Transmission coefficients are used in physics and electrical engineering when considering wave propagation in discontinuous media. The snells law is n₁sinθ1 = n₂sinθ2
The transmission coefficient describes the amplitude intensity or total power of the transmitted wave relative to the incident wave. The transmission coefficient is defined as the ratio of the transmitted particle flux to the incident particle flux and depends on the incident energy.
The sum of the reflected and transmitted energy must equal the total incident energy, so the transmission coefficient is calculated simply by subtracting the reflection coefficient. The ratio of the reflected wave amplitude to the incident wave amplitude is called the reflection coefficient.
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A new ride being built at an amusement park includes a vertical drop of 79.8 meters. Starting from rest, the ride vertically drops that distance before the track curves forward. If friction is neglected, what would be the speed of the roller coaster at the bottom of the drop?
Answer:
Approximately \(39.6\; {\rm m\cdot s^{-1}}\) (assuming that \(g = 9.81\; {\rm m\cdot s^{-2}}\).)
Explanation:
Under the assumptions, vertical acceleration of the vehicle during the ride would be equal to the gravitational field strength: \(a = g = 9.81\; {\rm m\cdot s^{-2}}\).
Apply the following SUVAT equation to find the velocity of the vehicle at the bottom of the drop:
\(v^{2} - u^{2} = 2\, a\, x\),
Where:
\(v\) is the final velocity at the bottom of the drop;\(u\) is the initial velocity at the beginning of the drop; \(u = 0\; {\rm m\cdot s^{-1}}\) since the vehicle started from rest;\(a = g = 9.81\; {\rm m\cdot s^{-2}}\) is the vertical acceleration of the vehicle during the drop;\(x = 79.8\; {\rm m}\) is the vertical displacement of the vehicle during the drop.Rearrange this equation to find \(v\):
\(\begin{aligned}v &= \sqrt{u^{2} + 2\, a\, x} \\ &\approx \sqrt{0^{2} + 2\, (9.81)\, (79.8)} \; {\rm m\cdot s^{-1}} \\ &\approx 39.6\; {\rm m\cdot s^{-1}}\end{aligned}\).
Hence, the speed of this vehicle at the bottom of the drop would be approximately \(39.6\; {\rm m\cdot s^{-1}}\).
which of the following terms refer to the area immediately around the crime?
A crime scene
B bird's-eye view
C extent
D core area
Answer:
A....It is a crime sene
Explanation:
Electric field lines are used to represent the vector electric field around point charges and charged objects. Which of the following statements are true about electric field lines. Select ALL that apply.
Select all that apply
A. Electric field lines cannot cross.
B. Lines of electric field only originate from positive charges.
C. Field lines point in the direction of the force the electric field creates on an electron.
D. The strength of the electric field is greater in regions where the field lines are closer together.
E. In an electric-field-line drawing with many point charges, the number of field lines originating or terminating on each charge is proportional to the charge. That is, bigger charges have proportionally more field lines. F. The true strength of an electric field at any point can be determined from an electric field representation.
Electric field lines are a powerful tool to understand and visualize electric fields. They help to represent the direction and magnitude of the electric field at various points around a charged object.
The following statements are true about electric field lines:
A. Electric field lines cannot cross: This is because at the point where two field lines cross, there would be two directions for the electric field, which is impossible. Hence, the lines do not cross, and this is one of the fundamental characteristics of electric field lines.
B. Lines of electric field only originate from positive charges: Electric field lines originate from positive charges and terminate at negative charges. This is because positive charges repel positive charges and attract negative charges. Therefore, the electric field lines originating from a positive charge terminate at a negative charge.
C. Field lines point in the direction of the force the electric field creates on an electron: Electric field lines point in the direction of the force that would be experienced by a positive charge placed at any point in the field. Electrons, being negatively charged, would experience a force in the opposite direction to the electric field.
D. The strength of the electric field is greater in regions where the field lines are closer together: The density of field lines indicates the strength of the electric field. The closer the lines are, the stronger the field at that point.
E. In an electric-field-line drawing with many point charges, the number of field lines originating or terminating on each charge is proportional to the charge. That is, bigger charges have proportionally more field lines: The number of field lines originating or terminating on each charge is directly proportional to the magnitude of the charge.
F. The true strength of an electric field at any point can be determined from an electric field representation: The strength of the electric field at a point can be determined by the density of electric field lines at that point. However, the actual strength of the field would require quantitative measurements using instruments such as a voltmeter or an electrometer.
In conclusion, electric field lines are an essential tool in understanding the behavior of electric fields. They provide a visual representation of the electric field, its direction, and its strength at various points in space.
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What bet force is required to stop a 2250 kg car if the decelerates at a rate of -4.3 m/s^2 please answer fast
Answer:
Force = Mass × Acceleration
\({ \tt{force = 2250 \times 4.3}} \\ = { \tt{9675 \: newtons}}\)
which type of electromagnetic wave has more energy than ultraviolet waves?
A Visible light
B Infrared
C Microwaves
D X-rays
Answer:
D. X-rays have more energy than ultraviolet waves.
between each pair of vertebrae in the spinal column is a cylindrical disc of cartilage. Typically this dic has a radius of about 2.64cm and thickness about 1.17mm. The shear modulus of cartilage is 1.2*10^7 N/m^2. Suppose a shearing force of magnitude 14 N is applied parallel to the top surface of the disc while the bottom surface remains fixed in the palace. How far does the top surface move relative to the bottom surface
The top surface moves relative to the bottom surface by 1.167 x 10⁻⁶ m.
What is the displacement of the surface?The distance the top surface move relative to the bottom surface is calculated as follows;
shear strain = F/(αx)
where;
F is shearing forceα is the shear modulus x is thicknessshear strain = (14 )/(1.2 x 10⁷ x 0.00117 m)
shear strain = 0.000997
The movement of the top surface;
top surface movement = shear strain x thickness
= 0.000997 x 0.00117 m
= 1.167 x 10⁻⁶ m
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Carmen is helping load furniture and boxes onto a moving truck. She
picks up boxes of her things, places them on a cart, and pushes the cart
to the moving van. Which term best describes the type of force Carmen
is using?
A. contact
B. friction
C. gravity
D. noncontact
The term that best describes the type of force Carmen is using is "contact force" . Contact force refers to the force that occurs when two objects physically touch or interact with each other.
The correct answer is option A.
In this scenario, Carmen is physically picking up boxes and pushing the cart, which involves direct contact between her body, the boxes, and the cart.
Contact forces are classified as a type of mechanical force, which includes various interactions such as pushing, pulling, lifting, and carrying objects. These forces arise due to the electromagnetic interactions between the atoms and molecules of the objects involved.
Friction (option B) is a specific type of contact force that resists the relative motion or tendency of motion between two surfaces in contact. While friction may be present when Carmen pushes the cart, it is not the primary force being described in this situation.
Gravity (option C) is a non-contact force that attracts objects towards each other due to their masses. While gravity is always present, it is not directly involved in Carmen's action of picking up the boxes and pushing the cart.
Non-contact forces (option D) refer to forces that act on objects without any physical contact. Examples include magnetic forces, electrical forces, and gravitational forces. However, in this scenario, Carmen's actions involve direct physical contact, so non-contact forces do not apply.
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Which radioactive isotopes did the Curies discover
the Curies discovered the existence of the elements radium and polonium in their research of pitchblende.
Answer:
radium and polonium
Explanation:
Because I googled it.
Which two substances are elements?
A. sand and air B. salt and sand
C. iron and helium
D. helium and water
What is the displacement of the object after 3 seconds?
Answer:
3 meters
Explanation:
What must the charge (sign and magnitude) of a 1.60 g particle be for it to remain balanced against gravity when placed in a downward-directed electric field of magnitude 680 N/C
Answer:
Explanation:
The charge must be negative so that force in a downward electric field will be upward so that its weight is balanced .
