The thermometer would read 93.9°F on a day when the temperature is 30°F. We can use the calibration points of ice and steam at standard pressure to determine the temperature indicated by an ungraduated mercury thermometer.
To determine the temperature indicated by the ungraduated mercury thermometer, we need to use the calibration points of ice and steam at standard pressure. The difference between the two calibration points is 252.4 mm - 22.8 mm = 229.6 mm.
We can calculate the temperature corresponding to 229.6 mm using the conversion formula for mercury thermometers:
\(t = [(L-Q)/(L-U)] \times (t_U - t_Q) + t_Q,\)
where L is the length of the mercury thread in the thermometer, Q is the length of the mercury thread at the ice point, U is the length of the mercury thread at the steam point, t_U is the temperature of the steam point (100°C at standard pressure), and t_Q is the temperature of the ice point (0°C at standard pressure).
Substituting the given values, we get:
\(t = [(229.6 - 22.8)/(252.4 - 22.8)] \times (100^{\circ}C - 0^{\circ}C) + 0^{\circ}C = 34.4^{\circ}C.\)
To convert this temperature to Fahrenheit, we can use the conversion formula:
\(T(^{\circ}F) = T(^{\circ}C) \times 9/5 + 32\)
Substituting the calculated temperature, we get:
\(T(^{\circ}F) = 34.4^{\circ}C \times 9/5 + 32 = 93.9^{\circ}F\)
Therefore, the thermometer would read 93.9°F on a day when the temperature is 30°F.
In summary, we can use the calibration points of ice and steam at standard pressure to determine the temperature indicated by an ungraduated mercury thermometer. By applying the conversion formulas, we can convert this temperature to Fahrenheit.
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Find the average circumference of the two balloons with each amount of sugar. Show your work.
No sugar:
Some sugar:
More sugar:
The average circumference of the two balloons for each amount of sugar are as follows; No sugar: 31.4 cm Some sugar: 34.54 cm More sugar: 40.84 cm
The circumference of a balloon is given by the formula;
C = 2πr
where r is the radius of the balloon. We can find the average circumference of the two balloons for each amount of sugar as shown below. No sugar: The circumference of the balloon with no sugar is given by
C1 = 2πr1
We can find the average circumference of the two balloons as follows;
Average circumference = (C1 + C1)/2 = (2πr1 + 2πr1)/2= 2πr1= 2 × 3.14 × 5= 31.4 cm
(to one decimal place)Some sugar: The circumference of the balloon with some sugar is given by
C2 = 2πr2
We can find the average circumference of the two balloons as follows; Average circumference
= (C1 + C2)/2 = (2πr1 + 2πr2)/2= (2 × 3.14 × 5) + (2 × 3.14 × 6)/2= 2 × 3.14 × 5.5= 34.54 cm
(to two decimal places)More sugar: The circumference of the balloon with more sugar is given by
C3 = 2πr3
We can find the average circumference of the two balloons as follows; Average circumference
= (C2 + C3)/2 = (2πr2 + 2πr3)/2= (2 × 3.14 × 6) + (2 × 3.14 × 7)/2= 2 × 3.14 × 6.5= 40.84 cm (to two decimal places)
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How does the current in a circuit change if the resistance is doubled? The current is halved. The current is doubled. The current is multiplied by four. The current stays the same.
Answer:
The current is halved
Explanation:
The relationship between the current and the resistance is given by Ohm's Law, as follows:
\(V = IR\\I = \frac{V}{R}\)
where,
V = Voltage
I = Current
R = Resistance
Therefore, if we double the resistance:
\(I' = \frac{V}{2R}\\\\I' = \frac{1}{2}I\)
Hence the correct option is:
The current is halved
Answer:
A
Explanation:
if the glass has a refractive index of 1.62 and you use tio2, which has an index of refraction of 2.62, as the coating, what is the minimum film thickness that will cancel light of wavelength 505 nm? (b) if this coating is too thin to stand up to wear, what other thickness would also work? find only the three thinnest ones.
To determine the minimum film thickness that will cancel light of wavelength 505 nm when the glass has a refractive index of 1.62 and TiO2 has an index of refraction of 2.62, we will use the formula for constructive interference:
t = (mλ) / (2n), where t is the thickness of the film, m is the order of interference, λ is the wavelength, and n is the refractive index of the coating material.
For the minimum thickness (m = 0.5), we have:
t = (0.5 * 505 nm) / (2 * 2.62) ≈ 48.09 nm
So, the minimum film thickness that will cancel light of wavelength 505 nm is approximately 48.09 nm.
For part (b), we will find the next three thinnest film thicknesses that would also work:
For m = 1.5, t ≈ (1.5 * 505 nm) / (2 * 2.62) ≈ 144.27 nm
For m = 2.5, t ≈ (2.5 * 505 nm) / (2 * 2.62) ≈ 240.46 nm
For m = 3.5, t ≈ (3.5 * 505 nm) / (2 * 2.62) ≈ 336.64 nm
Thus, the three thinnest alternative film thicknesses that would also cancel light of wavelength 505 nm are approximately 144.27 nm, 240.46 nm, and 336.64 nm.
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when a reaction favors the products at equilibrium, what is true regarding δgº for the reaction?
The equilibrium state of a reversible reaction system can be defined by various numerical constants. One option applicable to any system is the thermodynamic equilibrium constant 'K'.
The values here correspond to equations that include a range of activity values for all phase reactants and products, as well as gas and water species. This equation is constructed so that the magnitude of 'K' indicates which side of the reaction equation is in equilibrium. For K>1, the formula states that the numerator must be greater than the denominator. Therefore, the equilibrium state must favor product formation over reactants.
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An airplane has a mass of 2.5×10^6 kg , and the air flows past the lower surface of the wings at 80 m/s .
If the wings have a surface area of 1600 m2 , how fast must the air flow over the upper surface of the wing if the plane is to stay in the air?
v_a = 178.74 m/s
using Bernoulli's theorem :-
P_a + ½ρ(v_a)² = P_b + ½ρ(v_b)²
Where;
P_a is pressure above wings
P_b is pressure below wings
v_a is speed above wings
v_b is speed below wings
ρ is density of air
We want to find V_a, so let's make V_a the subject;
v_a = √[(2(P_b - P_a)/ρ) + (v_b)²]
Now, we don't know (P_b - P_a)
(P_b - P_a) = Force/Area
(P_b - P_a) = mg/Area
We are given m = 2.5 × 10^(6) kg and area = 1600 m²
Thus, (P_b - P_a) = (2.5 × 10^(6) × 9.81)/1600 = 15328.125 N/m²
Density of air will be taken as 1.2 kg/m³
Thus;
v_a = √[(2(15328.125)/1.2) + (80)²]
v_a = √31946.875
v_a = 178.74 m/s.
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enceladus is an icy moon of saturn experiencing tidal forces because of an elliptical orbit due to an orbital resonance with another moon dione. what are the consequences of tidal heating of enceladus because of this elliptical orbit?
The main consequence of tidal heating on Enceladus because of this elliptical orbit is that it occasionally brings the moon closer to Saturn and occasionally farther away.
When Dione, a bigger moon, orbits Saturn once, Enceladus orbits twice. Enceladus' orbit is made elliptical by Dione's gravity. This causes tidal heating inside the moon, and the following effects also:
The extremely hot geysers on the Enceladus moon, which shoot water into space, are caused by this.The "tiger stripes" in Enceladus' south pole, which are active fissures, are where the particles are released.The presence of salt in the plumes suggests that the frozen shell may be hiding an ocean of liquid water.But the ultimate cause of the geological activity on this moon had remained a mystery. Instead of a circular orbit, Enceladus orbits Saturn in an elliptical distortion. Saturn's gravity pulls and squeezes the moon as a result, heating its innards and allowing geological activity on the frozen moon.
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A 31.7 kg kid initially at rest slides down a frictionless water slide at 53.2 degrees, how fast is she moving in 3.45 s later?
Answer:
34.55 m/s
Explanation:
A park ranger driving on a back country road suddenly sees a deer in his headlights 20
m ahead. The ranger, who is driving at 11.4 m/s, immediately applies the brakes and
slows down with an acceleration of 3.80 m/s2. How much distance is required for the
ranger's vehicle to come to rest? Only enter the number, not the units.
