The standard free-energy change for the reaction H₂(g) + Br₂(l) → 2HBr(g) at 25°C can be calculated using the equation ΔG° = ΔH° - TΔS°, where ΔH° is the standard enthalpy change, T is the temperature, and ΔS° is the standard entropy change.
To calculate the standard free-energy change for the reaction H₂(g) + Br₂(l) → 2HBr(g) at 25°C, you need to use the equation: ΔG° = ΔH° - TΔS°. Follow these steps:
1. Determine the standard enthalpy change (ΔH°) for the reaction.
2. Determine the standard entropy change (ΔS°) for the reaction.
3. Calculate ΔG° using the equation and the given temperature (25°C = 298.15 K).
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What kind of intermolecular forces act between a hydrogen molecule and an argon atom? a. Dipole-dipole interaction
b. Interaction c. Hydrogen-bonding d. Dispersion forces e. lon-dipole interaction
The kind of intermolecular forces that act between a hydrogen molecule and an argon atom is dispersion forces (option D).
Intermolecular forces are the attractive forces that act between molecules or atoms. The strength of these forces determines the physical properties of substances such as boiling points, melting points, and solubility. The five main types of intermolecular forces are: Dispersion forcesDipole-dipole interactionsHydrogen bondingIon-dipole interactionsIn the given case, a hydrogen molecule is a nonpolar molecule consisting of two hydrogen atoms sharing electrons equally between them. An argon atom is also a nonpolar atom because it has a complete octet of electrons and no permanent dipole moment.
Therefore, the only intermolecular force that can act between them is the dispersion force. Dispersion forces are caused by temporary dipoles that are induced in nonpolar molecules or atoms when they come close to each other. These temporary dipoles cause the electron distribution in adjacent molecules or atoms to become distorted, leading to a weak attraction between them. Since hydrogen molecules and argon atoms are both nonpolar, they experience dispersion forces when they come close to each other. Hence, option D is the correct answer.
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i got more for everyone
Answer:
d is the answer o(kkkkkkkkkkkkkkk
What is the resistance of a 20.0-m-long piece of 12-gauge copper wire having a 2.053-mm diameter?
The resistance of the copper wire is 0.1039 Ω.
In calculating the resistance of a wire, the formula below can be used.
Resistance = (Resistivity*Length of wire)/(Cross-section Area)
The resistivity of copper wire is 1.72 x 10-8 Ωm. The length of the wire is 20.0 m and the area of the wire is 3.3103x10-6 square meters. The area of the wire is calculated by using the formula below.
Cross-section area= (π/4)(diameter)^2
Cross-section area=(π/4)(2.053 mm or 2.053x10-3 m)^2
Cross-section area= 3.3103x10-6 square meters
Calculating for the resistance of the wire:
Resistance= (1.72x10-8 Ωm * 20.0 m)/( 3.3103x10-6 m2)
Resistance=0.1039 Ω
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Un Hidrocarburo de peso molecuar 42g/mol contiene un 85,7 de carbono, ¿cual es la formula empirica y molecular?
Answer:
1 respuesta. fórmula empírica = CH2
Explanation:
Translatation: 1 Answer. empirical formula = CH2
PLEASE HELP!!!! DUE SOON!!
Use the portion of the periodic table shown below to answer the questions.
A portion of the first three columns of the periodic table is shown. Column one from top to bottom reads 11 sodium 22.990, 19 potassium 39.098, and 37 rubidium 85.468. Column two reads 12 magnesium 24.305, 20 calcium 40.078, and 38 strontium 87.62. Column three reads 21 scandium 44.956 and 39 yttrium 88.906.
Part 1: Name two elements that have the same properties as magnesium (Mg). (4 points)
Part 2: Determine the number of protons, electrons, and neutrons present in an atom of potassium (K). Explain how you determined your answer using complete sentences. (6 points)
Answer:
Explanation:
Calcium and Beryllium are similar to Magnesium because all the three elements belong to the same group and have 2 valence electrons in their outer shell.
Potassium has 19 protons and - since the number of protons is the same as the number of electrons- also 19 electrons. To find out the number of neutrons you have to look at the atomic mass or weight of the element.
A) For a volume of tissue, calculate the dose in mGy for a
fluence of 1 × 10^6 [cm−2] of an energy of 1 MeV.
