boxes a and b have masses of 12.0 kg and 4.00 kg, respectively. the two boxes are released from rest, as shown.

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{force}{mass} \\ \)

From the question

force = 97.7 N

mass = 34.2 kg

We have

\(a = \frac{97.7}{34.2} = 2.856725 \\ \)

We have the final answer as

Hope this helps you

Answer:

The earths core is made up of heavy elements such as iron and nickel and along with lighter elements such as potassium and sodium!!

Explanation:

i took a quiz and got this answer right!

The earth's core and surface are made up of:

The core is made up of heavy elements, such as iron and nickel, and lighter elements, such as potassium and sodium make up the surface.

The deepest layer of Earth's crust is its inner core. The extremely hot and dense core of Earth is where life exists. The chilly, brittle crust, the mainly solid mantle, and the ball-shaped core are all covered by each other.

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Answer:   the acceleration of the masses is given by = 0, which means the angular acceleration of the pulley is zero. This implies that the masses m and 2m move with constant velocity,  they are in equilibrium.

The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.

Let the mass of the body A be ‘m’.

The two strings are taut so they exert a tension ‘T’ on body A.

Let ‘a’ be the acceleration produced in the system.

The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)

As the two strings are taut, we can say that tension in both strings is equal.

Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.

The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)

As per the given problem, the system is released from rest.

Hence the initial velocity is zero.

Also, we are given that the system accelerates at 2 m/s2.

Therefore a = 2 m/s2 …(2)

From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5

Thus, the mass of A is 8m/5 kg.

Answer: Mass of A = 8m/5 kg.

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Explanation:

Dark Energy. Dark Energy is a hypothetical form of energy that exerts a negative, repulsive pressure, behaving like the opposite of gravity. It has been hypothesised to account for the observational properties of distant type Ia supernovae, which show the universe going through an accelerated period of expansion

The maximum weight that has to be lifted is 3922 N. and the diameter of the pipe under the platform if the diameter is 37.

Platform is defined as a collection of technologies that serve as the foundation for the development of new applications, procedures, or technologies.  By facilitating transactions, a platform eventually makes this wealth generation possible.

A maximum weight of (3,471 + 451) g = 3922 N must be lifted. The other piston cannot be subjected to more than 100 N of force. The ratio of the two pistons' diameters needs to be sqrt (3922 / 106) = 37.

Thus, the maximum weight that has to be lifted is 3922 N. and the diameter of the pipe under the platform if the diameter is 37.

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The net force on A is  1.7312 × 10⁻⁷ N

It states that the force of attraction between two masses M and m is directly proportional to the product of their masses and inversely proportional to the square of their distance apart, R.

So, F = GMm/R² where G = universal gravitational constant = 6.67 × 10⁻¹¹ Nm²/kg²

Now let

So, the force of attraction between them is

F = Gm₁m₂/R₁² (positive since it is directed towards B in the positive x direction)

Substituting the values of the variables into the equation, we have

F = Gm₁m₂/R₁²

F = 6.67 × 10⁻¹¹ Nm²/kg² × 199.1 kg × 592.9 kg/(7.5 m)²

F = 787369.4213 × 10⁻¹¹ Nm²/56.25 m²

F = 13997.68 × 10⁻¹¹ N

F = 1.399768 × 10⁻⁷ N

F ≅ 1.3998 × 10⁻⁷ N

Also, let

So, the force of attraction between them is

F' = Gm₁m₃/R₂² (positive since it is directed towards C in the positive x direction)

Substituting the values of the variables into the equation, we have

F' = Gm₁m₂/R₁²

F' = 6.67 × 10⁻¹¹ Nm²/kg² × 199.1 kg × 330 kg/(11.5 m)²

F' = 438239.01 × 10⁻¹¹ Nm²/132.25 m²

F' = 3313.72 × 10⁻¹¹ N

F' = 0.331372 × 10⁻⁷ N

F' ≅  0.3314 × 10⁻⁷ N

So, the net force acting on object A is F" = F + F'

= 1.3998 × 10⁻⁷ N +  0.3314 × 10⁻⁷ N

= 1.7312 × 10⁻⁷ N

So, the net force on A is  1.7312 × 10⁻⁷ N

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(a) The amount of gravitational potential energy possessed by the object at the given height is 147.

(b) The kinetic energy, KE the object have just before hitting the ground is 147 J.

The amount of gravitational potential energy possessed by the object at the given height is calculated as follows;

GPE = mgh

where;

GPE = 5 kg x 9.8 m/s² x 3 m

GPE = 147 J

Based on the law of conservation of energy, the amount of kinetic energy possessed by the object just before hitting the ground will the same as the gravitational potential energy at the initial height.

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Answer:

because

Explanation:

because we need eye to see if you don't have eyes how you regnise some one

if you have ears how can you know who's voice is who's

if don't have fingers how can you know what your are holding this is why they are called physical sensors

Answer:

because  they stimulate our brain and the sensor of human body detect stimuli.

Explanation:

The mass of the planet is  5.98 × 10^24 kg.

To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.

First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.

Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.

Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.

Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2

Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2

Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.

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The velocity of the running back is 8 m/s.

To calculate the velocity of the running back, we can use the work-energy principle. The work-energy principle states that the work done on an object will be equal to the change in its kinetic energy.

Given; Mass of the running back (m); 80 kg

Work done (W); 2560 Joules

We can use the formula for kinetic energy;

KE = 0.5 × m × v²

where KE is the kinetic energy, m is the mass, and v is the velocity of the running back.

According to the work-energy principle, the work done is equal to the change in kinetic energy;

W = KE - KE0

where KE0 is the initial kinetic energy.

Rearranging the formula for kinetic energy, we get;

KE = 0.5 × m × v²

Substituting the given values, we get;

2560 = 0.5 × 80 × v²

Solving for v;

v² = (2 × 2560) / 80

v² = 64

v = √(64)

v = 8 m/s

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The magnitude of the charge of the given moveable beads is 9.33 nC.

The tension in the string is calculated as follows;

Tcos45 = mg

where;

F = Tsin45

\(\frac{kq^2}{r^2} = Tsin(45)\\\\\frac{kq^2}{r^2} = \frac{mg}{cos45} \times sin(45)\\\\\frac{kq^2}{r^2} = mg\\\\q = \sqrt{\frac{mgr^2}{k} }\)

\(q = \sqrt{\frac{(0.032 \times 10^{-3})(9.8)(0.05)^2}{9\times 10^9} } \\\\q = 9.33\times 10^{-9} \ C\\\\q = 9.33 \ nC\)

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Answer:

T = 480.2N

Explanation:

In order to find the required force, you take into account that the sum of forces must be equal to zero if the object has a constant speed.

The forces on the boxes are:

\(T-Mg=0\)      (1)

T: tension of the rope

M: mass of the boxes 0= 49kg

g: gravitational acceleration = 9.8m/s^2

The pulley is frictionless, then, you can assume that the tension of the rope T, is equal to the force that the woman makes.

By using the equation (1) you obtain:

\(T=Mg=(49kg)(9.8m/s^2)=480.2N\)

The woman needs to pull the rope at 480.2N

Static friction cancels out the force of the push, so it also has a magnitude of 25 N.

Answer:

The net torque is 0.98 Nm.

Explanation:

The torque is given by

Torque = force x perpendicular distance

The clock wise torque is taken as negative while the counter clock wise torque is taken as positive.

Take the torques about the fulcrum.

Torque =  1 x 9.8 x 0.4 - 0.5 x 9.8 x 0.6

Torque = 3.92 - 2.94 = 0.98 Nm

Answer:

It's true that organisms get energy from food.

Answer:

Explanation:

Organisms ingest large molecules, like carbohydrates, proteins, and fats, and convert them into smaller molecules like carbon dioxide and water. This process is called cellular respiration, a form of catabolism, and makes energy available for the cell to use

Answer:

here is answer!

Explanation:

Question 1:

Light bends when it transitions from air to glass due to differences in refractive indices. It follows an incident path in air, refracts at the air-glass boundary, and continues through the glass as a transmitted ray. Total internal reflection may occur if the angle of incidence is large enough.

Question 2:

Brightness in the wave model of light is determined by the amplitude and intensity of the light waves. Higher amplitudes and intensities correspond to brighter light. When multiple light waves overlap, their amplitudes add up, resulting in increased brightness

The minimum stopping distance of the car is determined as 8 m.

The minimum stopping distance of the car is calculated as follows;

d = (u²)/(2a)

where;

when the minimum stopping distance = 2 m, initial velocity = 40 km/hr = 11.11 m/s

2 = (11.11²)/(2a)

a = (11.11²)/(2 x 2)

a = 30.86 m/s²

when the speed becomes 80 km/h, the minimum stopping distance is calculated as;

u = 80 km/h = 22.22 m/s

d = (22.22² )/ (2 x 30.86)

d = 8 m

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So, we have that the speed of the person relative to the dock is 6.36 m/s

Let

where their speeds are the magnitudes of their velocities

Given that a ferry approaches shore, moving north with a speed of 6.2 m/s relative to the dock and a person on the ferry walks from one side of the ferry to the other, moving east with a speed of 1.4 m/s relative to the ferry.

