A 1-kilogram object is thrown horizontally and a 2-kilogram object is dropped vertically at
the same instant and from the same point above the ground. Which of the following will
be the same for both objects at any given instant?

The instantaneous current at the same moment in the RL circuit can be expressed as I = Imaxsin(150), where Imax represents the maximum current.

1. Given that the instantaneous voltage at a specific moment in the RL circuit is V = Vmaxsin(150).

2. We can express the current at the same moment using Ohm's Law, which states that V = IR, where V is voltage, I is current, and R is resistance.

3. In an RL circuit, the resistance is represented by the symbol R, and it is typically associated with the resistance of the wire or any resistors in the circuit.

4. However, the given equation does not explicitly mention resistance.

5. Since we are considering an RL circuit, it suggests the presence of inductance (L) along with resistance (R).

6. In an RL circuit, the voltage across the inductor (VL) can be expressed as VL = L(di/dt), where L is the inductance and di/dt represents the rate of change of current.

7. At any given instant, the total voltage across the circuit (V) can be expressed as the sum of the voltage across the resistor (VR) and the voltage across the inductor (VL).

8. Therefore, V = VR + VL.

9. Since the given equation represents the instantaneous voltage (V), we can deduce that V = VR.

10. By comparing V = VR with Ohm's Law (V = IR), we can conclude that I = Imaxsin(150), where Imax represents the maximum current.

The specific values of Vmax, Imax, and the phase angle have not been provided in the question, so we are working with the general expression.

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Given the mass of the cell is 1 * 10⁻¹⁴ kg, the number of cells in the 65 kg person is  6.5 * 10¹⁵  cells.

The number of cells in a human is calculated as follows:

The mass of an average cell is ten times the mass of a bacterium.

The mass of a bacterium = 1 * 10⁻¹⁵ kg

mass of an average cell = 10 *  1 * 10⁻¹⁵ kg =  1 * 10⁻¹⁴ kg

Number of cells = mass of person/mass of cell

Number of cells = 65 kg/1 * 10⁻¹⁴ kg

Number of cells = 6.5 * 10¹⁵  cells.

In conclusion, the number of cells is obtained by dividing the mass of the person by the mass of a average cell.

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Note that the complete question is given below:

Assuming the mass of an average cell is ten times the mass of a bacterium (which is 10⁻¹⁵ kg): Calculate the number of cells in a human assuming the mass of the person is 10² kg.

The maximum displacement = 0.0189 m

The Total energy of the system = 1.188 J

The Gravitational potential energy = 0.22 J

Let m be = Mass of the object = 1.2 kg

As given K = Spring Constant of the spring = 300 N/m

Let v denote = Maximum speed with which the body oscillates = 30 cm/s

Let 'x' be the maximum displacement of the body

x²= mv²/k=1.2* 0.3 /300= 0.0189

Total energy= kinteric energy+potential energy =kx²/2 + mv²/2

=1.188J

The Gravitational potential energy of the system is

E=Mgx=1.2*9.8*0.0189

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The 1.2 kg object's maximum displacement when it is suspended from a spring with a 300 N/m force constant oscillates at a maximum speed of 30 cm/s. This displacement is equal to 0.0189 m.

When the object is displaced to its maximum, the system's total energy is 1.188 J.

The energy of gravity is equal to 0.22 J.

Allow m to be equal to 1.2 kg, the object's mass.

K = Spring as stated. Springs have a constant of 300 N/m.

the body can oscillate at a maximum speed of 30 cm/s (let v signify this).

Suppose that "x" represents the body's largest displacement.

x²= mv²/k=1.2* 0.3 /300= 0.0189

Total energy = interstellar energy + potential energy = kx2/2 + mv2/2

=1.188J

According to the system's gravitational potential energy,

E=Mgx=1.2*9.8*0.0189

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Answer:

There is more to motion than distance and displacement. Questions such as, “How long does a foot race take?” and “What was the runner’s speed?” cannot be answered without an understanding of other concepts. In this section we will look at time, speed, and velocity to expand our understanding of motion.

A description of how fast or slow an object moves is its speed. Speed is the rate at which an object changes its location. Like distance, speed is a scalar because it has a magnitude but not a direction. Because speed is a rate, it depends on the time interval of motion. You can calculate the elapsed time or the change in time, Δt, of motion as the difference between the ending time and the beginning time

The SI unit of time is the second (s), and the SI unit of speed is meters per second (m/s), but sometimes kilometers per hour (km/h), miles per hour (mph) or other units of speed are used.

When you describe an object's speed, you often describe the average over a time period. Average speed, vavg, is the distance traveled divided by the time during which the motion occurs.

vavg=

distance

time

You can, of course, rearrange the equation to solve for either distance or time

time =

distance

vavg

.

distance = vavg × time

Suppose, for example, a car travels 150 kilometers in 3.2 hours. Its average speed for the trip is

vavg =

distance

time

=

150 km

3.2 h

47 km/h.

A car's speed would likely increase and decrease many times over a 3.2 hour trip. Its speed at a specific instant in time, however, is its instantaneous speed. A car's speedometer describes its instantaneous speed.

Explanation:

Answer:

obj A is making a parabolic path whereas object B is moving in a straight path . on going further the position of object A decreases whereas the position of object B goes on increasing

The Tension of the string is going to be less when submerged in water by a value called the buoyancy force, so below in the attached file is explanation on how to calculate the apparent weight and density of the submerged object

El lanzamiento de proyectiles permite calcular el angulo de lanzamiento o elevación  para alcanzar el objetivo es:  9.3º

El lanzamiento de proyectiles es una aplicación de la cinemática donde en el eje x ( horizontal) no hay aceleración y el el eje y (vertical) con sentido positivo hacia arriba tiene la aceleración de la gravedad.

El rango de lanzamiento de proyectiles es la distancia horizontal recorrida para la misma altura inicial.

               \(R = \frac{vo^2 sen 2 \theta}{g}\)  

Donde R es el alcance, v₀ la velocidad inicial, θ el angulo de lanzamiento o elevación y g la aceleración de la gravedad.

             sen 2θ =  \(\frac{gR}{vo^2 }\)

             2θ = sen⁻¹ \(\frac{gR}{vo^2}\)  

calculemos

              2θ = sin⁻¹ ( \(\frac{9.8 \ 4000}{350^2 }\) )

              θ =  18,662 /2

              θ =  9.3º

En conclusion usando el lanzamiento de proyectiles podemos calcular el angulo de lanzamiento para alcanzar el objetivo es:  9.3º

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The net force on particle q2 is a positive force pointing to the right.

To determine the net force on particle q2, we need to calculate the individual forces exerted on q2 by q1 and q3 and then add them vectorially.

The force between two charged particles can be calculated using Coulomb's law, which states that the force (F) between two charged particles is directly proportional to the product of their charges (q1 and q2) and inversely proportional to the square of the distance (r) between them:

F = k * (|q1| * |q2|) / r^2

where k is the electrostatic constant.

Given:

q1 = +8.0 μC

q2 = +3.5 μC

q3 = -2.5 μC

Distance between q1 and q2 (r12) = 0.10 m

Distance between q2 and q3 (r23) = 0.15 m

First, let's calculate the force between q1 and q2:

F12 = k * (|q1| * |q2|) / r12^2

Substituting the values:

\(F12 = (9 \times 10^9 N m^2/C^2) * ((8.0 \times 10^-6 C) * (3.5 \times 10^-6 C)) / (0.10 m)^2\)

Calculating the force F12 will give us the magnitude of the force between q1 and q2. However, since q1 and q2 have the same charge sign, the force will be repulsive, pointing to the right.

Next, let's calculate the force between q2 and q3:

\(F23 = k * (|q2| * |q3|) / r_{23}^2\)

Substituting the values:

F23 = (9 x 10^9 N m^2/C^2) * ((3.5 x 10^-6 C) * (2.5 x 10^-6 C)) / (0.15 m)^2

Calculating the force F23 will give us the magnitude of the force between q2 and q3. Since q2 and q3 have opposite charge signs, the force will be attractive, pointing to the left.

To find the net force on q2, we need to subtract the force F23 from F12 since they act in opposite directions:

Net force on q2 = F12 - F23

Finally, we need to consider the direction of the forces. Since F12 is repulsive (positive) and F23 is attractive (negative), the net force on q2 will be positive, pointing to the right.

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Answer:

(42/100) (25)=area

10.5 m^2 = area

The magnitude of the vector is approximately 35.85 m.

The angle that this vector makes with the positive x-axis is approximately 32 degrees.

To find the magnitude of the vector with components Ax=29 m and Ay=18 m, we use the Pythagorean theorem:

|A| = √(Ax^2 + Ay^2)

|A| = √(29^2 + 18^2)

|A| = √(841 + 324)

|A| = √1165

|A| =  34.13 m

To find the angle that this vector makes with the positive x-axis, we can use the inverse tangent function:

θ = tan^-1(Ay/Ax)

θ = tan^-1(18/29)

θ = 31.82 degrees

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The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.

The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.

Initially, the capacitor is uncharged, so the second term is zero.

Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.

When the magnetic field is switched on, a current begins to flow in the solenoid.

This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.

Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.

The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.

Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.

This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.

The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)

The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)

The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)

This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.

The solution is t = 1.74 ms.

The units are in seconds.

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According to the description provided, it seems that Serena is achieving generativity through the variation of generativity known as "generativity in work."

Generativity in work refers to the ability to find meaning and purpose in one's work, and to contribute to the betterment of society through that work.

Serena's work as a genealogist at the local historical society is a clear example of this, as she is helping people connect with their roots and understand their family history, which can be a powerful source of meaning and identity.

Additionally, her work is preserving and sharing important historical information, which contributes to the community's understanding of its past and can inform decisions about the future.

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the acceleration of the more massive box is = F/3M.

This equation a = v/t denotes acceleration (a), which is the velocity that changes (v) over the time period (t).

The three main types of accelerated motions are uniform acceleration, quasi acceleration, and average acceleration.The motion in which an item moves inside a straight line while increasing in velocity at regular intervals is referred to as uniform acceleration.

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A fox getting its energy from a mouse and a mouse getting its energy from the grass  shows evidence of the carbon cycle

The carbon cycle is a necessary component within the global interchange between living species and the environment.

Through photosynthesis, plants absorb carbon dioxide from the atmosphere and convert it into vitalizing organic matter for consumption by animals; these organisms expend the energy obtained and consequently expel carbon dioxide back up into the air via respiration.

Moreover, when animals meet their demise and decompose, the carbon in their bodies is redeposited into Earth's soil only to eventually be delivered once again to the atmosphere through erosive activities or those generated from volcanoes.

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Answer:

A. Coefficient of kinetic friction, μ = 0.34

B. The box moves a distance of 9.64 m before coming to a stop

C. The heavier box will stop after 2.1 seconds

Explanation:

a. The coefficient of kinetic or sliding friction is given as: μ = F/R

where applied force, F = m × (∆v)/t

∆v = v - u

∆v = 0 - 8 m/s = -8 m/s; t = 2.4 s

R = normal reaction = m×g

where g = 9.8 m/s²

Substituting in the kinetic friction formula; μ = m∆v/t ÷ 1/m×g

μ = ∆v/g×t

μ = 8 / 9.8 × 2.4

μ = 0.34

b. Using the equation v² = u² + 2as to calculate the distance travelled by the box

where v = 0 m/s; u = 8.0 m/s; a = ? s = ?

From F = ma = μR

a = μR/m = (μ × m × g)/m

a = μg

a = 0.34 × 9.8

a = 3.32 m/s²

This is negative acceleration or deceleration

Substituting in the equation of motion

8² + 2 × -3.32 × s = 0

-6.64s = -64

s = 9.64 m

Therefore, the box moves a distance of 9.64 m before coming to a stop

c. The coefficient of friction is independent of mass.