Let the charge be - q .
force on charge
= q x E where E is electric field
= q x 680
weight = 1.6 x 10⁻³ x 9.8
so
q x 680 = 1.6 x 10⁻³ x 9.8
q = 1.6 x 10⁻³ x 9.8 / 680
= 23 x 10⁻⁶ C
- 23 μ C .
A 50-kg ice skater turns a bend at 7 m/sec. If the radius of the curve is 5 m, what is the centripetal force in Newtons provided by the friction between the blade of the skate and the ice?
The centripetal force in Newtons provided by the friction between the blade of the skate and the ice is 490 N
How do i determine the centripetal force?The following data were obtained from the question:
Mass of ice skater (m) = 50 KgVelocity (v) = 7 m/sRadius (r) = 5 metersCentripetal force (F) =?The centripetal force can be obtained as illustrated below:
F = mv²/r
= (50 × 7²) / 5
= (50 × 49) / 5
= 2450 / 5
= 490 N
Thus, we can concluded that the centripetal force is 490 N
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27. The number of coils of wire through which a bar magnet is moved is increased. The
amount the needle on the meter is deflected
A. increases
B. decreases
C. shows no change
D. does not move at all
The amount the needle on the meter is deflected A. increases
This phenomenon can be explained by Faraday's law of electromagnetic induction. According to this law, when a magnetic field (created by the bar magnet) passes through a coil of wire, it induces an electric current in the wire. This induced current generates its own magnetic field, which interacts with the magnetic field of the bar magnet.
The deflection of the meter needle is a result of this induced current. When the number of coils of wire is increased, there is a greater number of wire loops for the magnetic field to pass through. This leads to a stronger induction of electric current, resulting in a larger deflection of the meter needle.
By increasing the number of coils, more magnetic flux is linked with the wire, resulting in a higher induced electromotive force (emf) and a greater current. This increased current produces a stronger magnetic field around the wire, leading to a larger deflection on the meter. Therefore, increasing the number of coils of wire enhances the magnetic field interaction, resulting in an increased deflection of the meter needle. Therefore, Option A is correct.
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4. Four objects are situated along the y axis as follows: a 2.00kg object is at +3.00m, a 3.00kg object is at +2.50m, a 2.50kg object is at the origin, and a 4.00kg object is at -0.500m. Where is the center of mass of these objects?
Answer: 1.348 meters
Explanation: Although the sign is missing from the location of the 4.00 kg object, it is assumed to be positive. The net moment of all the objects about the center of mass must be zero. Let the center of mass be on the y axis at a point c . Adding the four moments together, we get:
(2.00)(3.00−c)+(3.00)(2.50−c)+(2.50)(0−c)+(4.00)(0.500−c)=0
6.00−2.00c+7.50−3.00c+0−2.50c+2.00−4.00c=0
11.5c=15.50
c= 1.348 metres
The center of mass is on the y axis at y = 1.348 metres.
You cause a particle to move from point A, where the electric potential is 14.7 V, to point B, where the electric potential is −24.5 V. Calculate the change that occurs in the particle's electrostatic potential energy, when the particle is an electron, a proton, a neutral hydrogen atom, and a singly ionized helium atom (i.e., lacking one electron from its neutral state).
Answer:
Explanation:
If a particle to move from point A, where the electric potential is 14.7 V, to point B, where the electric potential is −24.5 V, the change in electric potential is expressed as:
∆V = VB-VA
Given VB = -24.5V
VA = 14.7V
∆V = -24.5-14.7
∆V = -39.2V
To calculate the change that occurs in the particle's electrostatic potential energy, when the particle is an electron, we will use the formula:
∆U = q∆V where q is the charge on the electron
Charge on an electron = -1.6×10^-19C
∆U = -1.6×10^-19C×-39.2
∆U = 62.72×10^-19 Joules
For a proton:
q = 1.6×10^-19C
∆U = 1.6×10^-19C×-39.2
∆U = -62.72×10^-19 J (calculation is similar as above, the only difference is the sign)
For a neutral hydrogen atom:
Charge on a neutral hydrogen atom is +1
∆U = 1×-39.2
∆U = -39.2Joules
For a singly ionized helium atom
Charge on the atom q = +1
∆U = 1×-39.2
∆U = -39.2Joules
A knife thrower throws a knife toward a 300 g target that is sliding in her direction at a speed of 2.30 m/s on a horizontal frictionless surface. She throws a 22.5 g knife at the target with a speed of 40.0 m/s. The target is stopped by the impact and the knife passes through the target. Determine the speed of the knife (in m/s) after passing through the target.
