Convert
12 x 1025 kg/mL to fg/cm3

Answer:

neutron and proton in the nucleus

electron in the electron cloud

Answer:

the answer is B,A, B

Explanation:

The neutron is found at  

B

The electron is found at  

A

The proton is found at  

B

The calculated value is 0.375 mol/0.225 L

The percentage of a solute in the solvent is one way to express the concentration of a solution. The % can then be calculated in one of two ways: (1) using the ratio of the solute's mass to that of the solution, or (2) using the solute's volume to that of the solution.

Determine how many moles of solute are present.

Moles of NaOH are equal to 15.0 g of NaOH being 1 mol, and 40 g of NaOH being 0.375 mol.

Determine how many litres of solution are in the mixture.

Volume = 225 mL/1000 mL = 0.225 L Soln

Subtract the number of litres of solution from the moles of solute.

Molarity: 1.67 mol/L = 0.375 mol/0.225 L

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The changes to the atmosphere that caused temperatures to increase, making the Eocene such a warm time in Earth’s history was the increase in concentrations of greenhouse gases, primarily carbon dioxide (CO2) and methane (CH4).

The Eocene period was a geological epoch that lasted from approximately 56 to 34 million years ago, occurring between the Paleocene and Oligocene epochs.

During this epoch, the Earth experienced a greenhouse climate, with higher global temperatures and high levels of carbon dioxide in the atmosphere.

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Answer:

B.

Explanation:

Density = mass / volume

mass = 100 grams

volume = 8.65 mL

Density = 100 / 8.65 = 11.56 B.

Biotechnology is the use of living organisms or other biological systems in the manufacture of drugs or other products or for environmental management, as in waste recycling: includes the use of bioreactors in manufacturing, microorganisms to degrade oil slicks or organic waste, genetically engineered bacteria to produce human hormones, and monoclonal antibodies to identify antigens.

Biotech offers the possibility of improving human health, the environment, and agriculture while creating more sustainable modes of production.

The rate expression is k [BF₃]²[NH₃], overall order is 3, rate constant k is 1.13 × 10⁻³ mol⁻² dm⁶ s⁻¹.

The rate expression for this reaction can be written as:

Rate = k [BF₃]^m[NH₃]^n

The method of initial rates can be used to calculate the values of m and n. When we compare experiments 1 and 2, notice that halving the concentration of [NH3] reduces the initial rate of reaction. This suggests that the reaction is first order in terms of [NH3], implying that n = 1.

When comparing experiments 1 and 3, notice that increasing the concentration of [BF3] by a factor of 2.5 increases the initial rate of reaction by a factor of 9.39 (i.e., 2.13/0.227). This shows that the reaction is about second order in relation to [BF3], i.e., m 2.

Therefore, the rate expression for the reaction is:

Rate = k [BF₃]²[NH₃]

The overall order of the reaction is m + n = 3.

Using the data from experiment 4, substitute the values and solve for k:

Rate = k [BF₃]²[NH₃]

1.02 × 10-¹ = k (3.00 × 10⁻¹)² (1.00 x 10⁻¹)

k = 1.02 × 10-¹ / (3.00 × 10⁻¹)² (1.00 x 10⁻¹)

k = 1.13 × 10⁻³ mol⁻² dm⁶ s⁻¹

Therefore, the rate constant k is 1.13 × 10⁻³ mol⁻² dm⁶ s⁻¹.

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The answer is c and possibly a I don't know why im here i dont know what this is so bye...

Explanation:

C I hope this is right for your question.

Answer:

B

Explanation:

2.8.1 Na

2.8.2 Mg

and so on and so forth

Option B, where [OH-] is 1.0 x 10-13 mol dm-³3, is the only one that can be considered basic. Therefore, Option B is the correct answer.

To determine whether a solution is basic or acidic at 25 °C, we can compare the concentration of hydroxide ions ([OH-]) with the concentration of hydronium ions ([\(H_3O\)+]). In a neutral solution, the concentrations of [\(H_3O\)+] and [OH-] are equal, resulting in a pH of 7.

Option A states that the concentration of [\(H_3O\)+] is 1.0 x 10-3 mol dm-3. Since [\(H_3O\)+] represents the concentration of hydronium ions, this solution would be acidic because the concentration of [\(H_3O\)+] is higher than [OH-], indicating an excess of hydronium ions.

Option B states that the concentration of [OH-] is 1.0 x 10-13 mol dm-³3. In this case, [OH-] is higher than [\(H_3O\)+], indicating an excess of hydroxide ions. Therefore, this solution would be considered basic.

Option C states that the solution has a pH of 4.00. A pH of 4.00 is below the neutral pH of 7, indicating an excess of hydronium ions and an acidic solution. Therefore, this option does not represent a basic solution.

Option D states that the concentration of [\(H_3O\)+] is 1.0 x 10-13 mol dm-3. Similar to Option A, this concentration of [\(H_3O\)+] indicates an acidic solution, not a basic one.

Option B

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Answer:

D is the correct answer

Explanation:

In order for a solution to be basic at 25 C, the H+ concentration has to be less than the OH- concentration, and given that H+ times OH- is 10^-14, we deduce that H+ must be less than 10^-7 for the solution to be acidic. Thus, A can be eliminated, and so can C. With B, we calculate an H+ concentration of 0.1M, which also fails to be less than 10^-7
Thus, D is the correct answer and we can verify that as H+ is less than 10^-7.



Note: I do not know why my previous answer was deleted for "being incorrect", and i'm not sure how the incorrect answer was "expert verified", but I am as certain that D is the correct answer as i am sure of 3*(4+5-1) being equal to 24.

According to kinetic theory of gases, Because solids have a defined geometry, they do not exhibit random particle motion. As a result, choice C is the right one.

A lot of the fundamental ideas of thermodynamics were discovered with the help of the kinetic theory of gases, a straightforward yet historically significant classic model of the thermal behaviour of gases. According to the model, a gas is made up of several identical submicroscopic components (atoms or molecules) that are all moving rapidly and randomly. They are thought to be significantly smaller when measured than the typical particle spacing.  Random elastic collisions within the particles and with the container's walls occur between the particles. Because solids have a defined geometry, they do not exhibit random particle motion.

Therefore, the correct option is option C.

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ANSWER

The concentration of ethanol in ppm is 23,3333.33ppm

EXPLANATION

Given that

The mass of ethanol dissolved in water is 35 grams

The mass of the water is 115 grams

Follow the steps below to find the concentration of ethanol

Recall, that the ethanol is the solute and the water is the solvent

Solution = solute + solvent

Hence, the mass of the solution is calculated below as

Mass of the solution = 35 + 115

Mass of the solution = 150 grams

The next step is to calculate the concentration of ethanol

Convert the percentage to part per million

Therefore, the concentration of ethanol in ppm is 23,3333.33ppm

The three examples of giant ionic structures used in industrial world today include. NaCl: sodium chloride. NaBr: sodium bromide. NaF: sodium fluoride.

A giant ionic structure is also known as an ionic compound which has a regular repeating arrangement called an ionic lattice.

Typical examples of giant ionic structures include the following:

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This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97. The incorrect representation for a neutral atom is 36Li

To determine the correct representation for a neutral atom, we need to consider the atomic number (Z) and mass number (A) of the element. The atomic number represents the number of protons in the nucleus, while the mass number represents the sum of protons and neutrons.

Let's analyze the given representations:

36Li:

This representation suggests that the element is lithium (Li) with a mass number of 36, which is incorrect. The correct mass number for lithium is approximately 6.94.

613C:

This representation suggests that the element is carbon (C) with a mass number of 13, which is correct. Carbon has different isotopes, and 13C represents one of its stable isotopes.

3063Cu:

This representation suggests that the element is copper (Cu) with a mass number of 63, which is correct. Copper has different isotopes, and 63Cu represents one of its stable isotopes.

1530P:

This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97.

Therefore, the incorrect representation for a neutral atom is 36Li, as it does not match the known properties of lithium.

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Answer:

Example of ionic bonds— Sodium chloride and calcium oxide. Example of covalent bond— Water, carbon

Explanation:

ionic bond, also called electrovalent bond, type of linkage formed from the electrostatic attraction between oppositely charged ions in a chemical compound. Such a bond forms when the valence (outermost) electrons of one atom are transferred permanently to another atom.

A covalent bond consists of the mutual sharing of one or more pairs of electrons between two atoms. These electrons are simultaneously attracted by the two atomic nuclei. A covalent bond forms when the difference between the electronegativities of two atoms is too small for an electron transfer to occur to form ions.

Answer:

You basically want to balance these equations.

(6)CH4 → (1)C6H6 + (9)H2

(2)C2H6 + (7)O2 → (4)CO2 + (6)H2O

NOTE: DO NOT PUT BRACKETS IN YOUR ANSWER, I HAVE PUT HERE FOR THE ANSWERS INSTEAD OF QUESTION MARKS.

The molecular orbitals for each of the required molecules has been shown in the images attached.

