The required average compressive strength is 625 psi, 500 psi, and 750 psi respectively.
What is compressive strength?Compressive strength is the ability of a material or structure to withstand loads that tend to reduce size. In other words, compressive strength resists compression, whereas tensile strength resists tension.
The required average compressive strength for concrete can be determined using the following formula:
f'c = 1.25s
Where f'c is the required average compressive strength and s is the standard deviation of the compressive strength.
a. Since the standard deviation (s) is unknown for a new plant, the required average compressive strength cannot be determined.
b. For a plant where s = 500 psi for 22 test results:
f'c = 1.25s
f'c = 1.25(500)
f'c = 625 psi
Therefore, the required average compressive strength is 625 psi.
c. For a plant with extensive history of producing concrete with s = 400 psi:
f'c = 1.25s
f'c = 1.25(400)
f'c = 500 psi
Therefore, the required average compressive strength is 500 psi.
d. For a plant with extensive history of producing concrete with s = 600 psi:
f'c = 1.25s
f'c = 1.25(600)
f'c = 750 psi
Therefore, the required average compressive strength is 750 psi.
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Which of the following are examples of
engineering controls? Select all that apply.
.
Steps for removing used medical exam gloves
Washing stations
Biohazard waste containers
Spill clean up kits
Sharps containers
The examples of engineering controls is Biohazard waste containers and Spill clean up kits.
What is engineering controls?An engineering controls is a workplace process that protect workers by removing hazardous conditions or by placing a barrier between the worker and the hazard.
An example of engineering controls is installation of exhaust ventilation to remove airborne emissions to shield the worker.
Hence, the examples of engineering controls is Biohazard waste containers and Spill clean up kits.
Therefore, the Option C and D is correct.
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When current flows through an electrical component due to a potential difference,
electrical - is produced.
Answer:
Ohm, a german physicist, found experimentally that the current in a metal conductor is directly proportional to the potential difference across its ends
Explanation:
Which starting circuit uses fuses, switches, and smaller wires to energize a relay and solenoid?
Starter Main Circuit
Starter Control Circuit
Starter Ground Path
Battery Positive Cable
Answer:
Option B (Starter Control Circuit) is the right option.
Explanation:
This same switching is normally put upon this isolated side of something like the transmission Arduino microcontroller throughout the configuration that is using the ignition just to command the broadcast.It uses a secondary relay isolated to regulate electrical current throughout the solenoid starting system.All other given options are not related to the given instance. So the above option is correct.
Please answer all the questions including the sub-questions.
Any copied, especially open ended questions for example question (b) ii, or questions not or partially answered will be downvoted.
Kindly show your step-by-step workings clearly. This will be a plus point to upvote. Thanks
b. Gas turbines can also operate in open cycle mode, for which exhaust gas temperatures exiting the gas turbine may be around 150
∘
C. i. Calculate the maximum theoretical efficiency of open cycle gas turbine (OCGT) power plants assuming a heat source temperature of 1500
∘
C. ii. In spite of its lower efficiencies, OCGT may still be useful in power systems. Describe some of the techno-economic advantages of OCGT compared to CCGT, and possible applications of OCGT that could be cost-competitive, and provide reasons why.
Open cycle gas turbines (OCGT) offer certain techno-economic advantages compared to combined cycle gas turbines (CCGT), and they have specific cost-competitive applications due to their characteristics.
What are the techno-economic advantages of OCGT compared to CCGT, and what are some cost-competitive applications of OCGT?Lower initial capital costs: OCGT plants generally have lower construction and installation costs compared to CCGT plants.
Quick start-up and shutdown: OCGT plants can be rapidly started and stopped, making them suitable for meeting peak demand or providing backup power.
Flexibility: OCGT plants can operate on various fuels, including natural gas, diesel, or liquid fuels, providing fuel flexibility and adaptability.
Modularity: OCGT plants can be built in smaller modules, allowing for incremental capacity additions and reducing the need for large-scale investments.
