what can be used to power things like lightbulbs but also can be used to send and receive information?
gamma rays
Electrical circuits
Electromagnet signals
Radio waves

Answer:

The initial momentum of the bowling ball is 20 kgm/s.

Explanation:

Given;

mass of the bowling ball, m₁ = 5.0 kg

initial velocity of the bowling ball, u₁ = 4.0 m/s

mass of the Frodo, m₂ = 60 kg

initial velocity of Frodo, u₂ = 0

The initial momentum of the bowling ball is calculated as;

P = m₁u₁

P = 5 x 4

P = 20 kgm/s

Therefore, the initial momentum of the bowling ball is 20 kgm/s.

Answer:

\(\boxed {\boxed {\sf 1440 \ Joules}}\)

Explanation:

Kinetic energy can be found using this formula:

\(E_k= \frac{1}{2} mv^2\)

The mass is 20 kilograms and the velocity is 12 meters per second.

\(m= 20 \ kg \\v= 12 \ m/s\)

Substitute the values into the formula.

\(E_k= \frac{1}{2} (20 \ kg)(12 \ m/s)^2\)

Solve the exponent first.

\(E_k= \frac{1}{2} (20 \ kg)(144 \ m^2/s^2)\)

Multiply the numbers in parentheses.

\(E_k= \frac{1}{2} (2880 \ kg*m^2/s^2)\)

Multiply by 1/2 or divide by 2.

\(E_k=1440 \ kg*m^2/s^2\)

\(E_k= 1440 \ J\)

The object's kinetic energy is 1440 Joules.

Answer:

The speed at which a planet orbits the Sun changes depending upon how far it is from the Sun. When a planet is closer to the Sun the Sun’s gravitational pull is stronger, so the planet moves faster. When a planet is further away from the sun the Sun’s gravitational pull is weaker, so the planet moves slower in its orbit.

Answer:

does not have a definite shape or volume=gas

has a definite volume but has no shape=liquid

has a definite shape and volume=solid

changes to liquid on heating=melting

changes to solid on cooling=freezes

changes to liquid on cooling=condensation

Answer:

The force applied to make the object move

Answer:

input work = output work

E * ED = L* LD

Explanation:

The principle of lever is that input work is always equal to output work .

Answer:Conduction

Explanation:the transfer of heat energy occurs between two objects that are touching.

The semi-major axis of an ellipse is half the length of the longest diameter of the ellipse.

The semi-major axis of an ellipse is a fundamental parameter that determines its shape and size. It is defined as half the length of the longest diameter of the ellipse. The diameter of an ellipse is any line segment that passes through the center and has endpoints on the boundary of the ellipse. The longest diameter, also known as the major axis, is the diameter that has the largest length among all possible diameters of the ellipse.

To find the semi-major axis, we take half the length of the major axis. The major axis passes through the center of the ellipse and is the longest distance between any two points on the ellipse. By halving the length of the major axis, we obtain the semi-major axis, which represents the distance from the center to either focus of the ellipse.

The foci of an ellipse are two fixed points located on the major axis, equidistant from the center. The semi-major axis is indeed the distance between these two foci, as it is half the length of the longest diameter, which connects them. Thus, the semi-major axis provides a concise measure of the size and shape of an ellipse.

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The energy contained in a 2.83-m length of the beam is approximately 6.03 x 10^-9 J.

To calculate the energy contained in a beam of light, we need to use the formula:

Energy = Power x Time

However, we need to first find the time for a length of 2.83 m of the beam to pass by a certain point. We can do this by using the formula:

Time = Distance / Speed

The speed of light in vacuum is approximately 3 x 10^8 m/s. However, the speed of light in the beam will be slightly lower due to the refractive index of the medium through which it is traveling. For an argon-ion laser, this refractive index is close to 1, so we can assume that the speed of light in the beam is approximately the same as the speed of light in vacuum.

Therefore, the time for a length of 2.83 m of the beam to pass by a certain point is:

Time = Distance / Speed = 2.83 m / (3 x 10^8 m/s) = 9.43 x 10^-9 s

Now, we can calculate the energy contained in this length of the beam using the formula:

Energy = Power x Time

Energy = 0.639 W x 9.43 x 10^-9 s

Energy = 6.03 x 10^-9 J

Therefore, the energy contained in a 2.83-m length of the beam is approximately 6.03 x 10^-9 J.

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To determine the free vibration response of the structure of Problem 10.6 (and Problem 9.5) when it is displaced as shown in Fig. P10.8a and b and released, follow these steps:

1. First, identify the natural frequencies and mode shapes of the structure from Problems 9.5 and 10.6.

2. Next, apply the initial displacement conditions from Fig. P10.8a and b to the mode shapes.

3. Calculate the modal participation factors by taking the dot product of the initial displacement vector with the mode shapes.

4. Determine the amplitude of vibration for each mode by dividing the modal participation factor by the natural frequency of the corresponding mode.

5. The free vibration response can now be calculated as a linear combination of the mode shapes, scaled by their respective amplitudes and time-varying factors (e.g., sine or cosine of the natural frequency multiplied by time).

Regarding the relative contributions of the two vibration modes to the response produced by the initial displacements:

- If the modal participation factor for one mode is significantly larger than the other, it indicates that the corresponding mode contributes more to the overall response.

- In contrast, if the modal participation factors are similar in magnitude, both modes contribute comparably to the overall response.

It is important to neglect damping in this analysis to focus on the inherent characteristics of the structure and the initial displacements.

This will provide a simplified yet insightful understanding of the structure's free vibration response.

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El flujo magnético a través de una bobina con 460 vueltas de superficie de 2 m² cuyo eje forma un ángulo de 60 ° con un campo magnético uniforme de 2 es 779.42 Weber

La fórmula para calcular el flujo magnético a través de una bobina se expresa como:

\(\phi = NABsin\theta\) dónde:

Dados los siguientes parámetros

N = 450 turns

A = 2 m²

B = 2

\(\theta\) = 60degrees

Sustituya los parámetros dados en la fórmula como se muestra:

\(\phi=450 \times 2\times 2sin60^0\\\phi = 900sin60^0\\\phi = 900(0.8660)\\\phi=779.42Weber\)

El flujo magnético a través de una bobina con 460 vueltas de superficie de 2 m² cuyo eje forma un ángulo de 60 ° con un campo magnético uniforme de 2 es 779.42 Weber

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Answer:

Burning fossil fuels contributes to climate change.

Fossil fuels are nonrenewable.

Explanation:

Fossil fuels are fuels formed from the remains of dead organic matters that have long been buried under the ground while hydrogen fuel cells are formed from electrochemical reactions.

Fossil fuel burning creates pollution in the environment and some of the pollutants generated contribute to global warming and associated climate change. This is as opposed to fuel cells that generate power through electrochemical reactions and whose products can be converted for other uses.

Also, fossil fuel deposits are finite and non-renewable. Once their deposits become exhausted, there is no way to artificially regenerate them unlike fuel cells.

Answer:

i hope this helps

Explanation:

At the instant where the cart leaves the ramp, the velocities of the ramp and the cart are relative to the ground as \((mgh/m+M)^{1/2}\) and \((2gh(m+M)/3m)^{1/2}\) respectively.

The velocities of the ramp and cart relative to the ground at the instant the cart leaves the ramp can be calculated using conservation of energy and momentum. The velocity of the cart relative to the ground can be found using conservation of energy as follows:

mgh = 1/2mv² + 1/2Iw²

where m is mass of cart, g is acceleration due to gravity, h is height of ramp, v is velocity of cart relative to ground, I is moment of inertia of ramp about its center of mass and w is angular velocity of ramp about its center of mass.

The velocity of ramp relative to ground can be found using conservation of momentum as follows:

mv = (m+M)V

where M is mass of ramp and V is velocity of ramp relative to ground.

Solving these equations simultaneously gives:

\(V = mgh/(m+M)^{1/2}\)

\(v = 2gh(m+M)/(3m)^{1/2}\)

where h = height of ramp.

Therefore, at the instant when cart leaves the ramp, velocity of cart relative to ground will be \((2gh(m+M)/(3m))^{1/2}\) and velocity of ramp relative to ground will be \((mgh/(m+M))^{1/2}\).

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Answer:

Plug in the given values and solve for the final velocity. Remember, when the ball is on the ground it has a height of zero.

Explanation:

The extra cost of fuel for driving 83 mph instead of 73 mph is $3.7671.

