Define physical laws​

The distance between the two objects is reduced in half, that will be the changed force of attraction between them is option (E) 2.5 newtons.

According to Newton's law of universal gravitation, the force of attraction between two objects is inversely proportional to the square of the distance between them.

If the distance between Object A and Object B is reduced to half, the force of attraction will increase by a factor of 2² = 4. This means that the new force of attraction will be one-fourth of the original force.

Given that the original force of attraction is 5 newtons, the changed force of attraction between Object A and Object B, when the distance is reduced in half, will be 5 newtons / 4 = 1.25 newtons, which can be rounded to 2.5 newtons.The correct answer is option e.

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Answer:

intensity

Explanation:

b. example, The sun is very bright and intense. and sounds can be very loud.

Answer:

10m

Explanation:

let's take the acceleration as a constant throughout the complete motion...

therefore first let's find the acceleration

\(s = ut + \frac{1}{2} a {t}^{2} \\ 2 = \frac{1}{2} a {1}^{2} \\ a = 4m {s}^{ - 2} \)

then we have to find v1

apply V = u + at

v = 4×1

= 4ms^-1

lets find the distance travel by the object DURING THE TIME INTERVAL 1-2

\(s = ut + \frac{1}{2} a {t}^{2} \\ s = 4 \times 1 + \frac{1}{2} \times 4 \times {1}^{2} \\ s= 6m \)

then let's find the V2

\( {v}^{2} = {u}^{2} + 2as \\ {v}^{2} = {4 }^{2} + 2 \times 4 \times 6 \\ {v}^{2} = 64 \\ v = \sqrt{64} = 8m {s}^{ - 1} \)

\(s = ut + \frac{1}{2} a {t}^{2} \\ s = 8 \times 1 + \frac{1}{2} \times 4 \times {1}^{2} \\ s = 10m \)

The distance traveled by the object during the time interval from t = 2 seconds to t = 3 seconds would be 10 meters, therefore the correct answer is option B.

There are three equations of motion given by  Newton

v = u + at

S = ut + 1/2×a×t²

v² - u² = 2×a×s

As given in the problem, an object released from rest at time t = 0 slides down a frictionless incline a distance of 2 m during the time interval from t=0 seconds to t = 1 seconds.

2 = ut + 1/2*a*t²

2 = 0 + 0.5×a×1²

a = 2 / 0.5

a = 4 meters / second²

Now to find the velocity after the 2 seconds,

v = u + at

v = 0 + 4×2

v = 8 m/s

Now by using the second equation of motion,

S = ut + 1/2×a×t²

S = 8×1 + 0.5×4×1²

S = 8 + 2

S = 10 meters

Thus, The distance traveled by the object during the time interval from t = 2 seconds to t = 3 seconds would be 10 meters, therefore the correct answer is option B.

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The motorcycle had covered a distance of 16 meters in half the total time.

a) To calculate the acceleration, we can use the formula:

a = (v - u) / t

where a is the acceleration, v is the final velocity, u is the initial velocity (which is 0 since the motorcycle starts from rest), and t is the time.

Given:

u = 0 m/s (initial velocity)

v = ? (final velocity)

t = 4 s (time)

s = 64 m (distance)

Using the equation of motion:

s = ut + 1/2at^2

We can rearrange the equation to solve for acceleration:

a = 2s / t^2

a = 2(64) / (4)^2

a = 128 / 16

a = 8 m/s^2

Therefore, the acceleration of the motorcycle is 8 m/s^2.

b) To find the final velocity, we can use the formula:

v = u + at

v = 0 + (8)(4)

v = 32 m/s

Therefore, the final velocity of the motorcycle is 32 m/s.

c) To determine the time at which the motorcycle had covered half the total distance, we divide the total distance by 2 and use the formula:

s = ut + 1/2at^2

32 = 0 + 1/2(8)t^2

16 = 4t^2

t^2 = 4

t = 2 s

Therefore, the motorcycle had covered half the total distance at 2 seconds.

d) To calculate the distance covered in half the total time, we use the formula:

s = ut + 1/2at^2

s = 0 + 1/2(8)(2)^2

s = 0 + 1/2(8)(4)

s = 0 + 16

s = 16 m

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The equipotential surfaces associated with a point charge are concentric shells.

Charged material experiences a force when it is exposed to an electromagnetic field due to the physical property of electric charge. You can have a positive or negative electric charge.

The equipotential surface is the region where all points with the same potential are located. On the equipotential surface, a charge can be moved from one point to another without exerting any effort.

