Cooking, water boiling, and heat from fire are examples of heat transfer.
Heat transfer refers to the movement of thermal energy or heat from one body or substance to another through conduction, radiation, or convection. Cooking, boiling water, and heat from fire are examples of heat transfer. The process of cooking involves the transfer of heat from a heat source (gas stove, electric stove, fire) to food through conduction.
As the heat is transferred from the source to the pot, it heats the water and food in the pot causing them to cook. Water boiling is also a result of heat transfer. When heat is applied to a pot of water, it heats up the water molecules, causing them to move more quickly. As the temperature of the water reaches its boiling point, the water molecules start to change into steam, and the water starts to boil.
Heat from fire is also an example of heat transfer. When wood or other fuels are burned, they produce heat. The heat energy produced from the burning fuel is then transferred to the surrounding air, causing the temperature to increase and allowing us to stay warm.
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How many electrons are present in the nonbonding π molecular orbital of the allyl anion? a.2 b.1 c.3 d.0
There are 2 electrons present in nonbonding π molecular orbital of the allyl anion.
Frequently mentioned as reaction intermediates include allylic radicals, anions, and cations. Each one has three adjacent sp2-hybridized carbon centers, and they all rely on resonance for stability. Two resonance structures could be used to present each species, with the charged and unpaired electron scattered across both the 1,3 and 0 positions.
A total of two pi electrons are present in the allyl cation; in the resonance, there are two electrons in the pi bond and none on the allyl carbon. Keep in mind that the allyl cation's lowest-energy molecular orbital, 1, is its "highest occupied" molecular orbital.
Therefore, there are 2 electrons present in nonbonding π molecular orbital of the allyl anion.
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How does it? Please help
Sugar could be classified as which of the following?Question 5 options:compoundsolution (homogenous)elementmechanical mixture (heterogenous)
Compound, according to our last session.
Which molecule is polar?
A. CO2
B. PF3
C. CH4
D. BF3
How do you correctly put the number 0.00000000008759 in scientific notation with 3 sig figs?
• 8.76 x 10-11
O 87.6 x 10-11
O 8.759 x 10-11
O 8.759 x 1011
Answer:
8.759×10-11
Explanation:
it may be to sure try to convert the answer
2 moles of NO, was placed in an empty I dm' bottle and allowed to reach equilibrium according to the equation:
At equilibrium, 1.2 moles of N,O, dissociated. Calculate the value of the equilibrium constant for the reaction at that
temperature.
If 3.5 kJ of energy are added to a 28.2 g sample of iron at 20 degrees C, what is the final temperature of the iron in kelvins?
295.8k
that is the procedure above
Which statement describes the periodic table?
Answer:
The periodic table is a tabular array of the chemical elements organized by atomic number, from the element with the lowest atomic number, hydrogen, to the element with the highest atomic number, oganesson. The atomic number of an element is the number of protons in the nucleus of an atom of that element.
Which state of matter has a definite volume but an indefinite shape?
a) Liquid
b) Gas
c) Solid
Answer:
Liquid
Explanation:
If you put 1 liter of water in a vessel of any shape, water changes its shape according to the shape of the vessel but still remains 1 liter. So, any liquid has fixed volume but doesn't have fixed shape.
a mixture of methane and hydrogen gases at a total pressure of 889 mm hg contains methane at a partial pressure of 332 mm hg. if the gas mixture contains 2.48 grams of methane, how many grams of hydrogen are present?
Methane is present in a mixture of hydrogen and other gases with a partial pressure of 332 mm hg, or 889 mm hg overall. 3.287 grams of hydrogen are present in a gas mixture containing 2.48 grams of methane.
