Dr. Suwary runs really fast. She is in a race and is running at 50 m/s. Dr. Suwary's enemy is
starting to catch up so Dr. Suwary, decides to accelerate at 50 m/s? to a new velocity of
100 m/s. How long does it take?

The wavelength of the wave shown in the image is approximately 0.0018 m.

we can see that there are two points marked as "A" on the string, which represents two consecutive peaks of the wave. The distance between these two points is 45 m.

The wavelength of a wave is the distance between two consecutive peaks or troughs of the wave. Therefore, in this case, the wavelength is simply the distance between the two points marked as "A".

Using the ruler provided in the image, we can measure the distance between the two points marked as "A" to be approximately 0.18 cm. However, this measurement is not in meters, which is the standard unit for measuring wavelength.

To convert the measurement to meters, we need to divide it by 100, since there are 100 centimeters in 1 meter. Therefore, the distance between the two points marked as "A" is:

0.18 cm ÷ 100 = 0.0018 m

So the wavelength of the wave shown in the image is approximately 0.0018 m.

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The resultant of the displacement is 336.5m

The process of splitting a vector into its components is called resolution of the vector. The vectors are splitted into vertical and horizontal component.

For the first displacement;

The vertical component = - 150 sin45 = -106.1 m

The horizontal component = - 150 cos 45° = -106.1 m

For the second displacement;

The vertical displacement = - 85sin90 = -85

The horizontal component = 0

For the third displacement;

The vertical displacement = 550 sin55 = 450.5

The horizontal displacement = 550 cos 55 = 315.5

Sum of vertical component = 450.5-85-106.1 = 263.4

sum of horizontal component = 315.5 -106.1 = 209.4

Using Pythagorean theorem

R = √ 263.4² + 209.4²

R = √113227.92

R = 336.5m

The resultant angle = tan^-1( 263.4/209.4)

= tan^-1(1.26)

= 51.56°

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The pressure of the tank, when filled with water at a depth of 6 m, is approximately 580.124 atmospheres (atm). To calculate the pressure of the tank, one can use the equation: Pressure (P) = Density (ρ) × g × Depth (h)

Pressure (P) = Density (ρ) × g × Depth (h)

Given: Density of water (ρ) = 1000 kg/m³

Acceleration due to gravity (g) = 9.8 m/s²

Depth (h) = 6 m

Using the given values, one can calculate the pressure:

Pressure = 1000 kg/m³ × 9.8 m/s² × 6 m Pressure

= 58800 kg·m⁻¹·s⁻²

Now, let's convert the units to pascals (Pa) using the conversion 1 atm = 1.013 x \(10^5\) Pa:

Pressure = 58800 kg·m⁻¹·s⁻² × (1 atm / 1.013 x\(10^5\) Pa)

Pressure = 580.124 atm

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Over time, these tiny fragments will pile up at the bottom of the river and form sediment. Sedimentation can cause the formation of new rocks or change the structure of existing rocks by burying them.

The water in a fast-moving river causes rocks to bump and scrape against one another. As the rocks scrape against each other, they break off tiny pieces from their surface.

Over time, these tiny fragments will pile up at the bottom of the river and form sediment. Sedimentation can cause the formation of new rocks or change the structure of existing rocks by burying them.

The rocks are going to get smaller and rounder, which is why rocks in fast-moving rivers are usually smoother than rocks in slow-moving water.

The erosion process can also form potholes or other unique shapes in rocks. Furthermore, fast-moving water can push rocks downstream, where they may settle in a new location or be washed away entirely.

The movement of rocks in a river can also change the shape and structure of the riverbed. When rocks are removed from a river, the water may begin to flow differently, which can cause erosion in other areas.

In summary, the rocks will get smaller and smoother over time due to the constant erosion and sedimentation caused by the water in the fast-moving river.

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Answer:

The force of gravity on an object depends on the mass of the object and the mass and distance of the celestial body it is on or near. The formula for the force of gravity is:

F = G * (m1 * m2) / r^2

where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them.