Thus,a point charge's related equipotential surfaces are concentric shells.

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If we replace the incandescent bulb with a voltage meter and return the loop to its original configuration, then moving the bar magnet back and forth through the loop will induce an electrical current in the loop, as described by Faraday's law of electromagnetic induction.

A magnet is a material or object that produces a magnetic field, which is a force that can attract or repel certain other materials, such as iron or steel. The magnetic field is created by the motion of electric charges within the magnet, which align in such a way that they produce a net magnetic field. Magnets can be made from a variety of materials, including iron, cobalt, nickel, and certain alloys. They come in many different shapes and sizes, including bars, discs, horseshoes, and rings.

Here,

The type of current that is generated depends on the direction and rate of the magnet's motion. If the magnet is moved back and forth with a constant speed and in a straight line, the current induced in the loop will be an alternating current (AC), because the direction of the current will reverse every time the magnet changes direction. This can be observed by the voltage meter reading a voltage that periodically changes in direction.

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Answer:

240 rupees

Explanation:

As 7 kg of onions costs 140 rupees, each kg costs 20 rupees, and 12x20=240 rupees.

Answer:  7kg = 140 Rupees. Now we had the cost of one onion is 20 Rupees. = 240 Rupees.

Answer:

Explanation:

Do math

Answer:

0.25916 lb-s/ft^2

Explanation:

Given:-

- The specific gravity of oil, SGo = 0.8

- The specific gravity of sphere, SGo = 8

- Terminal velocity of sphere, v = 2.5 fpm

- The diameter of sphere, D = 0.25 in

Find:-

What is the viscosity of the oil?

Solution:-

- Consider a sphere completely submerged into oil and travelling with terminal velocity ( v ).

- Develop a free body diagram for the sphere. There are forces acting on the sphere.

- The downward acting force is due to the weight of the sphere ( W ):

                         \(W = m_s*g\)

Where,

The mass ( m_s ) of the sphere is given as:

                          \(m_s = S.G_s*p_w*V_s\)

Where,

              ρ_w : Density of water = 1.940 slugs/ft3

               V_s: The volume of object ( sphere )

- The volume of sphere is expressed as a function of radius:

                        \(V_s = \frac{\pi *D^3}{6}\)

Hence,

                        \(W = S.G_s*p_w*\frac{\pi*D^3 }{6}* g\\\\W = 8*1.940*\frac{\pi*(0.25/12)^3 }{6}*32\\\\W = 0.00235 lb\)

- One of the upward acting force is the buoyant force ( Fb ) that is proportional to the volume of fluid displaced by the immersed object.

- The buoyant force ( Fb ) is given by:

                    \(F_b = S.G_o*p_w*V_s*g\)

- Therefore the buoyant force ( Fb ) becomes:

                    \(F_b = 0.8*1.94*\frac{\pi*(0.25/12)^3 }{6} *32\\\\F_b = (4.73451*10^-^6)*(49.664)\\\\F_b = 0.00023 lb\)

- The other upward acting force is the frictional drag ( F_d ) i.e the resistive frictional force acting on the contact points of the sphere and the fluid oil.

- From stokes formulations the drag force acting on a spherical object which is completely immersed in a fluid is given as:

                    \(F_d = 3*\pi*D*u*v\)

Where,

                    μ: The viscosity of fluid

                    v : The velocity of object

Therefore,

                       \(F_d = 3*\pi*\frac{0.25}{12} *u*0.041666\\\\F_d = 0.00818*u\\\)

- Apply Newton's second law of motion for the sphere travelling in the fluid:

                      \(F_n_e_t = m_s*a\)

Where,

                     a: Acceleration of object = 0 ( Terminal velocity condition )

                     \(F_n_e_t = 0\)

- Plug in the three forces acting on the metal sphere:

                     \(F_d + F_b - W = 0\\\\F_d = W - F_b\\\\0.00818*u = 0.00235 - 0.00023\\\\u = \frac{0.00212}{0.00818} = 0.25916 \frac{lb-s}{ft^2}\)

First divide the parts where it is a rectangle and semicircle.

Find the area of the rectangle:

A = length × breadth

A = 18m × 16m

A = 288m²

Then find the area of the semi-circle. We know that the area of a circle is πr² and half that area gives you the area of a semi-circle: πr²/2

A = πr²/2

A = π(6)²/2

A = 18πm² or 56.549m²

Total Area = 288m² + 18πm²

                                OR

                    288m² + 56.549m² = 344.549m²

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Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe.