Given,
total pressure (P\(_{t}\))=889 mm hg
partial pressure (P\(_{me}\))=332 mm hg
mass of methane,(m\(_{me}\))=2.48g
P\(_{t}\)=P\(_{me}\)+P\(_{H}\)
P\(_{H}\)=P\(_{t}\)-P\(_{me}\)=889-332=507mm hg
partial pressure P\(_{H}\)=507 mmHg
now, X\(_{H}\)(mole fraction of hydrogen)=P\(_{H}\)/P\(_{t}\)=507/889=0.5703
now, the mass of methane/total mass=X\(_{\triangleq}\)=1- X\(_{H}\)
2.48/(2.48+m\(_{H}\))=1-0.5703
m\(_{H}\)=3.287g
In order to measure an object's surface tension, a force must be applied perpendicularly to the object's surface over a given area. Alternatively spelled gauge pressure, gauge pressure is the pressure in relation to atmospheric pressure.
Pressure is expressed using a number of different units. The SI unit of pressure, the pascal (Pa), for instance, is equal to one newton per square meter (N/m2); similarly, the traditional unit of pressure in the imperial and U.S. customary systems is the pound-force per square inch (psi). Some of these measurements are the result of dividing a unit of force by a unit of area. The atmosphere, or atm, is equal to this pressure, which can alternatively be stated as the pressure in terms of its standard value.
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If you are given a bottle 4% Xylocaine and a vial 1:1000 epi, and you desire to have a final 20cc solution of 1% lidocaine with epi 1:150,000, how much (cc) of each drug, plus dilutent, must go into the final solution?
To prepare a final solution of 20 cc with 1% lidocaine and epi 1:150,000, you would need to combine 0.13 cc of 4% Xylocaine, 5 cc of 1:1000 epi, and 14.67 cc of diluent (such as saline) in the final solution.
To calculate the required amounts of each component, we need to consider the desired concentrations and the available concentrations of the drugs.
Desired concentration of lidocaine = 1%
Desired concentration of epi = 1:150,000
Volume of the final solution = 20 cc
the desired amount of lidocaine in the final solution is:
(1/100) * 20 cc = 0.2 cc
Next, let's calculate the amount of epi needed:
1:150,000 epi means there is 1 part of epi in 150,000 parts of the solution. So the desired amount of epi is:
(1/150,000) * 20 cc = 0.0001333 cc (approximated to 0.13 cc)
Since the available concentration of epi is given as 1:1000, which means there is 1 part of epi in 1000 parts of the solution, we can directly take 0.13 cc from the vial
To determine the amount of 4% Xylocaine needed, we can use the equation:
(amount of drug) / (final volume) = (desired concentration) / (available concentration)
(amount of Xylocaine) / 20 cc = 1% / 4%
(amount of Xylocaine) = (20 cc) * (1% / 4%) = 5 cc
Finally, the remaining volume of the final solution should be made up of a diluent, such as saline, to reach the total volume of 20 cc:
(amount of diluent) = (20 cc) - (0.2 cc + 0.13 cc + 5 cc) = 14.67 cc
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CHEMISTRY QUESTION, PLEASE HELP!!!
Reaction B (attached); The change in enthalpy for the forward reaction is -91kJ/mol. (Energy is a product, flowing from the chemical reaction to the surroundings. )
The forward reaction for Reaction B (attached) is.
- endothermic
- exothermic
If Reaction B (attached) was ta equilibrium and then was heated ______ CH3OH would be present after the reaction adjusts to the new temperature.
- more
- less
- the same amount of
If Reaction B (attached) was at equilibrium and then the pressure in its container was increased, ____ CH3OH would be present after the reaction adjusts to the new pressure.
- more
- less
- the same amount of
If Reaction B (attached) was at equilibrium and then H2 was added, _____ CH3OH would be present after the reaction adjusts.
- more
- less
- the same amount of
If Reaction B (attached) was at equilibrium and then H2 was added, ____ CO would be present after the reaction adjusts.
- more
- less
- the same amount
The forward reaction for Reaction B is endothermic, as indicated by the negative change in enthalpy (-91 kJ/mol) for the forward reaction.