To compare the force of gravity on an 81 kg mass on the Moon's surface with the force on the Earth's surface, we need to calculate each force using the above formula and then compare the results.

First, let's calculate the force of gravity on an 81 kg mass on the Earth's surface:

F_Earth = G * (m1 * m2) / r^2

= 6.67 x 10^-11 Nm^2/kg^2 * (81 kg * 5.97 x 10^24 kg) / (6.38 x 10^6 m)^2

= 7.92 x 10^2 N

So the force of gravity on an 81 kg mass on the Earth's surface is 792 N.

Next, let's calculate the force of gravity on an 81 kg mass on the Moon's surface:

F_Moon = G * (m1 * m2) / r^2

= 6.67 x 10^-11 Nm^2/kg^2 * (81 kg * 7.35 x 10^22 kg) / (1.74 x 10^6 m)^2

= 1.32 x 10^3 N

So the force of gravity on an 81 kg mass on the Moon's surface is 1320 N.

Therefore, the force of gravity on the Moon's surface is greater than the force of gravity on the Earth's surface. The ratio of F_Earth to F_Moon is:

F_Earth / F_Moon = 792 N / 1320 N

= 0.6

So the force of gravity on the Moon's surface is about 60% of the force of gravity on the Earth's surface.

Answer:

Explanation:

work done=force*displacement

=350N*15m

=5250 joule

Answer:

Researchers use a wide range of technologies today to help gather data, depending on the field of study and the type of data they need to collect. Here are some examples:

   Sensors: Sensors are devices that can detect and measure physical quantities such as temperature, pressure, and motion. Researchers use sensors to collect data on the environment, human behavior, and other phenomena.

   Drones: Drones or unmanned aerial vehicles (UAVs) are aircraft that are remotely controlled or can fly autonomously. Researchers use drones to collect data from hard-to-reach or dangerous areas, such as remote forests, volcanoes, or disaster zones.

   Satellites: Satellites are spacecraft that orbit the Earth and can collect data on a wide range of environmental and climatic factors, such as temperature, rainfall, and ocean currents. Researchers use satellite data to study climate change, natural disasters, and other global phenomena.

   Imaging technologies: Imaging technologies such as magnetic resonance imaging (MRI) and computed tomography (CT) scans are used to collect detailed images of the body's internal structures. Researchers use these images to study the human brain, diagnose diseases, and develop new medical treatments.

   Social media and online platforms: Social media and online platforms provide researchers with access to large amounts of data on human behavior, opinions, and attitudes. Researchers use this data to study social trends, political movements, and public opinion.

   Wearable technology: Wearable technology such as fitness trackers and smartwatches collect data on physical activity, heart rate, and other health metrics. Researchers use this data to study human health and behavior.

These are just a few examples of the many technologies researchers use today to help gather data. The use of advanced technology has revolutionized the way researchers collect and analyze data, allowing them to make new discoveries and gain a deeper understanding of the world around us.

Answer:

P = 198.118 kPa

Explanation:

Given:

Atmospheric pressure = P\(_{atm\\}\) = 1.01×10⁵

depth = h = 9.91 m

To find:

Absolute pressure P\(_{abs}\)

Solution:

Density of water = ρ = 1.000x10 ³kg/m ³

acceleration due to gravity = ρ = 9.8 m/s²

P\(_{abs}\) = P\(_{atm\\}\) + ρgh

      = 1.01×10⁵ + 1.000x10 ³x 9.8 x 9.91

      = 101000 + 1000(9.8)(9.91)

      = 101000 + 97118

      = 198118 Pa

      = 198.118 kPa

P\(_{abs}\) = 198.118 kPa

The absolute pressure at a depth below the surface of this deep lake is 198.118 kPa.

