Acquisition rate is a measure of the:1. A) percentage of visitors who indicate an interest in a site's products by registering or visiting a product's pages. 2. B) percentage of visitors who become customers. 3. C) percentage of existing customers who continue to buy on a regular basis. 4. D) percentage of shoppers who do not return within a year after their initial purchase.

Answer:

The thickness of the oil reservoir is 10cm, the production rate of oil is 100m3, the well radius is 10cm, the permeability of the reservoir is 1um2, the porosity is 0.2, the viscosity of the oil is 4mPa.s, the density of oil is 850kg/m3. If the flow regime can be considered as linear flow, can this flow in the reservoir satisfy Darcy's

Answer:

a la 1/s^2(s + 10)

Explanation:

I got it right on math lab

Answer:

The resistance of the flow of charges in an electric circuit (electrical resistance) is analogous to the frictional effect between water flow through a pipe and the pipe's surface

Explanation:

In comparison to its similarity to the diameter of the pipe affects the flow of water and acts a a factor affecting resistance so are there factors affecting electrical resistance.

in an electrical circuit:

the total length of the wire is to the length of a pipe of water

the cross-sectional area of the wire is to the diameter of a pipe of water.

Thus, the cross sectional are affects the amount of electrical resistance. Wider wires have wider cross-sectional area and vice versa. Also, water will flow (i.e. current) through a wider pipe (i.e. large diameter) at a faster rate than a narrow pipe (i.e. small diameter). This is due to the lower amount of resistance offered by the wider pipe.

in the same manner, the wider the wire, the lesser the electrical resistance to the flow of elsctric charge and vice versa for thiner wires.

0.810 mm² and 0.90 mm is  the sample variance and sample standard deviation, 2.18 mm is the sample mean, given below Each dot represents an observation and their position on the number line represents their corresponding value. This type of diagram allows us to see the distribution of the data and identify any outliers.

To ensure aircraft safety, preventing fatigue crack propagation is crucial. In an engineering study focused on this issue, the lengths of fatigue cracks in 9 cyclically loaded wing boxes were measured. The recorded lengths, in mm, were as follows: 2.13, 2.96, 3.02, 1.82, 1.15, 1.37, 2.04, 2.47, and 2.60.
To analyze this data, we need to calculate some statistical measures.
(a) To determine the sample mean, we add up all the crack lengths and divide by the sample size:
Mean = (2.13 + 2.96 + 3.02 + 1.82 + 1.15 + 1.37 + 2.04 + 2.47 + 2.60) / 9 = 2.18 mm
Therefore, the sample mean is 2.18 mm.
(b) To calculate the sample variance, we need to first calculate the deviation of each observation from the mean:
Deviation of 2.13 = 2.13 - 2.18 = -0.05
Deviation of 2.96 = 2.96 - 2.18 = 0.78
Deviation of 3.02 = 3.02 - 2.18 = 0.84
Deviation of 1.82 = 1.82 - 2.18 = -0.36
Deviation of 1.15 = 1.15 - 2.18 = -1.03
Deviation of 1.37 = 1.37 - 2.18 = -0.81
Deviation of 2.04 = 2.04 - 2.18 = -0.14
Deviation of 2.47 = 2.47 - 2.18 = 0.29
Deviation of 2.60 = 2.60 - 2.18 = 0.42
Next, we square each deviation and add them up:
Variance = [(-0.05)² + (0.78)² + (0.84)² + (-0.36)² + (-1.03)² + (-0.81)² + (-0.14)² + (0.29)² + (0.42)²] / 8
Variance = 0.810 mm²
Finally, we can calculate the sample standard deviation as the square root of the variance:
Standard Deviation = √(0.810) = 0.90 mm
Therefore, the sample variance is 0.810 mm^2 and the sample standard deviation is 0.90 mm.
(c) To create a dot diagram, we simply plot each observation on a number line. Here is a dot diagram of the fatigue crack length data:
1.15 •
1.37 •
1.82 •
2.04 •
2.13 •
2.47 •
2.60 •
2.96 •
3.02 •
Each dot represents an observation and their position on the number line represents their corresponding value. This type of diagram allows us to see the distribution of the data and identify any outliers.

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This function will return the minimum value in the range of cells A2:A6.

Function is a self-contained block of code that is used to perform a particular task in a computer program. It is a set of instructions that can be called upon to perform a specific action. Functions are often used to break up a program into smaller, more manageable pieces that can be reused or combined with other functions to create more complex programs. Functions can also be used to simplify and shorten the length of a program, which makes it easier to read and debug. A function typically takes an input, performs a calculation or some type of action with that input, and then returns the result.

For finding the best manufacturing candidate based on minimum cost, we can use the MIN function. The MIN function returns the smallest numeric value in a set of values.

Syntax: =MIN(number1, [number2], ...)

Example: =MIN(A2:A6)

This function will return the minimum value in the range of cells A2:A6.

For finding the best shipping candidate based on minimum cost, we can use the MIN function in the same way. The syntax and example would be the same as above.

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Answer:

Fast Fourier ( FFT ) algorithms speed up computation of Fourier coefficients by simply reducing the the computing time of a traditional direct form  Fourier series. it  achieves this by breaking complex DFTS into smaller DFTS to reduce its complexity and in turn reduce its computing time

Explanation:

Fast Fourier ( FFT ) algorithms speed up computation of Fourier coefficients by simply reducing the the computing time of a traditional direct form  Fourier series. it  achieves this by breaking complex DFTS into smaller DFTS to reduce its complexity and in turn reduce its computing time. an example of such FFT is Cooley-Tukey algorithm

Answer:

\(\triangle h=4.935m\)

Explanation:

From the question we are told that:

Liquid density \(\rho=800\)

Diameter of pipe \(d=4cm \approx 0.004m\)

Diameter of venture \(d=10cm \approx 0.010m\)

Specific weight of mercury P_mg \(133 kN/m^3\)

Flow rate \(r=0.05 m^3/s\)

Area A:

            \(A_1=\frac{\pi}{4}0.1^2\\A_1=0.00785m^2\\A_2=\frac{\pi}{4}0.04^2\\A_2=0.001256m^2\\\)

Generally the Bernoulli's equation is mathematically given by

\(\frac{P_1}{\rho_1g}+\frac{V_1^2}{2g}=\frac{P_2}{\rho g}+\frac{V_2^2}{2g}\\\)

Where

\(V_1=\frac{r}{A_1} \\\\ &V_1=\frac{r}{A_2}\)

Therefore

\(P_1-P_2=\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})\)

Generally the equation for pressure difference b/w manometer fluid is given as

\(P_1-P_2=(p_mg-pg)\triangle h\)

Therefore

\((p_mg-pg)\triangle h=\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})\)

\(\triangle h=\frac{\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})}{(p_mg-pg)}\)

\(\triangle h=\frac{\frac{(800)(0.05)^2}{2}(\frac{(0.1)^2-(0.4)^2}{(0.1)^2(0.04)^2})}{(1.33*10^3-800*9.81)}\)

\(\triangle h=4.935m\)

Therefore elevation change is mathematically given by

\(\triangle h=4.935m\)

An engine starting system must crank or spin the engine until fuel ignites forces the pistons down and the engine begins to operate on its own power.

Engine is a machine that converts energy into mechanical work. It is a device that takes an energy source, such as electricity, fuel, or solar power, and converts it into a form of energy that can be used to drive a machine, such as a car, truck, boat, or generator. Engines are used in almost all forms of transportation, from cars and trucks to boats and planes. They are also used in many industrial and commercial applications, such as manufacturing, power generation, and construction. Engines are composed of a number of components, including cylinders, pistons, valves, and a crankshaft. The pistons in the cylinders move up and down, creating energy that is then converted into movement that drives the crankshaft and ultimately powers the machine. Engines are usually powered by gasoline, diesel, or other fuels, although some can use electricity or solar power. They come in many different sizes and configurations, and are found in a variety of vehicles, from cars and motorcycles to boats and plane.

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An engine starting system must crank or spin the engine until fuel Combustion forces the pistons down and the engine begins to operate on its own power.

Combustion is a chemical reaction in which a substance reacts quickly with oxygen and produces heat. The original substance is referred to as the fuel, and the source of oxygen is referred to as the oxidizer. The fuel can be solid, liquid, or gas, but it is usually a liquid for aeroplane propulsion. Similarly, the oxidizer could be a solid, liquid, or gas, but for aeroplanes, it is usually a gas (air). A solid fuel and oxidizer are used in model rockets.

New chemical substances are formed during combustion from the fuel and the oxidizer. These substances are referred to as exhaust. The majority of the exhaust is caused by chemical reactions between the fuel and oxygen.

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If a pilot-operated check valve (POC) does not check flow, you will see a. erratic actuator movement.