B) what condition is necessary to make this calculation and
why?
For a volume of tissue, the Dose `D would be 1 × 10^6 [cm−2] × 0.0233 [cm2 g−1] × 1 [MeV] / 1.602 × 10^-13 [J MeV−1] × 1.0 [g] = 1.448 mGy]`. The condition that is necessary to make this calculation is to assume a tissue type because the value of the energy absorption coefficient varies with different tissue types.
A) Calculation of dose in mGy for a volume of tissue and fluence of 1 × 10^6 [cm−2] of an energy of 1 MeV
For this calculation, the required formula is:
`Dose = Fluence × Energy Absorption Coefficient`
The fluence given is:
1 × 10^6 [cm−2] of an energy of 1 MeV
The value of energy absorption coefficient varies according to the tissue. Therefore, we have to assume a tissue type.For example, for the tissue type of soft tissue, the value of the energy absorption coefficient is:
0.0233 [cm2 g−1]
Thus, Dose `D = 1 × 10^6 [cm−2] × 0.0233 [cm2 g−1] × 1 [MeV] / 1.602 × 10^-13 [J MeV−1] × 1.0 [g] = 1.448 mGy]`
B) Condition necessary to make this calculation and why?
The condition that is necessary to make this calculation is to assume a tissue type because the value of the energy absorption coefficient varies with different tissue types.
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3. What type of gas do plants take in?
oxygen
carbon dioxide
Answer:
Archaeology is the study of the human past using material remains. These remains can be any objects that people created, modified, or used.
Explanation:
All amino acids are chiral (and therefore optically active) except for __________. All amino acids are L- aminos (in fischer projection, amino group is drawn on the left) so all are in the (S) absolute configuration except _____________.
All amino acids are chiral (and therefore optically active) except for glycine.
All amino acids are L-amino acids (in Fischer projection, the amino group is drawn on the left) so all are in the (S) absolute configuration except for cysteine.
Proteins are made up of substances called amino acids. Proteins and amino acids are the components of life. Amino acids are the byproducts of the digestion or breakdown of proteins. Amino acids are used by the human body to create proteins that aid in: Dissect the food
Twenty distinct smaller, simpler amino acid combinations make up the molecules that make up each protein. Long strands of amino acids that are folded into a three-dimensional structure make up protein molecules.
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Density = mass/volume
What is the volume in mmº of a sample of helium that has a mass of 0.08 g, given
the density is 0.17847 g/L?
Explanation:
Volume = Mass ÷ Density
= 0.08 g ÷ 0.17847 g/L
= 0.448254609 L
since 1 L = 1,000,000 mm³
then 0.448254609 L = 448254.609 mm³
Describe the formation of ionic bonds between elements from Group I and Group VII, including the use of dot-and-cross diagrams
Explanation:
In a physical change the nature of the substance, the particles of which it is composed and the numbers of particles remain unchanged. In a chemical change the properties of the new substances are different from the original, the particles are different and the number of particles can change
The formation of ionic bonds between elements from Group I (alkali metals) and Group VII (halogens) occurs through a transfer of electrons. Alkali metals have one valence electron in their outermost shell, while halogens require one more electron to complete their outermost shell and achieve a stable electron configuration.
Let's take the example of sodium (Na) from Group I and chlorine (Cl) from Group VII to illustrate the formation of an ionic bond. Sodium has one valence electron, while chlorine requires one electron to complete its outer shell.
In a dot-and-cross diagram, sodium is represented by the symbol Na, with a dot next to it representing its single valence electron. Chlorine is represented by the symbol Cl, with seven dots around it representing its seven valence electrons.
To form an ionic bond, sodium will transfer its single valence electron to chlorine. This results in sodium losing one electron to become a positively charged sodium ion (Na+), as it now has one less electron than protons. Chlorine, on the other hand, gains the electron from sodium, resulting in a negatively charged chloride ion (Cl-), as it now has one more electron than protons.
In the dot-and-cross diagram, the electron transfer is represented by an arrow from sodium to chlorine, indicating the movement of the electron. The final configuration shows the sodium ion (Na+) with no dots around it, indicating the loss of its valence electron, and the chloride ion (Cl-) with eight dots around it, representing the complete octet in its outermost shell.
