The work done upon the cart and the subsequent potential energy change is 13.2 J.
Force on the cart that is being pulled = F = 20.8 N
Weight of cart that is being pulled = W = 3 Kg
Height of the inclined plane = h = 0.636 m
The work done upon the cart = w =
= w = F X h X cosθ
Here, the angle is zero and angle is denoted by 'θ'. Thus, θ = 0.
Therefore, work done = w =
= w = F X h X cosθ
= w = 20.8 X 3 X 1 [ as cosθ =1 ]
= w = 13.2 J
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Your driver's license is at risk of being cancelled if you: O A. Lied on the license application. O B. Are caught driving under the influence. O C. Cause an accident that injures another person. O D. Have more than three traffic violations in one year
Your driver's license is at risk of being cancelled if you have more than three traffic violations in one year. The correct option is D.
What is driving license?The license by the central government to an individual to travel on road by his own vehicle on terms and conditions to be strictly followed.
When a driver is moving with his vehicle and come across the traffic signal, he must follow them. If he violates the traffic signals more than three times, he will get his license cancelled.
Thus, your driver's license is at risk of being cancelled if you have more than three traffic violations in one year. The correct option is D.
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The inner planets have a smaller diameter than the outer planets.
True
False
Answer:true
Explanation:
No work is done if you push against the wall of a building.why?
Explanation:
Even though the man exerts force on the wall, the wall doesn't move . Work done= Force applied* displacement and since the displacement of the wall is zero., work done is also zero.
Tim rides at an average speed of 8 mph (mile per hour). How long does it take
for him to ride 44 miles h (show process)
Answer: 5.5 hours
Explanation: 44/8=5.5.
Answer:
5.5 Hours at 8mph to go 44 miles
Explanation:
d=s/t
t=s/d
44/8 = 5.5 time it took 5.5 hours it will take him to ride 44 miles
Energy must be measured in
Answer:
joule
Explanation:
hop it helps give a good rate ples
Answer:
joule
Explanation:
How much force is applied if a 130 kg mass is accelerated at 5 m/s^2
Answer:
650N
Explanation:
f = ma
130kg x 5 m/s^2 = 650N
You are freezing juice to make your own popsicles. Describe what happens on a molecular level as the juice freezes. Be sure to us e appropriate science vocabulary in your response.
Answer:
When water freezes to form ice, the molecules would be vibrating in place rather than moving round. It is a result of a decrease in the kinetic energy of the molecules of water. It is said that the temperature and the kinetic energy of the molecules is directly proportional which means that when temperature is increased, the kinetic energy of the molecules would increase as well making the molecules move around. However for this case, when we day the system is cooled then it means the temperature is decreased which would result to the decrease of the kinetic energy of the molecules.
Luminance has a higher sensitivity than chrominance in the human visual system (HVS). Chroma subsampling is thus a tool for video compression.
(i) List THREE (3) more subsampling techniques and their respective compression ratios. In the H.264 baseline profile, what subsampling scheme is employed?
Three subsampling techniques commonly used in video compression are: 4:2:0 subsampling, 4:2:2 subsampling and 4:1:1 subsampling.
4:2:0 subsampling: This technique reduces the resolution of the chrominance (color) components by sampling them at half the rate of the luminance (brightness) component. It achieves a compression ratio of 2:1.
4:2:2 subsampling: In this technique, the chrominance components are sampled at half the rate of the luminance component horizontally, but at full resolution vertically. It achieves a compression ratio of 2:1.
4:1:1 subsampling: This technique samples the chrominance components at one-fourth the rate of the luminance component horizontally. It achieves a compression ratio of 4:1.
In the H.264 baseline profile, the subsampling scheme employed is 4:2:0.
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A vector is 253 m long andpoints in a 55.8 degreedirection.Find the y-component of thevector.
The components of the vector v are given as:
\(\begin{gathered} v_x=v\cos \theta \\ v_y=v\sin \theta \end{gathered}\)where v is the magnitude of the vector and theta is the angle.
In this case we have v=253 and theta=55.8°, plugging this values into the y component we have:
\(\begin{gathered} v_y=253\sin 55.8 \\ v_y=209.25 \end{gathered}\)Therefore the y component is 209.25 meters.
I have a 10kg crate on top of a ramp that has a 30m long surface and rises 5m in the air. If the μk is .05, what is the speed at the bottom?
