Calculate the acceleration of a box that has a mass of 12kg being pushed with a force of 36N. (Write the answer below and put correct units)
​

Answer:

640 N

Explanation:

Given :

Mass of horse, m = 40kg

initial speed of horse, u = 8 m/s

final speed of horse, v = 0 m/s  (because horse comes to a sudden stop)

time taken to stop, t = 0.5 s

recall that acceleration = change in speed / time taken for the change

or

a = (v - u) / t     (substituting the above values)

a = (0 - 8) / 0.5

a = -16 m/s²   (i.e it is a deceleration of 16 m/s²)

since we are not concerned about the direction of the force, we can simply use the absolute value of acceleration which is a = 16 m/s²

also recall that

Force = mass x acceleration

F = ma    (substituting the values above)

F = 40kg x 16 m/s

F = 640 N

Answer:

Explanation:

First, we need to convert the velocity to meters per second:

60 mph = 88.5 ft/s = 26.82 m/s

Now we can use the formula:

v = at

where v is the final velocity, a is the acceleration, and t is the time.

Rearranging this formula, we get:

t = v/a

Substituting the values, we get:

t = 26.82 m/s / 13.5 m/s^2 = 1.987 seconds (rounded to three decimal places)

Therefore, it will take approximately 1.987 seconds to reach 60 mph with an average acceleration of 13.5 m/her/sec.

The vehicle will hit 60 mph in 7152 seconds (or about 1 hour and 59 minutes) with an average acceleration of 13.5 m/hr/sec.

The definition of acceleration is. The pace at which velocity changes with regard to time. Because it has both amount and direction, acceleration is a vector variable. It is also the second derivative of location in relation to time, or the first derivative of motion in relation to time.

We can begin by converting the final velocity to meters per second (m/s) as the initial acceleration is given in m/hr/sec.

60 mph = 26.8224 m/s (1 mile = 1.60934 km, 1 hour = 3600 seconds)

Now, we can use the formula:

v = u + at

Where,

v = final velocity = 26.8224 m/s

u = initial velocity = 0 m/s (car starts at rest)

a = acceleration = 13.5 m/hr/sec = 0.00375 m/s^2 (convert from m/hr/sec to m/s^2)

t = time taken to reach the final velocity

Substituting the values, we get:

26.8224 = 0 + (0.00375)t

t = 26.8224 / 0.00375

t ≈ 7152 seconds

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Answer:

Force/Area in fact Pascal is defined as Newton/m^2

Answer:

0.0141 kg/kg.

Explanation:

So, we are given the following parameters or information from the problem above:

The relative humidity = 10% was humidified to 40%, the temperature = 40°C.

From the chart, at temperature = 40°C and relative humidity = 10%, the weight of dry air = a1 = 0.0046 kg/kg, volume = 0.89 m³/kg.

Also, from the chart  at temperature = 40°C and relative humidity = 40%, the weight of dry air = a2 = 0.00187 kg/kg, volume = 0.913 m³/kg.

Therefore, the amount of moisture added in the humidifier per kg of dry air = 0.0046 kg/kg - 0.00187 kg/kg = 0.0141 kg/kg.

Answer:

a) the excitation energy is E₂ λ = 520 nm

the emission energy is E₁,  λ= 640 nm

b)   #_photons = 2.6 10¹⁸ photons,  

c) he excitation wavelength   λ = 520 nm is green, therefore the filter is also green

the emission wavelength is lam = 640 nm is orange

Explanation:

a) the energy of a photo is given by the planck relation

           E = h f

the speed of light is

          c = λ f

          f = c /λ

we substitute

          E = hc /λ

let's calculate the energy for the two photons

λ = 640 nm = 640 10⁻⁰ m

            E₁ = 6.63 10⁻³⁴ 3 10⁸/640 10⁻⁹

            E₁ = 3.1 10⁻¹⁹ J

λ = 520 nm = 520 10⁻⁹ m

             E₂ = 6.63 10⁻³⁴ 3 10⁸/520 10⁻⁹

            E₂ = 3.825 10⁻¹⁹  J

therefore the excitation energy is E₂ λ = 520 nm

the emission energy is E₁,  λ= 640 nm

b) For this part let's use a direct proportion rule (rule of three). If a photon (lam = 520 nm) has an energy of 3.825 10⁻¹⁹ J, how many photons have an energy of E = 1 10-3 J. Remember that the power is the energy per unit of time