Using the formula in (a): μ = ∆v/g×t

t = ∆v/μg

t = 7/0.34 × 9.8

t = 2.10 s

Therefore, the heavier box will stop after 2.1 seconds

The  coefficient of kinetic friction of the box is 0.34.

The distance traveled by the box is 9.6 m.

The time taken for the heavier box to stop is 2.1 s.

The  coefficient of kinetic friction of the box is calculated as follows;

\(\mu mg = ma\\\\\mu g = a\\\\\mu g = \frac{v}{t} \\\\\mu = \frac{v}{gt} \\\\\mu = \frac{8}{9.8 \times 2.4} \\\\\mu = 0.34\)

The distance traveled by the box is calculated as follows;

\(v^2 = u^2 + 2as\\\\2as = -u^2\\\\s = \frac{-u^2}{2a} \\\\s = \frac{-u^2}{2\mu g} \\\\s = \frac{-(8)^2}{2\times 0.34 \times 9.8} \\\\s = -9.6 \ m\\\\|s| = 9.6 \ m\)

The time taken for the heavier box to stop is calculated as;

\(\mu = \frac{v}{gt} \\\\t = \frac{v}{\mu g} \\\\t = \frac{7}{0.34 \times 9.8}\\\\ t = 2.1 \ s\)

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The total momentum of the system is 2.14i + 21.27j.

A vector quantity with both direction and magnitude is momentum. Kg m/s (kilogram meter per second) or N s serve as its units (newton second).

The total starting momentum of a system must match the entire final momentum of the system since momentum is a conserved quantity. The overall momentum does not change.

The total momentum of the system is defined as follows:

As momentum is vector quantity and vectors can be added, so, the momentum of a system is given by

P = Pₓ + P'

where Pₓ is the x-component of momentum

P' is the y-component of the momentum

Also, we know that

P=mv

where m is mass

v is velocity

Thus,

P = Pₓ + P'

P = m₁vₓ + m₂v'

vₓ is the x-component of the velocity

v' is the y- component of the velocity

Given, m₁= 3.2kg

m₂ = 2.9kg

Now,

P = 3.2 (2.3i + 4.2j) + 2.9 (-1.8i +2.7j)

P = (7.36i + 13.44j) + (-5.22i + 7.83j)

P = 2.14i + 21.27j

Thus, the total momentum of the given system is 2.14i + 21.27j.

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Answer:

The total surface area of the seven little spheres is 1.91 times the total surface area of the bigger sphere.

Explanation:

Volume of a Sphere

The volume of a sphere of radius r is given by:

\(\displaystyle V=\frac{4}{3}\cdot \pi\cdot r^3\)

The volume of each little sphere is:

\(\displaystyle V_l=\frac{4}{3}\cdot \pi\cdot 2^3\)

\(V_l=33.51\ mm^3\)

When the seven little spheres coalesce, they form a single bigger sphere of volume:

\(V_b=7*V_l=234.57\ mm^3\)

Knowing the volume, we can find the radius rb by solving the formula for r:

\(\displaystyle V_b=\frac{4}{3}\cdot \pi\cdot r_b^3\)

Multiplying by 3:

\(3V_b=4\cdot \pi\cdot r_b^3\)

Dividing by 4π:

\(\displaystyle \frac{3V_b}{4\cdot \pi}= r_b^3\)

Taking the cubic root:

\(\displaystyle r_b=\sqrt[3]{\frac{3V_b}{4\cdot \pi}}\)

Substituting:

\(\displaystyle r_b=\sqrt[3]{\frac{3*234.57}{4\cdot \pi}}\)

\(r_b=3.83\ mm\)

The surface area of the seven little spheres is:

\(A_l=7*(4\pi r^2)=7*(4\pi 2^2)=351.86\ mm^2\)

The surface area of the bigger sphere is:

\(A_b=4\pi r_b^2=4\pi (3.83)^2=184.33\ mm^2\)

The ratio between them is:

\(\displaystyle \frac{351.86\ mm^2}{184.33\ mm^2}=1.91\)

The total surface area of the seven little spheres is 1.91 times the total surface area of the bigger sphere.

I apologize, but I can't help with the specific calculations you've provided. Calculating forces and friction coefficients requires specific numerical values and equations. However, I can explain the concepts and provide a general understanding of the questions you've asked.

3.1 To calculate the magnitude of the force exerted by the athlete vertically on the track, you need the vertical component of the force applied. If the angle of 50° is measured from the horizontal, you can calculate the vertical component using the equation: horizontal force = force × sin(angle).

3.2 To calculate the magnitude of the force exerted by the athlete horizontally on the track, you need the horizontal component of the force applied. Using the same angle of 50° measured from the horizontal, you can calculate the horizontal component using the equation: vertical force = force × cos(angle).

3.4 To determine the minimum value of the static friction coefficient, you would need additional information such as the mass of the athlete. In addition, you would need the normal track force. The coefficient of static friction is a dimensionless value that represents the maximum frictional force that can exist between two surfaces without causing them to slip. The formula to calculate static frictional force is static frictional force = coefficient of static friction × normal force.

3.5 To determine the resultant force exerted on an object when three forces are applied, you need to calculate the vector sum of the forces. You can add forces vectorially by breaking them down into their horizontal and vertical components. You can also sum up the components separately, and then combine them to find the resultant force.

Please provide more specific numerical values or equations if you would like assistance with the calculations.

The masses of the two objects MA and MB in the binary system are 4 Mo respectively.

The masses of binary systems can be calculated using Kepler's laws of planetary motion and observations of the system.

Let's denote the masses of the two objects as MA and MB, where MA is the mass of object A and MB is the mass of object B. We know that the total mass of the binary system is 8 Mo, so:

MA + MB = 8 Mo

We also know that the ratio of the distances between the two objects is 1/3. Let's denote the distance between the two objects as d, so we have:

d(A to B) / d(Binary System) = 1/3

We can simplify this equation by using the fact that the distances between the objects and the binary system add up to the total distance between the objects:

d(A to B) + d(B to binary system) = d(Binary system)

Since we know the ratio of the distances, we can substitute 1/3d for d(B to binary system):

d(A to B) + 1/3d = d(Binary system)

3d(A to B) + d = 3d(Binary system)

Substituting d(A to B) for d(Binary system) - d(B to binary system), we get:

3d(A to B) + d = 3(d(A to B) + d(B to binary system))

2d(A to B) = 2d(B to binary system)

d(A to B) / d(B to binary system) = 1

So the two objects are at the same distance from the binary system center of mass. This means that the masses of the two objects are equal:

MA = MB

Substituting this into the first equation, we get:

2MA = 8 Mo

MA = MB = 4 Mo

Therefore, the mass of each object is 4 Mo.

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Answer: 1.02 N/m

Explanation:

To find the spring constant k, we can use Hooke's Law, which states that the force exerted by a spring (F) is proportional to the displacement from its equilibrium position (x). The equation for Hooke's Law is:

F = kx

In this case, the force exerted by the spring (F) is equal to the weight of the mass (mg). The problem provides the weight (63 N) and the displacement (61 m). We can rearrange the equation to solve for k:

k = F/x

Now, we can plug in the given values:

k = (63 N) / (61 m)

k ≈ 1.032 N/m

Rounded to two decimal places, the spring constant k is approximately 1.02 N/m.

The perception that seems infertile couples who adopt a child are generally more likely to conceive a progeny themselves best describes an illusory correlation.

Illusory correlation when we overexcite to one outcome and ignore the other. In psychology, it states that the relationship between the variables, even such a relation does not exist.

In the given passage couples who adopt a child are subsequently more likely to conceive a child themselves best explains, suggesting the illusory correlation.

Therefore, this passage suggests an illusory correlation.

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Answer:

The answer is electromagnetic

Answer:

electromagnetic

Explanation:

edge 2021

Answer:

K = 1800 kJ

Explanation:

Given that,

The speed of the object, v = 30 m/s

Mass of the object, m = 4000 kg

We need to find the kinetic energy of the object. The formula for the kinetic energy is given by :

\(K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 4000\times 30^2\\\\K=1800000\\\\or\\\\K=1800\ kJ\)

So, the required kinetic energy is equal to 1800 kJ.

Explanation:

the sum of two or more vector is resultant vector.

Considering the Coulomb's Law, the magnitude of the charge on each particle is 4.2426 C.

Coulomb's law or law of electrostatics is the relationship between the interactions of electric charges, that is, it explains the force experienced by two electric charges at rest.

This law says that the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them, expressed mathematically as:

\(F=k\frac{Qq}{d^{2} }\)

where:

The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.

In this case, you know that:

Replacing in the Coulomb's Law:

\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{Qq}{(0.3 m)^{2} }\)

Being Q=q:

\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{q^{2} }{(0.3 m)^{2} }\)

Solving:

1.8×10⁻⁸ N÷ 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\)= q²÷ (0.3 m)²

2×10⁻¹⁸ C²/m²= q²÷ (0.3 m)²

2×10⁻¹⁸ C²/m²= q²÷ 0.09 m²

2×10⁻¹⁸ C²/m² ×0.09 m²= q²

1.8×10⁻¹⁹ C²= q²

√1.8×10⁻¹⁹ C²= q

4.2426 C= q= Q

Finally, each charge has a value of 4.2426 C.

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Walrus' kinetic energy = 2.05 x \(10^6\) J.

To calculate the walrus' kinetic energy,

we need to use the formula KE = 0.5\(mv^2\), where m is the mass of the walrus and v is its velocity.

We know the mass of the walrus is 907 kg and its velocity is 23 m/s.

Substituting these values in the formula, we get KE = 0.5 x 907 x \((23)^2\) = 2.05 x\(10^6\) J.

Therefore, the walrus' kinetic energy is 2.05 x \(10^6\) J.

It is important to note that kinetic energy is the energy an object possesses due to its motion, and is directly proportional to both its mass and velocity.

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Answer:

Explanation:

To find the distance covered by the car after it applied brakes, we use 3rd equation of motion.

2as = Vf² - Vi²

s = (Vf² - Vi²)/2a

1.

We have:

Vi = Initial Velocity = 5 m/s

Vf = Final Velocity = 0 m/s    (Since, car finally stops)

a = deceleration = - 2 m/s²

s = distance covered by the car = ?

Therefore,

s = [(0 m/s)² - (5 m/s)²]/2(- 2 m/s²)

s = 6.25 m

2.

We have:

Vi = Initial Velocity = 10 m/s

Vf = Final Velocity = 0 m/s    (Since, car finally stops)

a = deceleration = - 2 m/s²

s = distance covered by the car = ?

Therefore,

s = [(0 m/s)² - (10 m/s)²]/2(- 2 m/s²)

s = 25 m

Hence, the distance traveled by the car is affected by the initial speed in accordance with a direct relationship.

Answer:

the bubble appears DARK

Explanation:

This problem shows the interference by reflection of light on the surface, let's take it into account;

* There is a phase change of 180º on the surface when it stops from a lower medium to a higher index

* Within the film the wavelength changes due to the fraction index

           \(\lambda_n = \frac{\lambda_o}{n}\)

if we plug this into the expression for constructive interference we have

       2tn = (m + ½) λ₀

for destructive interference it is

       2tn = m λ₀

apply these expressions to our case

indicate that the incident wavelength is red λ₀ = 700 nm

Let's find the minimum thickness that the film must have to have a constructive interference

the refractive index of soap is n = 1.4

from the constructive interference equation

            t = (0+ ½) 700 10⁻⁹ / 2 1.4

            t = 1.25 10⁻⁷ m

just before the soap bubble explodes the thickness (t) of the film less than the calculated value there is no possibility of constructive interference, therefore the bubble appears DARK