If Reaction B was at equilibrium and then was heated, the amount of CH₃OH would be less after the reaction adjusts to the new temperature. This is because the forward reaction is endothermic, meaning that an increase in temperature would shift the equilibrium towards the reactants side to counteract the increase in temperature.
If the pressure in the container of Reaction B was increased, the amount of CH₃OH would be more after the reaction adjusts to the new pressure. This is because the forward reaction produces fewer moles of gas than the reverse reaction, so increasing the pressure would shift the equilibrium towards the side with fewer moles of gas (the products side) to counteract the increase in pressure.
If H₂ was added to Reaction B at equilibrium, the amount of CH₃OH would be more after the reaction adjusts. This is because H₂ is a reactant in the reverse reaction, so adding more H₂ would shift the equilibrium towards the products side to counteract the increase in H₂.
If H₂ was added to Reaction B at equilibrium, the amount of CO would be less after the reaction adjusts. This is because CO is a product in the forward reaction, so adding more H₂ would shift the equilibrium towards the products side to counteract the increase in H₂, resulting in a decrease in CO.
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SO3 + H2O --> H2SO4, how many grams of sulfuric acid can be produced from 200 g of sulfur trioxide and 100 g of water
544.5 g of sulfuric acid can be produced from 200 g of SO₃ and 100 g of H₂O.
The balanced equation for the reaction between sulfur trioxide (SO₃) and water (H₂O) to produce sulfuric acid (H₂SO₄) is:
SO₃ + H₂O → H₂SO₄
To determine how many grams of sulfuric acid can be produced from 200 g of SO₃ and 100 g of H₂O, we need to use stoichiometry.
First, we need to find the limiting reactant, which is the reactant that will be completely consumed first, thereby limiting the amount of product that can be formed. We can determine the limiting reactant by calculating the number of moles of each reactant and comparing them based on their stoichiometric coefficients in the balanced equation.
Moles of SO₃ = 200 g / 80.06 g/mol = 2.499 mol
Moles of H₂O = 100 g / 18.02 g/mol = 5.548 mol
Based on the balanced equation, the stoichiometric ratio of SO₃ to H₂O is 1:1. Therefore, H₂O is the limiting reactant since we have more moles of H₂O than SO₃.
The amount of sulfuric acid that can be produced is limited by the amount of H₂O, which is 5.548 moles. According to the balanced equation, each mole of H₂O reacts with one mole of SO₃ to produce one mole of H₂SO₄. Therefore, the number of moles of H₂SO₄ that can be produced is also 5.548 moles.
The molar mass of H₂SO₄ is 98.08 g/mol. Therefore, the mass of H₂SO₄ that can be produced from 5.548 moles of H₂SO₄ is:
Mass of H₂SO₄ = 5.548 mol × 98.08 g/mol
= 544.5 g
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What are the reasons for Small Island States are particularly concerned with reducing carbon dioxide emissions
Answer:
- Because it could lead to rise in sea levels which could cause heavy floods in the Small Island States and thus destroy their economies.
Explanation:
The reason is that too much carbon dioxide emissions trapped in the atmosphere can cause global worming which includes climate change and rise in sea levels.
Now, due to the fact that we know islands are lands surrounded by water, a rise in sea level of by as small as 1 metre could be very dangerous to these small islands in that they could cause them to become flooded and thus cause harm to lives and properties thereby damaging their economies.
Rapid breathing pays back the __________ debt by breaking down lactic acid. creatine glycogen oxygen glucose
Rapid breathing pays back the oxygen debt by breaking down lactic acid. creatine glycogen oxygen glucose.
Even after exercise must be finished, the "oxygen debt" could be paid when laborious breathing and an elevated heart rate were needed to eliminate lactic acid and replenish depleted energy stores.
The oxygen debt would be the quantity of oxygen needed to replenish the body's oxygen stores and remove the lactic acid. It can take anywhere between a few hours for little activity and several days after just a marathon when an individual has been exercising to start repaying an oxygen debt.
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A 2.9 kg model rocket accelerates at 15.3 m/s2 with a force of 44 N. Before launch, the model rocket was not moving. After the solid rocket engine ignited, hot gases were pushed out from the rocket engine nozzle and propelled the rocket toward the sky.
Which of Newton’s laws apply in this example? Check all that apply.
Answer:
newton's firts law
Explanation:
because it states that everybody continue its state in rest unless an external force is appy to change its state from rest to motion.
Answer:
A, B, C
Explanation:
The science of firearm and tool mark identification has evolved over the years. Research and identify five important events that contributed to the evolution of firearm and tool mark identification in forensic science.
Here's the answer:
One of the first times that firearm evidence was permitted in court as evidence was in 1896 in a Kansas State court. A witness, experienced in firearm use, conducted experiments. He testified how human hair is affected when shot at different firing ranges.
In 1907 in Brownsville, Texas, the first article examining fired cartridge casings as evidence was written. Witnesses reported an alleged riot, where soldiers reportedly fired 150-200 shots into a town. In order to evaluate the accusation, the arsenal staff examined the casings found at the alleged scene. They tested the weapons in question. Although no charges came of the investigation, the resulting article was the first recorded instance of this type of examination using fired casings.
In 1915, a man was exonerated based on ballistic evidence. The Governor of New York assigned a special investigator named Charles E. Waite to review the evidence of a man sentenced to death for shooting his employer. Waite examined the bullets and found that they did not come from the accused man’s revolver, a key piece of evidence in his conviction.
In 1921, in Oregon, a sheriff provided expert testimony identifying a fired cartridge case to a specific rifle. The sheriff noted a small flaw on the rifle that matched a mark on the rim of the ejected cartridge case.
In 1925, the Bureau of Forensic Ballistics was established. The bureau was formed to provide firearm identification services to law enforcement agencies throughout the United States. One of the founders of this bureau adapted a comparison microscope still used today.
The evolution of firearm and tool mark identification in forensic science has been shaped by various significant events. Here are five key milestones that have contributed to its development:
St. Valentine's Day Massacre (1929): The high-profile nature of this event, where seven gangsters were murdered, highlighted the need for improved forensic techniques. This led to the establishment of the first scientific crime laboratory in the United States by the Chicago Police Department, which included firearm examination as an important discipline. Landsdowne Committee (1960): The committee, led by Sir Ronald Fisher, conducted an investigation into the principles and reliability of firearm identification. Their report laid the foundation for statistical methods in firearms identification, emphasizing the importance of scientific rigor and standardization.
Introduction of the Comparison Microscope (1963): The comparison microscope revolutionized firearm examination by allowing side-by-side comparisons of bullet striations and tool marks. This breakthrough greatly enhanced the accuracy and efficiency of forensic analysis.The FBI's Firearms and Toolmarks Examiner Training Program (1978): The FBI established a comprehensive training program for firearms examiners, providing standardized protocols and promoting expertise in the field. This program played a vital role in enhancing the quality and consistency of firearm and tool mark identification across the United States.Introduction of Computerized Systems (1990s):
The integration of computerized systems allowed for digitization, storage, and retrieval of firearm and tool mark data. This advancement improved information management, facilitated comparison searches, and increased the speed and accuracy of identification processes.
These events represent significant milestones in the evolution of firearm and tool mark identification, leading to advancements in techniques, standardization, training, and technological integration, ultimately enhancing the reliability and efficiency of forensic science in this field.
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Force, mass, and acceleration have to do with which law of motion?
Newton's 1st Law
Newton's 2nd Law
Newton's 3rd Law
Newton's 4th Law
Newton's law of motion states the relationship between the force acting on the body in motion. The relation between force, mass, and acceleration is given by Newton's second law.
What is Newton's second law?Newton's second law states the relationship between mass, force, and acceleration. It relates the force with the change of the motion of an object with a mass.
Newton's second law is given as,
\(\rm F = ma\)
Where F is force, m is the mass of the object and a is the acceleration.
