Determine Hrxn for the reaction CH4(g) + 4Cl2(g)→CCl4(l) + HCl(g). Consult the Appendix in your e-text for any values you might need.

Answer:

b

Explanation:

Answer: The concentration(molarity) of the solution will be 1.35 X10-4 M

Explanation: Molarity is defined as number of moles of solute present in one litre of any solution.

Mathematically,

Molarity= no of moles of solute/volume of solution(in liters)

M=N/V(liters)

Also upon dilution the number of moles of the solution remain unchanged

Therefore initial no of moles(before dilution)= final no of moles(after dilution)

M1V1=M2V2

According to the question,

Molarity of Na2S04 before dilution(M1)=1.5 M

Volume of NA2SO4(V1)=45 mL

Molarity of Na2S04 after dilution(M2)=x M

Volume of Na2S04(V2)=500 mL

x=M1V1/V2

=1.5X45/500

=0.135 M =1.35 X10-4 M

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Answer:

Explanation:

Combined Gas Law

T2= T1P2V2/ (P1V1) = 348.15 X .5 X 3.4/(2 X 7.5) =39.46 K or -233.69C

Taking into account the definition of dilution, the answer is "The volume of stock solution used is less than 3 Liters."

When it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

In this case, you know:

Replacing in the definition of dilution:

10 M× Vi= 1 M× 3 L

Solving:

Vi= (1 M× 3 L)÷ 10 M

Vi= 0.3 L

In summary, to prepare 3 Liters of 1 M solution, you need 0.3 L of the 10 M concentration stock solution and dilute to 3 L. Therefore, the answer is "The volume of stock solution used is less than 3 Liters."

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Answer:

We need more? What else is in the question? This is unanswerable.

Explanation:

Answer:

NaCO3 + CaPO2>>>>>NaPO2+CaCO3

Answer:

a. The Zn and HCl both retained their identity.

Answer:

123 g

Explanation:

First, we convert 10.0 dL into mL, keeping in mind that:

Now we can multiply the density by the volume in order to calculate the mass:

10.0 dL of a substance with a density of 0.123 g/mL would weigh 123 grams.

A total of 1.5 moles of ammonia (NH₃) could be produced.

To react with 56.0 g of N₂, 6.000 moles of H₂ gas are required.

A. We need to balance the chemical equation first:

N₂ + 3H₂ → 2NH₃

From the balanced equation, we can see that 1 mole of N₂ reacts with 3 moles of H₂ to produce 2 moles of NH₃.

Therefore, if 0.75 moles of N₂ are reacted with enough hydrogen gas, we can calculate the moles of NH₃ produced using the mole ratio:

0.75 moles N₂ × (2 moles NH₃ / 1 mole N₂) = 1.5 moles NH₃

Therefore, 1.5 moles of NH₃ can be produced.

B. We can use the molar mass of N₂ to convert 56.0 g of N₂ to moles:

56.0 g N₂ × (1 mole N₂ / 28.02 g) = 2.000 mole N₂

From the balanced equation, we know that 1 mole of N₂ reacts with 3 moles of H₂ to produce 2 moles of NH₃.

Therefore, the moles of H₂ required can be calculated using the mole ratio:

2.000 mole N₂ × (3 mole H₂ / 1 mole N₂) = 6.000 mole H₂

Therefore, 6.000 moles of H₂ are needed to react with 56.0 g of N₂.

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0.677 moles of gold (Au) will be produced when 210.39 g of lead (Pb) reacts with excess gold sulfate, using the stoichiometric ratio of 3:2 between Pb and Au.

We can use stoichiometry to determine the number of moles of gold produced from the given mass of lead.

First, we need to find the molar mass of lead (Pb), which is 207.2 g/mol.

Next, we can use the given mass of lead to find the number of moles:

n(Pb) = m(Pb) / M(Pb)

n(Pb) = 210.39 g / 207.2 g/mol

n(Pb) = 1.015 mol

According to the balanced chemical equation, the stoichiometric ratio of lead to gold is 3:2. This means that for every 3 moles of lead that react, 2 moles of gold are produced.

Therefore, the number of moles of gold produced can be calculated as:

n(Au) = (2/3) × n(Pb)

n(Au) = (2/3) × 1.015 mol

n(Au) = 0.677 mol

So, 0.677 moles of gold (Au) will be produced when 210.39 g of lead (Pb) reacts with excess gold sulfate.

