an electromagnetic wave propagates in the y direction and the magnetic field oscillates parallel to the x axis the wavelength of the wave is 25 nm and the amplitude of the oscillation is 0.0015t which of the following equations best describes the magnetic field as a function of time at a particular position

Answers

Answer 1

The equation that best describes the magnetic field as a function of time at a particular position is B(t) = (0.0015t)sin(2πx/λ), where B(t) is the magnetic field at time t, x is the position along the x-axis, λ is the wavelength (25 nm), and t is the time.

In an electromagnetic wave, the magnetic field and the electric field are perpendicular to each other and to the direction of propagation. Given that the electromagnetic wave propagates in the y-direction and the magnetic field oscillates parallel to the x-axis, we can conclude that the electric field oscillates parallel to the z-axis (perpendicular to both y and x directions).

The general equation for the magnetic field of an electromagnetic wave is B(t) = B₀sin(kx - ωt), where B₀ is the amplitude, k is the wave number, x is the position, ω is the angular frequency, and t is the time.

To find the specific equation for the given scenario, we need to determine the values of B₀, k, and ω. The amplitude of the oscillation is given as 0.0015t, which means the amplitude changes with time.

The wavelength λ is given as 25 nm, which is the distance between corresponding points on the wave (such as two consecutive peaks or troughs). The wave number k is related to the wavelength by the equation k = 2π/λ.

The angular frequency ω is related to the wavelength and the speed of light c by the equation ω = 2πc/λ.

Now, let's calculate the values:

Given wavelength λ = 25 nm = 25 × 10^(-9) m.

Wave number k = 2π/λ = 2π/(25 × 10^(-9)) = 2π × 10^9 / 25.

Speed of light c = 3 × 10^8 m/s (approximate value).

Angular frequency ω = 2πc/λ = (2π × 3 × 10^8) / (25 × 10^(-9)) = 2π × 3 × 10^17 / 25.

Therefore, the equation that best describes the magnetic field as a function of time at a particular position is B(t) = (0.0015t)sin((2π/25) x).

The magnetic field at a particular position and time can be calculated using the equation B(t) = (0.0015t)sin((2π/25) x), where B(t) is the magnetic field at time t, x is the position along the x-axis, and the values 0.0015t and (2π/25) come from the given amplitude and wavelength respectively.

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Related Questions

If an object travels 15 metres in 5 seconds, what is the slope of its distance-time graph?

Answers

Answer:

3 m/s

Explanation:

The slope is distance divided by time, also known as 'speed'.

15 meters / 5 seconds = 3 meters per second.

When a car’s velocity is positive and its acceleration is also positive what is happening to the car’s overall motion?

Answers

When a car's velocity is positive and its acceleration is also positive, the car's overall motion is speeding up in a forward direction.

Velocity is the measure of an object's speed in a specific direction, while acceleration is the measure of how quickly an object's velocity changes over time. So, if both the velocity and acceleration are positive, the car's speed is increasing in the forward direction. This means that the car is moving faster and faster in a forward direction.

Likewise, it can be said that the automobile develops an accelerated movement.

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Does high air pressure mean high humidity?

Answers

Answer:

Explanation:

What type of repetitions are completed with an intentionally reduced range of motion?

A student picks up four books from the floor, walks across the room through some distance with the book
at the same height and then keeps these books at the new place. In which of these sequence of actions
work is said to be performed ?

Answers

Work is performed while initially lifting books off the floor. The work is due to gravity.

Name three types of energy that exist in a large piece of charcoal on a grill in the sunlight. Explain why the charcoal has each type of energy.

Answers

Answer:

* thermal energy

potential energy,

potential energy

Explanation:

The ship has various types of energy,

* thermal energy. This energy is associated with the temperature of the coal, the hotter the greater its internal energy,

* potential energy                                                                              this energy is stored in the constituent atoms within carbon

* potential energy. It is due to the configuration of the system, in this case the sun heats the coal

Sandra is on a rotating Ferris wheel.
When Sandra is at the bottom of the Ferris wheel's rotation, how does the magnitude of the normal force ???? exerted on her by her seat compare to her weight m???? ?
A. ????=m????
B. ????>m????
C. ????=12m????
D. ???? E. ????=2m????