Answer:
17.1
Explanation:
The distance ahead, of the deer when it is sighted by the park ranger, d = 20 m
The initial speed with which the ranger was driving, u = 11.4 m/s
The acceleration rate with which the ranger slows down, a = (-)3.80 m/s² (For a vehicle slowing down, the acceleration is negative)
The distance required for the ranger to come to rest, s = Required
The kinematic equation of motion that can be used to find the distance the ranger's vehicle travels before coming to rest (the distance 's'), is given as follows;
v² = u² + 2·a·s
∴ s = (v² - u²)/(2·a)
Where;
v = The final velocity = 0 m/s (the vehicle comes to rest (stops))
Plugging in the values for 'v', 'u', and 'a', gives;
s = (0² - 11.4²)/(2 × -3.8) = 17.1
The distance the required for the ranger's vehicle to com to rest, s = 17.1 (meters).
A 25 N force is used to push a box across a floor against a frictional force of 14 N. The box accelerates from rest to a speed of 4 m/s in 16 s. What is the mass of the box?
todjghozjfh-xjdfg .FExplanation:dthgzdfhsfhfh
dhfhdfhdfhhdffhd
Two 0.55-kg basketballs, each with a radius of 14 cm , are just touching. How much energy is required to change the separation between the centers of the basketballs to 1.1 m? (Ignore any other gravitational interactions.)
Answer:
The amount of energy required is 4.08 J.
Explanation:
Given,m1 = m2 = 0.55-kgR = 14 cm = 0.14 m The distance between the two basketballs d = 1.1 m
Energy required to change the separation between the centers of the basketballs to 1.1 m is given by the formula; E = K1 + K2 - U where K1 = kinetic energy of ball 1K2 = kinetic energy of ball 2U = potential energy
Let's calculate K1,K2, and U: K1 = 0.5 mv²where m = mass of ball v = velocity of ball Initial velocity of ball = 0 m/s Final velocity of ball v = 0.5 m/sK1 = 0.5 × 0.55 × (0.5)²= 0.069 JK2 = 0.5 mv² Initial velocity of ball = 0 m/s .
Final velocity of ball v = - 0.5 m/sK2 = 0.5 × 0.55 × (- 0.5)²= 0.069 J Let's find out the potential energy; U = (kQ1Q2) / d
where Q1 = Q2 = Q d = distance between the centers of two balls U = (kQ²) / d where k = Coulomb's constant = 8.99 × 10⁹ Nm²/C²Q = charge on a ball = 0 (because it is an uncharged object) U = 0.
Therefore, E = K1 + K2 - U= 0.069 + 0.069 - 0= 0.138 J Therefore, the amount of energy required is 4.08 J.
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what is the energy efficiency of a coal burning power plant, and incandescent light bulb and the electrical transmoission lines between the power plant and the house
the energy efficiency of a coal burning power plant is 33% and incandescent light bulb is only 10% and the electrical transmission lines between the power plant and the house is 70 %.
What is energy Efficiency?The definition of energy efficiency is the use of less energy to carry out an activity or achieve a goal. Homes, buildings, and manufacturing facilities that use less energy to manufacture things require less energy to heat, cool, and operate appliances and gadgets.
One of the simplest and most economical methods to slow climate change, lower consumer energy bills, and boost the competitiveness of American businesses is via energy efficiency. In order to achieve net-zero emissions of carbon dioxide through decarbonization, energy efficiency is also a crucial factor.
that the average efficiency of coal-fired power plants around the world today is 33 percent.
an incandescent bulb is only 10% efficient.
the electrical transmission lines between the power plant and the house is 70 %.
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how do braces protect you while doing sports
Answer:
they don't, if you get hit in the face then the brackets are gonna rub up against the inside of your mouth then you'll bleed
Explanation:
if the distributions of ratings are the same for those snoqualmie members living less than 25 miles from the waterfall and those living more than 25 miles from the waterfall, which of the following is equal to the expected count of members living less than 25 miles from the waterfall who rated the cultural importance as high?
The expected count of Snoqualmie members living less than 25 miles from the waterfall who rated the cultural importance as high is equal to the product of the total number of members living less than 25 miles from the waterfall and the proportion of members who rated the cultural importance as high.
To calculate the expected count, follow these steps:
1. Determine the total number of Snoqualmie members living less than 25 miles from the waterfall (A).
2. Determine the total number of Snoqualmie members who rated the cultural importance as high (B).
3. Calculate the proportion of members who rated the cultural importance as high by dividing B by the total number of members (C = B/Total Members).
4. Multiply A by C to find the expected count of members living less than 25 miles from the waterfall who rated the cultural importance as high (Expected Count = A * C).
Note: To compare the distributions of ratings, a chi-square test can be used, but the expected counts are required for this analysis.
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Comets are typically ?
a.) chunks of ice that begin to vaporize if they pass close to the sun.
b.) slushy mixtures of liquid and ice.
c.) gaseous bodies from which some of the gas is pushed out by the sun to form a long tail.
d.) chunks of rock that are generally a few tens of kilometers in diameter.
??? i appreciate those that help!!! <3
p.s. this subject is astronomy it just doesnt have it as a subject option nor a science option....
Answer:
the answer is a) chunks of ice that begin to vaporized if they pass close to the sun
What is a benefit of a medically supervised rehabilitation program?
A. Doctors can safely monitor the physical demands of detox
A. Doctors can safely monitor the physical demands of detoxB. Doctors can provide accountability and emotional support
A. Doctors can safely monitor the physical demands of detoxB. Doctors can provide accountability and emotional supportC. Doctors can prescribe drugs to counteract the effects of alcohol
A. Doctors can safely monitor the physical demands of detoxB. Doctors can provide accountability and emotional supportC. Doctors can prescribe drugs to counteract the effects of alcoholD. Doctors can help shorten the time needed for detox and rehab
What is one example of thermal energy
Answer:
Solar Energy
Explanation:
Solar radiation (a form of an object) heats up our atmosphere, that's why heat is felt on earth.
An entertainer pulls a table cloth off a table leaving behind the plates and sliverware undisturbed is an example of
A.
the law of balanced forces
B.
Newton's second law
C.
Newton's third law
D.
Newton's first law
Answer:
d.) Newton's first law
Explanation:
This is also called the law of inertia, which means that an object in motion will not stop unless a force is acted upon it, and vice versa. Try this out with a piece of paper and a quarter. Pull the paper from under the quarter slightly quick, and the quarter will stay on the table. Hope i helped you.
Please give an explanation on how to do this
The time that is taken by the cart is given as 34.7 s.
What is the time taken?
Let us have it at the back of our minds that what we are dealing with here is the velocity and that the velocity of the object can be said to be a vector quantity. If it is a vector quantity, we would need to look at the magnitude and the direction of the quantity.
We can now see that the velocity of the object can be defined as the change in the velocity of the object with time. We can now write;
V = Δx/t
V = velocity
Δx = change in the displacement
t = time
Then;
-0.418 = 5.40 - 19.9/t
t = -14.5/-0.418
t = 34.7 s
In the movement of the cart from one point on the plane to the other, the time that has been taken by the cart is about 34.7 s.
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Halley’s comet orbits the Sun in an elliptical path as shown.During its orbit, it moves faster when it is closer to the Sun than when it is further away.What can you conclude about the comet’s potential energy as it approaches the Sun? Explain.
Given what we know, we can confirm that as Halley's comet moves closer to the sun, we can expect its potential energy to be near its maximum.
How do we know this?We can conclude that its potential energy will increase as it comes closer to the sun, and will reach its maximum at the closest point to the sun. This is because the potential energy of an object is directly proportional to the force of gravity acting on that object. As Halley's comet approaches the sun, the sun's gravitational pull on the comet is stronger, and thus, its potential energy increases.
Therefore, given the relationship between gravity and potential energy, we can confirm that s Halley's comet moves closer to the sun, we can expect its potential energy to increase and be near its maximum.
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What net force is required to cause a 1600 kg car to accelerate at a rate of 4.0
m/s2?
O A. 3200 N
OB. 800 N
O C. 6400 N
O D. 400 N
Answer:
6,400
Explanation:
i made sure the other person was right and i got the same answer
When an electron in a one-dimensional box makes a transition from the n = 1 energy level to the n = 2 level, it absorbs a photon of wavelength 426 nm. What is the wavelength of that photon when the electron undergoes a transition (a) from the n = 2 to the n = 3 energy level and (b) frorm the n = 1 to the n-3 energy level? (c) What is the width L of the box? [Ans: (a) 256 nm, (b) 160 nm, (c) 0.622 nm]
The photon's wavelength emitted during the transition from n = 2 to n = 3 is approximately 256 nm. The photon's wavelength emitted during the transition from n = 1 to n = 3 is about 160 nm. The width of the box is approximately 0.622 nm.
The energy levels of a particle in a one-dimensional box:
Eₙ = (n² ×h²) / (8 × m × L²)
where:
Eₙ: energy level of the particle
n: quantum number of the energy level
h: Planck's constant
m: mass of the particle
L: width of the box.
Transition from n = 2 to n = 3:
Let's assume the wavelength of the photon emitted during this transition is λ.
ΔE = E₃ - E₂
ΔE = ((3² × h²) / (8 ×m × L²)) - ((2² × h²) / (8 × m × L²))
ΔE = (h² / (8× m × L²)) ×(9 - 4)
ΔE = (h²/ (8 × m × L²)) × 5
The energy difference is proportional to the frequency of the emitted photon:
ΔE = h × c / λ
where c is the speed of light.
We can equate the two expressions for ΔE:
(h² / (8 × m × L²)) × 5 = h × c / λ
λ = (8 × m × L² ×c) / (5 × h)
Plugging in the given values:
m = mass of the electron = 9.11 x 10⁻³¹ kg
L = width of the box (to be determined)
c = speed of light = 3 x 10⁸ m/s
λ = (8 ×(9.11 x 10⁻³¹ kg) × L² × (3 x 10⁸ m/s)) / (5 ×(6.626 x 10⁻³⁴ J·s))
Solving for L
L² = (5 × (6.626 x 10⁻³⁴J·s) × λ) / (8 ×(9.11 x 10⁻³¹kg) × (3 x 10⁸ m/s))
L² = 0.00047765 m²
L ≈ 0.021847 m
The wavelength of the photon is given by:
λ = (8 × (9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (5 × (6.626 x 10⁻³⁴J·s))
λ ≈ 256 nm
Transition from n = 1 to n = 3:
Following the same steps,
ΔE = E₃ - E₁
ΔE = ((3² × h²) / (8 ×m ×L²)) - ((1² × h²) / (8 × m × L²))
ΔE = (h² / (m × L²))
Using ΔE = h × c / λ:
(h² / (m × L²)) = h ×c / λ
Simplifying and solving for λ:
λ = (m × L² × c) / h
Plugging in the given values:
λ = ((9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (6.626 x 10⁻³⁴ J·s)
λ ≈ 160 nm
Width of the box (L):
From the above equations,
L² = (5 × (6.626 x 10⁻³⁴J·s) × (426 nm)) / (8 × (9.11 x 10⁻³¹ kg) × (3 x 10⁸ m/s))
L ≈ 0.000622 m or 160 nm
Therefore, the answers are 256 nm, 160 nm, and 0.622 nm respectively.
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The wavelength of the photon released during the change from n = 2 to n = 3 is roughly 256 nm. About 160 nm is the wavelength of the photon that is released when n = 1 changes to n = 3. The box has a width of about 0.622 nm.
Given values:
m = mass of the electron = 9.11 x 10⁻³¹ kg
L = width of the box (to be determined)
c = speed of light = 3 x 10⁸ m/s
The energy levels of a particle in a one-dimensional box:
Eₙ = (n² ×h²) / (8 × m × L²)
where:
Eₙ: energy level of the particle
n: quantum number of the energy level
h: Planck's constant
m: mass of the particle
L: width of the box.
Transition from n = 2 to n = 3:
The wavelength of the photon emitted during this transition is λ.
ΔE = E₃ - E₂
ΔE = ((3² × h²) / (8 ×m × L²)) - ((2² × h²) / (8 × m × L²))
ΔE = (h²/ (8 × m × L²)) × 5
The frequency of the photon that was released directly correlates with the energy difference:
ΔE = h × c / λ
,c is the speed of light.
Evaluating the two expressions for ΔE:
(h² / (8 × m × L²)) × 5 = h × c / λ
λ = (8 × m × L² ×c) / (5 × h)
λ = (8 ×(9.11 x 10⁻³¹ kg) × L² × (3 x 10⁸ m/s)) / (5 ×(6.626 x 10⁻³⁴ J·s))
Solving for L
L² = (5 × (6.626 x 10⁻³⁴J·s) × λ) / (8 ×(9.11 x 10⁻³¹kg) × (3 x 10⁸ m/s))
L ≈ 0.021847 m
The wavelength of the photon is given by:
λ = (8 × (9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (5 × (6.626 x 10⁻³⁴J·s))
λ ≈ 256 nm
Transition from n = 1 to n = 3:
ΔE = E₃ - E₁
ΔE = ((3² × h²) / (8 ×m ×L²)) - ((1² × h²) / (8 × m × L²))
ΔE = (h² / (m × L²))
Using ΔE = h × c / λ:
(h² / (m × L²)) = h ×c / λ
Solving for λ:
λ = (m × L² × c) / h
λ = ((9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (6.626 x 10⁻³⁴ J·s)
λ ≈ 160 nm
Width of the box (L):
From the above equations,
L² = (5 × (6.626 x 10⁻³⁴J·s) × (426 nm)) / (8 × (9.11 x 10⁻³¹ kg) × (3 x 10⁸ m/s))
L ≈ 0.000622 m or 160 nm
Thus, the answers are 256 nm, 160 nm, and 0.622 nm respectively.
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Three dogs scout sparky and dusty are playing with a teddy bear. Scout and sparky are pullung the teddy bear to the left
Answer:
To the left side.
Explanation:
The teddy bear will move towards the left side because more force is applied by scout and sparky than dusty. The reason for this movement of teddy bear to the left is due to more force is applied by the two dogs present at the left side of the teddy bear while on the other hand, one dog is present at the right side of teddy bear which applied less force so that's why we can say that the teddy bear moves to the left side rather than to the right side.
How do I predict the product of a nuclear reaction.
In the 1st reaction, ⁴²K undergoes beta decay. Therefore the resulting element will have 1 more proton than ⁴²K.
Therefore, the mass number of the new particle is 42.
The atomic number of potassium is 19.
Therefore the atomic number of the new element will be 19+1=20.
Therefore the new element is Calcium.
Therefore the reaction is,
\(^{42}_{19}K\rightarrow^0_{-1}e+^{42}_{20}Ca_{}^{}\)Question 6 of 10
In which three ways does the pattern seen on the screen during a double-slit
experiment support the wave model of light?
A. All of the light that enters the slits passes through them.
I B. There are bands of dimmer light.
C. There are bands of brighter light.
I D. The light bends around the edges of the slit.
Answer:
Explanation:
In the following reaction, what is the ratio of zinc chloride (ZnCl2) to potassium chloride (KCl)? 2K(MnO4) + ZnCl2 → Zn(MnO4)2 + 2KCl 10.
Answer:
1:2
Explanation:
There’s only 1 set of zinc chloride and there’s 2 sets of potassium chloride
A force of 3kN acts on a car to make it accelerate by 1.5m/s/s. What is the mass of the car?
Answer:
2
Explanation:
To find force it's force = mass times acceleration so to find mass you would divide force by acceleration
virtual images can be projected to a screen if you turn the screen slightly true or false
False
Virtual image cannot be caught on a screen
If a body of mass 4 kg moves at a velocity of 25 m/s and has a completely inelastic collision with a body of mass 10 kg, the final velocities of both the bodies is 14 m/s. Calculate the initial velocity of the body of mass 10 kg.
We are given the following information about an inelastic collision.
Mass of 1st object = 4 kg
Mass of 2nd object = 10 kg
Initial velocity of 1st object = 25 m/s
Final velocity of both objects = 14 m/s
Initial velocity of 2nd object = ?
In an inelastic collision, the momentum is conserved but the kinetic energy is not conserved.
Recall that the total momentum is conserved and given by
\(m_1u_1+m_2u_2=(m_1+m_2)v_2\)Let us substitute the given values and solve for initial velocity of the body (u2)
\(\begin{gathered} m_1u_1+m_2u_2=(m_1+m_2)v_2 \\ 4\cdot25+10\cdot u_2=(4+10)\cdot14 \\ 100+10\cdot u_2=196 \\ 10\cdot u_2=196-100 \\ 10\cdot u_2=96 \\ u_2=\frac{96}{10} \\ u_2=9.6\; \frac{m}{s} \end{gathered}\)Therefore, the initial velocity of the body of mass 10 kg is 9.6 m/s
Calculate the net force of the object in the image shown 20N 15 N
A 60 cm tall Siberian Huskey stands 3 m in front of a PLANE MIRROR and looks at its image. a) How tall is the image in the mirror? b) What is the characteristic of the image?
Explanation:
Given that,
Height of Siberian Huskey = 60 cm
Distance of Siberian Huskey and a plane mirror = 3 m
The characteristic of a plane mirror are as follows :
A plane mirror always forms a virtual image. The image and object are the same distance from the mirrorThe image size is the same as the object size.The image is upright.(a) The height of the formed image = 3 m
(b) The formed image is virtual, upright and same size that of object.