Galileo Galilei played a crucial role in challenging the prevailing geocentric model of the universe proposed by Aristotle and supported by Ptolemy. He provided several lines of evidence that effectively disproved their theories and supported the heliocentric model proposed by Nicolaus Copernicus. Some of the key evidence used by Galileo includes:

1. Observations through a telescope: Galileo was one of the first astronomers to use a telescope to observe the heavens. His telescopic observations revealed several important discoveries that contradicted the Aristotelian-Ptolemaic worldview. He observed the phases of Venus, which demonstrated that Venus orbits the Sun and not Earth. He also observed the four largest moons of Jupiter, now known as the Galilean moons, which provided evidence for celestial bodies orbiting a planet other than Earth.

2. Sunspots: Galileo's observations of sunspots provided evidence that the Sun is not a perfect celestial body, as suggested by Aristotle. Sunspots indicated that the Sun has imperfections and undergoes changes, challenging the notion of celestial perfection.

3. Mountains on the Moon: Galileo observed the rugged and uneven surface of the Moon, which contradicted Aristotle's belief in celestial spheres made of perfect, unchanging material. The presence of mountains on the Moon suggested that celestial bodies are subject to the same physical laws as Earth.

4. Phases of Venus: Galileo's observations of the phases of Venus provided direct evidence for the heliocentric model. As Venus orbits the Sun, it goes through phases similar to the Moon, ranging from crescent to full. This observation strongly supported the idea that Venus revolves around the Sun.

These lines of evidence presented by Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe. His work marked a significant turning point in the history of science and laid the foundation for modern astronomy.

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Answer:

A. Build a nest.

Explanation:

It wont do any of the other things and they need a place to sleep and lay eggs plus it is a bird

The heron birds belong to Ardeidae family. Some of the species among them are referred to as egrets or bitterns rather than a heron. A heron bird  build a nest during Spring. The correct option is A.

The heron is known as a long-legged, long-necked, fresh water and coastal birds. It a medium to large size bird with long necks and legs. They exhibit sexual dimorphism in size. The two male and female sex of the same species show distinct attributes beyond their difference in sexual organs.

Almost all the heron species are found in water and they are essentially non-swimming water birds which feed on the margins of lakes, ponds, sea, rivers and swamps. The small species of heron are generally referred to as the dwarf bittern.

The nesting season indicates the time of year during which birds build nests and lay eggs in them. In most cases bring up their young. It is in the spring season lot of food are available.

Thus the correct option is A.

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The mass of Brachiosaurus moves with a momentum of 134,054 kgm/s  and the velocity is 3.9 m/s, which is 34.37 kg.

The momentum is the product of mass and velocity. The momentum is the vector quantity and the unit of momentum is Kgm/s.

Momentum = mass × velocity

 mass    = momentum/velocity

momentum =  134,052 kgm / s

velocity = 3.9 m/s

mass = 134052 / 3.9

         = 34.37 kg

Thus, the mass of Brachiosaurus is 34.37 kg.

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The time required to crumple the barrier and safely slow down the person with a force of 1650 N is approximately C, 1.1 seconds.

To determine the time required to crumple the barrier and safely slow down the person with a maximum force of 1650 N, use the equation of motion:

F = m × a

where:

F = force

m = mass

a = acceleration

Given:

m = 68 kg

F = 1650 N

Find the acceleration (a) first. Rearranging the equation:

a = F / m

Substituting the values:

a = 1650 N / 68 kg

a ≈ 24.26 m/s²

Now, use the equation of motion to find the time (t):

v = u + at

where:

v = final velocity (0 m/s as the person comes to a stop)

u = initial velocity (27 m/s)

a = acceleration (24.26 m/s²)

t = time

Rearranging the equation:

t = (v - u) / a

Substituting the values:

t = (0 m/s - 27 m/s) / 24.26 m/s²

t ≈ -27 m/s / 24.26 m/s²

t ≈ -1.11 s

The negative sign indicates that the time is in the opposite direction to the initial velocity. Taking the absolute value, the time required to crumple the barrier and safely slow down the person with a force of 1650 N is approximately 1.11 seconds.

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Answer:

The radius of the circular plate is 0.774 m

Explanation:

Given;

distance between the parallel plates, d = 1.53 cm = 0.0153 m

electric field energy density between plates, \(U_E\)  = 4.41 J/m³

Potential energy of the capacitor, \(U_c\) = 0.127 J

Energy density is given as;

\(U_E = \frac{U_c}{V}\)

where;

V is volume

\(V = \frac{U_c}{U_E} = \frac{0.127}{4.41} = 0.0288 \ m^3\)

Volume is given as;

V = Ad

where;

A is area

A = V / d

A = (0.0288) / (0.0153)

A = 1.882 m²

Area of circular plate is given as;

A = πr²

where;

r is the radius of the circular plate

\(r = \sqrt{\frac{A}{\pi} } \\\\r = \sqrt{\frac{1.882}{\pi}}\\\\r = 0.774 \ m\)

Therefore, the radius of the circular plate is 0.774 m

Fan made of plastic bottle is an innovative way to reuse plastic bottles and can be easily made at home. This can be done by following simple steps, and a few materials are required to make it. The fan can be created by using a plastic bottle, scissors, string, a ruler, and a marker.

First, the bottle needs to be cut into half, and the upper part needs to be cut into three equal sections, then fold each section to make a blade. With the help of a ruler and marker, make a mark on each section, then make a hole in the center of each blade. Insert a string through the holes and tie the ends of the strings. The fan is ready to use by holding the string and swinging it back and forth.

The use of plastic bottle fans can significantly reduce the number of plastic waste and provide a practical solution to avoid environmental pollution. Besides, it is easy to make, and the materials are readily available, which can be used for various occasions, such as picnics, camping, or any outdoor activities.

In conclusion, the creation of a fan made of plastic bottle with string is an excellent way to reuse plastic bottles and can be made with simple steps. This project encourages everyone to contribute to environmental protection by utilizing what is available at home and reducing the number of plastic wastes.

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\( \\ \)

Like gases, plasmas have no fixed shape or volume, and are less dense than solids or liquids. But unlike ordinary gases, plasmas are made up of atoms in which some or all of the electrons have been stripped away and positively charged nuclei, called ions, roam freely.

\( \\ \)

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Answer:

Magnitude of Paula’s acceleration\($a=39 \cdot 8m/sec^{2}$.\)

Explanation:

• An object is said to be accelerated if there is a change in its velocity. At any point on a trajectory, the magnitude of the acceleration is given by the rate of change of velocity in both magnitude and direction at that point.

• To find the magnitude of her acceleration, use the formula:                               \($${v^2} = {u^2} + 2as$$\)

Where, is final velocity, is initial velocity, is acceleration and is displacement.

• Placing the value of the given initial velocity, \($u=0m/s$\), displacement, \($s = 0 \cdot 201m$\) and the final velocity,\($v = 4m/s$\) in the above formula.

\(\[\begin{align}& \therefore{v^2} = {u^2} + 2as \\& \Rightarrow {\left( 4 \right)^2} = 0+ 2\left( a \right) \left( { 0 \cdot 201} \right) \\& \Rightarrow 16 = 0 \cdot 402a \\& \Rightarrow a = 39 \cdot 8m/sec^{2} \\\end{align}\]\)

\(\[& \therefore{v^2} = {u^2} + 2as \\& \Rightarrow {\left( 4 \right)^2} = 0+ 2\left( a \right) \left( { 0 \cdot 201} \right) \\& \Rightarrow 16 = 0 \cdot 402a \\& \Rightarrow a = 39 \cdot 8m/sec^{2} \\\]\)

• Hence, magnitude of her acceleration, \($a=39 \cdot 8m/sec^2$\)

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The third equation of free fall can be applied to determine the acceleration. So that Paola's acceleration during the flight is 39.80 m/\(s^{2}\).

Acceleration is a quantity that has a direct relationship with velocity and also inversely proportional to the time taken. It is a vector quantity.

To determine Paola's acceleration, the third equation of free fall is appropriate.

i.e \(V^{2}\) = \(U^{2}\) ± 2as

where: V is the final velocity, U is the initial velocity, a is the acceleration, and s is the distance covered.

From the given question, s = 20.1 cm (0.201 m), U = 4.0 m/s, V = 0.

So that since Poala flies against gravity, then we have:

\(V^{2}\) = \(U^{2}\) - 2as

0 = \((4)^{2}\) - 2(a x 0.201)

  = 16 - 0.402a

0.402a = 16

a = \(\frac{16}{0.402}\)

  = 39.801

a = 39.80 m/\(s^{2}\)

Therefore Paola's acceleration is 39.80 m/\(s^{2}\).

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The percentage of mechanical energy lost (converted into thermal energy) during the collision will be equal to 95.2%.

Kinetic energy is the term used in physics to describe the force that a moving item has.

It is described as the amount of effort necessary to accelerate anybody with a particular mass from rest to a given velocity. Except for variations in speed, the body retains the kinetic energy it gains during acceleration.

