Danielle invests $25,000 in an account that compounds interest continuously and earns 9%. How long will it take for her money to triple? Round to the nearest tenth of a year.

Answer:

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Step-by-step explanation:

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The two groups are given one is those who are studied and other is those who are not studied.

Studied - 88,100,94,79,92,100,95,83,89,99,100,91,89,95,100,93,96,84.

Arrange in order.

79, 83, 84, 88, 89, 89, 91, 92, 93, 94, 95, 95, 96, 99, 100, 100, 100, 100

The mean of this group is

The mean is 92.6.

The median of this group is

Use the median formula for even

Substitute the value of n =18

The median is 93.5.

The mode of this group is 100 as it is appears 3 times .

The another group is not studied group.

Not studied - 82,72,45,91,58,83,65,87,90,77,73,89.

Arrange in order-

45, 58, 65, 72, 73, 77, 82, 83, 87, 89, 90, 91

The mean is determined as

The median is determined as

Substitute n=12.

There is no mode.

So, from the all the data given.

The mean of the group that studied is over 15 percent points higher than the mean of the group that did not studied.

The median of the group that did not studied is less than 80.

In general , those students that studied scored much higher than those students that did not study.

The correct options are a , c and e.

The power series expansion of\(f(x) = 6x^2 - 4\) centered at x = 0 is: \(6x^2 - 4 = -4 + 3x^2 + ...\)

To expand the function \(f(x) = 6x^2 - 4\) in a power series centered at x = 0, we can use the formula:

\(f(x) = ∑n=0^∞ an(x - 0)^n\)

where \(an = f^(n)(0) / n!\) is the nth derivative of f(x) evaluated at x = 0.

First, let's find the first few derivatives of f(x):

\(f(x) = 6x^2 - 4\)

f'(x) = 12x

f''(x) = 12

f'''(x) = 0

f''''(x) = 0

...

Notice that the derivatives of f(x) are zero starting from the third derivative. Therefore, we can write the power series expansion of f(x) as:

\(f(x) = f(0) + f'(0)x + f''(0)x^2 + ...\\= -4 + 0x + 6x^2 + 0x^3 + ...\)

Using the formula for an in the power series expansion, we get:

\(an = f^(n)(0) / n!\)

a0 = f(0) = -4 / 0! = -4

a1 = f'(0) = 0 / 1! = 0

a2 = f''(0) = 6 / 2! = 3

a3 = f'''(0) = 0 / 3! = 0

a4 = f''''(0) = 0 / 4! = 0

...

Substituting these coefficients into the power series expansion, we get:

\(f(x) = -4 + 0x + 3x^2 + 0x^3 + ...\)

Therefore, the power series expansion of\(f(x) = 6x^2 - 4\) centered at x = 0 is: \(6x^2 - 4 = -4 + 3x^2 + ...\)

Note that this power series converges for all values of x with |x| < 1.

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Answer:  1.5

Step-by-step explanation: 4.05x3=12.15

                                             2.75x4.5=12.375  

4.5-3=1.5

Answer:5.7

Step-by-step explanation:

Answer:

Look on brainless

Step-by-step explanation:

Answer: the one to the bottom right. The one under the red one.

Step-by-step explanation:

Hope this helps

Answer:

its d because who askes that question

Answer:

b) SSA

Step-by-step explanation:

come on !

SAS means side-angle-side. that means 2 sides with included angle. we don't have this here.

SSA means side-side-angle. 2 sides and an angle. that is what we have here.

ASA means angle-side-angle. 2 angles with the side between them. that is not the case here.

Janet can simplify and solve the resulting equation to find the Value(s) of y.(y^2 - 1)(y + 1) * (y + y^2 - 5) = (y^2 - 1)(y + 1) * (y^2 + y + 2)

To solve the equation y + y^2 - 5 / (y^2 - 1) = y^2 + y + 2 / (y + 1), Janet needs to get rid of the denominators in order to simplify the equation and solve for y. One way to do this is by multiplying both sides of the equation by the common denominator of all the fractions involved.

In this case, the common denominator is (y^2 - 1)(y + 1). So, Janet should multiply both sides of the equation by (y^2 - 1)(y + 1) to eliminate the denominators.

Multiplying both sides by (y^2 - 1)(y + 1) yields:

(y^2 - 1)(y + 1) * (y + y^2 - 5) / (y^2 - 1) = (y^2 - 1)(y + 1) * (y^2 + y + 2) / (y + 1)

By multiplying, we cancel out the denominators:

(y^2 - 1)(y + 1) * (y + y^2 - 5) = (y^2 - 1)(y + 1) * (y^2 + y + 2)

Now, Janet can simplify and solve the resulting equation to find the value(s) of y.

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When a nonlinear system of equations contains one linear function that touches the quadratic function at its maximum, then the system has one solution

A system of equations is considered nonlinear if it contains at least one nonlinear equation. One linear function in a nonlinear system of equations touches the quadratic function at maximum. It illustrates one solution.

The given system of equation is presented as follows;

Linear function: f(x) = mx + c

Quadratic function: f(x) = ax² + bx + c

It should be noted that given that the linear function touches the quadratic function at maximum we have;

ax² + bx + c = 0

Therefore, if a nonlinear system of equations contains one linear function that touches the quadratic function at its maximum has one solution.

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Answer:

Final temeprature = 29 - 29 = 0c

Step-by-step explanation:

The key to solving this problem is in the statement "the average temperature had fallen by 29c"

This means that the average temperature had reduced by a value of 29c from the initial value, hence we will subtract 29 from the initial temperature

Initial temperature = temperature in July = 29c

in order to find the final temperature, we will subtract 29c from the initial temperature:

Final temperature (temperature in December) = 29 - 29 = 0c

Answer:

Nominal decisions can be broken into two distinct categories: dichotomous decisions and polychotomous decisions.

The number of months that it will take for Wesley to get to the same weight as Jim, given their respective weights, is 6 months

Assuming the number of months is denoted by x, the equation to find Wesley's weight in a given month would be:

= Wesley's current weight + ( 7 x number of months)
= 132 +  7x

This means that Jim's weight would then be:
= 150 + 4 x

This means that the month where both of them will have the same weight would be:

132 + 7x = 150 + 4x

7x - 4x = 150 - 132

3x = 18

x = 18 / 3

x = 6 months

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Answer:

infinite solutions

Step-by-step explanation:

-3x = -x – 2x

Combine like terms

-3x = -3x

Add 3x to each side

-3x+3x = -3x+3x

0 =0

This is always true so there are infinite solutions

\(\\ \rm\Rrightarrow 26+6b\geqslant 2(3b+4)\)

\(\\ \rm\Rrightarrow 26+6b\geqslant 6b+8\)

\(\\ \rm\Rrightarrow 6b-6b\geqslant 8-26\)

\(\\ \rm\Rrightarrow 0\geqslant -14\)

Hence

It has no solutions

Answer:

A. All Real Numbers

Step-by-step explanation:

26 + 6b ≥ 2(3b + 4)

~Simplify

26 + 6b ≥ 6b + 8

~Subtract 26 to both sides

6b ≥ 6b - 18

~Subtract 6b to both sides

0 ≥ -18

Best of Luck!

Answer:

See below ~

Step-by-step explanation:

Given

Solving

Solution

Answer:WAIT HE IS TELLING THE TIME

Step-by-step explanation:

Answer:51 degrees

Step-by-step explanation:

At noon the temperature is 75 degrees

the temperature drops 3 degrees every half hour.

First solve for time elapsed between noon and 4, which is 4 hours.

Next, we can change our rate to be in terms of full hours instead of half hours using the fact that 1 hr = 2 half hours, so the temperature drops 6 degrees every hour.

Four hours have elapsed so multiply 6*4 = 24 degrees and then subtract it from the starting 75

75 - 24 = 51.

Answer:

A

Step-by-step explanation:

because when we multiply two powers the power will add

The relation "r" on the set of all integers, where x = y^2, is not reflexive.

A relation is reflexive if every element in the set is related to itself. In this case, for the relation x = y^2 to be reflexive, every integer "x" should be related to itself, meaning that x = x^2. However, this is not true for all integers.

For example, if we consider x = 2, it is not equal to 2^2 = 4. Similarly, if we consider x = -3, it is not equal to (-3)^2 = 9.

Since there are integers that do not satisfy the condition x = x^2, the relation x = y^2 is not reflexive on the set of all integers.