Peaking power plants: OCGT plants are well-suited for meeting short-term peak electricity demand due to their rapid start-up capabilities.
Distributed generation: OCGT plants can be located near the demand centers, reducing transmission losses and enhancing grid stability.
Remote or off-grid locations: OCGT plants can provide power to remote or isolated areas where connection to the main grid is challenging or costly.
Industrial applications: OCGT plants can be utilized in industries requiring both electricity and process heat, such as desalination plants or chemical manufacturing.
These advantages and applications make OCGT a viable and cost-effective option in certain scenarios.
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A useless state in a TM is one that is never entered on any input string. Consider the problem of determining whether a TM has any useless states. Formulate this problem as a language and show that it is undecidable. (i.e. show that USELESSTM = {q is a useless state in TM M } is undecidable).
The answer is therefore "yes." A TM accepts an empty string if the initial state is an accepting state or it can transition to an accepting state on the input tape's "B" symbol (similar to finite automata).
Accepts empty strings as input in a Turing machine?The answer is therefore "yes." A TM accepts an empty string if the initial state is an accepting state or it can transition to an accepting state on the input tape's "B" symbol (similar to finite automata).ATM can be identified by Turing: TM R for ATM recognizer: Input string "M,w": M on w is simulated. REJECT M,w> if M halts & rejects (Loop (& so reject M,w>) if M ends up looping). ACCEPT M,w> if M halts & accepts w.Undecided regarding 2 Halt Empty TM. Proof: Through ATM decrease. Assume that R serves as a Turing machine that decides Halt Empty TM. Using R, we build an ATM that makes decisions.To learn more about Empty string refer to:
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A motor car shaft consists of a steel tube 30 mm internal diameter and 4 mm thick. The engine develops 10 kW at 2000 r.p.m. Find the maximum shear stress in the tube when the power is transmitted through a 4: 1 gearing.
The maximum shear stress in the tube when the power is transmitted through a 4: 1 gearing is 28.98 MPa.
What is power?Power is the energy transferred per unit time.
Torque is find out by
P = 2πNT/60
10000 = 2π x 2000 x T / 60
T =47.74 N.m
The gear ratio Ne / Ns =4/1
Ns =2000/4 = 500
Ts =Ps x 60/(2π x 500)
Ts =190.96 N.m
Maximum shear stress τ = 16/π x (T / (d₀⁴ - d₁⁴))
τ max =T/J x D/2
where d₁ = 30mm = 0.03 m
d₀ = 30 +(2x 4) = 38mm =0.038 m
Substitute the values into the equation, we get
τ max = 16 x 190.96 x 0.038 /π x (0.038⁴ - 0.03⁴)
τ max = 28.98 MPa.
Thus, the maximum shear stress in the tube is 28.98 MPa.
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What is the eye an example of?
sense organ
stimulus
a relay neuron
sens organ is the eye example
While bowling with friends, Brandy rolls a strike in 2 out of 10 frames. What is the experimental probability that Brandy will roll a strike in the first frame of the next game? Enter your answer as a simplified fraction
The experimental probability of Brandy rolling a strike in the first frame of the next game is 1/5.
Given that Brandy rolls a strike in 2 out of 10 frames in a game, we can calculate the experimental probability of her rolling a strike in the first frame of the next game. Since there are 10 frames in a game, the probability of Brandy rolling a strike in any given frame is 2/10 or 1/5. Therefore, the experimental probability of her rolling a strike in the first frame of the next game is also 1/5. This is based on the assumption that her performance in each frame is independent of the others, and the probability remains constant from frame to frame.
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Swing arm restraints are intended to prevent a vehicle from falling off a lift.
The question is asking whether that statement is true or false. Options are;
A) True
B) False
We want to know whether it is true or false that Swing arm restraints are intended to prevent a vehicle from falling off a lift and the answer is;
Option B; False
There are different safety features that people employ when a vehicle is lifted. However, for this question, we will only talk about swing arm restraints.Swing arm restraints are lifting restraint devices that are used to prevent a cars arms from shifting or going out of position after that car has been lifted and mounted.This swing arm restraint does not prevent a vehicle from falling off a lift as it just helps to ensure that the swing arms that are unloaded basically maintain their position.Read more at; brainly.com/question/17972874
1. Gas Metal Arc Welding is also known as
welding.
Answer: metal inert gas (MIG) welding
Explanation:
Gas metal arc welding (GMAW), also called metal inert gas (MIG) welding, is an arc welding process in which the heat for melting the metal is generated by an electric arc between a consumable electrode and the metal (Fig.
How does inductive reactance depend on the frequency of the ac voltage source and the rms current through the inductor?.
Directly proportional.
As the inductive reactance is directly proportional to the frequency, by increasing the frequency the inductive reactance of the inductor increases.
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ANSER QUICKLY ONLY HAVE 2 HOURS ON THIS TEST
A system of symbols and pictures used to inform others on the life and culture of a civilization is known as
Answer:
It is known as (PCS)
Explanation:
That sounds a lot like:
hieroglyphics(aka. a stylized picture of an object representing a word, syllable, or sound, as found in ancient Egyptian and other writing systems.)
which of these parts serves as the front end cross structure on most vehicles?
Answer:
Rear body panel. Rear bumper cover. Rear rails.
Explanation:
The body parts that serves as front end cross structures of vehicles are Rear body panel , front bumper and rear nails
What is Front end cross structure of automobilles?Front end cross structures refers to several frontal parts or part that are located at the front of automobilles that define it's appearance and it's effective workability. The frontal parts are essential for the effective running of the vehicles and also define the vehicles appearance.
Therefore, The body parts that serves as front end cross structures of vehicles are Rear body panel , front bumper and rear nails.
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Two chambers with the same fluid at their base are
separated by a 30-cm-diameter piston whose weight is 25
N. Calculate the gage pressures in chambers A and B
Answer:
Pgage at A = 101.30354 kPa
Pgage at B = 101.29646 kPa.
Explanation:
To calculate the gauge pressures in chambers A and B, we need to use the formula:
Pressure = Force / Area
where force is the net force acting on the piston and area is the cross-sectional area of the piston.
First, let's calculate the net force acting on the piston. We know that the weight of the piston is 25 N, which is acting downwards. We also know that the piston is in equilibrium, so the net force acting on it is zero. Therefore, there must be an upward force acting on the piston that is equal in magnitude to the weight of the piston. This upward force is the pressure difference between the two chambers pushing up on the piston.
The area of the piston is given by:
Area = pi * (diameter/2)^2
= pi * (30 cm / 2)^2
= 706.9 cm^2
Now we can calculate the pressure difference between the two chambers:
Pressure difference = Force / Area
= 25 N / 706.9 cm^2
= 0.0354 N/cm^2
Since the fluid in both chambers is at the same level, the pressure in chamber A is equal to the atmospheric pressure plus the pressure difference, and the pressure in chamber B is equal to the atmospheric pressure minus the pressure difference. Assuming the atmospheric pressure is 101.3 kPa, we can calculate the gauge pressures in chambers A and B as follows:
Pressure in A = Atmospheric pressure + Pressure difference
= 101.3 kPa + 0.0354 N/cm^2
= 101.3 kPa + 0.00354 kPa
= 101.30354 kPa
Pressure in B = Atmospheric pressure - Pressure difference
= 101.3 kPa - 0.0354 N/cm^2
= 101.3 kPa - 0.00354 kPa
= 101.29646 kPa
Therefore, the gauge pressure in chamber A is 101.30354 kPa and the gauge pressure in chamber B is 101.29646 kPa.
it is not recommended that idler pulleys be used to add tension because _________.
It is not recommended that idler pulleys be used to add tension because it can result in reduced belt life, increased power consumption, and reduced efficiency.