Answer:
The speed of the knife after passing through the target is 9.33 m/s.
Explanation:
We can find the speed of the knife after the impact by conservation of linear momentum:
\( p_{i} = p_{f} \)
\( m_{k}v_{i_{k}} + m_{t}v_{i_{t}} = m_{k}v_{f_{k}} + m_{t}v_{f_{t}} \)
Where:
\( m_{k}\): is the mass of the knife = 22.5 g = 0.0225 kg
\( m_{t}\): is the mass of the target = 300 g = 0.300 kg
\( v_{i_{k}}\): is the initial speed of the knife = 40.0 m/s
\( v_{i_{t}} \): is the initial speed of the target = 2.30 m/s
\(v_{f_{k}}\): is the final speed of the knife =?
\( v_{f_{t}} \): is the final speed of the target = 0 (it is stopped)
Taking as a positive direction the direction of the knife movement, we have:
\( m_{k}v_{i_{k}} - m_{t}v_{i_{t}} = m_{k}v_{f_{k}} \)
\( v_{f_{k}} = \frac{m_{k}v_{i_{k}} - m_{t}v_{i_{t}}}{m_{k}} = \frac{0.0225 kg*40.0 m/s - 0.300 kg*2.30 m/s}{0.0225 kg} = 9.33 m/s \)
Therefore, the speed of the knife after passing through the target is 9.33 m/s.
I hope it helps you!
light of wavelength 485 nm passes through a single slit of width 8.32 *10^-6m. what is the single between the first (m=1) and second (m=2) interference minima?
Answer:
3.35
Explanation:
Got it on Acellus
The light of wavelength 485 nm passes through a single slit. The single between the first (m=1) and second (m=2) interference minima is 3.36°.
What is diffraction?Diffraction is the phenomenon of bending of waves through obstacles.
Given is the wavelength λ= 485 nm, silt width d = 8.32 *10⁻⁶ m, then the angle θ will be
d sinθ =mλ
for m=1, sin θ₁ = λ/d
for m=2, sin θ₂ = 2λ/d
Substitute the values into both expressions to find the angles,
sin θ₁ = 485 x 10⁻⁹ / 8.32 *10⁻⁶
θ₁ = 3.34°
and sin θ₂ = (2 x 485 x 10⁻⁹ )/ 8.32 *10⁻⁶
θ₂ = 6.7°
The angle between m =1 and m=2 will be
θ₂ -θ₁ = 6.7° - 3.34° =3.36°
Thus, angle between the first (m=1) and second (m=2) interference minima is 3.36°.
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A mass m at the end of a spring of spring constant k is undergoing simple harmonic oscillations with amplitude A.
Part (a) At what positive value of displacement x in terms of A is the potential energy 1/9 of the total mechanical energy?
Part (b) What fraction of the total mechanical energy is kinetic if the displacement is 1/2 the amplitude?
Part (c) By what factor does the maximum kinetic energy change if the amplitude is increased by a factor of 3?
Answer:
a) The potential energy of the system is 1/9 of the total mechanical energy, when \(x= \frac{1}{3}\cdot A\).
b) The fraction of the total mechanical energy that is kinetic if the displacement is 1/2 the amplitude is 1/2.
c) The maximum kinetic energy is increased by a factor of 9.
