define "seperation of centrifugation"




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Answer:

c....

Explanation:

hope its help...

correct me if im wrong:>

Is he strong enough to lift a 5.3kg weight?

Answer: A. No

Explanation: Obviously, a rooster is not strong enough to lift a 5.3kg weight because a normal rooster would weigh 10kg.

Answer:

C. Smoking damages the cilia in the respiratory system

Answer:

C. Smoking damages the cilia in the respiratory system.

Explanation:

Hope this helped.

Answer:

An exothermic reaction

Answer:

Nucleic acids

Answer:

Nucleic acids is the correct answer hope it helps

Answer:

4H₂O(l) → 4H₂(g) + 2O₂(g)

Balancing equations

1. 3Fe(s) + 4H₂O(g) → Fe₃0₄(s) + 4H₂(g)

2. 2AlBr₃(aq) + 3Cl₂(g) → 2AlCl₃(aq) + 3Br₂(l)

3. 2HNO₃(aq) + Ba(OH)₂(aq) → Ba(NO₃)₂(aq) + 2H₂O(l)

4. 2Al(s) + 3Pb(NO₃)₂ → 2Al(NO₃)₃(aq) + 3Pb(s)

5. 3NaOH(aq) + Fe(NO₃)₃ → Fe(OH)₃(s) + 3NaNO₃(aq)

Explanation:

From the question given, I have been able to balance the chemical equations correctly.

In balancing chemical equations, the chemical equation must have equal number of atoms for each element that are both in the reactant side and in the product side.

For the above to be achieved, the number of atoms in each element will have to be multiplied and added.

A look at the balanced chemical equation above, you will discover that each element has the same number of atoms both in the reactant side and in the product side.

The bond order is calculated as follows: Bond Order = (2 x 2) + (2 x 1) / 4 = 6 / 4 = 1.33

The arsenate ion (AsO4 3-) has:

A) Four equivalent resonance structures.

B) There are two double bonds around the central arsenic atom.

C) There are two single bonds around the central arsenic atom.

D) The bond order of all the bonds in the arsenate ion is 1.33. This is because there are two double bonds and two single bonds in each of the equivalent resonance structures, and the average bond order is the sum of the bond orders divided by the number of bonds. Thus, the bond order is calculated as follows:

Bond Order = (2 x 2) + (2 x 1) / 4 = 6 / 4 = 1.33

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The molar mass of the unknown gas is 43.87 g/mol.

To determine the molar mass of the unknown gas, consider Graham's law of effusion, wherein we can equate the ratio between the times of effusion of the two gases, to the ratio of the roots of the molar masses of the unknown gas and He gas, such that:

t_He / t_unknown gas = √MW_He / √MW_unknown gas

If He gas is observed to effuse through a porous barrier in 8.76 minutes and under the same conditions, the same number of moles of an unknown gas requires 29.0 minutes to effuse through the same barrier, then the molar mass of the unknown gas can be solved as follows.

8.76 minutes / 29.0 minutes = (√4.002602 g/mol) / √MW_unknown gas

√MW_unknown gas = (√4.002602)(29.0 minutes) / (8.76 minutes)

MW_unknown gas = 43.87 g/mol

Hence, the molar mass of the unknown gas is 43.87 g/mol.

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The correct option is D, The equivalence point occurs at a pH greater than 7 for a titration of a weak acid with a strong base. This is because the strong base will react with the weak acid to form a salt and water.

Titration is a commonly used analytical technique in chemistry for determining the concentration of an unknown solution by adding a known amount of a standardized solution of known concentration. The process involves slowly adding the standardized solution to the unknown solution until the chemical reaction between the two is complete. The point at which the reaction is complete is known as the equivalence point and can be detected using various indicators that change color or other properties at this point.

The main aim of titration is to accurately measure the concentration of a particular substance in a solution. For example, an acid-base titration can be used to determine the concentration of an acid in a solution by adding a known amount of a strong base until the equivalence point is reached. Similarly, a redox titration can be used to determine the concentration of a reducing or oxidizing agent in a solution.

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Launching a projectile over a significant distance, such as several hundred miles, presents a range of complex challenges that must be carefully addressed. The success of achieving such a long range relies on accounting for various factors that influence the projectile's trajectory, including aerodynamics, atmospheric conditions, Earth's curvature, and external forces.

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Answer:

323.15

Explanation:

323.15

Answer:323.15

Explanation:

A nitrogen molecule moving at a velocity of 5000 mph has the shortest de Broglie wavelength.  option D)

The de Broglie wavelength of a particle is given by the formula:

λ = h / p

where λ is the de Broglie wavelength, h is the Planck constant, and p is the momentum of the particle.

The momentum of a particle is given by:

p = mv

where m is the mass of the particle and v is its velocity.

We can see that the de Broglie wavelength is inversely proportional to the momentum of the particle. So, the particle with the highest momentum will have the shortest de Broglie wavelength.

Let's calculate the momentum of each particle:

A) An airplane with a velocity of 300 mph has a very large mass and hence, a very low momentum. Its de Broglie wavelength will be very long.

B) A helium nucleus has a very small mass and a high velocity. Its momentum will be relatively high compared to the other particles.