Given the following data:

Scientific data:

To calculate the absolute pressure at a depth below the surface of a deep lake:

Mathematically, absolute pressure is given by this formula:

\(P_{abs} = P + \rho gh\)

Substituting the given parameters into the formula, we have;

\(P_{abs} = 1.01 \times 10^5 + 1000 \times 9.8 \times 9.91 \\\\ P_{abs} = 101000+ 97118 \\\\\)

Absolute pressure = 198118 Pa

Note: 1 kPa = 1000 Pa

Absolute pressure = 198.118 kPa

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The level within a capillary tube with a radius of 0.45 mm rises to a height of 3 cm above the water's surface when submerged in it.

When water saturation decreases, Pnw outside the pore throat is larger than Pw within the pore throat, resulting in a positive pressure (Pc=PnwPw), which is the definition of capillary pressure.

A micron is equal to 0.001 mm in diameter, therefore the capillaries are just big enough for red blood cells to travel through in a single line. Endothelial cells, which also make up the smooth channel surface of the bigger vessels, are the single layer of cells that make up their walls.

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Answer:

Semi-centrifugal clutches are used in high powered race cars, to reduce the driver effort. Working is just like semi-centrifugal clutch.

The clutch action is purely under centrifugal force.

At low engine rpm the centrifugal force is low, so there is slip, as engine rpm increases, so does the centrifugal force.

Given

Radius = 10 m

r = 10 m

speed = 8 m/s

Explanation

A. centripetal acceleration, the acceleration of a body traversing a circular path.

B. Net force

The final area of the plate is 4.0000352 \(m^2\) if the temperature raised to 100 °C and the coefficient of linear expansion of iron is 1.1 x 10-7.

Expecting that the plate of iron is rectangular, we can involve the recipe for warm extension of solids to compute the last region of the plate. The equation for direct warm development is given by ΔL = αLΔT, where ΔL is the adjustment of length, α is the coefficient of straight extension, L is the first length, and ΔT is the adjustment of temperature.

Since the region of the plate is given by A = L*W, where L is the length and W is the width, we can involve the equation for straight warm extension to compute the adjustment of length of the plate and afterward use it to compute the last region.

ΔL = αLΔT = \((1.1 x 10^-7 m/oC)(2 m)(80 oC) = 1.76 x 10^-5 m\)

The last length of the plate is L + ΔL = 2 m + 1.76 x \(10^-5\) m = 2.0000176 m (approx.)

The last width of the plate is thought to be unaltered as it isn't impacted by the adjustment of temperature.

Thusly, the last region of the plate is A = L*W = (2.0000176 m)(2 m) = 4.0000352 \(m^2\) (approx.)

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Answer:

cos 0 = 1.

Fs = 7×8 = 56 J

Explanation:

Answer:

The answer is 0.042 Hz (rounded)

or 0.0417 Hz

Explanation:

Hope it helps

Answer:

The answer is 0.041Hz

Explanation:

The answer is 0.041Hz

I guess

Answer:

6235.5J

Explanation:

Using ( nစ)p= ncp x change in temp

But cp= ( 1+ f/2)R

So cp= ( 1+ 3/2R

Cp= 5R/2

So = n x 5R/2x 150k

= 2 x 5/2x 8.314 x150

= 6235.5J

Answer:

2500 J

Explanation:

Q=(3/2)nRΔT

Q=(3/2)*2 mol*(8.314 J/mol*k)*100 k

Q=2494 J

Answer:

1.84 m

Explanation:

For the small lead ball to be balanced at the tip of the vertical circle just before it is released, the reaction force , N equal the weight of the lead ball W + the centripetal force, F. This normal reaction ,N also equals the tension T in the string.

So, T = mg + mrω² = ma where m = mass of small lead ball, g = acceleration due to gravity = 9.8 m/s², r = length of rope = 1.10 m and ω = angular speed of lead ball = 3 rev/s = 3 × 2π rad/s = 6π rad/s = 18.85 rad/s and a = acceleration of normal force. So,

a = g + rω²

= 9.8 m/s² + 1.10 m × (18.85 rad/s)²

= 9.8 m/s² + 390.85 m/s²

= 400.65 m/s²

Now, using v² = u² + 2a(h₂ - h₁)  where u = initial velocity of ball = rω = 1.10 m × 18.85 rad/s = 20.74 m/s, v = final velocity of ball at maximum height = 0 m/s (since the ball is stationary at maximum height), a = acceleration of small lead ball = -400.65 m/s² (negative since it is in the downward direction of the tension), h₁ = initial position of lead ball above the ground = 1.3 m and h₂ = final position of lead ball above the ground = unknown.

v² = u² + 2a(h₂ - h₁)

So, v² - u² = 2a(h₂ - h₁)

h₂ - h₁ =  (v² - u²)/2a

h₂ =  h₁ + (v² - u²)/2a

substituting the values of the variables into the equation, we have

h₂ =  1.3 m + ((0 m/s)² - (20.74 m/s)²)/2(-400.65 m/s²)

h₂ =  1.3 m + [-430.15 (m/s)²]/-801.3 m/s²

h₂ =  1.3 m + 0.54 m

h₂ =  1.84 m

Answer:

Its nymber 2

Explanation:

Answer:

The Number is concept. It is depending with what you mean by infinity. Some of the numbers include 1 through 2 or infinite. If you work with vector space of tuples with any components could be infinite you just know what typed of infinity work with.

Explanation:

May you have a bless day. And send positive all over the world.

The velocity of the race car after it traveled 32.2 meter is 14.47m/s.

Velocity is simply the speed at which an object moves in a particular direction.

From the Third Equation of Motion

v² = u² + 2as

Given that;

Plug the given values into the above formula and solve for final velocity.

v² = u² + 2as

v² = (0)² + ( 2 × 3.25 m/s² × 32.2 m ​)

v² =  2 × 3.25 m/s² × 32.2 m

v² = 209.3 m²/s²

v = √( 209.3 m²/s² )

v = 14.47m/s

Therefore, the final velocity is 14.47m/s.

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Answer:

b. If Wire B carries a northward conventional current and lies to the left (west) of wire A, then it will experience an attractive force to the right (towards Wire A).

d. If Wire B carries a southward conventional current and lies to the left (west) of wire A, then it will experience a repulsive force to the left (away from Wire A).

Explanation:

Two parallel conductors experience attractive force when the current flowing in the conductors are in the same direction.

Also two parallel conductors experience repulsive force when the current flowing in the conductors are in opposite direction.

Therefore, b and d are the correct options.

b. If Wire B carries a northward conventional current and lies to the left (west) of wire A, then it will experience an attractive force to the right (towards Wire A).

d. If Wire B carries a southward conventional current and lies to the left (west) of wire A, then it will experience a repulsive force to the left (away from Wire A).

Answer:

Acceleration: \(2.80\; {\rm m\cdot s^{-2}}\) (towards the north.)

Displacement: approximately \((-167)\; {\rm m}\) (towards the south.)

Explanation:

The initial velocity \(u\) of the train (before braking) will be negative since the the train was travelling south. Thus: \(u = (-31.2)\; {\rm m\cdot s^{-1}}\).

The train continues southwards after braking. Therefore, the final velocity \(v\) of the train (after braking) will also be negative: \(v = (-6.00)\; {\rm m \cdot s^{-1}}\).

Find the change in the velocity of the train by subtracting the initial value from the final value:  

\(\begin{aligned}\Delta v &= v - u \\ &= (-6.00)\; {\rm m\cdot s^{-1} - (-31.2)\; {\rm m\cdot s^{-1} \\ &= 25.2\; {\rm m\cdot s^{-1}} \end{aligned}\).

Divide change in velocity by the time required \(t = 9.00\; {\rm s}\) to find the (constant) acceleration \(a\) of the train:

\(\begin{aligned} a &= \frac{\Delta v}{t} \\ &= \frac{25.2\; {\rm m\cdot s^{-1}}}{9.00\; {\rm s}} \\ &= 2.80\; {\rm m\cdot s^{-2}}\end{aligned}\).

Note that acceleration is positive since the velocity is becoming less negative. The velocity component of the train towards the south has been reduced.

