Answer:
21
Step-by-step explanation:
3x7=21 possible combinations
A book is marked down by 28 percent from an original price of $19.50. What is the new price?
Step-by-step explanation:
First find 28% of $19.50:
($19.50) / (100) × (28) = $5.46
Now minus the 285 from the original price:
($19.50) - ($5.46) = $14.04
The answer is $14.04
Hope it helped :)
In circle B, BC = 11 and m/CBD = 20°. Find the length of CD. Express your
answer as a fraction times T.
Answer: Length of CD =
B
Submit Answer
BRE
Help me please
The length of the arc CD is 3.84 units
What is length of an arc?Arc length formula is used to calculate the measure of the distance along the curved line making up the arc.
The length of an arc is expressed as;
l = θ/360 × 2πr
where r is radius of the circle and θ is the angle substended by the arc.
2πr is the circumference of the circle so we can also say that the length of an arc is
θ/360 × circumference of circle
Therefore;
l = 20/360 × 2 × 22/7 × 11
l = 9680/2520
l = 3.84 units
Therefore length of the arc CD is 3.84units
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Find the root of the following equation using Factorization method
√2x² + 7x + 5√2 = 0
Answer:
- 5√2 / 2 , - √2
Step-by-step explanation:
√2 x² + 7x + 5√2 = 0
√2 5
1 √2
(√2 x + 5) (x + √2) = 0
√2 x + 5 =0 x = - 5/√2 = - 5√2 / 2
or x + √2 = 0 x = -√2
Complete the folllowing two column proof
The two column proof is written as follows
Statement Reason
line LQ || Line NP given
< Q is congruent to < N Alternate interior angles
< L is congruent to < P Alternate interior angles
< LMQ is congruent to < PMN Vertical angle theorem
Δ LMQ similar Δ PMN Definition of similar triangles
What is similar triangles?Similar triangles are triangles that have the same shape but may differ in size. In other words, they have the same angles but their sides may be of different lengths.
If two triangles are similar, it means that their corresponding angles are equal, and their corresponding sides are in proportion to each other.
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The distance between city A and city B is 760km. A car starts to travel from A to B at 80 km/h at 8 o'clock. The other car starts to travel from B to A at 120 km/h at 10 o'clock. At what time will the cars meet?
Question 3
the stock market crash of 1929 saw many share prices collapse to a fraction of their previous value. the worst period for this were the two
days monday, october 28 and tuesday, october 29 in which the dow jones industrial average dropped by a total of 25% to a value of 198
points. what was its value before the 2-day drop?
Using proportions, it is found that it's value before the 2-day drop was of 264 points.
What is a proportion?A proportion is a fraction of a total amount, and the measures are related using a rule of three.
In this problem, the value dropped by 25%, that is, it was 75% of the original amount, and the dropped value was of 198 points, hence the original amount was:
0.75x = 198
x = 198/0.75
x = 264
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A woman has 31 coins in her pocket, all of which are dimes and quarters. If the total value of the coins is $ 5.65, how many dimes and how many quarters does she have?
Answer:
14 dimes and 17 quarters
Step-by-step explanation:
d and q are the number of dimes and quarters, respectively.
"31 coins, all of which are dimes and quarters."
d+q = 31
d = 31-q
"the value of the coins is $5.65"
0.10d + 0.25q = 5.65
substitution
0.10(31-q) + 0.25q = 5.65
3.10-0.10q + 0.25q = 5.65
0.15q = 2.55
q = 17
d = 31-q = 14
14 dimes and 17 quarters
Find the centroid of the region bounded by the given curves. y = 8 sin(2x), y = 8 cos(2x), x = 0, x = 8
The coordinates of the centroid are the average values of the \(x\)- and \(y\)-coordinates of the points \((x,y)\) that belong to the region. Let \(R\) denote the bounded region. These averages are given by the integral expressions
\(\dfrac{\displaystyle \iint_R x \, dA}{\displaystyle \iint_R dA} \text{ and } \dfrac{\displaystyle \iint_R y \, dA}{\displaystyle \iint_R dA}\)
The denominator is just the area of \(R\), given by
\(\displaystyle \iint_R dA = \int_0^8 \int_{\min(8\sin(2x), 8\cos(2x))}^{\max(8\sin(2x),8\cos(2x))} dy \, dx \\\\ ~~~~~~~~ = \int_0^8 |8\sin(2x) - 8\cos(2x)| \, dx \\\\ ~~~~~~~~ = 8\sqrt2 \int_0^8 \left|\sin\left(2x-\frac\pi4\right)\right| \, dx\)
where we rewrite the integrand using the identities
\(\sin(\alpha + \beta) = \cos(\alpha)\cos(\beta) + \sin(\alpha)\sin(\beta)\)
Now, if
\(8(\cos(2x) - \sin(2x)) = R \sin(2x + \alpha) = R \sin(2x) \cos(\alpha) + R \cos(2x) \sin(\alpha)\)
with \(R>0\), then
\(\begin{cases} R\cos(\alpha) = 8 \\ R\sin(\alpha) = -8 \end{cases} \implies \begin{cases}R^2 = 128 \\ \tan(\alpha) = -1\end{cases} \implies R=8\sqrt2\text{ and } \alpha = -\dfrac\pi4\)
Find where this simpler sine curve crosses the \(x\)-axis.
\(\sin\left(2x - \dfrac\pi4\right) = 0\)
\(2x - \dfrac\pi4 = n\pi\)
\(2x = \dfrac\pi4 + n\pi\)
\(x = \dfrac\pi8 + \dfrac{n\pi}2\)
In the interval [0, 8], this happens a total of 5 times at
\(x \in \left\{\dfrac\pi8, \dfrac{5\pi}8, \dfrac{9\pi}8, \dfrac{13\pi}8, \dfrac{17\pi}8\right\}\)
See the attached plots, which demonstrates the area between the two curves is the same as the area between the simpler sine wave and the \(x\)-axis.
By symmetry, the areas of the middle four regions (the completely filled "lobes") are the same, so the area integral reduces to
\(\displaystyle \iint_R dA \\\\ ~~~~ = 8\sqrt2 \left(-\int_0^{\pi/8} \sin\left(2x-\frac\pi4\right) \, dx + 4 \int_{\pi/8}^{5\pi/8} \sin\left(2x-\frac\pi4\right) \, dx \right. \\\\ ~~~~~~~~~~~~~~~~~~~~ \left. - \int_{17\pi/8}^8 \sin\left(2x-\frac\pi4\right) \, dx\right)\)
The signs of each integral are decided by whether \(\sin\left(2x-\frac\pi4\right)\) lies above or below axis over each interval. These integrals are totally doable, but rather tedious. You should end up with
\(\displaystyle \iint_R dA = 40\sqrt2 - 4 (1 + \cos(16) + \sin(16)) \\\\ ~~~~~~~~ \approx 57.5508\)
Similarly, we compute the slightly more complicated \(x\)-integral to be
\(\displaystyle \iint_R x dA = \int_0^8 \int_{\min(8\sin(2x), 8\cos(2x))}^{\max(8\sin(2x),8\cos(2x))} x \, dy \, dx \\\\ ~~~~~~~~ = 8\sqrt2 \int_0^8 x \left|\sin\left(2x-\frac\pi4\right)\right| \, dx \\\\ ~~~~~~~~ \approx 239.127\)
and the even more complicated \(y\)-integral to be
\(\displaystyle \iint_R y dA = \int_0^8 \int_{\min(8\sin(2x), 8\cos(2x))}^{\max(8\sin(2x),8\cos(2x))} y \, dy \, dx \\\\ ~~~~~~~~ = \frac12 \int_0^8 \left(\max(8\sin(2x),8\cos(2x))^2 - \min(8\sin(2x),8\cos(2x))^2\right) \, dx \\\\ ~~~~~~~~ \approx 11.5886\)
Then the centroid of \(R\) is
\((x,y) = \left(\dfrac{239.127}{57.5508}, \dfrac{11.5886}{57.5508}\right) \approx \boxed{(4.15518, 0.200064)}\)
(1) Find the volume in the first octant bounded by y^2=4−x and y=2z
(2) Find the volume bounded by z=x^2+y^2and z=4
the volume in the first octant bounded by\(y^2=4−x\) and y=2z is pi/36 sqrt(3).
(1) To find the volume in the first octant bounded by the surfaces \(y^2 = 4 - x\) and y = 2z, we can set up a triple integral in cylindrical coordinates.
First, we need to determine the bounds for our variables. Since we are working in the first octant, we know that 0 <= z, 0 <= theta <= pi/2, and 0 <= r.
Next, we need to find the equation for the upper and lower bounds of z in terms of r and theta. We can start with the equation \(y^2 = 4 - x\) and substitute y = 2z to get:
\((2z)^2 = 4 - x\)
\(4z^2 = 4 - x\)
\(x = 4 - 4z^2\)
We can then use this equation along with the equation z = y/2 to get the bounds for z:
\(0 < = z < = (4 - x)^(1/2)/2 = (4 - 4z^2)^(1/2)/2\)
Squaring both sides, we get:
\(0 < = z^2 < = (1 - z^2)/2\)
\(0 < = 2z^2 < = 1 - z^2\)
\(z^2 < = 1/3\)
So the bounds for z are:
\(0 < = z < = (1/3)^(1/2)\)
Finally, we can set up the triple integral in cylindrical coordinates:
V = ∫∫∫ r dz dtheta dr
with bounds:
0 <= r
0 <= theta <= pi/2
\(0 < = z < = (1/3)^(1/2)\)
and integrand:
r
So the volume in the first octant bounded by y^2=4−x and y=2z is:
V = ∫∫∫ r dz dtheta dr
= ∫ from 0 to\((1/3)^(1/2) ∫ from 0 to pi/2 ∫ from 0 to r r dz dtheta dr\)
= ∫ from 0 to\((1/3)^(1/2) ∫ from 0 to pi/2 r^2/2 dtheta dr\)
= ∫ from 0 to\((1/3)^(1/2) r^2 pi/4 dr\)
\(= pi/12 (1/3)^(3/2)\)
= pi/36 sqrt(3)
Therefore, the volume in the first octant bounded by\(y^2=4−x\) and y=2z is pi/36 sqrt(3).
(2) To find the volume bounded by z = x^2 + y^2 and z = 4, we can use a triple integral in cylindrical coordinates.
First, we need to determine the bounds for our variables. Since we are working in the region where z is bounded by \(z = x^2 + y^2\) and z = 4, we know that 0 <= z <= 4.
Next, we can rewrite the equation \(z = x^2 + y^2\) in cylindrical coordinates as \(z = r^2.\)
So the bounds for r and theta are:
0 <= r <= 2
0 <= theta <= 2pi
And the bounds for z are:
\(r^2 < = z < = 4\)
Finally, we can set up the triple integral in cylindrical coordinates:
V = ∫∫∫ r dz dtheta dr
with bounds:
0 <= r <= 2
0 <= theta <= 2pi
\(r^2 < = z < = 4\)
and integrand: 1
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A food company advertises that their boxes of cereal weigh 18 ounces. Let X denote the actual amount of cereal in each box. Suppose we know that X is Normally distributed with a mean of 18.03 ounces having standard deviation of 0.05 ounces. Determine the probability that the mean amount of cereal per box in a case is less than 18 ounces
The probability that the mean amount of cereal per box in a case is less than 18 ounces is 0.2743 for a random variable following a normal distribution.
A probability distribution that is symmetric about the mean is the normal distribution, sometimes referred to as the Gaussian distribution. The normal distribution appears as a “bell curve” on a graph.
Given,
X is a random variable denoting the actual amount of cereal in each box.
Mean, \(\mu\)=18.03 ounces
Standard deviation, \(\sigma\)=0.05 ounces
To determine the probability that the mean amount of cereal per box in a case is less than 18 ounces= P(X<18)
\(P(\frac{X-\mu}{\sigma} < \frac{18-\mu}{\sigma})\)
\(P(z < 18-18.03/0.05)=P(z < -0.6)\)
\(P(z < -0.6)=0.2743\)
Thus, the probability that the mean amount of cereal per box in a case is less than 18 ounces is 0.2743
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Which expression gives the volume of a cylinder, where B is the base area and h is the height?
The expression for the volume of the cylinder is πB.
What is a cylinder?The cylinder is a three-dimensional figure that has a radius and a height.
The volume of a cylinder is πr²h.
Example:
The volume of a cup with a height of 5 cm and a radius of 2 cm is
Volume = 3.14 x 2 x 2 x 5 = 62.8 cubic cm
We have,
Volume = πr²h
Base area = πr²
Now,
B = πr²
r² = B/h
r = √(B/h)
Now,
Volume.
= πr²h
= π x B/h x h
= πB
Thus,
The volume of the cylinder is πB.
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The correct answer is Bh
find the initial value seventeen years from now, Ms. speedis car, which is depreciating at 20% per year, will be worth $500
Answer:
Around 22200 dollars
Step-by-step explanation:
Firstly, it was depreciating 20% per year for 17 years. So, if we were to go back in time, it would be appreciating by 25%. Therefore, after doing the plugging in, it is 500 * 1.25^17. The initial value is around 22200. It is around 22204, to be exact.
Solid #1
SA= 539 cm?
V = 2058 cm
Solid #2
SA = 704 cm?
V?
Answer:
2688 cm³
Step-by-step explanation:
2058×704/539 = 2688 cm³
8(4x - 12).
Plz help
Consider triangle HJL, where line HK is the perpendicular bisector of segment JL. Which additional piece of information is needed to prove HJKandHLK BY THE SIDE-side-side congruence theorem
Given
Answer
Since it is given
KJ=KL
HK=HK (Common)
The only condition to show SSS congruency is HJ = HL
Julie is arranging 36 books and 54 magazines on a book shelf. If she puts the same amount and not mix them. What is the greatest number that she can put on each shelf? 5) Between what tu HELP ASAP
Answer:
To determine the greatest number of books and magazines Julie can put on each shelf without mixing them, we need to find the highest common factor (HCF) of the given numbers.
The prime factorization of 36 is 2^2 * 3^2.
The prime factorization of 54 is 2 * 3^3.
To find the HCF, we take the highest power of each common prime factor. In this case, the HCF would be 2^2 * 3^2, which is 4 * 9 = 36.
Therefore, Julie can put a maximum of 36 books and 36 magazines on each shelf without mixing them.
HOPE I HELPED
find the missing length. show work!! 20 points
Answer:
15
Step-by-step explanation:
According to propagation rule,
\(\frac{9}{3} =\frac{x}{5} \\45=3x\\x=15\)
Therefore, option (B) is correct
Help me PLSSSSSSSSSSS
Answer:
8. Because if you add the degree of angle 7 to angle 8, then it makes a 180 degree angle, which is supplementary. Hope this helped
Above is a map that supports the idea that the continents were once joined together. Some fossils can be found on multiple continents that are now very far apart. Provide another piece of evidence to support the idea that continents were once joined together.
Answer:
DNA from multiple beings have been found all over the world, this is also a theory because of the ability for the continents to be formed together, they almost click together like puzzle pieces!
Step-by-step explanation:
Answer:
Another piece of evidence that could support the idea that continents were once joined together could be that mountain ranges can be found on multiple continents even though now they are very far apart. For example, the Appalachian Mountains can be connected to mountains in Europe. This supports the idea that continents were once joined together.
Let me know if this helps!
Express the following summation in closed form (an expression that can be directly computed from k). (Refer to slide 11) 3 + 5 + 7 + 9 + ... + 2k+1 Can you please explain step by step so I can gain better understanding.
This is the closed-form expression for the summation, which can be directly computed from k.
The expression "3 + 5 + 7 + 9 + ... + 2k+1" is a finite arithmetic series, which can be expressed in closed form using the formula:
Sn = n/2 * (2a + (n-1)d)
where:
n = number of terms
a = first term
d = common difference
In this case, we have:
n = k
a = 3
d = 2
Substituting the values in the formula, we get:
Sn = k/2 * (2 * 3 + (k-1) * 2)
= k/2 * (6 + 2k - 2)
= k/2 * (2k + 4)
Thus, This is the closed-form expression for the summation, which can be directly computed from k.
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A ball is thrown downward from the top of a 200 foot building with an initial velocity of 24 ft. /s.  The height of the ball H in feet after tea seconds is given by the equation H equals -16 T^2-24t+200. How long after the ball is thrown will it strike the ground?
The time it takes the ball to strike the ground after it is thrown, found using the kinematic equation, H = -16·t² - 24·t + 200 is approximately 2.86 seconds
What is a kinematic equation?A kinematic equation is an equation of the motion of an object moving with a constant acceleration.
The direction in which the ball is thrown = Downwards
Height of the building = 200 foot
Initial velocity of the ball = 24 ft./s
The kinematic equation that indicates the height of the ball after t seconds is, H = -16·t² - 24·t + 200
At ground level, H = 0, therefore;
H = 0 = -16·t² - 24·t + 200
-16·t² - 24·t + 200 = 0
-2·t² - 3·t + 25 = 0
t = (3 ± √((-3)² - 4 × (-2)×25))/(2×(-2))
t = (3 ± √(209))/(-4)
t = (3 + √(209))/(-4) ≈ -4.36 and t = (3 - √(209))/(-4)) ≈ 2.86
The time it takes the ball to strike the ground after it is thrown is approximately 2.86 seconds.Learn more about kinematic equations in mathematics here:
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18 Which shows the equation 2x - 8y = -16 in slope-intercept form?
1
Y =
А
cy= -4x + 2
x + 2
2
x
B
D y= -4x-2
♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️
\(2x - 8y = - 16\)
Subtract sides 2x
\( - 2x + 2x - 8y = - 2x - 16\)
\( - 8y = - 2x - 16\)
Negatives simplifies
\(8y = 2x + 16\)
Divide sides by 8
\( \frac{8y}{8} = \frac{2x + 16}{8} \\ \)
\(y = \frac{2}{8} x + \frac{16}{8} \\ \)
\(y = \frac{1}{4} x + 2 \\ \)
Done...
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If T is the midpoint of SU, what are ST, TU, and SU.
*Question 16*
We have ST=5x, TU=3x+32 and they're equal if T is the midpoint:
5x = 3x + 32
2x = 32
x = 16
ST = 5x = 80
So TU = 80 and SU=160
Answer: Second choice
A tree cast a shadow 21 meters long
The angle of elevation for the sun is 51 degrees
What is the height of the tree?
Step-by-step explanation:
I do not understand .____.
Calculate the missing information for the installment loan that is being paid off early.
The computation illustrates that the rebate fraction is 0.18
How to compute the value?Given that : the total number of payments = 36
The number of payments made = 21
Remaining payments = 36-21 =15
We know that the sum of the digits for n payments
S = (n(n+1))/2
sum of the digits payments remaining = 15*(15+1)/2
= (15*16)/2
= 240/2
= 120
Sum of the digits number of payments = 36*(37)/2
= 1332
= 666
Rebate fraction = 120/666 =0.18
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Complete question
Calculate the missing information for the installment loan that is being paid off early.
Number of payment = 36
Payment made = 21
Payment remaining = ?
Rebate fraction = ?
A second order dynamic plant is described with a state space model below.
A = [ 0 1 ] B = [0 ] C= [1 0] D=0
[ -1 -2] [-1]
There is need to design an observer for real operation. The analysis and design tasks are listed below. a) Discuss in what situation it needs for introducing the observer and what the role of each matrix of (L, M, and N) is in the observer. (the words limit is 80) b) From det[s1 - L], discuss why specify the observer poles with s, = -4 s, =-5 against the plant dynamics. (the words limit is 40) c) Design the state observer with the specified poles s =-4 =-5. d) Show the designed observer block diagram with matrices (L, M, and N)
a) Situations when an observer needs to be introduced and the role of each matrix: In order to observe the state of a system in practice, an observer must be introduced. The observer's role is to assess the system's state variables based on the system's input and output values, as well as the system's dynamics. The observer consists of three matrices:L: State feedback gain matrix M: Determines the observer's internal dynamics N: Maps the output signal to the observer's inputThe purpose of the observer is to estimate the system's states so that they can be fed back into the control loop.
b) Det[s1 - L] discussion: When designing an observer, the choice of observer poles has a significant impact on the system's efficiency. If the observer poles are placed far too close to the system poles, the observer may become unstable and diverge from the true state values. Alternatively, if the observer poles are placed far too far from the system poles, the observer may not be sensitive enough to changes in the system's states.In this context, det[s1 - L] refers to the determinant of the system's matrix minus the state feedback gain matrix. To ensure that the observer's poles are not too close or too far from the system's poles, this determinant must be non-zero.
c) Designing state observer: The observer's gain matrix L can be determined using the Ackerman formula.
By using Ackerman formula, the observer gain matrix is:L = acker(A', C', [s1, s2])L = [21 12]s1 = -4; s2 = -5 The observer's matrix M is given by:M = A - LC = [0 1;-1 -2] - [21; 12][1 0]M = [-21 -12;-21 -8]
The observer's matrix N is given by:N = B - LD = [0] - [21; 12][0]N = [0]d) Observer block diagram with matrices:Based on the information given above, the observer's block diagram with matrices L, M, and N can be presented in the following diagram:state observer block diagram
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If you want to know the probability of spinning a spinner in a game that has 8 equal-sized
wedges and it lands on red, which represents one of the those wedges. You determine that probability to be 1/8 or 0.125.
Identify if the following is experimental, classical, or subjective simple probability:
the answer is 1/8. Because you divide how many pieces there are by that same number.
18/19 as a decimal rounded to the nearest tenth.
Answer: 0.9
Step-by-step explanation: First, divide 18 by 19. The exact answer to the fraction is 0.94736842105. To round to the nearest tenth, check if the answer directly to the right of the number after the decimal point is above or below five. In this case, it is below, rounding the answer to 0.9. Hope that helps!
Please help, This is past due. I’ll give brainiest to the first with an explain.
Answer:
13
\(FC + CB = \frac{DC}{2} +\frac{AB}{2}\)
Step-by-step explanation:
Line CB is half of Line AB, which the questions says line AB is the length of 20. 20/2 = 10.
Line CB is 10.
The question also says that point F is the midpoint of line DC. Line DE is 12. Line DC is half of 12, which means its 6. F is the midpoint of Line DC which means it's also half of Line DC, which is 3.
Line FC is 3.
The question asks you to find the value of Line FC PLUS Line CB. So 10 + 3 = 13.
Your answer is 13.
Answer:
13
Step-by-step explanation:
AB and DE split each other equally in half so
if AB = 20 then CB = 10
and if DE = 12 then DC = 6
meaning that FC = 3
3+10=13
12. Given that the coefficient of x² in the expansion of (1-ax)' is 60 and that a > 0, find the value of a.