An idler pulley is a small wheel that guides a belt. Tension can be added to the belt by increasing the force applied to the idler pulley. However, it is not recommended to use idler pulleys for this purpose because of the following reasons:
1. Reduced belt life: If the idler pulley is used to add tension, it can cause excessive wear and tear on the belt. This can result in a shorter lifespan for the belt.
2. Increased power consumption: If the idler pulley is used to add tension, it can increase the power consumption of the machine. This is because the added tension requires more power to operate the belt.
3. Reduced efficiency: If the idler pulley is used to add tension, it can reduce the efficiency of the machine. This is because the added tension requires more energy to operate the belt, which can lead to reduced overall efficiency.
It is not recommended that idler pulleys be used to add tension because it can result in reduced belt life, increased power consumption, and reduced efficiency. Idler pulleys are a common component of many machines and are used to guide belts. Tension can be added to the belt by increasing the force applied to the idler pulley.
However, this is not recommended because it can cause several problems that can impact the overall performance of the machine.One of the main problems with using an idler pulley to add tension is that it can result in reduced belt life. This is because the added tension can cause excessive wear and tear on the belt, which can lead to a shorter lifespan for the belt.
In addition, the added tension can increase the power consumption of the machine. This is because the added tension requires more power to operate the belt, which can lead to increased power consumption and higher energy costs. Furthermore, the added tension can also reduce the efficiency of the machine. This is because the added tension requires more energy to operate the belt, which can lead to reduced overall efficiency.
It is not recommended to use idler pulleys to add tension because of the negative impact it can have on the overall performance of the machine. It can result in reduced belt life, increased power consumption, and reduced efficiency. Therefore, it is best to use other methods to add tension to the belt.
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the fixed scale specifies 10.5 millimeters and the thimble specifies 30 hundredths of a mm. what is the total value shown by the micrometer when you add these readings together
Answer:
10.80 mm
Explanation:
Given that the reading of the fixed scale is : 10.5 mm
The thimble scale specifies : 0.30 mm
The micrometer reading will be : 10.5 + 0.30 =10.80 mm
Determine the z-transform, including the ROC, for the sequence au in where a =5.
The z-transform of a sequence x[n] is defined as X(z) = ∑(x[n] * z^(-n)), where the summation is over all values of "n".
To determine the z-transform of the sequence au, where a = 5, we need to define the sequence and apply the z-transform formula. However, it seems that there is missing information in your question. The sequence "u" is not defined, and the value of "n" is also missing.
In general, the z-transform of a sequence x[n] is defined as:
X(z) = ∑(x[n] * z^(-n)), where the summation is over all values of "n".
To calculate the z-transform, we need the specific values of the sequence "u" and the range of "n" for which it is defined. Please provide additional details or the specific values of the sequence so that I can assist you in calculating the z-transform and determining the region of convergence (ROC) for the given sequence.
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If the incline were frictionless, would a round object, released from rest, begin to roll? Why or why not? Is friction always necessary for rolling to occur?
If the incline were frictionless, a round object released from rest would begin to roll. This is because the force of gravity acting on the object will cause it to move down the incline.
If the incline were frictionless, would a round object, released from rest, begin to roll?As the object rolls down the incline, its kinetic energy will increase, while its potential energy decreases.
The rolling of the object is due to the torque created by the force of gravity acting on the center of mass of the object. This torque causes the object to begin rolling without any external force or friction.
Friction is not always necessary for rolling to occur. Rolling can occur due to torque created by gravity or other forces acting on the object's center of mass. However, friction can help to stabilize the rolling motion of an object and prevent slipping.
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Instruction:
Use your preferable Programming Language (c++)
Upload assignment solution in BlackBoard as a pdf file.
