Answer:
1 the forces are:friction, gravitational pull
2.i guess due to uniform change in displacement per unit time therefore uniform acceleration
Indicate the unit of measurement that scientists use for each of the following measurements:
Force:
Acceleration:
Velocity:
Mass:
Answer:
Force: Newtons (F = M a = kg * m /s^2)
Acceleration: m / sec^2 (a = meters / sec^2)
Velocity: m / sec (v = meters / sec)
Mass: kg (M = kilograms)
When a parachutist jumps from an airplane, he eventually reaches a constant speed, called the terminal velocity. This means thatSelect one:a. the force of air resistance is equal to zero. b. the effect of gravity has died down.c. the effect of gravity increases as he becomes closer to the ground.d the acceleration is equal to g.e. the force of air resistance is equal to the weight of the parachutist.
When an object moves at constant speed, the net force acting on that object is equal to 0:
\(\Sigma\vec{F}=0\)Two forces act over a parachutist while falling: the force of gravity (weight) and the air resistance. Those two forces have opposite directions, we can consider that the air resistance is positive because it points upwards, and the weight is negative because it points downwards:
\(\begin{gathered} \Sigma F=F_{\text{air}}-F_{\text{gravity}}=0 \\ \Rightarrow F_{air}=F_{gravity} \end{gathered}\)Then, when the parachutist reaches the terminal velocity, the force of air resistance is equal to the weight of the parachutist.
Therefore, the answer is option e:
\(\begin{gathered} e) \\ \text{The force of air resistance is equal} \\ \text{to the weight of the parachutist.} \end{gathered}\)
To heat the house, the boiler transfers 15 MJ of energy in 10 minutes.
Calculate the power of the boiler.
The formula is P = E/t, where P means power in watts, E means energy j , and t means time in seconds. This formula states that power is the consumption of energy per unit of time.
P = 15 M / 10*60
M = mega = 10⁶
15 *10⁶ / 600
= 25000 watt
To solve this, we must be knowing each and every concept behind energy transfer. By doing work or by transferring heat, energy can be transferred. Therefore, to heat the house, the boiler transfers 15 MJ of energy in 10 minutes, the power of the boiler is 25000 watt.
What is energy transfer?Energy transfer is a phenomenon in which energy transfer from one matter to another matter. energy requirement is necessary to move nay object so work has to be done by the gas to the piston.
Heat can be transferred by three ways radiation, convention or conduction. In conduction, direct contact of two body is necessary for transfer of molecules.
Mathematically, the formula for power can be given as
Power = Energy/time
time=10×60=600s
mega = 10⁶
Power=15 ×10⁶ / 600
Power = 25000 watt
Therefore, to heat the house, the boiler transfers 15 MJ of energy in 10 minutes, the power of the boiler is 25000 watt.
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What happened to the kelp forest when the otter was hunted to near extinction?
Answer: Sea otter is the pioneer species in the kelp forest as it regulates and controls the population of other species in the kelp forest.
Explanation:
If sea otters are hunted and their population is brought to extinction then this will cause major harm the ecosystem of the kelp forest and it will disturb the ecological balance in the kelp forest. The herbivorous animals consumed by the sea otters will increase in population and they will consume a lot of vegetation in the forest. The kelp forest which forms the coastline will not remain effective in providing protection against the storms to the neighboring areas.
How many kilojoules of heat must be supplied to 4.1 g of ice at -26 oc to convert it to steam at 147 oc?
The amount of heat supplied to 4.1 g of ice at -26°C to convert it to steam at 147°C will be 12.81 kJ.
What is the heat supplied?The heat supplied is by the summation of the sensible heat and the latent heat of the substance.
Heat = Sensible heat + Latent heat
The mass of the substance is 4.1 grams (4.1 × 10⁻³ kilograms).
The sensible heat is given as
Q = mCΔT
Where C is the specific heat at constant volume (4.18 kJ / kg-K up to 100°C and 0.718 kJ / kg-K after 100°C), m is the mass and ΔT is the temperature difference.
The latent heat is given as
Q = mL, where L is the specific latent heat of a substance (334 kJ / kg at 0°C and 2230 kJ / kg at 100°C).
Heat = 4.1 × 10⁻³ × [4.18(0 + 26) + 334 + 4.18(100 - 0) + 2230 + 0.718(147 - 100)]
Heat = 4.1 × 10⁻³ × [108.68 + 334 + 418 + 2230 + 33.746]
Heat = 4.1 × 10⁻³ × 3124.426
Heat = 12.810 kJ
The amount of heat supplied to 4.1 g of ice at -26°C to convert it to steam at 147°C will be 12.81 kJ.
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Suppose you want to produce a double-slit interference pattern where the distance between successive bright fringes on the screen is at least 1.25 cm. If the slits have a width of 0.0400 mm and a separation of 0.250 mm, what is the minimum distance needed from the slits to the screen when a He-Ne laser (λ = 633 nm) is used?
Answer: The minimum distance needed from the slits to the screen is approximately 2.46 meters when a He-Ne laser (λ = 633 nm) is used.
Explanation: The distance between successive bright fringes in a double-slit interference pattern is given by the equation:
d(sinθ) = mλ
where d is the distance between the slits, θ is the angle between the line connecting the center of the two slits and the line connecting a point on the screen to the center of the slits, m is an integer representing the order of the bright fringe, and λ is the wavelength of the light.
To find the minimum distance from the slits to the screen that will produce a fringe spacing of at least 1.25 cm, we can use the equation for the first-order bright fringe:
d(sinθ) = λ
where m = 1.
We can solve this equation for sinθ:
sinθ = λ/d
Substituting the values we were given, we get:
sinθ = (633 nm) / (0.250 mm) = 0.002532
Now we can use the small-angle approximation, which states that sinθ ≈ θ for small angles, to find the angle θ:
θ ≈ sinθ = 0.002532
Finally, we can use the following formula to find the distance from the slits to the screen:
y = L*tanθ
where y is the distance from the central maximum to the first-order bright fringe, L is the distance from the slits to the screen, and θ is the angle we just found.
Since we want the distance between successive bright fringes to be at least 1.25 cm, we can set y equal to 1.25 cm and solve for L:
L = y/tanθ = (1.25 cm) / tan(0.002532) ≈ 2.46 m
Therefore, the minimum distance needed from the slits to the screen is approximately 2.46 meters when a He-Ne laser (λ = 633 nm) is used.
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Identify the fundamental particles that make up a proton.
a uniform beam 6.0 metre long and weighing 4kg rests on support at p and q placed left and right 1.0 metres from each end of the beam weights of mass 10 kg and 8kg are placed near p and q respectively one each end of the beam.calculate the reaction at p and q?
Answer:
Explanation:
I need the answer me too
Answer:
p and q are 4.0 m apart
moments around q
4 p = (10 * 5) + (4 * 2) - (8 * 1)
p = 12.5
Rp = 12.5 g
moments around p
4 q = (8 * 5) * (4 * 2) - (10 * 1)
q = 9.5
Rq = 9.5 g
plz mark me as brainly
Explanation:
What will be the final velocity of a car, if it starts to move from rest and accelerates at 10 m/s² after 5 seconds ?
Answer:
50m/s.
Explanation:
Answer:
\(V_f=50m/s\)
Explanation:
Use the the formula for final velocity (kinematic equation):
\(V_f=V_i+at\)
Final velocity = Initial velocity + acceleration times time
Given values:
Rest - indicates 0 initial velocity
Acceleration - 10 m/s^2
Time - 5 seconds
Insert the given values:
\(V_f=0+5\times10\)
\(V_f=50m/s\)
A football player pushes a 590 n tackling sled. his coach observes this and believes that this is too light and wants to present the player with a greater physical challenge. he asks two players (player a weighs 100 kg and player b weighs 125 kg). the coefficient of static friction between the sled and grass is 0.70. how much force must the player exert to start the tackling sled in motion with players a and b on it
The player has to apply a force of 1956.5N to start tackling sled in motion.
Coefficient of static friction μ\(_{s}\) = 0.70
Weight of sled = mg
= 590N
Weight of Player A = \(m_{a}g\)
= 100 × 9.8
= 980N
Weight of Player B = \(m_{b}g\)
= 125 × 9.8
= 1225N
Combined weight of sled:
W = (590+980+1225)N
= 2795N
Now, friction on sled:
f = μ\(_{s}\)R
= 0.70 × 2795
= 1956.5N
Therefore, the player has to apply force equal to static friction to start tackling sled in motion.
∴ Force = Static friction = 1956.5N
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Question 8
A student claims that Earth has a magnetic field. Which evidence would best support the student's claim?
The student creates a working circuit that illuminates a bulb using wire and a battery.
A
B
C
D
The student turns in all directions with a compass and the needle always points north.
The student receives a shock after walking across the carpet and touching a doorknob.
The student rolls a ball down a large hill and the ball comes to a complete stop at the bottom:
24
The student turns in all directions with a compass and the needle always points north is the best evidence would best support the student's claim that earth has a magnetic field. Hence option 'B' is correct.
What is a magnetic field, exactly?The area where the force of the magnetism works around the magnetic material or even a flowing electric charge is known as the magnetic field. a diagram that shows the magnetic field and how the magnetic force can be spread inside and outside of a magnetic material.
What generates the magnetic field?Electric ions in motion are what generate magnetism. The smallest building blocks of matter are termed atoms. There are electrons in every atom, which are charged entities. The electrons that make up an atom's nucleus, or centre, spin like tops.
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Suggest why the designer of a car simulator needs to study physics
The designer of a car simulator needs to study physics because their simulator must obey all the laws of physics. For instance, we can investigate if a car will flip if it drives on a circular track with a specific radius. Physics is also important in determining the cause of many vehicle accidents. As a result, physics is essential in the study of automotive motion.
What is a Car Simulator?
Driving simulators, like flight simulators, immerse the driver in an artificial environment that is thought to be a legitimate alternative for one or more components of the actual driving experience. Driving simulators, on the other hand, support much more than driver instruction, in contrast to flight simulators, which were designed primarily for pilot training.
A driving simulator can alleviate these fears by illustrating what occurs when a motorist exceeds the speed limit and how this affects their response time. There is no way to educate kids this similar circumstances on the road without endangering everyone.
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Emmy is running a marathon to try to get a Boston qualifying time. She runs at a constant velocity of 6 mph from 7:00 am to 8:30 am.
At 9:00 am, her velocity jumped to 8 mph. She completed her race at 10:30 am at a velocity of 10 mph. Calculate her acceleration
from 9:00 am - 10:30 am.
Answer:
answer is c
Explanation:
The bar across the top of an Office Online program that allows users to find the commands to complete a task is called the
Answer:
C: Ribbon
Explanation:
These are options for the question
A: Button
B: Clipboard
C: Ribbon
D: Task list
Ribbon as existed as far as late 1980s and can be described as a control element that control several tabs that user is working with, and give room for user to locate the appropriate Command for his/her task execution.
these tabs could be a contextual tabs or other, The application of Ribbon can be found in Word processor.
It should be noted that the bar across the top of an Office Online program that allows users to find the commands to complete a task is called the Ribbon
An electron moves in a circular path of radius 20 cm in a uniform magnetic field of 2 x 10³ T Find the speed of the electron and period of revolution. Mass of electron = 9.1 x 10-31 kg. [Ans: 7.02 x 10 m/sec and 5.6 x 10 rev/sec]
The linear speed of the electron is 7.03 x 10¹³ m/s and the angular speed of the electron is 5.6 x 10¹³ rev/s.
Speed of the electron
The speed of the electron is calculated as follows;
F = ma = mv²/r ---(1)
F = qvB ----- (2)
mv²/r = qvB
mv/r = qB
mv = qBr
v = qBr/m
where;
m is mass of the electronB is magnetic fieldr is radius of the circleq is charge of the electronv = (1.6 x 10⁻¹⁹ x 2 x 10³ x 0.2) / (9.1 x 10⁻³¹)
v = 7.03 x 10¹³ m/s
Angular speed of the electronω = v/r
ω = (7.03 x 10¹³ m/s) / (0.2 m) = 3.51 x 10¹⁴ rad/s
ω = 3.51 x 10¹⁴ rad/s x 1 rev/2π rad
ω = 5.6 x 10¹³ rev/s
Thus, the linear speed of the electron is 7.03 x 10¹³ m/s and the angular speed of the electron is 5.6 x 10¹³ rev/s.
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A stationary boat accelerates to 90km/hr over 1km.What is the time it takes to do this?
The time taken by the boat to accelerate from zero to 90 km/hr over 1 km is 11.11 seconds, and the acceleration is 8.1 m/s2.
The problem has provided the initial speed of the boat as zero, and the final speed as 90 km/hr.
We need to find the time taken by the boat to accelerate from zero to 90 km/hr over 1 km.
We can use the formula of acceleration to solve this problem.
The formula is:
v = u + at
where, v is the final velocity
u is the initial velocity
a is the acceleration
t is the time taken
From the above formula, we can write:
90 = 0 + a * t
where acceleration is a, and time taken is t.
Therefore, a * t = 90...…..(1)
The boat has traveled 1 km, which is 1000 m.
We can use the formula of average speed to calculate acceleration.
The formula is:
v = d / t
where, v is the speed
d is the distance traveled
t is the time taken.
We can write this formula as:
t = d / v,
where distance traveled is d, and the speed is v.
Substituting the values in the above equation, we get:
t = 1000 / 90t = 11.11 seconds.
From equation 1, we get a = 90 / t,
substituting the value of t, we get:
a = 90 / 11.11
a = 8.1 m/s2
Therefore, the time taken by the boat to accelerate from zero to 90 km/hr over 1 km is 11.11 seconds, and the acceleration is 8.1 m/s2.
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Let’s say hypothetically I was living the same day over and over again, and I couldn't fix it, would other people be able to still go to the next day?
Answer:
no because it will also affect other people
What causes the spinning tube of air created by winds moving in opposite directions to tip upwards and become vertical?
A
The updraft of wind in a supercell
B
Dust and debris picked up by a mesocyclone
C
The increasing speed of the tube’s rotation
D
A lack of gravity during stormy weather
The spinning tube of air created by winds moving in opposite directions to tip upwards and become vertical because of the updraft of wind in a supercell. Hence, option (A) is correct.
What is supercell?As a deep, continuously revolving updraft known as a mesocyclone, a supercell is a type of thunderstorm. This causes these storms to occasionally be called spinning thunderstorms.
Supercells, which are the least frequent and have the potential to be the most severe of the four types of thunderstorms (supercell, squall line, multi-cell, and single-cell), are the least common overall.
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what must the coefficient of static friction be for a car traveling at 115 km/h around the same turn?
Generally, the coefficient of static friction should be at least 0.7 for a car traveling at this speed, but this value could be higher depending on the specific conditions.
The coefficient of static friction, or μs, is the ratio of the maximum static force that can be applied without causing slipping to the normal force between two surfaces. The coefficient is affected by the surfaces in contact and the material they are made of.
The tires of a car also have an effect on the coefficient of static friction. Tires with a greater tread depth can provide better grip on the road and therefore have a higher coefficient of static friction than tires with a shallow tread. Tire pressure also plays a role, as low pressure can reduce the coefficient of static friction.
The weight of the vehicle is also an important factor. Heavier vehicles tend to have a higher coefficient of static friction, as the greater mass increases the normal force between the car and the surface.
In conclusion, the coefficient of static friction for a car traveling at 115 km/h around a turn depends on several factors, including the road surface, the vehicle's tires, and the vehicle's weight.
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13. A hydraulic lift system utilizes one 4.25-in diameter cylinder. Workers must determine how much the
system is capable of lifting before deciding how much weight can be lifted safely. The system runs at a gauge
pressure of 2500-lb/in².
a. Sketch and label all known and unknown values.
b. What is the area of the piston?
c. How much is the system capable of lifting?
The area of the piston is approximately 14.205 square inches.
The system is capable of lifting approximately 35,512.5 pounds.
How to solveKnown values:
Diameter of the cylinder: 4.25 inches
Gauge pressure of the system: 2500 lb/in²
Unknown values:
Area of the piston (A)
Lifting capacity of the system (F)
b. What is the area of the piston?
To calculate the area of the piston (A), we need to use the formula for the area of a circle, since the piston is circular. The formula is:
A = π * (d/2)^2
where d is the diameter of the piston, and π is the constant Pi (approximately 3.14159).
A = π * (4.25/2)^2
A ≈ 3.14159 * (2.125)^2
A ≈ 3.14159 * 4.515625
A ≈ 14.205 sq inches
The area of the piston is approximately 14.205 square inches.
c. How much is the system capable of lifting?
To determine the lifting capacity of the system (F), we can use Pascal's law, which states that pressure is distributed evenly in a fluid. The formula for the force exerted by the hydraulic fluid is:
F = P * A
where F is the lifting capacity, P is the gauge pressure, and A is the area of the piston.
F = 2500 lb/in² * 14.205 in²
F = 35512.5 lb
The system is capable of lifting approximately 35,512.5 pounds. Keep in mind that safety factors must be considered when determining the safe lifting capacity in a real-world scenario.
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Over 4 seconds, a car's momentum decreases by 1000 kg m/s how much force did it take to make this happen?
Answer:
250N
Explanation:
Given parameters:
Time = 4s
Momentum = 1000kgm/s
Unknown:
Force = ?
Solution:
To solve this problem, we use Newton's second law of motion;
Ft = Momentum
F is the force
t is the time
So;
F x 4 = 1000kgm/s
F = 250N
A truck enters a highway driving 60 mph A car enters the highway at the same place 0 nutes later and dives 72 mph in t The car will pass the truck in (Round to the nearest minute) minutes same directi
A truck enters a highway driving 60 mph A car enters the highway at the same place 0 nutes later and dives 72 mph in t The car will pass the truck in (Round to the nearest minute) minutes same direction From So the car enters the highway,However, this contradicts the information given that the car enters the highway 0 minutes later than the truck.
To determine how long it will take the car to pass the truck, we can set up an equation based on their relative speeds and distances traveled.
Let's assume that the car passes the truck after time 't' minutes.
In 't' minutes, the truck will have traveled a distance of 60 × (t/60) = t miles.
The car enters the highway 0 minutes later and travels at a speed of 72 mph. Therefore, when the car passes the truck, it will have traveled a distance of 72 × (t/60) = 1.2t miles.
To find when the car passes the truck, we can set up the following equation:
t = 1.2t
Simplifying the equation, we get:
t - 1.2t = 0.2t
0.2t = 0
This equation does not yield a valid solution since it implies that the time required for the car to pass the truck is 0 minutes. However, this contradicts the information given that the car enters the highway 0 minutes later than the truck.
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for a nucleus to exhibit the nuclear magnetic resonance phenomenon, it must be magnetic. magnetic nuclei include:
The nuclei that exhibit the nuclear magnetic resonance phenomenon, the magnetic nuclei include all nuclei with even numbers of neutrons and protons.
Nuclei with certain magnetic characteristics are required in materials that take part in the MR process. The nuclei themselves must be tiny magnets with a magnetic property or magnetic moment in order for them to interact with a magnetic field.
An individual nucleus's neutron-proton composition determines its magnetic properties. Only some nuclides with an unusual balance of neutrons and protons exhibit magnetic properties.
All nuclei with even numbers of neutrons and protons are magnetic nuclei. Therefore, option a is correct.
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--The complete question is, For a nucleus to exhibit the nuclear magnetic resonance phenomenon, it must be magnetic. Magnetic nuclei
include:
a. all nuclei with even numbers of neutrons and protons
b. all nuclei with odd numbers of protons
c. all nuclei with odd numbers of neutrons
d. both b and c--
Can someone explain what is referred by the cross sectional area of a solenoid? Is this the same for an air solenoid vs a solenoid with a solid core vs a solenoid with a hollow core?
Answer:
the cross section refers to the way in which it is wound, in general to the circle
circle does not depend on what it has inside
Explanation:
A solenoid is a wire wound in general in a circular shape, even when it is not forced, the cross section refers to the way in which it is wound, in general to the circle and is joined to determine the area
A = π r²
This circle does not depend on what it has inside, that is, it is the same section in the air, in a liquid or with a solid inside,
how would the strength of the force between the moon and earth change if the mass of the moon were somehow made two times greater than its actual mass? be specific, how many times larger or smaller would it be. explain your reasoning.
The force between the Moon and the Earth is calculated using the formula \(F = G(m_1*m_2)/r^2\), where F is the force between the two objects, G is the universal gravitational constant, \(m_1\) and \(m_2\) are the masses of the two objects, and r is the distance between the two objects. Therefore, if the mass of the Moon is somehow made two times greater than its actual mass, the force between the Moon and the Earth would also increase.
To calculate the exact increase in force, we can use the same formula and compare the force before and after the increase in mass. Let's assume that the mass of the Moon is m before the increase and 2m after the increase. We can then use the formula to calculate the force before and after the increase, as follows:
- Before: \(F_1 = G\frac{mM}{r^2}\)
- After: \(F_2 = G\frac{2mM}{r^2}\)
To compare the two forces, we can divide \(F_2\) by \(F_1\):
\(\frac{F_2}{F_1} = [G\frac{2mM}{r^2} ]/[G\frac{mM}{r^2} ]\)
\(\frac{F_2}{F_1} =2\)
Therefore, the force between the Moon and the Earth would become two times greater if the mass of the Moon were somehow made two times greater than its actual mass. This is because the force of gravity is directly proportional to the masses of the objects involved.
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PLEASE HELLPPP ILL GIVE BRAINLY
which part of the United States would have generally cooler temperatures due to the effects of currents?
A ) East Coast
B ) Gulf Coast
C ) West coast
D ) Central States
Answer:
West coast
Explanation:
i think this is the ans
how do different types of motion affect forces?
Answer:
A force is a push or pull on an object. Forces usually cannot be seen but their effects can.
Nothing moves, changes speed, stops or changes direction without force. Heavier objects need more
force to get them to move or change direction.
Explanation:
A simple harmonic oscillator has a mass m=2.0 kg and a spring constant k=800 N/m.a) What is the frequency of oscillations?b) If the oscillator has a maximum speed of v=10.0 m/s, what is the maximum oscillation amplitude?c) What length would a simple pendulum need to be in order to oscillate at the same frequency?
a)
In order to calculate the frequency of oscillations of a simple harmonic oscillator, first let's calculate the period, using the formula:
\(\begin{gathered} T=2\pi\sqrt[]{\frac{m}{k}} \\ T=2\pi\sqrt[]{\frac{2}{800}} \\ T=2\pi\sqrt[]{\frac{1}{400}} \\ T=2\pi\cdot\frac{1}{20} \\ T=\frac{\pi}{10}=0.31416\text{ s} \end{gathered}\)Since the frequency is the inverse of the period, we have:
\(\begin{gathered} f=\frac{1}{T} \\ f=\frac{1}{\frac{\pi}{10}} \\ f=\frac{10}{\pi}=3.183\text{ Hz} \end{gathered}\)b)
In order to calculate the maximum oscillation amplitude given the maximum speed, let's use the formula below:
\(\begin{gathered} v_{\max }=X\sqrt[]{\frac{k}{m}} \\ 10=X\cdot\sqrt[]{\frac{800}{2}} \\ 10=X\cdot20 \\ X=\frac{10}{20}=0.5\text{ meters} \end{gathered}\)c)
The formula for the pendulum frequency is:
\(\begin{gathered} f=\frac{1}{T} \\ f=\frac{1}{2\pi\sqrt[]{\frac{L}{g}}} \\ f=\frac{\sqrt[]{\frac{g}{L}}}{2\pi} \end{gathered}\)Then, for f = 3.183 and g = 9.81, we have:
\(\begin{gathered} 3.183=\frac{\frac{\sqrt[]{9.81}}{\sqrt[]{L}}}{2\pi} \\ \frac{\sqrt[]{9.81}}{\sqrt[]{L}}=3.183\cdot2\pi \\ \frac{3.132}{\sqrt[]{L}}=20 \\ \sqrt[]{L}=\frac{3.132}{20} \\ \sqrt[]{L}=0.1566 \\ L=0.3957 \end{gathered}\)So the length is 0.3957 m or 39.57 cm.
Part F
For both Tracker experiments, calculate the average vertical acceleration, where the time period is t = 0.10 second tot = 1.00 second. Consider
only the magnitude of the vertical velocity in the calculations. Record your results to three significant figures.
Comment: How does the average acceleration of the two balls compare to the theoretical value of -9.81 meters/second, and how do the
accelerations of the two balls compare to each other?
At an equal time interval, acceleration increases with increase in velocity and it will maintain a positive value. When this value is compared to -9.8 m/s² (acceleration due to gravity), the value obtained will be greater than the value of acceleration due to gravity.
Generally, acceleration is defined as the change in velocity per change in time of motion.
Acceleration of an object at any given time, t, can be calculated using the following equations below;
\(a = \frac{\Delta v}{\Delta t} = \frac{v-u}{t_2-t_1}\)
where;
v is final velocity at t₂u is the initial velocity at t₁t₂ is the final time of motiont₁ is the initial time of motionFrom the formula above, we can conclude that at an equal time interval, acceleration increases with increase in velocity and it will maintain a positive value. When this value is compared to -9.8 m/s² (acceleration due to gravity), the value obtained will be greater than the value of acceleration due to gravity.
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Answer:
t an equal time interval, acceleration increases with increase in velocity and it will maintain a positive value. When this value is compared to -9.8 m/s² (acceleration due to gravity), the value obtained will be greater than the value of acceleration due to gravity.
Generally, acceleration is defined as the change in velocity per change in time of motion.
Acceleration of an object at any given time, t, can be calculated using the following equations below;
Explanation:
3.5 x 10^-3 as a regular number (convert from scientific notation to a real number)
Answer: 0.0035
============================================
Explanation:
The exponent is -3, so we move the decimal point 3 spots to the left to go from 3.5 to 0.0035
If the exponent was positive, then we would move the decimal point to the right that amount of spaces.