What are some applications of flame tests in industry? Describe at least three, one of them MUST include
firework industry.

Answer:

Fossils of the same animals have been found on South America and on Africa.

Africa and South America look as if they could be fit together perfectly (they almost can!)

Explanation:

Basically, the idea is that South Africa and Africa were once the same landmass. The same animals lived in that landmass, but when they broke off, then the animals were on different continent, yet they came from the same place.

Answer:

The effect of the incorporation of the bill of rights was that state governments were required to provide most bill of rights protections.

Explanation:

The median of the following set of data (39.8, 39.6, 39.2, 39.6 and 39.5) is 39.6.

Median is a number separating the higher half from the lower half of a data sample, population, or probability distribution.

The median of a finite list of numbers can be found by arranging all the observations from lowest value to highest value and picking the middle one (e.g., the median of {3, 3, 5, 9, 11} is 5.

The following set of data was given this question;

39.8, 39.6, 39.2, 39.6 and 39.5

We arrange these data as follows:

39.2, 39.5, 39.6, 39.6, 39.8

The middle number or median is 39.6

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Sodium dichromate is the empirical formula for the chemical.

An allotrope of carbon with the chemical formula carbon 6, benzotriyne or cyclo[6]carbon is a hypothetical molecule. Six carbon atoms form the molecule's ring, which is joined by alternating triple and single bonds.

We must identify the compound's simplest whole-number atom ratio in order to obtain the empirical formula. To begin, we can convert the masses of each element to moles as follows:

moles of sodium = 29.84 g / 22.99 g/mol = 1.299 mol

moles of creatinine = 67.49 g / 52.00 g/mol = 1.298 mol

moles of oxygen = 72.67 g / 16.00 g/mol = 4.542 mol

sodium.creatinine.oxygen = 1.299 mol / 1.298 mol : 1.298 mol / 1.298 mol : 4.542 mol / 1.298 mol

sodium.creatinine.oxygen = 1.001 : 1.001 : 3.500

sodium.creatinine.oxygen = 1001 : 1001 : 3500

sodium.creatinine.oxygen = 1001/GCF : 1001/GCF : 3500/GCF

sodium.creatinine.oxygen = 143 : 143 : 500.

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The heat capacity of liquid is  1.53 J/ g°C

Heat capacity measures the energy required to raise temperature of a unit mass of a substance by a unit degree

Formula used:

          Q = m × c ×  ΔT

               = m × c × ( T₂ - T₁ )

where,

Q = Amount of heat gained or lost  = 53 J

m = mass of liquid = 15 g

c = specific heat of liquid = ?

ΔT = change in temperature

T₁ = initial temperature = 10.7 °C

T₂ = final temperature = 13 °C

Substituting the values in the formula

        53 J = 15 g × c × ( 13 - 10.7) °C

         53 J = 15 g × c × 2.3 °C

             c = 53/ ( 15 × 2.3 )

                = 1.53 J/ g°C

Thus we can conclude that the heat capacity of liquid is  1.53 J/ g°C

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NaHCO₃ → Na₂CO₃ + CO₂+ H₂O is an chemical equation for the enthalpy of formation of NaHCO₃. The correct constituent elements will be Na(s), H₂(g), O₂(g).

Sodium carbonate as well as washing soda or the soda ash is the sodium salt of the carbonic acid. It is prepared by passing the carbon dioxide gas in a concentrated solution of the sodium hydroxide. Further on heating, sodium bicarbonate gives sodium carbonate, CO2 and water.

NaHCO₃ → Na₂CO₃ + CO₂(g) + H₂O(l)

Sodium bicarbonate, also known as sodium hydrogen carbonate, or the bicarbonate of soda, NaHCO₃  is the source of carbon dioxide and so it is used as an ingredient in baking powders, in effervescent salts as well as beverages, and as the main constituent of the dry-chemical fire extinguishers.

