An ant is on the pendulum bob of a clock. What would be its displacement in one time period?

They each pull equally hard, forcing the Sun to shift slightly. when the Sun's gravitational pull holds the planets in their orbits,

The average period of the solar cycles, including irradiance, sunspots, solar flares, radio flux, and polarity flip, is 11 Earth years. According to scientists, the Sun's internal processes and atmospheric interactions are what cause various solar activity. According to the authors, these behaviours and cycles also have an outside origin. Because planets need external constant loading to support their ongoing internal processes and dynamic systems. Here, the Sun's dynamical system and internal processes are activated by the planets' uneven gravitational fields, particularly by the biggest planet in the solar system, Jupiter, which has 67 moons and an orbital period of 11.856 years. As a result, distinct solar cycles are produced.

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Answer:

There are four natural states of matter: Solids, liquids, gases and plasma.

Explanation:

The fifth state is the man-made Bose-Einstein condensates. In a solid, particles are packed tightly together so they don't move much.

Answer:

a = 2.5 [m/s²]

Explanation:

To solve this problem we must use the following equation of kinematics.

\(v_{f} =v_{o} +a*t\)

where:

Vf = final velocity = 25 [m/s]

Vo = initial velocity = 0 (star from the rest)

a = acceleration [m/s²]

t = time = 10 [s]

25 = 0 + (a*10)

a = 25/10

a = 2.5 [m/s²]

Answer:

111op

Explanation:

Answer:

11op

Explanation:good job and work hard

Answer:

\(difference \: in \: weight = 150n - 100n = 50n\)

Now,buyantant force

\(difference \: in \: weight \: = volume(body) \times density \: of \: water \: \times g\)

so;

\(50 = {v}^{b} \times 1 \times {10}^{3} \times 9.8m {s}^{2}\)

\( {v}^{b} = \frac{50}{1000 } \times 9.8\)

\( = \frac{50}{9800} \)

\( = 0.0051\)

Now,

\(mass \: in \: air \: = 150n = \frac{150}{9.8kg} \)

\(density = \frac{weght}{volume} \)

\( = \frac{150}{0.0051} \times 9.8 \\ x = 3000\)

And now,

\(specific \: density \: = \frac{density of \: the \: body}{density \: of \: water} \)

\( = \frac{3000}{1000} \)

\( = 3\)

Hence that,specific density of a given body is 3

please mark me as brainliest, please

(a) In a parallel-flow arrangement, the outlet temperature of the water and the air can be determined using the energy balance equation. The heat transfer rate between the water and the air is equal to the product of the water mass flow rate, specific heat capacity of water, and the change in temperature of the water:

Similarly, the heat transfer rate between the air and the water is equal to the product of the air mass flow rate, specific heat capacity of air, and the change in temperature of the air:

Since the heat exchanger is operating under fully-developed flow conditions, the outlet temperature of the water and the air can be found by equating the heat transfer rates:

By substituting the given values, including the specific heat capacities of water and air, and solving the equations, the outlet temperatures of the air and water can be calculated.

(b) In a counter-flow arrangement, the outlet temperatures of the air and water can be determined using a similar energy balance equation. However, in this case, the change in temperature of the air is taken as the difference between the outlet and inlet temperatures of the air:

Again, by equating the heat transfer rates, substituting the given values, and solving the equations, the outlet temperatures of the air and water in a counter-flow arrangement can be calculated.

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The neutral point is located at a distance x from the 10 nC charge and (d+x) from the -20 nC charge.

Yes, there is a point between a 10 nC charge and a -20 nC charge at which the electric field is zero. This point is known as the "neutral point" or the "equipotential point" and it lies on the line that joins the two charges.

To find the position of the neutral point, we can use the principle of superposition of electric fields. According to this principle, the electric field at any point due to a collection of charges is the vector sum of the electric fields due to each individual charge.

Let's assume that the 10 nC charge is located at the origin and the -20 nC charge is located on the x-axis at a distance of d from the origin. The electric field due to the 10 nC charge at any point on the x-axis is given by:

E1 = k*q1/x^2

where k is Coulomb's constant, q1 is the charge on the 10 nC charge, and x is the distance from the 10 nC charge to the point on the x-axis.

Similarly, the electric field due to the -20 nC charge at any point on the x-axis is given by:

E2 = k*q2/(d+x)^2

where q2 is the charge on the -20 nC charge and (d+x) is the distance from the -20 nC charge to the point on the x-axis.

For the neutral point, the electric field due to the 10 nC charge and the electric field due to the -20 nC charge must cancel each other out. In other words, E1 + E2 = 0. Solving this equation for x, we get:

x = d*q2/(q1-q2)

Therefore, the neutral point is located at a distance x from the 10 nC charge and (d+x) from the -20 nC charge.

If q1 and q2 have the same magnitude (in this case, 10 nC), the neutral point will be located at the midpoint between the two charges, which is at a distance of d/2 from each charge. However, in this case, since the charges have opposite signs, the neutral point will be located closer to the negative charge (-20 nC).

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Answer:

 W = 500 J

Explanation:

Work is defined by

         W = F . x

if we develop the dot product

         W = F x cos θ

where is the angle between the force and the displacement, in this case the angle is zero, so cos 0 = 1

          W = F x

indicate that each person applies a force of 500 N, so the total force is

         F = 1000 N

let's reduce the distance to the SI system

          x = 50 cm = 0.50 m

let's calculate

          W = 1000 0.50

          W = 500 J

Lifting a 50-kg sack through a vertical distance of 2 m requires same amount of work as lifting a 25-kg sack through a vertical distance of 4 m

To determine which will require more work, we shall determine the work done in lifting each sack. Details below:

i. Work done in lifting 50 Kg

Wd = mgh

Wd = 50 × 9.8 × 2

Workdone = 980 J

ii. Work done in lifting 25 Kg

Wd = mgh

Wd = 25 × 9.8 × 4

Workdone = 980 J

SUMMARY

Thus, equal amount of work done is needed.

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Answer:

105.6 KJ

Answer

3.7/5

4

hope this will help you friend.

The correct answer is option B: Q1 > Q2 > Q3.

Since the capacitors are connected in series, the charge on each capacitor must be the same. Therefore, Q1 = Q2 = Q3. However, the voltage across each capacitor will be different based on their capacitance values. Using the equation Q = CV, where Q is the charge, C is the capacitance, and V is the voltage, we can calculate the voltage across each capacitor as follows:

V1 = Q1/C1

V2 = Q2/C2 = Q1/(2C1)

V3 = Q3/C3 = Q1/(3C1)

Since the voltage across C2 is half that of C1, and the voltage across C3 is one-third that of C1, the voltage across C1 must be the largest. Therefore, Q1 has the largest charge, followed by Q2 and Q3. Thus, the correct answer is option B: Q1 > Q2 > Q3.

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The magnitude of the fan's angular acceleration, is 0.008033 rad/s² when A fan spinning at 89 rad/s is turned off. It turns 1250 complete revolutions before coming to a stop.

To find the magnitude of the fan's angular acceleration, we can use the equation:

Angular acceleration (α) = (final angular velocity - initial angular velocity) / time

First, let's convert the number of revolutions to radians. Since one revolution is equal to 2π radians, we have:

1250 revolutions * 2π radians/revolution = 2500π radians

The initial angular velocity (ωi) is given as 89 rad/s, and the final angular velocity (ωf) is 0 rad/s (since the fan comes to a stop).

The time (t) it takes for the fan to stop spinning can be calculated using the formula:

Number of revolutions = (final angular velocity - initial angular velocity) * time / (2π)

Substituting the known values, we have:

1250 = (0 - 89) * t / (2π)

Simplifying the equation:

1250 = -89t / (2π)

Now we can solve for t:

t = (1250 * 2π) / (-89)

Substituting this value back into the angular acceleration formula:

Angular acceleration (α) = (0 - 89) / [(1250 * 2π) / (-89)]

Simplifying further:

α = -89 / [(1250 * 2π) / (-89)]

Calculating this expression:

α ≈ -0.008033 rad/s² (rounded to the appropriate number of decimal places)

Therefore, the magnitude of the fan's angular acceleration is approximately 0.008033 rad/s².

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Answer:

104.3 cm  or 179.7

Explanation:

First find time that it takes for the object to hit the ground

\(\sqrt{(2H)/g} -> \sqrt{(2 x 179)/ 9.8} = 6.04s\\\)*

Then find xf of projectile \(xf= 5.9(6.04) = 37.7\\\\\)

not 100% sure if the projectile is going away from the object or towards it but you either do 142- 37.7   or    142+37.7  

hope that helps

"217 cm" would be the difference throughout the landing locations of the two objects.

Given:

Initial horizontal speed,

Height,

By applying equation of motion, we get

→               \(S = ut+\frac{1}{2}at^2\)

By substituting the values, we get

→ \(179\times 10^{-2}=0+\frac{1}{2}\times 9.8\times t^2\)

→            \(3.58= 9.8t^2\)

                 \(t^2 =\frac{3.58}{9.8}\)

                  \(t = \sqrt{0.36531}\)

                     \(= 0.61 \ s\)

now,

The horizontal distance travelled by the first particle will be:

→ \(d = v\times t\)

     \(= 5.9\times 0.61\)

     \(= 3.59 \ m\)

or,

     \(= 359 \ cm\)

hence,

The distance between particle will be:

= \(d -142\)

= \(359-142\)

= \(217 \ cm\)

Thus the above approach is right.

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Answer:

= 7.88 × 10^-12 T

Explanation:

From the above question, we are told that:

Kinetic Energy of the proton is K. E = 10.0 MeV

Step 1

We convert 10.0 MeV to Joules

1 Mev = 1.602 × 10-13 Joules

10.0 MeV = 10.0 × 1.602 × 10^-13 Joules = 1.602 × 10^-12 J

Hence, the Kinectic energy of a proton = 1.602 × 10^-12 J

Step 2

Find the Speed of the Proton

The formula for Kinectic Energy =

K.E = 1/ 2 mv²

Where

m = mass of the proton

v = speed of the proton

K.E of the proton = 1.602 × 10^-12 J

Mass of the proton = 1.6726219 × 10^-27 kilograms

Speed of the proton = ?

1.602 × 10^-12J = 1/2 × 1.6726219 × 10^-27 × v²

1.602 × 10^-12J = 8.3631095 ×10^-28 × v²

v² = 1.602 × 10^-12/8.3631095 ×10^-28

v = √(1.602 × 10^-12/8.3631095 ×10^-28)

v = 43772331.227m/s

v = 4.3772331227 × 10^7m/s

Approximately = 4.4 × 10^7 m/s

Step 3

Find the Magnetic Field of that region of space

The formula for Magnetic Field =

B = m v / q r

We are told that the proton executes a circular orbit, hence,

mv = √2m(KE)

m = Mass of the proton = 1.6726219 × 10^-27 kg

K.E of the proton = 1.602 × 10^-12 J

v = speed of the proton = 4.4 × 10^7 m/s

q = Electric charge = 1.6 × 10^-19 C

r = radius of the orbit = 5.80Ã10^10 m

= 5.8 × 10^10m

Magnetic Field =

=√ (2 × 1.6726219 × 10^-27 kg × 1.602 × 10^-12 J) /( 1.6 × 10^-19 C × 5.80 × 10^10 m)

= 7.88 × 10^-12 T

The magnetic field in that region of space is approximately 7.88 × 10^-12 T

Answer:

The answer is either looking glass or stained glass.

Explanation:

The popular glass used in astrology is stained glass which is popular in symbolization of huge astrology figures. As for looking glass, it's more popular in astrological souvenirs or objects.

Answer:

i think answer is pisces horoscope

According to the law of reflection, when a light wave hits a smooth surface, the angle of reflection is equal to the angle of incidence. Therefore, if the angle of incidence is 40 degrees, the angle of reflection will also be 40 degrees.

The law of reflection states that the angle of incidence (the angle between the incident light ray and the normal to the surface) is equal to the angle of reflection (the angle between the reflected light ray and the normal to the surface). This law holds true for smooth surfaces, such as mirrors or still water.

In this case, when a light wave hits a smooth surface at an angle of incidence of 40 degrees, the angle of reflection will also be 40 degrees. The incident light ray and the reflected light ray will be on opposite sides of the normal to the surface, forming an equal angle with it.

Understanding the law of reflection is crucial in various applications, including optics, image formation, and the study of light behavior. It allows us to predict and analyze the behavior of light rays when they encounter reflective surfaces, enabling us to understand how images are formed and how light interacts with different materials.

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We can expect the maximum electron kinetic energy to be higher when illuminated by light with a wavelength of 250 nm compared to 350 nm.

The phenomenon of light causing the emission of electrons from a metal surface is known as the photoelectric effect. The energy of the incident photons determines the maximum kinetic energy of the emitted electrons.

In this case, when the metal surface was illuminated by light with a wavelength of 350 nm, the maximum kinetic energy of the emitted electrons was found to be 1.90 eV. Now, if the same metal is illuminated by light with a shorter wavelength of 250 nm, the energy of the incident photons would increase.

This would result in a higher maximum kinetic energy of the emitted electrons, as per the photoelectric effect. Therefore, we can expect the maximum electron kinetic energy to be higher when illuminated by light with a wavelength of 250 nm compared to 350 nm.

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The distance and displacement are the two quantities which seem to mean the same but are distinctly different from each other. Here let us assume the speed of a object as 4m/s and time as 10 s, then the distance is 40m.

The distance of an object can be defined as the complete path travelled by an object. It is a scalar quantity. It has both magnitude and direction. The SI unit of distance is meter (m).

The equation connecting distance, speed and time is given as:

Speed = Distance / Time

Distance = Speed × Time

= 4 × 10

= 40 m

Thus the distance is 40m.

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Your question is incomplete, but most probably your full question was.

Calculate the distance covered by a mousetrap car in (m) when the speed of a object is 4m/s and time is 10 seconds.

Given a circular window with a diameter of 2.85 cm, the force can be calculated using the equation F = P * A, where F is the force, P is the pressure, and A is the area of the circular window.

The force exerted by the fluid on the window of an instrument probe is a result of the pressure exerted by the fluid at a certain depth. The pressure exerted by a fluid is given by the equation P = ρ * g * h, where ρ is the density of the fluid, g is the acceleration due to gravity, and h is the depth.

To find the force exerted by only the fluid on the window, we first need to calculate the pressure exerted by the fluid at the given depth. We can use the equation P = ρ * g * h, where ρ is the density of the fluid, g is approximately 9.8 m/s², and h is the depth. The pressure obtained will be in Pascals (Pa).

Next, we calculate the area of the circular window using the given diameter. The area of a circle is given by the equation A = π * (r²), where r is the radius. We divide the diameter by 2 to obtain the radius, and then substitute the value into the equation to find the area.

Finally, we can calculate the force exerted by the fluid on the window using the equation F = P * A. Substituting the values for pressure and area, we can calculate the force in Newtons (N).

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Answer:

Train will take 156 sec to travel 12km.

the horizontal component of the golf ball's initial velocity is 47.92 m/s.

The given parameters;

initial velocity of the golf, v = 60 m/s

angle of projection of the golf, Ф = 37°

The horizontal component of the golf ball's initial velocity is calculated as follows;

\(v_0_x = v\times cos(\theta)\\\\\)

\(v_0_x\) = 60 m/s  x cos (37)

\(v_0_x\) = 60 m/s x 0.7986

\(v_0_x\) = 47.92 m/s

Thus, the horizontal component of the golf ball's initial velocity is 47.92 m/s.

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Answer:

The magnetic force disappears

The separation distance S between the rocks will initially increase as Rock Y falls since Rock X is already ahead of it. However, as Rock Y accelerates and gains speed, the separation distance S between the rocks will start to decrease.

Distance refers to the amount of space or physical separation between two points or objects. It is a fundamental concept in physics, mathematics, and everyday life. Distance can be measured in different units such as meters, kilometers, miles, or light-years, depending on the context and the scale of the objects being measured.

In physics, distance is a key component of many equations that describe the behavior of particles and objects. For example, the distance between two electric charges or masses determines the strength of the force between them. In mathematics, distance is the length of the shortest path between two points in a Euclidean space, and it plays a crucial role in geometry, topology, and calculus.

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If the firm's MARR is 14% per year, the cost per kilowatt-hour of generating electricity is $1.571.

Given that a binary geothermal system will cost $90 million to build and $10 million to operate per year, then the present worth of the initial capital cost and annual cost can be found using the present worth factor as shown below:

PWF = 1-1/(1+i)n

where,

i = interest rate per period and

n = number of periods

PW of the initial capital cost = $90 million x PWF

(i=14%, n is 1)

= $90 million x 0.877

= $78.93 million

PW of the annual cost = $10 million x P(A/P, 14%, 30)

= $10 million x 9.209

= $92.09 million

Total PW = PW of the initial capital cost + PW of the annual cost

= $78.93 million + $92.09 million

= $171.02 million

Since the plant is to last for 30 years, the total energy output for the life of the project will be as follows:

Energy output = Capacity factor x Installed capacity x Number of years in operation x Number of hours per year

Energy output = 0.7 x 50 MW x 30 years x 8760 h/yr

Energy output = 108,540,000,000 Wh or 108,540,000 kWh

The cost per kilowatt-hour of generating electricity can then be found as follows:

Cost per kWh = Total PW/Total kWh

= $171.02 million/ (108,540,000 kWh x 1000)

= $1.571 per kWh

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Fluid clutches are used on equipment that is subject to frequent stopping.

Fluid couplings are used in various equipment in which the rotational torque must be transferred smoothly and without shock from the motor to the driven machine.

They are characterized by high transmittable torque and power, quick response times, and a good damping effect.

It absorbs and smooths torsional vibrations from the driveshaft, resulting in a longer lifespan of the drive components.

Equipment that is subject to frequent stopping.

For equipment that is subject to frequent stopping, fluid clutches are commonly used.

This is due to the fact that fluid clutches may be started and stopped frequently without causing harm or wear to the machine.

For this reason, fluid clutches are commonly used in machinery that needs a smooth start and stop, which is important to avoid any harm to the machinery.

In addition, fluid clutches are also less likely to slip, making them ideal for continuous running machines.

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Fluid clutches are used on equipment that is subject to frequent stopping. The correct answer is option C.

A fluid clutch is a type of mechanical device that transmits torque and rotational power from one shaft to another via a fluid.

Fluid clutches are used to couple two rotating shafts and control the amount of torque transferred between them.

Fluid clutches are used in many types of industrial machinery, including printing presses, machine tools, and pumps, as well as in cars and other vehicles.

These clutches can handle higher torque and power loads than most other types of clutches, making them well suited for heavy-duty applications.  

They are most commonly used on equipment that is subject to frequent stopping, such as industrial machines and vehicles, but can also be used on equipment that is subject to other forms of stress, such as misalignment and continuous running. So, the correct answer is option C.

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