Pilot operated test valves paintings through permitting loose float from the inlet port via the opening port. Supplying a pilot strain to the pilot port permits float withinside the contrary direction. Air strain on pinnacle of the poppet meeting opens the seal permitting air to float freely.

An actuator fault is a form of failure affecting the machine inputs. Due to strange operation or fabric aging, actuator faults might also additionally arise withinside the machine. An actuator may be represented through additive and/or multiplicative fault.

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The term used to describe the study of designing machines and work settings to minimize injury and illness is ergonomics.

Ergonomics is the science of designing machines and work settings to fit the needs of the worker, taking into account their physical, cognitive, and psychological capabilities.

This includes designing machines and work settings to reduce the risk of injury or illness, and to improve comfort, safety, and efficiency.

Ergonomics also focuses on designing workstations, tools, and processes to be as ergonomically friendly as possible. This includes providing adjustable chairs, adjustable keyboards and mice, and making sure that tasks don't require the worker to be in the same position for extended periods of time.

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False. Fire extinguishing equipment cannot be frozen according to Ref. 213/91.

According to Ref. 213/91, fire extinguishing equipment cannot be frozen. Fire extinguishers are essential safety devices designed to combat fires effectively. They contain pressurized agents that are specifically formulated to extinguish different types of fires. Freezing temperatures can significantly impair the functionality of fire extinguishers and render them ineffective in emergency situations.

When fire extinguishing equipment freezes, several issues can arise. First, the contents of the extinguisher may expand as they freeze, potentially leading to ruptures or leaks in the container. This can cause the extinguisher to malfunction or become hazardous when used. Second, freezing temperatures can affect the performance of the extinguishing agent itself. Certain agents, such as water-based solutions, can solidify or lose their effectiveness when exposed to extreme cold.

It is crucial to store fire extinguishers in suitable environments that are above freezing temperatures. This ensures that the equipment remains in optimal condition and is ready for immediate use during emergencies. Regular inspections and maintenance are also essential to identify any signs of damage or deterioration that may compromise the functionality of fire extinguishers.

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Answer:

letter B

Explanation:

basta yan anwer

Answer:

using standardized parts

Explanation:

Answer:

A, D, F

Explanation:

took on edge.

Answer:

The answer is A,D,F

A:observing and interpreting readings on gauges, meters, and charts

D:testing boiler water quality or arranging for testing

F:operating or tending stationary engines, boilers, and auxiliary equipment

Explanation:

I got all right on edge.

Answer:

A) Power output = 541.67 MW

B) Backwork ratio = 0.4

C) Improved thermal efficiency = 0.598

Explanation:

We are given;

Net power output; W'_net = 325 MW

Minimum Temperature; T1 = 300 K

Maximum Temperature; T4 = 1500 K

Compression Pressure ratio;P2/P1 = 12

From online tables, we have the following properties of air;

Specific heat capacity; C_p = 1.004 KJ/Kg

Adiabatic constant; k = 1.4

Temperature at stage 2 will be given by the formula;

T2 = T1(P2/P1)^((k - 1)/k)

Plugging in the relevant values gives;

T2 = 300(12)^((1.4 - 1)/1.4)

T2 = 610.18 K

Similarly, Temperature at stage 3 will be;

T3 = T4(P2/P1)^((k - 1)/k)

Plugging in the relevant values gives;

T3 = 750(12)^((1.4 - 1)/1.4)

T3 = 1525.45 K

Now, let's calculate the specific heat addition given by the formula;

q = C_p(T3 - T2)

q = 1.004(1525.45 - 610.18)

q = 918.93 KJ/Kg

Let's now calculate the specific net work output;

w_net = C_p[(T3 - T4) - (T2 - T1)]

w_net = 1.004[(1525.45 - 750) - (610.18 - 300)]

w_net = 467.13 KJ/Kg

A) Power output is given by;

W_T = (W'_net/W_net) × C_p(T3 - T4)

W_T = (325/467.13) × 1.004(1525.45 - 750)

W_T = 541.67 MW

B) back work ratio is;

f = (T2 - T1)/(T3 - T4)

f = (610.18 - 300)/(1525.45 - 750)

f = 0.4

C) Thermal efficiency is given by;

η = w_net/q

Since we are told that a regenerator, with an effectiveness of 85 percent, were installed in the power plant.

Thus;

η = (w_net/q)÷0.85

η = (467.13/918.94) ÷ 0.85

η = 0.598

Answer: straight blade and locking

Explanation: Electrical receptacles come in straight blade and locking varieties.