Assignments groups should include 2-3 students
Part I: Round-off errors (5 marks)
Q.I.1: Write a code that evaluates 0.1 + 0.2 + 0.3 - 0.6. Provide the output the operation. Provide your comments
Q.I.2: Write a code that evaluates 1 – 1/3 + 1/3 one time, 100 times and 1000 times. Provide discuss the 3 results.
The code evaluates the expression 0.1 + 0.2 + 0.3 - 0.6 and outputs the result.
Here are the code solutions:
Q.I.1:
```cpp
#include <iostream>
int main() {
double result = 0.1 + 0.2 + 0.3 - 0.6;
std::cout << "Result: " << result << std::endl;
return 0;
}
```
Output: The code evaluates the expression 0.1 + 0.2 + 0.3 - 0.6 and outputs the result. The expected result should be 0, but due to the nature of floating-point arithmetic, there might be a small round-off error. The output could be a very small value like 1.11022e-16, which is close to zero but not exactly zero.
Q.I.2:
```cpp
#include <iostream>
int main() {
double result = 1.0;
for (int i = 1; i <= 1000; i++) {
result -= 1.0 / 3.0;
}
std::cout << "Result after 1 time: " << result << std::endl;
result = 1.0;
for (int i = 1; i <= 100; i++) {
result -= 1.0 / 3.0;
}
std::cout << "Result after 100 times: " << result << std::endl;
result = 1.0;
for (int i = 1; i <= 1000; i++) {
result -= 1.0 / 3.0;
}
std::cout << "Result after 1000 times: " << result << std::endl;
return 0;
}
```
Output: The code evaluates the expression 1 - 1/3 + 1/3, repeating it 1, 100, and 1000 times, respectively. The expected result should be 1, as the subtraction and addition of 1/3 should cancel each other out. However, due to round-off errors in floating-point arithmetic, the result may not always be exactly 1. The outputs will show how the accumulation of round-off errors affects the final result as the expression is repeated more times.
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Explain the Application of transformer how it works
Answer:
It is used to transform voltage.
Explanation:
Transformers are the electronic device used to convert alternating current from one voltage to another. There are two types of transformer such as step up transformer and step down transformer. Transformer are used for increasing low AC voltages at high current which is called step-up transformer while on the other hand, decreasing high AC voltages at low current known as a step-down transformer in electric power applications. Step-up transformers are used to increase the voltage and step-down transformers are used to reduce the voltage levels.
Let's now zoom in to the switches between Alice and Bob. Suppose that a pair of switches X and '1' are connected by a fiber optic link. The first switch begins transmitting the largest IP packet allowed by Ethernet, sending at the 00-24 rate (you will have to look up what these two values are). Just as switch X finishes sending the packet payload, switch Y receives the first bit of the IP packet, meaning the "width" of the packet is the length of the fiber. The speed of light in fiber is 2;"3 the speed of light in a vacuum. j. [4 points] What is the distance between switch X and switch Y? k. [2 points] Suppose the link is swapped to 00-3. Does the "width" of a packet on the wire become shorter or longer? Why?
The distance between switch X and switch Y is determined by the time it takes for the first bit of the IP packet to travel from switch X to switch Y.
The distance between switch X and switch Y can be calculated by considering the speed of light in fiber optic cables. Since the speed of light in fiber is 2/3 times the speed of light in a vacuum, we can use this information to determine the distance.
First, let's find the time it takes for the first bit of the IP packet to travel from switch X to switch Y. The rate at which the packet is being sent is given as 00-24. In Ethernet notation, 00 represents 10 Mbps and 24 represents 1 Gbps. Therefore, the packet is being sent at a rate of 10 Mbps.
The largest IP packet allowed by Ethernet is 1500 bytes. To find the time it takes for the packet payload to be transmitted, we divide the packet size by the transmission rate:
1500 bytes / 10 Mbps = 0.15 milliseconds
Now, since the "width" of the packet is equal to the time it takes for the first bit to reach switch Y, and the speed of light in fiber is 2/3 times the speed of light in a vacuum, we can calculate the distance as follows:
Distance = (Speed of light in fiber) * (Time it takes for the first bit to travel)
= (2/3 * Speed of light in vacuum) * (0.15 milliseconds)
≈ 0.1 * Speed of light in vacuum
Therefore, the distance between switch X and switch Y is approximately 0.1 times the speed of light in a vacuum.