Explanation:
a) From Mechanical Physics, we remember that the mechanical energy of mass-spring system (\(E\)), measured in joules, is the sum of the translational kinetic energy (\(K\)), measured in joules, and elastic potential energy (\(U\)), measured in joules. That is:
\(E = K + U\) (1)
By definitions of translational kinetic energy and elastic potential energy, we have the following expressions:
\(K = \frac{1}{2}\cdot m \cdot v^{2}\) (2)
\(U = \frac{1}{2}\cdot k\cdot x^{2}\) (3)
Where:
\(m\) - Mass, measured in kilograms.
\(v\) - Velocity of the mass, measured in meters per second.
\(k\) - Spring constant, measured in newtons per meter.
\(x\) - Elongation of the spring, measured in meters.
If we know that \(U = \frac{1}{9}\cdot E\), \(k = k\) and \(E = \frac{1}{2}\cdot k \cdot A^{2}\), then:
\(\frac{1}{18}\cdot k\cdot A^{2} = \frac{1}{2}\cdot k\cdot x^{2}\)
\(\frac{1}{9}\cdot A^{2} = x^{2}\)
\(x= \frac{1}{3}\cdot A\)
The potential energy of the system is 1/9 of the total mechanical energy, when \(x= \frac{1}{3}\cdot A\).
b) If we know that \(k = k\), \(x = \frac{1}{2}\cdot A\) and \(E = \frac{1}{2}\cdot k \cdot A^{2}\), then the equation of energy conservation associated with the system is:
\(\frac{1}{2}\cdot k\cdot A^{2} = \frac{1}{4}\cdot k\cdot A^{2}+K\)
\(K = \frac{1}{4}\cdot k\cdot A^{2}\)
The fraction of the total mechanical energy that is kinetic if the displacement is 1/2 the amplitude is 1/2.
c) From the Energy Conservation equation associated with the system, we know that increasing the amplitude by a factor of 3 represents an increase in the elastic potential energy by a factor of 9. Then, the maximum kinetic energy is increased by a factor of 9.
The 3.0 cm-diameter water line in the figure splits into two 1.0 cm-diameter pipes. All pipes are circular and at the same elevation. At point A, the water speed is 1.4 m/s and the gauge pressure is 70 kPa.
What is the gauge pressure at point B?
The gauge pressure at B is 11.5 kPa.
From continuity equation,
Velocity of water B = (2* π* 3²)/ (2* π* 1²) = 9 m/s
Then from Bernoulli's equation,
v²/2 + Ф + p/ρ = constant
ρ = 1000 kg/m³
3²/2 + Ф + 50000/1000 = 9²/2 + Ф + P/1000
Pressure at B = 11.5 kPa
Pressure measured in relation to atmospheric pressure is known as gauge pressure. The gauge pressure is positive when the atmospheric pressure is above that level and negative when it is below it.
In actuality, air pressure raises the pressure in any fluid that isn't contained by a hard container. Pascal's principle. is the reason. why this occurs. In relation to atmospheric or barometric pressure, gauge pressure is referred to. In a perfect vacuum of space, there is no matter, hence the pressure is known as absolute pressure.
The most popular measures for measuring vacuum are torr (milli-meter of mercury), micron (micrometer of mercury), and inch of mercury (inHg). While the units of torr, micron, and in Hg often denote absolute pressure, inHg typically denotes gauge pressure.
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AC power switches direction at a frequency of 60 Hz. What is the period of this oscillation?
When the direction of a current changes 60 times in a second, the current is said to be 60 Hz.
An AC power grid with a 60 Hz frequency has a period, what is it?While the passing current does not affect the wavelength, the operating frequency does.A sine wave's period, which is defined as the interval between two identical spots on the wave, will be roughly 16.6 milliseconds at a rate of 60Hz (60 oscillations per second), as depicted in the diagram.
Describe a 60 Hz AC?A frequent word for 60 cycles per second, or more commonly 60 Hertz, is the frequency of dc power (Hz).In honor of German physicist Heinrich Hertz, who established the transmission and presence of electric oscillations, the latter unit is used.
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A copper wire of length L and cross-sectional area A has resistance R. A second copper wire at the same temperature has a length of 2L and a cross-sectional area of A. What is the resistance of the second copper wire?
