Can you put fruit in a pewter bowl?

Answer:

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

\(n = \frac{N}{L} \\ \)

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

\(n = \frac{2.39 \times {10}^{23} }{6.02 \times {10}^{23} } \\ = 0.39700996...\)

We have the final answer as

Hope this helps you

Answer:

table salt

Explanation:

The correct answer is (c) two, because TiO₂ is a compound made up of one titanium (Ti) atom and two oxygen (O) atoms.

TiO₂ is a compound that consists of one titanium atom and two oxygen atoms. The chemical formula for TiO₂ indicates that each molecule of TiO₂ contains two atoms of oxygen. Therefore, if you have one molecule of TiO₂, it must contain two molecules of oxygen.

Option (a) is incorrect because TiO₂ is not a mixture of Ti and O₂, but a compound made up of Ti and O atoms. Option (b) is incorrect because O₂ is a different molecule than TiO₂ and is not part of the compound. Option (d) is incorrect because TiO₂ contains one molecule, not three.

Therefore, the correct answer is (c) two, because each molecule of TiO₂ contains two oxygen atoms.

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Answer:

as water moves into a more narrow space and accelerates causing air to speed up with the tube.

hope this helps ;)

The balanced chemical equation for the acid-base reaction is:

2HCl + Ca(OH)2 → CaCl2 + 2H2O

A balanced chemical equation is a representation of a chemical reaction that shows the relative number of reactant and product molecules involved. It follows the law of conservation of mass, which states that matter cannot be created or destroyed in a chemical reaction. In a balanced equation, the number of atoms of each element on both sides of the equation is equal.

A balanced chemical equation includes chemical formulas of reactants on the left side of the arrow and the chemical formulas of products on the right side. Coefficients are used to balance the equation by adjusting the number of molecules or moles of each substance involved. These coefficients indicate the relative stoichiometric ratios between reactants and products.

According to the equation, for every 1 molecule of CaCl2 that forms, 2 water molecules are produced. Therefore, the correct answer is:

twice as many, 2x

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Therefore, you would need to weigh approximately 5.16 grams of Au(III) nitrate to obtain exactly 3.00 grams of gold atoms.

To calculate the grams of Au(III) nitrate needed to obtain 3.00 grams of gold atoms, you'll need to consider the molar mass and stoichiometry.

First, find the molar mass of Au(III) nitrate (Au(NO3)3) by adding the atomic masses of each element:

Au (197 g/mol) + 3x N (14 g/mol) + 9x O (16 g/mol)

= 339 g/mol.

Next, determine the ratio of gold atoms to Au(III) nitrate in the balanced chemical equation. In this case, it's 1:1.

Now, divide the molar mass of Au(III) nitrate by the molar mass of gold atoms (197 g/mol) to get the ratio of grams of Au(III) nitrate to grams of gold atoms:

339 g/mol ÷ 197 g/mol = 1.72 g/mol.

Finally, multiply the ratio by the desired amount of gold atoms (3.00 g) to find the grams of Au(III) nitrate needed:

1.72 g/mol x 3.00 g = 5.16 grams.

Therefore, you would need to weigh approximately 5.16 grams of Au(III) nitrate to obtain exactly 3.00 grams of gold atoms.

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It will have a mass of 3.025 amu. This is because the mass of a tritium atom is made up of the mass of one proton, two neutrons, and three electrons.

The mass of a single atom of 3H (tritium) can be predicted by adding the mass of the three protons, three neutrons, and three electrons in the atom. Since a single atom of 3H (tritium) contains 3 protons, 3 neutrons, and 3 electrons, the mass of a single atom of 3H (tritium) can be calculated by adding the mass of each of these particles together.

The mass of a single atom of 3H (tritium) can be calculated using the equation:

Mass of 3H (tritium) = \((3 * Mass of Proton) + (3 * Mass of Neutron) + (3 * Mass of Electron)\)

Mass of 3H (tritium) =\((3 *1.0074 amu) + (3 *1.0087 amu) + (3 * 0.00054858 amu)\)

Mass of 3H (tritium) = \(3.0218 amu\)

Therefore ,he mass of a single atom of 3h (tritium) is 3.0218 amu

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complete question:the mass of a proton is 1.0074 amu, the mass of a neutron is 1.0087 amu, and the mass of an electron is 0.00054858 amu. given this information, what can you predict for the mass of a single atom of 3h (tritium)?

it will have a mass of exactly 3 amu

it will have a mass of 1.008 amu

it will have a mass of 3.025 amu

it will have a mass somewhat greater than 3.025 amu

it will have a mass somewhat less than 3.025 amu

Answer:

Elements are all the subtances on the periodic table. Compound are elements that are fused by chemical means like potassium chloride. Mixture are elements that are not chemically fused but just in a sense mixed together.