Answers

Sandra is on a rotating Ferris wheel. When Sandra is at the bottom of the Ferris wheel's rotation, then the magnitude of the normal force N exerted on her by her seat will be more as compared to her weight mg, i.e. N > mg. So option B. is correct.

A force that maintains an object rotating on its axis or moving into an angular path. Centripetal force is a vector quantity and the direction of the centripetal force is towards the center of its orbit. Here the normal force is more than the weight. Referring to Newton's second law of motion, with the presumption that the Ferris wheel moves at a constant velocity, the forces are

F = ma

Fc + N - w = 0

N = w - Fc

Where N is the normal force, w is the weight, and Fc is the centripetal force. We notice that the normal force is greater than the weight by a facet of the centripetal force.

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Vocabulary should be taught:
Through planned lessons.
At home.
Through natural conversations and interactions.
Through both conversations and lessons.
To English language learners.

Answers

Answer:

The third one

Explanation:

it is better for vocab to be taught through natural learning and lessons, instead of one or the other.

how far away is jupiter from the sun in kilometers

Answers

Answer:

741.56 million km

A. Determine the mass of a football which has a weight of 0.80N on a planet where the acceleration due to gravity is 2.0ms-².

B. What would be the football's weight on Earth?​

Answers

Yo buddy I’m bout to go to church for a bit early so I’ll be there at all this time is good to hear me you can do that early

answer questions show work #3
3. Determine the value of ID and VDs for the DS following amplifier. 10 RD 10V 3KD Points 0.47μF 01 G= 0.47μF Hilt RG 1.5MO -1V N5486 VGSoff = -4V IDSS = 14mA

Answers

The given amplifier circuit is a common-source amplifier. The equivalent circuit diagram of the amplifier includes a MOSFET N5486 transistor. We can determine the drain current (ID) and drain-source voltage (VDS) using the following equations:

1. Voltage at the source terminal (VS) is calculated using Ohm's law: VS = IS x RS.2. The drain current (ID) can be calculated using the equation ID = IS (1 + GVin), where Vin is the input voltage, G is the voltage gain, and IS is the current flowing through RD.Let's calculate the values of ID and VDS:

Given:- IS = VDD / RD = 10V / 10Ω = 1A- Vin = -1V / (1.5 x 10^6Ω + 0.47μF) = -0.6666667μA (using voltage divider rule)- G = -RD / RS = -10Ω / 3kΩ = -0.003333 Calculating ID:ID = 1A (1 - 0.003333 x 0.6666667 x 10^6)≈ 0.997A = 997mACalculating VDS:VDS = VDD - IDRD= 10V - 997mA x 10Ω≈ 10V - 9.97V≈ 0.03VTherefore, the values of ID and VDS are approximately ID = 997mA and VDS ≈ 0.03V, respectively.

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PLEASE HELP ME QUICK
A 10.0 kg dog moving at 6.0 m/s to the right collides with a 5.0 kg cat
moving at 3 m/s to the left. If the cat moves to the right at 12.0 m/s after
the collision, what is the speed of the dog?
O 1.5 m/s to the left
O 1.5 m/s to the right
O 3.0 m/s to the left
0 3.0 m/s to the right

Answers

Answer:

i think its 1.5 m/s to the right?

Explanation:

How much energy is required to raise the temperature of 5g of air by 10°C?

Answers

You need to know the specific heat capacity of air.
Then energy needed = 0.005 x sp.heat.cap x 10

The amount of energy required to raise the temperature of 5g of air by 10°C is 1,419.95 Joules

The formula for calculating the energy required to raise the temperature of 5g of air by 10°C is expressed according to the formula;

\(Q = mc\triangle \theta\)

m is the mass of the substance

c is the specific heat capacity of air

\(\triangle \theta\) is the temperature change

Given the following parameters

m = 5g

c = 1.0035J⋅g−1⋅K−1

\(\triangle \theta\) = 10 + 273 = 283K

Substitute the given parameters into the formula to have:

\(Q=5\times 1.0035 \times 283\\Q=1,419.95 Joules\)

Hence the amount of energy required to raise the temperature of 5g of air by 10°C is 1,419.95 Joules

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how much work is required to move it at constant speed 5.0 m along the floor against a friction force of 230 n .\

Answers

(a) To move the crate, you need to exert 7150 J of energy.

(b) The Vertical Movement of the Crate Will Take 6000 J of Work.

Determine a constant speed?

A frictional force is one that tends to oppose the motion of two bodies in contact.

The crate must be moved using both effort against resistance and effort across a distance of 5.0 meters.

Wr = Wf plus Wd.

Where Wr = work needed to move the crate, Wf = work done to overcome friction, and Wd = work needed to move the crate 5.0 meters.

Given are the following values: Wf = friction force distance = 2305 = 1150 J and Wd = force distance = 12005.0 = 6000 J.

Wr = 6000 + 1150 Wr = 7150 J when these values are substituted into equation 1.

The amount of effort needed to move the crate is therefore 7150 J.

(b) The amount of labor necessary to lift the crate vertically: mgh or

Vertically moving the crate requires the following amount of work: Wh. Equation 2 h = vertical height, W = weight of the block

Provided:W = 1200 N, h = 5.0 m

Equation 2 can be solved by substituting these numbers as follows: Vertical movement of the crate: work required = 12005

Moving the box upward will require 6000 J of work.  

The complete question is,

On the ground is a crate weighing 1200 N. How much effort is needed to move it (a) 5.0 m along the floor while battling a 230 N friction force; and (b) 5.0 m vertically?

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Define centre of mass.​

Answers

Answer:

The center of mass is a position defined relative to an object or system of object

determine the longitudinal young’s modulus e1 and longitudinal tensile strength f1t of a unidirectional carbon/glass composite with the constituent properties

Answers

To determine the longitudinal Young's modulus (E1) and longitudinal tensile strength (σ1t) of a unidirectional carbon/glass composite, we need the specific properties of the carbon and glass constituents, as well as the fiber volume fraction.

The longitudinal Young's modulus (E1) of the composite can be calculated using the rule of mixtures: E1 = Vcarbon * Ecarbon + Vglass * Eglass. where Vcarbon and Vglass are the volume fractions of carbon and glass fibers, respectively, and Ecarbon and Eglass are the Young's moduli of carbon and glass fibers, respectively. The longitudinal tensile strength (σ1t) can be determined using the following equation: σ1t = Vcarbon * σcarbon + Vglass * σglass. where σcarbon and σglass are the tensile strengths of carbon and glass fibers, respectively. The fiber volume fractions (Vcarbon and Vglass) depend on the specific composite fabrication process and design considerations. Once you provide the constituent properties (Ecarbon, Eglass, σcarbon, and σglass) and the fiber volume fractions, I can assist you in calculating E1 and σ1t.

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Help asaaap it's about doppler effect

Help asaaap it's about doppler effect

Answers

The frequency that the bad guy hear is 12000 hz when the police car is moving with speed of 80m/s.

Frequencyfo=fs(vvov), where fo is the observed frequency, fs is the source frequency, v is the speed of sound, vo is the observer's speed, the top sign indicates the observer is approaching the source, and the bottom sign indicates the observer is leaving the source.Equation fo=800(80-65) fo = 12000 after substituting the variablesThe apparent change in frequency of a wave as a result of an observer moving with respect to the wave source is known as the Doppler effect or Doppler shift. It bears the name of the Austrian physicist Christian Doppler, who first described the phenomenon in 1842.

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a brake is applied to a spinning wheel, initially moving counterclockwise, causing it to slow down with a constant angular acceleration of magnitude 5.40 rad/s2. immediately after the brake is applied, the wheel rotates through 50.4 rad during a 4.00 s time interval. what is the angular speed (in rad/s) of the wheel at the end of this time interval?

Answers

A brake is applied to a spinning wheel, initially moving counterclockwise, causing it to slow down with a constant angular acceleration of magnitude 5.40 rad/s2. Immediately after the brake is applied, the wheel rotates through 50.4 rad during a 4.00 s time interval. The angular speed (in rad/s) of the wheel at the end of this time interval is: 21.6 rad/s

The angular speed of the wheel at the end of the 4.00 s time interval can be calculated by using the equation for angular acceleration,

\(ω = ω0 + αt.\)

In this case, the initial angular speed of the wheel is 0 rad/s since it was at rest when the brake was applied, and the angular acceleration is 5.40 rad/s2.  

This gives us the equation\(ω = 0 + 5.40t.\)

Substituting the time of 4.00 s, we get \(ω = 5.40(4.00) = 21.6 rad/s.\)

This is the angular speed of the wheel at the end of the 4.00 s time interval. This can also be determined by using the equation for the change in angular displacement, \(Δθ = ω0t + ½αt2.\)

In this case, the initial angular displacement of the wheel is 0 rad and the angular acceleration is 5.40 rad/s2. This gives us the equation

\(Δθ = 0 + ½(5.40)(4.002) = 43.2 rad.\)

Since the wheel rotated through 50.4 rad during the 4.00 s time interval, the angular speed must be \(ω = Δθ/t = 50.4/4.00 = 12.6 rad/s.\)

The angular speed of the wheel at the end of the 4.00 s time interval is 21.6 rad/s, due to the constant angular acceleration of magnitude 5.40 rad/s2. The angular speed can also be determined by using the equation for the change in angular displacement, which gives 12.6 rad/s.

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A cat weighing 7 kg chases a mouse at a speed of 4 m/s. What is the kinetic energy of the cat?

Answers

54J
You calculate kinetic energy by the equation.
KE= 1/2mv^2
m= mass
v= velocity
then we have
KE = 1/2 x 3 x 6^2
KE = 1/2 x 3 x 36 = 54J

QUESTION 4 1 kilogram equals how many grams? 1 kg = g a. 10,000 b. 1,000 c. 10 d. 100

Answers

1 kilogram equals 1,000 grams. Therefore, the correct option is (b) 1,000.

What is mass?

The amount of substance in an item or system is described by mass, which is a fundamental physical attribute of matter. It is a scalar quantity, which means it simply has magnitude and no direction. The kilogram (kg) is the unit of mass, defined as the mass of a specific platinum-iridium cylinder stored at the International Bureau of Weights and Measures in France. An object's mass is a measure of how much stuff it contains. Unlike weight, which is affected by gravitational forces, mass is an intrinsic feature of matter that does not vary with position. Inertia is a measure of an object's inertia, which is its resistance to changes in motion.

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can an object under constant acceleration come to rest and stay at rest?

Answers

Explanation:

No.  If the object stays at rest, its acceleration is 0.  So the acceleration must have changed.

A block of wood is kept on table top. The mass of wooden block is 5 kg and its dimensions are 40cmx20cmx10cm. 1. Calculate the area of the wooden block in cm2 and in2. 2. Calculate the volume of the wooden block in cm3 and in3. 3. Compute the density of the wooden block in g/cm3 and lb/in3. 4. Compute the pressure. 5. Compute the pressure on top surface of the wooden block. 6. Compute the pressure on the bottom surface of the wooden block. 7. Compute the force on top surface of the wooden block. 8. Compute the force on the bottom surface of the wooden block. 9. What is the difference between the force on the bottom and the force on top?

Answers

Let's calculate the values based on the given information:

The area of the wooden block can be calculated by multiplying the length and width of one of its faces:

Area = Length * Width

Area = 40 cm * 20 cm

Area = 800 cm²

To convert to square inches, we can use the conversion factor 1 inch = 2.54 cm:

Area in square inches = Area in square centimeters / (2.54 cm/inch)²

Area in square inches = 800 cm² / (2.54 cm/inch)²

Area in square inches ≈ 124.03 in²

The volume of the wooden block can be calculated by multiplying its length, width, and height:

Volume = Length * Width * Height

Volume = 40 cm * 20 cm * 10 cm

Volume = 8000 cm³

To convert to cubic inches, we can use the conversion factor 1 inch = 2.54 cm:

Volume in cubic inches = Volume in cubic centimeters / (2.54 cm/inch)³

Volume in cubic inches = 8000 cm³ / (2.54 cm/inch)³

Volume in cubic inches ≈ 488.19 in³

The density of the wooden block can be calculated by dividing its mass by its volume:

Density = Mass / Volume

Density = 5 kg / 8000 cm³

To convert to grams per cubic centimeter (g/cm³), we can use the conversion factor 1 kg = 1000 g:

Density in g/cm³ = Density in kg/cm³ * 1000 g/kg

Density in g/cm³ = (5 kg / 8000 cm³) * 1000 g/kg

Density in g/cm³ ≈ 0.625 g/cm³

To convert to pounds per cubic inch (lb/in³), we can use the conversion factor 1 kg = 2.20462 lb and 1 inch = 2.54 cm:

Density in lb/in³ = Density in kg/cm³ * (2.20462 lb/kg) / (2.54 cm/inch)³

Density in lb/in³ = (5 kg / 8000 cm³) * (2.20462 lb/kg) / (2.54 cm/inch)³

Density in lb/in³ ≈ 0.036 lb/in³

Pressure is defined as force divided by area. In this case, we need more information to calculate the pressure. If the block is subjected to a specific force, we can divide that force by the appropriate surface area to find the pressure.

The pressure on the top surface of the wooden block depends on the force applied to it. Without information about the applied force, we cannot calculate the pressure.

Similarly, the pressure on the bottom surface of the wooden block depends on the force applied to it. Without information about the applied force, we cannot calculate the pressure.

The force on the top surface of the wooden block depends on the pressure applied and the surface area. Without information about the pressure or force applied, we cannot calculate the force.

The force on the bottom surface of the wooden block depends on the pressure applied and the surface area. Without information about the pressure or force applied, we cannot calculate the force.

Without the values for forces on the top and bottom surfaces, we cannot determine the difference between them.

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The area of the wooden block is 2800 cm² and 434.96 in².The volume of the wooden block is 8000 cm³ and 487.61 in³.The density of the wooden block is 0.625 g/cm³ and 0.0226 lb/in³.The pressure on the wooden block is 0.06125 N/cm² and 0.0089 psi.The pressure on the top surface of the wooden block is 0.06125 N/cm² or 0.0089 psi.The pressure on the bottom surface of the wooden block is 0.06125 N/cm² or 0.0089 psi.The force acting on the top surface of the wooden block is 49 N.The force acting on the bottom surface of the wooden block is 49 N.The force on the bottom surface is equal in magnitude to the force on the top surface.

1. The area of the wooden block can be calculated using the formula for the surface area of a rectangular prism: SA = 2(lw + lh + wh), where l, w, and h are the length, width, and height of the block, respectively. Using the given dimensions, we can find the surface area in cm²:

SA = 2(40 × 20 + 40 × 10 + 20 × 10)

SA = 2(800 + 400 + 200)

SA = 2(1400)

SA = 2800 cm²

To convert cm² to in², we can use the conversion factor 1 in² = 6.45 cm². So, the area in in² is:

2800 ÷ 6.45 = 434.96 in² (rounded to two decimal places)

2. The volume of the wooden block can be calculated using the formula for the volume of a rectangular prism: V = lwh. Using the given dimensions, we can find the volume in cm³:

V = 40 × 20 × 10

V = 8000 cm³

To convert cm³ to in³, we can use the conversion factor 1 in³ = 16.39 cm³. So, the volume in in³ is:

8000 ÷ 16.39 = 487.61 in³ (rounded to two decimal places)

3. The density of the wooden block can be calculated using the formula: density = mass/volume. The mass of the block is given as 5 kg. To convert this to grams, we can use the conversion factor 1 kg = 1000 g. So, the mass in grams is:

5 kg × 1000 g/kg = 5000 g

Using the volume calculated in part 2, we can find the density in g/cm³:

density = 5000 g/8000 cm³

density = 0.625 g/cm³

To convert g/cm³ to lb/in³, we can use the conversion factor 1 g/cm³ = 0.0361 lb/in³. So, the density in lb/in³ is:

0.625 g/cm³ × 0.0361 lb/in³/g/cm³ = 0.0226 lb/in³

4. The pressure on the wooden block is given by the formula: pressure = force/area. To find the pressure, we need to know the force acting on the block. Since the block is simply resting on the tabletop, the force acting on it is due to its weight. Using the formula for weight: w = mg, where w is weight, m is mass, and g is the acceleration due to gravity (9.8 m/s²).

To find the weight in newtons (N), we can use the conversion factor 1 kg = 9.8 N. So, the weight of the block is:

5 kg × 9.8 N/kg = 49 N

Using the area of the block's base (40 cm × 20 cm = 800 cm²), we can find the pressure in N/cm²:

pressure = 49 N/800 cm²

pressure = 0.06125 N/cm²

To convert N/cm² to psi, we can use the conversion factor 1 psi = 6894.76 N/m². So, the pressure in psi is:

0.06125 N/cm² × (1 m²/10,000 cm²) × (1 psi/6894.76 N/m²) = 0.0089 psi (rounded to four decimal places)

5. The pressure on the top surface of the wooden block is the same as the pressure calculated in part 4: 0.06125 N/cm² or 0.0089 psi.

6. To find the pressure on the bottom surface of the block, we can use the formula: pressure = force/area. Since the bottom surface has the same area as the top surface, the pressure will also be the same: 0.06125 N/cm² or 0.0089 psi.

7. The force acting on the top surface of the wooden block is simply its weight, which we calculated to be 49 N in part 4.

8. The force acting on the bottom surface of the wooden block is also its weight, which we calculated to be 49 N in part 4.

9. The force on the bottom surface is equal in magnitude to the force on the top surface.

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mixtures cannot be physically separated true or false

Answers

Answer: False

Explanation: You'll be able continuously tell a blend, since each of the substances can be isolated from the group in numerous physical ways. You'll be able continuously get the sand out of the water by sifting the water absent. Some of the time a blend partitioned on their possess eg. water & cooking oil.

calculate the wavelength (in m) of a 650.00 hz sound in air at room temperature and pressure, where the velocity of sound is 344 m/s.

Answers

The wavelength of a 650.00 Hz sound in air at room temperature and pressure, where the velocity of sound is 344 m/s, is approximately 0.529 m.

What is the wavelength of a 650.00 Hz sound in air at room temperature and pressure?

Sound waves travel through a medium by creating compressions and rarefactions. The wavelength of a sound wave is the distance between two consecutive points that are in phase, such as two compressions or two rarefactions. To calculate the wavelength, we can use the formula: wavelength = velocity of sound / frequency.

In this case, the frequency of the sound is 650.00 Hz, and the velocity of sound in air at room temperature and pressure is 344 m/s. Plugging these values into the formula, we get: wavelength = 344 m/s / 650.00 Hz = 0.529 m.

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Can you explain what a mixture is from a chemical prospective?

Answers

Answer:

I know I'm late but...

Explanation:

A mixture is the combination of two or more substances together. And I'm pretty sure that a mixture has no chemical substances. And mixtures can be physically separated.

Hope this helps you!

Stay safe and have a wonderful day/night!! :)

Please give brainliest to the person above!!!!!

Use the drop-down menu to answer the question. A student is going to produce static charge in a glass rod by rubbing it with a piece of silk. Which method of transferring charge is being described?.

Answers

Answer:

Friction

Explanation:

edge 2022

This method of transferring charge by rubbing objects is charging by friction.

What is meant by charging ?

Charging is defined as the phenomenon of transferring charge between two objects by supplying electrons between the objects.

Here,

The student done an experiment of rubbing a glass rod with a piece of silk and as a result, static charge is produced.

This is because, when the two objects are rubbed against each other, there occurs a friction between them. During this process, the glass rod that has free electrons that are freely bound to it will transfer its electrons to the piece of silk cloth. As a result, the glass rod will lose electrons and will have an electron deficiency, that means the glass rod becomes positively charged. At the same time, the silk cloth will acquire the electrons and the piece of silk becomes negatively charged.

This phenomenon of transferring charge between two objects when they are rubbed against each other is called charging by friction.

Hence,

This method of transferring charge by rubbing objects is charging by friction.

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Why do we need to have an understanding about impulse and momentum ?

Answers

Impulse is the interval of a force ,f,over the time interval ,t,for which it acts
Formula p=f t
Momentum is the quantity of motion of a moving body measured as a product of its mass and velocity
Formula p=m v
P=momentum
M=mass
V=velocity

what would be the noontime altitude of the sun at the time of the summer solstice?

Answers

At the time of the summer solstice, the noontime altitude of the sun is at its highest point, around 90°.

What is altitude?

Altitude is the height above sea level. It is typically measured in either metres or feet. In aviation, altitude can also refer to the vertical distance between an aircraft and a certain reference point on the ground. Altitude can be used to determine the air pressure, temperature, and density of the air. Altitude can also be used to calculate the distance a plane can travel without refueling. Altitude can play an important role in the weather of an area, as air pressure and temperature tend to decrease with altitude. Altitude can also affect the type of vegetation found in an area. In mountain regions, the altitude can have a dramatic effect on the climate, creating distinct areas of vegetation and wildlife. Altitude can also affect the types of crops that can be grown in an area, depending on the air pressure, temperature, and precipitation.

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A box has pushed across the floor for 5.2 M with a 48 N force how much work is done?

Answers

Work is force x displacement
So force is 48 and displacement is 5.2 as given

Therefore 48 x 5.2
Which is 249.6
Approximately 250 J (joules)

What volume is occupied by 24.2 g of argon gas at a pressure of 1.23 atm and a temperature of 318 K ? Express your answer with the appropriate units.

Answers

The volume occupied by the 24.2 g of argon gas at a pressure of 1.23 atm and a temperature of 318 K is 12.6 L.

Mass of argon, m = 24.2 g

Pressure, P = 1.23 atm

Temperature, T = 318 K

We need to find the volume occupied by the argon gas.

The volume occupied by a gas can be calculated using the ideal gas law, PV = nRT,

where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature.

We can rearrange this equation to solve for V:

V = nRT/P

We know the mass of argon, so we can calculate the number of moles using the molar mass of argon:

Ar molar mass = 39.948 g/moln = m/M = 24.2 g / 39.948 g/mol = 0.6069 mol

Now we can substitute the given values into the equation for V and solve for V:

V = (0.6069 mol)(0.08206 L atm/mol K)(318 K)/(1.23 atm) = 12.6 L

Therefore, the volume occupied by the 24.2 g of argon gas at a pressure of 1.23 atm and a temperature of 318 K is 12.6 L.

The volume occupied by the 24.2 g of argon gas at a pressure of 1.23 atm and a temperature of 318 K is 12.6 L.

We used the ideal gas law to calculate the volume of argon gas. We first calculated the number of moles of gas from the mass of argon, and then substituted the given values into the equation for V. The final answer is 12.6 L.

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If I increase mass of 2 objects 2 times and increase the distance 2 times what happen to the force

Answers

Relation between Distance and acceleration

\(\\ \tt\longmapsto a=dv/dt\)

\(\\ \tt\longmapsto a=ds/dt^2\)

So

\(\\ \tt\longmapsto a\propto s\)

Acceleration is directly proportional to distance.

And

According to Newton's law

\(\\ \tt\longmapsto F=ma\)

\(\\ \tt\longmapsto F\propto m,a\)

So Force will be four times .
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