At point P, the electric potential is 0. This is due to the fact that the positive and as a result, at point P, their electric potentials are cancelled.
What are the contrasting fees?Positive and negative electrical charges are referred to as opposite forms of charge. A positively charged object will draw a negatively charged object, in accordance with our core concept of charge interaction.
We can apply the following equation to find the electric potential at point P: V = kQ/r1 - kQ/r2.
where:
k = Coulomb's constant (9 x 10⁹ N m²/C²),Q = magnitude of the charge (3.3 μC = 3.3 x 10⁻⁶ C), r1 = distance from the positive charge to point P (a = 0.35 m), r2 = distance from the negative charge to point P (a = 0.35 m)
Using these values, we can calculate the potential at point P as follows:
V = (9 x 10⁹ N m²/C²) * (3.3 x 10⁻⁶ C) / (0.35 m) - (9 x 10⁹ N m²/C²) * (3.3 x 10⁻⁶ C) / (0.35 m)
V = 0.
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In hiking, what fitness component is required of you
You check in at the airport and have your luggage weighed. It comes to 25kg. The airport is at sea level and you take off and climb to 30,000 ft. How much less does your luggage now weigh?
mass of earth = 5.98 × 10 ^24
radius of earth = 6.37 × 10^ 6
Answer:
0.705 kg less
Explanation:
Altitude at sea level = 0 ft
Altitude after climbing = 30,000 ft = 30,000 x 0.3048 = 9,144 m
Weight = W = mg
Change in weight = ΔW = (M-luggage) × (g-sea level - g-altitude)
g at sea level:
g1 = (Gravitational constant × Mass of the Earth) / (Radius of the Earth)²
g at altitude of 30,000 ft:
g2 = (Gravitational constant × Mass of the Earth) / (Radius of the Earth + Altitude)²
Gravitational constant = 6.674 × 10^-11 m^3 kg^-1 s^-2
g1 = (6.674 × 10^-11 × 5.98 × 10^24) / (6.37 × 10^6)^2
g1 ≈ 9.8358 m/s^2
g2 = (6.674 × 10^-11 × 5.98 × 10^24) / (6.37 × 10^6 + 9,144)^2
g2 ≈ 9.8076 m/s^2
ΔW = (M-luggage) × (g1 - g2)
= 25 kg × (9.8358 - 9.8076)
≈ 0.705 kg
Therefore, your luggage would weigh approximately 0.705 kg less when you climb to 30,000 ft compared to its weight at the airport.
Can't guarantee this is right, but I checked the numbers a few times and this is the best I can do!
Makala arrives late to class and misses the first few minutes of the lecture. These are the notes she takes:
-Only applies to very small particles
-subatomic particles
-atoms
-nano-size systems
-Only applies over very short distances
-Causes different behavior than the physics observed in
large objects
What should Makala title her notes?
A: Nanotechnology
B: Quantum Mechanics
C: Microtechnology
D: Newtonian Physics
Answer:
B. Quantum Mechanics
Explanation:
Quantum mechanics is the foundation of all quantum physics including quantum chemistry, quantum field theory, and quantum information science.
Answer:
B. Quantum Mechanics
Explanation:
Edge 2021
An insect lands 0.1m from the centre of a turn table while the record is turning at 55 rev/min at what linear speed will the insect be carried
collision with the near stationary photograph
The linear speed will be the insect be 0.5759 meter/second carried collision with the near stationary photograph.
What is speed?
Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
Given that an insect lands 0.1m from the center of the turn table.
Rotational speed of the turn table = 55 rev/min
= (55×2π/60) rad/second
= 5.759 rad/second.
Hence, the speed of the insect be = Rotational speed × length
= 5.759 rad/second × 0.1 M.
= 0.5759 meter/second.
Therefore, the speed of the insect be 0.5759 meter/second.
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which of the following statements are true? check all that apply. which of the following statements are true?check all that apply. the first law of thermodynamics extends the principle of conservation of momentum to include molecular collisions. the work done by a thermodynamic system depends only on the initial and final states of the system. the amount of heat added or removed from a thermodynamic system depends on the path taken on a pv diagram. the first law of thermodynamics extends the principle of conservation of energy to include heat as well as mechanical energy. the amount of heat added or removed from a thermodynamic system depends only on the initial and final states of the system. the work done by a thermodynamic system is equal to the area under the curve on a pv diagram.
The following statements are true: The first law of thermodynamics extends the principle of conservation of energy to include heat as well as mechanical energy.
The work done by a thermodynamic system is equal to the area under the curve on a pv diagram.
The amount of heat added or removed from a thermodynamic system depends only on the initial and final states of the system.
What is thermodynamics?Thermodynamics is a branch of physics that deals with the relationships between heat, energy, and work. It focuses on the behavior of systems of matter and energy and their interactions with each other. It is widely used in fields such as chemistry, engineering, and materials science to understand and predict the behavior of complex systems.
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the higher the principal quantum number (n), the lower the orbital energy.
A. True
B. False
The statement is false
Does a higher quantum number imply more energy?The stronger the electron’s energy, the higher the primary quantum number. As a result, the electron’s energy level is determined by the primary quantum number. The form of the electron wave is determined by the azimuthal quantum number, l. The electron sublevels are also known as l values.
The energy level of an electron in an atom is represented by the primary quantum number. It is responsible for determining the size and energy of an atomic orbital. The greater the value of the primary quantum number, the larger the size of the atomic orbital and the higher the energy level. When the value of the primary quantum number rises, the difference in energy falls.
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What is the economic term for the act of sacrificing one good or service to purchase or produce another?
Answer:
Trade-off. sacrificing one good or service to purchase or produce another.13. A ball is thrown horizontally by a pitcher at 25.0 m/s from shoulder height (2.0m). If the catcher is 20.0 m away, will the ball reach the catcher before bouncing?
Answer:
The ball will NOT reach the catcher before bouncing
Explanation:
y = (vertical vi)t + (1/2)gt²
2 = 0 + (1/2)(9.8)t²
t = 0.64 s
x = (horizontal vi)t + (1/2)at²
x = (25)(0.64) + 0
x = 16 m
16 m < 20 m
The ball will bounce at 16 m
Olive Udadi accompanies her father to the park for an afternoon of fun. While there, she
hops on the swing and begins a motion characterized by a complete back-and-forth cycle every
2 seconds. The frequency of swing is _________ and the period of swing is __________.
The frequency of swing is inverse of the period of swing.
The simple harmonic motion is defined as the to and fro motion of the object against the fixed point in a cycle. The simple harmonic motion depends upon the frequency and time period of the object.
The frequency definition states that it is the number of complete cycles of waves passing a point in unit time. The time period is the time taken by a complete cycle of the wave to pass a point.
Here, the frequency and the time period of the object is inverse of each other.
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Find the vector whose magnitude is 5 and which is in the direction of the vector 4i -3j +k
The vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.
To solve this problemThe given vector can be normalized before being multiplied by the desired magnitude. This is how to locate the vector:
The vector that has been provided should be normalized by dividing each of its components by its magnitude. The Pythagorean theorem can be used to determine the magnitude of the vector 4i - 3j + k:
Magnitude = √(4² + (-3)² + 1²) = √(16 + 9 + 1) = √26
Normalize the vector by dividing each component by the magnitude:
Normalized vector = (4/√26)i + (-3/√26)j + (1/√26)k
Multiply the normalized vector by the desired magnitude:
To obtain a vector with a magnitude of 5, multiply each component of the normalized vector by 5:
Desired vector = 5 * ((4/√26)i + (-3/√26)j + (1/√26)k)
Simplifying the expression gives:
Desired vector ≈ (20/√26)i + (-15/√26)j + (5/√26)k
So, the vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.
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The speed of a cart is increased uniformly from 0.32 meters per second to 1.43 meters per second in 1.82 seconds. The cart’s acceleration is
Answer:
0.610m/s^2
Explanation:
Acceleration is defined as the ΔV/ΔT. In this case, the change in velocity is 1.43-0.32=1.11 m/s. The change in time is 1.82 seconds. Plugging in what we know, it will result in an acceleration of 0.610 m/s^2.
In a chemistry lab, a teacher challenges their students to find the fastest way to dissolve a cube of sugar in a specific amount of water. Using equipment available in a standard
chemistry lab, describe a procedure and explain why this procedure is effective.
Answer:
One effective procedure for dissolving a cube of sugar in water quickly using equipment available in a standard chemistry lab is:
Boil a specific amount of water in a beaker or flask on a hot plate or Bunsen burner.
Once the water has reached boiling point, remove it from the heat source and add the sugar cube.
Stir the mixture vigorously using a stirring rod or magnetic stirrer until the sugar has completely dissolved.
If necessary, cool the solution by placing the beaker or flask in an ice bath or allowing it to cool naturally to room temperature.
This procedure is effective because the solubility of sugar in water increases with temperature. By heating the water, the energy of the water molecules is increased, which allows them to break apart the sugar molecules more easily. Stirring the mixture further increases the contact between the sugar and the water, which facilitates the dissolution process. The cooling step is necessary to prevent recrystallization of the dissolved sugar as the solution cools down, which would result in a slower dissolution process. Overall, this procedure can dissolve a sugar cube in water quickly and efficiently using equipment readily available in a standard chemistry lab.
Explanation:
You launch a model rocket from ground level. It moves directly upward with a constant acceleration of 71.0 m/s2 for 1.45 seconds, at which point it runs out of fuel. Assuming air resistance on the rocket is negligible, what is the maximum altitude (above the ground) achieved by the rocket?
m
Answer:
74.0 meters
Explanation:
We can use the kinematic equation for displacement with constant acceleration to solve this problem:
Δy = v0t + 1/2at^2
where Δy is the displacement (i.e., the change in height), v0 is the initial velocity (which is 0), a is the constant acceleration, and t is the time taken.
Plugging in the given values, we get:
Δy = 0 + 1/2(71.0 m/s^2)(1.45 s)^2
Δy = 74.0 m
Therefore, the maximum altitude achieved by the rocket is 74.0 meters above the ground.
Predict the velocity vy when y=-3.5 meters. Use the average acceleration you calculated in Activity 1. Use the formula v = Vo2 + 2ay, where v = final velocity, Vo = initial velocity, a = average acceleration, and y = y displacement. (Note that v is the final velocity in the y direction: Vy.)
Answer:
8.1
Explanation:
One particle has mass m and a second particle has mass 2m. The second particle is moving with speed v and the first with speed 2v. How do their kinetic energies compare?
Answer:
Explanation:
The formula for kinetic energy to be used here is 1/2mv².
If the first particle is "particle a" and the second particle is "particle n"; there kinetic energies (K.E) will be
K.Eₐ = 1/2.m2v² = mv²
K.Eₙ = 1/2.2mv² = mv²
From the above, it can be said that there kinetic energies are the same.
NOTE that the m and v used in the question means mass and velocity respectively.
A 12kg object is moving up at a rate of 5m/s when it is 3m above the ground. How high in the air will it be when it stops moving
The air will be when it stops moving 180J.
The generally accepted boundary where space begins, which is also the point where the atmospheric pressure is assumed to be zero, is called the Kalman line. Simply put, gases move from areas of high pressure to areas of low pressure. And the greater the pressure difference, the faster air moves from high pressure to low pressure. This draft is the wind we experience.
As the air rises the surface pressure decreases. As the air rises, it expands and cools adiabatic cooling that is, it cools by changing volume rather than by increasing or decreasing heat. As a result, condensation/sedimentation occurs. Cold air sinks. The boundary between Earth and space is called the Kalman Line, an imaginary line 100 kilometers above Earth. This line is considered the boundary between space and the Earth's atmosphere.
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Which two of the following statements about inertia are true?
1. Inertia is the force that keeps a moving object in motion.
2. Inertia is the force that keeps a stationary object at rest.
3. Inertia is the natural tendency of a stationary object to resist motion.
4. Inertia is the natural tendency of a moving object to resist a change in its velocity.
The statements that apply to inertia are that it is a force that maintains moving objects in motion, a force that keeps stationary objects at rest, a force that causes stationary objects to naturally resist motion, and a force that causes moving objects to naturally resist changes in velocity.
What is Newton's first law?According to Newton's first law, until pushed to alter its condition by the intervention of an external force, every object will continue to be at rest or in uniform motion along a single direction.
As given all the following the statements that are true about inertia are,
1. Inertia is the force that keeps a moving object in motion.
2. Inertia is the force that keeps a stationary object at rest.
3. Inertia is the natural tendency of a stationary object to resist motion.
4. Inertia is the natural tendency of a moving object to resist a change in its velocity.
Thus, all the given options are correct about inertia.
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During another immunity challenge, a box (m = 26 kg) is positioned on an inclined surface (angle = 33°). A rope is attached to the box and the rope is placed through a pulley and another box(m = 32 kg) filled with puzzle pieces and is suspended from the other end of the rope (see figure below). Several tribemates are positioned on the inclined surface holding onto the first box andwaiting for the rest of their tribe to position themselves below the box with the puzzle pieces in order to catch it and complete the rest of the challenge. When the tribemates on the inclinedsurface release the first box from rest, how long does it take the other tribemates to catch the box of puzzle pieces if the box falls from a height of 4.2 m one the system is released and thecoefficient of kinetic friction between the first box and the inclined surface is 0.25? What is the tension in the rope connecting the two boxes?
Here's a diagram of the situation with all the forces acting on the boxes.
To calculate the tension in the rope, we need to calculate the sum of forces pulling on the rope.
Let's call Fg1 the force of gravity of the first box (on the incline) and Fg2 the force of gravity on the second.
Remember that F = mg, where m is mass and g is gravitational acceleration (9.81 m/s^2)
Fg2 = 32*9.81 = 313.92 N
Fg1 = 26*9.81 = 255.06 N
Since the first box is on an incline, the gravitational force can be broken up into two components: the component parallel (tangent) to the incline, and the other perpendicular (normal) to the incline. Let's call those forces FT and FN respectively.
Let's rearrange the force arrows to form a right triangle:
Since we know Fg1 and an angle measure in this triangle, we can calculate FN and FT using trigonometry.
FN = Fg1*cos(33) = 255.06*cos(33) = 213.911 N
FT = Fg1*sin(33) = 255.06*sin(33) = 138.916 N
Now that we have FN, we can calculate the force of friction, let's call that Ff.
Ff = μ*FN, where μ is the coefficient of friction.
Ff = 0.25*213.911 = 53.478 N
In relation to the whole pulley system, the boxes pull each other toward their respective directions. For example, the first box pulls the second box to the left of the pulley, and the second box pulls the first to the right. Imagine the boxes on opposite sides of a tug-of-war. The box that pulls with the most force will win the tug-of-war and pull the entire pulley system in its direction.
The second box is tugging with a force of Fg2, its gravitational force.
The first box is tugging with FT+Ff, its tangent gravitational force and the force of friction.
The total tension in the rope is the sum of all of these tugging forces.
Total tension = Fg2 + FT + Ff = 313.92+138.916+53.478
Total tension = 506.314 N (answer to second part)
Now, the second box tugs with a force of 313.92 N, and the first box tugs with a force of 138.916+53.478 = 192.394 N, and since the tugging force of the second box is greater, the whole pulley system will move in that direction. The resultant force is the tugging force of the second box minus that of the first box. Let's call this FR.
FR = 313.92 - 192.394 = 121.526 N
The pulley now pulls the mass of both of these boxes combined with this force. Let's call this m.
m = 26kg + 32kg = 58 kg
Remember again that F = m*a. Let's substitute FR for F, then calculate a.
121.526 = 58a; a = 2.0953 m/s^2
So the pulley system accelerates at this rate, so therefore the second box falls at this rate as well.
We also have that it falls a distance d = 4.2m before it's caught, and the pulley system starts at rest (up until the second box is released), so the initial velocity vi = 0.
We need to calculate the time it takes for the box to fall this far, t.
Given the variables we know and need, we can use the following equation:
d = vi*t + (a/2)*t^2
We can substitute for d, vi, and a, then solve for t.
4.2 = 0 + (2.0953/2)*t^2
Solving for t,
t = 2.0022 s (answer to first part)
An ideal gas initially is allowed to expand isothermally until its volume of 1.6 L and pressure is 5 kPa, undergoes isothermal expansion until its volume is 8 L and its pressure is 1 kPa.
1. Calculate the work done by the gas. Answer in units of kJ.
2. Find the heat added to the gas during this process. Answer in units of kJ.
(a) The work done by the gas during the isothermal expansion is -25.6 J.
(b) The heat added to the gas during this process is 25.6 J.
Net work done by the ideal gas against the external pressureThe net work done by the ideal gas in the isothermal expansion is calculated as follows;
W(net) = ΔP x ΔV
W(net) = ( 1 kPa - 5 kPa) x (8L - 1.6 L)
W(net) = -25.6 kPa.L
W(net) = -25.6 J
Head added to the gasThe heat added to the gas is calculated as follows;
W = -Q
-25.6 J = -Q
Q = 25.6 J
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Which correctly describes latent heat?
A. The heat of molecules that are under pressure
B. The heat held inside of ice crystals colder than -2°C
C. The heat absorbed or lost by a substance while it's changing state
D. The heat used to change the temperature of a liquid
Option C. The heat absorbed or lost by a substance while it's changing state correctly describes latent heat
Latent heat is the heat absorbed or lost by a substance while it is changing state.
The latent heat is a type of heat that is transferred during phase change, i.e., while a substance undergoes a change of state.
For example, when ice melts into liquid water, or when liquid water evaporates into water vapor, heat is absorbed from the surroundings.
Latent heat is not associated with a temperature change; rather, it's associated with a change of state.
For instance, the temperature of water remains at 100°C while boiling.
When water is boiling, the latent heat of vaporization is absorbed and utilized to break the hydrogen bonds holding water molecules together to change water from the liquid phase to the gaseous phase.
When the water is boiling, adding more heat won't increase the water's temperature, instead, the extra heat will be absorbed to change the phase of water molecules.
Therefore, the correct answer to the given question is option C: The heat absorbed or lost by a substance while it is changing state.
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3. Which vehicle has more momentum? *
1 point
A.
B
VA= 25 m/s
Ug = 20 m/s
ma= 15000 Kg me = 15000 Kg
Ο Α
О.
B
Answer:
the one with v = 25 m/s
Explanation:
Momentum = m * v
if they both have the same mass (15000 kg) , then the one with the higher v has more momentum...I think A= 25 m/s
A 43 kg object is hanging from a rope. If it has the potential to do 3160 J of work, how high is it above the ground?
?
d. Write the importance of International Bureau of
Weights and measures in the country?
As
Answer:
The effectiveness of that same country's worldwide weights, as well as Measures Bureau, has always been chosen to give elsewhere here.
Explanation:
The International association formed to unify imperial measurements in order to set and maintain basic universal requirements as well as prototypes. Check the minimum standard.It becomes an interagency body set up by that of the Metre Convention, wherein the member countries work on such measuring science including quality control concerns.A student is conducting an experiment that involves adding hydrochloric acid to various minerals to detect if they have carbonates in them. The student holds a mineral up and adds hydrochloric acid to it. The acid runs down the side and onto the student’s hand causing irritation and a minor burn. If they had done a risk assessment first, how would this situation be different? A. It would be the same, there is no way to predict the random chance of acid dripping off the mineral in a risk assessment. B. The student would have no injuries because he would know hydrochloric acid is dangerous and would be wearing gloves when using it. C. The student would be safer because he would have been wearing goggles, but his hand still would not have been protected. D. The student would not have picked up the mineral because he would know that some of the minerals have dangerous chemicals in them.
By the experiment "The student would have no injuries because he would know hydrochloric acid is dangerous and would be wearing gloves when using it. "
What is experiment ?An experiment would be a technique used to confirm or deny a hypothesis, as well as assess the likelihood or effectiveness of something that has never been tried before.
What is hydrochloric acid?Hydrochloric acid is a kind of compound in which hydrogen and chlorine element is present.
Maintain a safe distance between your hands and your body, mouth, eyes, as well as a face when utilizing lab supplies and chemicals.