C) A nitrogen molecule has a higher mass than helium, but its velocity is the same. So, its momentum will be lower than that of the helium nucleus.

D) A nitrogen molecule with a velocity of 5000 mph will have a higher momentum than the other particles because of its higher velocity.

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Answer:

Excess fertilizer alters the soil by creating too high of a salt concentration, and this can hurt beneficial soil microorganisms. Over- fertilization can lead to sudden plant growth with an insufficient root system to supply adequate water and nutrients to the plant

Explanation:

Answer:

maybe a convergent.......

Answer:

The correct answer is the divergent boundary.

Explanation:

Hi there, let's work through this together! A divergent boundary in plate tectonics refers to a linear characteristic, which prevails amid the two tectonic plates that are moving away from each other. The Mid-Atlantic Ridge and the Great Rift Valley are the examples of divergent boundaries.

Iceland is an illustration of a country going through a continental divergent boundary. The Mid-Atlantic Ridge differentiates Iceland and is the boundary between the Eurasian and the North American tectonic plates. Hope this helped!

ฮH=+ ฮ๐=+ (Endothermic and expansion)

In this phase change, heat is absorbed by the system, and the volume of the system increases.

ฮH=+ ฮ๐=โ (Endothermic and compression)

In this phase change, heat is absorbed by the system, but the volume of the system decreases.

ฮH=โ ฮ๐=+ (Exothermic and expansion)

In this phase change, heat is released by the system, and the volume of the system increases.

ฮH=โ ฮ๐=โ (Exothermic and compression)

In this phase change, heat is released by the system, but the volume of the system decreases.

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Hydrolysis occurs when Fe2O3 is dissolved in water, resulting in the formation of Fe(OH)3 and H+ ions. For every Fe in Fe2O3, there are 1.5 O. Thus, the iron content of Fe2O3 is reduced.

Water in the liquid state serves as the solvent in an aqueous solution. In other words, water molecules surround and integrate solute (dissolved) ions and molecules into their web of bonds. Following that, the dissolved species dispersed all over the water.

Aqueous solutions are made up of water and one or more dissolved materials. Solids, gases, or other liquids can all dissolve in an aqueous solution.

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Question:

How Many Particles Fe2O3 Will Produce In An Aqueous Solution (In Water).

A) The partial pressure of argon in the flask is approximately 0.906 atm. B) The partial pressure of ethane in the flask is approximately 0.144 atm.

We need to calculate the partial pressure of argon (PAr) in the flask.

Given;

Volume (V) = 1.00 L

Total pressure (Ptotal) = 1.050 atm

Temperature (T) = 25 °C = 298 K

Mass of argon (m) = 1.10 g

Molar mass of argon (M) = 39.95 g/mol

First, let's calculate the number of moles of argon using the mass and molar mass:

n = m / M

n = 1.10 g / 39.95 g/mol

Next, we can calculate the partial pressure of argon (PAr) using the ideal gas law;

PV = nRT

PAr × V = n × R × T

PAr = (n × R × T) / V

Substituting the given values;

PAr = (n × R × T) / V

PAr = [(1.10 g / 39.95 g/mol) × (0.0821 L·atm/(mol·K) × 298 K] / 1.00 L

Calculating PAr using the above expression, we get;

PAr ≈ 0.906 atm

Therefore, the partial pressure of argon in the flask is approximately 0.906 atm.

Given;

Total pressure (Ptotal) = 1.050 atm

Partial pressure of argon (PAr) = 0.906 atm (calculated in Part A)

To find the partial pressure of ethane (Pethane), we can use Dalton's law of partial pressures, which states that the total pressure of a mixture of gases is equal to the sum of the partial pressures of the individual gases.

Ptotal = PAr + Pethane

Rearranging the equation to solve for Pethane;

Pethane = Ptotal - PAr

Substituting the given values;

Pethane = 1.050 atm - 0.906 atm

Calculating Pethane using the above expression, we get;

Pethane ≈ 0.144 atm

Therefore, the partial pressure of ethane in the flask is approximately 0.144 atm.

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--The given question is incomplete, the complete question is

"Part A What is the partial pressure of argon, Par, in the flask? Express your answer to three significant figures and include the appropriate units. Constants1 Periodic Table A 1.00 L flask is filled with 1.10 g of argon at 25 °C. A sample of ethane vapor is added to the same flask until the total pressure is 1.050 atm View Available Hint(s) PAr Value Units Submit."--

Answer:

can you give me more info

Explanation:

i think it d or c

i got charts to help

Answer:

7.44 grams CaCl2 will produce 10.0 grams KCl.

Explanation:

The equation is balanced:

I've repeated it here, with the elements corrected for their initial capital letter.

CaCl2( aq) K2CO3( aq) → 2KCl( aq) CaCO3( aq)

This equation tells us that 1 mole of CaCl2 will produce 2 moles of KCl.

If we want 10.0g of KCl, we need to convert that mass into moles KCl by dividing by the molar mass of KCl, which is 74.55 grams/mole.

 (10.0 grams KCl)/(74.55 grams/mole) = 0.1341 moles of KCl.