A. 2R
B. 4R
C. R
D. 1/2 R
Answer: 4R
Explanation:R=pL/A
R second wire=p2L/1/2A
=4R
"An egg is free-falling from a nest in a tree. Neglect air resistance."
A There are two forces acting on the egg and
the forces are balanced.
C There are three forces acting on the egg and
the forces are unbalanced.
B There is one force acting on the egg and the
force is unbalanced.
D
There are four forces acting on the egg and
the forces are balanced.
In a scenario where an egg is free-falling from a nest in a tree and neglecting air resistance, there is one force acting on the egg and the force is unbalanced which is denoted as option B.
What is a Force?This is referred to as an external agent which is capable of influencing the motion of an object or body. It is also capable of changing the state of rest of a body and the unit in Newton.
When an object is falling from a height and there is no air resistance then the only force acting on it is gravitational force which is unbalanced as there is no equal and opposite force to make it stable.
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6.
least 2 m. If the same car is moving with the speed 80K/h,what is the minimum stopping distance?
A car moving with a speed of 40 km/h can be stopped by applying the brakes after at-
The minimum stopping distance of the car is determined as 8 m.
What is the minimum stopping distance?The minimum stopping distance of the car is calculated as follows;
d = (u²)/(2a)
where;
d is the minimum stopping distanceu is the initial velocitya is the acceleration of the carwhen the minimum stopping distance = 2 m, initial velocity = 40 km/hr = 11.11 m/s
2 = (11.11²)/(2a)
a = (11.11²)/(2 x 2)
a = 30.86 m/s²
when the speed becomes 80 km/h, the minimum stopping distance is calculated as;
u = 80 km/h = 22.22 m/s
d = (22.22² )/ (2 x 30.86)
d = 8 m
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A skydiver jumps out of a helicopter and falls freely for 8.2 s before opening the parachute.(
a) What is the skydiver's downward velocity when the parachute opens?
(b) How far below the helicopter is the skydiver when the parachute opens?
PLEASE HELP!!
parameters given are:
time= 8.2 seconds
g(acceleration due to gravity)= \(9.8 m/s{2}\)
(a) skydivers downward velocity is given as
Vf = Vo + g(t)
Vf= 0 + 9.8 + (8.2)
Vf= \(80.36 m/s^{2}\)
(b) distance of the skydiver below the helicopter
h= Vo + 1/2 gt^2
h= 0 + (0.5) *(9.8) * (8.2)^2
h= 0.5* 9.8 * 67.24
h= 329.48m
What is Velocity?
Velocity is the rate at which an object changes its direction.
The skydivers downward velocity is 80.36m/s^2
The distance form the skydiver to the helicopter is 329.48 meters
In conclusion, initial velocity in the given question is equal to zero.
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6. What is the lowest temperature on the Kelvin scale? What happens to matter when it
reaches this temperature?
7. What is different about the degrees on the Fahrenheit and Kelvin scales and the Celsius
and Kelvin scales?
Part F
Imagine you were a sportscaster at the Olympics. You'd created a mathematical model similar to the one you just did. Imagine that you had a
computer program that could do an instantaneous analysis of video motion using that model. How could you use it in your sportscast?
A program that could do an instantaneous analysis of video motion will be useful it in a sportscast to analyze events as they occur.
Why will a program be needed?A motion video is defined as the display of video images at a rate (such as thirty frames per second) that causes objects to appear to move smoothly and continuously.
Sports inherently involve fast and accurate motion, which can be difficult for competitors to master but also for coaches and trainers to analyze and audiences to follow. Because of the nature of most sports, monitoring with sensors or other devices attached to players or equipment is generally not possible. This opens up a plethora of opportunities for the use of computer vision techniques to assist competitors, coaches, and the audience
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52. For the potential-energy diagram in Figure P10.52, what is the maximum speed of a 2.0g particle that oscillates between x=2.0mm and x=8.0 mm?
The maximum speed of a 2.0 g particle that oscilates between x= 2.00 mm to x = 8.00 mm is 70.71 m/s.
What is speed?Speed is the ratio of distance to time of a body.
To calculate the maximum speed of the particle, we use the formula below.
Formula:
v = √(2E/m).................. Equation 1Where:
v = Maximum SpeedE = Energym = Mass of the particleFrom the Graph in the question,
Given:
E = 5 Jm = 2.0 g = 0.002 kgSubstitute these values into equation 1
v = √(2×5/0.002)v = √5000v = 70.71 m/sHence, the maximum speed is 70.71 m/s.
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a 20g wt causes an extension of 0.72cm in a spring. The extension caused by a load of 80g wr assuming hooke's law is obeyed by the spring
100PTS
will MARK as BRAINLIEST
Answer:
Explanation:
We can use Hooke's law to solve this problem. Hooke's law states that the force required to extend or compress a spring by some distance x is proportional to that distance. Mathematically, this can be written as:
F = kx
where F is the force applied to the spring, x is the distance the spring is stretched or compressed, and k is the spring constant, a measure of the stiffness of the spring.
To find the spring constant, we can use the given information that a 20g weight causes an extension of 0.72cm in the spring. We can convert the weight to force using the acceleration due to gravity, g:
F = mg = (0.02 kg)(9.8 m/s^2) = 0.196 N
Now we can solve for the spring constant:
k = F/x = 0.196 N / 0.0072 m = 27.2 N/m
Finally, we can use this spring constant to find the extension caused by an 80g weight:
F = mg = (0.08 kg)(9.8 m/s^2) = 0.784 N
x = F/k = 0.784 N / 27.2 N/m = 0.0288 m
So the extension caused by an 80g weight is 0.0288 m or 2.88 cm.
What is the gravitational acceleration I’d experience? How does it compare to Earth’s (for reference, Earth’s gravitational acceleration is 9.81 m/s2)?
Answer:
free-falling object is an object that is falling under the sole influence of gravity. A free-falling object has an acceleration of 9.8 m/s/s, downward (on Earth). This numerical value for the acceleration of a free-falling object is such an important value that it is given a special name. It is known as the acceleration of gravity - the acceleration for any object moving under the sole influence of gravity. A matter of fact, this quantity known as the acceleration of gravity is such an important quantity that physicists have a special symbol to denote it - the symbol g. The numerical value for the acceleration of gravity is most accurately known as 9.8 m/s/s. There are slight variations in this numerical value (to the second decimal place) that are dependent primarily upon on altitude. We will occasionally use the approximated value of 10 m/s/s in The Physics Classroom Tutorial in order to reduce the complexity of the many mathematical tasks that we will perform with this number. By so doing, we will be able to better focus on the conceptual nature of physics without too much of a sacrifice in numerical accuracy.
g = 9.8 m/s/s, downward
( ~ 10 m/s/s, downward)
Explanation:
Look It Up!
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Question 15 of 32
A bungee jumper jumps off a bridge and bounces up and down several times.
She finally comes to rest 30 m below the bridge from which she just jumped.
If her mass is 50 kg and the spring constant of the bungee cord is 10 N/m,
how much energy was lost due to air resistance while she was bouncing?
(Recall that g = 9.8 m/s²)
A. 7330 N
B. 9200 N
C. 10,200 N
D. 8605 N
C. 10,200 N is how much energy was lost due to air resistance while she was bouncing
How much energy was lostThe energy lost due to air resistance while the bungee jumper was bouncing can be calculated by finding the total mechanical energy of the system at the beginning of the jump and comparing it to the total mechanical energy at the end of the jump.
At the beginning of the jump, the total mechanical energy is given by:
Ei = mgh
where m is the mass of the bungee jumper, g is the acceleration due to gravity, and h is the height of the bridge. Therefore, at the beginning of the jump:
50 x 30 x 10 - 1/2 x 30^2 x 10
= 15000 - 4500
= 10,200 N
Read more on energy here:https://brainly.com/question/13881533
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