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ở phía hút của máy bơm, đồng hồ áp suất bourdon ghi độ chân không 40kPa. Áp suất tuyệt đối tương ứng là bao nhiêu nếu áp suất khí quyển địa phương là 100kPa(abs)
Answer:
Nhiều kỹ thuật đã được phát triển cho các phép đo áp suất và chân không. Dụng cụ được sử dụng để đo áp suất được gọi là đồng hồ đo áp suất hoặc đồng hồ đo chân không hoặc áp kế.
Một "'áp kế"' cũng có thể được đề cập đến một dụng cụ đo áp suất, thường được giới hạn để đo áp suất gần đến khí quyển. Thuật ngữ "áp kế" thường được sử dụng để chỉ cụ thể để các dụng cụ cột chất lỏng thủy tĩnh.
Đo chân không được sử dụng để đo lường áp suất trong chân không mà được chia thành hai tiểu thể loại, chân không cao và thấp (và đôi khi chân không cực cao). Phạm vi áp suất áp dụng của một số kỹ thuật được dùng để đo chân không có sự chồng chéo lên nhau. Do đó, bằng cách kết hợp nhiều loại khác nhau của đánh giá, nó có thể để đo áp suất hệ thống liên tục từ 10 mbar xuống đến 10 -11 mbar.
what technology has been used for building super structures
Answer: Advanced technologixal machines
Explanation: such as big cranes, multiple workers helping creat said structure, and big bull dozers
Match each type of access point on the left with the wireless network architecture where it is commonly used on the right. Each type of access point may be used once, more than once, or not at all.
Independent access point infrastructure/ Intelligent AP, Hub-and-spoke infrastructure/ Lightweight AP, Distributed wireless mesh infrastructure/ Intelligent AP.
A WLAN, or wireless local area network, is created by an access point, which is often found in a large building or workplace. An access point transmits a WiFi signal to a predetermined region after being connected to a wired router, switch, or hub through an Ethernet cable. It's true that it depends on the requirements. While medium to big businesses and organizations will undoubtedly need a network of access points and switches, homeowners and small businesses may find routers to be the best (if not the only) answer. Devices are connected wirelessly using wireless access points. They function by sending out a signal that various objects can connect to.
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Under a subsection for geological hazards the buyer is encouraged to obtain an read the booklet
Answer:
Buyer is encouraged to obtain and read the booklet entitled "The Homeowners Guide to Earthquake Safety." In most cases a questionnaire within the booklet must be completed by Seller and the entire booklet given to the Buyer if the Property was built prior to 1960.
Silica-rich magmas are noted for their high viscosity, which results in slow moving lava flows and highly explosive eruptions. True or Fa;se
High viscosity, a characteristic of silica-rich magmas, is known to cause both slow-moving lava flows and explosive eruptions.
What impact does excessive silica have on the lava's viscosity?The shape of a volcano is shaped by variations in a magma's viscosity. Viscosity is significantly lower in high-silica (basalt) magmas. Longer distances are covered with greater ease. Low-silica magma cools and solidifies, adding a new thin layer of rock to the volcano as it does so.
According to new modeling study from the University of Washington, silica-rich magma reservoirs—the kind that triggers the most explosive volcanic eruptions—can linger in the Earth's upper crust for hundreds of thousands of years without causing an eruption.
Viscous magmas make it difficult for gases to escape, which can lead to extremely high gas pressure. Long molecular chains made of silica and other elements tangle together over time.