We know that we'll need half that amount of moles CaCl2, since the balanced equation says we'll get twice the moles KCl for every one mole CaCl2.

So we'll need (0.1341 moles KCl)*(1 mole CaCl2/2moles KCl) = 0.0671 moles CaCl2.

The molar mass of CaCl2 is 110.98 grams/mole.

(0.0671 moles CaCl2)*(110.98 grams/mole) = 7.44 grams CaCl2

7.44 grams CaCl2 will produce 10.0 grams KCl.

Answer:the plastic bag will attract the cloth

Explanation:

Answer:

c

Explanation:

hope this helps

1.22 grams of water has 5.0 x10^22 H2O water molecules.

A molecule is a group of two or more atoms held together by attractive forces known as chemical bonds. There is no guarantee that the term will include ions that meet this criterion, depending on the context.

Calculate the number of moles of water = mass / molar mass of water

Moles = 1.2 g/ 18 g/mol = 0.083 mol H2O

1 mole of any substance = 6.02 x 10^23 H2O molecules (Avogadro's number)

Resolution:

Molecules = 0.083 moles (6.02 x 10^23 H2O molecules/mole)

= 0.5 x 10^23 or 5.0 x10^22 H2O molecules

answer:

Number of molecules = 5.0 x 10^22 H2O molecules  

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Answer:

B

Explanation:

Use the molar mass of H2SO4 to get moles of H2SO4; 51.2g/98.079g=0.522

Divide 500 mL by 1000 to get L

Molarity = moles of solute/L of solution; so divide the moles by 0.5L

Answer:

shuuuuuuuuuuuuuuuuuuuuuuush

Explanation:

shush suuush shuuush

Answer:

please give me brainlist and follow

Explanation:

Contamination of ground water can result in poor drinking water quality, loss of water supply, degraded surface water systems, high cleanup costs, high costs for alternative water supplies, and/or potential health problems. The consequences of contaminated ground water or degraded surface water are often serious.

Answer:

There are several factors that contribute to the preservation of impact craters on the surface of bodies in the Solar System.

One factor is the lack of erosion or weathering on these bodies. Many of the bodies in the Solar System, such as the Moon and many of the outer planets' moons, do not have atmospheres or hydrospheric systems (like oceans, lakes, or rivers) that can erode or weather the surface over time. This means that the surface of these bodies is not subjected to the same types of processes that can wear away or smooth out surface features on Earth. As a result, impact craters and other surface features can remain well-preserved for millions of years.

Another factor that can contribute to the preservation of impact craters is the presence of a surface layer of material that is resistant to erosion. For example, on the Moon, the surface is covered by a layer of fine-grained dust called regolith, which is made up of small rocks and particles that have been ground up by impact and other processes. This regolith layer is relatively soft and easily disturbed, but it also acts as a protective layer that can preserve the underlying surface features. Similarly, on some of the outer planets' moons, there may be a layer of ice or other materials that can act as a protective layer and preserve impact craters and other surface features.

Examples of bodies in the Solar System that have well-preserved impact craters include the Moon, Mars, and many of the outer planets' moons, such as Europa and Ganymede. The lack of erosion and the presence of protective surface layers on these bodies have allowed them to maintain countless well-preserved indications of impacts on their surfaces even after many millions of years.

Explanation:

To solve this, we must know each and every concept behind solar system. Therefore, impact craters enable scientists to investigate the geological history of a planet.

The Solar System is composed of the Sun and the objects that orbit it. It was created by the gravitational collapse of a massive interstellar molecular cloud 4.6 billion years ago. The Sun contains the vast bulk of the system's mass (99.86%)

Several processes contribute to the preservation of impact craters on the surfaces of Solar System worlds. The absence of erosion or weathering on these bodies is one cause. Another aspect that can aid in the preservation of impact craters is the existence of an erosion-resistant surface layer of material.

Therefore, impact craters enable scientists to investigate the geological history of a planet.

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Answer:

Mass and Volume

Explanation:

The formula for density is

\(\frac{Mass}{Volume}\)

The statement "A sigma bond is weaker than a pi bond" is not correct. In fact, a sigma bond is stronger than a pi bond because it allows for a greater overlap of orbitals, resulting in a more stable bond.

A sigma bond is formed by the direct overlap of atomic orbitals along the axis connecting the two bonded nuclei, while a pi bond is formed by the overlap of atomic orbitals that are parallel to the bonded nuclei.

In terms of double bonds versus single bonds, a double bond is stronger than a single bond because it consists of one sigma bond and one pi bond, resulting in more electron density between the bonded nuclei.

Additionally, a double bond is shorter than a single bond because the two bonded atoms are held closer together due to the presence of the additional bond.

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Answer:

See the answer below

Explanation:

In chemistry, indicators are substances that are capable of changing colors with respect to the pH. Each indicator has its characteristic color in acidic pH and another characteristic color in alkaline pH.

Methyl orange indicator appears red in acidic solution and yellow in basic solutions. Phenolphthalein is usually colorless in acidic solutions and appears pink in basic solutions. A red litmus paper will turn blue in alkaline solutions while a blue litmus paper will turn red in acidic solutions.