The resulting sodium ion and chloride ion are held together by the strong electrostatic attraction between the oppositely charged ions. This attraction forms an ionic bond, creating an ionic compound known as sodium chloride (NaCl), commonly known as table salt.
This process of electron transfer and formation of ionic bonds occurs between elements from Group I and Group VII, leading to the creation of stable compounds with full outer shells for both elements.\(\huge{\mathcal{\colorbox{black}{\textcolor{lime}{\textsf{I hope this helps !}}}}}\)
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A cellophane membrane whose thickness is 0.025 mm is to be used in an artificial kidney device to remove urea from the human blood. The membrane area to be used is 2.5 m and the process is to be operated at 37°C. The concentration of urea in the blood is 0.25 kg/m² and in the permeate side, the concentration of urea is 0.05 kg m. The convective mass transfer coefficient on the blood side is k = 1x 10 m/s and that on the aqueous solution side is k= 4 x 10 m/s. The distribution coefficient K=1.75 and the diffusivity of urea through the membrane D 1.25 x 10-10 m/s. If. in total. 15.0448 g of urea is removed, determine how long it takes to effect the urea removal.
The problem involves the use of a cellophane membrane in an artificial kidney device to remove urea from human blood. The membrane has a specific area, and the concentrations of urea on both sides of the membrane are provided.
The convective mass transfer coefficients, distribution coefficient, and diffusivity of urea through the membrane are also given. The goal is to determine the time required to remove a specific amount of urea.
To calculate the time required for urea removal, we can use the principles of mass transfer. The mass transfer rate can be determined using the equation:
Mass transfer rate = A * k * (C1 - C2)
where A is the membrane area, k is the convective mass transfer coefficient, and C1 and C2 are the concentrations of urea on the blood and permeate sides, respectively.
First, we calculate the mass transfer rate using the given values. Then, by rearranging the equation, we can solve for time:
Time = (Amount of urea to be removed) / (Mass transfer rate)
Substituting the given values, we can calculate the time required to effect the urea removal.
It's important to note that the distribution coefficient and diffusivity of urea through the membrane are not directly involved in calculating the time. They are relevant for understanding the behavior of urea across the membrane and the overall efficiency of the process, but they do not directly affect the time required for urea removal.
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if 3 ml of a 0.5 m hbr solution is added to 20 ml of a 0.5 m naoh solution, the resulting solution would be .
The resulting solution from adding 3 mL of a 0.5 M HBr solution to 20 mL of a 0.5 M NaOH solution would be a 0.5 M NaBr solution.
The reaction between the two solutions is a double replacement reaction, with HBr and NaOH switching partners and forming NaBr and H2O. The mole-to-mole ratio between the two reagents, HBr and NaOH, is 1:1, and thus the molarity of the resulting NaBr solution is also 0.5 M. This is because the molarity of the solution is determined by the amount of moles of the product present in the solution, and the moles of the product are determined by the moles of the reagents in the reaction.
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Which event most likely occurs at point v? cooling erosion heating melting
The event which most likely occurs at point V during a rock cycle is cooling.
What is point V?Point V is present in the rock cycle, where changes in the state or nature of rock takes place.
When mangma comes towards the surface of the earth then due to change in temperature and pressure it will concerts into the igneous rock by cooling process and coverts into the harder form.
Hence at point V, colling is occur.
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Answer:
A. cooling
Explanation:
edge 22'
calculate the molarity of a solution made by dissolving 1.25moles of na2cro4 in enough water to form exactly 0.550 l of solution.
2.27 M is the molarity of a solution made by dissolving 1.25moles of Na\(_2\)CrO\(_4\) in enough water to form exactly 0.550 l of solution.
A chemical solution's concentration is measured in molarity (M). It refers to the solute's moles per litre of solution. Keep in mind that this is not the same as solvent in litres (a common error). Although molarity is a useful unit, it does have one significant drawback. Temperature impacts a solution's volume, therefore when the temperature varies, it does not stay constant. Typically, you convert grammes of solute to moles and then divide this quantity by litres of solution because you cannot measure solute in moles physically.
Molarity = moles of solute/volume of solution in liters
Molarity = 1.25 moles/0.550 L = 2.27 M
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CaC2 + 2H2O → C2H2 + Ca(OH)2If 4.8 moles of CaC2 are consumed in this reaction, how many grams of H2O are needed?