The speed of your automobile has a huge effect on fuel consumption. Traveling at 65 miles per hour (mph) instead of 55mph can consume almost 20% more fuel. As a general rule, for every mile per hour over 55 , you lose 2% in fuel economy.

If you take a 400-mile trip and your average speed is 83mph rather than the posted speed limit of 73mph, then the extra cost of the fuel is calculated as:

* **Fuel consumption at 83 mph:** 30 mpg * (1 - 2% * (83 - 55)) = 27.6 mpg

* **Fuel consumption at 73 mph:** 30 mpg * (1 - 2% * (73 - 55)) = 29 mpg

* **Extra fuel used:** 400 miles / 27.6 mpg - 400 miles / 29 mpg = 2.4 gallons

* **Extra cost of fuel:** $3.26/gallon * 2.4 gallons = $3.7671

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Scientific experiments follow principles called the scientific method that ensure that accurate tests are performed, reliable results are collected, and reasonable conclusions are drawn. Scientific experiments must follow the basic principles of good research so that the final presented results can be believed to be reliable.

Observations of new physical processes or phenomena occur infrequently, but there are areas of science that are not fully understood. Scientists must verbalize their observations in order to formulate meaningful hypotheses.

It's not enough to just guess why something happens. Scientists must prove their theories to be correct. Predictions are made to test observations under different circumstances. The aim is to learn more about this phenomenon and prove its existence. One of his ways of improving the scientific method is by creating 'models'. Models can be used to infer difficult and unobservable concepts.

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Answer:

They are temperature, atmospheric pressure, wind, humidity, precipitation, and cloudiness. Together, these components describe the weather at any given time.

Answer:

electrical to mechanical

Explanation:

Answer:

The velocity of the car of mass 4 kg with respect to ground is 0 m/s

Explanation:

The problem initially stated that the car is at rest. at this stage, the velocity of the car relative to the ground is already = 0 m/s.

When the 10 kg car began to move, the problem did not specify at any point that the 4 kg car began to move also. Hence, the motion of the 10 kg car did not affect the 4 kg car in any way.

As a result, relative to the ground, the velocity of the 4 kg car is still 0 m/s since no motion was recorded by the car.

Answer:

C

Explanation:

When light transitions from the air to the water the light bends due to refraction. The refractive index is related to the speed of light in both air and water. The Wikipedia article on Refraction does and excellent job of explaining this.

Answer:

The correct option is C. A picture of a straw in a glass of water showing the shift in position of the straw due to the water.

Explanation:

Hope this helps you. Have a nice day ahead( ; ^_^

Two vinyl balloons with an identical charge are given a separation distance of 52 cm. The balloons experience a repulsive force of 2.74x10³ N. then  magnitude of charge on each one of the balloons is

According to the law, the strength of the electrostatic force of attraction or repulsion between two point charges is inversely proportional to the square of the distance between them and directly proportional to the product of the magnitudes of the charges. Coulomb investigated the repellent force between things with identical electrical charges:

Given,

F = 2.74x10³ N.

r = 52 × 10 ⁻² m

Coulomb's law is given by,

F = q₁q₂ ÷ 4π∈r²

2.74x10³ N = q₁q₂ ÷ 4π 8.85×10⁻¹² × (52 × 10 ⁻²)²

2.74x10³ N = q₁q₂ ÷ 3 × 10⁻¹¹

q₁q₂ = 2.74x10³ ×  3 × 10⁻¹¹

q² = 8.2 × 10⁻⁸

q = 2.8 × 10⁻⁴ C

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Answer:

2.5

Explanation:

The equivalent resistance of the combination of the two same

resistors when connected in parallel is 0.4 ohms.

There are two types of connection of resistor-

          \(R_{eq}=R_1+R_2+....R_n\)

        \(R_{eq}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+....\dfrac{1}{R_n}\)

A combination of two identical resistors connected in series has an equivalent resistance of 10 ohms. As these two resistor has the same resistance, say (R). Thus,

\(R_{eq}=R+R10=2R\\R=5\rm\; ohm\)

Equivalent resistance, when connected in parallel, is,

\(R_{eq}=\dfrac{1}{R}+\dfrac{1}{R}\\R_{eq}=\dfrac{1}{5}+\dfrac{1}{5}\\R_{eq}=\dfrac{2}{5}\\R_{eq}=0.4\rm\; ohm\)

The equivalent resistance of the combination of the two same

resistors when connected in parallel is 0.4 ohms.

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We want to see if the Trust SSC can archive a higher maximum speed.

Remember the second Newton's law:

Force = mass*acceleration.

And acceleration is the rate of change of the velocity.

Assuming the mass of the Trust SSC does not change, increasing the force would mean that we increase the acceleration, and thus, larger velocities can be reached.

Now there are some problems.

How we do increase the force?.

It is hard to ve precise, mostly because we don't really know how the system works, we just got some given random data that we can't use without context.

Another thing we need to remember, this velocity is measured in only one mile. So because we have a fixed distance to measure it, we only can get larger velocities by increasing the acceleration.

And to increase the acceleration we can increase the force, as discussed, or, decrease the mass.

How to decrease the mass? Using lighter materials.

Now let's see an example on how decreasing the mass would affect the acceleration.

Then an aproximate force is given by:

F = 10,700kg*20.8 m/s^2 = 222,560 N

Now, if we decrease the mass a little bit, for example to 10,000kg, and we do not change the force, the new acceleration will be given by:

10,000kg*a = 222,560 N

a = (222,560 N)/(10,000kg) = 22.3 m/s^2

So decreasing the mass a little, increases the acceleration, which would make a larger maximum velocity.

Concluding, there are two ways of increasing the maximum velocity:

Increasing the force.

Decreasing the mass of the car.

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The final charge on the capacitor is 72 μC.

We can use the formula for the charge on a capacitor in an RC circuit:

Q = C * V * (1 - e^(-t/RC))

where

Q is the charge on the capacitor,

C is the capacitance,

V is the voltage of the battery,

t is the time,

R is the resistance, and

e is the mathematical constant approximately equal to 2.71828.

Given: V = 8.0 V, R = 1 Ω, C = 9 μF, and the capacitor is initially uncharged.

Since the capacitor is initially uncharged, we can assume that Q = 0 at t = 0.

Then, we can solve for Q at t → infinity:

Q = C * V * (1 - e^(-t/RC))

Q = 9 μF * 8.0 V * (1 - e^(-∞))

Q = 9 μF * 8.0 V * (1 - 0)

Q = 72 μC

Therefore, the final charge on the capacitor is 72 μC.

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Horizontal divergence occurs to the east of an upper-air trough. This is because upper-air troughs are regions of low pressure where the air is rising and converging.

As the air rises, it cools and condenses, leading to the formation of clouds and precipitation. As a result, there is a surplus of air at the upper levels, which creates a region of low pressure.

To balance out this low pressure region, air from the surrounding areas flows towards the trough. As this air flows towards the trough, it converges and rises, causing further cooling and precipitation. However, once the air reaches the trough, it can no longer converge and rise. Instead, it must diverge and flow outwards in order to balance out the low pressure region.

This horizontal divergence to the east of the trough creates a region of sinking air and high pressure. As the air sinks, it warms and dries out, leading to clear skies and fair weather conditions. In summary, horizontal divergence occurs to the east of an upper-air trough as a result of the need to balance out the low pressure region created by the rising air within the trough.

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The Mercalli scale would most likely be used to tell how much earthquake damage was done to homes and other buildings.

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It should be noted that after the big bang occurred, the universe "Became Denser" (Option B)

According to the Big Bang Theory, after the explosion which triggered the transformation of radiation into matter, gravity pulled dark matter together which in turn attracted normal matter.

Hence, it is right given the above analogy that the Universe became denser.

It should be mentioned that the big-bang hypothesis is a widely accepted account of the universe's evolution. Its defining characteristic is the universe's birth from a condition of great heat and density—the so-called big bang, which occurred 13.8 billion years ago.

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Answer:

12 (Magnesium- Mg)

Explanation:

Looking at the four numbers, we have:

Magnesium, Silicon, Sulfur, and Chlorine.

We can eliminate two of the answers immediately just by looking at the periodic table.

Sulfur and Chlorine are on the nonmetal side of the periodic table. So that's definitely not it. That leaves Magnesium and Silicon.

Silicon is a Metalloid. Magnesium is an Alkaline earth Metal.

Metaloids are elements that have a mix of both metal and nonmetal properties (luster, how it feels, etc.). Since it's a MIX and Magnesium is just straight METAL-

We can say Magnesium has the most metallic properties.

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