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A. When the number of bonding is equal to the number of non bonging electrons.

Geometry of molecules: The geometry of a molecule determines the reactivity, polarity and biological activity of that molecule. Electron arrangement: electron geometry is found by taking both lone electron pairs and bonds in a molecule.

In atomic physics and quantum chemistry, the electron configuration exists as the distribution of electrons of an atom or molecule in atomic or molecular orbitals.

Molecular geometry, also understood as the molecular structure exists as the three-dimensional structure or arrangement of atoms in a molecule. Understanding the molecular structure of a compound can assist specify the polarity, reactivity, phase of matter, color, magnetism, as well as biological activity.

An electron arrangement exists as a path in which electrons are placed in an atom.

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1.6×10²³ atoms of F are there in  5.54 g of   F\(_2\). It is also the smallest piece of substance with chemical element-like characteristics.

The smallest unit of matter that may be split without producing electrically charged particles is the atom. It is also the smallest piece of substance with chemical element-like characteristics. As a result, the atom serves as the fundamental unit of chemistry.

Space makes up the majority of an atom. The remainder is made up of a cloud of electrons with negative charges around a positive-charged nucleus made up of protons and neutrons.

moles of F\(_2\)=5.54 / 37.9=0.14

number of atoms of  F\(_2\) = 0.14×6.022×10²³=8.4×10²²atoms

number of atoms of  F=2×8.4×10²²atoms=1.6×10²³ atoms

Therefore, 1.6×10²³ atoms of F are there in 5.54 g of   F\(_2\).

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Answer:

Okay I will, Maritime tropical (mT) air masses are warm, moist, and usually unstable. Some maritime tropical air masses originate in the subtropical Pacific Ocean, where it is warm and air must travel a long distance over water. These rarely extend north or east of southern California.

got it

Explanation:

In air mass. The maritime Tropical (mT) is the most important moisture-bearing and rain-producing air mass throughout the year. In winter it moves poleward and is cooled by the ground surface. Consequently, it is characterized by fog or low stratus or stratocumulus clouds, with drizzle and poor visibility.

The oxidation state of nitrogen (N) in NaNO3 is +5. option B

To determine the oxidation state of nitrogen (N) in sodium nitrate (NaNO3), we need to assign oxidation numbers to each element in the compound.

In NaNO3, we know that the sodium ion (Na+) has a +1 oxidation state because it is an alkali metal. Oxygen (O) typically has an oxidation state of -2 in compounds, and there are three oxygen atoms in NaNO3. Since the compound is neutral, the sum of the oxidation states must be zero.

Let's assume that the oxidation state of nitrogen is x. Therefore, we can set up the equation:

(+1) + x + (-2) * 3 = 0

Simplifying the equation:

+1 + x - 6 = 0

x - 5 = 0

x = +5

Therefore, the oxidation state of nitrogen (N) in NaNO3 is +5.

The oxidation state of an element indicates the number of electrons it has gained or lost in a compound. In this case, the nitrogen atom in NaNO3 has gained five electrons to achieve a stable oxidation state of +5.

It is important to note that oxidation states are formal charges and do not necessarily represent the actual distribution of electrons in a compound. They are assigned based on a set of rules and can be useful in understanding the reactivity and behavior of elements in chemical reactions.

Option B

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The student's method for preparing pure crystals of copper sulfate contains errors and does not produce the desired outcome.

Use copper oxide instead of calcium carbonate: The student should add copper oxide (CuO) to the hydrochloric acid instead of calcium carbonate. Copper oxide reacts with hydrochloric acid to form copper chloride, which can then be converted to copper sulfate through a subsequent reaction with sulfuric acid.

Add sulfuric acid to the copper chloride solution: After the copper chloride solution is formed, the student should add sulfuric acid to it. This reaction between copper chloride and sulfuric acid will yield copper sulfate and hydrochloric acid. The student should ensure that the correct stoichiometric ratio is maintained to maximize the yield of copper sulfate crystals.