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Answer:

poly Gon have \( \huge\color{blue}{ \rule{1pt}{999999pt}}\)\( \huge\color{blue}{ \rule{1pt}{999999pt}}\)\( \huge\color{blue}{ \rule{1pt}{999999pt}}\)\( \huge\color{blue}{ \rule{1pt}{999999pt}}\)\( \huge\color{blue}{ \rule{1pt}{999999pt}}\)\( \huge\color{blue}{ \rule{1pt}{999999pt}}\)\( \huge\color{blue}{ \rule{1pt}{999999pt}}\)\( \huge\color{blue}{ \rule{1pt}{999999pt}}\)

0.01 second does it take to send Data out 10 bits.

What are an example and data?

Text, observations, figures, photos, numbers, graphs, and symbols can all be used as forms of data. Individual prices, weights, addresses, ages, names, temperatures, dates, or distances, for instance, might be included in the data.

                      Data is a basic type of knowledge and has no meaning or use by itself.

Sending rate = 1000 bps

Rate of 1000 bps means that data is sent at a rate of 1000 bits per second

Hence, to send out 10 bits

1000 bits = 1 second

10 bits = x

1000x = 10

x = 10 / 1000

x = 0.01 second

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The sum of deviations of the individual observations from their sample mean is , always equal to zero , the correct answer is (e) .

The sum of deviations from their sample mean is always equal to zero,  because deviation of each observation from sample mean can be positive or negative, depending on whether observation is above or below mean, respectively.

The mean is the average of all the observations, the positive and negative deviations will cancel each other out, and the sum of all deviations will always equal zero.

Therefore, the correct answer is (e) always equal to zero.

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The given question is incomplete , the complete question is

The sum of deviations of the individual observations from their sample mean is

(a) Sometimes greater than and sometimes less than zero, depending on the observations

(b) Always less than zero

(c) Always greater than zero

(d) We do not have enough info to answer this question

(e) always equal to zero.

The sequence is arithmetic. The common difference is 6. Answer: b

If a sequence is arithmetic, there exists a common difference d that is added to each term to get the next term. For instance, given the sequence 2, 5, 8, 11, 14, ...  to get each of the subsequent terms, we add 3. 2 + 3 = 5; 5 + 3 = 8, and so on.

The given sequence is 2,7,13,20, ...To determine whether it is an arithmetic sequence, we need to find the common difference d.

Subtract each subsequent term from its preceding term;7 - 2 = 513 - 7 = 620 - 13 = 7

Therefore, the common difference d is 6.

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At least 15/16 or 15 out of 16 numbers in the data set must lie within 4 standard deviations from the mean.

Chebyshev's Theorem states that for any set of numbers, the fraction that will lie within k standard deviations of the mean is at least\(1 - 1/k^2\).

In this case, we are interested in finding the fraction of numbers that must lie within 4 standard deviations from the mean. Therefore, k = 4.

Using the formula from Chebyshev's Theorem, we can calculate the fraction:

\(1 - 1/k^2 = 1 - 1/4^2 = 1 - 1/16 = 15/16.\)

Hence, at least 15/16 or 15 out of 16 numbers in the data set must lie within 4 standard deviations from the mean.

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Question

Chebyshev's Theorem states that for any set of numbers, the fraction that will lie within k standard deviations of the mean is at least 1 - 1/k2. Use this theorem to find the fraction of all the numbers of a data set that must lie within 4 standard deviations from the mean. At least of all numbers must lie within 4 standard deviations from the mean. (Type an integer or a fraction.)

The distributive property of multiplications states allows you to multiply each term on the parentheses term by the constant outside the parentheses, for example:

To solve

You have to multiply each term on the parentheses by 4, that is, multiply 2x by 4 and 3 by 4

And you get that the equivalent expression is 8x+12

To solve

You have to multiply the three terms inside the parentheses by 6, so that

The equivalent expression is 6x+6y+6z

The model of the total cost of the family plan in dollars for p devices is given by, C(p) = 100 + 35 p, where C(p) is the total cost.

Family plan offers $ 100 fixed monthly fee and unlimited talk and text on up to 5 lines and data charges of $ 35 for each device for up to 2 gb of data per device.

Mobile share plan offers $140 monthly fee for up to 10 devices, unlimited talk and text for all the lines, and data charges of $15 for each device up to a shared total of 10 gb of data.

Here number of devices which need data plans as part of their cost is ' p '.

So the model which depicts the total cost of family plan is given by,

C(p) = 100 + 35 p, where C(p) is the total cost.

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Answer:

hour and a half

Step-by-step explanation: