Amy bought a diamond ring for $6,000. If the value
of the ring increases at a constant rate of 5.8% per
year, how long will it take for the ring to be worth
$19,000?
Show work

Answer:

B

Step-by-step explanation:

to find the inverse of a function, repalace f(x) with x, and replace x with y, proceed to solve for y and the answer you get is B

Answer:

B

Step-by-step explanation:

f(x)=5x/3+5

y=5x/3+5

x=5y/3+5

now solve for y

3x=5y+15

5y=3x-15

y=3x/5-3 or 3(x-5)/5

The solution set of the example inequality, 2•x + 3 ≤ -3, is the option;

A possible inequality that can be used to get one of the options, (the inequality is not included in the question) is as follows;

Solving the above inequality, we have;

2•x + 3 ≤ -3

2•x ≤ -3 - 3 = -6

2•x ≤ -6

Therefore;

x ≤ -6 ÷ 2 = -3

x ≤ -3

Which gives;

-∞ < x ≤ -3 in interval notation is (-∞, -3]

The solution set of the inequality, 2•x + 3 ≤ -3, is therefore the option;

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(1) To show that X has a subsequence X' such that either X' is in A or X' is in B, we can use the fact that A and B are subsets of the metric space (M,d) to construct two subsequences, one consisting of terms from A and the other consisting of terms from B.

Let X_A be the subsequence of X that consists of all terms in A, and let X_B be the subsequence of X that consists of all terms in B. If either of these subsequences is infinite, then we are done. Otherwise, both A and B are finite sets, and we can construct a subsequence X' by interleaving the terms from X_A and X_B in any way we choose.

For example, suppose A = {a1, a2, a3} and B = {b1, b2}. Then X_A = (a1, a2, a3) and X_B = (b1, b2), and we can construct the subsequence X' = (a1, b1, a2, b2, a3). This subsequence has terms from both A and B, but we can easily extract a sub-subsequence consisting only of terms from A or only of terms from B if we wish.

(2) To show that the union of two sequentially compact sets in a metric space (M,d) is sequentially compact, we need to show that every sequence in the union has a convergent subsequence. Let A and B be two sequentially compact subsets of M, and let X be a sequence in A ∪ B. By (1), X has a subsequence X' that is either in A or in B.

If X' is in A, then it has a convergent subsequence by the sequential compactness of A. This subsequence is also a subsequence of X and therefore converges in A ∪ B. If X' is in B, then it has a convergent subsequence by the sequential compactness of B, and we can again argue that this subsequence converges in A ∪ B.

Therefore, every sequence in A ∪ B has a convergent subsequence, and so A ∪ B is sequentially compact.
(1) Since X = (xk) is a sequence in A ∪ B, each term xk is either in A or in B. Divide the terms of X into two subsequences: X_A consisting of terms in A, and X_B consisting of terms in B. At least one of these subsequences must be infinite (since a finite subsequence cannot exhaust the entire sequence X).

Without loss of generality, assume X_A is infinite. Then X_A is a subsequence of X consisting only of terms in A. Let X' = X_A. Then X' is a subsequence of X such that X' is in A. Similarly, if X_B were infinite, we could construct a subsequence X' in B.

(2) To show that the union of two sequentially compact sets in a metric space (M, d) is sequentially compact, we need to show that any sequence in the union has a convergent subsequence.

Let A and B be two sequentially compact sets in (M, d), and let X = (xk) be a sequence in A ∪ B. By part (1), we know that X has a subsequence X' such that either X' is in A or X' is in B. Without loss of generality, assume X' is in A.

Since A is sequentially compact, X' has a convergent subsequence X'' in A. Thus, X'' is a convergent subsequence of X in A ∪ B. Similarly, if X' were in B, we would have a convergent subsequence in B. Therefore, the union A ∪ B is sequentially compact.

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Answer:

The hourly rate

Step-by-step explanation:

The answer is B.

the graph of x²+2 (quadratic) has domain values less than 1 because the circle in the graph is an open circle

The graph of -x+2 (linear) has domain values greater than or equal to 1 because the circle in the graph is a closed circle

Hope it helps!

Answer: ?

Step-by-step explanation:

Answer:

x=5 and y=16

Step-by-step explanation:

x = number of pants

y = number of shirts

Set up equations:

Set the equations up as a system:

25x+14.5y=357

x+y=21

Steps:

Solve the system by substitution.

(You can also solve this system by elimination.)

25x + 14.5y=  357

x + y = 21

Step 1: Solve x+y=21 for x:

(x + y) − y = (21) − y(Subtract y from both sides)

x = −y + 21

Step 2: Substitute −y + 21 for x in 25x + 14.5y = 357:

25x + 14.5y = 357

25(−y + 21) + 14.5y = 357

−10.5y + 525 = 357 (Simplify both sides of the equation)

(−10.5y + 525) − 525 = (357) − 525(Subtract 525 to both sides)

−10.5y =  −168

−10.5y / −10.5 = −168 / −10.5 (Divide both sides by -10.5)

y = 16

Step 3: Substitute 16 for y in x = −y + 21:

x = −y + 21

x = −16 + 21

x = 5 (Simplify both sides of the equation)

Answer:

x=5 and y=16

Answer:

Step-by-step explanation:

Cashews $2.36×(1+20%)=2.832

almonds $1.48×1.2=1.776

penut $0.98×（1+20%）=1.176

1/4 cashew 1/4almonds  1/2peanut

(2.832+1.776)/4+(1.176/2)=1.74$

Answer:

I will study about it and tell u okk

Answer:

Jeff, 4.5 hours; Julia 9 hours.

Step-by-step explanation:

To solve the problem, we need to write two equations using the given information.

So, writing the first equation we have:

We know that Jeff can weed the garden twice as fas as his sister Julia, so:

Also, from the statement we know that they can weed the garden in 3 hours, so, writing the second equation we have:

Then, we need to substitute the first equation into the second equation in order to isolate Julia's rate, so, solving we have:

We have that Julia could weed the garden by herself in 9 hours.

So, calculating how long will it take to Jeff, we have:

We have that Jeff could weed the same garden by himself in 4.5 hours.

hope this helps!

If Jacqueline bought a bicycle at wholesale cost for $210 dollars. If the bicycle is normally $300 from the local bike shop, Then 30% markup the bike shop adds to the wholesale cost

Percentage, a relative value indicating hundredth parts of any quantity.

Given,

Jacqueline bought a bicycle at wholesale cost for $210 dollars.

The actual price of bicycle is normally $300 from the local bike shop.

We need to find the percent markup the bike shop adds to the wholesale cost.

For this we need to find the difference and we have to divide it by actual price

300-210/300=90/300=0.3

Now multiply 0.3 with 100 as hundredths to get the percentage value

0.3×100=30

Hence 30 percent markup the bike shop adds to the wholesale cost

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The given initial value problem's exact solution: y(t) = 1, and thus y(1) = 1. The Euler approximation of y(1) using a step-size h = 0.5 i: y(1) ≈ 1. Given the initial value problem:

y' = ty ' (0)

 = 0

We are to determine the exact solution y(t) and compute y(1), and also find the Euler approximation of y on the interval [0, 1] using a step-size h = 0.5 (half step size).

(a) The given initial value problem is a first-order linear differential equation, whose standard form is:

y' + P(t)y = Q(t), where P(t) = 0 and Q(t) = 0. Thus, the integrating factor is:

I(t) = e^∫ P(t)dt

      = e^∫ 0 dt

      = 1.

The exact solution y(t) is obtained by multiplying both sides of the differential equation by the integrating factor,

I(t) = 1, and integrating:

y' + P(t)y = Q(t) becomes

y' + 0y = 0, which implies

y' = 0.

Hence, y(t) = Ce^0 = C, where C is a constant determined using the initial condition y(0) = 1. Therefore, we have:

C = y(0) = 1.

Hence, the initial value problem's exact solution is y(t) = 1, and thus y(1) = 1.

(b) Euler Approximation of y using step-size h = 0.5We have h = Δt = 0.5, t0 = 0, tn = 1. The number of steps, n, is given by:

n = (tn - t0)/h

n = (1 - 0)/0.5

n = 2.

Therefore, we have two grid points:

t0 = 0, and

t1 = 0 + 0.5

  = 0.5

For the Euler approximation of y on [0, 1], we use the formula:

yi+1 = yi + h * f(ti, yi), for i = 0, 1, 2, ..., n - 1, where

f(ti, yi) = tiyi

= (0)(yi)

= 0, for i = 0, 1, 2, ..., n - 1.