The given reaction is already balanced, that is to say tha the number of atoms in the reactants matches the number of atoms in the products. In the reaction, we can see the relationship between CaC2 and H2O. For each mole of CaC2 two moles of H2O react.
So, if 4.8 moles of CaC2 are consumed the moles of H2O needed will be:
Mol of H2O = Mol of CaC2 x 2
Mol of H2O = 4.8 x 2 = 9.6 mol of H2O
Now, to calculate the grams of H2O we will use the following equation and the mass molar of H2O.
Mass molar of H2O =18.01 g/mol
\(\begin{gathered} \text{Mass of H2O=Mol of H2O }\times Mass\text{ molar of H2O} \\ \text{Mass of H2O = 9.6 mol }\times18.01\frac{\text{ g}}{mol} \\ \text{Mass of H2O = 172.9 g} \end{gathered}\)So, if 4.8 moles of CaC2 are consumed in this reaction, 172.9 g of H2O are needed
16) Acculturation refers to
2 Points
A.)a belief that a certain food is poisonous.
B.)changes in dietary intake, lifestyle, and disease risk to match those of a new country,
C.)scientifically unsubstantiated beliefs about certain foods.
D.)a process of dividing cultures according to food intake,
Answer:
B.)changes in dietary intake, lifestyle, and disease risk to match those of a new country,
Give the number of protons (p), electrons (e), and neutrons (n) in one atom of chlorine-37. 17 p. 37 e, 17 n 37 p. 17 e, 20 n 17 p. 17 e, 37 n 17 p. 17 e, 20 n 37 p. 37 e, 17 n
There really are 17 electrons and 20 neutrons.
What role do electrons play in atoms?The atom's negatively charged particles are called electrons. The total negative charge of an electron's electrons counteracts the dipole moment of its protons there in atomic nucleus. The electron is a very little particle related to all of the other parts of the atom.
Briefing:
The mass number for the above is 37.
The atomic number is simply the quantity of protons or electrons in an atom.
So ..
Electrons: 17
Atomic mass divided by atomic number equals neutron number.
Put the values in, then.
37 — 17 = 20 .
Therefore , the number of neutrons is 20.
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when 34 700 j of heat are applied to a 350 g sample of liquid methanol, what must its heat of vaporization be to convert it all to gas?
Answer:
The temperature at which the vapor pressure of a liquid is just equal to the external ... The conversion of a liquid to a gas below the boiling point is called ... equilibrium temperature of the mixture was 36.0 °C. What is the specific heat (J/ g°C) of the metal
Explanation:
A 53. 5 mL ample of an 5. 4 % (m / v) KBr olution i diluted with water o that the final volume i 205. 0 mL Expre your anwer to two ignificant figure and include the appropriate unit
The concentration after dilution is 1.4%.
We are aware that concentration and volume are related to each other by the formula -
\( C_{1}\) \( V_{1}\) = \( C_{2}\) \( V_{2}\), where we have initial concentration and volume on Left Hand Side and final concentration and volume on Right Hand Side.
Keep the values to calculate final concentration.
\( C_{2}\) = (53.5 × 5.4)/205.0
Performing multiplication on Right and Side
\( C_{2}\) = 288.9/205.0
Performing division on Right Hand Side
\( C_{2}\) = 1.4%
Hence, the final concentration is 1.4%.
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The complete question is -
A 53.5 mL sample of an 5.4 % (m/v) KBr solution is diluted with water so that the final volume is 205.0 mL.
Calculate the final concentration and express your answer to two significant figures and include the appropriate units.
does freezing involve a chemical reaction
I NEED NOW PLEASE HELP How many grams of KF are need in order to produce 2.0 mol CaF?
which of the following statements is true? excited electrons do not return to ground state until they move away from the heat of the flame. only one electron can be excited at a time. an electron may fall back to ground state in a single step or in multiple steps. each element emits a single, characteristic wavelength of light during the flame test.
The statement that is true among the options provided is: "An electron may fall back to the ground state in a single step or in multiple steps."
Higher energy levels are attained by excited electrons in atoms. The extra energy is finally released as light when they reach their ground state, though. The electron may return to its ground state in a single step, emitting a photon with a certain wavelength, or it may do so in several phases, releasing photons with various wavelengths.
The following additional options' statements are untrue:
Without having to leave the heat of the flame, excited electrons can return to the ground state. The flame's heat is what initially excite the electrons, yet the atom can still return to its ground state while it is still in the flame.
The claim that only one electron can be excited at a time is untrue since several electrons can be excited simultaneously.
In a flame test, each element emits a variety of recognizable light wavelengths. The energy differences between the excited states and the ground state of various electrons in the atom are reflected in the specific wavelengths that are emitted.
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You are given a bottle of carbon with 500 g of pure carbon powder and asked to measure out 1 mole. How many grams of carbon should you get?
The mass of carbon that you get is equal to 12 grams.
What is a mole?A mole is described as a scientific standard unit that is used to evaluate the huge number of quantities of ions, atoms, molecules, or other particular particles. The atomic mass can be defined as the mass of the one mole of any element and that of any compound is known as molar mass.
The number of entities in one mole was experimentally found to be equal to approximately 6.023 × 10 ²³ which is called Avogadro’s number.
Given, the total mass of carbon powder in the bottle = 500g
The mass of carbon asked to measure = 1 mole
The atomic mass of the carbon element = 12 g
It means the mass of the one mole of carbon element = 12 g
Therefore the mass of carbon that you get will be equal to 12 grams.
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The the _____ temperature _____ the the air molecules move. (Choose 2) higher, faster lower, faster lower, slower higher, slower
Answer:
The higher the temperature the faster the air molecules move. / The lower the temperature the slower the air molecules move.
Explanation:
Both answers work. Higher temp = more energy = moving faster, and the opposite applies. Lower temp = less energy = moving slower.
Dibuja un átomo de nitrógeno con 7 protones 7 neutrones y electrones ?
No hablo bien español, pero aquí hay una imagen:
Can somebody please give me the IMF types of the following compounds?
NH3
HCL
CH4
My choices are Dispersion, Dipole Dipole, or Hydrogen Bonding.
Answer:
NH3 is Ammonia Which is Hydrogen Bonding
HCL is hydrochloric acid which is Dipole Dipole
CH4 is Methane which is Dispersion
what were your hypotheses regarding the number of buoyant leaf discs in each of the four experimental procedures from part 31 of the procedure, distilled water light; distilled water dark; sodium bicarbonate light; sodium bicarbonate dark.
The hypothesis for part 31 of the procedure was that the number of buoyant leaf discs in each of the four experimental procedures would differ based on the solution used and the presence or absence of light.
Specifically, it was hypothesized that the number of buoyant leaf discs would be highest in the sodium bicarbonate solution with light, followed by the sodium bicarbonate solution without light, the distilled water with light, and the distilled water without light.
It was further hypothesized that the sodium bicarbonate solution would be more effective at keeping the leaf discs buoyant than the distilled water, due to the presence of carbon dioxide which is less dense than water.
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Explain how water molecules differ from
many other molecules.
Answer:
Water behaves differently from most other chemical compounds. In almost all substances the atoms and molecules move closer together as they get colder. They then solidify. Water, however, attains its greatest density at four degrees Celsius because the water molecules are packed closest together at this temperature.
Explanation:
A sample of nitrogen gas occupies a volume of 320.9 ml at 65.4c what volume will it occupy at 29.8
The volume of the nitrogen gas sample at 29.8°C would be approximately 365.2 ml. This can be calculated using the combined gas law, which relates the initial and final volumes, temperatures.
Pressures of a gas sample. Given that the pressure remains constant, the equation can be simplified to:
(V1/T1) = (V2/T2)
Where:
V1 = Initial volume (320.9 ml)
T1 = Initial temperature (65.4°C + 273.15 K)
V2 = Final volume (unknown)
T2 = Final temperature (29.8°C + 273.15 K)
Solving for V2, we can rearrange the equation as:
V2 = (V1 x T2) / T1
Plugging in the values:
V2 = (320.9 ml x (29.8°C + 273.15 K)) / (65.4°C + 273.15 K)
V2 ≈ 365.2 ml
Therefore, the nitrogen gas sample would occupy approximately 365.2 ml at a temperature of 29.8°C.
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Substitution method
4s+3p=85.50
3s+5p=115
Explanation:
I don't know what the answer is sorry