(a) The electron configuration of fluorine is 1s² 2s² 2p⁵.

(b) The electron configuration of Phosphorus is 1s² 2s² 2p⁶ 3s² 3p³.

(a) Fluorine (F) with atomic number 9:

The electron configuration of fluorine can be determined by sequentially filling up the orbitals with electrons, following the Aufbau principle and the Pauli exclusion principle. The atomic number 9 tells us that fluorine has 9 electrons.

1s² 2s² 2p⁵

Energy Level Diagram: Refer fig 1

(b) Phosphorus (P) with atomic number 15:

Following the same principles, we can determine the electron configuration of phosphorus with its atomic number of 15.

1s² 2s² 2p⁶ 3s² 3p³

Energy Level Diagram: Refer fig 2

In the energy level diagram, each line represents an energy level or shell, while the superscripts indicate the number of electrons in each orbital. The arrows represent the electrons, with the upward arrow indicating a spin-up electron and the downward arrow indicating a spin-down electron.

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Answer: s - stable

i - unstable

th - unstable

Explanation: only the first has the same number of neutrons as protons (i hope this is right i’m just a sophomore chem student lol)

The percent abundance of the post-1982 pennies is 56%.

Percent abundance is the percentage amount of all naturally occurring isotopes of an element.

The percent abundance of the post-1982 pennies is calculated as follows;

percent abundance = number of  post-1982 pennies / total number of pennies x 100%

percent abundance =  (28) / (50) x 100%

percent abundance =  56%

Thus, the percent abundance of the post-1982 pennies is 56%.

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Answer:

FOR PRE 44

Explanation:

22/50X100=44

20 %

Explanation:

becuz 25 divided by 125 multiplied by 100 is 20

The atoms of a specific element is A zinc Zn atom containing 30 protons inside the nucleus and 30 electrons outside the nucleus.

Each element's atoms contain a characteristic number of protons and electrons. The number of protons determines the atomic number of an element and is used to distinguish one element from another. All atoms of a given element are identical in that they have the same number of protons, which are one of the building blocks of an atom.

Atoms of different elements have different numbers of protons, so they are also different from atoms of all other elements. Atoms can only have electrons and protons, but neutrons are the correct description for an element's atom. There are two properties that can be used to identify an element. Atomic number or number of protons in an atom. The number of neutrons and the number of electrons are often the same as the number of protons.

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To determine the phases present, a fraction of each phase, and the composition of each phase in a carbon-fe alloy containing 1.5 wt% C cooled down to 800°C, you would need to refer to the phase diagram for carbon-iron (Fe-C) alloy, also known as the iron-carbon phase diagram.

1. Consult the phase diagram: Look for the region that corresponds to the composition of the alloy, which is 1.5 wt% C.

Find the temperature range of 800°C.

2. Determine the phases present: From the phase diagram, identify the phases present at 800°C for an alloy with 1.5 wt% C.

3. Determine the fraction of each phase present: The phase diagram may provide information about the fraction of each phase present at 800°C for the given composition.

4. Determine the composition of each phase: The phase diagram should also indicate the composition of each phase present at 800°C.

Please refer to the specific phase diagram for the carbon-fe alloy you are working with to find the exact information on phases, fractions, and compositions at 800°C for an alloy with 1.5 wt% C.

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Answer:

Amplitude is measured from the center line to the highest point in the waves.

Wavelength is the distance between one wave to the other from the highest point.

Frequency is the rate of the waves.

A heating curve is a graph that shows the changes in temperature and physical state of a substance as heat is added at a constant rate.

Solid section: At the beginning of the heating curve, the substance is in its solid state. The temperature is relatively low and remains constant as heat is added. During this section, the energy added is used to overcome the intermolecular forces that hold the particles together in a fixed, orderly arrangement.

Melting section: As heat is added to the solid, its temperature increases until it reaches its melting point. At this point, the energy added is used to overcome the intermolecular forces holding the particles in the solid together, causing the substance to transition from a solid to a liquid state. During this section, the temperature remains constant until all the solid has melted.

Liquid section: Once the substance has completely melted, the temperature of the liquid starts to increase as heat is added. During this section, the energy added is used to increase the kinetic energy of the particles, causing them to move faster and spread apart.

Boiling section: When the temperature of the liquid reaches its boiling point, the energy added is used to overcome the intermolecular forces holding the particles together in the liquid and to separate the particles from each other, causing the substance to transition from a liquid to a gas state. During this section, the temperature remains constant until all the liquid has vaporized.

