An increase in which of the following would increase the boiling point of a
liquid?

Answer: C

Explanation: This is because of a nice thing called guessing

If you were to take a large sample of the four giant planets, the most common element you would find in them is Hydrogen.

If you were to take a large sample of the four giant planets, the most common element you would find in them is Hydrogen.

The four giant planets are Jupiter, Saturn, Uranus, and Neptune.

They are sometimes referred to as gas giants due to their large size and gaseous composition.

They are composed mainly of hydrogen and helium with smaller amounts of other elements.

Hydrogen is by far the most abundant element in these planets, making up approximately 90% of their composition. Hydrogen is a chemical element with the symbol H and atomic number 1.

Hydrogen is a light, odorless, colorless, tasteless, non-toxic, and highly flammable diatomic gas with the molecular formula H2.

It is the simplest atom, consisting of one proton and one electron.

In the universe, hydrogen is the most abundant element, accounting for approximately 75% of its elemental mass.

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Considering the definition of STP conditions, 28 grams of O₂ will ocupy at STP 19.6 L.

The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

On the other side, the molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

In this case, you  have 28 g of O₂. The molar mass es 32 \(\frac{g}{mole}\)

Next, you can apply the following rule of three: if 32 grams of the compound are contained in 1 mole, 28 grams are contained in how many moles?

\(number of moles=\frac{28 gramsx1 mole}{32 grams}\)

number of moles= 0.875 moles

Now, you can apply the following rule of three: if by definition of STP conditions 1 mole of O₂ occupies a volume of 22.4 liters, 0.875 moles occupies how much volume?

\(volume=\frac{0.875 molesx22.4 L}{1 mole}\)

volume= 19.6 L

Finally, 28 grams of O₂ will ocupy at STP 19.6 L.

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Among the given options, the most likely to contain trans fatty acids would be partially hydrogenated vegetable oil.

Trans fatty acids are commonly found in processed foods that use partially hydrogenated oils as an ingredient. Partial hydrogenation is a process that converts liquid vegetable oils into solid or semi-solid fats, thereby increasing their shelf life and stability.

However, this process also generates trans fatty acids as a byproduct. Trans fats have been linked to various health issues, including heart disease. To make healthier choices, it is advisable to avoid products that list partially hydrogenated vegetable oil on their food labels.

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Answer:d

Explanation:

Answer:

protons

Atomic number and protons

After the discovery of protons , scientists realised that the atomic number of an element is the same as the number of protons in its nucleus . In the modern periodic table, the elements are arranged according to their atomic number - not their relative atomic mass .

Elements 'X', 'Y' and 'Z' have these atomic radii, in nanometers. X 0.072 nm Y 0.099 nm Z 0.111 nm. When atomic radii are correctly arranged,  the elements appears as z , y and then x across the period.

The atomic radii decreases across the period as we move from the left to right in the periodic table. the atomic radii will decreases as we move from the left to the right in the periodic table because in the period from the left to right the number of the electron will increases.

Thus, the order of the given elements arranged in the period in the periodic table as first z , then y and then x.

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Answer:

Group 2A (or IIA) of the periodic table are the alkaline earth metals: beryllium (Be), magnesium (Mg), calcium (Ca), strontium (Sr), barium (Ba), and radium (Ra). They are harder and less reactive than the alkali metals of Group 1A.

Explanation:

Answer:

Explanation: It’s the correct answer on Edmentum.

Answer:

nucleus

Explanation:

Answer:

The nucleus

Explanation:

The nucleus can be thought of as the brains of a cell.

-CancerQuest

The safest solution to protect yourself from chemical hazards in the work environment is to wear PPE kit.

What function does PPE serve?

PPE, or personal protective equipment, is clothing and gear used to reduce exposure to dangers that might result in life-threatening diseases and injuries at work. These diseases and injuries might be brought on by exposure to workplace risks such as chemical, radioactive, physical, electrical, or mechanical ones.

According to the given question:

Personal protective equipment, or "PPE," is clothing worn to reduce exposure to a range of risks. PPE examples include gloves, eye and foot protection, hard helmets, respirators, complete body suits, and protected hearing gear (earplugs, muffs).

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Answer:

Ae4

Explanation:

which virtually showed the reaction between group 4 element and group 7 element

(i) In propylene (propene), each carbon atom is sp2 hybridized. (ii) In propyne, each carbon atom is sp hybridized.

In propylene (propene), the carbon atoms undergo sp2 hybridization. This means that each carbon atom in the propylene molecule has three regions of electron density, formed by the combination of one s orbital and two p orbitals. One of the p orbitals remains unhybridized and forms a π bond with the adjacent carbon atom. The remaining three sp2 hybrid orbitals form σ bonds, two with the hydrogen atoms and one with the neighboring carbon atom. Therefore, in propylene, there is one π bond and three σ bonds per carbon atom.

In propyne, the carbon atoms undergo sp hybridization. Each carbon atom in the propyne molecule has two regions of electron density, formed by the combination of one s orbital and one p orbital. The remaining two sp hybrid orbitals form σ bonds, one with a hydrogen atom and one with the neighboring carbon atom. Additionally, each carbon atom in propyne has two unhybridized p orbitals that form two π bonds with the adjacent carbon atoms. Therefore, in propyne, there are two π bonds and two σ bonds per carbon atom.

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The iodination of salicylamide refers to the reaction between salicylamide and iodine in the presence of an oxidizing agent. The iodination reaction occurs at the ortho and para positions in the ring, with the para position being the more favorable site for iodination due to the greater electron density in that position.

This is due to the electron withdrawing effect of the nitrogen atom and the benzene ring, which makes the para position more electron-rich and therefore more nucleophilic.

The reaction mechanism for the iodination of salicylamide involves the formation of a nitrene intermediate, which attacks the iodine molecule, followed by proton transfer to form the final product. The para position is favored in this reaction because the intermediate species formed at the para position is more stable than that formed at the ortho position, resulting in a higher yield of the para isomer.

In summary, the para position is the most likely main product of the iodination of salicylamide due to its greater electron density and the stability of the intermediate species formed in that position.

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Answer:

Hey mate.......

Explanation:

This is ur answer......

Climate change has been a key factor in increasing the risk and extent of wildfires in the Western United States. Research shows that changes in climate create warmer, drier conditions. Increased drought, and a longer fire season are boosting these increases in wildfire risk. But global warming has changed some of the underlying variables that make wildfires more or less likely to occur every year. Warmer temperatures increase the likelihood that fires will burn more intensely. They also cause snow to melt sooner, and lead to drier soils, forests, and plants, which act as kindling.

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The specific heat of the metal is 0.214 J/g°C.

When a metal and water are mixed in a perfectly insulated container, they reach a final temperature through heat transfer. In this case, the initial temperature of the metal is 93.50°C, while the initial temperature of the water is 23.50°C. The final temperature of the mixture is 33.80°C.

To calculate the specific heat of the metal, we can use the principle of conservation of energy. The heat lost by the metal (Qmetal) is equal to the heat gained by the water (Qwater). The formula for heat transfer is:

Q = m * c * ΔT

Where:

Q is the heat transferred

m is the mass of the substance

c is the specific heat

ΔT is the change in temperature

Let's denote the specific heat of the metal as cm and the specific heat of water as cw. The heat lost by the metal can be calculated as:

Qmetal = cm * mmetal * (Tfinal - Tinitial_metal)

The heat gained by the water can be calculated as:

Qwater = cw * mwater * (Tfinal - Tinitial_water)

Since the container is perfectly insulated, the heat lost by the metal is equal to the heat gained by the water:

Qmetal = Qwater

cm * mmetal * (Tfinal - Tinitial_metal) = cw * mwater * (Tfinal - Tinitial_water)

Rearranging the equation, we can solve for the specific heat of the metal:

cm = (cw * mwater * (Tfinal - Tinitial_water)) / (mmetal * (Tfinal - Tinitial_metal))

Substituting the given values:

cm = (4.18 J/g°C * 105 g * (33.80°C - 23.50°C)) / (175 g * (33.80°C - 93.50°C))

After evaluating the expression, the specific heat of the metal is calculated to be approximately 0.214 J/g°C.

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Explanation:

Trend of Atomic Radii in Periodic Table :

(Note : There are exceptions to above trend)

The pH of the resulting solution is approximately 2.46.

To determine the pH of the resulting solution after Kingsley adds 47.17 mL of NaOH to 250.00 mL of the HCOOH solution, and the neutralization reaction results in 0.09 moles of HCOOH and 0.026 moles of HCOO- left in solution, follow these steps:

1. Calculate the concentrations of HCOOH and HCOO- in the solution by dividing their moles by the total volume of the solution (in liters). The total volume is the sum of the initial HCOOH solution (250 mL) and the added NaOH (47.17 mL), which equals 297.17 mL or 0.29717 L.
  - [HCOOH] = 0.09 moles / 0.29717 L = 0.303 M
  - [HCOO-] = 0.026 moles / 0.29717 L = 0.087 M

2. Use the Henderson-Hasselbalch equation to calculate the pH:
  - pH = pKa + log ([HCOO-] / [HCOOH])
  - The pKa value for HCOOH (formic acid) is approximately 3.75.
  - pH = 3.75 + log (0.087 / 0.303) = 3.75 - 1.29 = 2.46

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we get x = 0.000882 MTherefore, the pH of the solution will be:`pH = -log[H+]``pH = -log(0.000882) = 3.055`Therefore, the pH of the resulting solution is 3.055.

Determine the pH of the resulting solution?

To determine the pH of the resulting solution, first, we need to calculate the concentration of HCOO- and HCOOH using the number of moles and volume of the solution given. Then, we can use the dissociation constant of HCOOH to calculate the concentration of H+ ions and thus the pH of the solution. Let's solve it step by step.Volume of HCOOH solution = 250.00 mlVolume of NaOH solution = 47.17 mlNumber of moles of HCOOH = 0.09 molesNumber of moles of HCOO- = 0.026 molesLet's calculate the molar concentration of HCOOH and HCOO-.

Molar concentration of HCOOH= 0.09 mol/0.250 L = 0.36 MMolar concentration of HCOO-= 0.026 mol/0.250 L = 0.104 M Now, let's calculate the concentration of H+ ions using the dissociation constant of HCOOH.`HCOOH ⇌ H+ + HCOO-``Ka = [H+][HCOO-]/[HCOOH]`Let x be the concentration of H+ ions. Then, the concentration of HCOO- ions will be x and the concentration of HCOOH ions will be 0.36 - x. Now, substituting the values in the above equation, we get:`1.8 × 10 ⁻⁴ = x(0.104)/(0.36 - x)`Solving the above equation.

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Answer:

.52

Explanation:

Each time the boy breathes, he exhales 0.5012 L of gas. The moles of gas exhale is 0.52 moles.

Gas is defined as a sample of matter that, even in the presence of gravity and regardless of the amount of substance in the container, adopts the shape of the container in which it is housed and develops a uniform density inside the container. They extend to fill their containers and are simple to compress.

0.5012 L g of pure CO2 are exhaled by the individual. Divide the result by the molar mass to get the number of moles. Therefore, the individual exhales about 0.52 moles of carbon dioxide every hour. The lungs are compressed, and air is forced outward. 4.4% of the carbon dioxide in exhaled air is carbon dioxide.

Thus, each time the boy breathes, he exhales 0.5012 L of gas. The moles of gas exhale is 0.52 moles.

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The presence of 18O in the ortho-carboxy-substituted phenol indicates that the ortho-carboxy group is an intramolecular nucleophilic catalyst in the hydrolysis of aspirin, while the absence of 18O indicates that the ortho-carboxy group is an intramolecular general-base catalyst.

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The molarity of the given throat spray is 0.042 M.

Explanation :

What is Molarity?

Molarity is a measure of the concentration of a solute in a solution in terms of moles of solute per liter of solution. It is denoted by M or mol/L. It is calculated using the following formula:Molarity = Number of moles of solute / Volume of solution (in liters)

Calculating the Molarity

The throat spray has a density of 0.9956 g/mL. This means that 1 mL of the throat spray has a mass of 0.9956 g. Let the volume of the throat spray be V mL.