The speed at the bottom is 10 m/sec.
What is speed?The speed of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.
I have a 10kg crate on top of a ramp that has a 30m long surface and rises 5m in the air. If the μk is .05,
work = change in kinetic energy
mgh = 0.5 mv²
10*10*5 = 0.5 * 10 * v²
v = 10 m/sec
The speed at the bottom is 10 m/sec
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What angle is necessary to keep a 10 kg box motionless if the coefficient of static friction between the box and the ramp is 0.55?
a.33.4°
b.28.8°
c.56.6°
d.45.0°
The angle necessary to keep a 10 kg box motionless, given a coefficient of static friction of 0.55 between the box and the ramp, is 33.4°, which corresponds to Option A.
To determine the angle, we can use the relationship between the coefficient of static friction, the angle of the incline, and the gravitational force acting on the box. The maximum static friction force can be calculated using the formula:
Friction force = coefficient of static friction * Normal force
The Normal force can be found by decomposing the gravitational force acting on the box into components parallel and perpendicular to the incline. The perpendicular component (Normal force) is equal to the weight of the box (mass * gravitational acceleration).
Since the box is motionless, the friction force must be equal to the component of the gravitational force acting parallel to the incline:
Friction force = Component of weight parallel to incline
By substituting the given values and solving for the angle, we find:
coefficient of static friction = tan(angle)
angle = arctan(coefficient of static friction)
angle = arctan(0.55) ≈ 33.4°
Therefore, the correct answer is Option A, 33.4°.
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A 193.1g mass is hung from a 19.4g clamp on the right side of the stick, a 183.9 mass is hung from a 12.1g clamp on the left side of the meter stick. Determine the total torque from the unknown mass
The total torque created by the two known masses is 1.848 Nm.
How to calculate the torqueWe can use the formula for torque, which is given by:
τ = F x r x sin(θ)
where τ is the torque, F is the force applied, r is the distance from the pivot point to the point where the force is applied, and θ is the angle between the force and the lever arm.
For the first mass (193.1 g), the force applied is the weight of the mass, which is:
F1 = m1 x g = 0.1931 kg x 9.81 m/s^2 = 1.893 N
The distance from the pivot point to the point where the force is applied is half the length of the meter stick, which is:
r1 = L/2 = 0.5 m
The angle between the force and the lever arm is 90 degrees, so:
θ1 = 90 degrees
Using these values, we can calculate the torque created by the first mass as:
τ1 = F1 x r1 x sin(θ1) = 1.893 N x 0.5 m x sin(90 degrees) = 0.9465 Nm
For the second mass (183.9 g), we can follow the same procedure and find:
F2 = m2 x g = 0.1839 kg x 9.81 m/s^2 = 1.803 N
r2 = L/2 = 0.5 m
θ2 = 90 degrees
τ2 = F2 x r2 x sin(θ2) = 1.803 N x 0.5 m x sin(90 degrees) = 0.9015 Nm
The total torque created by the two known masses is the sum of these individual torques, which is:
τtotal = τ1 + τ2 = 0.9465 Nm + 0.9015 Nm = 1.848 Nm
Therefore, the total torque created by the two known masses is 1.848 Nm.
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snell's law depends on the refractive indexes of the materials as well as on the _____ of the angles of the light rays.
Snell's law depends not only on the refractive indexes of the materials but also on the "angle of incidence" and "angle of refraction" of the light rays.
Snell's law describes the relationship between the angles of incidence and refraction when light passes through the interface between two different materials. It states that the ratio of the sine of the angle of incidence to the sine of the angle of refraction is equal to the ratio of the refractive indexes of the two materials.
Mathematically, Snell's law is expressed as:
n₁ * sin(θ₁) = n₂ * sin(θ₂),
where n₁ and n₂ are the refractive indexes of the first and second materials, respectively, and θ₁ and θ₂ are the angles of incidence and refraction, respectively.
Therefore, the accurate determination of the angles of incidence and refraction is crucial for applying Snell's law to analyze the behavior of light as it passes through different media.
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If a pendulum makes exactly 60 oscillations in 15 seconds, then
its period is
a 0.500 s
b 0.05 s
c 0.25 S
d 2.5 s
Answer:
The answer is C 0.25s
Explanation:
T=60/15
T=4
p=1/T
P=1/4
P=0.25s
the mass of the fully fueled space shuttle is 16 times its empty mass. the space shuttle carries large amounts of fuel because it must keep firing its engine to stay in orbit.
B) The statement is false. The mass of the fully fueled space shuttle is not 16 times its empty mass.
While the space shuttle does carry large amounts of fuel, the increase in mass due to fuel is not as significant as implied in the statement.
The space shuttle is designed to carry both its own weight and the weight of the fuel required for its mission. However, the mass of the fuel is not equal to 16 times the empty mass of the shuttle. The actual ratio of the fully fueled mass to the empty mass depends on various factors, including the specific mission requirements and payload.
Fuel is necessary for the space shuttle to achieve and maintain orbit. Once in space, the shuttle uses its engines to counteract the gravitational pull of the Earth and stay in orbit. However, the amount of fuel needed is carefully calculated to optimize the shuttle's performance and achieve the desired mission objectives. Carrying excessive fuel would increase the mass and operational costs of the shuttle without providing significant benefits.
Therefore, while the space shuttle does carry a considerable amount of fuel, it is not accurate to say that its fully fueled mass is 16 times its empty mass.
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A 1.2kw toaster takes roughly 4 minutes to heat four slices of bread find the cost of operating the toaster once per day for 1 month assume energy cost 9cents/kwh
The electronic usage cost in 1 month is 21.6 cents.
The cost of electronic usage depends on the power of electronic devices. Power is the energy dissipated because of resistance. The magnitude of power is proportional to current and voltage. It can be determined as
P = I . V
where P is power, I is current and V is voltage.
The electrical energy can be calculated by using
E = P . t
where E is energy and t is time.
From the question above, we know that
P = 1.2 kW
cost = 9 cents/ kWh
t = 4 min = 4/60 hour
Find the energy consumed per day
E = P . t
E = 1.2 kW . 4/60
E = 0.08 kWh
Find the energy consumed per month
total energy = E x 30
total energy = 0.08 x 30
total energy = 2.4 kWh
Calculate monthly electronic cost
monthly cost = total energy x cost
monthly cost = 2.4 x 9
monthly cost = 21.6 cents
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Complete the following ---
Area of piston A: 0.01m^2
Force applied on piston A: 6N
Pressure in the liquid: ?
Area of piston B: 0.1cm^2
Force produced by piston B: ?
(note: there's a difference of m^2 and cm^2 in the areas so it's difficult for me...)
Answer: The force produced by piston B is 0.006 N.
Explanation:
No problem! We can convert the area of piston B to square meters to make the units consistent:
Area of piston B = 0.1 cm^2 = 0.1 x (0.01 m/cm)^2 = 0.00001 m^2
Now we can use the formula:
pressure = force/area
For piston A, we have:
pressure = 6 N / 0.01 m^2 = 600 Pa
So the pressure in the liquid is 600 Pa.
To find the force produced by piston B, we rearrange the formula:
force = pressure x area
Using the pressure we just found and the area of piston B, we get:
force = 600 Pa x 0.00001 m^2 = 0.006 N
So the force produced by piston B is 0.006 N.
A thin uniform disk of mass m and radius r has a string wrapped
The magnitude of the weight of the disk is greater than the magnitude of the tension force of the string. ((c) \(F_{T} < F_{g}\))
How to analysis a rigid body on dynamical conditionA rigid body is a system whose geometry cannot be neglected and in which deformations due to external forces applied on the system are negligible.
In this question we need to establish a free body diagram with all critical forces and motion conditions. There are two external forces: (i) tension (\(F_{T}\)), (ii) weight (\(F_{g}\)), both in newtons.
The disk falls due to gravity and rotates around the string in a case of rolling, which combines rotation and translation. By Newton's laws of motion we have the following expression:
\(\sum F = -F_{g}+F_{T} = -m\cdot R\cdot \alpha\) (1)
Where:
\(m\) - Mass of the disk, in kilograms.\(\alpha\) - Angular acceleration, in radians per square second.By algebra we derive the following relationship between the two forces:
\(-F_{g} = -F_{T}-m\cdot R\cdot \alpha\)
\(F_{g} > F_{T}\)
Therefore, the magnitude of the weight of the disk is greater than the magnitude of the tension force of the string. ((c) \(F_{T} < F_{g}\)) \(\blacksquare\)
Remark
The statement is incomplete and poorly formatted. Correct and complete form is shown below:
A thin uniform disk of mass m and radius r has a string wrapped around its edge and attached to the ceiling. The bottom of the disk is at height 3R above the floor, as shown above. The disk is released from rest. The rotational inertia of a disk around its center is \(I = \frac{1}{2}\cdot M\cdot R^{2}\).
When released from rest, the disk falls and the string unwinds. The force that the string exerts on the disk is \(F_{T}\), and the gravitational force exerted on the disk is \(F_{g}\). Which of the following expression correctly relates \(F_{T}\) and \(F_{g}\) as the disk falls?
(a) \(F_{T} > F_{g}\), (b) \(F_{T} = F_{g}\), (c) \(F_{T} < F_{g}\)
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How do the echoes of the sounds of animals help them?
Answer:
Echolocating animals emit calls out to the environment and listen to the echoes of those calls that return from various objects near them. They use these echoes to locate and identify the objects. Echolocation is used for navigation, foraging, and hunting in various environments.
Light from a red laser passes through a narrow single slit to form a diffraction pattern. If the width of the slit is increased, what happens to the central maximum? The central maximum shifts to downward on the screen. The width of the central maximum decreases. The width of the central maximum does not change. The central maximum shifts to upward on the screen. The width of the central maximum increases. Two identical light waves, A and B, are emitted from different sources and meet at a point P. The distance from the source of A to the point P is L_A, and the source of B is a distance L_B from P. Which of the following statements is necessarily true concerning the interference of the two waves? A and B will interfere constructively because their amplitudes are the same. A and B will interfere destructively if L_A > L_B. A and B will interfere constructively because their wavelengths are the same. A and B will interfere constructively If L_A - L_B = m lambda, where m = 1/2, 3/2, 5/2, ... A and B will interfere constructively it L_A - L_B = m lambda, where m = 0, 1, 2, 3.... A beam of light passes from air into water. Which is necessarily true? The wavelength is unchanged, and the frequency decreases. The frequency is unchanged, and the wavelength decreases. The wavelength is unchanged, and the frequency increases. The frequency is unchanged, and the wavelength increases. Both the wavelength and the frequency decrease. Both the wavelength and the frequency increase.
If the width of the slit through which light from a red laser passes to form a diffraction pattern is increased, the width of the central maximum increases.
In the phenomenon of diffraction, light bends around the edges of obstacles or through the edges of an aperture or a slit. The pattern formed on a screen placed on the other side of the obstacle or slit is referred to as a diffraction pattern. In a diffraction pattern formed by a narrow single slit through which light from a red laser passes, the central maximum is the bright region at the center of the pattern.
The intensity of the light in the central maximum is the highest of all the diffraction maxima.The width of the central maximum increases as the width of the slit through which light from a red laser passes to form a diffraction pattern is increased. This is because when the slit width is increased, the amount of diffraction of light increases. The greater the diffraction, the wider the central maximum.
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A cannonball is launched off a 100 m cliff horizontally with an initial velocity of 50 m/s. The goal is to have the cannonball travel a target distance of 400m. Based on this, will the cannonball reach the target distance?.
The pace at which an object's location shifts when seen from a particular angle and measured against a particular interval of time is referred to as its velocity.
What is initial and final velocity?When gravity first exerts force on an object, its initial velocity defines how quickly the object moves. The final velocity, on the other hand, is a vector number that gauges a moving body's speed and direction after it has reached its maximum acceleration.
No, it won't hit the intended objective.
The concept of velocity refers to the rate and direction of motion of a point. For instance, the orientation of a circular path is always perpendicular to the line that connects a point to the center of the circle.
No, the cannonball won't reach the target.
the settings provided;
cliff height, h = 100 m cannon's target distance, R = 400 m starting horizontal velocity, or = 50 m/s
The amount of time it takes for the cannonball to fall from the specified height is provided by:
h = voyt + gt2
1000+0.5 x 9.8 x 12 100= 4.9/2
12- 100 = 4.9
t=20.41
t = 4.52
The cannon ball's horizontal distance at this point is computed as follows:
X = vor xt
X= 50 x 4.52
X = 226 m
Less than the 400 m goal distance is 226 m.
As a result, we may infer that the cannon ball will miss its target.