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Answer:

2C2 H6 +7O2=4co2+6h2o+heat

Answer: One mole

Explanation: One mole of a substance is equal to 6.022 × 10²³ units of that substance (such as atoms, molecules, or ions). The number 6.022 × 10²³ is known as Avogadro's number or Avogadro's constant.

Answer:

Explanation:

i dont kow

The complete ionic equation and the net ionic equation for the reaction of aqueous ammonia and aluminum nitrate is written as follows:

\(Al^{3+} (aq)+3(NO_{3})^{-}(aq)+3NH_{4}^{+} (aq) + OH^{-}(aq)\rightarrow Al(OH)_{3}(s)+3NH_{4}^{+}(aq)+NO_{3}^{-}(aq)\)

\(Al^{3+}(aq)+ OH^{-}(aq)\rightarrow Al(OH)_{3}(s)\)

In an ionic equation all the ions are charges are balanced to the proper stoichiometric ratio. The states of each species have to be written in the brackets.

The reaction of aluminum nitrate and aqueous ammonia is written as follows:

\(Al(NO_{3})_{3}(aq) + 3NH_{4}OH(aq)\rightarrow Al(OH)_{3}(s) +3NH_{4}NO_{3}(aq)\)

The complete ionic equation is written below:

\(Al^{3+} (aq)+3(NO_{3})^{-}(aq)+3NH_{4}^{+} (aq) + OH^{-}(aq)\rightarrow Al(OH)_{3}(s)+3NH_{4}^{+}(aq)+NO_{3}^{-}(aq)\)

From this complete ionic equation the net ionic equation can be written by cancelling same species from both side as below:

\(Al^{3+}(aq)+ OH^{-}(aq)\rightarrow Al(OH)_{3}(s)\)

Therefore, the net product aluminum hydroxide is precipitated and the net ionic equation is written as above.

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This element is in group 1.

According to the octet rule, this element would be expected to form an ion with a charge of +1.

If X is in period 5, the ion formed has the same electron configuration as the noble gas Krypton

The symbol for the ion is Rb⁺

Electronic configuration refers to the arrangement of electrons in the orbitals of an atom or molecule, indicating the energy level of the electrons, the number of electrons in each energy level, and the number of electrons in each orbital.

Considering the given element:

It has one valence electron, hence it is in group 1. Group 1 elements form ions with a charge of +1.

Losing one electron will give the ion the same electron configuration as Kyrton since it is the noble gas in Period 4.

The element is rubidium and the ion is Rb⁺.

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Precision relates to the consistency and reproducibility of measurements, while accuracy reflects how close measurements are to the true value.

Precision and accuracy are two important concepts in the context of errors in measurements. While they both pertain to the quality of data, they refer to different aspects.

Precision refers to the degree of consistency or reproducibility in a series of measurements. It reflects the scatter or spread of data points around the average value. If the measurements have low scatter and are tightly clustered, they are considered precise. On the other hand, if the measurements have a high scatter and are widely dispersed, they are considered imprecise.

Accuracy, on the other hand, refers to the closeness of measurements to the true or target value. It represents how well the measured values align with the actual value. Accuracy is achieved when measurements have a small systematic or constant error, which is the difference between the average measured value and the true value.

Errors in measurements can be classified into two types: random errors and systematic errors.

Random errors are associated with the inherent limitations of measurement instruments or fluctuations in the measurement process. They lead to imprecise data and affect the precision of measurements. Random errors can be reduced by repeating measurements and calculating the average to minimize the effect of individual errors.

Systematic errors, on the other hand, are caused by consistent biases or inaccuracies in the measurement process. They affect the accuracy of measurements and lead to a deviation from the true value. Systematic errors can arise from factors such as instrumental calibration issues, environmental conditions, or experimental techniques. These errors need to be identified and minimized to improve the accuracy of measurements.

In summary, precision refers to the degree of consistency or reproducibility of measurements, while accuracy refers to the closeness of measurements to the true value. Random errors affect precision, while systematic errors affect accuracy. To ensure high-quality measurements, both precision and accuracy need to be considered and appropriate techniques should be employed to minimize errors.

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Gas particles have not definite volume, so they spread out and occupy much space as possible.

There's a great deal of empty space between particles, that have plenty of kinetic energy and are not particularly interested in each other. Gas particles circulate very fast and collide with one another, causing them to diffuse, or spread out until they're evenly distributed all through the quantity of the container.

