after i stops my lexus engine, the warning sign appears when open door, but off when close the door, why?

The circuit has a constant gain of 1 for high frequencies, implying that it acts as a low-pass filter. To find the frequency response function H(w) for the given circuit, we need to determine the transfer function H(w) = V0(w) / Vi(w), where V0(w) is the output voltage and Vi(w) is the input voltage in the frequency domain.

L = 1 H (inductance)

R = 3.9 KΩ (resistance)

The circuit can be represented by the following equation:

H(w) = (jwL + R) / (jwL + R + 1)

To sketch the magnitude of the frequency response function H(w), we need to plot the magnitude |H(w)| as a function of frequency w.

Taking the magnitude of the transfer function, we have:

|H(w)| = |(jwL + R) / (jwL + R + 1)|

Next, let's analyze the type of ideal filter approximated by this circuit. We can examine the transfer function to determine the filter characteristics.

From the transfer function:

H(w) = (jwL + R) / (jwL + R + 1)

As w approaches infinity, the jwL term dominates the transfer function, and the transfer function becomes:

H(w) ≈ jwL / jwL = 1

This indicates that the circuit has a constant gain of 1 for high frequencies, implying that it acts as a low-pass filter. It allows low-frequency signals to pass through relatively unattenuated while attenuating high-frequency signals.

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Larry Crabb, a Christian author and counselor, has a view of the two books, God's Word and God's Works. He believes that both books are revelations of God and that they should be studied together in order to gain a fuller understanding of Him.

Crabb argues that God's Word is a revelation of God's character and nature. It tells us who He is and what He is like. God's Works, on the other hand, are a revelation of God's power and love. They show us what He can do and what He is willing to do for us.

Crabb believes that we should study both books in order to gain a balanced understanding of God. He says that "the Bible is not enough, but it is essential." We need to study God's Word in order to learn about His character and nature, but we also need to study God's Works in order to see His power and love in action.

Crabb's view of the two books is a helpful reminder that God is not just a distant being who is far removed from our lives. He is a personal God who is involved in our world and who loves us deeply. By studying both God's Word and God's Works, we can come to know Him better and grow in our relationship with Him.

Here are some of the benefits of studying God's Word and God's Works together:

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The time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

The cooling law is given by:

$$\frac{dQ}{dt}=-k(T-T_0)$$

where Q is the heat in the object, t is the time taken, T is the temperature of the object at time t, T0 is the temperature of the environment and k is a constant known as the cooling constant.

We need to find the time it takes for the coffee to reach a drinking temperature of 73°C given that its initial temperature is 93°C.

Therefore, we need to find the time it takes for the coffee to cool down from 93°C to 73°C when placed in a room temperature of 18°C.

Let’s assume that the heat energy that is lost by the coffee is equal to the heat energy gained by the environment. We can express this as:

dQ = - dQ where dQ is the heat energy gained by the environment.

We can substitute dQ with C(T-T0) where C is the specific heat capacity of the object.

We can rearrange the equation as follows:

$$-\frac{dQ}{dt}=k(T-T_0)$$

$$-\frac{d}{dt}C(T-T_0)=k(T-T_0)$$

$$\frac{d}{dt}T=-k(T-T_0)$$

The differential equation above can be solved using separation of variables as follows:

$$\frac{d}{dt}\ln(T-T_0)=-k$$

$$\ln(T-T_0)=-kt+c_1$$

$$T-T_0=e^{-kt+c_1}$$

$$T=T_0+Ce^{-kt}$$

where C = e^(c1).

We can now use the values given to find the specific value of C which is the temperature difference when t=0, that is, the temperature difference between the initial temperature of the coffee and the room temperature.

$$T=T_0+Ce^{-kt}$$

$$73=18+C\cdot e^{-0.09t}$$

$$55=C\cdot e^{-0.09t}$$

$$C=55e^{0.09t}$$

$$T=18+55e^{0.09t}$$

We can now solve for the value of t when T=93 as follows:

$$93=18+55e^{0.09t}$$

$$e^{0.09t}=\frac{93-18}{55}$$

$$e^{0.09t}=1.3636$$

$$t=\frac{\ln(1.3636)}{0.09}$$

Using a calculator, we can find that the time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

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Productivity increases when inputs decrease while outputs remain the same (option C).

Productivity refers to the efficiency and effectiveness of producing goods or services. It is a measure of how much output is generated per unit of input. When productivity increases, it means that more output is being produced with the same amount of input or resources.

In option C, inputs decrease while outputs remain the same. This implies that the same level of output is achieved with fewer resources or inputs. This indicates an improvement in efficiency and productivity. By reducing inputs while maintaining the same output level, a business can optimize its resource utilization and achieve higher productivity.

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One unusual aspect of asteroid Bennu compared to larger asteroids is its extremely rough and rocky surface. This is due to its small size (only about 500 meters in diameter), which means it doesn't have enough gravity to smooth out the boulders and rocks that make up its surface.

Additionally, Bennu has a very low density, which suggests that it is made up of porous materials rather than solid rock like larger asteroids. This unique composition makes Bennu an interesting target for scientific study and exploration.

Asteroid Bennu is unusual compared to larger asteroids primarily due to its relatively small size, rapid rotation, and its potential Earth impact hazard. While larger asteroids may have more stable rotation rates and less chance of Earth impact, Bennu's smaller size makes it more susceptible to the Yarkovsky effect, which alters its orbit due to the way it absorbs and re-emits sunlight as thermal radiation.

This effect, along with its rapid rotation, increases the probability of a future Earth impact, making it a point of interest for scientists and researchers.

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0.566 kilograms of water is vaporized and it can be calculated by dividing the total heat added by the latent heat of vaporization.

To determine the amount of water vaporized, we need to use the formula:

Q = m * Lv,

where Q is the total heat added, m is the mass of water, and Lv is the latent heat of vaporization. Rearranging the formula, we get:

m = Q / Lv.

Given that\(Lv = 2.26 * 10^6 J/kg\) and Q = 1,278,900 J, we can substitute these values into the formula to find the mass:

\(m = 1,278,900 J / (2.26 *10^6 J/kg) = 0.566 kg.\)

Therefore, 0.566 kilograms of water at 100.0\(^0C\) can be vaporized when 1,278,900 Joules of heat are added to it.

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Skater X travels to the left, and the center of mass of the system travels to the right, option A is correct.

The two-skater system has an initial momentum of zero before the push. After the push, the system will have a nonzero momentum to the right due to Skater Y's velocity. However, the total momentum of the system must still be conserved.

Let's use the law of conservation of momentum to determine the direction of the velocity of Skater X and the direction of the velocity of the center of mass of the system after the push.

Conservation of momentum:

initial momentum = final momentum

\(0 = m_Xv_X + m_Yv_Y\)

where \(m_X\) and \(m_Y\) are the masses of Skater X and Skater Y, respectively, \(v_X\) is the velocity of Skater X after the push, and \(v_Y\) is the velocity of Skater Y after the push.

We know that Skater Y travels with a speed of \(2v_0\) to the right after the push, so

\(v_Y = 2v_0\).

Solving for \(v_X\), we get:

\(v_X\) = \(-(m_Y\) ÷ \(m_X)\) × \(v_Y\)

Since \(m_Y > m_X\), \(v_X\) will be negative, meaning Skater X will travel to the left. This eliminates options C and D.

Now, let's consider the direction of the velocity of the center of mass of the system. The velocity of the center of mass is given by:

\(v_{CM} = (m_Xv_X + m_Yv_Y)\) ÷ \((m_X + m_Y)\)

\(v_{CM} = (m_Y\) ÷ \(m_X)\) × \(v_Y\) ÷ \((m_X + m_Y)\)

Since \(m_Y > m_X, m_Y/m_X > 1\), and \(v_Y\) is positive, \(v_{CM}\) must be positive as well, meaning the center of mass travels to the right. This eliminates option B.

Hence, option A is correct.

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The complete question is:

Two ice skaters, Skater X and Skater Y, are at rest on a horizontal surface made of ice. The friction between the ice and the skaters is negligible. Skater X, who has a smaller mass than Skater Y, pushes Skater Y such that Skater Y travels with a speed of \(2v_0\). to the right. Which of the following indicates the direction of the velocity of Skater X and the direction of the velocity of the center of mass of the two-skater system after the push?

A. Skater X To the left; Center of Mass To the right

B. Skater X To the left; Center of Mass Zero

C. Skater X Zero; Center of Mass To the right

D. Skater X Zero; Center of Mass Zero

Given that, 1 Liter equals 1.0567 quartz and 1 quartz equals 32 oz, the volume 1.00 oz equals 0.02957 L.

Given that;

First, we convert 1.00 oz to qt

32 oz = 1 qt

1.00 oz = x

x = 1.00 / 32

x = 0.03125 qt

Now, we convert 0.03125 qt to liter

1.0567 qt = 1 L

0.03125 qt = x

x = 0.03125 / 1.0567

x = 0.02957 L

Given that, 1 Liter equals 1.0567 quartz and 1 quartz equals 32 oz, the volume 1.00 oz equals 0.02957 L.

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The two variables that are multiplied together to calculate weight are mass and acceleration due to gravity.

Weight is a measure of the force exerted on an object due to gravity. It is calculated by multiplying two variables: mass and acceleration due to gravity. Mass refers to the amount of matter contained in an object, while acceleration due to gravity represents the gravitational force acting on the object. The formula for calculating weight is weight = mass x acceleration due to gravity. The mass of an object determines its inertia and is usually measured in kilograms, while the acceleration due to gravity is a constant value that depends on the location and is approximately 9.8 meters per second squared on Earth. By multiplying these two variables, we can determine the force of gravity acting on an object, which we commonly refer to as its weight.

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Answer:

Magnitude of frictional force = 30 N

Explanation:

According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:

Fn=m.a

The net force is the vector addition of each individual force. If the sum of all the forces acting on an object is zero, then the acceleration is zero. That means the object moves at a constant speed or is at rest.

When an object is pushed across a horizontal rough surface, there are two forces acting in the direction of the motion: The applied force and the frictional force.

If the applied force is greater than the frictional force, then the object moves at a constant positive acceleration. If the frictional force is greater than the applied force, then the object won't move at all (if it was at rest) or will start a deaccelerated motion (braking).

Finally, if both forces are equal, the object will move at a constant speed or remains at rest. Since the box is moving at a constant speed, we can conclude the frictional force equals the applied force:

Magnitude of frictional force = 30 N

To give a long answer to your question, the specific heat capacity of a substance is the amount of heat energy required to raise the temperature of one gram of the substance by one degree Celsius. Therefore, a substance with a high specific heat capacity requires a lot of heat energy to raise its temperature by one degree Celsius, while a substance with a low specific heat capacity requires relatively less heat energy to achieve the same temperature increase.

Now, coming to your specific question, a substance that cools off quickly would have a low specific heat capacity. This is because a substance with a high specific heat capacity would require a lot of heat energy to raise its temperature, and once heated, it would also take longer to cool down. On the other hand, a substance with a low specific heat capacity would require relatively less heat energy to raise its temperature and would cool off quickly once the source of heat is removed.

To summarize, the specific heat capacity of a substance determines how quickly it can absorb or release heat energy. A substance with a low specific heat capacity cools off quickly, while a substance with a high specific heat capacity takes longer to cool down.

A substance that cools off quickly has a low specific heat capacity. This means it requires less energy to change its temperature, causing it to heat up or cool down faster compared to a substance with a high specific heat capacity.

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Answer:

I. Vs = 8.0 Volts.

II. Is = 4.5 Amperes.

Explanation:

Given the following data;

Np = 1.5Ns = \( \frac {N_{P}}{N_{S}} = 1.5 \)  ..... equation 1

Ip = 3.0 A

Vp = 12 V

To find the voltage and current on the secondary coil;

I. For the voltage in the secondary coil (Vs), we would use the following formula;

\( \frac {V_{P}}{V_{S}} = \frac {N_{P}}{N_{S}} \)  ...... equation 2.

Substituting eqn 1 into eqn 2, we have;

\( \frac {V_{P}}{V_{S}} = 1.5 \)

\( \frac {12}{V_{S}} = 1.5 \)

Cross-multiplying, we have;

\( V_{S} * 1.5 = 12 \)

\( V_{S} = \frac {12}{1.5} \)

Vs = 8.0 V

II. For the current in the secondary coil (Is), we would use the following formula;

\( \frac {I_{S}}{I_{P}} = \frac {N_{P}}{N_{S}} \)  .... equation 3

Substituting eqn 1 into eqn 3, we have;

\( \frac {I_{S}}{I_{P}} = 1.5 \)

\( \frac {I_{S}}{3.0} = 1.5 \)

Cross-multiplying, we have;

\( I_{S} = 1.5 * 3.0 \)

Is = 4.5 A

The models of the universe allow finding the result for how serious the universe in the distant future is:

The Big Bang model shows that the universe was created at a certain point and time where from which all matter is separating at a speed from these objects.

Based on these models and the measurements that the galaxies are moving away, in the distant future the galaxies must be very far from each other so that the universe would be composed of isolated entities without the possibility of interaction between them.

Within each galaxy the bodies are not separated because in each one there is a black body whose gravity holds the stars within its galaxy together.

In conclusion of the models of the universe we can find the result for how serious the universe in the distant future is:

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Given that a car and a train each make a trip that is 120 km and the average speed of a train is 40 km/h faster than a car. We need to find the average speed of the car.Let the average speed of a car be x km/hour.So the average speed of the train is (x + 40) km/hour. According to the question, time taken by the train is 30 minutes less than the car, so time taken by the car is:

t = d/swhere t = time taken, d = distance covered, and s = speed of the carThe time taken by the train is:t - 0.5h = d/(x + 40)Here, 0.5 hour is equal to 30 minutes.Now, both the car and the train covered the same distance. Hence we have:t = d/xUsing the formulae for t in both equations, we have:d/x - 0.5 = d/(x + 40)Cross-multiplying the above equation, we get:d(x + 40) - 0.5x(x + 40) = dxSimplifying the above expression, we get:x² - 80x - 2400 = 0We can solve the above quadratic equation to get the values of x.

Using the main answer, the average speed of the car is 60 km/h.The explanation to find the average speed of the car:Given, a car and a train each make a trip that is 120 km. Let the average speed of a car be x km/h. Therefore, the average speed of the train is (x + 40) km/hour.The time taken by the train is t - 0.5h = d/(x + 40).Using the formulae for t in both equations, we have:d/x - 0.5 = d/(x + 40)Cross-multiplying the above equation, we get:d(x + 40) - 0.5x(x + 40) = dxSimplifying the above expression, we get:x² - 80x - 2400 = 0We can solve the above quadratic equation to get the values of x.Using the main answer, the average speed of the car is 60 km/h.

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Answer:

The person can jump 48 m on the Moon

Explanation:

The question parameters are;

The maximum long jump distance of a person on Earth, \(R_{max}\) = 3 m

The acceleration due to gravity on the Moon = 1 ÷ 16 of that on Earth

The distance the person can jump on the Moon is given as follows;

A person performing a jump across an horizontal distance on Earth (under gravitational force) follows the path of the motion of a projectile

The horizontal range, \(R_{max}\), of a projectile motion is found by using the following formula

\(R_{max} = \dfrac{u^2}{g}\)

Where;

g = The acceleration due to gravity = 9.8 m/s²

Therefore, we have;

\(R_{max} = 3 \, m = \dfrac{u^2}{9.8 \, m/s^2 }\)

u² = 3 m × 9.8 m/s² = 29.4 m²/s²

Therefore, on the Moon, we have;

The acceleration due to gravity on the Moon, \(g_{Moon}\) = 1/16 × g

∴ \(g_{Moon}\) = 1/16 × g = 1/16 × 9.8 m/s² ≈ 0.6125 m/s²

\(R_{max \ Moon} = \dfrac{u^2}{g_{Moon}} = \dfrac{29.4 \ m^2/s^2}{0.6125 \, m/s^2 } \approx 48 \, m\)

The maximum distance the person can jump on the Moon with the same velocity which was used on Earth is \(R_{max \ Moon}\) ≈ 48 m

Answer:

c. eco

ya que hay trasmisión de energía de un lado al hacer ecos

The linear expansivity of brass of length 120 m that assumed a new length of 120.05 m when heated to a temperature 100° c​ is 4.167.10⁻¹⁶ 1/K.

Linear expansivity is the ratio of the length increase of a solid specimen to the temperature change. The expansivity (α) of a specimen is given by the formula l2 = l1(1 +), where l1 is the length of the specimen, and l2 is the length of the specimen when the temperature increases by °.

The linear expansion coefficient can be written in SI units as either °C-1 or °K-1. C in this context stands for Celsius, and K for Kelvin. M0L0T0K1 will be the size of the linear expansion coefficient.

Modifying or lengthening is referred to as expansion. When one dimension (length) changes in length in relation to the volume, this is referred to as linear expansion.

When the temperature rises by one degree, a solid's linear expansivity increases by a fractional amount.

calculate the linear expansivity of brass of length 120 m ?

Assuming the temperature change is 100°C.

       α=L−L0/L0- ΔT⇒(1)  Δ Greek value is 4

Given L=120

L0=120.05

T=100°c

 substitute the given values in equation 1 we have

        α=120-120.5/120.05-4(100)

           =4.167.10⁻¹⁶ 1/K

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Answer:

The conservation of momentum and impulse are  the physics principle of the measure the force of the heart's contraction    

The momentum is defined as the product of the mass of the body by its speed. If we make the system isolated, the moment or quantity of movement must be conserved since there are external forces.

                P = mv

               Δp = p_f - p₀

Where p is the momentum, m and v the mass and velocity of the body

In this case we consider the body as an isolated system and if it is immobile, zero velocity, the initial momentum is zero

               p₀ = 0

When the heart pumps the room it goes out in one direction and the body recoils in the opposite direction, so the final momentum is

              p_f = m v₁ - (M-m) v₂

Where m is the amount of blood pumped, (M-m) the remaining mass of the body, v₁ and v₂ the velocity of the blood and the body

If the body is isolated, the momentum will be preserved

               p_f = p₀

               m v₁ - (M-m) v₂ = 0

               v₁ = \(\frac{M-m}{m} \ v_2\)

The To measure the force of the contraction of the heart we use that the impulse is equal to the variation of the momentum

                 I_ {avg} = F t = ΔP

                  F = \(\frac{\Delta p}{t}\)

Where t is the time and is measured with a stopwatch with the pulsations of each patient.

                  F = \(\frac{m \ v_1 - (M-m) \ v_2 }{t}\)

The construction of a system for the measurement must consist of spring or some means of oscillation and use the movement to measure the recoil speed of the patient which is small.

In conclusion, we use the conservation of momentum and impulse are the  physics principle of the measure the force of the heart's contraction    .

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Explanation:

A machine is a device that does work. Most machines consist of a number of elements, such as gears and ball bearings, that work together in a complex way. Nonetheless, no matter how complex they are, all machines are based in some way on six types of simple machines. These six types of machines are the lever, the wheel and axle, the pulley, the inclined plane, the wedge, and the screw.

Velocity of the arrow while leaving the bow is 33.54 m/s.

Kinetic energy is the energy that an object has when it is in motion. If you want to accelerate an object you have to apply a force. To add strength, we need our work. When the work is done, the energy is transferred to the object and it moves at a new constant speed.

Energy stored in the string = Kinetic energy of the arrow.

1/2(ke²) = 1/2(mv²)

Where k = spring constant of the bowstring

e = extension

m = mass of the arrow

v = velocity of the arrow.

Let's make v the subject of this equation

v = √(ke²/m)

Given: k = 1250 N/m

e = 30 cm or 0.3 m

m = 100 g or 0.1 kg

Substitute the values into the equation:

v = √(1250×0.30²/0.1)

v = √(1125)

v = 33.54 m/s

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Answer:b

Explanation:

A steel ball, a magnet, and a piece of paper are used in an activity by a pupil. The ball is under the influence of the magnet. Therefore, choice A is right.

When electric charges move, a phenomenon known as magnetism is produced. These tiny movements can occasionally be found inside a material known as magnets. Magnets and the magnetic fields created by moving electric charges can attract or repel other magnets, which can also change how other charged particles move.

Because they can support a magnetic field that lasts forever, some materials, like iron, are categorized as permanent magnets. These are the magnets that are typically encountered in day-to-day life. Other materials like iron, cobalt, and nickel can be briefly given a magnetic field when placed inside a stronger, bigger magnetic field, but they will eventually lose their magnetic qualities.

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The term used to describe the energy of a system that is available to do work is free energy.

Free energy is the energy that is available in a particular chemical system to do useful work.

The Gibbs free energy denoted by G is the enthalpy of a system minus the product of its entropy and absolute temperature.

It is referred to as free because the energy is readily available anytime. Free energy is measured in kilojoules per mole (KJ/mol).

Therefore, it can be said that the term used to describe the energy of a system that is available to do work is free energy.

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The ratio of the photon rate is 0.124.

The photon rate of a source is given by the formula:

r = P / E

where r is the photon rate, P is the power of the source, and E is the energy per photon. The energy per photon is given by the formula:

E = hc / λ

where h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon.

For the first source:

E1 = hc / λ1

    = (6.626 x 10⁻³⁴ J s) x (3.00 x 10⁸ m/s) / (525 x 10⁻⁹ m)

    = 3.79 x 10⁻¹⁹ J

r1 = P1 / E1

   = (1 x 10⁻³ W) / (3.79 x 10⁻¹⁹ J)

   = 2.64 x 10¹⁵ photons/s

For the second source:

E2 = hc / λ2

     = (6.626 x 10⁻³⁴ J s) x (3.00 x 10⁸ m/s) / (1050 x 10⁻⁹ m)

     = 1.88 x 10⁻¹⁹ J

r2 = P2 / E2

   = (4 x 10⁻³ W) / (1.88 x 10⁻¹⁹ J)

   = 2.13 x 10¹⁶ photons/s

As a result, the photon rate ratio is:

r1/r2 = (2.64 x 10¹⁵ photons/s) / (2.13 x 10¹⁶ photons/s)

        = 0.124

The ratio of photon rates is approximately 0.124. This indicates that the second source, with a higher power and shorter wavelength, produces significantly more photons per second compared to the first source. The ratio can be used to compare the brightness or intensity of the two sources, assuming that the detectors used to measure the photon rate are equally sensitive to both wavelengths.

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ANSWERS

a. 635.26 Hz

b. 673.23 Hz

c. 597.87 Hz

d. 562.14 Hz

EXPLANATION

a. In this case, the source is the train moving toward the station. The frequency of the source, fs = 616 Hz, the velocity of the source is vs = 10.4 m/s. The "observer" is the people in the station and we can assume that they are at rest, so the velocity of the observer, vo, is 0 m/s.

We have to find what is the frequency that the observer gets,

In this formula, v represents the velocity of sound, v = 343 m/s.

The frequency heard by the observer is,

Hence, a frequency of 635.26 Hz is heard at the station.

b. This is a different case because the observer is now another train, moving toward the station in the opposite direction - which means that the observer is moving toward the source, and it does it at 20.5 m/s. We also have to find the frequency heard by the observer,

Replace with the known values: v = 343 m/s, vo = 20.5 m/s, vs = 10.4 m/s, fs = 616 Hz,

Hence, the other train hears a frequency of 673.23 Hz

c. Now the velocity and frequency of the source are the same, but instead of moving toward the observer, it is moving away from it. The equation changes to,

Hence, the frequency heard at the station will be 597.87 Hz.

d. Again, this case is similar to part b, but in this case, the source and the observer are both moving away from each other, so the equation changes to,

Hence, the other train will hear a frequency of 562.14 Hz.

The index of refraction for the cubic zirconia at the given speed of light is 2.16.

The given parameters:

The index of refraction for the cubic zirconia is the ratio of the speed of light in air to speed of light in cubic zirconia and it is calculated as follows;

\(\eta = \frac{c}{v} \\\\\eta = \frac{3\times 10^8}{1.39 \times 10^8} \\\\\eta = 2.16\)

Thus, the index of refraction for the cubic zirconia at the given speed of light is 2.16.

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Answer:

the correct one is D

Explanation:

A question that can be answered with a scientific investigation must be a question where measurements of some kind can be made and with these measurements check that the question is correct or not.

When examining the  answers the correct one is D

'''In a series circuit, the sum of the voltages consumed by each individual resistance is equal to the source voltage. Components connected in parallel are connected along multiple paths so that the current can split up; the same voltage is applied to each component.''

Initial velocity,u = 26 m/s

Final velocity,v = 18 m/s

Acceleration,a = -2 m/s²

Calculate the time take by a body.

According to the first equation of motion:

\( \bf \: v = u + at\)

★ Substituting the values in the above formula,we get:

\( \sf\implies18 = 26 + ( - 2) \times t\)

\( \sf \implies18 = 26 - 2t\)

\( \sf \implies \: 2t = 26 - 18\)

\( \sf \implies \: 2t = 8\)

\( \sf \implies \: t = \cancel\dfrac{8}{2} \)

\( \sf \implies \: t = 4 \: sec\)

Acceleration is the rate of change in velocity. Here, the change in velocity is 8 m/s and the acceleration is  - 2 m/s². The time taken to change the velocity is thus, 4 seconds.

Acceleration is the ratio of the change in velocity to the change in time. Acceleration is a vector quantity having both magnitude and direction. The change in direction or magnitude of velocity makes an acceleration on the object.

The relation between acceleration, velocity and time is given by the expression:

v = u  + at

where, v is the final velocity and u be the initial velocity. a and t be the acceleration and time.

Given that, final velocity = 18 m/s

initial velocity = 26 m/s

acceleration =  - 2 m/s²

then t = ( v - u ) / a

          = (18 - 26 m/s) / -2 m/s²

          = 4 s

Therefore, the time taken  for the vehicle to slow down is 4 seconds.

To refer more on acceleration, refer here:

https://brainly.com/question/3046924

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Answer:

0.84m

Explanation:

0.51+0.43=0.93

πr can be 22/7 or 3.14

radius is 2x2= 4

3.14 divide0.93divide 4

=0.84m/s

Answer:

0.605 m (approx.)

Explanation:

We know, given the radius and the circular velocity we can yield the centripetal acceleration using this equation,

\(a = \frac{v^2}{r}\)

From this equation, we can solve for \($r$\) like this,

\(r = \frac{v^2}{a}\\r = \frac{0.51^2}{0.43} m \\ = 0.605 m\)