To solve this problem, we need to use the Pythagorean theorem to find the distance between the two cars.
After two hours, the car traveling south will have gone 56*2 = 112 miles, and the car traveling west will have gone 42*2 = 84 miles. If we draw a right triangle with the two cars at the vertices of the right angle, then the distance between them is the hypotenuse of the triangle. Using the Pythagorean theorem, we have:
distance^2 = 112^2 + 84^2
distance^2 = 12,544 + 7,056
distance^2 = 19,600
distance = sqrt(19,600)
distance = 140 miles
To find the rate at which the distance between the cars is increasing, we need to take the derivative of the distance equation with respect to time. Since both cars are moving at a constant speed, we can use the chain rule to get:
d(distance)/dt = (d(distance)/dx) * (dx/dt) + (d(distance)/dy) * (dy/dt)
where x is the distance traveled by the car traveling west, y is the distance traveled by the car traveling south, and t is time. Taking the derivatives, we have:
d(distance)/dx = 2x/2(distance) = x/distance
d(distance)/dy = 2y/2(distance) = y/distance
dx/dt = 42 mph
dy/dt = 56 mph
Substituting in the values we know, we get:
d(distance)/dt = (84/140) * 42 + (112/140) * 56
d(distance)/dt = 0.6 * 42 + 0.8 * 56
d(distance)/dt = 25.2 + 44.8
d(distance)/dt = 70
Therefore, the rate at which the distance between the two cars is increasing two hours later is 70 miles per hour.
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Sometimes, a crackling sound is heard while taking off a sweater during winters. Explain
Answer:
it is somewhat frozen
Explanation:
If the deflection of a spring is doubled, then how much does the force change?
Answer:
The force is doubled as well.
Explanation:
If you double the spring then the force doubles as well.
If the deflection of the spring is doubled, the force exerted by the spring will also be doubled.
What is the Hooke's Law?The relationship between the deflection of a spring and the force it exerts is described by Hooke's Law, which states that the force exerted by a spring is directly proportional to its deflection. Mathematically, this can be expressed as:
F = kx
where F is the force exerted by the spring, x is the deflection of the spring, and k is the spring constant, which represents the stiffness of the spring.
If we double the deflection of the spring, then x becomes 2x, and the force exerted by the spring becomes:
F = k(2x) = 2kx
Thus, if the deflection of the spring is doubled, the force exerted by the spring will also be doubled (assuming the spring constant remains constant).
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if you run off the pavement, you should: turn the steering wheel quickly toward the road steer straight and slow down before attempting to return to the pavement steer straight ahead and speed up apply the brakes hard submit answer
pavement is defined as the surface of Road or sidewalk.
for example, the surface of Expressway.
There are two types of pavement.
rigid pavement which consists of one layer.
flexible pavement which consist of multiple layers.
While driving on roads of rural areas, if our right wheel moves off the pavement, we should always hold the steering wheel firmly and then take our foot off the pedal, then apply brake lightly until we are moving at a low speed.
if you run off the pavement, you should: turn the steering wheel quickly toward the road steer straight and slow down before attempting to return to the pavement steer straight ahead and speed up apply the brakes hard
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What positive impact can animals have on the environment?
(A They eat fruit
(B They eat insects
(C They pollinate flowers
(D They spread disease
Answer:
maybe C they pollinate flowers
Explanation:
because when you search you will see pollination
14.27 If you carry heavy weights in your hands, how will this affect the natural frequency at which your arms swing back and forth/
A frequency will increase
B The frequency will stay the same
C The fluency will decrease
The natural frequency at which your arms swing back and forth will change if you are holding heavy objects in your palms. The frequency will rise if the right response (option A).
Your arms move in a manner akin to a pendulum as you swing them. The length and bulk of your arms dictate the natural frequency at which they swing back and forth.
Your arms gain bulk as a result of adding weight to your hands, increasing the natural frequency of your arm swing.
Your arm swing may feel more unnatural due to this increased frequency.
Maintaining your arm swing can be harder and could wear more quickly.
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A 0.225 kg block of iron at -28.7 °C is put in a cup of 0.150 kg of water at 18.9 °C. What is their equilibrium temperature?
Answer:
12.3°C should be the correct answer
Answer:
12.3
Explanation:
Explain the free motion of particles.