A gas is depend that has neither a hard and fast extent nor a set form. rather, a gas takes each the quantity and the form of its container. It spreads out to take up all to be had area.

They don't have any precise volume. This means that gases always spread out in all instructions to fill the field into which they may be positioned. This spreading out of gases to fill all of the available space is referred to as diffusion. They may be compressed effortlessly.

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Jeremiah can arrange the materials in the following way to create a model that shows the processes by which water is cycled from a lake into the atmosphere and back to the lake

The following can be a representation of the water cycle;

Fill the glass jar with water to resemble the lake.

Put the lamp next to the jar to symbolize the sun.

Wrap the jar in plastic sheet to imitate the atmosphere.

Turn on the bulb to represent the sun warming the water.

When the water in the jar warms up and evaporates into water vapor, moisture will condense on the plastic wrap.

The water vapor will ascend and collect on the plastic wrap to represent the water vapor rising into the atmosphere.

Water vapor cools as it rises and condenses back into liquid form, as shown by the water droplets gathering on the plastic wrap.

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Answer:

of, relating to, or having a strong affinity for water

Explanation:

Answer:

water loving or havin affection for water, not like hydrophobic wich is fear of water or not resistant to water

Explanation:

Answer:

I dont understand what the question means

Explanation:

Answer:

the answer i believe is increased nutritional value of crops

Explanation:

Answer: increased nutritional value of crops

Explanation:) edge 2022

Answer:

The answer is A. Aquifer

Explanation:

It stores groundwater.

The mass of the asteroid is C. 1.2 x \(10^{12}\) Kg

To find the mass of the other asteroid, we can rearrange the equation for the gravitational force between two objects:

F = (G * m1 * m2) / \(r^{2}\)

where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two asteroids, and r is the distance between them.

Given that the distance between the asteroids is 75000 m, the force of gravity between them is 1.14 N, and one asteroid has a mass of 8 x \(10^{7}\) kg, we can substitute these values into the equation and solve for the mass of the other asteroid (m2):

1.14 N = (6.67430 × \(10^{-11}\) N \(m^{2}\)/\(Kg^{2}\) * 8 x \(10^{7}\) kg * \(m2\)) / \((75000 m)^{2}\)

Simplifying and solving the equation, we find that the mass of the other asteroid (m2) is approximately 1.2 x \(10^{12}\) kg. Therefore, Option C is correct.

The question was incomplete. find the full content below:

Two asteroids are 75000 m apart one has a mass of 8 x \(10^{7}\) kg if the force of gravity between them is 1.14 what is the mass of the asteroid

A. 3.4 x \(10^{11}\) kg

B. 8.3 x \(10^{12}\) kg

C. 1.2 x \(10^{12}\) kg

D. 1.2 x \(10^{10}\) kg

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Answer:

14.9 mol

Explanation:

To find the number of moles in a given mass of a sample of sodium chloride (NaCl), we can multiply the number of grams in the sample by the molar mass of sodium chloride, which is 58.44 g/mol.

871 g × (1 mol / 58.44 g)

= 871/58.44 mol

≈ 14.9 mol

Note that we rounded to 3 significant figures in the final answer because that is how many significant figures were given in the mass measurement of the sodium chloride sample.

Approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

To determine the number of molecules of HCl required to form 34.52 g of MgCl₂, we need to use the molar mass and stoichiometry of the balanced equation:

Mg(OH)₂(s) + 2 HCl(aq) → 2 H₂O(l) + MgCl₂(aq)

The molar mass of MgCl₂ is 95.21 g/mol.

First, we need to calculate the number of moles of MgCl₂ formed:

Moles of MgCl₂ = mass of MgCl₂ / molar mass of MgCl₂

Moles of MgCl₂ = 34.52 g / 95.21 g/mol

Moles of MgCl₂ = 0.363 mol

According to the balanced equation, the stoichiometric ratio between HCl and MgCl₂ is 2:1. Therefore, the moles of HCl required can be calculated as follows:

Moles of HCl = 2 * Moles of MgCl₂

Moles of HCl = 2 * 0.363 mol

Moles of HCl = 0.726 mol

To calculate the number of molecules, we need to use Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol.

Number of molecules of HCl = Moles of HCl * Avogadro's number

Number of molecules of HCl = 0.726 mol * 6.022 x 10^23 molecules/mol

Number of molecules of HCl = 4.37 x 10^23 molecules

Therefore, approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

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The statement that accurately describes the photoelectric effect is Shining a HIGH frequency light over a metal will cause ELECTRONS to be ejected. That is option B.

Photoelectric effect is defined as the process by which electrically charged particles are released from or within a material when it absorbs electromagnetic radiation.

The photoelectric effect can also be defined as the ejection of electrons from a metal plate when light falls on it.

Therefore, statement that accurately describes the photoelectric effect is Shining a HIGH frequency light over a metal will cause ELECTRONS to be ejected.

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Students put solid butter and solid water on a table. The air temperature around the table is 20°C. After two hours, The butter will remain a solid, and the water will become a liquid. Therefore, option B is correct.

A state of matter is one of the various forms that matter can take. In everyday life, four states of matter are visible: solid, liquid, gas, and plasma.

On a table, students placed solid butter and solid water. The temperature of the air around the table is 20°C. The butter will remain solid after two hours, while the water will become liquid.

Thus, option B is correct.

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Your question is incomplete, most probably your question was

The pictures show butter and water in solid states. The melting point of each substance is shown.

Students put solid butter and solid water on a table. The air temperature around the table is 20°C.

A. The butter and water will both become liquids.

B. The butter will remain a solid, and the water will become a liquid.

C. The butter and water will both remain solids.

D. The butter will become a liquid, and the water will remain a solid.

Answer:

1000 K

Explanation:

Given data

We can find the temperature of carbon dioxide using the ideal gas equation.

\(P \times V = n \times R \times T\\T = \frac{P \times V}{n \times R} = \frac{0.8210atm \times 50L}{0.5mol \times \frac{0.08206atm.L}{mol.K} }=1000 K\)

The temperature of the gas is 1000 K.

Answer:

1.6 L CH3OH

Explanation:

3.20 L H2 x (1 mol H2/22.4 L H2) x (1 mol CH3OH/2 mol H2) x (22.4 L CH3OH/1 mol CH3OH) = 1.60 LCH3OH

1.602 liters of CH₃OH gas are formed when 3.20 L of H₂ gas are completely reacted at STP according to the following chemical reaction:

CO(g) + 2 H₂(g) → CH₃OH(g)

Remember 1 mol of an ideal gas has a volume of 22.4 L at STP

To find the volume of CH₃OH gas formed when 3.20 L of H₂ gas is completely reacted, we need to use stoichiometry and the given balanced chemical equation.

The balanced equation is:

CO(g) + 2 H₂(g) → CH₃OH(g)

From the balanced equation, we can see that 1 mol of CO reacts with 2 moles of H₂ to produce 1 mole of CH₃OH.

Step 1: Convert the given volume of H₂ gas to moles at STP.

Using the information provided, 1 mol of any ideal gas at STP (Standard Temperature and Pressure) occupies 22.4 L.

Number of moles of H₂ gas = Volume of H2 gas at STP / Volume of 1 mol of H₂ gas at STP

Number of moles of H₂ gas = 3.20 L / 22.4 L/mol

Number of moles of H₂ gas = 0.14286 moles (rounded to 5 decimal places)

Step 2: Use stoichiometry to find the moles of CH₃OH formed.

From the balanced equation, we know that 1 mol of CO reacts with 2 moles of H₂ to produce 1 mole of CH₃OH.

Since the ratio of H₂ to CH₃OH is 2:1, the number of moles of CH₃OH formed will be half of the moles of H₂ used in the reaction.

Number of moles of CH₃OH = (1/2) * Number of moles of H₂

Number of moles of CH₃OH = (1/2) * 0.14286

Number of moles of CH₃OH = 0.07143 moles (rounded to 5 decimal places)

Step 3: Convert the moles of CH₃OH to volume at STP.

Using the information provided, 1 mol of any ideal gas at STP (Standard Temperature and Pressure) occupies 22.4 L.

Volume of CH₃OH gas at STP = Number of moles of CH₃OH * Volume of 1 mol of CH₃OH gas at STP

Volume of CH₃OH gas at STP = 0.07143 moles * 22.4 L/mol

Volume of CH₃OH gas at STP = 1.602 L (rounded to 3 decimal places)

Therefore, approximately 1.602 liters of CH₃OH gas are formed when 3.20 liters of H₂ gas are completely reacted at STP.

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