Therefore, the mass of the throat spray can be expressed as:

m = 0.0140 × V (since 1.40% mass phenol means 1.40 g of phenol in 100 g of solution)

Now, let's substitute the given values in the formula for molarity and simplify it:

Molarity (M) = Number of moles of solute / Volume of solution (in liters)

Number of moles of solute = Mass of solute / Molar mass

Molar mass of phenol (C6H5OH) = 6 × 12.01 g/mol (for C) + 5 × 1.01 g/mol (for H) + 16.00 g/mol (for O)= 94.11 g/mol (approx)

Molarity = Number of moles of solute / Volume of solution (in liters)= (0.000148 V) / (V / 1000)= 0.148 M/L= 0.042 M (approx.)

Therefore, the molarity of the given throat spray is 0.042 M.

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Answer:

Fats........................

Lipids is the class of macromolecule was described as being most like the hydrocarbons.

Macromolecules are bigger molecules of large size and made of smaller molecules called as monomers, Polymers are macromolecules.

All Macromolecules are not like the hydrocarbon because the macromolecules not only consists of  C and H atoms but also N and O.

Macromolecules are classified into 4 types

Proteins , Carbohydrates , Lipids and Nucleic Acids

Lipids is the class of macromolecule was described as being most like the hydrocarbons.

Lipids are a broad category of chemicals that are mostly nonpolar in nature.

This is due to the fact that they are hydrocarbons with nonpolar carbon–carbon or carbon–hydrogen bonds.

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To prepare a 130 mL of a 1.6% agarose gel for gel electrophoresis, you would need 2.08 grams of agarose. Option b is correct

A molecular biology technique called electrophoresis is used to separate biomolecules based on their mass and electrical charges.

A molecular biology technique called electrophoresis allows biomolecules like DNA or proteins to be separated based on their electrical charges and weight. For instance, DNA migrates to the positive pole when subjected to an electrophoretic field due to its negative charge, and distinct DNA molecules may also be distinguished by the weight of their base pairs.

To sum up, the technique of electrophoresis is employed in molecular biology labs to separate biomolecules based on their mass and electrical charges.

tiny size DNA is moved by gel electrophoresis across a matrix of molecules that blocks larger molecules from migrating but allows smaller ones to do so. This enables the size separation of molecules.

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The complete question is

How much agarose, in grams, would you need to prepare a 130 mL of a 1.6% agarose gel for gel electrophoresis?

a. 1.3 g b.  2.08 g c. 1.6 g d. 20.8

Answer:

blue only

Explanation:

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The molarity of the diluted standard solution is obtained by calculation to be 0.015 M.

Recall the dilution formula;

C1V1 = C2V2

C1 = Initial concentration = 0.1140 M

V1 = initial volume =  6.50mL

C2 = Final concentration = ?

V2 = Final volume = 50.0mL

Making C2 the subject of the formula and substituting values;

C2 = C1V1/V2

C2 = 0.1140 M ×  6.50mL/50.0mL

C2 = 0.015 M

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A 7.5 10-3 M Ba(OH)2 solutions at 25°C has a pH of 1.82. (option b).

A homogenous solution of two or more ingredients with particles smaller than one nm is referred to as a solution. Solutions come in many forms, such as soda water, salt and sugar solutions, etc. In a solution, every element appears as a single phase.

In chemistry, a solution is a homogeneous mix of two or more molecules in relative proportions that can be constantly changed up to what is known as the limit of solubility. Although the term "solution" is frequently used to refer to the liquid state of matter, solutions of gases and solids are also possible.

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Answer:

1. V2.

2. 299K.

3. 451K

4. 0.25 x 451 = V2 x 299

Explanation:

1. The data obtained from the question include:

Initial volume (V1) = 0.25mL

Initial temperature (T1) = 26°C

Final temperature (T2) = 178°C

Final volume (V2) =.?

2. Conversion from celsius to Kelvin temperature.

T(K) = T (°C) + 273

Initial temperature (T1) = 26°C

Initial temperature (T1) = 26°C + 273 = 299K

3. Conversion from celsius to Kelvin temperature.

T(K) = T (°C) + 273

Final temperature (T2) = 178°C

Final temperature (T1) = 178°C + 273 = 451K

4. Initial volume (V1) = 0.25mL

Initial temperature (T1) = 299K

Final temperature (T2) = 451K

Final volume (V2) =.?

V1 x T2 = V2 x T1

0.25 x 451 = V2 x 299