HELP are all three of these are either
One Unique Triangles
Multiple Triangles
No triangles

A business that manufactured small alarm clocks has weekly fixed cost $4000. The average cost for the business to manufacture x clocks is described by 0.7x + divide 4000 x

To find the average cost for a business to manufacture x clocks is given by0.7x + 4000/x

The cost for a business that manufactured small alarm clocks has a fixed weekly cost of $4000. We are supposed to find the average cost for the business to manufacture x clocks.  The average cost is described by 0.7x + 4000/x.

Cost function is given as:

C(x) = 0.7x + 4000/x

Where C(x) is the cost function of the business in dollars.

Now we have to find the average cost of producing x units of the product.

So, the average cost function AC(x) is given as:

AC(x) = C(x)/x

So, we get

AC(x) = (0.7x + 4000/x)/x

AC(x) = 0.7 + 4000/x²

Therefore, the average cost function of the business is AC(x) = 0.7 + 4000/x².

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Answer:

9.2

Step-by-step explanation:

divide percentages by 100 if you're converting it to a decimal

;)

Answer:

9.2

920%

900-20

9.00

+

0.20

_____

9.20 or 9.2

Answer: x=64

Step-by-step explanation: do 4992/78 which equals 64

Answer: x=64

Step-by-step explanation: isolate the it

\([Hello,BrainlyUser]\)

Answer:

[5] \(2x^2+xy+-3y^2\)

[6] \(2x^3+-7x^2+-3x\)

[7] \(4a+2b\)

[8] \(6x+2y-5\)

[9] \(x^2-3xy-10y+75\)

Step-by-step explanation:

Let's start with [5]

\(3x^2-2xy-2x^2-(x^2-3xy+y^2)\)

Distribute the Negative Sign:

\(=3x^2-2xy-2y^2-1(x^2-3xy+y^2)\)

\(=3x^2+-2xy+-2y^2+-1x^2+-1(-3xy)+-1y^2\)

\(=3x^2+-2xy+-2y^2+-x^2+3xy+-y^2\)

Combine like term

\(=3x^2+-2xy+-2y^2+-x^2+3xy+-y^2\)

\(=(3x^2+-1x^2)+(-2xy+3xy)+(-2y^2+-y^2)\)

\(=2x^2+xy+-3y^2\)

Answer = \(2x^2+xy+-3y^2\)

-------------------------------------------------------------------------------------------------------------

[6] \(\left(2x^3-5x^2-3x\right)-2x^2\)

Combine like terms

\(\left(2x^3-5x^2-3x\right)-2x^2\)

\(=(2x^2)+(-5x^2+-2x^2)+(-3x)\)

\(=2x^3+-7x^2+-3x\)

Answer = \(2x^3+-7x^2+-3x\)

-------------------------------------------------------------------------------------------------------------     [7]  \(4a-(3a-2b)+3a\)

\(=4a+-3a+2b+3a\)

Combine like terms:

\(=(4a+-3a+3a)+(2b)\)

\(=4a+2b\)

Answer = \(4a+2b\)

-------------------------------------------------------------------------------------------------------------

[8]  \(\left[3x-\left[x-4x+2y\right)+4y\right]-5\)

\(3x-(-3x-2y+4y)-5\)

\(=3x-(-3x+2y)-5\)

\(=3x+3x-2y-5\)

\(=6x-2y-5\)

Answer = \(6x-2y-5\)

-------------------------------------------------------------------------------------------------------------

[9] \(x^2-3xy+5\left\{2+\left[y-3\left(y-6\right)-5\right]\right\}\)

Combine likes terms

\(x^2-3xy-10y+75\)

Answer = \(x^2-3xy-10y+75\)

[CloudBreeze]

Answer:

1:3

Step-by-step explanation:

Hope this helps!

In the given boundary-value problem, we are asked to set up the set of equations required to solve the problem using the finite difference method. The equation is y" = 2x²y + xy + 2, and we are given the boundary conditions y(1) = -1 and y(4) = 4.

To solve the problem using the finite difference method, we can approximate the second derivative y" using the central difference formula: y" ≈ (yₙ₊₁ - 2yₙ + yₙ₋₁) / h². Substituting this approximation into the original differential equation, we obtain the finite difference equation: (yₙ₊₁ - 2yₙ + yₙ₋₁) / h² = 2xₙ²yₙ + xₙyₙ + 2.