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A steam power plant operates on the reheat Rankine cycle. Steam enters the highpressure turbine at 12.5 MPa and 550°C at a rate of 7.7 kg/s and leaves at 2 MPa. Steam is then reheated at constant pressure to 450 °C before it expands in the low-pressure turbine. The isentropic efficiencies of the turbine and the pump are 85 percent and 90 percent, respectively. Steam leaves the condenser as a saturated liquid. If the moisture content of the steam at the exit of the turbine is not to exceed 5 percent, determine (a) the condenser pressure, (b) the net power output, and (c) the thermal efficiency
Answer:
A) condenser pressure = 9.73 kPa,
B) 10242 kw
C) 36.9%
Explanation:
given data
entrance pressure of steam = 12.5 MPa
temperature of steam = 550⁰c
flow rate of steam = 7.7 kg/s
outer pressure = 2 MPa
reheated steam temperature = 450⁰c
isentropic efficiency of turbine( nt ) = 85% = 0.85
isentropic efficiency of pump = 90% = 0.90
From steam tables
at 12.5 MPa and 550⁰c ; h3 = 3476.5 kJ/kg, S3 = 6.6317 kJ/kgK
also for an Isentropic expansion
S4s = S3 .
therefore when S4s = 6.6317 kJ/kg and P4 = 2 MPa
h4s = 2948.1 kJ/kg
nt = 0.85
nt (0.85) = \(\frac{h3-h4}{h3-h4s}\) = \(\frac{3476.5 - h4}{3476.5 - 2948.1}\)
making h4 subject of the equation
h4 = 3476.5 - 0.85 (3476.5 - 2948.1)
h4 = 3027.3 kj/kg
at P5 = 2 MPa and T5 = 450⁰c
h5 = 3358.2 kj/kg, s5 = 7.2815 kj/kgk
at P6 , x6 = 0.95 and s5 = s6
using nt = 0.85 we can calculate for h6 and h6s
from the chart attached below we can see that
p6 = 9.73 kPa, h6 = 2463.3 kj/kg
B) the net power output
solution is attached below
c) thermal efficiency
thermal efficiency = 1 - \(\frac{qout}{qin}\) = 1 - ( 2273.7/ 3603.8) = 36.9% ≈ 37%
Find the error in the following pseudo code
Declare Boolean finished = false
Declare Integer value, cube
While not finished
Display “enter a value”
Input value
Set cube = value ^3
Display cube
End while
Pseudocodes are used as a prototype of an actual program.
The error in the pseudocode is that, the while loop in the pseudocode will run endlessly.
From the pseudocode, the first line is:
Declare Boolean finished = false
The while loop is created to keep running as long as finished = false.
So, for the while loop to end, the finished variable must be updated to true.
This action is not implemented in the pseudocode.
Hence, the error in the pseudocode is that, the while loop is an endless loop
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Working surfaces are classified as Very Light Duty, Light Duty, Medium Duty and Heavy Duty. Classify the following:
a. Roofing
b. Light Frame Construction
c. Concrete finishing using hand tools
d. Concrete finishing using motorized screeds
e. Structural Steel Erection
1. Very Light Duty
2. Light Duty
3. medium duty
4. Heavy Duty
The classification of the working surfaces are as follows;
Roofing → heavy duty Light frame construction → medium dutyConcrete finishing using hand tools → medium duty Concrete finishing using motorized screeds → Light DutyStructural Steel Erection → Heavy Duty What are working surfaces?A working surface is a flat surface on which various activities can be carried out.
In a construction system, the duty carried on a particular working surface varies from another. They can be categorized into heavy-duty, medium-duty, light-duty, and very light-duty.
The classification of the working surfaces are as follows;
Roofing → heavy duty Light frame construction → medium dutyConcrete finishing using hand tools → medium duty Concrete finishing using motorized screeds → Light DutyStructural Steel Erection → Heavy DutyLearn more about the working surface here:
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What is the preferred development environment
Answer:The preferred development environment can vary depending on personal preferences, the type of project, and the programming language being used.
Explanation: