BONUS: Make a sketch and label all the forces. A 2.00 kg box slides down an inclined plane
(ramp) at an angle of 20.0 degrees at a constant velocity. If the horizontal length of the
inclined plane is 2.00 m (you need to determine the actual slope length or hypotenuse):
(a) Calculate the work done by the force of gravity.
(b) Calculate the work done by the force of kinetic friction.
By signing my name to the test below, I pledge that the work that I have turned in for this
test is entirely my own and I have neither given nor received help from anyone else.

Neutrons and protons in an atom are acted upon by the strong force.

Strong force or strong nuclear force, a fundamental interaction of nature that acts between subatomic particles of matter. The strong force binds quarks together in clusters to make more-familiar subatomic particles such as protons and electrons.

Quarks are fundamental building blocks of matter. They are most commonly found inside protons and neutrons.

So being only option in which electrons are not present , option D is the correct answer.

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Answer:

doubled

Explanation:

When thrust is double so will the pressure I hope this helps

enjoy

For a 18V source and resistors of 30Ω and 60Ω, I1 is 0.6A, I2 is 0.3A, and I3 is 0.9A.

To calculate the currents (I1, I2, and I3), we can use Ohm's law, which states that the current flowing through a conductor is equal to the voltage across the conductor divided by the resistance of the conductor.

Voltage (V) = 18V

Resistance (R1) = 30Ω

Resistance (R2) = 60Ω

To find the current I1 flowing through the 30Ω resistor, we use Ohm's law:

I1 = V / R1

Substituting the values:

I1 = 18V / 30Ω

I1 = 0.6A

Therefore, the current I1 is 0.6A.

To find the current I2 flowing through the 60Ω resistor, we again use Ohm's law:

I2 = V / R2

Substituting the values:

I2 = 18V / 60Ω

I2 = 0.3A

Therefore, the current I2 is 0.3A.

To find the current I3, we need to consider the circuit configuration. Assuming the resistors are connected in series, the total resistance (\(R_t_o_t_a_l\)) can be calculated by summing the individual resistances:

\(R_t_o_t_a_l\) = R1 + R2

\(R_t_o_t_a_l\) = 30Ω + 60Ω

\(R_t_o_t_a_l\) = 90Ω

Now, we can find the current I3 using Ohm's law:

I3 is the total current flowing in the circuit, which can be calculated by adding the currents flowing through R1 and R2:

I3 = I1 + I2

I3 = 0.6A + 0.3A

I3 = 0.9A (Amperes)

In summary, with an 18V source and resistors of 30Ω and 60Ω, the currents can be summarized as follows: I1 = 0.6A, I2 = 0.3A, and I3 = 0.9A.

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Answer:

The value is  \(v = 2 \ m/s\)

Explanation:

From the question we are told that

   The velocity of the each of the three cars is \(u_1 = u_2 = u_3 = 2 \ m/s\)

    The velocity of the fourth car is  \(u_4 = 4 \ m/s\)

    The initial velocity of the fifth car \(u_5 = 0 \ m/s\)

Generally from the law of momentum conservation we have that

    \(m_1 u_1 + m_2 u_2 + m_3 u_3 +m_4u_4 + m_5u_5 = [m_1 + m_2 + m_3 +m_4+ m_5]v\)

Given that the cars are identical then their mass will be the same

i.e

    \(m_1 =m_2 = m_3 = m_4 = m_5 = m\)

=>   \([u_1 + u_2 + u_3 +u_4 + u_5]m = 5mv\)

=>   \(2+ 2 + 2 +4 + 0 = 5v\)

= >   \(v = 2 \ m/s\)

The net force on particle q2 is a positive force pointing to the right.

To determine the net force on particle q2, we need to calculate the individual forces exerted on q2 by q1 and q3 and then add them vectorially.

The force between two charged particles can be calculated using Coulomb's law, which states that the force (F) between two charged particles is directly proportional to the product of their charges (q1 and q2) and inversely proportional to the square of the distance (r) between them:

F = k * (|q1| * |q2|) / r^2

where k is the electrostatic constant.

Given:

q1 = +8.0 μC

q2 = +3.5 μC

q3 = -2.5 μC

Distance between q1 and q2 (r12) = 0.10 m

Distance between q2 and q3 (r23) = 0.15 m

First, let's calculate the force between q1 and q2:

F12 = k * (|q1| * |q2|) / r12^2

Substituting the values:

\(F12 = (9 \times 10^9 N m^2/C^2) * ((8.0 \times 10^-6 C) * (3.5 \times 10^-6 C)) / (0.10 m)^2\)

Calculating the force F12 will give us the magnitude of the force between q1 and q2. However, since q1 and q2 have the same charge sign, the force will be repulsive, pointing to the right.

Next, let's calculate the force between q2 and q3:

\(F23 = k * (|q2| * |q3|) / r_{23}^2\)

Substituting the values:

F23 = (9 x 10^9 N m^2/C^2) * ((3.5 x 10^-6 C) * (2.5 x 10^-6 C)) / (0.15 m)^2

Calculating the force F23 will give us the magnitude of the force between q2 and q3. Since q2 and q3 have opposite charge signs, the force will be attractive, pointing to the left.

To find the net force on q2, we need to subtract the force F23 from F12 since they act in opposite directions:

Net force on q2 = F12 - F23

Finally, we need to consider the direction of the forces. Since F12 is repulsive (positive) and F23 is attractive (negative), the net force on q2 will be positive, pointing to the right.

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Answer:

c.

Equal to 200 N..........

Answer:

20 kg

Explanation:

The kinetic energy (KE) of an object is given by:

KE = (1/2) * m * v^2

Where m is the mass of the object, and v is its velocity.

We can rearrange this formula to solve for the mass:

m = 2 * KE / v^2

Plugging in the values given:

m = 2 * 1000 J / (10 m/s)^2

m = 20 kg

Therefore, the mass of the Puffin flying at 10 m/s with 1000 J of KE is 20 kg.

The pilot's total velocity is 116.3 knots in the direction of 62.3⁰.

The pilot's total velocity is calculated by applying the principle of relative velocity.

The total velocity is also the resultant velocity and the magnitude of the pilot's total velocity is calculated by applying Pythagoras theorem as follows;

R = √ (V₁² + V₂²)

R =  √ (54² + 103²)

R = 116.3 knots

The direction of the velocity vector is calculated as follows;

tan θ = (103 knots) / (54 knots)

θ = tan⁻¹ (103/54)

θ = 62.3⁰

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Answer:

Explanation:

1. First draw a free body diagram of the scenerio (a block sliding down a a slant surface).
2. Then we analyze the forces and write equations that satisfy Fnet = ma. This will give us the acceleration as the block slides down the surface.

3. Last, we can use the kinematic equation (vf^2 = vi^2 + 2as) and to solve the final speed of the block.

In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.

This relationship is described by the equation for the generated emf in a DC generator:

Emf = Φ * N * A * Z / 60

Where:

Emf is the generated electromotive force (in volts),

Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),

N is the number of turns in the armature winding,

A is the effective area of the armature coil (in square meters),

Z is the total number of armature conductors, and

60 is a constant representing the conversion from seconds to minutes.

From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.

The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.

The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.

Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.

By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.

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The mass of the planet is  5.98 × 10^24 kg.

To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.

First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.

Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.

Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.

Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2

Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2

Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.

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The acceleration and velocity of the plane is 78.57 m/s² and 157.14 m/s respectively

To calculate the acceleration of the plane, we use the formula below.

Where:

From the question,

Given:

Substitute these values into equation 1

To calculate the velocity, we use the formula below.

Where:

From the question,

Given:

Substitute these values into equation 2

Hence, The acceleration and velocity of the plane is 78.57 m/s² and 157.14 m/s respectively.
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An item at rest will remain at rest, and an object in motion will continue to move in a straight path at a constant speed, according to the first law of motion, commonly known as the law of inertia.

Newton's laws of motion govern how a baseball moves as a result of being thrown or struck. According to Newton's first law, a moving ball will continue to move in a straight line until other forces are acting on it.

The ball is severely distorted by the enormous force the bat applies to it ball being struck. The average force acting during the bat-ball collision is therefore about two tons, with a peak force of nearly four tons, during the 0.7 millisecond contact time. There's a lot of force there!

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Slope is rise over run, meaning the ratio of the change in height to the change in horizontal distance. So a slope of 15.80 corresponds to an angle of ascension θ of

tan(θ) = 15.80   →   θ ≈ 86.38°

The order of the blocks (i.e. whether the large one is pulling the smaller one up or vice versa) does not matter, since friction is not a concern. So if we take the connected blocks as a single mass, by Newton's law we have a net force acting parallel to the incline of

∑ F = P - (M + m) g sin(θ) = (M + m) a

(see the attached free body diagram)

where

P = magnitude of the push

g = 9.80 m/s²

a = 2.53 m/s²

and M and m are the given masses.

Then the system requires a push of

P = (M + m) (a + g sin(θ))

P = (14.2 kg + 4.73 kg) (2.53 m/s² + (9.80 m/s²) sin(86.38°))

P ≈ 233 N

If you have to find the tension in the rope, consider the free body diagram for one of the blocks. By Newton's second law, the net parallel force acting on, say, the larger block (if it's being pulled by the rope) is

∑ F = T - M g sin(θ) = M a

where

T = tension in the rope

Then

T = M (a + g sin(θ))

T = (14.2 kg) (2.53 m/s² + (9.80 m/s²) sin(86.38°))

T ≈ 175 N

Oliver and Maria are debating how to precisely determine the fluid's pressure at a particular depth.

What forces need to be considered in order to understand how a sphere falls in a fluid?

Stokes' law describes how spheres settle in a Newtonian fluid. A particle will sink if the buoyant force acting on a sphere submerged in a Newtonian fluid is not equal to or greater than the gravitational force acting on the sphere. The net downward force on a sphere is what separates the settling force from the buoyant force.

What connection exists between point pressure and depth in a fluid?

Because a liquid's pressure also increases with depth, the pressure of a liquid is inversely proportional to its depth.

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Answer:

the red at the bottom should not count, but the red at the top is the least dense because it floats upon the other liquids

Explanation:

hope this helps

Answer:

Polishing the rough surface.

Oiling or lubricating with graphite or grease the moving parts of a machine.

Providing all bearings or wheels between the moving parts of a machine or vehicles reduce friction and allow smooth movement as rolling friction is less than sliding friction.

Explanation:

Answer:

The force of friction slows down the motion of objects! (Simple answer)

Explanation:

Friction is the rubbing of two objects on each other, so it slows down the motion.

Answer:

Wow wouldn't even know what it says lol. Thank you have a goodnight

The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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Answer:

198 meters

Explanation:

I'm not sure but hope it helps

Answer:

a = 0.1 s b. 10 s

Explanation:

Given that,

The frequency in circular motion, f = 10 Hz

(a) Let T is the period of itsrotation. We know that,

T = 1/f

So,

T = 1/10

= 0.1 s

(b) Frequency is number of rotations per unit time. So,

\(t=\dfrac{n}{f}\\\\t=\dfrac{100}{10}\\\\t=10\ s\)

Hence, this is the required solution.

The resultant of the displacement is 336.5m

The process of splitting a vector into its components is called resolution of the vector. The vectors are splitted into vertical and horizontal component.

For the first displacement;

The vertical component = - 150 sin45 = -106.1 m

The horizontal component = - 150 cos 45° = -106.1 m

For the second displacement;

The vertical displacement = - 85sin90 = -85

The horizontal component = 0

For the third displacement;

The vertical displacement = 550 sin55 = 450.5

The horizontal displacement = 550 cos 55 = 315.5

Sum of vertical component = 450.5-85-106.1 = 263.4

sum of horizontal component = 315.5 -106.1 = 209.4

Using Pythagorean theorem

R = √ 263.4² + 209.4²

R = √113227.92

R = 336.5m

The resultant angle = tan^-1( 263.4/209.4)

= tan^-1(1.26)

= 51.56°

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Answer:

Planks?

