Ashley’s math average decreased 12 points to 78. Then she completed an extra credit assignment and raised her final average by 5 points. Write an equation to show how Ashley’s average changed.

The statement “there exists a function f such that f(x) < 0, f’(x) > 0, and f”(x) < 0 for all x” is false.

To understand why this statement is false, we must first understand what the symbols mean. The symbol f(x) refers to a function of x, and the symbols f’(x) and f”(x) refer to the first and second derivatives of the function, respectively.

The statement is saying that for all x, the function f(x) will be less than 0, the first derivative f’(x) will be greater than 0, and the second derivative f”(x) will be less than 0.

To show that this statement is false, we need to find an example of a function where this is not the case. Let’s consider the function f(x) = x³. At x = 0, this function is equal to 0, and so f(x) < 0 is not true. Additionally, the first derivative at x = 0 is f’(0) = 0, which is not greater than 0. Thus, the statement is false.

We can also show that this statement is false by looking at the graph of the function f(x). A function with the properties given in the statement would have a graph that looks like a “U” shape, with a minimum point at the origin. However, this is not the case for the function f(x) = x³. The graph of this function is a parabola, which does not have the desired shape.

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Answer:

A = 30

B = 60

C = 90

Step-by-step explanation:

Ratio of 1:2:3 can be written as x + 2x + 3x, x being angle A (the smallest angle)

As the sum of all the angles of a triangle must be 180, this gives us the equation:

x + 2x + 3x = 180

6x = 180

x = 30

x = 30 = A

2x = 2(30) = 60 = B

3x = 3(30) = 90 = C

30 + 60 + 90 = 180

b. Linear programming model is the correct option.

A linear programming model is a mathematical technique used to find the best outcome in a given set of constraints. In this case, Manders Manufacturing Corporation is trying to determine the optimal product mix for its two products, metal (M) and scrap metal (S), based on certain constraints. The objective is to maximize the profit, represented by the function Z = $30M + $70S.

The constraints are represented by the inequalities:

3M + 2S ≤ 15

2M + 4S ≤ 18

These constraints define the limitations on the production of metal and scrap metal. The model aims to find values of M and S that satisfy these constraints while maximizing the objective function.

Using linear programming techniques, the corporation can solve this model to find the optimal values for M and S that will maximize their profit. This approach allows them to make data-driven decisions and allocate their resources efficiently. By formulating the problem as a linear programming model, Manders Manufacturing Corporation can make informed choices about the optimal product mix to achieve their business objectives.

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The set of mobile gaming apps in which the number of monthly users was greater than 12 million is {A, B}

A set is a collection of distinct objects, called elements or members, that are brought together by a common property or rule.

Sets can be represented using set notation, which uses curly brackets {} to enclose the elements of the set. For example, the set of natural numbers less than 5 can be represented as {1, 2, 3, 4}.

The set of mobile gaming apps in which the number of monthly users was greater than 12 million can be determined by checking given the table for mobile gaming apps with value greater than 12 million.

You will notice that only A and B have values greater than 12 million. That is 23 million and 13 million for A and B respectively.

Thus, the set will be {A, B}

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Answer:

12

Step-by-step explanation:

sum of all angles of triangle =180

3x-12+2x+11x=180

16x-12=180

16x=192

x=12

___________

\( \: \)

\(\boxed{ \rm{answer \: by \: { \boxed{ \rm{☆HayabusaBrainly}}}}}\)

3x - 12 + 2x + 11x = 180°

16x - 12 = 180°

16x = 180 + 12

16x = 192

x = 192 ÷ 16

x = 12✔ (D.)

Answer:

Step-by-step explanation:

C(x) = ax2 + bx + c

C(x) = x2  -19x + 50

8150 = x2  -19x + 50

x2  -19x + 50 = 8150

x2 -19x-8100 = 0

this is a quadratic equation, solved as

x = −b ± √(b2 − 4ac) 2a ·

or

x = −(-19) ± √((-19)x(-19) − 4(1) x(-8100))/2 ·

x= 19± √((-19)x(-19) − 4(1) x(-8100))/2

x = 100

Point B is located at 150,000 and can be described as both a multiple of a power of 10 and a value. Point A is located at 60,000,000 and can also be described as both a multiple of a power of 10 and a value. Point C can be plotted between B and A and can be described as both a multiple of a power of 10 and a value.

The number line can be used to represent both powers of 10 and standard decimal values. Point B can be described as (1.5) • 106 or 150,000, while point A can be described as (6) • 107 or 60,000,000. Point C can be plotted between B and A, and can be described as (3) • 107 or 30,000,000.

The number line provides a useful tool for representing numbers, whether they are expressed as powers of 10 or standard decimal values. Points on the number line can be described as both multiples of a power of 10 and values, depending on how they are represented.

Point B, for example, is located at 150,000 and can be described as a multiple of a power of 10 (1.5 • 106) or as a value. Similarly, point A is located at 60,000,000 and can be described as both a multiple of a power of 10 (6 • 107) and a value.

Point C can be plotted between B and A, and can be described as both a multiple of a power of 10 (3 • 107) and a value. The number line allows us to visualize the relative positions of numbers and to describe them in different ways, depending on our needs.

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Answer:

280 and 8

Step-by-step explanation:

the LCM is the lowest common multiple

the lowest multiple that can Divide 40 and 56 without a remainder = 280

the Hcf Is the highest common factor of 40 and 56

the highest number that can Divide both =8

Histograms are used to determine the empirical distribution of a variable. Therefore, option (e) is the correct one.

Histogram is used to summarize discrete or continuous data measured on an interval scale. It is often used to describe key features of the distribution of data in a practical way.

A histogram divides the range of possible values ​​in a data set into different classes or groups. For each group, a rectangle is created with a base length equal to the range of values ​​in that particular group and a length equal to the number of observations that fall into that group.

Histograms are similar to column charts, but there are no gaps between the bars. Histograms generally have equal width bars.

Thus, it can be concluded that histograms are used to determine the empirical distribution of a variable. Therefore, option (e) is the correct one.

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The other two angle measures of a right triangle with side lengths 5, 12, and 13 can be found using trigonometric ratios. Let's label the sides of the triangle as follows:

- The side opposite the angle we are looking for is 5.
- The side adjacent to the angle we are looking for is 12.
- The hypotenuse is 13.

To find the first angle, we will use the inverse tangent function (tan^(-1)). The formula is:
Angle = tan^(-1)(opposite/adjacent)

Plugging in the values, we get:
Angle = tan^(-1)(5/12)

Using a calculator, we find this angle to be approximately 22.6 degrees (rounded to the nearest degree).

To find the second angle, we will use the fact that the sum of the angles in a triangle is 180 degrees. Therefore, the second angle can be found by subtracting the right angle (90 degrees) and the first angle from 180 degrees.
Second angle = 180 - 90 - 22.6

Calculating this, we find the second angle to be approximately 67.4 degrees (rounded to the nearest degree).

Therefore, the other two angle measures of the right triangle are approximately 23 degrees and 67 degrees.

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Writing linear equations given two points can be a useful skill when graphing linear equations.

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The z-values for the given situations are approximate:

a. The area to the left of z is 0.1827. z = -0.90

b. The area between −z and z is 0.9830. z = 2.17

c. The area between −z and z is 0.2148. z = 0.85

d. The area to the left of z is 0.9997. z = 3.49

e. The area to the right of z is 0.6847. z= -0.48

a. For an area of 0.1827 to the left of z, the corresponding z-value can be found using a standard normal distribution table or a statistical calculator. The z-value is approximately -0.90.

b. To find the z-value for an area between -z and z equal to 0.9830, we need to find the value that corresponds to (1 - 0.9830)/2 = 0.0085 in the upper tail of the standard normal distribution. Using the table or calculator, the z-value is approximately 2.17.

c. Similarly, for an area between -z and z equal to 0.2148, we find the value that corresponds to (1 - 0.2148)/2 = 0.3926 in the upper tail. The z-value is approximately 0.85.

d. For an area of 0.9997 to the left of z, we find the value that corresponds to 0.9997 in the upper tail. The z-value is approximately 3.49.

e. To find the z-value for an area to the right of z equal to 0.6847, we find the value that corresponds to 1 - 0.6847 = 0.3153 in the upper tail. The z-value is approximately -0.48.

In summary, the z-values for the given situations are approximate:

a. -0.90

b. 2.17

c. 0.85

d. 3.49

e. -0.48

These values can be used to determine the corresponding percentiles or probabilities for the standard normal distribution. The values are typically found using standard normal distribution tables or statistical calculators that provide the cumulative probability distribution function (CDF) for the standard normal distribution.

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Answer: -8,-4,0,4,8,12

Step-by-step explanation:

The six numbers of the arithmetic progression are -8, -4, 0, 4, 8, 12

where

a = first term

d = common difference

n = number of terms

d = 4

first term = a

2nd term = a + 4

3rd term = a + (3 - 1) 4 = a + 8

4th term = a + (4 - 1) 4 = a + 12

5th term = a + (5 - 1) 4 = a + 16

6th term = a + (6 - 1) 4 = a + 20

sum of its 6 terms = 12

Therefore,

a + a + 4 + a + 8 + a + 12 + a + 16 + a + 20 = 12

6a + 60 = 12

6a = 12 - 60

6a = -48

a = -48/6

a = -8

2nd term = -8 + 4 = -4

3rd term = -8 + 8 = 0

4th term = -8 + 12 = 4

5th term = -8 + 16 = 8

6th term = -8 + 20 = 12

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The given expression is irreducible or prime in nature.

Given expression is

\(3x^2+x+7\)

The discriminant tells us whether there are two solutions, one solution, or no solutions.

Since Discriminant of this quadratic function is,

\((1)^2-4*3*7=-83\) , negative

So factors without imaginary terms are not possible.

Thus given expression is irreducible or prime in nature.

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The probability of having a number greater than 3 on the dice and at most 1 head is 0.375. To solve the problem, draw a tree diagram showing all possible outcomes and write the sample space on paper. The total number of possible outcomes is 24. so, correct option id A

Here is the solution to your problem with all the necessary terms included:When two coins are tossed and one dice is rolled, the probability of having a number greater than 3 on the dice and at most 1 head is 0.375.

To solve the problem, we will have to draw a tree diagram to show all the possible outcomes and write the sample space on a sheet of paper.Let's draw the tree diagram for the given problem statement:

Tree diagram for tossing two coins and rolling one dieThe above tree diagram shows all the possible outcomes for tossing two coins and rolling one die. The sample space for the given problem statement is:Sample space = {HH1, HH2, HH3, HH4, HH5, HH6, HT1, HT2, HT3, HT4, HT5, HT6, TH1, TH2, TH3, TH4, TH5, TH6, TT1, TT2, TT3, TT4, TT5, TT6}

The probability of having a number greater than 3 on the dice and at most 1 head can be calculated by finding the number of favorable outcomes and dividing it by the total number of possible outcomes.

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2 1/3 Lego planes every 40 minutes

To determine which set of data most likely has a mean closest to 29.5, we need to analyze the shape and position of the histograms in relation to the value 29.5.

Looking at the histograms described:

The first histogram ranges from 9 to 48, and the upward trend starts from 1 and ends at 33, followed by a downward trend. This histogram suggests that there may be values lower than 29.5, which would bring the mean below 29.5.

The second histogram ranges from 15 to 48, with an upward trend from 1 to 30 and then a downward trend. Similar to the first histogram, it suggests the possibility of values lower than 29.5, indicating a mean below 29.5.

The third histogram ranges from 12 to 56, and the upward trend starts from 1 and ends at 32, followed by a downward trend. This histogram covers a wider range but still suggests the possibility of values below 29.5, indicating a mean below 29.5.

The fourth histogram ranges from 15 to 54 and exhibits multiple trends. While it has fluctuations, it covers a wider range and includes both upward and downward trends. This histogram suggests the possibility of values above and below 29.5, potentially resulting in a mean closer to 29.5.

Based on the descriptions, the fourth histogram, with its more varied trends and wider range, is most likely to have a mean closest to 29.5.

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Answer:

f(5) = 22; f(9) = 34

Step-by-step explanation:

f(5) = 3(5) +7

f(5) = 22

f(9) = 3(9) +7

f(9) = 34

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data

x+1/2=21/14

x = ?

Step 02:

14 (x + 1 ) = 2 * 21

14x + 14 = 42

14x = 42 - 14

x = 28 / 14

x = 2

The answer is:

The value of x is 2

Answer:

xjxjxjzjzjxxjxjxjxjx

One way to summarize hotel costs versus quality ranking in New York City is by using a scatter plot graph. The x-axis represents the cost per night, and the y-axis represents the quality ranking. This graph allows for easy visual comparison between the two variables.

A scatter plot graph is an effective way to summarize the relationship between hotel costs and quality rankings in New York City.

By plotting the cost per night on the x-axis and the quality ranking on the y-axis, viewers can easily see the relationship between the two variables. Hotels with higher quality rankings and lower costs per night will appear in the upper left-hand corner of the graph, while hotels with lower quality rankings and higher costs per night will appear in the lower right-hand corner.

By using a scatter plot graph, the travel website can provide valuable information to users who are looking to compare hotel costs and quality rankings in New York City.

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The correct option is b which tells that an optimal solution to a linear programming problem must lie at the intersection of at least two constraints.

Linear programming is an optimization technique that is fine for the purpose of getting the best solution such as maximizing profit or certain 4th-era quantities.

When there are just two choice variables, the graphic method of solving a linear programming issue can be employed.

It is fine by modelling real-life problems into mathematical models that have linear relationships or constraints such as in the form of objective functions.

In linear programming, an objective function defines the formula for quantity optimization and the goal from this is to determine variable values that maximize or minimize the objective function depending on the problem robbery solved.

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Answer:

20

Step-by-step explanation:

a c will have the same angle as b d

Answer:

147.344

Step-by-step explanation:

1st way

184.18 times .20 = 36.836

184.18 minus 36.836 = 147.344

2nd way

100% - 20% off = 80%

184.14 times 80% = 147.344

The area of the parallelogram is 324 square yards.

What is a parallelogram ?

A parallelogram is a four-sided geometric shape that has two pairs of parallel sides. It isdefined by its four vertices, four sides, and two diagonals that intersect at their midpoint. The opposite sides of a parallelogram are congruent, and the opposite angles are also congruent. The adjacent angles are supplementary and add up to 180 degrees.

To find the area of a parallelogram, we need to multiply the length of the base by the height, which is the perpendicular distance from the base to the opposite side. This formula is similar to finding the area of a rectangle, where the base is one side of the rectangle and the height is the distance from that side to the opposite side.

Calculating the area of the given parallelogram :

The area of a parallelogram is  A = bh, where b is the base and h is the height.

Given the height of the parallelogram is 12 yards and the base is 27 yards. Using the formula for the area of a parallelogram, we can calculate the area as follows:

A = bh

A = 27 yards × 12 yards

A = 324 square yards

Therefore, the area of the parallelogram is 324 square yards.

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False. The expected cell frequency in statistical analysis, specifically in the context of contingency tables and chi-square tests, is not based on the researcher's opinion. Instead, it is determined through mathematical calculations and statistical assumptions.

In contingency tables, the expected cell frequency refers to the expected number of observations that would fall into a particular cell if the null hypothesis of independence is true (i.e., if there is no relationship between the variables being studied). The expected cell frequency is calculated based on the marginal totals (row totals and column totals) and the overall sample size.

The expected cell frequency is computed using statistical formulas and is not influenced by the researcher's opinion or subjective judgment. It is a crucial component in determining whether the observed frequencies in the cells significantly deviate from what would be expected under the null hypothesis.

By comparing the observed cell frequencies with the expected cell frequencies, statistical tests like the chi-square test can assess the association or independence between categorical variables in a data set.

Thus, the statement "the expected cell frequency is based on the researcher's opinion" is false. The expected cell frequency is derived through statistical calculations and is not subject to the researcher's subjective input.

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Answer:

2 hour of babysitting and 4 hours of stacking groceries

Step-by-step explanation:

sorry if wrong

The maximum amount of profit the company can make is 9274

Differentiation is the rate of change of one quantity with respect to the other.

It is the ratio of the change in one quantity, usually the dependent quantity to the change in another related quantity, usually the independent quantity.

Analysis:

y= -6x^2 + 600x - 5726

differentiating the equation,

dy/dx = -12x + 600

for maximum selling price, dy/dx = 0

-12x + 600 = 0

12x = 600

x = 50

The maximum selling price is 50, so substituting x to find y

y = -6(50)(50) + 600(50) - 5726 = 9274

In conclusion, the maximum amount of profit the company can make is 9274.

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The probability that the first 5 locations are in water and the last 2 locations are on land is 0.0010.

The probability of selecting a water location is 71%, which means the probability of selecting a land location is 29%. To find the probability of a specific sequence of locations, we multiply the probabilities of each individual event.

For the first 5 locations to be in water, the probability is (0.71)^5 since each location is independent. Similarly, the probability of the last 2 locations being on land is (0.29)^2.

To find the probability of both events occurring, we multiply these probabilities together: (0.71)^5 * (0.29)^2 = 0.0010.

Therefore, the probability that the first 5 locations are in water and the last 2 locations are on land is 0.0010.

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The scores that need to be examined in order to determine the median value of n = 24 are the 12th and 13th values.

In order to determine the median value of n = 24, you would need to examine the 12th and 13th scores. This is because the median value is the middle number of a sequence of values, so when there is an even number of values, the median is the average of the two numbers in the middle. So in the case of n = 24, there are two values in the middle, the 12th and 13th numbers. To find the median, you would need to add the two values together and divide the result by two. This will give you the median value of the sequence. If there were an odd number of values instead of an even number, then the median would be the middle number rather than the average of two numbers.

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