We have that their velocities are

So, V' = v + V

So, V' =  (1.4 m/s)i + (6.2 m/s)j

So, the speed of the person relative to the dock is the magnitude of V which is

V' = √(v² + V²)

So, substituting the value of the variables into the equation, we have

V' = √(v² + V²)

V' = √[(1.4 m/s)² + (6.2 m/s)²]

V' = √[1.96 m²/s² + 38.44 m²/s²]

V' = √[40.4 m²/s²]

V' = 6.36 m/s

So, the speed of the person relative to the dock is 6.36 m/s

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Complete Question

The complete question is shown on the first uploaded image

Answer:

a

 \(I =  476 \ N \cdot s \)

b

 \(I_1 =  14.21 \  N\cdot s \)

c

    \(F  = 20300 \  N \)

Explanation:

Considering the first question

From the question we are told that

   The force produced is \(F  =  3400 \ N\)

   The duration of the punch is  \(t =  0.14 \  s\)

Generally the impulse delivered is mathematically represented as

    \(I =  F  *  t\)

=>    \(I =  3400  *  0.14\)

=>    \(I =  476 \ N \cdot s \)

Considering the second  question

   The approaching velocity of the ball is  \(v_b  =  45 \ m/s\)

    The leaving  velocity of the ball is  \(v_l  =  -53 \ m/s\)

     The mass of the ball is  \(m_b  =  0.145 \  kg\)

Generally the magnitude of the impulse delivered is mathematically represented as

     \(I_1 =  m*  v_b  - m *  v_l\)

=>     \(I_1 =  [0.145 *  45]  - [0.145 * -53]\)

=>     \(I_1 =  14.21 \  N\cdot s \)

Considering the third  question

     The  duration of the impact of the bat is  \(t _1 =  0.7 \ ms  =  0.7 *10^{-3} \  s\)

      Generally the average force exerted by the bat is mathematically represented as  

       \(F  =  \frac{I_1}{t_1}\)

=>     \(F  =  \frac{14.21 }{0.7 *10^{-3}}\)

=>       \(F  = 20300 \  N \)

Answer:

The water and peanut butter have different chemical properties.

(Lipids are not soluble in water)

Answer:

a. The water and peanut butter have different chemical properties.

Explanation:

Soil, water, land and employment

The surface area of the 8 new cubes would be 96 cm².

Surface area is the total area of the exposed surface of a three-dimensional object, such as a cube, cylinder, or sphere. It is measured in square units, such as square inches, square feet, or square meters. Surface area is an important concept in geometry, trigonometry, and calculus. It is used in many areas of science, such as chemistry, physics, and engineering. Surface area is also important in everyday life, from home construction and remodeling to sports and recreation. For example, it is used to calculate the size of an area needed to paint a room, the amount of material needed to cover a swimming pool, or the dimensions of a soccer field.


This is because the surface area of a cube is equal to 6 times the length of one side of the cube squared. In this example, the length of one side of the 8 cubes is equal to 4 cm divided by 2 (since the cube was broken down into 8 cubes), which is equal to 2 cm. Therefore, the surface area of each of the 8 cubes would be 6 times 2 cm squared, which is equal to 12 cm².and the total surface area of the 8 cubes would be 12 cm^2 multiplied by 8, which is equal to 96 cm².

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Regarding a spring-mass system's duration, the square root of the mass and the spring constant have opposing correlations. The length of spring will be longer and vice versa as the mass grows. Therefore, the mass influences spring.

They swing back and forth around a stationary point. Classic examples of this type of vibrating motion are a simple pendulum and a mass on a spring.

Therefore, The use of motion detectors demonstrates that the vibrations of these objects have a sinusoidal nature, even if this is not obvious from plain viewing.

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The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).

The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.

In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²

(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:

Electric flux = Electric field strength × Area

Electric flux = 18 N C⁻¹ × 0.450 m²

Electric flux = 8.1 N m² C⁻¹

In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.

The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).

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Answer:

Force = 607.95 Newton

Explanation:

Given the following data;

Area = 0.00600 m^2

Pressure = 1 atm to Pascal = 101325 Pa

To find the force;

Pressure = Force/area

Force = pressure * area

Substituting into the equation, we have;

Force = 101325 * 0.00600

Force = 607.95 Newton.

Therefore, the amount of force exerted by the air on the stamp is 607.95 Newton.

Answer:

W=F⋅l=F⋅vt=900(N)⋅19.44(m/s)⋅900(s)=15.75⋅10

6 (J)

Explanation: