explain how iodine can be obtained from iodine-sodium chloride mixture

The downward slope represents the relation between durability of titanium and temperature because with increase temperature, strength of titanium decreases.

Titanium alloys have high tensile strength to weight ratio, good toughness and an ability to bear extreme temperatures of more than 600 °Celsius. This shows that if temperature increase from more than 600 °Celsius, the strength of the titanium tends to decrease because it can not withstand to it so the graph comes to downward when the temperature exceeds to 600°C.

So we can conclude that the downward slope represents the relation between durability of titanium and temperature because with increase temperature, strength of titanium decreases.

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Answer:

i should be A i hope this helps

Explanation:

Answer: 0.024 ml of hydrogen gas are collected at \(18.5^0C\) and 755.5mmHg in this single replacement reaction

Explanation:

To calculate the moles :

\(\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}\)    

\(\text{Moles of} Ba=\frac{85.0g}{137g/mol}=0.620moles\)

To calculate the number of moles for given molarity, we use the equation:

\(\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution in ml}}\)  

\(3.55M=\frac{\text{Moles of} HCl\times 1000}{275ml}\\\\\text{Moles of }HCl=\frac{3.55\times 275}{1000}=0.976mol\)

The balanced chemical reaction is:

\(Ba+2HCl\rightarrow BaCl_2+H_2\)

According to stoichiometry :

2 moles of \(HCl\) require = 1 mole of \(Ba\)

Thus 0.976 moles of \(HCl\) will require=\(\frac{1}{2}\times 0.976=0.488moles\) of \(Ba\)

Thus \(HCl\) is the limiting reagent as it limits the formation of product and \(Ba\) is the excess reagent.

As 2 moles of \(HCl\) give = 2 moles of \(H_2\)

Thus 0.976 moles of \(HCl\) give =\(\frac{2}{2}\times 0.976=0.976moles\)  of \(H_2\)

According to ideal gas equation:

\(PV=nRT\)

P = pressure of gas = 755.5 mmHg = 0.994 atm   (760 mm Hg = 1 atm )

V = Volume of gas in L = ?

n = number of moles = 0.976

R = gas constant =\(0.0821Latm/Kmol\)

T =temperature =\(18.5^0C=(18.5+273)K=291.5K\)

\(V=\frac{nRT}{P}\)

\(V=\frac{0.994atm\times 0.0820 L atm/K mol\times 291.5K}{0.994atm}=24.0L=0.024ml\)    (1L=1000ml)

Thus 0.024 ml of hydrogen gas are collected at \(18.5^0C\) and 755.5mmHg in this single replacement reaction

The experimental rate law for the given reaction is determined to be Rate = \(k[X][Y_2]\). The analysis of concentration changes indicates that the rate is directly proportional to the concentrations of both \(X\) and \(Y_2\), option A is correct.

To determine the experimental rate law, we need to analyze the effect of concentration changes on the rate of the reaction. Let's compare Experiments 1 and 2 while keeping the concentration of \(X\) constant:

Experiment 1:

\([X]_i = 0.15 M\)

\([Y_2]_i = 0.10 M\)

Rate = 32 M/s

Experiment 2:

\([X]_i = 0.15 M\)

\([Y_2]_i = 0.20 M\)

Rate = 64 M/s

We can see that doubling the concentration of \(Y_2\) (from 0.10 M to 0.20 M) results in a doubling of the rate. This suggests that the rate is directly proportional to the concentration of \(Y_2\).

Now, let's compare Experiments 2 and 3 while keeping the concentration of \(Y_2\) constant:

Experiment 2:

Rate = 64 M/s

Experiment 3:

\([X]_i = 0.30 M\)

\([Y_2]_i = 0.20 M\)

Rate = 128 M/s

We can see that doubling the concentration of \(X\) (from 0.15 M to 0.30 M) results in a doubling of the rate. This suggests that the rate is directly proportional to the concentration of \(X\).

Based on these observations, we can conclude that the rate law is:

Rate = \(k[X][Y_2]\)

Therefore, the correct answer is A) Rate = \(k[X][Y_2]\).