Answer:

you know you could use like quora or yahoo answers

Based on the given criteria, the following three structural steel wt shapes are acceptable as pin-ended columns to carry an axial compression load of 30 kips for an 18 ft long span:

1. W8x31: This shape has a weight of 31 pounds per foot and a moment of inertia of 82.7 in^4.
2. W9x31: This shape has a weight of 31 pounds per foot and a moment of inertia of 96.2 in^4.
3. W10.5x30: This shape has a weight of 30 pounds per foot and a moment of inertia of 109 in^4.
Out of these three options, the most economical shape is W10.5x30 as it has the lowest weight and the highest moment of inertia, making it the most cost-effective option.

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Answer:

The final volumetric flow rate will be "76.4 m³/s".

Explanation:

The given values are:

\(\dot{m_{1}}=10 \ kg/s\)

\(\dot{m_{2}}=20 \ Kg/s\)

\(T_{1}=293 \ K\)

\(T_{2}=313 \ K\)

\(P_{1}=P_{2}=P_{3}=10 \ bar\)

As we know,

⇒  \(E_{in}=E_{out}\)

\(\dot{m_{1}}h_{1}+\dot{m_{2}}h_{2}=\dot{m_{3}}h_{3}\)

\(e_{1}\dot{v_{1}}h_{1}+e_{2}\dot{v_{2}}h_{2}=e_{3}\dot{v_{3}}h_{3}\)

\(\frac{P_{1}}{RP_{1}}\dot{v_{1}} \ C_{p}T_{1}+ \frac{P_{2}}{RP_{2}}\dot{v_{2}} \ C_{p}T_{1}=\frac{P_{3}}{RP_{3}}\dot{v_{3}} \ C_{p}T_{3}\)

⇒  \(\dot{v_{3}}=\dot{v_{1}}+\dot{v_{2}}\)

         \(=\frac{\dot{m_{1}}}{e_{1}}+\frac{\dot{m_{2}}}{e_{2}}\)

On substituting the values, we get

         \(=\frac{10}{10\times 10^5}\times 8314\times 293+\frac{20\times 8314\times 313}{10\times 10^5}\)

         \(=76.4 \ m^3/s\)

ShopKey Pro presents repair information in a customized email template as well as auto repair software format or layout.

In regards to auto repair information tools, the solution that is known to be made available is the use of ShopKey® Pro with 1Search.

This is know  to be a kind of an exclusive auto repair software that helps to streamlines the search acts to bring closer a special  combination of OEM data as well as experience-based Real Fixes.

Therefore, based on the above, one can say that ShopKey Pro presents repair information in a customized email template as well as auto repair software format or layout.

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As part of the monitoring and controlling process in project management, one of the activities accomplished is assessing project quality.

This involves evaluating and measuring the project's deliverables and performance against predefined quality standards and criteria. It ensures that the project outputs meet the desired level of quality and helps identify any deviations or issues that may arise during project execution. This activity helps project managers take corrective actions and make necessary adjustments to maintain or improve project quality.

While completing project documentation, completing the lessons learned review, and creating the network diagram are important tasks in project management, they may be associated with other processes such as project closing, project review, or project planning, respectively, rather than being specifically part of the monitoring and controlling process.

Therefore, one of the activities accomplished is assessing project quality.

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a. The mass will have a velocity equal to half its maximum velocity at a distance of 0.707x0 from equilibrium.

b. The mass will have an acceleration equal to half its maximum acceleration at a distance of 0.5x0 from equilibrium.

The motion of a mass attached to a spring is described by the equation:

x = A cos(ωt + φ)

where x is the displacement from equilibrium, A is the amplitude of the motion, ω is the angular frequency (ω = sqrt(k/m) where k is the spring constant and m is the mass), t is time, and φ is the phase angle.

The maximum velocity and acceleration occur at the equilibrium position (x=0) and are given by:

v_max = Aω

a_max = Aω^2

To find the distance from equilibrium where the velocity is half its maximum value, we can solve for the displacement x when v = v_max/2:

v = -Aω sin(ωt + φ) = v_max/2

sin(ωt + φ) = -1/2

ωt + φ = -π/6 or 7π/6

Substituting ω = sqrt(k/m) and t = T/4 (where T is the period of the motion) gives:

sqrt(k/m)T/4 + φ = -π/6 or 7π/6

Solving for A cos(φ) (which is the displacement from equilibrium) gives:

A cos(φ) = ±(sqrt(3)/2)A

Therefore, the distance from equilibrium where the velocity is half its maximum value is 0.707x0.

To find the distance from equilibrium where the acceleration is half its maximum value, we can solve for the displacement x when a = a_max/2:

a = -Aω^2 cos(ωt + φ) = a_max/2

cos(ωt + φ) = -1/2

ωt + φ = ±2π/3

Substituting ω = sqrt(k/m) and t = T/3 gives:

sqrt(k/m)T/3 + φ = ±2π/3

Solving for A cos(φ) gives:

A cos(φ) = ±0.5x0

Therefore, the distance from equilibrium where the acceleration is half its maximum value is 0.5x0.

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Answer: Si (Yes)

Explanation:

Answer:

Protozoario o protozoo es un organismo unicelular y eucariota (con núcleo celular definido) perteneciente al Reino protista. Los protozoarios se encuentran junto con los protófitos o algas simples, generalmente acuáticas, dentro del Reino protista o también denominado Reino protoctista.

Explanation:

The reversed Carnot cycle is a theoretical cycle that is the most efficient refrigeration cycle possible for a given heat source and sink temperature.

The coefficient of performance (COP) of a reversed Carnot cycle is given by the ratio of the heat removed from the refrigeration space to the work input to the system.The work input to the refrigerator is 200 kW, and the heat rejection is 2000 kW to a heat reservoir at 27°C. Let's assume that the cooling load supplied to the refrigerator is Q_c.  The COP of a reversed Carnot cycle is given by the following equation: COP = Q_c / W where W is the work input to the system. The COP of a reversed Carnot cycle is given by: COP = T_L / (T_H - T_L)  where T_H is the temperature of the heat source and T_L is the temperature of the heat sink. Solving the equation for T_H, we get: T_H = T_L / (1 - COP/T_L)  Substituting the values, we get: COP = Q_c / W  COP = Q_c / 200 kW  COP = (27 + 273) / (T_H - (27 + 273))  T_H = (27 + 273) / (1 - COP/(27 + 273))  T_H = 300 / (1 - COP/300)  Using the values, we get: COP = Q_c / 200 kW   Q_c = COP x 200 kW Q_c = (27 + 273) / (T_H - (27 + 273)) x 200 kW  Plugging in the values, we get:  COP = (27 + 273) / (T_H - (27 + 273))  COP = (27 + 273) / (T_H - 300)  200 kW = (27 + 273) / (T_H - 300) x COP  200 kW = (27 + 273) x COP / (T_H - 300)  (T_H - 300) x 200 kW = (27 + 273) x COP   T_H = ((27 + 273) x COP) / 200 kW + 300   Calculating the COP:  COP = (27 + 273) / (T_H - (27 + 273))   COP = (27 + 273) / (T_H - 300)  Assuming a COP of 4, we can calculate the temperature of the heat source: T_H = ((27 + 273) x 4) / 200 kW + 300  T_H = 300.8 K or 27.65°C  Therefore, the cooling load supplied to the refrigerator is 800 kW, and the temperature of the heat source is 27.65°C.

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Answer:

sorry im answering questions for the points cuz im built dfferent

Explanation:

Answer: That happens to me too sometimes. I hate when people give the wrong answers...like if u don't know the answer, then don't respond

The correct option is (c) causes the aircraft to be used or authorizes its use. Regulations that relate to operate refer to the person who causes the aircraft to be used or authorizes its use.

Regulations that relate to operate mean that the person who causes the aircraft to be used or authorizes its use is responsible. Regulations are legal standards set by government authorities to provide guidance, protection, and safety to citizens.

For example, the Federal Aviation Administration (FAA) is responsible for setting regulations governing aircraft operation.

The pilot in command (PIC) is the pilot responsible for flying an aircraft during a flight operation. A PIC must have the legal authority and responsibility for the flight. They are responsible for the aircraft and crew, and must ensure that the flight is conducted safely in compliance with regulations.

As a result, the regulations that relate to operate do not apply to the pilot in command or the sole manipulator of the aircraft controls.

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Answer:

steep grading

Explanation:

the farthest

Answer:

The correct answer is option (c) An experimental observation that the velocity of a fluid in contact with a solid surface is equal to the velocity of the surface.

Explanation

Solution:

When a fluid is in proximity to the boundary the solid and the velocities are the same or uniform for the fluid and the surface, no slip condition does not exist.

However, because the no-slip meets the expectations for gas and liquids, this condition no way connected in this case of two solid in proximity.

hence, the other options are wrong here.