The number of milligrams of sugar his spoon holds is 1250 milligrams.
To find out how many milligrams of sugar Chad's spoon holds, we first need to know how much sugar he removed in total. To do this, we can subtract the amount of sugar he needed (280 grams) from the amount he poured (295 grams).
295 grams - 280 grams = 15 grams
Next, we need to divide the total amount of sugar Chad removed (15 grams) by the number of spoonfuls he used (12).
15 grams ÷ 12 = 1.25 grams per spoonful
Finally, we can convert grams to milligrams by multiplying by 1000.
1.25 grams x 1000 = 1250 milligrams
Therefore, Chad's spoon holds 1250 milligrams of sugar.
It's important to note that when cooking or baking, precise measurements are crucial to the success of the recipe. Even small changes can greatly affect the outcome. While it's great that Chad was able to remove the excess sugar, it's best to be as accurate as possible from the start.
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If one leg of a right triangle has a length of 7 and the hypotenuse has a length of 12, what is the length of the other leg?
A
19
B
V193
с
195
D5
Answer:
sqrt(95)
Step-by-step explanation:
c^2 = a^2 + b^2
12^2 = 7^2 + b^2
144 = 49 + b^2
95 = b^2
sqrt(95) = b
Line segment AC is given by A (-3,6) and B (6,9). Find the coordinates of point B such that AB:BC is 2:1 Please help now
Answer:
(0, 7)
Step-by-step explanation:
Using the midpoint formula expressed as;
M (X, Y )= [(ax1+bx2/a+b), (ay1+by2/a+b)]
where a and b are the ratios
Given
a = 2
b = 1
x1 = -3
y1 = 6
x2 = 6
y2 = 9
Get the coordinate of B
Get X;
X = ax1+bx2/a+b
X = 2(-3)+1(6)/2+1
X = -6+6/3
X = 0/3
X = 0
Get Y;
Y = ay1+by2/a+b
Y = 2(6)+1(9)/2+1
Y = 12+9/3
Y = 21/3
Y = 7
Hence the coordinate of B is (0, 7)
What’s 50.272 to 1 decimal place
TRUNCATED to one decimal place, it's 50.2
ROUNDED to one decimal place, it's 50.3
The round-off of 50.272 to 1 decimal place using rules of rounding
numbers are 50.3.
Rounding off numbers means making a number simpler by adjusting it to its nearest place according to certain rules.
Rounding a number to one decimal place means keeping only the first digit after the decimal point and neglecting the rest. In this case, the digit in the second decimal place is 7, which is greater than or equal to 5. As per the rounding rules, if the digit is greater than 5, the preceding digit is increased by 1.
So, 50.272 becomes 50.3 when rounded to one decimal place.
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can someone answer this question really quick
The expression 1/3a + yb -2/3b +1/3a is equivalent to 2/3a+ 2b.
What is the value of y?
Enter your answer as a mixed number, such as 5 4/7.
(a) Let S be the parallelogram with vertices (3,0), (9,1), (0,3), and (6,4) in R2. Find the area of S using determinants. Hint: you will first want to find the vectors that represent the edges of the parallelogram. (b) Let : R2 → R2 be the linear transformation given by the standard matrix A- 3 -4 Compute the area of the image of S under T
The absolute value of the determinant gives us the area of the parallelogram, which is 21 square units.
To begin, we need to find the vectors that represent the edges of the parallelogram. Recall that a vector is a quantity that has both magnitude and direction. The vector that represents an edge of the parallelogram is simply the difference between the coordinates of its endpoints. For example, the vector that represents the edge connecting the points (3,0) and (9,1) is given by:
<9-3, 1-0> = <6,1>
Similarly, we can find the other three vectors:
<0-3, 3-0> = <-3,3>
<6-0, 4-3> = <6,1>
<0-6, 3-4> = <-6,-1>
Next, we need to arrange these vectors as the rows or columns of a 2x2 matrix. It doesn't matter which arrangement we choose, as long as we are consistent. For this problem, let's use the rows:
| 6 1 |
|-3 3 |
Now, we can take the determinant of this matrix, which is given by:
det(S) = (6)(3) - (1)(-3) = 21
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Complete Question:
Let S be the parallelogram with vertices (3, 0), (9,1), (0,3), and (6,4) in R2. Find the area of S using determinants. Hint: you will first want to find the vectors that represent the edges of the parallelogram
gcf of 16y^3-8y^2-20y
The greatest common factor of the polynomial expression 16y^3-8y^2-20y is; 4y.
What is the GCF of the given expression?As evident in the task content, the greatest common factor of the expression 16y³ - 8y² - 20y is to be determined.
On this note, we have that;
Since 4y is the greatest of all common factors to all terms of the polynomial expression;
16y³ - 8y² - 20y = 4y (4y² - 2y - 5).
Ultimately, the required greatest common factor is; 4y.
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Oliver's Flavored Popcorn comes in cylindrical tins divided into three equal sections of caramel, cheese, and buttered flavors. If the tin is 10 inches in diameter and 15 inches tall, what is the volume to the nearest tenth of only the cheese popcorn?
Answer:
The volume of only the cheese popcorn is 392.5 cubic inches.
Step-by-step explanation:
To determine the volume of only the cheese popcorn,
First, we will determine the volume of the cylindrical tin
The volume of a cylinder is given by
V = πr²h
Where V is the volume of the cylinder
π is a constant, (Take π = 3.14)
r is the radius of the cylinder
and h is the height of the cylinder
From the question, the tin is 10 inches in diameter and 15 inches tall.
Diameter = 10 inches, therefore, we can find radius
Radius = Diameter/2 = 10/2 = 5 inches
r = 5 inches
h = 15 inches
Now, putting the values into the equation, we get
V = 3.14 × 5² × 15
V = 1177.5 cubic inches
This is the volume of the cylindrical tin.
Since the cylindrical tin is divided into three equal sections of caramel, cheese, and buttered flavors, then the volume of only the cheese popcorn will be one-third of the total volume of the cylindrical tin.
∴ The volume of only the cheese popcorn = 1/3 × 1177.5 = 392.5 cubic inches
Hence, the volume of only the cheese popcorn is 392.5 cubic inches.
3. Given a nonempty polyhedron P={(x,y)∈Rn×Rk:Ax+By≥b}, let Q denote its projection onto x-space, i.e., Q={x∈Rn:∃y∈Rk,Ax+By≥b}. Prove or disprove the following statements by counterexamples: 1) Suppose that (x^,y^) is an extreme point of P. Is x^ an extreme point of Q ? 2) Suppose that x^ is an extreme point of Q. Does there exist a y^ such that (x^,y^) is an extreme point of P ? 3) Suppose that x^ is an extreme point of Q and P does not contain a line. Does there exist a y^ such that (x^,y^) is an extreme point of P ?
P does not contain a line, it means that for any x in R^n, there exists a unique y in R^k such that Ax + By ≥ b. Therefore, x^ is uniquely determined by y^, and (x^, y^) is an extreme point of P.
1) The statement is true. Suppose (x^,y^) is an extreme point of P. To show that x^ is an extreme point of Q, we need to prove that for any two distinct points x_1, x_2 in Q, the line segment connecting x_1 and x_2 lies entirely in Q. Since Q is the projection of P onto x-space, it means that for any x in Q, there exists y in R^k such that Ax + By ≥ b.
Now, let's assume x_1 and x_2 are two distinct points in Q. Since they belong to Q, there exist corresponding y_1 and y_2 in R^k such that Ax_1 + By_1 ≥ b and Ax_2 + By_2 ≥ b. Since P is a polyhedron, the set of points that satisfy Ax + By ≥ b is a convex set. Therefore, the line segment connecting x_1 and x_2, denoted by [x_1, x_2], lies entirely in P. Since the projection of a convex set onto a subspace is also a convex set, [x_1, x_2] lies entirely in Q. Thus, x^ is an extreme point of Q.
2) The statement is false. Suppose x^ is an extreme point of Q. It does not necessarily imply the existence of a corresponding y^ such that (x^, y^) is an extreme point of P. This is because the projection Q onto x-space may not capture all the extreme points of P. It is possible for multiple points in P to project to the same point in Q, making it impossible to uniquely determine y^.
3) The statement is true. If x^ is an extreme point of Q and P does not contain a line, then there exists a corresponding y^ such that (x^, y^) is an extreme point of P. Since P does not contain a line, it means that for any x in R^n, there exists a unique y in R^k such that Ax + By ≥ b. Therefore, x^ is uniquely determined by y^, and (x^, y^) is an extreme point of P.
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Calculate the concentrations of all species present in 0.72 M
NH3 (Kb=1.8×10−5).
Express your answers using two significant figures separated by
commas. Enter the concentrations of the species in t
To calculate the concentrations of all species present in a 0.72 M NH3 solution (Kb=1.8×10−5), we can use the principles of the equilibrium expression for the dissociation of NH3 in water.
NH3 (ammonia) is a weak base that reacts with water to form NH4+ (ammonium) and OH- (hydroxide) ions. The equilibrium expression for this reaction can be written as:
NH3 + H2O ⇌ NH4+ + OH-
Since the initial concentration of NH3 is 0.72 M, we can assume that x mol/L of NH3 will dissociate to form x mol/L of NH4+ and OH-. Therefore, the concentrations of NH4+ and OH- will also be x mol/L.
To calculate the value of x, we can use the Kb expression, which relates the equilibrium constant to the concentrations of the species. In this case, Kb = [NH4+][OH-]/[NH3]. Substituting the known values, we have:
1.8×10−5 = x * x / (0.72 - x)
Solving this equation will give us the value of x, which represents the concentration of NH4+ and OH-. Finally, we can express the concentrations of NH3, NH4+, and OH- using two significant figures, separated by commas, based on the calculated value of x.
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The box plots display data collected when two teachers asked their classes how many pencils they lose in a school year.
A box plot uses a number line from 5 to 47 with tick marks every one unit. The box extends from 8 to 14 on the number line. A line in the box is at 11. The lines outside the box end at 7 and 45. The graph is titled Mr. Johnson's Class, and the line is labeled Number Of Pencils.
A box plot uses a number line from 0 to 51 with tick marks every one unit. The box extends from 12 to 21 on the number line. A line in the box is at 14.5. The lines outside the box end at 0 and 50. The graph is titled Mr. Simpson's Class, and the line is labeled Number Of Pencils.
Which class lost the most pencils overall based on the data displayed?
Mr. Simpson's class; it has a larger median value 14.5 pencils
Mr. Johnson's class; it has a larger median of 11 pencils
Mr. Simpson's class; it has a narrow spread in the data
Mr. Johnson's class; it has a wide spread in the data
The class that lost the most pencils overall based on the data displayed is D. Mr. Johnson's class; it has a wide spread in the data
How to explain the informationThe answer is Mr. Johnson's class. The median is the middle value in a set of data. In Mr. Johnson's class, the median is 11 pencils. This means that half of the students in his class lost 11 or fewer pencils, and half of the students lost 11 or more pencils.
In Mr. Simpson's class, the median is 14.5 pencils. This means that half of the students in his class lost 14.5 or fewer pencils, and half of the students lost 14.5 or more pencils.
Since the median for Mr. Johnson's class is lower than the median for Mr. Simpson's class, we can conclude that Mr. Johnson's class lost more pencils overall.
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Evaluate the following expression. Round to the nearest hundredth when necessary.
3 to the power of 3
(sorry i dont know the symbol for this)
Answer:
27.
Step-by-step explanation:
3 to the power of 3 = 3*3*3
3*3 = 9.
9*3 = 27
Hope this helps!
What is the answer to this question? -10 x -6?
Answer: 60
Step-by-step explanation:
-10 x -6 = 60
Negative x Negative = Positive
Answer: 60
Step-by-step explanation: When multiplying integers,
if the signs are the same, the product is positive.'
So a negative times a negative always equals a positive.
So in this problem, -10 × -6 is 60.
Which expression represents the probability that both students chosen are sophomores? startfraction (20 c 6) (19 c 5) over 20 c 2 endfraction startfraction (20 p 6) (19 p 5) over 20 p 2 endfraction.
The expression represents the probability that both students chosen are sophomores is C( 6 , 1 ) * C ( 5 , 1 ) / C ( 20 , 2 ) .
Given :
The requested probability can be computed as the ratio between the number of ways to choose two sophomores in alternate positions \(N_s\) and the total number of possible choices \(N_t\) .
p = \(N_s\) / \(N_t\)
There are 6 sophomores and 14 freshmen to choose from each separate set. There are 20 students in total .
We'll assume the positions of the selections are NOT significative, i.e. student A/student B is the same as student B/student A.
To choose 2 sophomores out of the 6 available, the first position has 6 elements to choose from, the second has now only 5.
C( 6 , 1 ) * C ( 5 , 1 ) ways .
The total number of possible choices is C ( 20 , 2 )
Probability = C( 6 , 1 ) * C ( 5 , 1 ) / C ( 20 , 2 )
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Full question :
Six sophomores and 14 freshmen are competing for two alternate positions on the debate team. Which expression represents the probability that both students chosen are sophomores? StartFraction (6 C 1) (5 C 1) Over 20 C 2 EndFraction StartFraction (6 P 1) (5 P 1) Over 20 P 2 EndFraction StartFraction (20 C 6) (19 C 5) Over 20 C 2 EndFraction StartFraction (20 P 6) (19 P 5) Over 20 P 2 EndFraction
PLEASE HELP ME QUICKLY!!!!!
Find the equation of the line of best fit in slope-intercept form.
Question 5 Maple Choice Worth 4 points)
Compare 9 - 10% to 3 - 102
09-10'is 3 times larger than 3 . 102
09.10 is 30 times larger than 3 - 10%
09-10is 300 mes larger than 3 - 102
09. tofis 3.000 times larger than 3 - 102
Answer:
last one. 9 × 10^4 is 300 times larger than 3 × 10^2
Step-by-step explanation:
this is because
9 × 10 × 10 × 10 × 10 = 90,000
and
3 × 10 × 10 = 300
there difference is x300 for the second one to reach it.
Joe reads 30 chapters of a book in 6 hours What is his rate in chapters per hour
Answer:5
Step-by-step explanation:
30 chapters in 6 hours. 30/6 =5
Let g(x) ax+3 for x<-2 and g(x) = x^2+2x, for x>=-2.. What
values of a is the graph of g(x) continuous at x=-2?
The value of a for which the function g(x) is continuous at x = -2 is a = 1/4.
Given function:
g(x) = ax + 3 for x < -2and g(x) = x² + 2x for x ≥ -2.
Now, to check the continuity of the function at x = -2, we have to equate both functions at x = -2.
In other words,
g(-2) = a(-2) + 3
= (-2)² + 2(-2)
In simplification,
we get:
4a - 1 = 0
⇒ 4a = 1
⇒ a = 1/4
Thus, the value of a for which the function g(x) is continuous at x = -2 is a = 1/4.
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Given the function f(x) = 4x + 10 and g(x), which function has a greater slope?
x g(x)
2 5
4 7
6 9
f(x) has a greater slope.
g(x) has a greater slope.
The slopes of f(x) and g(x) are the same.
The slope of g(x) is undefined.
the body paint, an automobile body paint shop, has determined that the painting time of automobiles is uniformly distributed and that the required time ranges between 45 minutes to 90 minutes. c) what is the probability that the painting time will be more than 50 minutes?
(50 - 45) / (90 - 45) = 0.5.
The probability that the painting time of an automobile will be more than 50 minutes is 0.5 because the painting time is uniformly distributed between 45 minutes to 90 minutes.
Mathematically speaking, the probability can be calculated by subtracting the lower limit of the time range (45 minutes) from the given time (50 minutes) and then dividing it by the difference between the upper limit of the time range (90 minutes) and the lower limit of the time range (45 minutes).
So, the probability of the painting time being more than 50 minutes is: (50 - 45) / (90 - 45) = 0.5.
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6x + 4y = 10 slove for x
Un poste mide 6m de alto y desde la parte superior del poste se ata una cuerda tensa desde la punta hasta el suelo a una distancia de seis metros de la base del poste
Answer:
Primero, dibuje el escenario. El camino tomado por Shane forma un triángulo rectángulo. La distancia desde el punto de partida forma la hipotenusa.
How do you find the angle of a triangle with 3 side lengths?
By using the SSS triangle property we will find the angle of the triangle.
SSS means-Side Side Side
"SSS" is when we know three sides of the triangle, and want to find the missing angles.
To solve an SSS triangle we use the following steps:
First to calculate one of the angles we use the Law of Cosines
Apply the same process the Law of Cosines again to find another angle.
finally, use the angles of a triangle to add to 180° to find the last angle.
We use the "angle" of the Law of Cosines:
\(cos(C)=\frac{a^2+b^2-c^2}{2ab}\)
\(cos(A)=\frac{b^2+c^2-a^2}{2ab}\)
\(cos(B)=\frac{a^2+c^2-b^2}{2ab}\)
By using these formulas the angles of a triangle are measured.
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PLEASE HELP
Carmen is writing an article for a magazine. She will be paid a flat fee and also will be paid for each word that is published. The total amount she can expect to be paid, in dollars, can be estimated using the function f(x) = 2.5x + 150 . where s is the number of words published . What is the inverse of this function?
Step-by-step explanation:
Given Function
f(x) = 2.5x + 150
f^-1(x) = ?
Let y = f(x)
y = 2.5x + 150
Interchanging the role of x and y we get,
x = 2.5y + 150
x - 150 = 2.5y
y = (x - 150) / 2.5
So therefore
f^ -1(x) = (x - 150) / 2.5
Hope it will help :)
Seven friends share 2 bags of trail mix equally. What fraction of a bag of trail mix does each friend get
Answer:
2/7
Step-by-step explanation:
✓To determine the fraction of the bag of trail mix gotten by each friends, we will need to divide the 2 bags of the trail mix by the number of friends ( 7 friends)
✓ The division can be written in terms of fraction which is
( 2 bags / 7 friends)
= 2/7
✓ The share of each friend = 2/7 of the bag of the trail mix
✓ Hence, fraction of a bag of trail mix that each friend get is 2/7
A fish is 2 feet under water and begins to descend (or swim down) 0.5 feet each second.
Can you create a table that would show us how deep under water the fish is at these times?
Answer:
1 second - 0.5m
2 seconds - 1m
3 seconds - 1.5m
4 seconds - 2m
Step-by-step explanation:
Help!
Sarah was standing on a dock next to the ocean. She kicked a soccer ball off the dock to her friend in the water. 4 seconds after she kicked the ball it reached a height of 9 feet above the water. It hit the water 6 seconds later.
Write an equation for the path of the rock in y=a(x-h)^2+k and give the height of the dock that she kicked the ball from. Show your work!
Answer:
1) The equation for the of the ball in y = a·(x - h)² + k is;
y = -16·(x - 5)² + 25
2) The height of the dock, d = -375 feet below the water level
Step-by-step explanation:
1) The question is with regards to quadratic function representing projectile motion
The given parameters are;
The height the ball reaches 4 seconds after Sarah kicked the ball = 9 feet
The time the ball hits the water = 6 seconds after reaching the 9 feet height
The form of the quadratic equation representing the motion is given as follows;
y = a·(x - h)² + k = a·x² - 2·a·h·x + a·h² + k
Let 'x' represent the time of motion of the ball, and let 'a', represent the acceleration due to gravity, we have;
The equation for the ball, y = a·(x - h)² + k
Where;
(h, k) = The coordinates of the vertex
h = The horizontal component of the vertex coordinate = 0
Therefore, we have;
When x = 0, y = d
d = -16·(0 - h)² + k = -16·h² + k
d = -16·h² + k
When x = 4, y = 9 - d
9 - d = -16(4 - h)² + k = -16(4 - h)² + k
When x = 2, y = d
d = -16(2 - h)² + k
When x = 6, y = 9
9 = -16(6 - 5)² + k
When x = 8, y = d
d = -16(8 - h)² + k
-16(8 - h)² - (-16(2 - h)²) = 0
h = 5
From 9 - d = -16(4 - h)² + k = -16(4 - 4)² + k
d = 9 - k
9 = -16(6 - h)² + k
k = 9 + 16(6 - 5)² = 25
d = 9 - k = 9 - 25 = -16
Therefore, h = 5, k = 25
The equation for the of the ball in y = a·(x - h)² + k is therefore;
y = -16·(x - 5)² + 25
2) When x = 0, y = d, ∴ d = -16(0 - 5)² + 25 = -375 feet below the water
The height of the dock, d = -375 feet below the water level
Mary is four years more than twice the age of sam. Mary is 20 years old. How old is sam?
Equation:
Solution:
Answer: Sam is 14 years old.
Step-by-step explanation:
Equation: 20/2+4= 14
Solution: Do order of operations or PEMDAS. Parentheses, exponents, multiplication or division, addition or subtraction.
20/2= 10+4= 14.
A store has a sale for 15% off. You want a jacket that was originally $45. How much
money will the jacket be on sale?
A) 38.25
B)6.75
C)51.75
D)45.99
Answer:
es 51.75
Step-by-step explanation:
por que al sumar 45 + 15 porciento da 51.75
HELPPPPPPPPPPPPPPPPPPPPPPPPPPP
Answer:
See below ↓↓
Step-by-step explanation:
(a) Most variability
Refers to the class with the biggest range⇒ Class D(b) Highest scores on average
Refers to the class with the highest mean score⇒ Class CWhat is the value of the expression below when z=3?
Answer:
82
Step-by-step explanation:
10z^2 - 2z - 2 =
10(3)^2 - 2(3) - 2 =
10(9) - 2(3) - 2 =
90 - 6 - 2 = 82