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The complete question is:

\(2X+Y_2\) → \(X_2Y_2\)

A chemist is studying the reaction between the gaseous chemical species \(X\) and \(Y_2\), represented by the equation above. Initial rates of reaction are measured at various concentrations of reactants. The results are recorded in the following table

Given the information in the table above, which of the following is the experimental rate law?

A) Rate = \(k[X][Y_2]\)

B) Rate = \(k[X]^2[Y_2]\)

C) Rate = \(k[X][Y_2]^2\)

D) Rate = \(k[X]^2[Y_2]^2\)

Answer:

C

Explanation:

I got A wrong so maybe

Answer:

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Explanation:

quieropapas

1. An increase in concentration increases the speed of reaction.

2. When temperature increases, average speed of molecules increases.

3. Average kinetic motion of molecules in a solution can be measured by measuring the heat in the solution.

As concentration increases, number of molecules in the solution increase, hence the reaction becomes faster. Since these factors increase in value, the frequency of collisions between the reactant molecules in the solution will increase, so the probability of collisions in right orientation and with right energy will be higher. Increase in temperature will increase the average speed and kinetic energy of the  molecules in solution. At constant volume, increased speed of reactant molecules in the solution will increase the probability of collisions in right orientation and right energy. Average kinetic energy of molecules in a solution can be measured using the equation, E=kT , where k = Boltzmann constant.

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Answer:

Accurate but not precise

Explanation:

The sample of balloon bags can be described as being accurate but not precise.

Recall that accuracy is the closeness of measurements to their true values while precision is the closeness of repeated measurement.

The balloon bags are accurate because it appears that the number of balloons in each bag is not far from the actual number of balloons that should be in them - exactly 100 in one and a few off in others. By the time the average number of balloons is calculated, it will not be far off from 100, if not exactly 100.

However, the sample bags are described as not being precise because of the inconsistency or lack of closeness in the number of balloons in each of them.

Answer:

Physicol properties can be extensive or intensive. Extensive properties vary with the amount of the substance and include mass, weight, and volume

Explanation:

The dye, the rate constant can be Solution 1 is 0.0075 min-1 and for Solution 2 is 0.0060 min-1.

A constant is a fixed value that does not change over time. It is often used to represent a necessary part of a program, such as a mathematical constant or a physical constant, like the speed of light. In programming languages, constants are usually declared with the keyword "const" or "define". Constant values are typically used to create functions or calculations that are not affected by changing values of other variables or constants.

The rate constant, k, is calculated using the equation:
k = (change in concentration of dye)/(time)(initial concentration of dye)^order of reaction
For the first graph, which indicates a first order reaction with respect to the dye, the rate constant can be calculated as follows:
Solution 1: k = (1.8 - 0.4) / (240)(0.4) = 0.0075 min-1
Solution 2: k = (1.8 - 0.4) / (300)(0.4) = 0.0060 min-1

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Answer:

reask the question plz

Explanation:

plz like and give it rating it would help a lot to me

Answer:C - 3.115 g

Explanation:Correct

Answer:

n = 0.223 mol.

Explanation:

Hello there!

In this case, according to the given information, it is possible for us to approach this problem via the ideal gas law, which involves the pressure, moles, temperature and volume of the gas:

\(PV=nRT\\\\\)

Thus, by solving for moles we obtain:

\(n=\frac{PV}{RT}\)

Therefore, we plug in the given volume, temperature (in Kelvins) and pressure to obtain:

\(n=\frac{0.9atm*8L}{0.08206\frac{atm*L}{mol*K}*(120+273)K} \\\\n=0.223mol\)

Best regards!

The enthalpy change for the reaction CaCO3 (s) -> CaO (s, graphite) + O2 (g) is 571.6 kJ.

The enthalpy of the reaction CaCO3 (s) -> CaO (s, graphite) + O2 (g) can be calculated by summing the enthalpies of the individual reactions involved. The given information provides the enthalpy change for the decomposition of CaCO3 (s) and the combustion of C (s) to form CO2 (g). By combining these reactions, the enthalpy change for the overall reaction can be determined.

