The magnitude of the resulting acceleration of the block is 5.60 m/s.
What is Newton's second law?The product of the block's mass and acceleration is the net force acting on the block. Newton's second law of motion is what is known as this.
The following is the expression for Newton's second law:
F = ma
The net horizontal force acting on the block is as follows:
Fnet =F + FcosΘ
Here, F is the force acting on the block, and 8 is the angle at which the force is applied to the block.
Substitute 30Θ for 8 and 30 N for F.
Fnet =30 N + (30 N)cosΘ = 55.98 N
From Newton's second law, the expression for the force is.
Fnet = ma
Substitute 10.0 kg for m and 55.98 N for Fnet
55.98 N = (10 kg)a
a (55.98 N /10 kg)
a = 5.598 m/s2 a = 5.60 m/s
Therefore, the acceleration of the block is 15.60 m/s
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The question is incomplete. Your most probably complete question is given below: The figure is added.
An average person is 175 cm tall. How
many people could you stack one on top of
another to reach the top of the CN Tower
(553 m)?
The number of people you will stack to reach the top of the CN Tower (553 m) is 316 people
Hor to convert 175 centimeters to metersWe'll begin by converting 175 cm to m. This can be obtained as illustrated below:
100 cm = 1 m
Therefore,
175 cm = (175 cm × 1 m) / 100 cm
175 cm = 1.75 m
Thus, 175 cm is equivalent to 1.75 m
How to determine the number of people neededThe number of people needed to be stacked to get to the top of the CN tower can be o btained asfollow:
Height of tower = 553 mHeight of a person = 1.75 mNumber of people needed =?Number of people needed = Height of tower / height of a person
Number of people needed = 553 / 1.75
Number of people needed = 316 people
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When people are asked to recall a list of words that they had earlier memorized
What happens to the gravitational force between two objects if the distance between them triples?
A. The force increases by a factor of 9
B. The force decreases by a factor of 9
C. The force decreases by a factor of 3
D. The force increases by a factor of 3
A 7.77 kg mass is moving due west at 7.77 m/s. A second mass of 8.88 kg is moving due south at 8.88 m/s. What is the magnitude of their combined velocity, in m/s, after they collide and stick together?
a) 1.11 m/s
b) 3.82 m/s
c) 5.96 m/s
d) 11.8 m/s
Answer:
8.362m/s
Explanation:
Given data
Mass m1= 7.77kg
Velocity v1= 7.77m/s
Mass m2= 8.88kg
Velocity v2= 8.88m/s
Apply the law of conservation of momentum for inelastic collision we have
m1v1+m2v2= (m+m2)V
7.77*7.77+ 8.88*8.88= (7.77+8.88)V
60.3729+78.8544= 16.65V
139.2273= 16.65V
Divide both sides by 16.65
V= 139.2273/16.65
V= 8.362m/s
Hence the final velocity is 8.362m/s
In the diagram, q1 = +6.39*10^-9 C and
q2 = +3.22*10^-9 C. What is the electric
field at point P? Include a + or - sign to
indicate the direction.
P
91
0.424 m-
0.636 m
-
92
(Remember, E points away from + charges,
and toward charges.)
(Unit = N/C)
E =+823.12N/C is the electric field at point P
Each point in space has an electric field associated with it when a charge of any kind is present. The value of E, often known as the electric field strength, electric field intensity, or just the electric field, expresses the strength and direction of the electric field. in the diagram, q1 = +6.39*10^-9 C and
q2 = +3.22*10^-9 C hence E = 823.12 N/C
A region of space surrounding andd P Include a + or - sign toindicate the direction.P910.424 m-0.636 m- electrically charged particle or object known as an electric field is one in which an electric charge would experience force. A vector quantity called an electric field can be represented by arrows pointing in the direction of or away from charges. The force per unit charge exerted on a positive test charge that is at rest at a given position is the force per unit charge that is used to define the electric field analytically.
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What causes a rare proxigean spring tide?
1 point
3. A 75 N box requires 250 J of work to move to a shelf. How high is the
shelf?
O 3.3 m
3.25m
0 3.9m
O 3.6m
1. Why is the flow of electrons from A to B?
2. What's the difference between flow of current & flow of electrons and why ar they opposite?
1. because A is more negative than B. A is -1000 V (we can imagine that A has excess 1000 electrons), in other, B which +3000 V can be assume that B need 3000 elctrons to be neutral. So, the electron will flow from A to B.