Newton's first law is about inertia, the third law is about the law of action and reaction, and the fourth law is about the law of gravitation.
Therefore, option B. Newton's second law states the relationship between force, mass, and acceleration.
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15) Give the name for HNO3.A) nitric acidB) nitrous acidC) hydrogen nitrateD) hydrogen nitriteE) hydrogen nitride
The correct name for HNO3 is A) nitric acid.
Nitric acid is a strong acid that is commonly used in the production of fertilizers, dyes, and explosives. It is also used in the etching of metals and in the purification of metals such as gold and silver.
The formula for nitric acid, HNO3, reflects the fact that it contains one hydrogen ion (H+) and one nitrate ion (NO3-). The nitrate ion is a polyatomic ion that consists of one nitrogen atom and three oxygen atoms.
So once again, you are correct that the name for HNO3 is A) nitric acid.
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235U+n 144 Ba + Kr +3,n Which of the following is the atomic mass X of Kr in the fission reaction shown?
a) 86 u
b) 88 u
c) 89 u
d) 92 u
The atomic mass X of Kr in the fission reaction is: C. 89u.
How to determine the atomic mass X?To determine the atomic mass X of Kr in the fission reaction 235U + n -> 144Ba + Kr + 3n, we need to apply the principle of conservation of mass:
Initial mass = Final mass
Initially, we have 235U and one neutron (n), so the total initial mass is 235 + 1 = 236 units. After the fission reaction, we have 144Ba, Kr, and 3 neutrons. The total final mass should also be 236 units.
Now, let's find the atomic mass X of Kr:
Initial mass = 144Ba + Kr + 3n
236 = 144 + X + 3
Since the mass of a neutron (n) is 1 unit, the equation becomes:
236 = 144 + X + 3
Solve for X:
X = 236 - 144 - 3
X = 89
Therefore, the atomic mass X of Kr in the fission reaction is 89 units, making the correct answer (c) 89 u.
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Consider the dissolution of NaBr and NaI. The values provided here will be helpful for answering the following questions.
ΔH∘soln (kJ/mol) ΔS∘soln Jmol•K
NaBr –0.860 57.0
NaI –7.50 74.0
a.Write a balanced equilibrium equation for the dissolution of NaI in water. Include phases.
b. Calculate the change in free energy if 1.18 moles of NaI is dissolved in water at 25.0°C.
c. What is the dissolution of 1.00 mol of NaBr at 298.15 K?
The change in free energy for the dissolution of 1.00 mol of NaBr at 298.15 K is -2.35 kJ.
a. The balanced equilibrium equation for the dissolution of NaI in water is:
NaI(s) ⇌ Na+(aq) + I-(aq)
b. The change in free energy (ΔG) can be calculated using the equation:
ΔG = ΔH - TΔS
where ΔH is the enthalpy change, T is the temperature in Kelvin, and ΔS is the entropy change. Plugging in the values for NaI:
ΔG = (-7.50 kJ/mol) - (298.15 K)(74.0 J/mol•K) / 1000 J/kJ
ΔG = -9.52 kJ/mol
Multiplying by the number of moles dissolved:
ΔG = -9.52 kJ/mol x 1.18 mol = -11.24 kJ
Therefore, the change in free energy when 1.18 moles of NaI is dissolved in water at 25.0°C is -11.24 kJ.
c. The change in free energy for the dissolution of NaBr can be calculated using the same equation:
ΔG = ΔH - TΔS
Plugging in the values for NaBr:
ΔG = (-0.860 kJ/mol) - (298.15 K)(57.0 J/mol•K) / 1000 J/kJ
ΔG = -2.35 kJ/mol
Therefore, the change in free energy for the dissolution of 1.00 mol of NaBr at 298.15 K is -2.35 kJ.