The given reactions are:

CaCO3 (s) -> CaO (s) + CO2 (g) (H = 178.1 kJ)

C (s, graphite) + O2 (g) -> CO2 (g) (H = -393.5 kJ)

To calculate the enthalpy change for the reaction CaCO3 (s) -> CaO (s, graphite) + O2 (g), we need to subtract the enthalpy change of reaction 2 from the enthalpy change of reaction 1. Since the enthalpy change is an extensive property, we can subtract the enthalpies directly:

ΔH = H(reaction 1) - H(reaction 2)

= 178.1 kJ - (-393.5 kJ)

= 178.1 kJ + 393.5 kJ

= 571.6 kJ

Therefore, the enthalpy change for the reaction CaCO3 (s) -> CaO (s, graphite) + O2 (g) is 571.6 kJ.

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Answer:

A. Things are measured the same way each time.

Explanation:

the aldol condensation of menthone and anisaldehyde can be monitored by tlc and each starting material and product gave a distinct spot on the plate.

if the Rf value is low the concentration is higher if the Rf value is high its highly soluble and will move faster.

Aldol condensation is a term used to describe a chemical reaction in which an enolate ion combines with a carbonyl compound to produce either a hydroxy ketone or an aldehyde, which is then dehydrated to produce a conjugated enone.

After running a TLC, scientists frequently cannot simply see where compounds are situated since organic compounds typically appear colorless on the white background of a TLC plate. After elution, the chemicals must be momentarily transformed into something visible, or "visualized."

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Answer

- What is an electron?

An electron a stable subatomic particle with a negative charge of electricity, it is found in all atoms and acting as the primary carrier of electricity in solids.

- How does the electrons movement creates an electric current?

Electrons flow in a certain rate, creating an electric current. So the electrons moving freely from one place to another place will conduct electric current.

the atomic radius is 0.144 nm.

Given:

FCC structure. Lattice constant = a = 0.40788 nm.

Atomic radius = r.

According to the definition of the FCC structure, there are 4 atoms per unit cell.

So, the length of the face diagonal can be found as follows:

a√2 = 0.40788 nm√2a = 0.40788 nm/√2a = 0.288 nm

From this, the radius can be calculated:

r = a/2r = 0.288 nm/2r = 0.144 nm

Therefore, the atomic radius is 0.144 nm.

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Cumulus is known as fair-weather clouds because they usually indicate fair, dry conditions. If there is precipitation, it is light. The clouds have a flattish base with rounded stacks or puffs on top. When the puffs look like cauliflower heads they’re called cumulus congestus or towering cumulus. They can get very high.

They are Mid-level clouds. The bases of these clouds form at about 2000–6200 m above sea level. They are mostly made of water droplets but can contain ice crystals. The clouds are often seen as bluish-grey sheets that cover most, if not all, of the sky. They can obscure the Sun

cumulus – meaning heap or pile, cumulus indicates fair weather, often popping up on bright sunny days.

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The new temperature of the neon gas is 151.45°C when the pressure changes to 145 kPa and the volume remains constant.

Assuming that the amount of neon gas remains constant, we can use the combined gas law to find the new temperature. The combined gas law states that:

(P1 x V1) / T1 = (P2 x V2) / T2

where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2, V2, and T2 are the final pressure, volume, and temperature, respectively. We are given P1 = 123 kPa, T1 = 89°C = 362 K, V1 = V2 (since the volume remains constant), and P2 = 145 kPa. Substituting these values into the combined gas law equation gives:

(123 kPa x V) / 362 K = (145 kPa x V) / T2

Simplifying this equation by cross-multiplying and rearranging gives:

T2 = (145 kPa x 362 K) / 123 kPa

T2 = 424.6 K

Finally, we can convert the temperature from Kelvin to Celsius by subtracting 273.15:

T2 = 424.6 K - 273.15

T2 = 151.45°C

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The ph of an aqueous solution that contain 2.50 × 10⁻⁴m hydronium ion is 3.60

To measure the ph we have

pH = -log (H₃O⁺)

     = -log (2.5 × 10⁻⁴ )

     = 3.60

Hence the ph of the aqueous solution is 3.60

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Answer:

d. The air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down.