2. Electrons being negatively charged flow from the negative terminal to the positive terminal of the voltage source. So, the actual direction of current should be from negative to positive terminal. However, the conventional direction had already been established. So, the current flow is considered in the direction opposite to the direction of flow of electrons. (from topperlearning dot com)
Which statement best describes the primary difference between scientific investigation and technological design?
Scientific investigation is more time consuming than technological design.
Technological design is more expensive than scientific investigation.
Technological design involves background research, and scientific investigation does not require research.
Scientific investigation involves experiments, and technological design involves products.
Su
The statement best describes the primary difference between scientific investigation and technological design is Scientific investigation involves experiments, and technological design involves products. Option D
What are scientific investigation and technological design?It can be said that both scientific investigation and technolgical design require problem-solving, creativity, and rigorous methods.
However, both of them have different objectives. While Scientific investigation seeks to expand knowledge and understanding of the natural world. Research involvs hypothesis testing and different experiments;
on the other hand, Technological design, wants to create or improve products, processes, or systems to meet specific needs or solve particular problems.
It can then be defined as the application of scientific knowledge for practical purposes.
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At a sports car rally, a car starting from rest accelerates uniformly at a rate of 9.0m/s² over a straight-line distance of 100m. The time to beat is 4.5s.
a Does the driver do it?
b. If not, what must the acceleration be to do so?
Answer:
The driver does not do it. The acceleration must be greater than 9.0m/s² in order to beat the time of 4.5s. The acceleration must be calculated using the equation a = (d/t)², where a is the acceleration, d is the distance, and t is the time. In this case, a = (100/4.5)², which is equal to approximately 27.78m/s². Therefore, the acceleration must be greater than 27.78m/s² in order to beat the time of 4.5s.
Explanation:
Which perspective studies help behavior and cognitive processes vary among cultures
A person of weighing 0.62 kN rides in an elevator that has an upward acceleration of 1 m/s2. What is the magnitude of the force of the elevator floor on the person, in newtons
Answer:
Force = 63.27 Newton
Explanation:
Given the following data;
Weight = 0.62 kN = 0.62 * 1000 = 620 N
Acceleration = 1 m/s²
To find the magnitude of the force of the elevator floor on the person;
First of all, we would determine the mass of the elevator;
Weight = mass * acceleration due to gravity
We know that acceleration due to gravity is equal to 9.8 m/s²
Substituting into the above formula, we have:
620 = mass * 9.8
Mass = 620/9.8
Mass = 63.27 kg
Next, we would determine the force by using the formula;
Force = mass * acceleration
Force = 63.27 * 1
Force = 63.27 Newton
Four ways to encourage immigrants positively
Answer:
See below.
Explanation:
1) Build relationships with key leaders and organizations
Early on, communicate with immigrant community leaders and groups to establish contacts, learn about these communities, and express your desire to include immigrant citizens in civic and political life. Make a list of them and keep it updated. Individuals and groups, be on the lookout for opportunities to meet with them and participate in local activities. Keep in touch with them on a regular basis and attend their events and activities.
2) Identify issues that immigrants care about
Identify problems of interest to immigrant populations through personal interactions, surveys, and meetings with local groups, and be prepared to include these themes in community talks and other public engagement initiatives. If a need is found, you can start with conversations and civic involvement in immigrant communities, since this can create channels for participation and leadership development for people who might not otherwise participate. Demonstrate how civic involvement may assist immigrants in achieving their goals and aspirations.
3) Overcome language barriers
Every participant should be prepared to participate, understood, and comprehend what others are saying as part of public engagement activities. Translation equipment and services should be provided, as well as outreach and issue background materials that are relevant for your community. The translation services should be mentioned in outreach for public engagement activities.
Ensure that documents are translated by native speakers or those who are entirely proficient in order for translations to be comprehended by readers. When conducting polls and surveys, it is preferable to ask questions in the native language of the residents. You may contact people with varied literacy levels through face-to-face, radio, and other non-written interactions.
4) Use effective media and outstretch strategies
Integrate immigrant-focused local and regional print and electronic media into your communication plan. Build ties with these media outlets, provide them access to information and local officials, send them news, announcements, and job ads, and work with them as partners to develop effective outreach to increase public participation. Inform suitable community, service, or business groups, schools, congregations, and others about a forthcoming public engagement activity. Request that the leaders of these organizations include particular solicitations for their immigrant members, as well as follow up with and assist those who are interested in attending.
28). A block weighs 90N and 80N respectively in air and in water. What will be the weight of the block in a brine of density 1.2g/cm?
Answer:
Buoyant force = g M / V * V = g d V where d is the mass / volume (density)
Fw = g * Vw * dw buoyant force of water on block (10 N)
Fbr = g * Vw * dbr buoyant force of brine on block
Fbr / Fw = 1.2 buoyant force of brine is 1.2 times that of water
Buoyant force of brine = 10 * 1.2 N = 12 N
Thus, the block will weight 90 - 12 = 78 N submersed in brine
88. A child pulls a cart to the left along a rough surface. Which one of the free body diagrams correctly depicts all the forces acting on the carrito?
Answer:
Eje x
fr- F = m a
eje y
N-W =0
Explanation:
Para este ejercicio, debemos usar la segunda ley de Newton, donde se necesita fija un sistema de referencia el mas usado es un sistema horizontal y vertical para los ejes x e y
en el adjunto puede ver el diagrama de cuerpo libre correcto,
las fuerza son
Eje x
fr- F = m a
eje y
N-W =0
la ecuacion para la fuerza de roce es
fr = my N
in which of the following types of circuits can the total power of the circuit be determined by adding the power dissipation of all the parts of the circuit?
In an equal circuit, all parts are associated across one another, subsequent in precisely two arrangements of electrically normal places.
The complete power in a series circuit is equivalent to the amount of power disseminated by the individual resistors.
The complete power disseminated will be equivalent to the amount of the power dispersed by every individual obstruction. Contingent upon the qualities that are known, blends of the power equation, also as Ohm's regulation, can be utilized to work out power disseminated (or some other obscure worth).
An equal circuit disseminates more power than a series circuit. For similar arrangements of resistors, the complete obstruction of the equal circuit is consistently lower than the all-out opposition in a series circuit.
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A jogger takes 30 s to run a total distance of 200 m by running 150 m [E] and then 50 m [W]. (a)
Calculate the jogger’s average speed (b) Calculate the jogger’s average velocity
Answer:
(a) 6.67 m/s (b) 3.33 m/s
Explanation:
if i understood your question correctly, the jogger goes 150m east before going in the opposite direction west for 50m. (see diagram)
in avg speed, we use the total distance (150m + 50m = 200m) and total time (30s)
v = d/t =200/30 =6.67 m/s
in avg velocity, we use the total displacement (150m - 50m = 100m) and total time (30s)
v= d/t = 100/30 = 3.33 m/s
A student measures the speed of sound by echo destiny classes hands and then measures the time to hear the echo his distance to the wall is 300 m The time delay between clap an echo is 1.5 seconds. Calculate the speed of sound
The calculated value of speed of sound be 400 m/s.
What is echo?An echo is a sound produced when sound waves are reflected off of a surface and returned to the listener. It is the sound that has been reflected, and it reaches the listener after the original sound has passed.
Given parameters:
The student's distance to the wall is = 300 m.
The time delay between clap an echo is 1.5 seconds.
In this time, sound waves goes to the wall and hits back to the student's ear.
So, total distance covered by the sound wave: d= 2 × 300 m = 600 m.
Hence, the speed of sound be - 600 m/1.5s = 400 m/s.
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The number of hours
of daylight tat a location receives varies depending on how far north or south it is from the
Answer:
equator
Explanation:
in south & north pole you could have 20+ hours daylight or night, everyday!
A cube of wood having an edge dimension of 18.7 cm and a density of 653 kg/m3 floats on water. (a) What is the distance from the horizontal top surface of the cube to the water level
Answer:
6.5 cm
Explanation:
Given that the edge dimension of a cube, a = 18.7 cm
Density of the cube, \(\rho_c= 653 kg/m^3\)
Volume of the cube, \(V_c= a^3= 18.7^3 cm^3=18.7^3\times 10^{-6}m^3\)
Mass of the cube. \(m_c= \rho_c \times V_c\)
\(=653\times 18.7^3\times 10^{-6}\) kg
Gravitational force action on the cube in the downward direction is
\(F_g=m_cg=653\times 18.7^3\times 10^{-6}\times g \;N \cdots(i)\)
where g is the acceleration due to gravity.
As the cube floats on the water, let the distance from the horizontal top surface of the cube to the water level is x cm.