Answer:
D : An electron may act with either particle-like or wave-like characteristics.
Explanation:
This is the whole basis of the Schrödinger equation.
The other options are correct, but they do not state the dual nature of the electron.
Help! Will Mark Brainliest!
A toy mouse has a mass of 2 kg and kinetic energy of 25 J. What is its speed?
A. 4 m/s
B. 3 m/s
C. 6 m/s
D. 5 m/s
Answer:
D 5m/s
Explanation:
A student claims that any object in motion must experience a force that keeps it in motion. Do you agree or disagree?Explain your reasoning.
Answer:
i disagree because if you throw a ball in the air gravity will bring it down so only the force that moved it was needed.
Explanation:
A hemispherical tank is full of oil (density = 50 pc). It has a diameter of 10 ft. Find the work done in Ib-ft in pumping all the liquid out of the tank
The work done in pumping all the liquid out of the tank is 2500π lb-ft.
Work done calculationThe potential energy of an object is given by the formula:
PE = mgh
Given:
Density of oil = 50 lb/ft^3
Diameter of the tank = 10 ft ( r = 5 ft)
To calculate the work done, we need to find the mass of the oil and the height it is lifted. Let's start by finding the mass:
Volume of oil in the tank:
The volume of a hemisphere = (2/3) * π * (r^3)
Volume = (2/3) * π * (5^3) = (2/3) * π * 125 = 250π/3 ft^3
Mass of the oil:
Mass = Volume * Density = (250π/3) * 50 lb
Now, we need to find the height of the tank. For a hemisphere, the height is equal to the radius (5 ft).
Finally, we can calculate the work done:
Work = PE = mgh = (250π/3) * 50 lb * 5 ft
Work = (250π/3) * 50 * 5 lb-ft
= 2500π lb-ft
So, the work done in pumping all the liquid out of the tank is approximately 2500π lb-ft.
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A.She says that as increase in pressure increases the volume of helium gas.
B.She says that a decrease in pressure decreases the volume of helium gas.
C. She says that a decrease in temperature increases the volume of helium gas.
D. She says that an increase in temperature increases the volume of helium gas.
Answer:
c
Explanation:
she say that a decrease in temperature increases the volume of helium gas
Answer: c
Explanation:
what distance, d , must separate galileo and his assistant in order for the human reaction time, δt = 0.2 s , to introduce no more than a 18 rror in the speed of ligh
To avoid an error of more than 18 in the speed of light due to human reaction time (δt = 0.2 s), Galileo and his assistant must be separated by a distance of at least d = cδt/18, where c is the speed of light.
Let's first consider the maximum error in the speed of light introduced by the human reaction time. The distance light travels in time δt = 0.2 s is given by:
d_max = c × δt
where c is the speed of light. The error introduced in the measurement of the speed of light due to the human reaction time is given by:
Δv = c × δt / d
where d is the distance between Galileo and his assistant. We want to find the maximum value of d that would introduce no more than an 18 error in the speed of light. Therefore, we can set up the following equation:
Δv / c = 18 / 100
Substituting the values of Δv and c, we get:
(c × δt / d) / c = 18 / 100
Simplifying, we get:
d = c × δt / (18 / 100) = (3 × 10^8 m/s) × (0.2 s) / (18 / 100) = 3.33 × 10^6 m
Therefore, the distance d must separate Galileo and his assistant in order for the human reaction time to introduce no more than an 18 error in the speed of light is approximately 3.33 million meters.
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Draw a wave that has a wavelength of 3 cm and an amplitude of 1 cm. Label the wavelength, the amplitude, the rest position, and the crest and trough of your wave.