Apply the SUVAT equation \((v^{2} - u^{2}) = 2\, a\, x\) to find the displacement \(x\) of the train:

\(\begin{aligned} x &= \frac{v^{2} - u^{2}}{2\, a} \\ &= \frac{(-6.00)^{2} - (-31.2)^{2}}{2 \times 2.80}\; {\rm m} \\ &\approx (-167)\; {\rm m} \end{aligned}\).

Note that displacement is negative since the train keeps travelling south. The position of the train after braking is to the south of where the train was before braking.

Location F is significant because it demonstrates that there are winters inside the southern hemisphere but that Antarctica has long, dark days and nights.when the winter season in the Hemisphere is in effect

Seasons are a result of the tilt of the Earth's axis; winter occurs when one hemisphere is pointed toward the sun.The beginning of winter is marked by various cultural definitions, some of which base their dates on the weather.In the Southern Quarter, it's indeed summer when it is winter inside the Northern Hemisphere, and conversely.

As a result, the first day of spring, summer, autumn, and winter in temperate regions of the northern hemisphere is March 1.In the temperate zone of the southern hemisphere, spring officially starts on 1 September, winter on 1 December, and fall on 1 March.

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Answer:

A ,C

Explanation:

Shows

Answer:

calcium chloride

Explanation:

an inorganic compound,a salt with the chemical formula CaCl2

Based on the diagram, the correct statement is: Government and consumers make economic decisions in a mixed economy, while consumers make economic decisions in a market economy.

In a mixed economy, economic decisions are made by both the government and consumers.

The government plays a significant role in regulating and influencing economic activities through policies, regulations, and interventions.

In market economy, economic decisions are primarily made by consumers. The market forces of supply and demand dictate the allocation of resources, production levels, and pricing.

The freedom to buy and sell whatever they choose is what ultimately determines how commodities and services are produced and distributed.

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Answer:

Based on the seconds given or recorded you might multiply seconds by 6 and that will give you your equation format to measure the speed of an animal. Cheetahs and wild boars are the fastest probably.

Explanation:

The vector whose magnitude is 36 and inclination is 60° is v = <18, 18√(3)>.

The inclination of a vector is the angle between the vector and a reference line. In this case, the reference line is the horizontal axis. Let the components be x and y. We know that the magnitude of the vector is 36, so,

magnitude = √(x² + y²) = 36

Squaring both sides of this equation, we get,

x² + y² = 1296

We also know that the inclination is 60°. The tangent of 60° is √(3), which is equal to the ratio of the vertical component to the horizontal component of the vector,

tan(60°) = y/x

y/x= √(3)

Multiplying both sides by x, we get,

y = √(3)x

Now we can substitute y in terms of x in the equation x² + y² = 1296,

x² + (√(3)x)² = 1296

Simplifying this equation, we get,

4x² = 1296

x² = 324

Taking the square root of both sides, we get,

x = +/- 18

Since the vector is making an angle of 60° with the horizontal, it must be in the first or fourth quadrant, where x is positive. Therefore, we take x = 18. Using y = √(3)x, we get,

y = sqrt(3)18

y = 18√(3)

So the vector is,

v = <18, 18√(3)>

Therefore, the vector whose magnitude is 36 and inclination is 60° is v = <18, 18√(3)>.

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Time taken by the rock to reach the ground form a height of 208 feet is 3.61 seconds.

The rock is falling freely under gravity. The relation between height and and time for the rock is given.

The rock is at a height of 208 feet.

To calculate the time when rock is hit the ground.

h = 0 feet.

The relation between height and time for rock is given by,

\(h = 208 - 16 t^2\)

Using 0 for the value of h.

\(0 = 208 - 16 t^2\\208 = 16 t^2\)

t = 3.61 seconds.

Time taken by the rock to reach the ground is 3.61 seconds.

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--The complete question is, A rock falls from a tower that is 208 feet high. As it is falling, its height is given by the formula h= 208-16t^2. how many seconds will it take for the rock to hit the ground (h=0)?--