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nếu có 40g dung dịch NaOH 20% phairn dùng hết bao nhiêu gam dung dịch HCl 25% để trung hoà
Answer:
nếu có 40g dung dịch NaOH 20% phairn dùng hết bao nhiêu gam dung dịch HCl 25% để trung hoà
Three safety-related rules concerning the location of machine controls on equipment involving fluid power components.
1. Ensure Clear and Visible Placement: Machine controls should be located in a position that is easily accessible, visible, and within reach of the equipment operator. Clear and intuitive labeling or color-coding can also be used to enhance visibility and assist in identifying the controls quickly.
2. Provide Adequate Guarding: The machine controls should be positioned in a manner that minimizes the risk of accidental activation or unintended operation. This can be achieved by incorporating appropriate guarding or barriers around the controls to prevent inadvertent contact or interference.
3. Consider Ergonomics and Operator Comfort: When determining the location of machine controls, it is essential to consider ergonomic principles and operator comfort. Controls should be positioned in a way that allows operators to maintain a comfortable and natural posture while operating the equipment. This can help reduce the risk of operator fatigue, musculoskeletal disorders, and errors due to discomfort or awkward reach.
These rules aim to promote operator safety, minimize the potential for accidents, and ensure efficient and effective control of equipment involving fluid power components.
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Which phrase describes an Al atom?
1. a negatively charged nucleus, surrOunded by negatively charged electrons
2.a negatively charged nucleus, surrounded by positively charged electrons
3. a positively charged nucleus, surrounded by negatively charged electrons
4. a positively charged nucleus, surrounded by positively charged electrons
1.02 density and the mass is 26.41 what is the volume ?
Answer:
Volume: 25.89ml/cm^3
Explanation:
Density = m/v
1.02g × v= 26.41g/v × v
1.02v = 26.41
1.02v/1.02 = 26.41/1.02
v =
25.89ml/cm^3
What is a stable electron configuration?
The boiling points of different substances are given in the table below.Substance
Boiling point (°C)
Acetic acid
118.1
Benzene
80.2
Chloroform
61.2
Water
100.0
Which substance most likely has the strongest intermolecular forces?
acetic acid
benzene
chloroform
water
Answer:
acetic acid
Explanation:
edg 2020
Acetic acid has the greatest magnitude of intermolecular interaction.
The boiling point of a liquid refers to the temperature at which the pressure of the liquid equals the atmospheric pressure. Usually, the boiling points of substances always depends on the nature of the intermolecular bonding interaction between the molecules of the substance.
The higher the boiling point, the greater the degree of intermolecular interaction between the substances. Since acetic acid has a boiling point of 118.1°C, then acetic acid has the greatest magnitude of intermolecular interaction .
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what is oxidation number of hg in k2(Hgl4)
Answer: +2
Explanation: Thus, Mercury has an oxidation number of +2 in Nessler's Reagent.
NMR spectroscopy, or ________________________ magnetic resonance spectroscopy, is a very important in the determination of organic structures. This technique relies on the interaction of a particular nucleus with a ________________________ field followed by absorption of energy of a specific ________________________, depending on the chemical environment of the nucleus.
NMR spectroscopy or nuclear magnetic resonance spectroscopy is very important in the determination of the organic structures. This technique relies on the interaction of a particular nucleus with a magnetic field followed by the absorption of energy of a specific frequency, depending on the chemical environment of the nucleus.
NMR spectroscopy is the use of NMR phenomena to study the physical, chemical, and biological properties of matter. Chemists use it to determine the identity and structure of molecules. Physicians use magnetic resonance imaging (MRI), a multidimensional NMR imaging technique, for diagnostic purposes.
NMR spectroscopy is an analytical chemistry technique used in quality control to determine the content and purity of organic compounds and the molecular structure of compounds. This technique includes nuclear detection.
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While not used as frequently, mole fraction is another unit of concentration. Mole fraction is the fraction of moles of one substance over the total moles in the sample. mole fraction (chi) equals moles of A over total moles What is the mole fraction of O2 in a sample with 3.50 grams of O2 and 25.6 g N2
Answer:
hi
Explanation: