in kwh is = 600÷1000

                                = 0.6kwh

Total energy consumed in 6 hours is = 0.6×6 = 3.6 kwh

So, the cost is = 3.6×0.09 = 0.324 dollars.

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Answer question quick

Answer question quick

Answers

Answer:

Yes , insulation has no role

Your sister weights 725 N on Earth (g=9. 80 m/s^2). If you take her to the Mars (g=3. 72 m/s^2) find her mass on Mars

Answers

According to the given statement , your sister's mass on Mars is approximately 74.0 kg.

To find your sister's mass on Mars, we can use the formula:

Weight = Mass * Acceleration due to gravity

First, let's calculate your sister's mass on Earth using the given weight and acceleration due to gravity:

Weight on Earth = 725 N
Acceleration due to gravity on Earth = 9.80 m/s²

Using the formula, we can rearrange it to solve for mass:

Mass on Earth = Weight on Earth / Acceleration due to gravity on Earth

Substituting the values, we get:

Mass on Earth = 725 N / 9.80 m/s²

Calculating this, we find that your sister's mass on Earth is approximately 74.0 kg.

Next, let's calculate your sister's mass on Mars using the given weight and acceleration due to gravity:

Weight on Mars = ?
Acceleration due to gravity on Mars = 3.72 m/s²

Using the same formula, we can rearrange it to solve for mass:

Mass on Mars = Weight on Mars / Acceleration due to gravity on Mars

We know that weight is directly proportional to mass, so the ratio of the weights on Mars and Earth will be the same as the ratio of the masses on Mars and Earth:

Weight on Mars / Weight on Earth = Mass on Mars / Mass on Earth

Substituting the known values, we have:

Weight on Mars / 725 N = Mass on Mars / 74.0 kg

Simplifying this equation, we can cross multiply:

Weight on Mars * 74.0 kg = 725 N * Mass on Mars

Dividing both sides of the equation by 725 N, we get:

Weight on Mars * 74.0 kg / 725 N = Mass on Mars

Finally, substituting the given values, we can calculate your sister's mass on Mars:

Mass on Mars = (725 N * 74.0 kg) / 725 N

Simplifying this, we find that your sister's mass on Mars is approximately 74.0 kg.

Therefore, your sister's mass on Mars is approximately 74.0 kg.

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Manu took a pebble and a sheet of paper both weigh one gram. His friend told that if we drop both at the same time, the pebble will fall straight to the floor, while the paper will slowly drift to the ground. Do you think friction have any role in this case? How can we relate that to the topic which we are learning today?

Answers

Answer: friction has no role to play in this case. because friction usually occurs between to parts which come in contacts. examples (a)our joints in the human body (b)two mechanical parts (shafts).

Explanation:

However what this topic relates to is gravity. The pebble and paper both weigh one gram, but have different density this is the sole reason why if both are drop from same height the pebble would reach the ground faster than the paper because it is more denser. unlike the paper with a lesser density which would take a longer time to reach the ground.

what is the cost of operating a 86.13-watt freezer for a month if the cost of electricity is $ 0.02 per kwh? assume we take a month as 30 days. g

Answers

The cost of operating a 86.13-watt freezer for a month, assuming the cost of electricity is $0.02 per kilowatt-hour and a month has 30 days, would be $1.24.

To calculate the cost of operating a 86.13-watt freezer for a month, we need to first calculate the amount of energy it consumes in a month. We know that the power rating of the freezer is 86.13 watts, which means it consumes 0.08613 kilowatts of electricity every hour. In a day, the freezer would consume 2.07 kilowatt-hours (0.08613 kW x 24 hours). For a 30-day month, the total energy consumption would be 62.1 kilowatt-hours (2.07 kW x 30 days).

Now that we know the total energy consumption, we can calculate the cost of electricity. The cost of electricity is $0.02 per kilowatt-hour, which means the cost of operating the freezer for a month would be 62.1 kilowatt-hours x $0.02 per kilowatt-hour = $1.24.

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Guys I need help on this

Guys I need help on this

Answers

Answer:

I think its B.

Explanation:

What are the purposes of these items aboard the Voyager probes? • Low-energy particle detector: • Magnetometer boom: • High-gain antenna: • Photopolarimeter: • Cosmic ray:

Answers

Explanation:

1. Low-energy particle detector: This particle detector measures the charged particles of the solar winds.

2. Magnetometer boom: This device measures magnetic fields produced by astronomical bodies.

3. High-gain antenna: A HGA has a narrow radio beam that is used to enhance the strength of signal. They simply amplify the weak signals.

4. Photopolarimeter: This is an instrument that is used to measure the strength and intensity and polarization of reflected light.

Answer:

what they said

Explanation:

An inductor is connected to a 20 kHz oscillator that produces an rms voltage of 9.0 V. The peak current is 60 mA. What is the value of the inductance L? Final answer in mH. Please explain step by step.

Answers

The value of the inductance L is approximately 1193.25 mH.

To solve for the value of the inductance L, we can use the formula:

Vrms = Ipeak * (2 * pi * f * L)

where:

Vrms = 9.0 V

Ipeak = 60 mA = 0.06 A

f = 20 kHz

Substituting the values into the formula:

9.0 V = 0.06 A * (2 * pi * 20,000 Hz * L

Simplifying:

L = 9.0 V / (0.06 A * 2 * pi * 20,000 Hz)

L = 9.0 / (0.007536)

L = 1193.25 mH (rounded to two decimal places)

Therefore, the value of the inductance L is approximately 1193.25 mH.

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An inductor is connected to a 20 kHz oscillator that produces an RMS voltage of 9.0 V. The peak current is 60 mA. The value of the inductance L is  1.692 mH.

Let's start by using the given information and then we'll solve for the value of the inductance L step by step:
1. Frequency of the oscillator (f) = 20 kHz = 20,000 Hz
2. RMS voltage (Vrms) = 9.0 V
3. Peak current (I_peak) = 60 mA = 0.06 A
Now, let's find the peak voltage (V_peak) using the relationship between RMS voltage and peak voltage:
Vrms = V_peak / √2
V_peak = Vrms * √2
V_peak = 9.0 V * √2 ≈ 12.73 V
Next, we'll calculate the impedance (Z) of the inductor using Ohm's law, which relates peak voltage and peak current:
Z = V_peak / I_peak
Z ≈ 12.73 V / 0.06 A ≈ 212.17 Ω
Now, we'll use the formula for the impedance of an inductor:
Z = 2 * π * f * L
Let's solve for the inductance L:
L = Z / (2 * π * f)
L ≈ 212.17 Ω / (2 * π * 20,000 Hz)
L ≈ 1.692 × 10^-3 H
Finally, convert the inductance L to millihenries (mH):
L ≈ 1.692 mH
So, the value of the inductance L is approximately 1.692 mH.

To learn more about inductor, refer:-

https://brainly.com/question/15893850

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What type of wave is created here?
A) longitudinal
B) transverse

Help me plssss!!!

What type of wave is created here? A) longitudinal B) transverse Help me plssss!!!

Answers

Answer:

b

Explanation:

Answer:

this is a longitudinal wave!!!

Explanation:

because you can see the compressions and rarefactions.

A bicyclist with a mass of 50 kg is traveling at a rate of 30 m/s. It accelerates to a rate of 50 m/s in 5 seconds. What is the net force acting on the bicycle?

Answers

Answer:

200 N

Explanation:

There is only two needed factors in play here; the mass and acceleration

According to Newton's 2nd Law: F = m*a

Now Acceleration is Velocity over Time, so we have another factor in play: Acceleration = 50-30/5 = 20/5 = 4m/s^2

Net force = (50 kg)(4 m/s^2) = 50*4 = 200 Newtons

21. When air is blown into a balloon, it expands equally in all directions. The best explanation for this is (circle the correct answer): A - The gas molecules in the balloon are expanding B - Internal air pressure acts at right angles to the balloon surface. C - As more air is blown in, the temperature increases causing the balloon to expand.

Answers

Answer:

C

Explanation:

I would have said B but air pressure acts at ALL angles(directions). C makes sense because the increase in the temperature would cause the molecules to bounce off the walls of the balloon and each other which exerts pressure.

Answer:

C c hagwguawnjaahwbhanwbhsqn2nusbwvwf

A book of a mass 0.5kg is dropped from a height of 2.8m. How much mechanical energy does it have right before it hits the ground? (Assume there is no air resistance.) Acceleration due to gravity is g= 9.8 m/s^2.

Answers

Answer:

13.7 J

Explanation:

In absence of air resistance, the mechanical energy of the object is conserved during the fall: this means that the initial gravitational potential energy that it has at the beginning of the fall will be entirely converted into kinetic energy when the book is just about the hit the ground.

Therefore, this also means that we can calculate the mechanical energy at the beginning of the fall, as this will be equal to the mechanical energy just before the book hits the ground.

At the beginning of the fall, the mechanical energy is all gravitational potential energy:

where

m = 0.5 kg is the mass of the book

is the acceleration of gravity

h = 2.8 m is the height above the ground

Substituting,

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