Hence, we have:

y0 = y(0) = 1, and

y1 = y0 + h * f(t0, y0)

= y0 + h * 0

= 1 + 0

= 1

Therefore, the Euler approximation of y(1) using a step-size h = 0.5 is: y(1) ≈ y1 = 1. Therefore, y(1) ≈ 1. The exact solution of the given initial value problem is: y(t) = 1, and thus y(1) = 1. The Euler approximation of y(1) using a step-size h = 0.5 is: y(1) ≈ 1.

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The diameter of one circle is 28 units

Find the diagram shown below:

Considering the semi-circle at the centre.

To get the value of "x"

x + 16  = 22

x = 22 - 16

x = 6

To get the value of "x"

16 +y  = 22

y = 22 - 16

y = 6

Diameter of one of the circle = x + 16 + y

Diameter of one of the circle = 6 + 16 + 6

Diameter of one of the circle = 28

Hence the diameter of one circle is 28 units

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Answer:PR = 64; m∠2 = 63°; m∠RSI = 54°

because GRIP is a rectangle

=>PR = GI = 2PS

<=> 10x + 4 = 2.(6x - 4)

<=> 10x + 4 = 12x - 8

<=> 2x = 12

<=> x = 6

because PR = GI => PR = 10x + 4 = 10.6 + 4 = 64

GRIP is a rectangle => PS = SI

=> ΔPSI is a isosceles triangle

=> m∠1 = m∠2

but m∠2 + m∠3 = 90°

=> m∠1 + m∠3 = 90°

<=> 2y + 7 + 6y + 3 = 90

<=> 8y + 10 = 90

<=> 8y = 80

<=> y = 10

with y = 10 => m∠2 = 2.10 + 7 = 27

we also have: RS = SI

=> ΔRSI is a isosceles triangle

=> m∠3 = m∠4 = 90° - 27° = 63°

=> m∠RSI = 180° - 63°.2 = 54°

Step-by-step explanation:

Answer:

hope this helps

Step-by-step explanation:

6.1 represent the lbs that a child gains every x years

10 represents the starting weight of a newborn

we have that

A quadratic equation that will have a solution of only x = 0 is given by the equation

By considering the given information that angles 21 and 23 are supplementary and analyzing the properties of supplementary angles and parallel lines, we have proven that segment HI is parallel to segment JK.

To prove that segment HI is parallel to segment JK based on the given information that angles 21 and 23 are supplementary, we can utilize the properties of supplementary angles and parallel lines.

First, let's examine the given figure and information.

We have a capital letter A with serifs, where segment HI represents one of the serifs, and segment JK represents a horizontal line within the letter A.

To begin the proof, we'll make use of the fact that angles 21 and 23 are supplementary.

Supplementary angles are defined as two angles whose measures sum up to 180 degrees.

We can observe that angle 21 is an interior angle of triangle AHI, and angle 23 is an interior angle of triangle AJK.

Since angles 21 and 23 are supplementary, their sum is equal to 180 degrees.

Now, let's assume that segments HI and JK are not parallel.

In this case, if we extend lines HA and JA, they will eventually intersect at point P.

Since the angles formed at the point of intersection are supplementary (angle 21 + angle 23 = 180 degrees), it would imply that angle 21 and angle PJK, as well as angle 23 and angle PHI, are also supplementary.

However, this leads to a contradiction. In the original figure, we can observe that angle 21 and angle PJK do not form a supplementary pair since angle PJK is a right angle (90 degrees) in the letter A.

Therefore, our assumption that segments HI and JK are not parallel must be incorrect.

Consequently, we can conclude that segment HI is indeed parallel to segment JK.

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The indefinite integral of  ∫3(ex−e^−x)^2dx  is  (3/2)e^2x - 6e^x - (3/2)e^(-2x) + C.

To find the indefinite integral of the function ∫3(ex−e^−x)^2dx, we can use symbolic integration techniques.

Let's start by expanding the squared term inside the integral:

∫3(ex−e^−x)^2dx = ∫3(e^2x - 2ex*e^(-x) + e^(-2x))dx

Now, we can distribute the constant factor of 3 to each term inside the integral:

∫3(e^2x - 2exe^(-x) + e^(-2x))dx = 3∫e^2xdx - 3∫2exe^(-x)dx + 3∫e^(-2x)dx

Using the power rule for integration, we can integrate each term separately:

∫e^2xdx = (1/2)e^2x + C1

∫2exe^(-x)dx = 2∫exe^(-x)dx = 2e^x + C2

∫e^(-2x)dx = (-1/2)e^(-2x) + C3

where C1, C2, and C3 are constants of integration.

Now, substituting the results back into the original equation, we have:

∫3(ex−e^−x)^2dx = 3((1/2)e^2x + C1) - 3(2e^x + C2) + 3((-1/2)e^(-2x) + C3)

Simplifying further:

∫3(ex−e^−x)^2dx = (3/2)e^2x - 6e^x - (3/2)e^(-2x) + 3C1 - 3C2 + 3C3

Finally, we can combine the constants of integration into a single constant C:

∫3(ex−e^−x)^2dx = (3/2)e^2x - 6e^x - (3/2)e^(-2x) + C

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Erika has 6.53 kilograms of apples, which is more than the 6 kilograms she needed for the recipe. Therefore, she has enough apples to make the recipe.

To determine if Erika has at least 6 kilograms of apples, we need to add the weight of all three bags of apples. The total weight of the apples is:

2.56 kg + 1.18 kg + 2.79 kg = 6.53 kg

Erika needs a certain amount of apples for a recipe, specifically 6 kilograms. She goes to the store and picks three different bags of apples - a 2.56-kilogram bag of red apples, a 1.18-kilogram bag of green apples, and a 2.79-kilogram bag of yellow apples. To determine if she has enough apples, she needs to add the weight of all three bags. The total weight of the apples comes out to be 6.53 kilograms. This means that Erika has more than the required 6 kilograms of apples and is sufficient to make the recipe. It's important to note that Erika has an excess of apples, which can be helpful in case she needs extra for the recipe or for future use. The combination of different types of apples can also add variety and flavor to the recipe.

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Formular for total surface area of a cylinder

S = 1231.5 sq ft

To determine which differential equation(s) are linear, we need to examine the form of each equation. A linear differential equation is one that can be written in the form a(x)y" + b(x)y' + c(x)y = g(x), where a(x), b(x), c(x), and g(x) are functions of x.

The differential equation 2xy" - 5xy' + y = sin(3x) is linear. It can be written in the form a(x)y" + b(x)y' + c(x)y = g(x), where a(x) = 2x, b(x) = -5x, c(x) = 1, and g(x) = sin(3x).
The differential equation (v)² + xy = In(x) is not linear. It does not follow the form a(x)y" + b(x)y' + c(x)y = g(x) because it contains a term with (v)², where v represents the derivative of y with respect to x. This term does not have a linear coefficient.
The differential equation y' + sin(y) = e^(3x) is linear. It can be written in the form a(x)y' + b(x)y = g(x), where a(x) = 1, b(x) = sin(y), and g(x) = e^(3x).
The differential equation (x²+1)y" - 3y - 2x³y = -x - 9 is not linear. It does not follow the form a(x)y" + b(x)y' + c(x)y = g(x) because it contains a term with (x²+1)y", where the coefficient is a function of x.
The differential equation y' + xy = y" is linear. It can be written in the form a(x)y' + b(x)y = g(x), where a(x) = 1, b(x) = x, and g(x) = y".

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Answer:

In technical terms, the slope of the line is the change in y over the change in x. But I just like to think of it as rise over run. To find the slope of the line, pick two points on the line

Answer:

C. 2x^2 + 3x - 1

is the answer

Answer:

10 times.

Step-by-step explanation:

The number in the tenths place is 90. The number in the ones place is 9. 9 times 10 is 90.

Answer:

lowest but make sure to keep the highest in your mind and keep working. you've got this! :)

Answer:

the lowest grade. But also stay on top of ur assignments on the subject u have the lowest grade on because u will fall back behind. this also goes for ur other higher grades. try to spend one hour in each assignments that is past due.

Lana paid $40.8

Explanation

you can easily solve this by using a rule of three.

Step 1

if the jacket was on sale for 15 off, then Lana paid :

85 % of the original price

Step 2

Let

x represents the value for the 85%

if

then

the proportion is the same, then

solve for x

Hence

Lana paid $40.8

Answer:

get y by itself and simplify

y=3/2x +7

Answer:

What in the world is this even for?

Answer:

a

Step-by-step explanation:

the graphic is step by step

Answer:

A

Step-by-step explanation:

Since the first number to the problem is -4, you start at -4 on the number line. The next number is +7.5 so you would move 7.5 spaces to the right on your number line. Finally, where you land would be your answer.

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