consider combustion of ch4 with 02 forming co2 and h20 as the products. find the equilibrium constant for the reaction at 1000 k. use an average beat capacity of cp

Answer:

The three pKa values for phosphoric acid (H3PO4) are 2.12, 7.21, and 12.32.

Answer:

2NaCN + CaCO3 --> Na2CO3 + Ca(CN)2

Explanation:

Knowing the names gets us: NaCN + CaCO3 --> Na2CO3 + Ca(CN)2

Balance: there are two sodiums and cyanides on the product side so add a 2 to the reactant side.

Answer:

736 mmHg = 0.97 atm (Approx.)

736 mmHg = 736 Torr

Explanation:

Given barometer in the laboratory atmospheric pressure data:

Atmospheric pressure in mmHg = 736 mmHg

Find:

Change given data into Torr

Change given data in atm (atmospheric pressure)

Computation:

We know that;

1 atm = 760 mmHg

So,

736 mmHg = 736 / 760

736 mmHg = 0.97 atm (Approx.)

We know that;

760 mmHg = 760 Torr

So,

736 mmHg = 736 Torr

Answer:        HHHHHHHHHHHHHHHHHHHHHHAHAHHAHAHHAHHAHHAHHAHHAHAHAHHHAHAHAHHAHAHHA

DON"T KNOW?

Explanation:

The question is incomplete, the complete question is:

Using the following portion of the activity series for oxidation half-reactions, determine which combination of reactants will result in a reaction.

\(Li(s)\rightarrow Li^+(aq)+e^-\)

\(Al(s)\rightarrow Al^{3+}(aq)+3e^-\)

A) Li(s) with Al(s)

B) Li(s) with \(Al^{3+}\) (aq)

C) \(Li^+\) (aq) with Al(s)

D) \(Li^+\) (aq) with \(Al^{3+}\) (aq)

Answer: The correct option is B): Li(s) with \(Al^{3+}\) (aq)

Explanation:

The oxidation reaction is defined as the reaction in which a chemical species loses electrons in a chemical reaction.

A reduction reaction is defined as the reaction in which a chemical species gains electrons in a chemical reaction.  

The chemical species will undergo a reduction reaction if the value of standard reduction potential is more positive or less negative.

For the given half-reactions:

\(Li(s)\rightarrow Li^+(aq)+e^-;E^o_{Li^+/Li}=-3.04V\)

\(Al(s)\rightarrow Al^{3+}(aq)+3e^-;E^o_{Al^{3+}/Al}=-1.662V\)

As the value of standard reduction potential of aluminium is less negative. Thus, it undergoes reduction reaction and lithium will undergo oxidation reaction.

The half-reaction follows:

Oxidation half-reaction:  \(Li(s)\rightarrow Li^+(aq)+e^-\)            ( × 3)

Reduction half-reaction:  \(Al^{3+}(aq)+3e^-\rightarrow Al(s)\)

Overall cell-reaction:  \(3Li(s)+Al^{3+}(aq)\rightarrow 3Li^+(aq)+Al(s)\)

Hence, the correct option is B): Li(s) with \(Al^{3+}\) (aq)

Circuits C and D are parallel circuits. Therefore, options C and D are correct.

Parallel circuits are a type of electrical circuit configuration where multiple components are connected in parallel to the same power source. In a parallel circuit, each component has its own separate path for current to flow. It allows independent current flow through each component.

In a parallel circuit, the components, such as resistors, lamps, or other electrical devices, are connected side by side, with each component having its own branch or "loop" connecting it to the power source.

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Answer:

A. 6.02 x 1023

C. 3.43

D. 7.02

F. 302

Explanation:

A. 6.02 consists of three significant figures. 1023 consists of four. When multiplying two values, the answer's significant figures match the multiplicand with lower significant figures (in this case, 6.02).

C. 3.43 consists of three significant figures.

D. 7.02 also consists of three significant figures.

F. 302 is three significant figures as well. If this number was 300 instead, then it would only be one significant figure.

Answer:

A,B&C

Explanation:

A. 6.02 consists of three significant figures.

1023 consists of four. When multiplying two

values, the answers significant figures match

the multiplicand with lower significant figures

(in this case, 6.02).

C. 3.43 consists of three significant figures.

D. 7.02 also consists of three significant figures.

F.302 is three significant figures as well. If this

number was 300 instead, then it would only be

one significant figure.

(a)  The mass percent of HCl in the solution is approximately 36.1%.

(b)  The molality of HCl in the solution is approximately 15.5 mol/kg.

(c)  The mole fraction of HCl in the solution is approximately 0.218.

(a) To calculate the mass percent of HCl, we need to determine the mass of HCl in a given volume of the solution.

Given: Concentration of HCl = 11.8 M

Density of the solution = 1.190 g/mL

First, we need to calculate the mass of the solution. Since density is mass per unit volume, the mass of 1 mL of the solution is 1.190 g.

Next, we need to calculate the mass of HCl in 1 mL of the solution. Since the concentration is given in moles per liter (M), and the molar mass of HCl is 36.46 g/mol, we can calculate the mass of HCl in 1 mL as follows:

Mass of HCl = concentration × volume × molar mass

          = 11.8 mol/L × 0.001 L × 36.46 g/mol

          = 0.430 g

Now, we can calculate the mass percent of HCl using the following formula:

Mass percent = (mass of solute ÷ mass of solution) × 100

           = (0.430 g ÷ 1.190 g) × 100

           ≈ 36.1%

(b) The molality of HCl is calculated by dividing the moles of solute (HCl) by the mass of the solvent (water) in kilograms.

Since the density of the solution is given as 1.190 g/mL, the mass of 1 mL of the solution is 1.190 g. However, we need to consider the density of the solvent (water) to calculate the mass of water in the solution.

Assuming the density of water is 1 g/mL, the mass of water in 1 mL of the solution is (1.190 g - 0.430 g) = 0.760 g.

To calculate the molality of HCl, we need to convert the mass of water to kilograms:

Mass of water (kg) = 0.760 g ÷ 1000 = 0.000760 kg

The molality (m) is calculated using the formula:

Molality = (moles of solute ÷ mass of solvent in kg)

        = (11.8 mol/L × 0.001 L) ÷ 0.000760 kg

        ≈ 15.5 mol/kg

(c) The mole fraction (X) of HCl is calculated by dividing the moles of HCl by the total moles of all components in the solution.

To calculate the mole fraction, we need to consider the volume of the solution and convert it to liters.

Given: Concentration of HCl = 11.8 M

Volume of the solution = 1 mL

Volume of the solution (L) = 1 mL ÷ 1000 = 0.001 L

To calculate the mole fraction of HCl, we need to calculate the moles of HCl and the moles of water (solvent) in the solution.

Moles of HCl = concentration × volume

            = 11.8 mol/L × 0.001 L

            = 0.0118 mol

Moles of water = mass of water ÷ molar mass of water

             = 0.760 g ÷ 18.015 g/mol (molar mass of water)

             = 0.0422 mol

Total moles in the solution = moles of HCl + moles of water

                           = 0.0118 mol + 0.0422 mol

                           = 0.054 mol

Mole fraction of HCl = moles of HCl ÷ total moles

                   = 0.0118 mol ÷ 0.054 mol

                   ≈ 0.218

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Answer:

1.543 pounds = 700 grams

Hello. You forgot to say that this question is about the possibility of using some type of product that prevents cut apples from becoming darker.

Answer and Explanation:

1. The problem with this activity is "What can you put on an apple slice to keep it from turning brown?" The problem in a scientific experiment is the element that provides a question about what is being observed.

2. Hypotheses are assumptions made about what was observed, in addition, hypotheses can answer the question shown in the problem. In the case of apples, the hypotheses can be: "Lemon juice is the most efficient product in delaying the blackening of cut apples." "Water is inefficient in preventing blackened cut apples." "Milk accelerates the blackness of cut apples."

3. The dependent viable is one that needs to be influenced by another element to bring about a result. In the case of the experiment with apples, the dependent variable is the blackening rate of the apple slices.

4. The independent variable, on the other hand, refers to the element that does not need any influence to cause a result, on the contrary, this variable acts on the dependent variable, influencing it. In the case of this experiment, the independent variable is the types of liquid tested to delay the blackening of cut apples.

5. Lemon was the most efficient liquid. Probably this efficiency is related to the lemon's ability to decrease the strength of antioxidants, due to its very low pH.

Answer: An object can change velocity in a number of ways: it can slow down, it can speed up, or it can change direction. A change in speed, or a change in direction, or a change in both speed and direction means that the object has a change in velocity.