Answer:
Please find attached, the required wave drawn with MS Excel
Explanation:
Functions that represent waves is given as follows
A general form of the wave equation is A·sin(B·x) + D
Where;
B = 2·π/T
T = The period of the wave = 1/f
D = The vertical shift of the wave = 0
A = The amplitude of the wave = 1 for sine wave
v = The wave velocity
λ = The wavelength of the wave
f = The frequency of the wave
v = f·λ
At constant v, λ ∝ 1/f
∴ λ ∝ T
Where T = 3, we have;
B = 2·π/T
∴ B = 2·π/3
Therefore, we have the wave with an amplitude of 1 cm, and wavelength, 3 cm, given as follows
y = sin((2·π/3)·x)
Plotting the above wave with MS Excel, we can get the attached wave
a 2000 spaceship is 11 * 10 to the power 5 above earths surface what is the gravitaional force in newtons acting on the spaceship
Answer: Gravitational force is 2.82 x 10^4 N
Formula to calculate gravitational force is:
F = G * (m1 * m2) / r^2
where F = gravitational force,
G = gravitational constant
m1 and m2 = the masses of the two objects
r = distance between the objects.
In this case,
mass of the spaceship (m1) = 2000 kg
mass of Earth (m2) = 5.97 x 10^24 kg.
distance between the spaceship and Earth's center =6.37 x 10^6 m
Putting these values into the formula, we get:
F = 6.67 x 10^-11 * (2000 kg * 5.97 x 10^24) / (6.37 x 10^6 + 11 x 10^5)^2
By simplification we get,
F = 6.67 x 10^-11 * (1.194 x 10^28) / (7.03 x 10^11)
F = 2.82 x 10^4 N
Thus, the gravitational force acting on the spaceship due to Earth's gravity is approximately 2.82 x 10^4 N.
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If a man with a mass of 75 kg, standing still, throws an object with a mass of 5 kg at 30 m/s, what will be the recoil velocity of the man, assuming he is standing on a frictionless surface?
Answer:
2 m/s
Explanation:
Given that,
Mass of a man, m₁ = 75 kg
Mass of object, m₂ = 5 kg
Velocity of the object, v₂ = 30 m/s
We need to find the recoil velocity of the man. Let it is v₁. In the whole process, the momentum of the system will remain conserved such that,
\(m_1v_1=m_2v_2\\\\v_1=\dfrac{m_2v_2}{m_1}\\\\v_1=\dfrac{5\times 30}{75}\\\\v_1=2\ m/s\)
So, the recoil velocity of the man is 2 m/s
Q.7. For a system with a transfer function of G(s)=- co² s² +2a+w² if the natural frequency is 0.5 and the damping ratio is 1.3, which of the following statements is correct regarding the unit step response of the system?
O A) Damped
O B) Undamped
O C) Underdamped
O D) Crittically Damped
O E) Overdamped
The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)
The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.
To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).
The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).
In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).
Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.
If co > co_critical, the system is considered overdamped (Option E).
If co = co_critical, the system is considered critically damped (Option D).
If co < co_critical, the system is considered underdamped (Option C).
Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.
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the manufacturer of a 12 v car headlight specifies it will draw a current of 6 a. you would like to check this claim with an ammeter designed to measure currents up to 10 a and having a resistance of 0.1 ohms. a). which of the two circuits in the attached figure represents a circuit where the ammeter correctly measures the current in the headlight?b) How much current (in A) would flow in the ammeter forCircuit a?
c) How much current (in A) flows through the ammeter for Circuitb?
A) Circuit A represents a circuit where the ammeter correctly measures the current in the headlight.
B) For Circuit A, the current flowing through the ammeter would be 6 A, as the ammeter has no resistance and is connected in series with the headlight.
C) For Circuit B, the current flowing through the ammeter would be 6 A - 0.1 A = 5.9 A.
What is ammeter ?An ammeter is an electrical instrument used to measure electrical current. It is connected in series with the circuit and measures the current directly. The ammeter is a type of galvanometer, which is a device used to detect and indicate small electric currents. The ammeter works by generating a magnetic field around the current-carrying conductor and measuring the strength of the field with an electromagnet. The strength of the field is directly proportional to the current flowing through the conductor. The ammeter can measure both direct and alternating currents. It has a low resistance and is usually connected in series with the circuit to ensure that all the current flows through it. The ammeter can also measure very small currents, making it an important instrument in the study of electricity.
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how much does a change in mass affect the kinetic energy of two balls of comparable diameter?
Answer:
Mass and kinetic energy have a positive relationship, which means that as mass increases, kinetic energy increases, if all other factors are held constant.
In this state, Kinetic energy is equal to half of the product mass and velocity. SI unit is joules. So it's if the mass is doubled then the kinetic energy also gets doubled.
If mass of an empty 7.0 mL pycnometer is 10.2g and the mass of the same pycnometer with an unknown liquid is 21.8g. Determine the density of the unknown liquid to ONE DECIMAL PLACE in g/mL.
The formula for calculating density is expressed as
Density = mass/volume
From the information given,
mass of empty pycnometer = 10.2
mass of the same pycnometer with an unknown liquid is 21.8.
Mass of unkown liquid = 21.8 - 10.2 = 11.6
volume of unknown liquid = 7
Thus,
Density = 11.6/7
Density = 1.7 g/ml
2. What type of signals does the nervous system send? What carries these signals
Answer:
Nervous system messages travel through neurons as electrical signals. When these signals reach the end of a neuron, they stimulate the release of chemicals called neurotransmitters. Neurotransmitters travel across synapses, spaces between neurons or between neurons and other body tissues and cells.
Explanation:
You are walking in Paris alongside the Eiffel Tower and suddenly a croissant smacks you on the head and knocks you to the ground. From your handy dandy tourist guidebook you find that the height of the Eiffel Tower is 144.3 m. If you neglect air resistance, calculate how many seconds the croissant dropped before it tagged you on the head assuming it started with a velocity of 0 m/s. (TWO decimal places!!)
The time taken by the croissant before it strike on the head is 5.4 s
Lets assume the height of the man is 1.3 m
Given height of the Eiffel Tower is 144.3 m
So the distance croissant travel before it hits the man on the head
= 144.3 - 1.3 m
= 143 m
According to the Second Equation of Motion which relates distance with the acceleration and time, we can say that
\(S = ut + \frac{1}{2} a t^{2}\)
here u = 0
a = g = 9.81 m/s²
S = 143 m
therefore \(S = \frac{1}{2} gt^{2}\)
\(t = \sqrt{\frac{2S}{g} }\)
\(t = \sqrt{\frac{2 * 143}{9.81} }\)
\(t = \sqrt{29.154}\)
t = 5.4 s
Therefore, if the air resistance is neglected the croissant will drop 5.4 s before it tagged the man on his head.
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The James Webb Space Telescope is positioned around 1.5 million kilometres from the Earth on the side facing away from the Sun. The telescope remains at this distance and orbits around the Sun with the Earth’s orbital velocity.
--Determine the angular velocity ω of the telescope as it orbits around the Sun.
--The centrifugal Fω and gravitational force FG are acting on objects orbiting the Sun: F =Fω−FG. Based on this, how much should the telescope accelerate towards or away from the Sun?
--Why is the orbit of the telescope stable nonetheless? What other forces need to be considered?
The angular velocity depends on the length of the orbit and the orbital
speed of the telescope.
Response:
First question:
The angular velocity of the telescope is approximately 0.199 rad/sSecond question:
The telescope should accelerates away by approximately F = 0.0005·mThird question:
The pulling force between the Earth and the satelliteWhat equations can be used to calculate the velocity and forces acting on the telescope?The distance of the James Webb telescope from the Sun = 1.5 million kilometers from Earth on the side facing away from the Sun
The orbital velocity of the telescope = The Earth's orbital velocity
First question:
\(Angular \ velocity = \mathbf{\dfrac{Angle \ turned}{Time \ taken}}\)
The orbital velocity of the Earth = 29.8 km/s
The distance between the Earth and the Sun = 148.27 million km
The radius of the orbit of the telescope = 148.27 + 1.5 = 149.77
Radius of the orbit, r = 149.77 million kilometer from the Sun
The length of the orbit of the James Webb telescope = 2 × π × r
Which gives;
r = 2 × π × 149.77 million kilometers ≈ 941.03 million kilometers
Therefore;
\(Angular \ velocity = \dfrac{29.8}{941.03}\times 2 \times \pi \approx 0.199\)
The angular velocity of the telescope, ω ≈ 0.199 rad/sSecond question:
Centrifugal force force, \(F_{\omega}\) = m·ω²·r
Which gives;
\(F_{\omega} = m \cdot \dfrac{28,500^2 \, m^2/s^2}{149.77 \times 10^9 \, m} \approx 0.0054233 \cdot m\)
\(Gravitational \ force, F_G = \mathbf{G \cdot \dfrac{m_{1} \cdot m_{2}}{r^{2}}}\)
Universal gravitational constant, G = 6.67408 × 10⁻¹¹ m³·kg⁻¹·s⁻²
Mass of the Sun = 1.989 × 10³⁰ kg
Which gives;
\(F_G = 6.67408 \times 10^{-11} \times \dfrac{1.989 \times 10^{30} \times m}{149.77 \times 10^9} \approx 0.00592 \cdot m\)
Which gives;
\(F_{\omega}\) < \(F_G\), therefore, the James Webb telescope has to accelerate away from the Sun
F = \(\mathbf{F_{\omega}}\) - \(\mathbf{F_G}\)
The amount by which the telescope accelerates away is approximately 0.00592·m - 0.0054233·m ≈ 0.0005·m (away from the Sun)
Third part:
Other forces include;
The force of attraction between the Earth and the telescope which can contribute to the the telescope having a stable orbit at the given speed.Learn more about orbital motion here:
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Jenny bought one meter of fishing line that was rated safe for fish up to 5 lbs (22. 2 N). She tied a 500 g toy on one end and started swinging it in a horizontal loop around her head. How fast would the toy have to be moving in order to snap the line?
The toy would have to be moving at approximately 6.66 m/s in order to snap the fishing line.
To determine the speed at which the toy would snap the fishing line, we need to consider the tension in the line caused by the centripetal force required to keep the toy moving in a horizontal loop.
The centripetal force (Fc) can be calculated using the formula:
Fc = m * v^2 / r
Where:
m is the mass of the toy (500 g = 0.5 kg)
v is the velocity of the toy
r is the radius of the circular motion (assuming the length of the fishing line is the radius)
The tension in the line (T) must be equal to or greater than the centripetal force to prevent the line from snapping. Therefore, we can equate T to Fc:
T = m * v^2 / r
Since the tension is limited to 22.2 N, we can set up the following equation:
22.2 N = 0.5 kg * v^2 / 1 m
Simplifying the equation:
22.2 N = 0.5 kg * v^2
v^2 = 22.2 N / 0.5 kg
v^2 = 44.4 m^2/s^2
Taking the square root of both sides:
v ≈ √44.4 m^2/s^2
v ≈ 6.66 m/s
Therefore, the toy would have to be moving at approximately 6.66 m/s in order to snap the fishing line.
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order for our moon
When the moon first formed, it was only 14,000 above the Earth's surface outside f
Roche limit. It took only to 100
to form.
When the moon first formed, it was only 14,000 miles above the Earth's surface outside the Roche limit.
The distance between two celestial bodies which are held together with the force of gravity between them, is called the Roche limit or Roche radius.
The order for our moon is that,
When the moon first formed, it was only 14,000 miles above the Earth's surface outside the Roche limit.
It took only to 100 years to form.
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93. High biological value proteins are classified as A_ complete proteins. B_ plant-based proteins C essential amino acids_ D free-form amino acids_
Essential amino acids are high biological value proteins (option C).
Biological value proteinsBiological value is the ratio between the amount of amino acids that can be retained (retention) by the body (for body protein synthesis) with the amount of amino acids that can be absorbed by the small intestine.
The quality of protein is determined by the type and proportion of amino acids it contains. Proteins with high biological value or high quality are proteins that contain all types of essential amino acids suitable for growth.
Proteins that are easily digested (hydrolyzed) by digestive enzymes, and contain complete and balanced amounts of essential amino acids (according to the body's needs), are proteins of high nutritional value.
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Which factor(s) affect(s) the brightness of a star as seen from earth?
A) the stars distance from earth
B) the stars temperature
C) the stars mass
D) the earths atmospheric conditions
E) all of the above
Answer:
mehoy noy
Explanation:
Negative charge âq is distributed uniformly around a quarter-circle of radius a that lies in the first quadrant, with the center of curvature at the origin
The electric field due to this charge distribution can be found by applying Gauss' law. The electric field at any point in space is the net sum of all the electric fields due to the individual charges.
What is Gauss' law ?Gauss' law states that the electric flux through any closed surface is equal to the charge enclosed by the surface divided by the permittivity of free space.
To calculate the electric field due to the charge distribution, the first step is to divide the quarter-circle into small segments. Each segment will have a charge q, and will be of width dx. The total charge in the quarter-circle is then given by the integral of q multiplied by dx from 0 to 2πa.
The electric field at any point P in the first quadrant is then given by the integral of q/4πε0 r2 multiplied by dx from 0 to 2πa, where r is the distance from the point P to the center of the quarter-circle. This gives the electric field at P to be:
E = (1/4πε0)∫ 0 to 2πa q/r2 dx
The electric field due to the charge distribution is therefore a function of the distance from the point P to the center of the quarter-circle, and is inversely proportional to the square of this distance.
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what is the dipole magnetic field strength at the equator at geosynchronous orbit? (the equatorial field at the surface is 30 000 nt).
At the geosynchronous orbit, the dipole magnetic field strength is 0.3 nT.
This means that the dipole magnetic field strength at geosynchronous orbit is around 10 000 nT. At the geosynchronous orbit, the strength of the dipole magnetic field is 0.3 nT. The dipole magnetic field is the simplest type of magnetic field that we know. It's generated by the magnetic moment of a simple magnet. This field, in contrast to other magnetic fields, is symmetric about a specific axis.
A geosynchronous orbit is a circular orbit that is equatorial and orbits the Earth. It has a period of 24 hours, which is the same as the Earth's rotation time. Since the Earth is not a perfect dipole, the dipole magnetic field strength varies at different locations. At the equator, the dipole magnetic field strength is 30 000 nT on the surface.
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Why does earth have so little carbon dioxide in its atmosphere compared to venus?.
Compared to Venus, Earth's volcanoes produced significantly less carbon dioxide gas. Carbon dioxide was originally abundant on Earth, but it was lost to space during the violent bombardment that occurred early in the history of our solar system.
Everything boils down to water. Although there are large oceans of liquid water on Earth, Venus and Mars' atmospheres are predicted to be dominated by carbon dioxide. Since carbon dioxide is easily dissolved in water, our oceans absorbed a large portion of the atmospheric CO2, leaving an ammonia-dominated environment. Evidently, Venus is close enough to the Sun that the small amount of carbon dioxide in its early atmosphere, which was similar to Earth's, led the surface to warm and release additional carbon dioxide into the atmosphere.
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A tortoise can move with a speed of 10.0cm/s, while a rabbit can move 10 times faster. In a race, both of them started at the same time, but the rabbit stopped to rest for three minutes. The tortoise wins by a distance of 10cm from the rabbit. How long is the race?
A. 125.2s
B. 159.8s
C. 199.9s
D. 205.7s
Answer:
C. 199.9 s
Explanation:
3 minutes = 3×60 = 180 seconds.
the turtle moves in that time 180×10 = 1800 cm.
in other words the rabbit gave it that much head-start (it does not matter if that was at the begin of in the middle of the race).
the rabbit moves with 10×10cm/s = 100cm/s.
the rabbit needs therefore 1800/100 = 18 seconds for the
1800 cm.
at that time the turtle has added another 18×10 = 180 cm.
for which the rabbit needs 180/100 = 1.8 seconds.
during that time the turtle has added 1.8×10 = 18 cm.
and so on.
in formal mathematics this looks like this :
1800 + 10x = 100x
after x seconds of the rabbit running both will have run the same distance, and it is a tie.
1800 = 90x
x = 20 seconds
so, at that point, the rabbit was actively running for 20 seconds and raced 20×100 = 2000 cm
and the turtle was actively running for 180 + 20 = 200 seconds, and also covered 200×10 = 2000 cm.
but our question tells us that the turtle won by 10 cm.
so, the race was over a little bit before these 200 seconds (for a tie).
this means, the rabbit could not run the last 10 cm for the tie (because the race was over and the turtle had won).
the rabbit would have needed 10/100 seconds for these 10 cm.
as speed = distance/time
we need to divide distance by speed
distance/1 / distance/time
to get time.
so,
10cm/1 / 100cm/s = 10s/100 = 1/10 s
so, we need to deduct this 1/10 s from the 200 seconds of the turtle (and also from the 20 seconds for the rabbit).
the race lasted of course the whole time the turtle was running (while the rabbit was resting, officially still participating in the race with speed 0 for 3 minutes).
and so, the race was 199.9 s long.