Crystal formation: The student should allow the solution to cool slowly after the reaction with sulfuric acid. This promotes the formation of larger, well-defined copper sulfate crystals.

Filtration and drying: Once the crystals have formed, the student should filter the solution to separate the solid crystals from the remaining liquid. The filtered crystals should then be thoroughly dried to remove any remaining water, resulting in pure copper sulfate crystals.

By following these improvements, the student can obtain pure crystals of copper sulfate.

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Taking into account the definition of pH and pOH, the OH- ion concentration in the solution is 1×10⁻⁶ M and the solution is basic.

The pH is a coefficient that indicates the degree of acidity or basicity of an aqueous solution and indicates the amount of hydrogen ions present in a solution or substance.

The pH is defined as:

pH= - log [H⁺]= - log [H₃O⁺]

Neutral pH is 7: if the number is higher, the solution is basic, and if it is lower, it is acidic.

Similarly, pOH indicates the amount of hydroxyl ions and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:

pOH= - log [OH⁻]

The relationship between pH and pOH  can be established as:

pOH + pH= 14

Being [H⁺]=1×10⁻⁸ M, the pH is calculated as:

pH= - log (1×10⁻⁸ M)

Solving:

pH= 8

The solution is basic because the pH is greater than 7.

Being pH= 8, pOH is calculated as:

pOH + 8= 14

pOH= 14 - 8

pOH= 6

Replacing in the definition of pOH the concentration of OH⁻ ions is obtained:

- log [OH⁻]= 6

Solving:

[OH⁻]= 10⁻⁶

[OH⁻]=1×10⁻⁶ M

In summary, the [OH⁻] is 1×10⁻⁶ M.

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Atomic number of Technetium is 43, Mass number is 99  and symbol is Tc ,hence symbol of isotope is  99 m43 Tc

General representation of atom is AZ X

Where ,  A is mass number , Z is atomic number and X is symbol of element. Atomic number of Technetium is 43, Mass number is 99  and symbol is Tc ,hence symbol of isotope is  99 m43 Tc ,Where m stands for meta stable.

A chemical element with the atomic number 43 and the symbol Tc is known as technetium. It is the lightest element whose radioactive isotopes are all present. Technetium is a synthetic element that is created in abundance. The most prevalent source of naturally occurring technetium is uranium and thorium ores, where it spontaneously fissions as a byproduct, while molybdenum ores produce it as a byproduct of neutron capture. This crystalline, silvery-gray transition metal in group 7 of the periodic table is sandwiched between rhenium and manganese, and its chemical characteristics fall somewhere in the middle of the two nearby elements. Only in traces, 99Tc is the most prevalent naturally occurring isotope.

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In the given Galvanic cell, the electrons are flowing from left to right. The Zinc is oxidized into Zn²⁺ ions.

A galvanic cell can be described as an electrochemical cell in which electricity is produced from spontaneous Oxidation-Reduction reactions. Galvanic cells exhibit spontaneous redox reactions but the energy generated from the said reaction.

A common apparatus of the galvanic cell consists of two different metals or electrodes such as Zinc and copper electrodes, each immersed in different beakers containing their respective ion solution. Therefore, the Zinc electrode is placed in ZnSO₄ solution and the copper electrode is placed in CuSO₄ solution.

On the left end, the zinc metal is oxidized into Zn²⁺ ions, and the electrons from the Zinc electrode travel to the copper electrode (right end). The cooper Cu²⁺ ions from the CuSO₄ solution accepts those electrons and deposit as copper metal on the copper electrode.

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bro hwnsbsjqjsnanqbsbjsjwhsshjs incorjssnsn

Answer:

The possible mass of the number of sodium is 23amu

Answer:

Rights

Explanation:

Every human has their rights such as those stated. These rights are what is protected by law.

