By now you should have an understanding of how relational databases work and how to use SQL to create and manipulate data. Now it’s time to put that knowledge into practice. For your semester project, you are going to create a database that you might find at a college. You will be building this database from the ground up so you have many decisions to make such as naming conventions, how to organize data, and what data types to use. Deliverables: Document "Relationship report" showing Table names used in the database Table relationships Keys Table Fields names Field Data types Constraints SQL (code) to create the following Faculty contact list Course Book List by Semester Course Schedule by semester Student Grade Report by semester Faculty Semester grade report (number of A's, B's, C's, D's, F's per course) Student GPA report by semester and overall (semester and cumulative) Mailing list for Diplomas Student Demographics over time (how many were under 18 last year, this year) Sample query output (at least 10 entries per query) Faculty contact list Course Book List by Semester Course Schedule by semester Student Grade Report by semester Faculty Semester grade report (number of A's, B's, C's, D's, F's per course) Student GPA report by semester and overall (semester and cumulative) Mailing list for Diplomas Student Demographics over time (how many were under 18 last year, this year)
I need this in screen shots please. I just dont get it when i read it thanks!

The approximate average power output is mathematically given as

P=1097.6w

Question Parameters:

Iowa with a 10 m2 swept area and 50 m hub height

Assume 80% of the Betz limit, 80% conversion efficiency, and air density of 1.0 kg/m3. Wind speed is 7 m/s2

Generally, the equation for the average output power  is mathematically given as

\(P=0.5 \phi BAu^3*n\\\)

Where

B= Benz coefficient

n=0.8

Therefore

P=0.5*1*0.8*10*7^3*0.8

P=1097.6w

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What is the approximate average power output of a well-designed modern turbine in Des Moines, Iowa with a 10 m2 swept area and 50 m hub height? Assume 80% of the Betz limit, 80% conversion efficiency, and air density of 1.0 kg/m3. Wind speed is 7 m/s2

The fact that Eli plans to set up a recycling program made him choose D. The material he chose is renewable and is much better for the environment.

It should be noted that recycling simply means the process of collecting and processing materials that can be turned into another product.

Therefore, the material he chose is renewable and is much better for the environment and thus influenced his decision.

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Focus primarily on highly precise specifics of what Cornell offers and how it matches with your interests and values. You can regard this as a "Why us?" essay with some optional "Why major" spice.

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Answer:

polymerisation,

Explanation:

The temperature after the heat-addition process is 1668.5 K.

The thermal efficiency is 55.5%.

The mean effective pressure is -772.1 kPa (negative sign indicates compressive work).

Compression ratio of air-standard Diesel cycle = r = 16

Cut off ratio = 2

Initial Temperature of Air = T₁ = 27 °C = 300 KV₁ = 97 kPa

Constant Specific Heat of air at constant Pressure = cp = 1.005 kJ/kg·K

Constant Specific Heat of air at constant Volume = cv = 0.718 kJ/kg·K

Gas constant of air = R = 0.287 kJ/kg·K

Adiabatic Index of air = k = 1.4

Formula Used:Cut off Ratio (rc) = V₃ / V₂Compression Ratio (r) = V₂ / V₁

The temperature after the heat-addition process is given as:

T₃ = (rc / (rc - 1)) x (cp x T₂ - cv x T₁)T₃ = (2 / (2 - 1)) x (1.005 x 990 - 0.718 x 300)T₃ = 1668.5 K

The thermal efficiency is given as:η = 1 - (1 / r^(k-1))η = 1 - (1 / 16^(1.4-1))η = 0.555 or 55.5%

The mean effective pressure is given as:MEP = (p₃V₃ - p₂V₂) / (V₃ - V₂)MEP = (1.427 x 10^5 x 0.04 - 9.7 x 10^4 x 0.25) / (0.04 - 0.25)MEP = - 772.1 kPa (Negative Sign indicates that it is a Compressive Work)

Therefore,The temperature after the heat-addition process is 1668.5 K.The thermal efficiency is 55.5%The mean effective pressure is -772.1 kPa.

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Put your printer through a hard reset. Try turning off both the printer and your computer, then restarting both if that doesn't fix the problem. Then try to remove and reinstall your printer's driver.

