Carbon dioxide is reduced by using electrons obtained from inorganic molecules, such as ammonia or hydrogen gas by ______________ since they do not use solar energy.

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Answer 1

Answer:

chemoautotrophs

Explanation:


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Explain the relationship between volume and temperature (Charles’ Law)

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Answer:

the volume of a give gas simple is directly propotional assolute temperature at constant pressure .the volume of a gavi. amount of gass is inversely propotional ot Its pressure when temperature is help constant

70 g of a solid solute is added to 50 g of water at 20 °c, and it all dissolves. when additional solute is added, it does not dissolve. identify the solute.

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70 g of a solid solute is added to 50 g of water at 20 °c, and it all dissolves. when additional solute is added, it does not dissolve. KI is the solute.

What is solute ?

A solute is a substance that has dissolved in a solution. Molecules of the solvent often outnumber those of the solute in a fluid solution. In our daily lives, salt and water are two of the most prevalent solutes. Salt becomes a solute when it is dissolved in water.

What is solvent?

Solvents are employed to dissolve the substances that serve as the formulation's solutes. The components of these solutes can be solids, liquids, or gases. The use of a suitable solvent in conjunction with the solute is required to create a solution.

given: 70g of solute is added to 50g of water at 20degree C

solution: at 20degree C,

since graph is for 100g of water

multiple by 2

2 x 50g of water=100g of water

similarly 2 x 70g of solute= 140g of solute

at 20degree C, The solute KI falls at 140g

Therefore , KI is the solute

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What is the purpose of chemistry lab?(solution)

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1. Some reactions will present an actual yield lower than the theoretical yield, and this can occur due to many situations, a couple of the reasons why that we can list is that some reactions don't have the reactants actually reacting to form the products, and another reason why is the loss of reactants in the process for many possible situations.

4. According to the solubility curve, if we have 30 grams of NH4Cl at 50°C, the reaction will be unsaturated

why would recrystallization, rather than chromatography, be the purification method of choice for the production of large amounts of compounds (multiple kilograms or more)?

Answers

Recrystallisation is preferred for large-scale production of compounds.

Recrystallization would be the purification method of choice for the production of large amounts of compounds because it is a simpler and more cost-effective method compared to chromatography. Chromatography is a time-consuming process and requires specialized equipment and skilled technicians to perform. It is also more expensive due to the cost of the equipment and consumables. Recrystallization, on the other hand, is a relatively simple process that involves dissolving the compound in a solvent and allowing it to crystallize out as the solvent is cooled. This process can be easily scaled up for large-scale production and requires minimal equipment and resources. Therefore, recrystallization is preferred for large-scale production of compounds.

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The melting point X of a certain specimen be assumed to be a continuous random variable which is uniformly distributed over the interval [110, 120]. Find density function of X, mean of X, variance of X and P (112 x < 115.).

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Density function: f(x) = 1/10, for 110 ≤ x ≤ 120, and f(x) = 0 otherwise.

Mean: μ = 115.

Variance: σ^2 = 25/3.

Probability: P(112 < X < 115) = 0.3.

Given that the melting point X is uniformly distributed over the interval [110, 120], we can find the density function, mean, variance, and probability as follows:

1. Density function:

Since X is uniformly distributed, the density function f(x) is constant within the interval [110, 120] and zero outside that interval. To find the density function, we need to determine the height of the constant density.

The total length of the interval is 120 - 110 = 10.

Since the density function is constant, the area under the density function curve must be equal to 1.

Therefore, the height of the constant density is 1 divided by the length of the interval: f(x) = 1/10, for 110 ≤ x ≤ 120, and f(x) = 0 otherwise.

2. Mean:

The mean (μ) of a uniform distribution is the average of the endpoints of the interval. In this case, the mean is (110 + 120) / 2 = 115.

3. Variance:

The variance (σ^2) of a uniform distribution is calculated using the formula: σ^2 = (b - a)^2 / 12, where a and b are the endpoints of the interval. In this case, the variance is (120 - 110)^2 / 12 = 10^2 / 12 = 100/12 = 25/3.

4. Probability:

To find P(112 < X < 115), we need to calculate the area under the density function curve between the points 112 and 115.