So, the distance from the horizontal bottom surface of the cube to the water level= (18.7 - x) cm.
Volume of water replaced, \(V_w=\) volume of a portion of the
cube inside the water.
So, \(V_w= 18.7\times 18.7\times(18.7 - x) cm^3= 18.7^2\times(18.7 - x)\times 10^{-6}m^3\)
As the density of water, \(\rho_w= 1000 kg/m^3\)
So, the mass of the water displaced, \(m_w= \rho_w\times V_w\)
\(m_w=1000\times 18.7^2\times(18.7 - x)\times 10^{-6}\) kg
The buoyancy force acting on the cube in the upward direction,
\(F_b= m_w\times g\)
So, \(F_b=1000\times 18.7^2\times(18.7 - x)\times 10^{-6}\times g \; N \cdots(ii)\)
For the floating condition, the gravitational force acting on the cube in the downward direction must be equal to the buoyancy force acting on the cube in the upward direction.
So, equation equations (i) and (ii), we have
\(F_b=F_g \\\\\Rightarrow 1000\times 18.7^2\times(18.7 - x)\times 10^{-6}\times g=653\times 18.7^3\times 10^{-6}\times g \\\\\)
\(\Rightarrow 18.7-x=\frac{653\times 18.7^3\times 10^{-6}\times g}{1000\times 18.7^2\times 10^{-6}\times g} \\\\\Rightarrow 18.7-x=\frac {653\times 18.7}{1000} \\\\\)
\(\Rightarrow 18.7-x=12.2 \\\\\Rightarrow x= 18.7-12.2 \\\\\)
\(\Rightarrow x= 6.5\) cm
Hence, the distance from the horizontal top surface of the cube to the water level is 6.5 cm.
When grip strength increases:
a. action potential voltage increases.
b. action potential frequency decreases.
c. action potential frequency increases.
d. action potential frequency increases.
e. the number of active motor units increases.
Answer:
e. the number of active motor units increases.
Explanation:
There is a direct relationship between the number of active motor units and the grip strength in a given scenario. For example, increase in the grip strength leads to increase in the number of active motor units. In the other-hand, the decrease in grip strength leads to the decrease in the number of active motor units.
A cement mixer of radius 2.5 m turns with a period of 50 sec/rev. What is the centripetal force of a
small piece of dried cement of mass 50 g stuck to the inside wall of the mixer?
The centripetal force acting on the small piece of dried cement is 0.01 N when mass 50 g stuck to the inside wall of mixer.
Centripetal force :Any force that alters velocity in the direction toward the center of a circular motion is referred to as a centripetal force. The centripetal force is produced by the portion of the force that is perpendicular to the velocity.
Evaluating :The period of the cement mixer can be calculated as:
T = 50 sec/rev
= 2πr/v,
where r is the radius of the mixer and
v is the velocity of the piece of dried cement.
Solving for v, we get v = 2πr/T.
Substituting the given values, we get
v = 2π(2.5 m)/(50 sec/rev)
= 0.314 m/s.
The centripetal force acting on the piece of dried cement can be calculated using the formula :
F = m v² / r,
where m is the mass of the cement,
v is the velocity, and
r is the radius of the mixer.
Substituting the given values, we get
F = (0.05 kg)(0.314 m/s)²/(2.5 m)
= 0.01 N.
Therefore, the centripetal force acting on the small piece of dried cement is 0.01 N.
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A 100 kg gymnast comes to a stop after tumbling. Her feet do 5,000 J of work to stop her.
Which of the following was the girl's velocity when she began to stop?
Answer:10 m/s
Explanation:
A 100 kg gymnast comes to a stop after tumbling. Her feet do 5,000 J of work to stop her. The girl's velocity when she began to stop is 10 m/sec.
What is velocity?When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time. Velocity is vector quantity.
Uniform motion an object is said to have uniform motion when object cover equal distance in equal interval of time within exact fixed direction. For a body in uniform motion, the magnitude of its velocity remains constant over time. Here in the question velocity is changing by using work energy theorem we have,
work done = change in kinetic energy
5000 = (.5).m.v² , where v is velocity.
5000 = (.5).100.v²
v = 10 m/sec
A 100 kg gymnast comes to a stop after tumbling. Her feet do 5,000 J of work to stop her. The girl's velocity when she began to stop is 10 m/sec.
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An aeroplane is circling above an airport in a horizontal circle at a speed of 400 kmh-1.The banking angle of the wings is 20.What is the radius of the circular path?