As per the information in the question,

Ball's mass, m₁ = 50 g = 0.05 kg

Speed  = v₀

Brick's Mass, m₂ = 1 kg

Assume the speed of the brick after the collision is v.

Use the equation of the principle of conservation of linear momentum,

\(m_1v_o+m_2u_2= v(m_1+m_2)\)

0.5(v₀) + 0 = v(1 + 0.05)

v = (0.05v₀)/1.05

v = 0.048v₀.

Then the total kinetic energy will be:

K.E(initial) = 1/2 × 0.05v₀² + 1/2 × 0.05 × 0²

K.E(initial) = 0.025v₀²

Then,

K.E(final) = 1/2 × (1.05) × (0.048v₀)²

K.E(final) = 0.0012v₀²

So, the amount of mechanical energy lost in collision,

= (0.025v₀² - 0.0012v₀²)/0.025v₀² × 100

= 95.2%.

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This question seems incomplete, the complete question may be:

A 50 g ball of clay traveling at speed vo hits and sticks to a 1.0 kg brick sitting at rest on a frictionless surface. a. Find an expression for the speed of the brick after the collision in terms of vo. b. What percentage of the mechanical energy is lost (i.e. converted to thermal energy) in this collision?

Answer:

Explanation:

In vertebrates, the circulatory system is responsible for transporting oxygen to all the tissues and removing carbon dioxide from them. ... In the grasshopper, exchange of oxygen and carbon dioxide occurs in the tracheal system. Hemolymph plays no part in the process.

The theorem showing that △ ABC ≅ △ def is Density functional theorem.

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The correct statement is " A dry cell battery has magnetic properties.", The correct option is C.

A dry cell battery does generate its own magnetic field due to the flow of electric current through the battery.

The magnetic field is created by the movement of charged particles (electrons) within the battery. This magnetic field is relatively weak and is not typically strong enough to be used for practical applications outside of the battery itself.

So, the magnetic properties of the dry cell battery are important for understanding its behavior within an electrical circuit.

Therefore, The correct answer is option C.

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Answer:

10 m/s²

Explanation:

Given

Solving

The correct answer is 10 m/s² .

Two things are said to be in contact if the smallest distance between a point in one of them and a point in the other one is zero.

Answer:  I'm not sure, but I think it would be a total lunar eclipse

When the moon passes through the penumbra of Earth’s shadow it is referred to as partial lunar eclipse. The correct option is C.

A partial lunar eclipse occurs when the moon is not completely immersed in the umbra of the earth's shadow.

During a partial solar eclipse, the Moon, Sun, and Earth do not align perfectly straight, and the Moon casts only the penumbra of its shadow on Earth. From our vantage point, it appears that the Moon has eaten the Sun.

A shadow's penumbra is the lighter outer edge. Partial solar eclipses are caused by the Moon's penumbra, while penumbral lunar eclipses are caused by the Earth's penumbra. The penumbra is a type of lighter shadow.

The Penumbra is a half-shadow region that occurs when an object only partially covers a light source.

Thus, the correct option is C.

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The time will be the same for both horizontal and vertical component. The initial speed is 10.7 m/s

Speed is a distance travel per time taken. It is a scalar quantity and it is measured in m/s

Given that a person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a height of 52 m and it lands a distance of 35 m from the base of the cliff.

The rock will move vertically downward with initial velocity = 0. The time taken will be constant. That is, same horizontally.

Let us first calculate the time by using the formula

h = ut + 1/2gt²

Where

Substitute all the necessary parameters into the formula

52 = 0 + 1/2 × 9.8 × t²

52 = 4.9t²

t² = 52/4.9

t² = 10.6

t = √10.6

t = 3.26 s

The speed at which the rock was initially kicked can be found by

R = Ut

35 = U × 3.26

U = 35/3.26

U = 10.7 m/s

Therefore, rock was initially kicked at a speed of 10.7 m/s

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The Enron scandal drew attention to accounting and corporate fraud as its shareholders lost $74 billion in the four years leading up to its bankruptcy, and its employees lost billions in pension benefits.

Enron's Board of Directors failed to fulfil its fiduciary duties towards the corporation's shareholders. Secondly, the top executives of Enron were greedy and acted in their own self-interest.

Enron's downfall was attributed to its reckless use of derivatives and special purpose entities. By hedging its risks with special purpose entities which it owned, Enron retained the risks associated with the transactions. This arrangement had Enron implementing hedges with itself.

Enron raised fundamental issues about corporate fraud, accounting transparency, and investor protection.

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