Since the density function is constant within the interval [110, 120], the probability is equal to the ratio of the length of the interval [112, 115] to the length of the entire interval [110, 120].

The length of the interval [112, 115] is 115 - 112 = 3.

The length of the entire interval [110, 120] is 120 - 110 = 10.

Therefore, P(112 < X < 115) = (3 / 10) = 0.3.

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A student dissolves a spoon full of table salt (sodium chloride) in a glass of water.
After the salt is completely dissolved, the major entities in the glass (other than the
water itself) are:
(select all that apply)
Sodium chloride crystals
Aqueous sodium ions
Chlorine gas
Solid sodium metal
Liquid sodium metal
Aqueous chloride ions

Answers

Answer:

Aqueous sodium ions, Aqueous chloride ions

Explanation:

Sodium chloride dissociates into Na+ and Cl- ions in water

Sodium chloride crystals may also be present in case of saturated solution

To calculate acceleration you must know both the objects velocity and _______________ 1pt

Answers

Answer:

i think its speed

Explanation:

Answer:

Velocety and mass

Explanation:

calculate the average atomic mass of copper if 69.15 of naturally occuring copper is cu-63 and 30.85 is cu 65

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The average atomic mass of copper is 63.62
calculate the average atomic mass of copper if 69.15 of naturally occuring copper is cu-63 and 30.85

Which of the following has the highest electromagnivity

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Answer:

Where are the answer choices

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Elements that are in the same _____ have the same number of electrons in their outer ______. These outer electrons are so important in determining the chemical ______ of an element that a special way to represent them has been developed. A(n) _____ uses the symbol of the element and dots to represent the electrons in the outer _______

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Elements that are in the same group have the same number of electrons in their outer shell. These outer electrons are so important in determining the chemical properties of an element that a special way to represent them has been developed. A(n) electron dot diagram uses the symbol of the element and dots to represent the electrons in the outer shell.

The elements in the same group have the same number of electrons in their outer shell because they have the same number of valence electrons. These valence electrons are responsible for the chemical properties of an element, which is why elements in the same group have similar chemical properties. The symbol of the element is used in the electron dot diagram to represent the element, and the dots are used to represent the valence electrons in the outer shell. This diagram is a useful tool for understanding the chemical behavior of an element and for predicting how it will react with other elements.

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how many moles of H2 would be required to produce 37.0 moles of water?

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Hii there !

The reaction accompanying production of water in this case would be -

\(\green{ \underline { \boxed{ \sf{H_2+ \frac{1}{2}O_2\longrightarrow H_2O}}}}\)

Thus ,by observing the reaction, we can conclude that 1 mole of Hydrogen (H\(_2\))react with 1/2 mole of oxygen(O\(_2\))to produce 1 mole of water (H\(_2\)O)

\(\implies\)Therefore, 37.0 moles of hydrogen(H\(_2\)) will be required to produce 37.0 moles of water.

Hope it helps.

The formulas for the of the t-statistic and f-ratio concern and involve group ___.

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The formulas for the of the t-statistic and f-ratio concern and involve group of standard deviation.

It is frequently noted that the t-statistic and the F-statistic may be calculated from the same data when ANOVA is applied to only two groups, and that the two statistics can therefore be connected using the straightforward formula t2 = F.

The fact that these tests use the F-values to test the hypotheses is the basis for the term "F-test." The ratio of two variances is known as an F-statistic, and it bears Sir Ronald Fisher's name. Variances quantify how evenly distributed the data points are around the mean. When the individual data points tend to deviate further from the mean, there are more variances.

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A 50-gallon drum is being used to concentrate clean water that is flowing into the top of the drum with chlorine.
Water flows in at a rate of 5 gallons per hour, with chlorine concentrated at 3 grams per gallon. Chlorinated water is then being
pumped out at the same rate to keep the drum full of liquid without overflowing. The water is initially clean and contains no
chlorine.
a) Write a differential equation modeling the rate at which chlorine accumulates in the drum, y, in grams, t hours since the concentration process begins.
b) Find any equilibrium point(s) and explain the practical meaning of this value(s).
c) Using the idea of a phase line (do not solve the ODE), describe what we can expect to happen to the amount of chlorine in the tank in the long-run.

Answers

A) The differential equation is dy/dt = (3/50) * 5 - (y/50) * 5.

B) Equilibrium point: y = 30g. It represents the steady-state chlorine concentration where the inflow rate matches the outflow rate.

C) The chlorine amount will approach and stabilize at 30g. No net change occurs as the inflow matches the outflow.

In part A, we are given the information about the rate at which clean water with chlorine is flowing into the drum and being pumped out to maintain the liquid level. The differential equation dy/dt = (3/50) * 5 - (y/50) * 5 models the rate at which chlorine accumulates in the drum over time. The first term represents the inflow rate of chlorine, and the second term represents the outflow rate. By subtracting the outflow rate from the inflow rate, we get the net rate of accumulation of chlorine in the drum.

In part B, we find the equilibrium point(s) by setting the rate of accumulation (dy/dt) to zero and solving for y. The equation (3/50) * 5 - (y/50) * 5 = 0 simplifies to 3 - y/10 = 0, and solving this equation gives y = 30. This means that when the concentration of chlorine in the drum reaches 30 grams, the inflow rate of chlorine matches the outflow rate, resulting in a steady-state concentration.

The practical meaning of this equilibrium value is that the drum will maintain a constant chlorine concentration of 30 grams in the long run, as long as the inflow and outflow rates remain unchanged.

In part C, using the concept of a phase line, we can expect that the amount of chlorine in the tank will approach and stabilize at the equilibrium value of 30 grams in the long run. Since the inflow rate of chlorine is balanced by the outflow rate, there will be no net change in the concentration over time. The system will reach a stable state where the chlorine concentration remains constant. Thus, the chlorine amount will remain at 30 grams indefinitely.

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When the dry ingredients of a cake are combined, what is the result? A.Element B.Mixture C.Compound D.Atom

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A combination of dry ingredients of a cake results in a mixture.

A mixture is a combination of substances that are only physically but not chemically combined.

Mixtures are different from elements, compounds, and atoms because:

elements are pure substances consisting of a single type of atomcompounds are a mixture of different elements that are chemically combinedatoms are the smallest particle of an element.

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Answer:

Its mixture

Explanation:

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If a lab requires each lab group to have 25ml of a solution and it takes 15 grams of CuNO3 to make 1 liter of solution how many grams are needed to make enough solution for 22 lab groups ?

Answers

We need to do some general algebra here.

We will find that you need 8.25 grams of CuNO₃ to make enough solution for the 22 labs.

We know that:

Each lab group needs 25 ml of solution.it takes 15 g of CuNO₃ to make one L of that solution.There are 22 labs.

Because each lab needs 25 ml of solution, 22 labs will need that amount 22 times, so the total amount of solution needed is:

22*25ml = 550 ml

Now we know that we need 15 grams to make one liter of solution, and:

1 L = 1000ml

Then you need 15g to make 1000ml

and x (we want to find this amount) to make 550ml

Then we can write two equations (not actual equations, as these are different units) like:

x = 550ml

15g = 1000ml

Now we can take the quotient between these two equations:

x/15 g = (550ml/1000ml)

And now we can solve this for x:

x = (550ml/1000ml)*15g = 8.25g

So you need 8.25 grams of CuNO₃ to make enough solution for the 22 labs.

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Carbon fiber (CFRC) is generally stronger than steel, however, steel has a density that is about ____ compared to carbon fiber.

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Carbon fiber Vs Steel:

Steel has a density that is about five times more when compared to carbon fiber.

What is Carbon fiber (CFRC):

Carbon is an element that occurs naturally, and carbon fiber is made of this element. Because of its crystalline structure, carbon fiber possesses excellent tensile strength and stiffness capabilities. It is used to create lightweight composite parts that have great strength by wrapping the fiber in a polymer matrix.

What is steel:

Steel has long been a preferred material due to its high elasticity, which is around 200 GPa. Its relative abundance and stiffness have made it a widely used manufacturing material. However, because of its weight and density of around 8 g/cm3, it can be exceedingly difficult on the machines it is intended to protect. This weighs nearly five times as much as carbon fiber materials which would offer an equivalent or higher level of stiffness.

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Please help with (i) (j) (k)

Please help with (i) (j) (k)

Answers

Answer:

Explanation: l m n o p q r s t u v w x y z

What are the conditions that are required for electrical energy to be present in an electrical circuit?

Answers

Answer:

 a supply of electric charges which are free to flow, some form of push to move the charges through the circuit and a pathway to carry the charges.

Explanation:

There's your answer have a good day

How many atoms are in 9.95 moles of iron?

How many molecules are in 0.03 moles of Carbon dioxide?

How many moles are found in 7.20 x 1023 atoms of platinum?

Answers

Answer:

59.92 × 10²³ atoms are in 9.95 moles of iron

1.8 ×10²² molecules are in 0.03 moles of Carbon dioxide

1.19 moles are found in 7.20 x 10^23 atoms of platinum

Bainliest. Mole Conversion
Using dimensional analysis determine how many moles are present in 125g of Oxygen gas. O = 16.0 g/mol (3 sig figs)

Answers

Answer:

125g × 1 mol/16 grams = 7.81 × avogadros #

Calculate the percentage of HF molecules ionized in a 0.10 M HF solution. The Ka of HF is 6.8 x 10-4

Answers

The percentage of HF molecules ionized in a 0.10 M HF solution is 26%.

The dissociation of HF in water is represented by the chemical equation:

HF(aq) + H₂O(l) ↔ H₃O+(aq) + F-(aq)

The equilibrium constant expression for this reaction is:

Ka = [H₃o⁺][F-] / [HF]

where [H₃o⁺] is the concentration of hydronium ions, [F-] is the concentration of fluoride ions, and [HF] is the concentration of undissociated HF.

We are given that the initial concentration of HF is 0.10 M, and the value of Ka is \(6.8 x 10^-4.\)

Let x be the extent of ionization, which is the concentration of H₃O+ and F- ions formed at equilibrium. Then, the equilibrium concentrations can be expressed as follows:

[H₃O+] = x

[F-] = x

[HF] = 0.10 - x

Substituting these expressions into the equilibrium constant expression, we get:

\(6.8 x 10^-4 = x^2 / (0.10 - x)\)

Solving for x using the quadratic formula, we get:

x = 0.026 M

The percentage of HF molecules ionized can be calculated as:

% ionization = (moles of HF ionized / initial moles of HF) x 100%

= [(0.026 mol/L) / (0.10 mol/L)] x 100%

= 26%

Therefore, the percentage of HF molecules ionized in a 0.10 M HF solution is 26%.

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importance of mole ratio in solvey process

Answers

Answer:

Sry i accidently clicked on ''SAVE''.

U can remove it or report it...

Explanation:

The following galvanic cell has a potential of 1.214 V at 25∘C:
Hg(l)|Hg2Br2(s)|Br−(0.10M)||MnO4−(0.10M),Mn2+(0.10M),H+(0.10M)|Pt(s)
Calculate the value of Ksp for Hg2Br2 at 25∘C.
Express your answer using one significant figure.

Answers

The value of Ksp for Hg2Br2 at 25∘C is 1.0 × 10^-12.

The given galvanic cell involves the reaction between Hg(l), Hg2Br2(s), Br−(0.10M), MnO4−(0.10M), Mn2+(0.10M), H+(0.10M), and Pt(s). The potential of the cell is given as 1.214 V at 25∘C.

To calculate the value of Ksp for Hg2Br2 at 25∘C, we can use the Nernst equation:

Ecell = E°cell - (0.0592/n) * log(Q)

Where Ecell is the cell potential, E°cell is the standard cell potential, n is the number of electrons transferred, and Q is the reaction quotient.

Since Hg2Br2 is a solid and its concentration does not appear in the reaction quotient, we can assume its activity is 1. Therefore, the reaction quotient simplifies to the concentrations of the other species involved in the cell:

Q = [Br−] / [MnO4−][Mn2+][H+]

By substituting the given concentrations and the calculated cell potential into the Nernst equation, we can solve for E°cell. Then, using the Nernst equation at equilibrium (Q = Ksp), we can solve for Ksp. In this case, the value of Ksp for Hg2Br2 at 25∘C is found to be 1.0 × 10^-12, rounded to one significant figure.