By the experiment "By the experiment "The student would have no injuries because he would know hydrochloric acid is dangerous and would be wearing gloves when using it. "
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A car travelled a distance of 200 m with initial velocity of 216 km/hr. Calculate the acceleration
in meters per second of the car if it has a final velocity of 360 km/hr.
Answer:
\(a = 16\ m/s^2\)
Explanation:
When the velocity changes uniformly, the object has a constant acceleration. The acceleration, the velocities, and the distance are related by the equation:
\(v_f^2=v_o^2+2ax\)
Where:
vf = final velocity
vo = initial velocity
a = acceleration
x = distance
Solving for a:
\(\displaystyle a=\frac{v_f^2-v_o^2}{2x}\)
The car travels a distance of x=200 m and the velocities are:
vo = 216 Km/h
vf = 360 Km/h
Both velocities must be converted to meters by seconds.
vo = 216 Km/h *1000/3600 = 60 m/s
vf = 360 Km/h *1000/3600 = 100 m/s
The acceleration is:
\(\displaystyle a=\frac{100^2-60^2}{2*200}\)
\(\displaystyle a=\frac{10000-3600}{400}\)
\(\displaystyle a=\frac{6400}{400}\)
\(\mathbf{a = 16\ m/s^2}\)
1)Draw a celestial sphere and label the horizon, the cardinal points, the celestial and anti meridians, the zenith and the nadir.
A celestial sphere is a tool that allows us to study in detail the characteristics of the planet and its reference points.
What is a celestial sphere?The celestial sphere is an astronomical tool that allows individuals to study the planet Earth and other planets. This tool is an ideal sphere that is used as a model of the Earth. Additionally, it represents the locations of celestial objects, meridians, parallels, geographical locations, among others.
What are meridians and parallels?The meridians and parallels are imaginary lines that are located on the earth to be located geographically on the surface. These also distribute the terrestrial locations in four quadrants (cardinal points).
NorthwestNortheastSouthwestSoutheastWhat is the Zenith and Nadir?The zenith is a term that refers to the highest point in the sky relative to the observer and it is just above the observer's head (90°).
The nadir is a term that refers to the intersection between the observer's vertical and the celestial sphere. That is to say: if you imagine a line that passes through the center of the Earth and through our location on its surface, the nadir is on that line, below our feet.
Below is an image in which the zenith, nadir, cardinal points, meridians and parallels are referenced.
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Why did the chicken cross the road
Answer:
to get to the other side.
Explanation:
bada bam, bop, BOOM
A car traveling at 14 m/s accelerates at 3.5 m/s² for 5 seconds. How much distance does it travel during that time?
Answer: 113.75
Explanation:
You know
acceleration = a = 3.5 m/s²
time = t = 5 seconds
initial velocity = u = 14 m/s
Unknown is distance = s = ?
Use equation: s = ut + \(\frac{1}{2}\) at²
Substitute all the known values inside the equation:
s = (14*5) + 0.5 * 3.5 * 5²
s = 70 + 43.75 = 113.75 m
The car travels 113.75 metres.
Suppose a radio signal (light) travels from Earth and through space at a speed of 3 × 108/ (this is the speed of light in vacuum). How far (in meters) into space did the signal travel during the first 10 minutes?
Answer:
18*10^10 meters
Explanation:
V= d/t 10 mins = 600 seconds
3*10^8 = d/600s
(3*10^8)*(6*10^2) = d
d = 18*10^10 m
Hi
Please help on question asap if the answer is correct I'll rate you five stars a thanks and maybe even brainliest!
When two light bulbs are connected in series, the resistance in the circuit is increase compared to that with one lightbulb. The increased resistance opposes the flow of current so far fewer electrons pass per second , transferring less energy. The lightbulbs are therefore not as bright as In a circuit with same voltage but only one bulb.
However, when Two lightbulbs are connected in parallel, each loop behaves like a separate circuit . The resistance in each branch is the same as if there were just one light bulb in the whole circuit.there is the same current in each branch of the circuit ,so the bulbs Will light up with the same brightness as a single bulb circuit. The energy stored in the battery will decrease twice as quickly and battery will run out faster than I series circuit.
6) explain the advantages and disadvantages of arranging components in series or parallel.