A train travels with a constant speed of 20.0m/s for 7.00s. Determine all
unknowns and answer the following question(s).
What is the magnitude of the train's acceleration?

In order to determine the number of particles of methane, use the following expression:

number of particles = (mass /molar mass ) x Avogadro's number

in this case, you have:

molar mass = 16.03 grams/mole

mass = 120 grams

Avogadro's number = 6.02*10²³ particles/mol

replace the previos values of the parameters into the formula for the number of particles:

number of particles=(120 grams/ 16.03 grams/ mol)x(6.02*10²³particles/mol)

= (7.46 mol) x (6.02*10²³ particles/mol)

= 4.50*10²⁴ particles

Hence, the number of particles of methane, in 120 grams, is 4.50*10²⁴

Answer:

The drawdown in a confined aquifer under transient conditions can be estimated using the Theis solution for the non-equilibrium radial flow of water. This solution is given by:

s = Q / (4πT) * W(u),

where s is the drawdown, Q is the pumping rate, T is the transmissivity, and W(u) is the well function (also called the Theis function) which depends on the variable u, where:

u = r²S / (4Tt),

where r is the distance from the pumping well and t is the time since pumping began.

Given T = 2500 m²/day, S = 1.0 x 10-3, and Q = 500 m³/day, we can calculate the drawdown at 10 m (r1 = 10 m) and 50 m (r2 = 50 m) for t = 150 days.

For (i) r1 = 10 m:

u1 = r1²S / (4Tt) = (10 m)² * 1.0 x 10-3 / (4 * 2500 m²/day * 150 days) = 0.000667

s1 = Q / (4πT) * W(u1) = 500 m³/day / (4π * 2500 m²/day) * W(0.000667).

For (ii) r2 = 50 m:

u2 = r2²S / (4Tt) = (50 m)² * 1.0 x 10-3 / (4 * 2500 m²/day * 150 days) = 0.01667

s2 = Q / (4πT) * W(u2) = 500 m³/day / (4π * 2500 m²/day) * W(0.01667).

Explanation:

Unfortunately, the well function W(u) cannot be evaluated directly without more specialized knowledge or tools. The well function is related to the exponential integral function, which requires numerical computation. You would typically use a table of values, a calculator with this function, or a computer program to evaluate it. After obtaining W(u), multiply it by the remaining fraction to find the drawdowns.

Answer: You need your bachelor's to become a nurse at an entry level.

Explanation: Most nurses enter nursing knowing they will eventually earn their baccalaureate degree. While it’s possible to obtain an Associate Degree in Nursing (ADN), capped by earning one’s RN license by taking and passing the standardized NCLEX-RN exam, many nurses choose to further their education—and career prospects—by obtaining their baccalaureate degree. Requirements vary by state, but at the very least, the path to RN usually involves earning an Associate Degree in Nursing (ADN), qualifying a candidate to take the standardized national licensure examination known as NCLEX-RN. Only after taking this exam and passing may a nurse work as an RN. This is true of all states and the District of Columbia. Some localities may also have additional requirements.

RN - Registered Nurse

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:)

The speed at which the copper bar needs to move at right angles to the magnetic field to generate 1.5 V across its ends can be calculated using the formula v = (E/B) * d, where E is the voltage, B is the magnetic field strength, and d is the width of the copper bar.

When a conductor moves through a magnetic field, a voltage is induced across its ends. This is known as electromagnetic induction. The magnitude of the induced voltage is given by the formula E = B * v * d, where B is the magnetic field strength, v is the velocity of the conductor perpendicular to the field, and d is the width of the conductor. Rearranging the formula, we get v = (E/B) * d.

Substituting the given values, we get v = (1.5 V) / (0.600 T * 0.0600 m) = 41.7 m/s. Therefore, the copper bar needs to move at a speed of 41.7 m/s (or 150 km/h) at right angles to the magnetic field to generate 1.5 V across its ends.

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Block 4 shows the greatest rise in temperature. The rise in the temperature is inversely proportional to the initial length. The concept of thermal expansion is used in the given problem.

Thermal expansion is the tendency of matter to alter its form, area, volume, and density in response to a change in temperature.

The formula for the thermal expansion is found as;

\(\rm \triangle L = L \alpha \triangle T \\\\\ \triangle T = \frac{\triangle L}{L\alpha}\)

The rise in the temperature is inversely proportional to the initial length;

Block 4 has the smallest initial length.

Hence, the block 4 has the greatest rise in temperature.

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Answer:

i believe the answer is C. the speed of each wave

Answer:

the speed of each wave

Explanation:

a p e x :))

In anthropological terms, _Kinship_____ is the means by which a person determines their kin relations over the course of past and future generations.

Kinship is the term which anthropologists define kin relations over generations.

Kinship includes blood, marriage, and other social links. It includes people's intricate family links and determines their social status.

Kinship systems help anthropologists analyse family structures, inheritance patterns, marital practises, and societal roles. Genealogies, oral histories, and cultural practises reveal kinship.

Understanding kinship is crucial in anthropological research as it provides insights into social organization, cultural norms, and the transmission of resources, rights, and obligations within a given society. It helps anthropologists understand how people define and navigate family ties, both past and future.

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Answer:

The net force exerted on the race-car driver is 727.3 N

Explanation:

Acceleration

According to Newton's second law of motion, the acceleration of an object a is directly proportional to the net force F and inversely proportional to the object's mass m:

\(F=m.a\)

Since we don't have the value of the acceleration, we must use the kinematic equations to calculate it.

The main formula for accelerated motion is:

\(v_f=v_o+a.t\)

Where vf is the final speed of the object, vo is its initial speed, a is the acceleration, and t is the time.

The race-car driver accelerates from vo=0 to 50 m/s in t=5.5 s. We can calculate the acceleration, solving the above equation for a:

\(\displaystyle a=\frac{v_f-v_o}{t}\)

\(\displaystyle a=\frac{50-0}{5.5}\)

\(a=9.09\ m/s^2\)

Now we calculate the net force:

\(F=80\ Kg\cdot 9.09\ m/s^2\)

\(\boxed{F=727.3\ N}\)

The net force exerted on the race-car driver is 727.3 N

The distance the 2.0 N object will move, given that 35 J of energy is used to move it is 17.5 m

Work done is defined as the product of force and the distance moved in the direction of the force. Mathematically, it is expressed as:

Work done (Wd) = force (F) × distance (d)

Using the above formula, we can detertmine the distance the object will move as illustrated below:

Work done (Wd) = force (F) × distance (d)

35 = 2 × distance moved

Divide both sides by 2

Distance moved = 35 / 2

Distance moved = 17.5 m

Therefore, we can conclude from the calculation made above that the distance moved is 17.5 m

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Complete question:

You use 35 J of energy to move a 2.0 N object. How far did you move it?

We have to use Newton's Second Law, knowing that the friction force is

Then,

Because the friction force is against the movement.

We know that m = 5kg, F = 75N, friction = 10.

Let's solve for a

The acceleration is 13 meters per square second.

Also, the force acting on the object is 65N because we have a net force present there.

Answer: last one radio waves

Or d

Explanation:

Answer:

infrared

Explanation:

ed2020

Superior colliculi structure is controlling this movement To attending the indi 500 and as cars pass you by, your eyes and head follow the race cars.

In neuroanatomy, the advanced colliculus (from the Latin 'upper hill') is a shape mendacity at the roof of the mammalian midbrain. In non-mammalian vertebrates, the homologous shape is known as the optic tectum or optic lobe. The adjective shape tectal is typically used for each system.

In mammals, the superior colliculus forms a chief thing of the midbrain. it's far a paired structure and collectively the paired inferior colliculi form the corpora quadrigemina. The superior colliculus is a layered shape, with a pattern, this is just like all mammals. The layers can be grouped into the superficial layers (stratum opticum and above) and the deeper last layers. Neurons within the superficial layers acquire direct input from the retina and reply nearly solely to visible stimuli.

Many neurons in the deeper layers additionally respond to different modalities and some reply to stimuli in a couple of modalities. The deeper layers also incorporate a populace of motor-related neurons, capable of activating eye actions as well as other responses. In different vertebrates, the number of layers in the homologous optic tectum varies.

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Answer:

B Gamma-Rays

Hope this Helps! Please mark Brainliest!

Answer:

The answer is B. Gamma Rays.

Explanation:

I take AP EX lessons and quiz all the time.