An illustration of a molecule's molecular orbitals and the corresponding energy levels is called a molecular orbital (MO) diagram. MO diagrams are used to illustrate how the atomic orbitals in a molecule combine to generate the molecular orbitals.

The diagram shows the internuclear distance between the two atoms on the horizontal axis and the relative energy of the atomic orbitals on the vertical axis.

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The calculated formula masses to 133.5 amu, we find that the substance with a formula mass closest to 133.5 amu is (d) AlCl3. Therefore, the answer is option D.

To identify the substance with a formula mass of 133.5 amu, we need to calculate the formula mass of each given substance and compare it to 133.5 amu.

(a) MgCl2:

The formula mass of MgCl2 can be calculated by adding the atomic masses of magnesium (Mg) and chlorine (Cl).

Mg: atomic mass = 24.31 amu

Cl: atomic mass = 35.45 amu

Formula mass of MgCl2 = (24.31 amu) + 2(35.45 amu) = 95.21 amu

(b) SCl:

The formula mass of SCl can be calculated by adding the atomic masses of sulfur (S) and chlorine (Cl).

S: atomic mass = 32.07 amu

Cl: atomic mass = 35.45 amu

Formula mass of SCl = 32.07 amu + 35.45 amu = 67.52 amu

(c) BCl:

The formula mass of BCl can be calculated by adding the atomic mass of boron (B) and chlorine (Cl).

B: atomic mass = 10.81 amu

Cl: atomic mass = 35.45 amu

Formula mass of BCl = 10.81 amu + 35.45 amu = 46.26 amu

(d) AlCl3:

The formula mass of AlCl3 can be calculated by adding the atomic mass of aluminum (Al) and 3 times the atomic mass of chlorine (Cl).

Al: atomic mass = 26.98 amu

Cl: atomic mass = 35.45 amu

Formula mass of AlCl3 = 26.98 amu + 3(35.45 amu) = 133.78 amu. Option D

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30 g of pure sulfuric acid (H2SO4) is required to make 150 g of 20% solution of H2SO4.

To find the mass of pure sulfuric acid (H2SO4) required to make a 20% and 150g of solution of H2SO4, you first need to understand the concept of concentration.The concentration of a solution is the amount of solute dissolved in a given volume or mass of solvent. It is expressed as a percentage or as the number of moles per liter of solution.20% solution means that 20 grams of solute is present in 100 grams of solution or 20 grams of solute is dissolved in 80 grams of solvent (water in this case).So, for 150 g of solution, the mass of solute (H2SO4) can be calculated as follows:20% solution means 20 g H2SO4 in 100 g solution.So, in 1 g solution, the mass of H2SO4 is:20 g / 100 g = 0.2 g/g solution.So, in 150 g of solution, the mass of H2SO4 is:0.2 g/g solution x 150 g = 30 g.So, 30 g of H2SO4 is required to make 20% and 150g of solution of H2SO4.To find the mass of pure sulfuric acid (H2SO4) required to make the solution, you need to consider the molar mass of H2SO4. The molar mass of H2SO4 is:2(1.01 g/mol) + 32.07 g/mol + 4(16.00 g/mol) = 98.08 g/mol.So, to find the mass of pure sulfuric acid (H2SO4) required to make the solution, you need to use the formula:mass = moles x molar mass.To find the moles of H2SO4, you need to use the formula:moles = concentration x volume / molar mass.For the 20% solution, the concentration is 20 g/100 g solution or 0.2 g/g solution.The volume of the solution is not given, so we cannot calculate the number of moles of H2SO4 required.For the 150 g solution, the mass of H2SO4 required is 30 g.

So, the number of moles of H2SO4 required is:moles = mass / molar mass = 30 g / 98.08 g/mol = 0.305 mol.So, the mass of pure sulfuric acid (H2SO4) required to make the solution is : mass = moles x molar mass = 0.305 mol x 98.08 g/mol = 29.93 g.

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a) Al(s) + SnSO4(aq) → six electrons transferred

b) Mg(s) + Fe(NO3)2(aq) → Two electrons transferred

The activity series is a list of metals and nonmetals in order of their relative reactivity. It is a useful tool for predicting the outcome of single displacement reactions and for understanding the behavior of metals and nonmetals in various chemical reactions.

In the activity series, the most reactive metals are listed at the top, while the least reactive metals are listed at the bottom. This means that the metals at the top of the activity series are more likely to lose electrons and undergo oxidation, while the metals at the bottom are less likely to lose electrons and undergo oxidation. Similarly, nonmetals are listed in order of their relative ability to gain electrons and undergo reduction.

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Answer:

methane and petrol okkkkkkkkkkkkkkkkkkk

Answer:

Monosaccharides

A monosaccharide is the monomer of a carbohydrate. Carbohydrates, such as sugars and starches, store energy. Others, such as cellulose and chitin, are structural in nature.

Answer:

monosaccharide

Explanation:

a monosaccharide is the monomer of carbohydrates.

Answer:

1- Hélium

2-protons

3-Electrons

4-2

Respectively thx

Answer:

Explanation:

NaCl is ionic (cause the first element which is Na is a metal)

NH3 is the answer

The half reaction with a more positive standard reduction potential will proceed spontaneously in a redox reaction

The half reaction with a more positive standard reduction potential will undergo reduction when compared to the half reaction with a more negative standard reduction potential.

Oxidation-reduction reactions, often known as redox reactions, are a set of chemical reactions that involve electron transfer between reactants. In a redox reaction, one reactant is oxidized, losing electrons, while the other reactant is reduced, gaining electrons.

The oxidation half-reaction is the process of losing electrons and increasing the oxidation number, whereas the reduction half-reaction is the process of gaining electrons and decreasing the oxidation number. The total reaction is referred to as the redox reaction.

Half-reaction:Half-reaction refers to the two parts of an oxidation-reduction reaction that happen separately. A half-reaction must always be either an oxidation reaction or a reduction reaction. It also describes the movement of electrons and hydrogen ions in an equation.

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Answer:

the more sun there is, the taller the plant

Explanation:

The concentration of C(g) at equilibrium will increase, while the concentrations of A(g) and B(g) will decrease because they are being consumed to form more C(g). The new equilibrium concentrations will depend on the magnitude of the temperature increase and the value of the new Kc constant.

What is Equilibrium?

In chemistry, equilibrium refers to a state in which the rate of the forward reaction is equal to the rate of the reverse reaction in a chemical reaction. In other words, the concentrations of the reactants and products do not change over time, and the reaction appears to have stopped.

Equilibrium is a dynamic state because the forward and reverse reactions continue to occur at the same rate. At equilibrium, the concentrations of the reactants and products remain constant, but the concentrations of the intermediates involved in the reaction may still change as the reaction proceeds.

An increase in temperature will shift the equilibrium position of the reaction that favors the endothermic direction, i.e., in the direction that absorbs heat. The balanced chemical equation shows that the forward reaction is endothermic because it involves the formation of two moles of C(g) from one mole of A(g) and one mole of B(g).

Since Kc is a constant at a particular temperature, an increase in temperature will cause Kc to increase. This means that the ratio of product concentrations to reactant concentrations at equilibrium (Qc) will be smaller than Kc, and the reaction will shift in the forward direction to reach a new equilibrium.

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0.595 moles of water can be made at 112.6 grams of \(HNO_{3}\) are consumed

To determine the number of moles of water produced when 112.6 grams of \(HNO_{3}\) are consumed, we use the equation's stoichiometry and molar masses.

To determine the number of moles of water produced when 112.6 grams of \(HNO_{3}\) are consumed, we need to use the molar mass of \(HNO_{3}\) and the stoichiometric coefficients of the balanced chemical equation.

The molar mass of \(HNO_{3}\) is calculated as follows:

1 mole of hydrogen (H) = 1 g/mol

1 mole of nitrogen (N) = 14 g/mol

3 moles of oxygen (O) = 3 × 16 g/mol = 48 g/mol

Adding these together, the molar mass of \(HNO_{3}\) is 1 + 14 + 48 = 63 g/mol.

Now, we can set up a conversion factor using the stoichiometry of the balanced equation:

From the equation: 5 + 6 \(HNO_{3}\) -> \(H_{2}SO_{4}\) + 6 \(NO_{2}\) + 2 \(H_{2}O\)

From the coefficients: 6 moles of \(HNO_{3}\) produce 2 moles of \(H_{2}O\)

To find the moles of water produced, we use the following calculation:

112.6 g \(HNO_{3}\) × (1 mol \(H_{2}O\) / 63 g \(HNO_{3}\)) × (2 mol \(H_{2}O\) / 6 mol \(HNO_{3}\)) = 0.595 mol \(H_{2}O\)

Therefore, when 112.6 grams of \(HNO_{3}\) are consumed, approximately 0.595 moles of water can be produced according to the given balanced equation and molar masses.

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Explanation:

the mixture in which mixting component are uniformly distributed and cannot be seen by our naked eyes