        #_photons = 1 10⁻³ J (1 photon / 3.825 10⁻¹⁹ J)

        #_photons = 2.6 10¹⁸ photons

c) the excitation wavelength   λ = 520 nm is green, therefore the filter is also green

the emission wavelength is lam = 640 nm is orange

An aerial photographic image's corners, edge-centers, or both may contain a series of marks known as fiducial marks. These traces are recorded on the original film by the camera.

Fiducial markers are tiny metal objects, usually made of gold, that are positioned inside or close to a tumor to help direct the placement of radiation beams during therapy. They are about the size of a grain of rice.

Tiny metal things are called fiducial markers (about the size of a grain of rice). They assist your healthcare professionals in aligning the radiation beams and guarantee that your radiation therapy is administered consistently.

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Fiducial marks are a set of marks that can be found in the corners, edge-centers, or both of an aerial photographic image. The camera captures these traces on the original film.

Given  the Ryerson Campus is at a scale of  1:1000

Then the photographic scale (s) = 1:3000

The focal length of camera (f) = 152mm = 0152m

The format is (k) =  230 x 230mm = 0.23m

the photographic scale (s) = F/H where H is the image height

1/3000 = 0.152 /H Then H = 456m

Assume that there is longitudinal overlap as P1 = 60% and side to side overlap as 30%. Therefore margin of ground photograph = (1-P1) x k/s

(1-0.6) x 0.23/1/3000 = 276mm

Now width of ground photograph = (1-0.3) x 0.23/1/3000 = 483m

Hence the central points are plotted within the area range in 276m x 483m magnitude.

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Answer:

Explanation:

The point P is influenced by two electric fields, that are from Q1 and Q2. Because Q1 is a positive point charge, the E-fields is going to the right and the E-fields from Q2 is going to the left because of negative point charge. So:

\(E_{1}=\frac{kQ_{1}}{R_{1}^{2}}\)

\(E_{2}=\frac{kQ_{2}}{R_{2}^{2}}\)

Where R1 = 2 + 3 = 5 m, and R2 = 3 m. With k = \(k=9\times 10^{9}\) in \(Nm^{2}/C^{2}\), we can obtain:

\(E_{1}=(9\times 10^{9})\frac{500\times10^{-6}}{25}=180\times 10^{3}\) N/C (+)

\(E_{2}=(9\times 10^{9})\frac{100\times 10^{-6}}{9}=100\times 10^{3}\) N/C (-)

So: the Electric Field at P : \(E_{P}=E_{1}-E_{2}=(180-100)\times 10^{3}=8\times 10^{4}\) N/C in magnitude

Physical anthropology studies the human body. This discipline is aimed at analyzing the evolution and diversity of human beings.

Physical anthropology is a branch of anthropology that studies the evolution and diversity of human beings.

Physical anthropology is also called biological anthropology due to its close relation with biological sciences.

This branch of anthropology (physical anthropology) is aimed at assessing the evolution and physical variation and/or behaviors of human beings.

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Answer:

B. the human body

Explanation:

Complete question is;

Shoveling snow can be extremely taxing since the arms have such a low efficiency in this activity. Suppose a person shoveling a sidewalk metabolizes food at the rate of 800 W. (The efficiency of a person shoveling is 3%.)

(a) What is her useful power output? (b) How long will it take her to lift 3000 kg of snow 1.20 m? (This could be the amount of heavy snow on 20 m of footpath.) (c) How much waste heat transfer in kilojoules will she generate in the process?

Answer:

A) P_out = 24 W

B) t = 1470 s

C) Q = 1140.72 KJ

Explanation:

We are given;

Input Power; P_in = 800 W

Efficiency; η = 3% = 0.03

A) Formula for efficiency is;

η = P_out/P_in

Making P_out the subject, we have;

P_out = η•P_in

P_out = 0.03 × 800

P_out = 24 W

B) We know that;

Power = work done/time taken

Thus;

P_out = mgh/t

We are given;

m = 3000 kg

h = 1.20 m

Thus, time is;

t = (3000 × 9.8 × 1.2)/24

t = 1470 s

C) amount of heat wasted is calculated from;

Q = (P_in - P_out)t

Q = (800 - 24) × 1470

Q = 1,140,720 J

Q = 1140.72 KJ

It as dangerous to be hit by the gun as by the bullet because of the following;

(A) The butt distributes the recoil force over an area much larger than that of the bullet.

(B) The rifle has a much lower speed than the bullet.

The principle of conservation of linear momentum states that in an isolated system, the total momentum of the system is conserved.

That is the sum of the initial momentum is equal to the sum of the final momentum.

momentum of the gun = momentum of the bullet

Mu = mU

where;

If the forward momentum of a bullet is the same as the backward momentum of the gun, the speed of the gun will be smaller than the speed of the bullet since the mass of the gun is bigger than mass of the bullet.

We cannot conclude on the kinetic energy, since it depends on both mass and velocity.

Finally, the butt distributes the recoil force over an area much larger than that of the bullet, since the butt has a larger surface area and will hit more surface area than the bullet.

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Answer: Increase in competition for abiotic factors.

Explanation: Resource availability is one of the main factors determining the ecological dynamics of populations or species. Fluctuations in resource availability can increase or decrease the intensity of resource competition. Resource availability and competition can also cause evolutionary changes in life-history traits

Answer:

headlight of vehicles use less energy and gives light to very limited area hence electricity can be conserved by doing this

Answer:

31.84

Explanation:

To find the magnitude of the sum of the three vectors, first, we need to add the vectors component-wise. Then, we can find the magnitude of the resulting vector.

Add the vectors component-wise:

Vector A + Vector B + Vector C = [13+13+0, 8+0+1, 0+8+8] = [26, 9, 16]

Find the magnitude of the resulting vector:

The magnitude of a vector [x, y, z] is given by the formula:

magnitude = sqrt(x^2 + y^2 + z^2)

Plugging in the values from the resulting vector:

magnitude = sqrt(26^2 + 9^2 + 16^2)

magnitude = sqrt(676 + 81 + 256)

magnitude = sqrt(1013)

magnitude ≈ 31.84

The magnitude of the sum of the three vectors is approximately 31.84.

Hope this helps!

Answer:

26m/s

Explanation:

Given parameters:

Initial velocity  = 18m/s

Time  = 2s

Acceleration  = 4m/s²

Unknown:

Final velocity

Solution:

To solve this problem, we use the expression below:

     Acceleration  = \(\frac{v - u }{t}\)

v is the final velocity

u is the initial velocity

 t is the time taken

    4   = \(\frac{v - 18}{2}\)    

      v - 18  = 8

       v  = 8 + 18 = 26m/s

To calculate the torque required to create an angular acceleration, we can use the formula:

Torque = Moment of Inertia × Angular Acceleration

The moment of inertia of a disk can be calculated using the formula:

Moment of Inertia = (1/2) × Mass × Radius^2

Given:

Mass = 15,000 kg

Radius = 6.14 m

Angular Acceleration = 0.0500 rad/s^2

First, calculate the moment of inertia:

Moment of Inertia = (1/2) × Mass × Radius^2

Moment of Inertia = (1/2) × 15,000 kg × (6.14 m)^2

Next, calculate the torque:

Torque = Moment of Inertia × Angular Acceleration

Torque = Moment of Inertia × 0.0500 rad/s^2

Now, let's plug in the values and calculate:

Moment of Inertia = (1/2) × 15,000 kg × (6.14 m)^2

Moment of Inertia ≈ 283,594.13 kg·m^2

Torque = 283,594.13 kg·m^2 × 0.0500 rad/s^2

Torque ≈ 14,179.71 N·m

Rounding to three significant figures, the torque required to create an angular acceleration of 0.0500 rad/s^2 is approximately 14,180 N·m.

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The average speed of Pluto in its orbit around the Sun is approximately 4.67 km/s.

To determine the average speed of Pluto, know the time it takes for Pluto to complete one orbit around the Sun.

Using Kepler's Third Law, find the orbital period of Pluto:

T² = (4π² / GM) × r³

where T = orbital period, G = gravitational constant, M = mass of the Sun, and r = average distance between Pluto and the Sun.

Plugging in the values:

T² = (4π² / (6.674 × 10⁻¹¹ m³ kg⁻¹ s⁻²) ) × (39.5 AU × 1.496 × 10¹¹ m/AU)³ / (1.989 × 10³⁰ kg)

T² = 905,594,481,160,410 s²

T = 30,105,559 s (or approximately 905.6 Earth years)

Now calculate the average speed of Pluto:

Average speed = Distance traveled / Time taken

Distance traveled = 2π × r (the circumference of Pluto's orbit)

Distance traveled = 2π × (39.5 AU × 1.496 × 10¹¹ m/AU)

Distance traveled = 7.44 × 10¹² m

Average speed = 7.44 × 10¹² m / (30,105,559 s × 365.25 days/year × 24 hours/day × 3600 s/hour)

Average speed = 4.67 × 10³ m/s

Therefore, the average speed of Pluto in its orbit around the Sun is approximately 4.67 km/s.

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When reading the simile "Bolt runs as fast as lightning," the most appropriate visual interpretation would be that "Bolt runs very fast."

This simile compares Bolt's speed to that of lightning, which is known for its incredible swiftness. The intention is to emphasize Bolt's exceptional speed by equating it to the rapid movement of lightning.

While the simile highlights Bolt's remarkable speed, it does not specify the manner in which he runs or the impact of each step. Therefore, the options suggesting Bolt runs in a straight line, in a wavy manner, or that each step produces thunder are not directly implied by the simile itself. These additional details go beyond the comparison of speed and introduce elements that are not explicitly mentioned.

Hence, the most accurate interpretation based solely on the simile is that Bolt runs very fast, comparable to the speed of lightning.

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Vehicles need to be serviced for several reasons such as preventing costly repairs and improving fuel economy.

First, regular maintenance can help to prevent costly repairs down the road. Second, maintenance can help to improve fuel economy and emissions. Third, maintenance can help to keep your vehicle safe and reliable.

The servicing requirements for petrol/diesel and electric vehicles differ in a number of ways. Petrol/diesel vehicles require oil changes more frequently than electric vehicles. This is because petrol/diesel engines use oil to lubricate the moving parts, while electric motors do not. Petrol/diesel vehicles also require tune-ups more frequently than electric vehicles.

This is because petrol/diesel engines have more moving parts that need to be synchronized, while electric motors have fewer moving parts.

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H= P × t

1kW= 1000w

10 min = 600s

H= 1000×600=600,000J

=> 143.40kcal

Answer:

im just so focused on the fact that im going to mars :O

The speed of sound (velocity) is 343 m/s and a burglar alarm on a car has a frequency of 1200hz. 0.286 m/sec is the wavelength of the burglar alarm on the car.

Frequency is a unit of measurement for how frequently a recurrent event, like a wave, takes place over a specified period of time. A cycle is one repetition of the repeating pattern. Frequency only exists in moving waves that change their places throughout time. One method to describe how quickly a wave moves is by its frequency.

Therefore, if a wave passes through in half a second, the frequency is 2 per second. The frequency is 100 times per hour if it takes 1/100 of an hour.

Given that,

speed of sound (velocity) is 343 m/s

frequency of 1200 Hz.

Now as we know,

v = n × λ

or, λ = v/n

or, λ = (343 m/sec) / 1200 Hz.

or, λ = 0.286 m/sec

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36 × 10⁻⁵ C is the total charge for Two air-filled parallel-plate capacitors with capacitances C1 and C2 are connected in parallel to a battery that has a voltage of 36.0 V; C1 = 4.00 μF and C2 = 6.00 μF.

As it is given

A battery is linked in parallel with two air-filled parallel-plate capacitors with capacitances C1 and C2.

C1 = 4μF

C2 = 6μF

For the capacitors connected in parallel

Resultant Capacitance = C1 + C2 = 10μF = 10 × 10⁻⁶ F

C = 10⁻⁵ F

Voltage = 36 V

Total charge = Resulting Capacitance × Voltage

                     = 10⁻⁵ × 36

                     = 36 × 10⁻⁵ C

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Given :

One particle, of mass m , moves with a speed v in the x-direction, and another particle, of mass 2 m , moves with a speed v/2 in the y-direction.

To Find :

The velocity of the center of mass of these two particles.

Solution :

Speed of mass m, \(v\ \hat i\).

Speed of mass 2m , \(\dfrac{v}{2}\ \hat{j}\) .

Speed of center of mass is given by :

\(v_{cm }= \dfrac{m\times( v\ \hat{i}) + 2m \times \dfrac{v}{2}\ \hat{j} }{m + 2m}\\\\v_{cm}=\dfrac{v( \hat{i} + \hat{j})}{3}\)

Hence, this is the required solution.

The velocity of the center of mass of these two particles will be \(\rm v_{cm}= \frac{v(\vec i+\vec j)}{3}\)

The change of displacement with regards to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is

\(\rm V_i\) is the speed of mass m

\(\rm \frac{v}{2} \hat j\) is the speed of mass 2m

Speed of the center of mass will be;

\(\rm v_{cm}=\frac{m \times (v \hat i)+2m \times \frac{v}{2}\hat j }{m+2m} \\\\ \rm v_{cm}= \frac{v(\vec i+\vec j)}{3}\)

Hence the  velocity of the center of mass of these two particles will be \(\rm v_{cm}= \frac{v(\vec i+\vec j)}{3}\).

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Answer:

Lift, weight, thrust and drag.

Answer:

According to Newton's first law of motion (inertia), an object at rest will remain at rest, or an object in motion will continue in motion at the same speed and in the same direction, until an outside force acts on it. For an aircraft to taxi or fly, a force must be applied to it. It would remain at rest without an outside force. Once the aircraft is moving, another force must act on it to bring it to a stop. It would continue in motion without an outside force. This willingness of an object to remain at rest or to continue in motion is referred to as inertia.

Newton's Second Law of Motion

The second law of motion (force) states that if a object moving with uniform speed is acted upon by an external force, the change of motion (acceleration) will be directly proportional to the amount of force and inversely proportional to the mass of the object being moved. The motion will take place in the direction in which the force acts. Simply stated, this means that an object being pushed by 10 pounds of force will travel faster than it would if it were pushed by 5 pounds of force. A heavier object will accelerate more slowly than a lighter object when an equal force is applied.

Newton's Third Law of Motion

The third law of motion (action and reaction) states that for every action (force) there is an equal and opposite reaction (force). This law can be demonstrated with a balloon. If you inflate a balloon with air and release it without securing the neck, as the air is expelled the balloon moves in the opposite direction of the air rushing out of it.

The sentence that best describes the motion is "the motion is a circular motion and has completed one revolution".

Question: "If a car moved one full circular track of 15 Km, which sentence describes its motion?​"

An object moves in a circle at a constant speed in a motion known as uniform circular motion. Any point on a propeller, for instance, that is spinning continuously, is moving uniformly in circles.

There are two types of circular motion: uniform and non-uniform.

Circular motion can be seen in the orbit of a satellite, ice skaters moving at a constant speed in a circle, and vehicles traveling in a circle.

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Explanation

In gases the particles move rapidly in all directions, frequently colliding with each other and the side of the container

so

I would draw it with the particles separated moving and colliding with the others

I hope this helps you

The force acting on the particle at t = 1 s is 24.4 N.

Mass of the particle, m = 2 units

Distance of the curve, r(t) = (4t²- t³)i - 5tj + (t⁴- 2)k

The velocity of the particle,

v = d[r(t)]/dt = (8t - 3t²)i - 5j + 4t³k

The acceleration of the particle,

a = d²[r(t)]/dt² = (8 - 6t)i + 12t²k

Let the time for which the force is acting be 1 second.

Therefore, acceleration at t = 1 is,

a₁ = 2i + 12k

Hence, the magnitude of acceleration,

|a₁| = √(2²+ 12²)

|a₁| = √148

|a₁| = 12.2 unit/s²

Therefore, the force acting on the particle at t = 1 s is,

F₁ = m x |a₁|

F₁ = 2 x 12.2

F₁ = 24.4 N

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