Gas section: Once the substance has completely vaporized, the temperature of the gas starts to increase as heat is added. During this section, the energy added is used to increase the kinetic energy of the particles, causing them to move faster and spread apart.

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In foods and drinks, aspartame, a synthetic, non-saccharide sweetener that is 200 times sweeter than sucrose, is frequently used as a sugar replacement.

a. The molar mass of aspartame can be calculated by summing the atomic masses of its constituent elements, which are carbon (C), hydrogen (H), nitrogen (N), and oxygen (O). Therefore,

Molar mass of aspartame = (14 x atomic mass of C) + (18 x atomic mass of H) + (2 x atomic mass of N) + (5 x atomic mass of O)

= (14 x 12.01) + (18 x 1.01) + (2 x 14.01) + (5 x 16.00)

= 294.30 g/mol

Therefore, the molar mass of aspartame is 294.30 g/mol.

b. To determine the number of moles of aspartame present in 1.00 mg of aspartame, we need to use the following formula:

Number of moles = Mass / Molar mass

where Mass is the mass of the substance in grams and Molar mass is the molar mass of the substance in grams per mole.

Converting the given mass of 1.00 mg to grams, we get:

Mass = 1.00 mg = 0.001 g

Using the molar mass calculated in part a, we get:

Number of moles = 0.001 g / 294.30 g/mol = 3.40 x 10^-6 moles

Therefore, there are 3.40 x 10^-6 moles of aspartame present in 1.00 mg of aspartame.

c. To determine the number of molecules of aspartame present in 1.00 mg of aspartame, we need to use Avogadro's number:

Number of molecules = Number of moles x Avogadro's number

where Avogadro's number is 6.02 x 10^23 molecules per mole.

From part b, we know that there are 3.40 x 10^-6 moles of aspartame present in 1.00 mg of aspartame. Substituting this value in the above equation, we get:

Number of molecules = 3.40 x 10^-6 moles x 6.02 x 10^23 molecules per mole

= 2.05 x 10^18 molecules

Therefore, there are 2.05 x 10^18 molecules of aspartame present in 1.00 mg of aspartame.

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Answer:

Unlike protons and neutrons, which are located inside the nucleus at the center of the atom, electrons are found outside the nucleus. Because opposite electric charges attract each other, negative electrons are attracted to the positive nucleus

If 0.01 mol of neon gas at a particular temperature and pressure occupies a volume of 0.225 L, then 0.05 mol of neon gas would occupy a volume of 1.125 L under the same conditions.

Given:

Number of moles of neon gas (n₁) = 0.01 mol

Volume of neon gas (V₁) = 0.225 L

We are required to find the volume of neon gas (V₂) when the number of moles (n₂) is 0.05 mol under the same conditions.

The relationship between the number of moles, volume, and pressure of a gas is given by the ideal gas law: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.

Since the temperature and pressure are the same in this case, we can rearrange the ideal gas law equation to solve for the volume:

V = (n₁ * V₁) / n₂

Substituting the given values into the equation:

V₂ = (0.01 mol * 0.225 L) / 0.05 mol

V₂ = 0.00225 L / 0.05 mol

V₂ = 0.045 L/mol

Therefore, 0.05 mol of neon gas would occupy a volume of 1.125 L under the same conditions.

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Answer:

Temperature and Volume

Explanation:

PV = n R T

P = n R T / V      pressure depends on the temperature and volume

The pressure of a gas depends on the temperature and volume of the gas.

PV = nRT

Where

From the equation given above, we obtained the following:

PV = nRT

Divide both sides by V

P = nRT / V

R is constant and n = 1

P = T / V

Thus, we can see that the pressure (P) is dependent on the temperature (T) and the volume (V)

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To determine the pressure of the ammonia gas at a new volume and temperature, we can use the combined gas law, which states that the ratio of the initial pressure, volume, and temperature is equal to the ratio of the final pressure, volume, and temperature.

Using the combined gas law equation: (P1 * V1) / T1 = (P2 * V2) / T2

Given:

P1 = 585 torr (initial pressure)

V1 = 20.0 ml (initial volume)

T1 = 20.0 °C + 273.15 = 293.15 K (initial temperature)

V2 = 50.0 ml (final volume)

T2 = 50.0 °C + 273.15 = 323.15 K (final temperature)

We need to solve for P2 (final pressure).

Rearranging the equation, we have:

P2 = (P1 * V1 * T2) / (V2 * T1)

Substituting the given values into the equation:

P2 = (585 torr * 20.0 ml * 323.15 K) / (50.0 ml * 293.15 K)

Calculating this expression gives us the final pressure (P2) of the ammonia gas at the new volume and temperature.

In summary, using the combined gas law equation, we can determine the pressure of the ammonia gas at a new volume and temperature. By substituting the given values into the equation and performing the calculation, we can find the final pressure of the gas.

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Answer:

A Single replacement/displacement reaction will occur, making the equation:

Calcium + Lead (II) nitrate → Calcium Nitrate + Lead (II)

Ca + Pb(NO3)2 → Ca(NO3)2 + Pb

Explanation:

Calcium is more reactive than Lead in the reactivity series so theoretically will replace in Lead in Lead Nitrate, forming Calcium Nitrate.

Hopefully this helps!!!

Answer:

The atoms are vibrating in place.

Explanation:

One of the properties of an ionic substance is the possession of a crystalline structure. As Gerry observed the salt under a microscope, he discovered that it has a crystalline structure. Crystalline salts are all ionic in nature, hence the salt observed by Gerry is an ionic salt.

Solids containing a definite crystalline structure always has their particles vibrating in place. This is immediately evident as Gerry looks at the salt through a microscope.

Answer:

D.The atoms are vibrating in place

Explanation:

Answer:

stars,auroras,a neon sign

Explanation:

just did it

i just answered this question and it was actually 1,4,1,2

The freezing point of the solution is -11.8 °C.

The boiling point of the solution is 103.31 °C.

To determine the freezing point of the solution, we can use the equation:

ΔTf = Kf * m

where:

ΔTf is the freezing point depression,

Kf is the cryoscopic constant (for water, Kf = 1.86 °C/m),

m is the molality of the solution (moles of solute per kilogram of solvent).

First, let's calculate the molality (m) of the solution:

Molar mass of ethylene glycol (C2H6O2):

C = 12.01 g/mol

H = 1.01 g/mol (x 6) = 6.06 g/mol

O = 16.00 g/mol (x 2) = 32.00 g/mol

Total molar mass = 12.01 g/mol + 6.06 g/mol + 32.00 g/mol = 50.07 g/mol

Number of moles of ethylene glycol (C2H6O2) = mass / molar mass

Number of moles = 30.8 g / 50.07 g/mol = 0.615 mol

Mass of water = volume x density = 96.6 mL x 1.00 g/mL = 96.6 g

Now, let's calculate the molality:

Molality (m) = moles of solute / mass of solvent (in kg)

Molality = 0.615 mol / 0.0966 kg = 6.36 mol/kg

Now we can calculate the freezing point depression (ΔTf):

ΔTf = Kf * m

ΔTf = 1.86 °C/m * 6.36 mol/kg = 11.8 °C

To find the freezing point of the solution, subtract the freezing point depression from the freezing point of pure water (0 °C):

Freezing point = 0 °C - 11.8 °C = -11.8 °C

To determine the boiling point of the solution, we can use the equation:

ΔTb = Kb * m

where:

ΔTb is the boiling point elevation,

Kb is the ebullioscopic constant (for water, Kb = 0.52 °C/m),

m is the molality of the solution (same value as calculated before: 6.36 mol/kg).

ΔTb = 0.52 °C/m * 6.36 mol/kg = 3.31 °C

To find the boiling point of the solution, add the boiling point elevation to the boiling point of pure water (100 °C):

Boiling point = 100 °C + 3.31 °C = 103.31 °C

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Considering the combined law equation, the new pressure of the sample is 723.81 mmHg.

Boyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant.

This law is expressed mathematically as:

P×V=k

where

Charles' law states that the volume of a gas in a closed container is directly proportional to the temperature of the container, when the temperature is constant.

This law is expressed mathematically as:

V÷T= k

where

Charles' law states that the pressure of a gas in a closed container is directly proportional to the temperature of the container, when the temperature is constant.

This law is expressed mathematically as:

P÷T= k

where

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

(V×P) ÷T= k

Considering an initial state 1 and a final state 2, it is fulfilled:

(V₁×P₁) ÷T₁= (V₂×P₂) ÷T₂

In this case, you know:

Replacing in the definition of combined law equation:

(5 L× 760 mmHg) ÷273 K= (6 L× P₂) ÷312 K

Solving:

[(5 L× 760 mmHg) ÷273 K]× (312 K÷ 6 L)=  P₂

723.81 mmHg= P₂

Finally, the new pressure is 723.81 mmHg.

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The substance in the image above would be classified as a mixture of elements (option E).

A compound is a substance formed by chemical bonding of two or more elements in definite proportions by weight.

On the other hand, a mixture is made when two or more substances are combined, but they are not combined chemically.

According to this question, an image is shown with two different substances or elements as distinguished by coloration (white and purple). These elements are combined but not chemically bonded, hence, is a mixture.

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