Explanation:

Answer:

λ = 4.46 x 10⁻⁷ m = 446 nm

Explanation:

Applying Law of Conservation of Energy in this condition, we will get the following equation:

Total Energy of Combined Photons = Energy of 1st Photon + Energy of 2nd Photon

hc/λ = hc/λ₁ + hc/λ₂

hc/λ = hc(1/λ₁ + 1/λ₂)

1/λ = 1/λ₁ + 1/λ₂

where,

λ = wavelength of combined photon = ?

λ₁ = wavelength of 1st photon = 853 nm = 8.53 x 10⁻⁷ m

λ₂ = wavelength of 2nd photon = 935 nm = 9.35 x 10⁻⁷ m

Therefore,

1/λ = 1/(8.53 x 10⁻⁷ m) + (9.35 x 10⁻⁷ m)

1/λ = (0.1172 x 10⁷ m⁻¹) + (0.1069 x 10⁷ m)

1/λ = 0.2241 x 10⁷ m⁻¹

λ = 1/(0.2241 x 10⁷ m⁻¹)

λ = 4.46 x 10⁻⁷ m = 446 nm

Answer:

446

Explanation:

Answer:

Make me a song give me some bars wait am i rappin to hard livin life high crazy right touch on her shhh f in th mhm aint waistin no time lets get into it tonight

Explanation:

Answer:The oxygen is coming from the atmosphere.

Explanation:

Answer:

To convert joules to calories, you can use the conversion factor:

1 calorie = 4.184 joules

To find out how many calories are in 4,180 joules, divide the given value by the conversion factor:

4,180 joules / 4.184 joules per calorie = 0.9 calories (approximately)

Therefore, there are approximately 0.9 calories in 4,180 joules.

Answer:

144 g of phosphorus contain 4.65 moles.

Explanation:

Given data:

Mass of phosphorus = 144 g

Number of moles = ?

Solution:

Formula:

Number of moles = mass/ molar mass

Molar mass of phosphorus is 31 g/mol

Now we will put the values in formula.

Number of moles = 144 g/ 31 g/mol

Number of moles = 4.65 mol

Thus, 144 g of phosphorus contain 4.65 moles.

Runoff includes; rivers, streams, creeks, and lakes.

Runoff refers to water that flows on the surface of the ground. Run off usually occurs after a heavy storm and may be responsible for some cases of flooding.

Runoff flows into water bodies such as rivers, streams, creeks, and lakes. These are water bodies that receives runoff water.

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Answer: all of these

Answer:The physical changes that are endothermic are melting, vaporization and sublimation.

Explanation:

Answer:

Its a compound :PP

Explanation:

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Answer:

Compound

Explanation:

The liquid substance used in the laboratory for dissolving dry mortar on floor flies is hydrochloric acid.

Hydrochloric acid is a strong acid that can dissolve many materials, including dry mortar.

Hydrochloric acid also known as muriatic acid or sulfuric acid, are commonly used to dissolve hardened mortar or concrete residues.

To use hydrochloric acid to dissolve dry mortar, you will need to mix the acid with water in a ratio of 1 part acd to 10 parts water.

You should then apply the mixture to the dry mortar using a brush or spray botle.

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When 6.8776g of aluminium reacts with an excess of oxygen, 6.8776g of aluminium oxide are produced.

What is the name of aluminum oxide?

Al2O3 is an inorganic chemical reagent with the chemical name aluminum oxide. Other names for it include alumina, alundum, al-alumina, and aloxide.

If there are 4 moles of Al that equals 107.926156 grams of 4Al

If there are 2 moles of Al2O3 that equals 203.9226g

If  107.9261 grams of 4Al equals 203.9226 grams of 2Al2O3 then, 3.64g of Al equals x

107.9261 / 3.64 = 203.9226 / x

(107.9261) x = (203.9226) 3.64

107.9261 x = 742.2782

dividing both LHS and RHS by 107.9261,

107.9261/107.9261x = 742.2782/107.9261

                             x = 6.8776g

Hence, 6.8776g of aluminium oxide are produced.

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Answer:

The given metal sample is not aluminum because its density is 3.0 g/cm³ while density of aluminum is  2.7 g/cm³.

Explanation:

Given data:

Density of aluminum = 2.7 g/cm³

Mass of metal sample = 52.0 g

Volume of metal sample = 17.1 cm³

which sample is that = ?

Solution:

The given problem will be solve through density formula.

d = m/v

d = density

m = mass

v= volume

Now we will put the values in formula.

d = 52.0 g/ 17.1 cm³

d = 3.0 g/cm³

It is given in question the density of aluminum is 2.7 g/cm³. The given metal sample is not aluminum because its density is 3.0 g/cm³.

Answer:

Left, Left, Right, Left, Right, Right

Explanation:

Follow that order!

The concept ideal gas equation is used here to determine the volume of the carbondioxide. Combustion reactions are generally highly exothermic reactions. The volume of CO₂ is

A combustion is a chemical reaction in which a fuel undergoes oxidation as a result of the reaction with an oxidizing agent which causes the release of energy in the form of heat.

15.0 °C = 288 K

The ideal gas equation is:

PV = nRT

V = nRT / P

V = 354 × 0.0821 × 288 / 0.995 = 8412.3 L

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Answer:

Preventing erosion – Land Reclamation

Protecting nesting areas – Protecting Biodiversity

Preventing littering – Land Reclamation

Preventing habitat disruption – Protecting Biodiversity

Protecting native species – Protecting Biodiversity

Preventing contamination of soil – Land Reclamation

Explanation:

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First, we need to know the total number of mass on the left side. The mass number of H plus He is 5, so the mass number of X must be 1.

Second, the sum of the atomic numbers on the left is 3, so the atomic number of X is 1.

Therefore, the missing element must have a mass number of 1, and an atomic number of 1, its chemical symbol H. It's a fusion reaction because the atom of He is heavier.

Hence,  If the concentration of Acetic acid in vinegar is more than 7%, the limiting reactant is baking soda. If the concentration of Acetic acid in vinegar is less than 7%, the limiting reactant is vinegar.

The limiting reactant (or limiting reagent) is the reactant that gets consumed first in a chemical reaction and therefore limits how much product can be formed.

To solve this problem, it is necessary to know the exact concentration of acetic acid in vinegar, because manufacturers produce many types of vinegar the with different concentrations. Most often, concentration of acetic acid in vinegar ranges from 4% to 8%. In this case, it is possible

to calculate the concentration of vinegar making the assumption that 250 ml of vinegar reacts completely with 24 grams of baking soda.

Acetic acid \(CH_3CO_2H\)  reacts with baking soda \(NaHCO_3\) according to the equation:

\(CH_3CO_2H + NaHCO_3\) → \(CH_3CO_2Na + CO_2 + H_2O\)

1. Molar mass of \(NaHCO_3\) is 23+1+12+16×3 = 84 g/mol

= \(\frac{1 mol \;NaHCO_3}{84 g \;NaHCO_3}\)

= \(\frac{24 g \;NaHCO_3 X 1 mol \;NaHCO_3}{84 g \;NaHCO_3}\)

=0.29 mol \(NaHCO_3\)

2. From the balanced equation we see that 1 mole of \(NaHCO_3\) reacts with 1 mole of \(CH_3CO_2H\) , then 0.29 moles of \(NaHCO_3\) react with 0.29 moles of \(CH_3CO_2H\).

3. Mass of 1 mole of \(CH_3CO_2H\) is 12+ 1×3+12+16×2=60 g/mol

= \(\frac{0.29 mol \;CH_3CO_2H X \;60 g \;CH_3CO_2H }{1 mol \;CH_3CO_2H}\)

\(=17.4 g CH_3CO_2H\)

4. In this step density of vinegar is needed.

Making the assumption that concentration of acetic acid is 7%, we can calculate the mass of acetic acid in 250 ml of vinegar:

Mass of vinegar=Volume × density

= 250 ml ×1.0084 g/ml

=252 g

Mass of acetic acid = mass of vinegar × concentration ÷ 100%

= 252 g × 7% ÷ 100%

= 17.6 g.

17.6 g \(CH_3CO_2H\) is very close to 17.4 g \(CH_3CO_2H\). It means, that 250 ml of vinegar with a concentration of acetic acid equal to 7% reacts completely with 24 g of baking soda.

Hence,  If the concentration of Acetic acid in vinegar is more than 7%, the limiting reactant is baking soda. If the concentration of Acetic acid in vinegar is less than 7%, the limiting reactant is vinegar.

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