Explanation:

hopes this helps  

                                                      sorry if it doesn't

:)

Oxidation D) occurs when the electrons are lost from an atom or compound. Oxidation refers to a chemical reaction where there is a transfer of electrons from one substance to another.

During oxidation, the substance that loses electrons is known as the reducing agent while the substance that gains electrons is known as the oxidizing agent. When an atom or compound loses electrons during oxidation, it becomes more positively charged, and this results in a decrease in its negative charge.

For example, when iron rusts, it undergoes oxidation as it loses electrons to oxygen. The iron atoms lose their electrons, and as a result, they become positively charged. This causes the iron compound to have a more positive charge than it did before the oxidation process.

In summary, oxidation occurs when electrons are lost from an atom or compound, which results in a decrease in the negative charge of the compound or atom.

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Answer:

6 mols H2 are needed

Explanation:

N2 = 28.01g/mol

H2 = 2.02g/mol

\(\frac{2 mol N_{2} }{1}\) * \(\frac{3 mol H_{2} }{ 1 mol N_{2} }\) = 6 mol H2

In the bicarbonate buffering system, carbon dioxide and water join to form carbonic acid, which dissociates into hydrogen and bicarbonate.

A buffer solution resists the changes in acidity by combining with the hydrogen ions that were added and inactivates them. It is a solution of weak acid and its conjugate base, (carbonic acid and bicarbonate). The natural conversion of carbon dioxide into carbonic acid is slow.

Bicarbonate buffer absorbs hydrogen ions and forms carbonic acid. The total number of hydrogen ions and hence the pH of the solution does not change. Bicarbonate is consumed and carbonic acid is produced when hydrogen ions are added.

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To synthesize (3E,5E)-3,5-octadiene-1,8-diol from 3,5-hexadiyn-1-ol, the following reagents should be used:

1. Lithium aluminum hydride (LiAlH4): This reagent can be used to reduce the alkyne group in 3,5-hexadiyn-1-ol to form a diol.
2. Hydrogen gas (H2) and a suitable catalyst such as palladium on carbon (Pd/C): This reagent combination can also be used to reduce the alkyne group in 3,5-hexadiyn-1-ol to form a diol.
By using either of these reagents, the alkyne group in 3,5-hexadiyn-1-ol can be selectively reduced, resulting in the formation of (3E,5E)-3,5-octadiene-1,8-diol.

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The gravity force on an object from the Earth is the same regardless of whether the object is surrounded by air .

the Earth has an average gravitational force. Different locations on Earth have gravitational forces that are larger or smaller than average. This is because each location has more or less mass than the average

******************* ijustwantthepoints *************************

(a) To get the pH of the media to 5.8, you would add NaOH solution. NaOH is used as a basic solution, and when it is added to a solution, it will increase the pH of the solution.

(b) The molecular weight of BA is 225.3. To prepare a 1M solution, you would have to weigh out 225.3 grams of BA.(c) To convert a 1M solution of BA to mg/mL, you can use the following equation: 1 mole = molecular weight in grams; 1000 millimoles = 1 mole. So, 1 M = 1000 mg/mL. Therefore, a 1M solution of BA is equivalent to 1000 mg/mL .(d) To convert a concentration of 1000 mg/mL .

Therefore, to calculate the weight required for a 5 mM solution, use the following formula :Mass of BA = molarity × volume × molecular weight= 5 × 0.001 × 225.3= 1.1265 grams(f) To convert a concentration of 5 mM to mg/mL, we use the following formula: Concentration (mg/mL) = (Concentration (mM) × Molecular weight) / 1000= (5 × 225.3) / 1000= 1.1265 mg/mL(g)

To convert a concentration of 1.1265 mg/mL to mg/L, we multiply by 1000, so 1.1265 mg/mL = 1126.5 mg/L.(h) Given that the stock solution of BA is 5 mM and the working solution is 0.2 mg/mL.

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