Explanation:

The horizontal distance moved by the mass in 5.0 s is 25 m. The formula for the horizontal distance moved by a mass in a vertical circle is: Horizontal distance = (2πr/T) × t where r = radius of the vertical circle, T = period of the circle, and t = time. Given: r = 10.0 m, T = 2π√(r/g) = 2π√(10.0/9.8) = 6.25 s, t = 5.0 s Therefore, Horizontal distance = (2πr/T) × t = (2π × 10.0/6.25) × 5.0 = 25 m

There are several differences in behavior between an electrically conducting sphere and an insulating sphere.
Firstly, a conducting sphere can be charged by friction, whereas an insulating sphere cannot. This is because the conducting sphere allows electrons.

Secondly, an uncharged object can be charged by touching it to a charged conducting sphere, but not by touching it to a charged insulating sphere. This is because the conducting sphere allows charge to flow easily between objects, while an insulating sphere does not.

Excess charge placed on a conducting sphere becomes distributed over the entire surface of the sphere. Excess charge placed on an insulating sphere can remain where it is placed. conducting spheres have mobile electrons that can move freely, allowing the charge to distribute evenly over the surface  Insulating spheres have electrons that are not as mobile, which means the charge cannot move as freely and tends to remain where it was placed. the fact that polarization occurs in conducting spheres when brought near a charged object, while insulating spheres do not experience this effect.

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Answer:

The primary contributors to heat in the core are the decay of radioactive elements, leftover heat from planetary formation, and heat released as the liquid outer core solidifies near its boundary with the inner core.

Answer:

this is just a black bar, I do not understand.

Explanation:

An electric field is defined along the x-axis by the function then if g=1.5m and h=6m, then v(g)-v(h) = 7768.40V.

When charge is present in any form, a point in space has an electric field that is connected to it.

The value of E, often known as the electric field strength, electric field intensity, or just the electric field, expresses the strength and direction of the electric field.

Each location in space where a charge exists in any form can be considered to have an electric field attached to it. The electric force per unit charge is another name for an electric field. The electric field’s equation is given as E = F / Q.

E = + 5 x^4 x^n

Also, E = -x^n r/rx (v)

⇒ 5 x^4 x^n = -x^n r/rx (v)

⇒ v = - ∫ 5 x^4 dx

⇒ v = -5 x^5/5

⇒ v = - x^5 v

So, v(g) - v(h) = - (1.5)^5 + (6)^5

= -7.59375 + 7776

=7768.40 V

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Answer:

D: 4.4m/s

Explanation:

From a known theorem the total work on a body is equal of the variation of kinetic energy:

\(W = \Delta K = K_f-K_i = \frac12 mv_f^2 - \frac12 m v_i^2\)

Taking the first and last step in the chain of equalities and replacing the values we have, we get:

\(5 = \frac12(1)v_f^2 - \frac12(1)(3)^2\\10= v_f^2 -9 \rightarrow v_f^2 = 19 \rightarrow v_f=\sqrt19 \approx 4.4m/s\)

A 27.6 cm diameter coil consists of 25 turns of circular copper wire 2.30 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil changes at a rate of 9.00E-3 T/s. Therefore, the current in the loop is -8.41 x 10-4 A and the rate at which thermal energy is produced is 2.31 x 10-6 W.

Given parameters are: Diameter of coil, D = 27.6 cm Radius of coil, r = 13.8 cm

Number of turns in the coil, N = 25 ,Circular wire diameter, d = 2.30 mm Magnetic field strength, B = 9.00 x 10-3 T/s.

The formula for magnetic field strength due to a coil is:B = μ0nI whereμ0 = permeability of free space = 4π x 10-7 T.m/IN = Number of turns per unit length of the coil = N/L (where L is the length of the coil), d = Diameter of circular wire = 2.30 mm I = Current flowing in the coil

Let's calculate N/LN/L = 25/(π x 0.023 m)≈1131.98 N/m

We can find the radius of the wire by dividing its diameter by 2.rw = 2.30/2 x 10-3 m = 1.15 x 10-3 m

Now, we can calculate the cross-sectional area of the wire as:A = πr2A = π x (1.15 x 10-3)2 m2A = 4.15 x 10-7 m2

Let's calculate the total resistance of the coil as well using the following formula :R = ρL/A

whereρ = resistivity of copper = 1.72 x 10-8 ΩmL = length of the coil = πD ≈ 86.6 cm = 0.866 mR = (1.72 x 10-8 Ωm x 0.866 m) / 4.15 x 10-7 m2R ≈ 3.6 Ω

To find the current in the coil, we can use Faraday's Law of Electromagnetic Induction, which is given by: V = - N dΦ/dt

where V = emf induced in the coil N = number of turns in the coilΦ = magnetic flux through the coildΦ/dt = rate of change of magnetic flux

The magnetic flux through the coil is given by:Φ = BAcosθwhereB = magnetic field strength A = area of the coilθ = angle between the normal to the coil and the direction of magnetic field

Let's calculate A and θ:A = πr2A = π x (13.8 x 10-2 m)2A ≈ 5.98 x 10-3 m2θ = 90° (because the magnetic field is perpendicular to the plane of the coil)Φ = BA = (9.00 x 10-3 T/s) x (5.98 x 10-3 m2)Φ ≈ 5.39 x 10-5 Wb

Let's calculate dΦ/dt using the following formula:dΦ/dt = NABcosθdΦ/dt = NAB x cos 90° = NABdΦ/dt = 25 x (5.39 x 10-5 Wb) x (9.00 x 10-3 T/s)dΦ/dt = 1.215 x 10-5 V/s

Now we can find the current using the following formula: V = IRV = - N dΦ/dt I = - V/R = - (N dΦ/dt)/RR = 3.6 ΩN = 25I = - (25 x 1.215 x 10-5 V/s) / 3.6 ΩI ≈ - 8.41 x 10-4 A (Note that the negative sign indicates that the current is flowing in the opposite direction to what was initially assumed.)

The rate at which thermal energy is produced can be found using the following formula: P = I2RwhereI = Current flowing in the coil R = Total resistance of the coil P = (- 8.41 x 10-4 A)2 x 3.6 ΩP ≈ 2.31 x 10-6 W

Therefore, the current in the loop is -8.41 x 10-4 A and the rate at which thermal energy is produced is 2.31 x 10-6 W.

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Answer:

Mass is a base unit, acceleration is a derived unit calculated as a function of length and time which are both base units. Any unit definition that is a function of more basic units is considered a derived unit.

82 E−19 s2/m3 is its ratio from the law of harmonies

Why do Mars and Jupiter share an asteroid belt?

It seems that one or more planets could have developed in the zone between Mars and Jupiter, but Jupiter's gravity kept tearing things apart. The material in this region was never able to form a single planet, only asteroid-sized particles.

The only dwarf planet in the inner solar system is Ceres, which is also the largest asteroid belt object between Mars and Jupiter. In 1801 when Giuseppe Piazzi initially noticed it, it was the first asteroid belt object to be found.

A planet's orbital period and radius are compared to those of other planets according to the Law of Harmonies. By employing the ratio T^2/R^3, various aspects of orbits are compared.

T is 7.93 E 7s

R is 2.77 E 11 m

Ratio will be 82 E−19 s2/m3

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Answer:

"transverse waves" such as electromagnetic waves

In something like a sound wave, the particles must vibrate longitudinally for the wave to progress thru the medium

Answer:

It’s D

Explanation:

Because I took the USA test prep and got it right

Because r is given, we can use the second expression in the equation ac=v2r;ac=rω2 a c = v 2 r ; a c = r ω 2 to calculate the centripetal acceleration. Solution.

Based on the light curve in the book, the distant Type 1 supernova will become too faint to be seen approximately 270 days after reaching its peak apparent magnitude of 24.

According to the given information, the peak apparent magnitude of the distant Type 1 supernova is 24. By referring to the light curve in the book, we can estimate the duration for which the supernova remains visible. Typically, the brightness of a supernova decreases exponentially over time.

While specific light curves may vary, a rough estimate can be made. Considering the options provided, the closest estimate is approximately 270 days. This means that after the supernova reaches its peak brightness, it will gradually fade and become too faint to be observed after around 270 days.

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Answer:

answer https:/

Explanation:

apparatus.com

Water has a stronger force of attraction between its particles than methane.

To justify this we have to remember that temperature is a measure of the kinetic energy of the particles (atoms and molecules) in a given system. As temperature increase the kinetic energy increases as well; now larger molecules will have more electron and nucleis that attract with each other, then they will need more kinetic energy (temperature) to boil.