Explanation:

It's kinda resting

Answer:

weights

walking

stretching

etc.

The maximum length of runway needed and tension in the towrope will be 175.05 m and 5999N.

For solving this question we will use the laws of Kinematics as well as the Newton's Laws of Motion. According to the third law of Kinematics

v² = u² + 2aS ; where v is the final velocity, u is the initial velocity, a is the acceleration and S is the displacement.

According to Newton's Laws of Motion we know that the net force is equal to product of mass and acceleration that is

F = ma ; where F is net force, m is mass of the body and a is the acceleration.

Now, form the free body diagram of the gliders, we balance the forces by Newton's law of motion as:

For glider 1 the forces in x axis will be:

T₁ - T₂ - f = ma                                                    ......(1)

where T₁ and T₂ are tensions on glider 1 and 2 respectively and f is the frictional force.

In y axis the forces will be:

N₁ - W = 0 ; where N₁ is the normal on first glider and W is the weight due to gravity.

For glider 2 the forces in x axis will be:

T₂ - f = ma                                                           ......(2)

where T₂ is tensions on glider 2 and f is the frictional force.

In y axis the forces will be:

N₂ - W = 0 ; where N₂ is the normal on second glider and W is the weight due to gravity.

From equation (1) and (2) we get

T₁ - 2f = 2ma

a = T₁ - 2f/2m

a = 12000 - 2(2800)/2(700)

a = 6400/1400

a = 4.57 m/s²

Now from laws of Kinematics we have

v² = u² + 2aS; here the initial velocity is zero so u = 0 and v = 40 m/s

(40)² = 0 + 2 × 4.57 × S

S = 1600/9.14

S = 175.05 m

Now for the tension in the second rope of glider we use equation (2) that is

T₂ - f = ma

T₂ = ma + f

T₂ = 700 × 4.57 + 2800

T₂ = 3199 + 2800

T₂ = 5999 N

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Answer:

\(\pi 1 = \frac{h}{l}\)

\(\pi 2 =\) б / \(l^2gp\)

\(\frac{h}{l} =\) Ф ( б / \(l^2gp\) )

Explanation:

Develop a suitable set of dimensionless parameters for this problem

The set of dimensionless parameters for this problem is :

\(\pi 1 = \frac{h}{l}\)

\(\pi 2 =\) б / \(l^2gp\)

\(\frac{h}{l} =\) Ф ( б / \(l^2gp\) )

and they are using the pi theorem, MLT systems

attached below is a detailed solution

Answer:

Electron

Explanation:

Because electron are not hadrons so electron are not affected by strong force

Particles that can not be affected by strong forces are electrons.

Electrons are the rotating material around the nucleus of an atomic element in orbit.

Atoms have electrostatic energy between their electrons. This force is not broken by a force as strong as nuclear power.

Strong force is a fundamental interaction of nature that acts between subatomic particles of matter.

There are four basic forces in nature:

Therefore, particles that are unaffected by strong force are electrons.

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Answer:

Since a sound wave consists of a repeating pattern of high pressure moving through a medium it is sometimes referred to as a pressure wave

Explanation:

Since a sound wave consists of a repeating pattern of high pressure moving through a medium it is sometimes referred to as a pressure wave

Answer:

A sound wave is a pattern of disturbance caused by the movement of energy.

Pressure Waves may refer to one of the two main types of elastic body waves , called seismic waves in seismology.

hope it helps !!~

In the diagram tha shows snapshots of an oscillator at different times, the frequency of the oscillation is 0.555 Hz.

The period of the oscillation is the time taken for the for the object to return to its original position. (ie. Displacement = 0). From the above snapshot,

Period of oscillation = 1.80s.

From here, finding the frequency is simple as, Frequency = 1/Period. Hence,

Frequency = 1/1.80

= 0.555 Hz (3 sf).

The frequency of the oscillation is indeed 0.555 Hz. The frequency represents the number of oscillations or cycles per second. In this case, the object completes approximately 0.555 oscillations per second.

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