For the given boundary conditions, y(1) = -1 and y(4) = 4, we can use these values to form additional equations. At x₀ = 1, we have the equation y₀ = -1. At xₙ = 4, we have the equation yₙ = 4.

In summary, the set of equations required to solve the boundary-value problem by the finite difference method, with the given boundary conditions, would be:

(y₂ - 2y₁ + y₀) / h² = 2x₁²y₁ + x₁y₁ + 2,

(y₃ - 2y₂ + y₁) / h² = 2x₂²y₂ + x₂y₂ + 2,

...

(yₙ₊₁ - 2yₙ + yₙ₋₁) / h² = 2xₙ²yₙ + xₙyₙ + 2,

y₀ = -1,

yₙ = 4.

These equations form a system of equations that can be solved numerically to obtain the solution to the boundary-value problem.

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The expression that is equivalent to (4mn/m^-2n^6)^-2 is \(\frac{n^{10}}{16m^{6}}\)

The expression is given as:

(4mn/m^-2n^6)^-2

Apply the law of indices

\((4m^{1 + 2}n^{1-6})^{-2\)

Evaluate the sum and the differences

\((4m^{3}n^{-5})^{-2\)

Apply the negative exponent

\(\frac{1}{16m^{2*3}}}n^{5*2}\)

Evaluate

\(\frac{1}{16m^{6}}n^{10}\)

Rewrite as:

\(\frac{n^{10}}{16m^{6}}\)

Hence, the expression that is equivalent to (4mn/m^-2n^6)^-2 is \(\frac{n^{10}}{16m^{6}}\)

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Answer:

-157

Step-by-step explanation:

25+(-13×14)=-157

On using the implicit differentiation the equation of the tangent line the the curve "x² + 2xy - y² + x = 39" at the point (5,9) is 29x - 8y = 73  .

The equation of the curve is  x² + 2xy - y² + x = 39 ;

to find the equation of the tangent , we differentiate the curve with respect to "x" ,

On differentiation ,

We get ,

⇒ d/dx (x² + 2xy - y² + x) = 0 ,

⇒ 2x + 2y + 2x(dy/dx) - 2y(dy/dx) + 1 = 0 ,

⇒ dy/dx = (1 + 2x + 2y)/(2y - 2x) ....equation(1)

We know that the equation of tangent at the point (x₀,y₀) is given as : ⇒ y = y₀ + y'(x₀)(x - x₀) ...equation(2)

where x₀ = 5 and y₀= 9

So from equation(1) , y'(x₀) = (1 + 10 + 18)/(18 - 10) = 29/8 ,

Then equation(2) becomes , y = 9 + 29/8(x - 5) ,

⇒ y = (29/8)x - (73/8) ,

⇒ 29x - 8y = 73 .

Therefore , the equation of the tangent line is 29x - 8y = 73 .

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The given question is incomplete , the complete question is

How do you use implicit differentiation to find an equation of the tangent line to the curve x² + 2xy - y² + x = 39 at the given point (5,9)?

Statistical guidance should perform well in situations such as clinical trials and market research where rigorous data analysis and inference are necessary. Statistical methods provide a systematic approach to control biases, handle variability, and draw reliable conclusions, ensuring accurate decision-making and predictions based on the data.

Statistical methods are crucial in determining sample sizes, designing the study, and analyzing the data to draw valid conclusions about the effectiveness and safety of the treatment.

In this situation, statistical guidance should do well because it provides a systematic framework to control for biases, random variability, and confounding factors, ensuring robust and reliable results that can be generalized to a larger population.

One example where statistical guidance should perform well is in clinical trials for new drugs or treatments.

Another example is in market research and opinion polling. Statistical techniques can be used to collect and analyze data from a representative sample of the target population, allowing for accurate estimation and prediction of consumer preferences, market trends, or election outcomes.

Statistical guidance should do well in this situation because it provides methods for random sampling, hypothesis testing, and confidence interval estimation, which help minimize sampling errors and increase the reliability of the findings.

Additionally, statistical models can capture complex relationships and make accurate predictions based on the observed data.

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For random samples of size 7 from a Normally distributed population, the "expected value" or "mean" of the sample means from all possible samples is equal to the population mean.

The concept we are referring to here is the Central Limit Theorem (CLT). According to the CLT, if we take random samples of size "n" from any population, regardless of its distribution, the distribution of the sample means will approach a Normal distribution as the sample size increases.

When the population itself follows a Normal distribution, the distribution of the sample means will also be Normal for any sample size. However, even if the population is not normally distributed, the distribution of the sample means will still tend to be Normal as the sample size increases.

The key property of the CLT is that the mean of the sample means, also known as the expected value or the average of the sample means, is equal to the population mean. This means that if we were to take all possible random samples of size 7 from the population, calculate the mean for each sample, and then calculate the average of all those means, it would be equal to the population mean.

Mathematically, if we denote the population mean as μ (mu) and the mean of the sample means as μ\(\bar X\) (mu-x-bar), then:

μ\(\bar X\) = μ

In simpler terms, this means that on average, the sample means will be equal to the population mean. However, individual sample means may vary around the population mean due to sampling variability.

So, in conclusion, for random samples of size 7 from a Normally distributed population, the expected value or mean of the sample means from all possible samples is equal to the population mean. This is a fundamental property of the Central Limit Theorem.

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No, the variances are not similar enough to use the pooled t test. The ratio of the two variances (25/8) is greater than 3, which is the typical cutoff for determining similarity of variances. Therefore, an alternative method such as the Welch's t-test or a non-parametric test should be used to compare the means.

To determine if the variances are similar enough to use a pooled t-test, you can perform an F-test for equality of variances. Follow these steps:

1. Calculate the F statistic by dividing the larger variance by the smaller variance: F = var2 / var1 = 25 / 8 = 3.125.

2. Determine the degrees of freedom for each group: df1 = 10 - 1 = 9 and df2 = 10 - 1 = 9.

3. Check the F critical value for the given degrees of freedom and chosen significance level (e.g., 0.05) using an F-distribution table or a calculator. For df1 = 9 and df2 = 9 at a 0.05 significance level, the F critical value is approximately 3.18.

4. Compare the calculated F statistic to the F critical value: 3.125 < 3.18.

Since the F statistic is less than the F critical value, we fail to reject the null hypothesis that the variances are equal. Therefore, the variances are similar enough to use the pooled t-test to evaluate differences in the means. The answer is yes.

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Answer:

A positive z-score indicates that a particular value is greater than the mean, a negative z-score indicates that a particular value is less than the mean, and a z-score of zero indicates that a particular value is equal to the mean.

Step-by-step explanation:

Examples: Calculating a Z-Score

Suppose we have the following dataset that shows the height (in inches) of a certain group of plants:

5, 7, 7, 8, 9, 10, 13, 17, 17, 18, 19, 19, 20

The sample mean of this dataset is 13 and the sample standard deviation is 5.51.

1. Find the z-score for the value “8” in this dataset.

Here is how to calculate the z-score:

z  =  (X – μ) / σ  =  (8 – 13) / 5.51  =  -0.91

This means that the value “8” is 0.91 standard deviations below the mean.

2. Find the z-score for the value “13” in this dataset.

Here is how to calculate the z-score:

z  =  (X – μ) / σ  =  (13 – 13) / 5.46  =  0

This means that the value “13” is exactly equal to the mean.

3. Find the z-score for the value “20” in this dataset.

Here is how to calculate the z-score:

z  =  (X – μ) / σ  =  (20 – 13) / 5.46  =  1.28

The negative z-score indicates that a particular value will be less than the mean.

The Gaussian Distribution is another name for it. The most significant continuous probability distribution is this one. Because the curve resembles a bell, it is also known as a bell curve.

The z-score is a statistical evaluation of a value's correlation to the mean of a collection of values, expressed in terms of standard deviation.

The z-score is given as

z = (x - μ) / σ

Where μ is the mean, σ is the standard deviation, and x is the sample.

The points regarding the z-score are as follows:

The negative z-score indicates that a particular value will be less than the mean.

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Answer:

x^4+x^3

Step-by-step explanation:

Answer:

1-x3

Step-by-step explanation:

-x3(3x+1)-8

9-x3-8

1-x3

The maximum height of the fireworks using the equation h=-4.6t^2+27.6t+33.6 is 75 meters.

Identifying the coefficients a, b, and c from the given quadratic equation.
a = -4.6, b = 27.6, and c = 33.6

Calculating the t-value of the vertex using the formula t = -b / (2 × a)
t = -27.6 / (2 × (-4.6)) = 27.6 / 9.2 = 3

Now, plugging in the t-value back into the equation to find the maximum height.
h = -4.6(3)^2 + 27.6(3) + 33.6

  = -4.6(9) + 82.8 + 33.6

  = -41.4 + 82.8 + 33.6

  = 75

The maximum height of the fireworks is 75 meters.

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Step-by-step explanation:

A. cos4x-sin4x=2-cos2x

Answer:314

Step-by-step explanation:

Answer:

choice A

Step-by-step explanation:

im not sure what you really wanted so i did the cheapest option

Answer:

\(x<11\)

Step-by-step explanation:

Hi there!

\(2x-5<17\)

Add 5 to both sides

\(2x-5+5<17+5\\2x<22\)

Divide both sides by 2

\(\frac{2x}{2} < \frac{22}{2} \\x<11\)

I hope this helps!

Therefore, there are 4,060 different combinations of three-person dance committees that can be selected from a class of 30 students.

To calculate the number of different combinations of three-person dance committees that can be selected from a class of 30 students, we can use the concept of combinations. The number of combinations of selecting r items from a set of n items is given by the formula:

C(n, r) = n! / (r! * (n - r)!)

In this case, we want to select three students from a class of 30, so we have:

C(30, 3) = 30! / (3! * (30 - 3)!)

Calculating this expression:

C(30, 3) = 30! / (3! * 27!)

= (30 * 29 * 28) / (3 * 2 * 1)

= 4060

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Step-by-step explanation:

well well from your question the value of g wasn't given and we are asked to solve for f

I will have to assume g=g

make f subject of formula

first we open the brackets

-3g+6f=5g

collect like terms

6f=5g+3g

6f=8g

f=8g/6

f=(4/3)g

Answer:

x = 8 degrees ; y= 12 degrees

Step-by-step explanation:

The process to subtract the mixed fractions with the whole numbers is explained below.

The Mixed Fractions are defined as type of fraction that consists of a whole number and a proper fraction.

Step(i) : We multiply whole number by denominator of fraction and add numerator.

For example, if mixed fraction 2(1/3), we multiply 2 by 3 and add 1 to get 7. So, 2(1/3) is equivalent to improper fraction 7/3.

Step(ii) : Find a common denominator for fractions. We find least common multiple (LCM) of denominators.

For example, if you want to subtract 2(1/3) from 5, denominators are 3 and 1, and LCM is 3.

Step(iii) : Convert whole number to a fraction with same denominator as common denominator.

For example, if LCM is 3 and we want to subtract 2(1/3) from 5, we will convert 5 to fraction 15/3.

Step(iv) : Rewrite each fraction with common denominator.

For example, if we want to subtract 2(1/3) from 5, we rewrite 2(1/3) as 7/3 and 15/3 as 5.

Step(v) : Subtract the fractions.

For example, to subtract 7/3 from 5, we subtract numerators and keep the denominator: 15/3 - 7/3 = 8/3.

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It is not divisible by 3. However, we know that 0k+1 22(k+1) – 1 must be divisible by 3 for all integers k. This is a contradiction, so our assumption must be false. Therefore, we have proven that for all integers n, 0n 22n – 1 is divisible by 3.

To prove that for all integers n, 0n 22n – 1 is divisible by 3, we will use mathematical induction.

First, let's check the base case. When n = 0, we have 0220 – 1 = 0, which is divisible by 3.

Next, let's assume that for some arbitrary integer k, 0k 22k – 1 is divisible by 3. This is our induction hypothesis.

Now, we want to prove that this is also true for k + 1. We have: 0k+1 22(k+1) – 1 = (2 × 0k 22k) + (0 × 22) – 1 = 2(0k 22k – 1) + 1

From our induction hypothesis, we know that 0k 22k – 1 is divisible by 3.

Therefore, we can write: 0k 22k – 1 = 3m where m is some integer.

Substituting this into our equation above, we get: 2(3m) + 1 = 6m + 1

Now, we can see that 6m is divisible by 3, so 6m + 1 is one more than a multiple of 3.