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PLEASE ANSWER QUICK!
Meiosis is a process that contributes to______
A. the production of somatic cells.
B. asexual reproduction.
C. creation of organisms with unique characteristics.
to start something moving, a push force must be ______ than resisting forces such a friction. what word complets the gap?
Answer:
To start something moving, a push force must be greater than resisting forces such a friction.
Explanation:
The force of resistance, for example friction, slows things down, so the push force must be greater in order to increase the speed or to start something moving.
Which natural science studies motion and forces?
a.
Mathematics
b.
Biology
c.
Chemistry
d.
Physics
Answer:
Physics
Explanation:
:):):)
Wind turbines work by converting __________ energy into _________ energy.
A. Chemical, Electromagnetic
B. Potential, Kinetic
C. Kinetic, Electric
D. Electric, Chemical
Answer: C
Explanation:
The kinetic energy of the wind turns the turbine which creates kinetic energy of it's own, this rotational kinetic energy can be called mechanical energy and is used to create electricity
Once a rock has become either igneous, sedimentary, or metamorphic it stays that way forever.
Responses
True
False
Answer:
True
Explanation:
3. According to the article, what is an effect
of migration from rural areas to cities?
a Colleges need to hire more faculty.
The country's infrastructure is burdened.
c Citizens are more likely to migrate to other countries.
The percentage of the population living in extreme
poverty goes down.
"The percentage of the population living in extreme poverty goes down." Therefore, option (D) is correct.
Migration from rural areas to cities can have a positive impact on poverty reduction. Urban areas often offer better access to job opportunities, education, healthcare, and social services, which can help individuals and families improve their living conditions.
As people migrate to cities and gain access to these resources, the percentage of the population living in extreme poverty tends to decrease.
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What does addition of two vectors give you?
Answer:
Explanation:
To add or subtract two vectors, add or subtract the corresponding components. Let →u=⟨u1,u2⟩ and →v=⟨v1,v2⟩ be two vectors. The sum of two or more vectors is called the resultant. The resultant of two vectors can be found using either the parallelogram method or the triangle method .
i need help!
Which condition of the eye is most likely to be responsible for each of these problems? a: A student who can read the whiteboard from the back of the room but has to strain to read the print in a textbook and gets headaches while reading from a computer screen at home b: A science teacher who has never had eye problems before begins to find it easier to read books and newspapers when they are held further away
Answer:
B Is not a problem
But A is
Explanation:
its either he is long sighted
so he is able to read from far and not near so it's better he sees a doctor to get recommend glasses
A 8.0\,\text {kg}8.0kg8, point, 0, start text, k, g, end text box is released from rest at a height y_0 =0.25\,\text my 0 =0.25my, start subscript, 0, end subscript, equals, 0, point, 25, start text, m, end text on a frictionless ramp. The box slides from the ramp onto a rough horizontal surface. The box slides 2.0\,\text m2.0m2, point, 0, start text, m, end text horizontally until it stops.
Answer:
μ = 0.125
Explanation:
To solve this problem, which is generally asked for the coefficient of friction, we will use the conservation of energy.
Let's start working on the ramp
starting point. Highest point of the ramp
Em₀ = U = m h y
final point. Lower part of the ramp, before entering the rough surface
\(Em_{f}\) = K = ½ m v²
as they indicate that there is no friction on the ramp
Em₀ = Em_{f}
m g y = ½ m v²
v = \(\sqrt{2gy}\)
we calculate
v = √(2 9.8 0.25)
v = 2.21 m / s
in the rough part we use the relationship between work and kinetic energy
W = ΔK = K_{f} -K₀
as it stops the final kinetic energy is zero
W = -K₀
The work is done by the friction force, which opposes the movement
W = - fr x
friction force has the expression
fr = μ N
let's write Newton's second law for the vertical axis
N-W = 0
N = W = m g
we substitute
-μ m g x = - ½ m v²
μ = \(\frac{v^{2} }{2 g x}\)
Let's calculate
μ = \(\frac{2.21^{2}}{2\ 9.8\ 2.0}\)
μ = 0.125
A 8.0 kg box is released from rest at a height y0 = 0.25 m on a frictionless ramp. The box slides from the ramp onto a rough horizontal surface. The box slides 2.0 m horizontally until it stops.
What is the friction coefficient of the horizontal surface?
Answer: 0.125