Can someone please help me with this

The probability of having an error when confidence limits are 3 standard deviations far from the mean is approximately 0.27.

Assume that the data is normally distributed. For a normal distribution, approximately 99.7% of the data is within 3 standard deviations of the mean.

As a result, if the lower and upper specification limits are 3 standard deviations away from the mean, they encompass 99.7% of the data.

As a result, there is only a 0.3% chance of an error. Since this is a two-tailed test, the probability of an error on each side is 0.15%

As a result, the probability of an error when the lower and upper specification limits are 3 standard deviations away from the mean is approximately 0.27.

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Answer:

y = 2

Step-by-step explanation:

-2y + 1 = y-5

-2 - y = -5 - 1

-3y = -6

y = -6 ÷ -3

y = 2

The surface area of solid B is 1024 cm².

If the solids A and B are mathematically similar, it means that their corresponding sides are in proportion, including their volumes and surface areas.

Given that the ratio of the volume of A to the volume of B is 125:64, we can express this as:

Volume of A / Volume of B = 125/64

Let's assume the volume of A is V_A and the volume of B is V_B.

V_A / V_B = 125/64

Now, let's consider the surface area of A, which is given as 400 cm².

We know that the surface area of a solid is proportional to the square of its corresponding sides.

Surface Area of A / Surface Area of B = (Side of A / Side of B)²

400 / Surface Area of B = (Side of A / Side of B)²

Since the solids A and B are mathematically similar, their sides are in the same ratio as their volumes:

Side of A / Side of B = ∛(V_A / V_B) = ∛(125/64)

Now, we can substitute this value back into the equation for the surface area:

400 / Surface Area of B = (∛(125/64))²

400 / Surface Area of B = (5/4)²

400 / Surface Area of B = 25/16

Cross-multiplying:

400 * 16 = Surface Area of B * 25

Surface Area of B = (400 * 16) / 25

Surface Area of B = 25600 / 25

Surface Area of B = 1024 cm²

As a result, solid B has a surface area of 1024 cm2.

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Answer:

6:05 is the answer it should be obvious

A continuous variable does allow fractional amounts. a discrete variable  does not allow fractional amounts.

Which variables require boundaries, also known as real limits, in their measurement scales?

A researcher must utilize genuine limits, which are boundaries that are exactly halfway between adjacent categories, to specify the units for a continuous variable.

What distinguishes a ratio scale from an ordinal scale?

For continuous data, what kind of data would you use?

Line graphs, skews, and other data analysis techniques are used to measure continuous data. One of the most popular kinds of continuous data analysis is regression analysis.

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Answer:

\(\left[\begin{array}{ccc}8&2&3\\6&-5&1\\1&8&4\end{array}\right]\)

Step-by-step explanation:

To find the transpose all we do is change the rows into the columns and change the columns into rows.

So simply:

\(\left[\begin{array}{ccc}8&2&3\\6&-5&1\\1&8&4\end{array}\right]\)

Answer:

Flip the elements around, aka, transpose!

[8 2 3]

[6 -5 1]

[1 8 4]

Answer:

SSS I believe sorry if im wrong

Step-by-step explanation:

Answer:

Probability = \(\frac{22}{31}\)

Step-by-step explanation:

Number of students working part time, living in dorm = 22

Total number of students working part (either living in dorm or not in dorm)

= 22 + 9

= 31

Probability of the students working part time and living in dorm,

P = \(\frac{\text{Favorable event}}{\text{Total outcomes}}\) = \(\frac{\text{Students working part time either living in dorm}}{\text{Total number of students working part time either living in dorm or not}}\)

P = \(\frac{22}{31}\)

Therefore, probability of the students chosen that he/she is working part time given that he/she lives in dorm is \(\frac{22}{31}\).

Answer:

\(x = 5\)

Step-by-step explanation:

\( {2}^{2x - 3} + 52 = 180\)

\( {2}^{2x - 3 } = 128\)

\( {2}^{2x - 3} = {2}^{7} \)

\(2x - 3 = 7\)

\(2x = 10\)

\(x = 5\)

\(~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{-7}~,~\stackrel{y_1}{5})\qquad B(\stackrel{x_2}{4}~,~\stackrel{y_2}{-9})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AB=\sqrt{[4 - (-7)]^2 + [-9 - 5]^2}\implies AB=\sqrt{(4+7)^2+(-14)^2} \\\\\\ AB=\sqrt{121+196}\implies AB=\sqrt{317}\)

Using the relation between velocity, distance and time, we have that:

Velocity is distance divided by time, that is:

s = d/t.

For this problem, the parameters are:

d = 50, t = 24.76.

Hence:

s = d/t

s = 50/24.76

s = 2.02 yd/sec.

Then:

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Answer:

Check below please.

Step-by-step explanation:

Hi,

Let's plot the figure, 1 square and 2 equilateral triangles.

1) Let's remember all the angles we already know, from the square and the equilateral triangle from their respective definition.

In other words:

Statement                               Reason                          

\(\angle A=\angle B=\angle C=\angle D=90^{\circ}\)   Given

\(\bigtriangleup AED \cong \bigtriangleup BFC\)                     \(\overline{AE}\cong \overline{AD}\cong \overline{ED} \:and\: A\widehat{E}D\cong A\widehat{D}E\cong D\widehat{A}E=60^{\circ}\\\overline{BF}\cong \overline{FC}\cong \overline{BC} \:and\: A\widehat{E}D\cong A\widehat{D}E\cong D\widehat{A}E=60^{\circ}\\\)

2) We have two triangles ABF and CDE

\(\bigtriangleup ABF, \:and \bigtriangleup CDE \\A\widehat{B}F=C\widehat{D}E=90^{\circ}+60^{\circ}=150^{\circ}\)

3) The Side, Angle Side Congruence Theorem assures us that both triangles are congruent. When there are two known legs (4 cm and 4 cm) of each  triangle, and their respective formed angle is also known (150º). Therefore, these two triangles are both congruent.

Statement                                                   Reason

\(\overline{DE}\cong \overline{DC} \cong\:\overline{AB}\cong \:\overline{BF} \:and \:C\widehat{D}E \cong A\widehat{B}F\)  \(SAS \:Theorem\)

Answer:

425

Step-by-step explanation:

Applying exponential properties, we have that the solution to the given expression is:

\(-\frac{125}{343}\)

When a fraction is elevated to the exponent, we apply the exponent to both the numerator and the denominator.

In this problem, we have that:

Negative base with odd exponent, hence the solution is negative and given as follows:

\(-\frac{125}{343}\)

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Interest groups facilitate citizen participation in governance by mobilizing people to take collective action through voting, fundraising, and informing the public and elected officials about their issues.

Higher Placement The College Board's Advanced Placement Program makes a college-level course and exam in United States Government and Politics available to high school students.

By organizing people to take collective action through voting, fundraising, and informing the public and elected officials about their issues, interest groups enable citizen participation in governance.

a group of individuals united by a shared interest or objective and working to sway public policy. group leaders. As adolescents gain knowledge, they frequently form their own groups. government.

Therefore, interest groups facilitate citizen participation in governance by mobilizing people to take collective action through voting, fundraising, and informing the public and elected officials about their issues.

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Answer:

Option a is the correct answer

Step-by-step explanation:

\( \huge( \sqrt[x]{2})^{ - 1} = {2}^{ - \frac{1}{x} } \)

Answer:

x goes up 1 and f(x) is subtracting 3

Answer:

multiply the probability of the first event by the second.

Step-by-step explanation:

Use the specific multiplication rule formula. Just multiply the probability of the first event by the second. For example, if the probability of event A is 2/9 and the probability of event B is 3/9 then the probability of both events happening at the same time is (2/9)*(3/9) = 6/81 = 2/27.

Answer:

\(\frac{1}{26} * \frac{1}{26} = \frac{1}{676} = .00148.\)

Step-by-step explanation:

Multiply the probability of P by the probability of Q.

In which the probability of P is equal to \(\frac{R}{Total NumberOf LettersInAlphabet} = \frac{1}{26}\)

In which the probability of Q is equal to \(\frac{P}{Total NumberOf LettersInAlphabet} = \frac{1}{26}\)

There's a 1 in 676 chance that you'd randomly pick R, put the tile back in, and then pick P in a sack of 26 letters of the latin alphabet.

Therefore , the solution of the given problem of equation comes out to be  y = 23.78t - 5t²

An equation is a mathematical formula that connects two assertions using the equal sign (=) to denote equivalence. In algebra, an equation is a mathematical statement that establishes the equivalence of two mathematical expressions. For instance, an equal sign separates the components 3x + 5 and 14 in the equation 3x + 5 = 14. A mathematical formula is used to explain the connection between two sentences on either side of a letter. Frequently, there is just one variable, which is also the symbol. for example, 2x - 4 = 2.

Here,
Given :parametric equation

x be the speed of water

t be the time

v be the speed of dolphin

=> x = (vcosx)t +x₀

=> v = 32

=> x = 48

=> x = (32 X cos 48)t + 0

=> x = 21.41t

thus,

=>  y = (vsintx)t - 1/2gt² + y₀

=>   y₀ = 0

=>  v = 32

=> x = 48

=> g = 10

=> y = (32sin48)t -1/2 *10*t² +0

=>  y = 23.78t - 5t²

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If 1472cm² of wrapping paper is needed to cover the smaller box, approximately 1672cm² of wrapping paper is needed to cover the larger box (assuming the surface area is directly proportional to the length).

Since the smaller and larger boxes have exactly the same shape, we can assume that their dimensions are proportional.

Let's denote the width and height of the smaller box as "w" and "h," respectively, and the width and height of the larger box as "W" and "H," respectively.

We know that the length of the smaller box is 16 cm, so we have:

Length of smaller box = 16 cm

Width of smaller box = w

Height of smaller box = h

To find the dimensions of the larger box, we can set up a proportion based on the lengths of the boxes:

16 cm / 18 cm = w / W

From this proportion, we can solve for W:

\(W = (18 cm \times w) / 16 cm\)

Now, let's consider the surface area of the boxes.

The surface area of a box is given by the sum of the areas of its six faces. Since the boxes have the same shape, the ratio of their surface areas will be equal to the square of the ratio of their lengths:

Surface area of smaller box / Surface area of larger box = (16 cm / 18 cm)^2.

We know that the surface area of the smaller box is 1472 cm^2, so we can set up the equation:

\(1472 cm^2\) / Surface area of larger box \(= (16 cm / 18 cm)^2\)

To find the surface area of the larger box, we rearrange the equation:

\(Surface $area of larger box = 1472 cm^2 / [(16 cm / 18 cm)^2]\)

Now we can substitute the value of W into the equation to find the surface area of the larger box:

Surface area of larger box \(= 1472 cm^2 / [(16 cm / 18 cm)^2] = 1472 cm^2 / [(18 cm \times w / 16 cm)^2]\)

\(= 1472 cm^2 / [(18 \times w / 16)^2] = 1472 cm^2 / [(9w / 8)^2]\)

\(= 1472 cm^2 / [(81w^2 / 64)]\)

Simplifying further:

Surface area of larger box \(= (1472 cm^2 \times 64) / (81w^2)\)

So the amount of wrapping paper needed to cover the larger box is given by the surface area of the larger box, which is:

\((1472 cm^2 \times 64) / (81w^2)\)

Note that we don't have enough information to calculate the exact value of the wrapping paper needed to cover the larger box since we don't know the width "w" of the smaller box.

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Step-by-step explanation:

multiply 5x+2y=19 by 3 youll get 15x+6y=57

eliminate y

7x-6y=9

15x+6y=57 +

22x=66

x=3

substitute x to 5x+2y=19

15+2y=19

2y=4

y=2

Answer:

$19.50

Step-by-step explanation:

(26÷100)75=19.50

The sum of the geometric series infinity ∑ (n = 0) (x - 5)ⁿ / 6ⁿ is {6 / (1 - x)}.

What is geometric series?

A geometric series in mathematics is made up of an unlimited number of terms with a fixed ratio between them.

As per data given,

The geometric series is infinity ∑ (n = 0) (x - 5)ⁿ / 6ⁿ

Rewrite geometric series,

infinity ∑ (n = 0) (x - 5)ⁿ / 6ⁿ = infinity ∑ (n = 0) {(x - 5)/6}ⁿ

Common ratio is r = (x - 5)/6

We know a geometric series converges when the radius is less than 1, so we have

I r I = I (x - 5)/6 I < 1

I x - 5 I < 6

-6 < x - 5 < 6

-1 < x < 11

Therefore, the series converges on ( -1, 11)

The sum of the series is, by using the formula {a / 1 - r}.

Substitute values in formula respectively,

a / 1 - r = 1 / {1 - (x - 5)/6}

           = 6 / {6 - (x - 5)}

           = 6 / (1 - x)

Hence, the sum of the geometric series infinity ∑ (n = 0) (x - 5)ⁿ / 6ⁿ is {6 / (1 - x)}.

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Answer:

In a rhombus, all sides are equal. Therefore, you can set WV (s+12) and UV (3s) equal to each other.

s+12 = 3s

Subtract s from both sides, so the variables are all on one side.

12 = 2s

Divide both sides by 2 to isolate the variable.

6 = s

UV = 3s

UV = 3(6)

UV = 18

Answer:

sxqdwbvgefccsgcvnevn veb ehev ev nnmb

Step-by-step explanation:

Answer:

Disconformity.

Nonconformity.

Angular unconformity.

Paraconformity.

Buttress unconformity.

Blended unconformity.

Step-by-step explanation:

There are all the Non-conformities so pick the odd one that doesn't have these