Therefore, it is not divisible by 3. However, we know that 0k+1 22(k+1) – 1 must be divisible by 3 for all integers k. This is a contradiction, so our assumption must be false. Therefore, we have proven that for all integers n, 0n 22n – 1 is divisible by 3.

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n os  et u o

Step-by-step explanation:

To determine whether the set S is linearly independent or linearly dependent.The set is linearly independent. This is because the only way to make a linear combination of vectors equal to the zero vector is to have all the coefficients equal to zero.

A linear combination of vectors is the sum of a scalar multiple of each vector in the set. We must check if the equation a(-2,2,4) + b(1,9,-2) + c(2,3,-3) = (0,0,0) has only the trivial solution, i.e., a=b=c=0. This gives us the system of equations,-2a + b + 2c = 01a + 9b + 3c = 02a - 2b - 3c = 0We can solve the system of equations by using Gauss-Jordan elimination. The augmented matrix for the system is:[-2 1 2 0][1 9 3 0][2 -2 -3 0]Let's use elementary row operations to simplify the matrix.

We can swap the first and second rows since the first element in the second row is 1.[1 9 3 0][-2 1 2 0][2 -2 -3 0]We can then add twice the first row to the third row to eliminate the leading coefficient in the third row.[1 9 3 0][-2 1 2 0][0 16 3 0]We can then add nine times the first row to the second row to eliminate the leading coefficient in the second row.[1 9 3 0][0 17 15 0][0 16 3 0]We can then add -16/17 times the second row to the third row to eliminate the leading coefficient in the third row.[1 9 3 0][0 17 15 0][0 0 -117/17 0]We see that the only solution is a=0, b=0, and c=0. Therefore, the set S is linearly independent.

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Step-by-step explanation:

There are several different sampling methods that could be employed for this study, including:

Simple random sampling: This method involves randomly selecting a certain number of students from each campus and measuring the distance between their hometowns and their campuses.

Stratified random sampling: This method involves dividing the student population at each campus into different strata (e.g. by major or year in school) and then randomly selecting a certain number of students from each stratum.

Cluster sampling: This method involves randomly selecting a certain number of campuses and then measuring the distance between the hometowns of all students at those campuses and their respective campuses.

Multi-stage sampling: This method involves using a combination of the above methods, such as first using cluster sampling to select a certain number of campuses and then using stratified random sampling to select a certain number of students from each campus.

This study would be an enumerative study because it seeks to measure the characteristics of a population, in this case, the average distance between the hometowns of students and their campuses, by counting and measuring them.

It is not an analytic study because it doesn't involve testing a hypothesis or making causal inferences.

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Answer:

where the picture

Step-by-step explanation:

Step-by-step explanation:

\( \underline{ \underline{ \text{Solving \: a \: quadratic \: equation \: by \: factorisation \: method}}} : \)

In this method , the second order of polynomial ax² + bx + c is factorised and expressed as the product of two linear factors. Then each linear factor is separately solved to get the required solutions of the equation by applying zero factor property. In zero factor property , if p•q = 0 , then either p = 0 or q = 0 . In other words , if the product of two numbers is 0 , then one or both of the numbers must be 0.

\( \underline{ \underline{ \text{Let's \: solve}}} : \)

\( \tt{ {x}^{2} + 16x + 55 = 0}\)

Here , we have to find the two numbers that multiplies to 55 and adds to 16.

⤑ \( \tt{ {x}^{2} + (11 + 5)x + 55 = 0}\)

⤑ \( \tt{ {x}^{2} + 11x + 5x + 55 = 0}\)

⤑ \( \tt{x(x + 11) + 5(x + 11) = 0}\)

⤑ \( \tt{(x + 5)(x + 11) = 0}\)

Either :

\( \tt{x + 5 = 0 \: \: \: \: \: \: \: \: \: \: \: \: \: Or : \: \: x + 11 = 0}\)

\( \sf{⟶ x = 0 - 5} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:⟶ x = 0 - 11\)

\( \tt{⟶x = - 5 } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:⟶ x = - 11\)

\( \red{ \boxed{ \boxed{ { \tt{Our \: final \: answer : \boxed{ \underline{ \bold{ \tt{x = - 5 \: , - 11}}}}}}}}}\)

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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