Answer: the radius of the circular path is approximately 1637.58 meters.
Explanation:
The centripetal force acting on the airplane is provided by the component of the gravitational force that acts towards the center of the circular path. This component is given by:
F_c = m * g * tan(banking angle)
Where:
F_c is the centripetal force
m is the mass of the airplane
g is the acceleration due to gravity
tan(banking angle) is the tangent of the banking angle
Now, the centripetal force is also given by the formula:
F_c = (m * v^2) / r
Where:
v is the speed of the airplane
r is the radius of the circular path
Equating the two expressions for F_c, we get:
(m * g * tan(banking angle)) = (m * v^2) / r
Canceling out the mass (m) on both sides of the equation, we have:
g * tan(banking angle) = v^2 / r
Solving for r, we get:
r = (v^2) / (g * tan(banking angle))
Substituting the given values:
v = 400 km/h = 400,000 m/h
g = 9.8 m/s^2
banking angle = 20°
Converting the speed to m/s:
v = 400,000 m/h * (1/3600) h/s = 111.11 m/s
Converting the banking angle to radians:
banking angle = 20° * (π/180) rad/° = 0.3491 rad
Now, substituting the values into the formula:
r = (111.11^2) / (9.8 * tan(0.3491))
r ≈ 1637.58 meters
Therefore, the radius of the circular path is approximately 1637.58 meters.
A subway train has a sound intensity level of 90 dB, and a riveting machine has a sound intensity level of 120 dB. How many times greater is the sound intensity of the machine than that of the train?
ANSWER:
1000 times
STEP-BY-STEP EXPLANATION:
Sound intensity level train = 90 dB
Sound intensity level machine = 120 dB
We can calculate the sound intensity in each case using the following formula:
\(\begin{gathered} \beta =10\log _{10}\left(\frac{I}{I_0}\right) \\ \\ I_0=10^{-12}\text{ W/m}^2 \end{gathered}\)We substitute each value and calculate I in each case:
\(\begin{gathered} \text{ For the train:} \\ \\ 90=10\cdot\log_{10}\left(\frac{I_1}{10^{-12}}\right) \\ \\ \log_{10}\left(\frac{I_1}{10^{-12}}\right)=\frac{90}{10} \\ \\ \log_{10}\left(\frac{I_1}{10^{-12}}\right)=9 \\ \\ \frac{I_1}{10^{-12}}=10^9 \\ \\ I_1=10^9\cdot\:10^{-12} \\ \\ I_1=0.001\text{ W/m}^2 \\ \\ \\ \text{ For the machine:} \\ \\ 120=10\cdot\log_{10}\left(\frac{I_2}{10^{-12}}\right) \\ \\ \log_{10}\left(\frac{I_2}{10^{-12}}\right)=\frac{120}{10} \\ \\ \log_{10}\left(\frac{I_2}{10^{-12}}\right)=12 \\ \\ \frac{I_2}{10^{-12}}=10^{12} \\ \\ I_2=10^{12}\cdot\:10^{-12} \\ \\ I_2=1\text{ W/m}^2 \\ \\ \text{ Therefore:} \\ \\ \frac{I_2}{I_1}=\frac{1}{0.001}=1000 \\ \\ \text{ It is 1000 times greater is the sound intensity of the machine than that of the train} \end{gathered}\)A tennis ball is hit with a vertical speed of 10 m/s and a horizontal speed of 30 m/s. How far will the ball travel horizontally before landing?
a. 10 m
b. 20 m
c. 40 m
d. 60 m
e. 80 m
Answer:
D) 60 m
Explanation:
We can use the constant acceleration equation that contains displacement, initial velocity, acceleration, and time. We want to solve for the time that the ball was in the air first.
Δx = v_i * t + 1/2at²Let's use this equation in terms of the y-direction.
Δx_y = (v_i)y * t + 1/2a_y * t²The vertical displacement will be 0 meters since the ball will be on the floor. The initial vertical velocity is 10 m/s, the vertical acceleration is g = 10 m/s², and we are going to solve for time t.
Let's set the upwards direction to be positive and the downwards direction to be negative. We must use -g to be consistent with our other values.
Plug the known values into the equation.
0 m = 10 m/s * t + 1/2(-10 m/s²) * t²Simplify the equation.
0 = -10t + 5t² 0 = 5t² - 10tFactor the equation.
0 = 5t(t - 2)Solve for t by setting both factors to 0.
5t = 0t - 2 = 0We get t = 0, t = 2. We must use t = 2 seconds because it is the only value for t that makes sense in the problem.
Now that we have the time that the ball was in the air, we can use the same constant acceleration equation to determine the horizontal displacement of the tennis ball. We will use this equation in terms of the x-direction:
Δx = v_i * t + 1/2at² Δx_x = (v_i)x * t + 1/2a_x * t²Plug the known values into the equation.
Δx_x = 30 m/s * 2 sec + 1/2(0 m/s²) * (2 sec)²We can eliminate the right side of the equation since anything multiplied by 0 outputs 0.
Δx_x = 30 * 2 Δx_x = 60The horizontal displacement of the ball is 60 meters. Therefore, the answer is D) 60 m.
The part of the circuit that converts electrical energy into other forms
Answer:
Load
Explanation:
The load in an electric circuit is any device that converts electrical energy into another form of energy.
Hint: sin2θ + cos2θ = 1 .
Consider the 692 N weight held by two
cables shown below. The left-hand cable had
tension 570 N and makes an angle of θ2 with
the ceiling. The right-hand cable had tension
530 N and makes an angle of θ1 with the
ceiling. a) What is the angle θ1 which the righthand cable makes with respect to the ceiling?
Answer in units of ◦.
b) What is the angle θ2 which the left-hand
cable makes with respect to the ceiling?
Answer in units of ◦.
a) The angle θ1 which the righthand cable makes with respect to the ceiling is sin^(-1)(692 N / 530 N).
b) The angle θ2 which the left-hand cable makes with respect to the ceiling is sin^(-1)(692 N / 570 N).
We may utilise the tension of the right-hand cable as well as its vertical and horizontal components to determine the angle 1. θ2 = sin^(-1)(692 N / 570 N).
We may apply the ideas of trigonometry and vector addition to address this issue.
a) The tension of the right-hand wire as well as its vertical and horizontal components can be used to determine the angle 1.
T1sin(1) calculates the vertical component of the right-hand cable's tension, which is equal to the object's weight (692 N).
T1sin(θ1) = 692 N
We may rearrange the equation to find 1:
θ1 = sin^(-1)(692 N / T1)
We can find 1 by substituting the given tension value, T1 = 530 N:
θ1 = sin^(-1)(692 N / 530 N)
b) Similarly, we can use the formula to determine the angle 2 the left-hand cable's tension and its vertical and horizontal components.
The vertical component of the left-hand cable's tension is given by T2sin(θ2), and it should also be equal to the weight of the object (692 N).
T2sin(θ2) = 692 N
To find θ2, we can rearrange the equation:
θ2 = sin^(-1)(692 N / T2)
Substituting the given tension value T2 = 570 N, we can solve for θ2:
θ2 = sin^(-1)(692 N / 570 N)
Calculating these angles using the given tension values will provide the answers in degrees.
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A trebuchet launches a pumpkin at an angle of 63 degrees at an initial velocity of 51 m/ s from the ground. What is the range of the pumpkin?
Answer:
214.72m
Explanation:
The range (R) of a projectile can be calculated using the formula:
R = u²sin2θ/g
Where R = Horizontal range
u = initial velocity
θ = angle of initial velocity
g = acceleration due to gravity (9.8m/s²)
According to the provided information in this question, R= ?, u= 51m/s, θ = 63°, g = 9.8m/s².
Hence, R = u²sin2θ/g
R = 51² × sin 2×63/ 9.8
R = 2601 × sin 126/9.8
R = 2601 × 0.809/9.8
R = 2104.25/9.8
R = 214.72m
100 POINTS AND BRAINLIST FOR BEST ANSWER!
Please help me i have a 77% in science and i need to bring it up today bc its the end of grades today. If you help me you are seriously the best person in the world, theres 4 questions.
Answer:
Air moves from regions of high pressure to regions of low pressure.
Explanation:
When airs moves horizontally from regions of high pressure to low pressure, it creates wind. If the difference between high and low pressure is greater, then it makes the wind faster.
Best of Luck!
Answer:
C. Air moves from regions of high pressure to regions of low pressure.
Explanation:
The air from the regions of high pressure will hold onto that pressure. So, when it moves into the regions with low pressure it'll turn into wind.
The greater the pressure, the stronger the wind and vise versa.
Hope this helps!