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what is the definition of balanced force

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Answer:

If a person pushes something and it doesn't change its position then it is called balanced force.

A demand o2 delivery system utilizes a _________________ to trigger o2 flow.

Answers

A demand O2 delivery system utilizes a "pressure drop" mechanism to trigger oxygen flow.

In a demand oxygen delivery system, the flow of oxygen is triggered by a pressure drop that occurs when the user initiates inhalation. When the user takes a breath, the drop in pressure in the system activates the mechanism that releases oxygen.

This mechanism can be a valve or regulator that opens to allow oxygen to flow from the source to the user.

The pressure drop required to trigger the oxygen flow depends on the specific design of the system and can vary. Generally, the pressure drop is set at a level that ensures the user's inhalation effort is sufficient to activate the oxygen flow while maintaining a safe and reliable operation.

The pressure drop is typically calibrated and adjusted during the manufacturing process to meet the desired specifications and requirements of the system.

In summary, a demand oxygen delivery system relies on a pressure drop mechanism to initiate the flow of oxygen. This mechanism ensures that oxygen is released when the user inhales, providing them with the required oxygen supply.

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a triprotic acid h3a has pka's of 2.50, 5.75, and 9.25. what is the pkb for the base a3-? if you need to, assume the solution is at 25 oc, where the kw is 1.00x10-14.

Answers

The given triprotic acid H₃A has pka's of 2.50, 5.75, and 9.25.

The pkb for the base A³⁻ can be calculated using the formula: pka + pkb = 14, where pka is the acid dissociation constant and pkb is the base dissociation constant.

Using this formula, we can first calculate the value of the third pkb as follows:

pka + pkb = 14 ⇒

pkb = 14 - 9.25

= 4.75

Similarly, we can calculate the second pkb:pka + pkb = 14

⇒ pkb

= 14 - 5.75

= 8.25

Now, we can calculate the first pkb:pka + pkb = 14 ⇒ pkb = 14 - 2.5 = 11.5

Therefore, the pkb values for the base A³⁻ are 11.5, 8.25, and 4.75 respectively.

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The 3 conditions under which colliding particles can react are

Answers

For collisions to be successful, reacting particles must (1) collide with (2) sufficient energy, and (3) with the proper orientation.

The state (or phase) of matter can be changed by

Answers

Answer:

The state (or phase) of matter can be changed by pressure and temperature condition .

What is not a possible source of error?

Question 4 options:

people observe things slightly differently and can make mistakes


all answers are sources of error


measuring devices have limits, might be broken, or might be calibrated incorrectly


Lap equipment is not always identical (they can vary)


outside factors can affect te experiment (temperature, humidity, light, wind, etc.)

Answers

All the choices in the question are sources of error i.e.

People observe things slightly differently and can make mistakesMeasuring devices have limits, might be broken, or might be calibrated incorrectlyOutside factors can affect the experiment (temperature, humidity, light, wind, etc.

Experiments are usually not 100% accurate. This means that an experiment is most of the time, with error. Errors usually occur in measurement or observation and can cause them to be different from the true values of what is being measured.

TYPES OF ERROR:

Error can either be systematic or random.

Random errors are errors causes by unpredictable circumstances in the experimentSystematic errors are caused by faulty or inaccurate instruments used.

According to this question, the following can be sources of errors in an experiment:

People observe things slightly differently and can make mistakesMeasuring devices have limits, might be broken, or might be calibrated incorrectlyOutside factors can affect the experiment (temperature, humidity, light, wind, etc.

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A rock weighing 75.0g is placed in a graduated cylinder displacing the volume from 31.4 ml to 36.5ml. What is the density of the rock in grams /cubic centimeter.

Answers

Answer:

14.71 g/cm³

Explanation:

The density of a substance can be found by using the formula

\(density = \frac{mass}{volume} \\\)

volume = final volume of water - initial volume of water

volume = 36.5 - 31.4 = 5.1 mL

But

1 mL = 1 cm³

5.1 mL = 5.1 cm³

From the question we have

\(density = \frac{75}{5.1} \\ = 14.705882..\)

We have the final answer as

14.71 g/cm³

Hope this helps you

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