Answer:

nope nope nope nope nope nope nope nope

Answer:

Al= (27/78)x100

Al= 34.6%

O= (48/78)x100

O= 61.5%

H= (3/78)x100

H= 3.85%

Answer:

B

Explanation:

the group number is=valence electrons. element 1 is in group 1 element 18 is in group 8. 1<8

Answer:

the answer is b

Explanation:

i just know

The concentration of all the species that are in the solution is 0.008 M.

We know that when we dissolve potassium fluoride in solution that it form the acid which is hydro fluoric acid and as such the solution would become acidic. We can now set up the ICE table as we see it below;

                    HF(aq)   +  \(H_{2} O\)(l)    ⇔   \(H_{3} O^+\)(aq)  + \(F^-\)(aq)

I                  0.11                                     x                 x

C                 -x                                       +x                +x

E               0.11 - x                                   x                  x

Ka = [ \(H_{3} O^+\)] [ \(F^-\)]/[HF]

6.3 * 10^-4 = x^2/0.11 - x

6.3 * 10^-4(0.11 - x) = x^2

6.93 * 10^-5 - 6.3 * 10^-4x = x^2

Using the quadratic method;

x^2 + 6.3 * 10^-4x - 6.93 * 10^-5 = 0

x=0.008 M

Hence;

[ \(H_{3} O^+\)] = [ \(F^-\)] = [\(K^+\)] = 0.008 M

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Li is the highest ionization energy

After 3 half-life, 12 of the 14 of the C-14 = 18 of the C-14 would remain.

?????????????????????????????????????????

Answer:

2.6622592x10^-20 grams

Explanation:

Mass of single atom of 500 sulfur is 20 grams.

Sulfur is the most vital minerals which is enormously available in the human body, it holds a significant role in the  processes like making proteins, gene expression regulation, building, and repairing DNA, it also support other metabolism.

Sulfur is the major element in the environment, is a key element of many fresh produces, body also uses sulfur for different bodily functions like building and repairing DNA,

It protect the cells against damage which is essential for the addition of number of sulfur-rich foods into the diet for optimal health and well-being.

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Answer:

That is correct my dude

Explanation:

\(\huge\underline\mathbb\pink{ANSWER\::}\\\\\)

_BaS + _PtF2 → _BaF2 + _Pts

Barium Sulfide + Platinum(II) Fluoride = Barium Fluoride + Platinum(II) Sulfide.

=> 1 BaS + 1 PtF2 → 1 BaF2 + 1 PtS

\(\\\\\\\)

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plot(density(x),col = "blue") #As we can see the distribution is fairly Normal

q q line(x, col = "blue") #In Q Q P Lot the straight blue line should pass through maximum number of point at 45 degree (x, col = "blue", freq = FALSE)

lines(density(x), col = "red", lwd = 2) #We can also check distribution of Normal by Histrogram and superimpose red line

ad .test(x) #Anderson Darling test gives p value 0.1424 that mean there is 14.24 percent chance that his data is coming from Normal

t(x) Cramer-von Mises test gives p value 0.2147 that mean there is 21.47 percent chance that his data is coming from Normal

Llliefors (Kolmogorov-Smirnov) test gives p value 0.2355 that mean there is 23.55 percent chance that his data is coming from Normal

Pearson chi-square test gives p value 0.7301 that mean there is 73.01 percent chance that his data is coming from Normal

Shapiro- Francia test gives p value 0.03482 that mean there is 3.48 percent chance that his data is coming from Normal

Shapiro-Wilks test gives p value 0.07154 that mean there is 7.15 percent chance that his data is coming from Normal

#If p-value <= Alpha(=0.05) reject null hypothesis(i.e sample points comes from Normal Population) but we take Shapiro-Wilks test into account because it is distribution free and regarded as best test for Normality hence we accept the null hypothesis and conclude that the sample comes from Normal Distribution but it is not very much likely.

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