A problem with the printer itself may exist if the status of your printer reads "Printer in error state." Check to see if the printer is on and wired or wirelessly linked to your computer. Make sure the cover is closed and the paper isn't jammed, and check if there isn't enough paper or ink.

Of all printer errors, paper jams are arguably the most dreadful. There are a few problems that might be present when it comes to smudges, faded lettering, and poor image quality.

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Answer:

Option B

Explanation:

Atoms of ferromagnetic materials have north and south pole but these atoms are oriented in random directions due to which they do no exhibit magnetic properties until unless they are brought into influence of any external temporary or permanent magnetic field.

Under the influence of external magnetic force, the atoms of the ferromagnetic material get oriented in a particular direction.

Hence, option B is correct

Answer:

Explanation:

B evaporator outlet: on the suction line between the evaporator and the compressor

The closest equivalent present worth of John's deposits is less than $8,000.

To determine the closest equivalent present worth of John's deposits, we need to calculate the present value of the cash flows he will make.

The deposit of $1000 at the end of the next year can be considered a future value (FV). We need to calculate its present value (PV) using the formula:

PV = FV / (1 + r)^n

Where:

FV = $1000

r = interest rate = 10% = 0.10

n = number of years = 1

PV = $1000 / (1 + 0.10)^1 = $909.09

Next, we calculate the present value of the increasing deposits of $100 per year for 10 years. These cash flows form an arithmetic progression with a common difference of $100.

Using the formula for the sum of an arithmetic progression, we can find the present value of these cash flows:

PV = (n/2) * (2a + (n-1)d)

Where:

n = number of terms = 10

a = first term = $100

d = common difference = $100

PV = (10/2) * (2*100 + (10-1)*100) = 5 * (200 + 9 * 100) = $5,500

Now, we can sum up the present values of both cash flows:

PV = $909.09 + $5,500 = $6,409.09

The closest equivalent present worth is between $8,000 - $8,300. Since the calculated present value is lower than $8,000, the closest equivalent present worth is less than $8,000.

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Answer:

Force is a kinetic quantity. Force = m x a. Hence, the mass of the body has an effect on force calculation.

Answer:

mechanical engineer

Explanation:

The relationship between green building and self-interest include the following:

This is the process of reducing the environmental impact of buildings. This therefore leads to enhancement of the health of people.

Its relationship with self interest can seen listed above as the most appropriate choice.

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When you walk into the station at the end of your route, you should option A: check in with your DSP and bring any undeliverable packages back to the Amazon Return to Station desk.

2. To make sure you are at the correct address, you should option A: compare the address on the package label with the physical home address. You can also compare the address listed in your delivery app with the physical address.

3. In the Delivery App, you can find the button to contact the customer in option A:  the Map screen or in the itinerary. It may be labeled "Contact Customer" or something similar.

When you finish your delivery route and return to the station, it is important to check in with your DSP (Delivery Service Provider) and return any undeliverable packages to the Amazon Return to Station desk. This helps to ensure that the packages are properly processed and that the delivery information is accurately recorded.

Therefore, To make sure you are at the correct address, you should compare the address on the package label with the physical home address.

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To calculate the mean of all numeric variables in the HELPrct data from the mosaicData package, we can use the colMeans() function in R. This function calculates the mean of each column in a data frame.

However, it only works on numeric columns, so we need to first remove any non-numeric columns or missing values.
To do this, we can use the select_if() function from the dplyr package to only select columns that are numeric. Then, we can use the na.omit() function to remove any rows with missing values. Finally, we can use the colMeans() function to calculate the mean of each column.
Here's the code:
library(mosaicData)
library(dplyr)
# Select only numeric columns
numeric_cols <- select_if(HELPrct, is.numeric)
# Remove rows with missing values
numeric_cols <- na.omit(numeric_cols)
# Calculate column means
means <- colMeans(numeric_cols)
# Print the result
print(means)
This will give us the mean of each numeric column in the HELPrct data, excluding any missing values.

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The correct option for the implication of low variety is B) Flexibility needed. Variety refers to the number of different products, services, or activities that an organization offers. High variety means that a company offers a wide variety of products or services, while low variety means that a company provides a limited range of products or services.

One of the implications of low variety is that customers have limited options. They are restricted to purchasing only those goods and services that the company offers, which may not match their requirements or preferences. This may lead to losing customers to rivals who offer a greater variety of goods and services.

In the case of low variety, it is critical to have the required flexibility. Customers may ask for certain specific goods or services that are not provided by the company. To meet customer requirements, the company should be adaptable and able to rapidly respond to customer requests by expanding its product line. As a result, low variety necessitates the need for flexibility.

The other given options are not valid. Low unit cost is not related to low variety. Unit cost may be affected by economies of scale and other factors, but it is not directly related to variety. High complexity is not related to low variety as well. As the range of goods and services offered by the company increases, the complexity of the company's operations and management also increases. Matching customers' specific needs is partially correct because the company cannot match customer specific needs in low variety. In low variety, the company has a limited range of goods and services, so it is not possible to fulfill all the customers’ specific needs.

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Answer:

whatsthe question choices

Answer: The two statements that apply to gas welding as compared to arc welding are:

1.Slower than arc welding

2.Easier to control than arc welding

Explanation: Gas welding is a slower process than arc welding because it requires heating the metal to be welded to a high temperature before the welding process can begin.

However, it is easier to control than arc welding because the welder can adjust the heat and flame of the gas torch to achieve the desired results. In contrast, arc welding requires more skill and practice to control the electric arc and produce a good weld.

Answer:

attached below

Explanation:

a) G(s) = 1 / s( s+2)(s + 4 )

Bode asymptotic magnitude and asymptotic phase plots

attached below

b) G(s) = (s+5)/(s+2)(s+4)

phase angles = tan^-1 w/s , -tan^-1 w/s , tan^-1 w/4

attached below

c) G(s)= (s+3)(s+5)/s(s+2)(s+4)

solution attached below

Answer: Your welcome!

Explanation:

Current I = 200/√(10^2 + (2π × 50 × 0.1)^2) = 200/√1000 = 14.14 A

Power P = I2R = 14.142 × 10 = 141.4 W

Power factor PF = cos φ = R/√(R2 + X2) = 10/√(102 + (2π × 50 × 0.1)2) = 0.99

Voltage drop across resistance VR = I × R = 14.14 × 10 = 141.4 V

Voltage drop across condenser VC = I × X = 14.14 × 2π × 50 × 0.1 = 44.18 V

The phasor diagram is shown below:

Phasor Diagram

V = 200 V at 0°

I = 14.14 A at -90°

VR = 141.4 V at 0°

VC = 44.18 V at +90°

The void ratio of the soil is 0.3125 if the soil has a water content of 20% and is 90% saturated.

The void ratio of soil is the ratio of the volume of voids (empty space) to the volume of solids in the soil. It can be calculated using the following formula:

Void ratio = Vv / Vs

where Vv is the volume of voids and Vs is the volume of solids.

We know that the soil is 90% saturated, which means that 90% of the voids are filled with water. Therefore, the volume of voids filled with water is 0.9 * Vv, and the volume of voids not filled with water is 0.1 * Vv.

We also know that the water content of the soil is 20%, which means that 20% of the total volume of the soil is water. Therefore, the volume of water is 0.2 * (Vv + Vs), and the volume of solid is (1 - 0.2) * (Vv + Vs) = 0.8 * (Vv + Vs)

Now we can substitute the values of the volume of water and solid in the void ratio equation

Void ratio = Vv / (0.8 * (Vv + Vs))

We can solve the above equation for Vv and plug in the values of the water content,

Vv = (0.2 * (Vv + Vs)) / (1 - 0.2) = 0.25 * (Vv + Vs)

Now we can substitute this value in the void ratio equation

Void ratio = 0.25 * (Vv + Vs) / (0.8 * (Vv + Vs)) = 0.25 / 0.8 = 0.3125

So the void ratio of this soil is 0.3125.

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Answer:

modern vehicles are made to crunch up a little bit so they that absorbe some of the impact instead of you

Explanation:

Stranded copper wire is used in most automotive electrical circuits because it is flexible, durable, and able to carry high amounts of current. The multiple strands also provide a better surface area for conducting electricity, which can improve the overall performance of the electrical system in the vehicle.

These little, bundled wires are crushed, then covered in non-conductive insulation. Because stranded wire is more flexible, it is perfect for bending and twisting to fit complex shapes or connecting electronic components in small areas. Stranded wire won't split or sever and is more malleable and flexible than solid wire. It is frequently utilised for indoor applications including speaker lines, circuit boards, and electronic devices.

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Stranded copper wire is used in most automotive electrical circuits because it is flexible, durable, and able to handle high electrical currents without overheating.

Additionally, the multiple strands of wire in a stranded copper wire provide more surface area for electrical current to flow through, reducing resistance and minimizing voltage drop.

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Answer:

P1+1/2pv2/1+pgh1=P2+1/2pv2/2+pgh2

Answer:

B

Explanation:

Aluminium doesn't rust unless exposed to copper for a duration of time.

Answer:

The shear stress will be 80 MPa

Explanation:

Here we have;

τ = (T·r)/J

For rectangular tube, we have;

Average shear stress given as follows;

Where;

\(\tau_{ave} = \frac{T}{2tA_{m}}\)

\(A_m\) = 100 mm × 200 mm = 20000 mm² = 0.02 m²

t = Thickness of the shaft in question = 2 mm = 0.002 m

T = Applied torque

Therefore, 50 MPa = T/(2×0.002×0.02)

T = 50 MPa × 0.00008 m³ = 4000 N·m

Where the dimension is 50 mm × 250 mm, which is 0.05 m × 0.25 m

Therefore, \(A_m\) = 0.05 m × 0.25 m = 0.0125 m².

Therefore, from the following average shear stress formula, we have;

\(\tau_{ave} = \frac{T}{2tA_{m}}\)

Plugging in then values, gives;

\(\tau_{ave} = \frac{4000}{2\times 0.002 \times 0.0125} = 80,000,000 Pa\)

The shear stress will be 80,000,000 Pa or 80 MPa.

The correct answer choice for implementing the enqueue() method in a queue with a linked list in Java is append().

When implementing a queue using a linked list, the enqueue operation adds an element to the end of the list, as it follows the FIFO (First-In-First-Out) principle. The append() method in the linked list class would typically be used to add a new element at the end of the list, making it the most appropriate choice for the enqueue operation.

The other answer choices are not directly related to the enqueue operation in a queue implementation using a linked list:

removeafter() is used to remove an element after a specified node, which is not necessary for the enqueue operation.

prepend() is used to add an element at the beginning of the list, which does not follow the FIFO principle of a queue.

insertafter() is used to insert an element after a specified node, but it is not typically used in the enqueue operation of a queue.

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Answer:

In series:

\( \frac{1}{r} = \frac{1}{r_{1} } + \frac{1}{r _{2} } + \frac{1}{r_{3} } \)

\( \frac{1}{r} = \frac{1}{4} + \frac{1}{6} + \frac{1}{8} \\ \\ \frac{1}{r} = \frac{13}{24} \\ \\ r = \frac{24}{13} \\ { \underline{r = 1.85 \: Ω}}\)

In parallel:

\(r = r _{1} + r _{2} + r _{3} \\ r = 4 + 6 + 8 \\ r = 18Ω\)

Since Tech B says that a metric grade 12.9 bolt is stronger than a metric 4.6 bolt. the person that is correct is option b. Tech B.

The grade of 12.9 bolt is known to be 1220 (176,000 psi). The alloy carbon steel is said to be one that is often used to make Metric 12.9 Hex Cap Screws that is heat-treated, quenched, as well as tempered.

Their strength is one that is comparable to alloy sockets, and with a proof load of 970 MPa and a minimum tensile strength of 1220 MPa.

Therefore, Since Tech B says that a metric grade 12.9 bolt is stronger than a metric 4.6 bolt. the person that is correct is option b. Tech B.

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See full question below

Tech A says that a standard grade 5 bolt is stronger than a standard grade 8 bolt. Tech B says that a metric grade 12.9 bolt is stronger than a metric 4.6 bolt. Who is correct?

a. Tech A

b. Tech B

c. both

d. neither