A throat spray is 1. 40% by mass phenol, c6h5oh c 6 h 5 oh , in water. If the solution has a density of 0. 9956 grams per/milliter, calculate the molarity of the solution.

Answer:

Explanation:

One

Pressure will favor the side with the least number of mols if it the larger number of moles counts only the gases. (Le Chetalier's Principle). In this case both CaCO3 and CaO are not soluble in water. The only gas is CO2. Since it represents the most number of mols the reactant is favored.

More or Less are very troublesome words in beginning science. Make sure you understand their meaning for this question. The more pressure applied, the more the reactants will be favored and the equation shifts left.

Two

Fe and Fe3O4 are both solids. It depends on the form that water takes. Looking it up, it is shown to be in a gas form. That means if you increase the pressure, nothing will happen. That is not your question, but you should note it.

The answer to your question is you increase the concentration of Fe or H2O, the equilibrium will shift right.

If you add more Fe3O4 or hydrogen it will shift left.

Chemists say that if you alter the equilibrium the equation will shift in the opposite direction to compensate for the action you have taken.

True. Antioxidants are frequently added to foods that contain fat as preservatives to prevent or postpone the development of rancidity brought on by oxidation.

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The average body sodium content of an adult male is 92 g, of which half (46 g) is found in the extracellular fluid (ECF) at a concentration of 135–145 mmol/L, 11 g is discovered in the intracellular fluid at a concentration of 10 mmol/L, and 35 g is discovered in the skeleton.

The sodium-potassium pump action moves sodium and potassium, respectively, from within to outside the cell and vice versa against the concentration gradient using the energy provided by ATP. This maintains the concentration gradient between the ECF and intracellular fluid. Sodium enters the polarised cells of the renal tubular epithelium or the intestinal wall through specific channels or other transport mechanisms from the tubular lumen or the gut, and is then extruded from the cell into the neighbouring capillaries due to the action of the pump, which is primarily distributed on the basolateral sides of the cell. Sodium transport in these cells is typically linked to the transport of other substrates, such as phosphates, amino acids, glucose, and galactose.

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Answer: The standard cell potential (E°cell) of the silver electrode is +0.93 V

Explanation:

To determine the potential of the silver electrode in the cell, we need to use the standard reduction potentials of the half-reactions involved and apply the Nernst equation.

The half-reactions involved in this cell are:

Ag⁺(aq) + e⁻ → Ag(s) (Silver half-reaction)

Pb²⁺(aq) + 2e⁻ → Pb(s) (Lead half-reaction)

The standard reduction potentials for these half-reactions are as follows:

E°(Ag⁺/Ag) = +0.80 V

E°(Pb²⁺/Pb) = -0.13 V

To find the potential of the silver electrode (E°cell), we need to subtract the reduction potential of the anode (Pb) from the reduction potential of the cathode (Ag):

E°cell = E°(cathode) - E°(anode)

E°cell = +0.80 V - (-0.13 V)

E°cell = +0.93 V

The standard cell potential (E°cell) is +0.93 V. This value represents the potential of the silver electrode in the cell.

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To determine the potential of the silver electrode in the cell, we need to use the standard reduction potentials of the half-reactions involved and apply the Nernst equation.

The half-reactions involved in this cell are:

Ag⁺(aq) + e⁻ → Ag(s) (Silver half-reaction)

Pb²⁺(aq) + 2e⁻ → Pb(s) (Lead half-reaction)

The standard reduction potentials for these half-reactions are as follows:

E°(Ag⁺/Ag) = +0.80 V

E°(Pb²⁺/Pb) = -0.13 V

To find the potential of the silver electrode (E°cell), we need to subtract the reduction potential of the anode (Pb) from the reduction potential of the cathode (Ag):

E°cell = E°(cathode) - E°(anode)

E°cell = +0.80 V - (-0.13 V)

E°cell = +0.93 V

The standard cell potential (E°cell) is +0.93 V. This value represents the potential of the silver electrode in the cell.

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Explanation:

To calculate the molarity of a solution, we need to know the number of moles of solute (in this case, KCl) and the volume of the solution in liters.

First, we need to calculate the number of moles of KCl. We can do this by using the formula: moles of KCl = (mass of KCl in grams) / (molar mass of KCl in grams/mole)

The molar mass of KCl is 74.5513 g/mol, so we can use this to calculate the number of moles of KCl in the solution:

moles of KCl = (0.93 g) / (74.5513 g/mol) = 0.01239 moles

Next, we can use this number of moles to calculate the molarity of the solution. Molarity is defined as moles of solute per liter of solution, so we can use the following formula to calculate the molarity of the solution:

molarity of solution = (moles of KCl) / (volume of solution in liters)

In this case, the volume of the solution is 0.75 L, so we can substitute these values into the formula:

molarity of solution = (0.01239 moles) / (0.75 L) = 0.0165 moles/L or approximately 0.0165 M

Following represents the number of Molecules of the type indicated is present as a reactant or product of the chemical reaction shown is the coefficient of the species

The number of atoms, molecules, or formula units of a reactant or product in a balanced chemical equation is the coefficient of that species then the mole ratio of two substances in a chemical reaction is the ratio of their coefficients in the balanced chemical equation and the this numbers are called as coefficient and they tell how many of each molecule are participate in the reaction

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The empirical formula of the unknown compound is CH₂O.

To determine the empirical formula of the unknown compound, we need to find the mole ratios of carbon and hydrogen in the compound based on the given masses of carbon dioxide (CO₂) and water (H₂O) produced during combustion analysis.

First, we calculate the moles of CO₂ and H₂O produced:

Moles of CO₂ = mass of CO₂ / molar mass of CO₂

= 2.845 g / 44.01 g/mol

= 0.0647 mol

Moles of H₂O = mass of H₂O / molar mass of H₂O

= 1.744 g / 18.015 g/mol

= 0.0968 mol

Next, we determine the mole ratio of carbon to hydrogen by dividing the moles of each element by their respective smallest values:

Carbon: 0.0647 mol / 0.0647 mol = 1

Hydrogen: 0.0968 mol / 0.0647 mol = 1.5

We need to simplify the ratio, so we multiply both values by 2 to obtain whole numbers:

Carbon: 1 × 2 = 2

Hydrogen: 1.5 × 2 = 3

The empirical formula of the unknown compound is CH₂O, indicating that it contains 2 carbon atoms, 3 hydrogen atoms, and 1 oxygen atom.

In summary, the empirical formula of the unknown compound is CH₂O.

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To produce 1000 kg of fishmeal (M = 1000 kg), you would need 3000 kg of pasta. To determine the amount of pasta required to produce 1000 kg of fishmeal, we need to consider the mass balance of the process. Let's break down the steps involved:

A. Extraction of fish oil:

The pasta obtained from the extraction stage contains 20% flour and 80% water. To calculate the amount of pasta, we need to determine the mass of flour and water in the pasta. Let's assume the total mass of the pasta is P kg.

Mass of flour = 20% of P = 0.2P kg

Mass of water = 80% of P = 0.8P kg

b. Drying of pasta:

During the drying stage, the pasta is dried in a rotary drum, resulting in fishmeal with 40% humidity. This means that the final fishmeal will contain 60% dry matter.

Let's assume the mass of the dried fishmeal is M kg.

Mass of dry matter = 60% of M = 0.6M kg

Since the dry matter in the fishmeal comes from the flour in the pasta, we can equate the mass of dry matter to the mass of flour:

0.6M kg = 0.2P kg

To produce 1000 kg of fishmeal, we want to find the corresponding value of P:

0.6M = 0.2P

P = (0.6M) / 0.2

P = 3M

Therefore, to produce 1000 kg of fishmeal (M = 1000 kg), you would need 3000 kg of pasta.

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The percentage of women with hypertension, defined as a diastolic blood pressure level above 90 mmHg, can be calculated using the standard normal distribution table.

To find the percentage, we need to calculate the z-score for a diastolic blood pressure of 90 mmHg using the formula:

z = (x - μ) / σ

where x is the diastolic blood pressure value, μ is the mean, and σ is the standard deviation.

In this case, x = 90 mmHg, μ = 70.2 mmHg, and σ = 10.8 mmHg.

Substituting these values into the formula, we get:

z = (90 - 70.2) / 10.8 = 1.833

Next, we need to find the corresponding area under the standard normal curve for a z-score of 1.833. By referring to the standard normal distribution table or using a calculator, we find that the area to the left of 1.833 is approximately 0.9664.

To determine the percentage of women with hypertension, we subtract this area from 1 and multiply by 100:

Percentage = (1 - 0.9664) × 100 ≈ 3.36%

Therefore, approximately 3.36% of women have hypertension based on the given diastolic blood pressure criteria.

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Answer:

"Avogadro's law is an experimental gas law relating the volume of a gas to the amount of substance of gas present. The law is a specific case of the ideal gas law. A modern statement is: Avogadro's law states that "equal volumes of all gases, at the same temperature and pressure, have the same number of molecules."

Answer:

Avogadro's law states that the equal volume of all gases at the same temperature and pressure contain the same number of molecule

Explanation:

Electromagnetic waves are waves which can travel through the vacuum of outer space. Electromagnetic waves are created by the vibration of an electric charge. This vibration creates a wave which has both an electric and a magnetic component.

The average speed

3. 89.7 m/min

4. 6.13 ft/min

Given

3. 1076 m in 12 min

4. 92 ft in 15 min

Required

average speed

Solution

3.

I am solving for : the average speed

The equation I need is :

\(\tt avg~speed=\dfrac{total~distance}{total~time}\)

This is how I set the equation

\(\tt avg~speed=\dfrac{1076~m}{12~min}\)

This is my answer = 89.7 m/min

4.

I am solving for : the average speed

The equation I need is :

\(\tt avg~speed=\dfrac{total~distance}{total~time}\)

This is how I set the equation

\(\tt avg~speed=\dfrac{92~ft}{15~min}\)

This is my answer = 6.13 ft/min

Answer:0.085

Explanation:

Answer:

D

Explanation:

The area of a shape is the amount of space a 2-dimensional shape covers. It's measured in units squared (units²). So, the answer is D.

The buffer capacity is greater than the amount of NaOH added (0.0027 > 0.0005), the buffered solution should be able to prevent a significant pH change.

The weak acid and its salt that would be used to create a buffered solution with a pH of 7.50 are acetic acid (CH₃COOH) and sodium acetate (CH₃COONa). This is because the pKa of acetic acid is 4.76, which is closest to the desired pH of 7.50. Additionally, the salt of acetic acid, sodium acetate, is readily available and easily dissolves in water to create a buffered solution.

To estimate the concentrations of the weak acid and its salt that are necessary to produce an initial pH of 7.50, we can use the Henderson-Hasselbalch equation:

pH = \(pKa + log([A^-]/[HA])\)

Rearranging the equation and substituting the desired pH and pKa values gives us:

[A⁻]/[HA] = \(10^{(7.50 - 4.76) }\)

=> 562.34

Since the concentrations of the acid and its salt should be very similar, we can assume that [A⁻] ≈ [HA]. Therefore, we can estimate the concentrations of the weak acid and its salt as:

[A⁻] ≈ [HA] ≈ 0.50 L / 562.34

=> 0.00089 M

To prevent a significant pH change if 0.25 moles of NaOH are added, we need to ensure that the buffer capacity is sufficient. The buffer capacity is given by:

β = \(2.303 \times ([A^-] + [HA]) / (1 + 10^{(pH - pKa) }+ 10^{(pKa - pH)})\)

Substituting the estimated concentrations and the desired pH and pKa values gives us:

β = 2.303 * (0.00089 + 0.00089) / (1 + 10^(7.50 - 4.76) + 10^(4.76 - 7.50))

β = 0.0027.

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Answer:

increase

Explanation:

Oxidation, in chemistry, refers to when electrons are lost by an atom, hence, making the atom more positively charged. In contrast to this is reduction, which is the acceptance of electrons.

In this case, a sulfide ion (S²-) is said to be oxidized i.e loses electrons, till it becomes a sulfur atom (S). As the oxidation number has increased from -2 to 0, this means that the number of protons has INCREASED.

Answer:

43.8%

Explanation:

Find the sum of the relative atomic mass of all the elements constituting the compound, which is known as the relative formula mass;

\(M_{r} = Relative \ formula \ mass \\\\M_{r} \ of \ ZnSO_{4} = 65.4 + 32.1 + 4(16) \\\\M_{r} \ of \ ZnSO_{4} = 97.5 + 64 \\\\M_{r} \ of \ ZnSO_{4} = 161.5 \\\\M_{r} \ of \ H_{2}O = 18 \\\\M_{r} \ of \ ZnSO_{4}.7H_{2}O = 161.5 + 7(18) \\\\M_{r} \ of \ ZnSO_{4}.7H_{2}O = 287.5\)

Then, divide the relative formula mass of all the water by that of the whole compound

w = % water

\(w = \frac{7(18)}{287.5} * 100 \\\\w = 0.43826... * 100\\\\w = 43.826...\)

w = 43.8%

Answer: Example: The water in a species envirmoent suddenly becomes more acid therefore, the species adapts it's body to become more resistent and tolerate to chemicals.

This might also give it an adavantage to the species who have not yet adapted to the change

Explanation: There are three type of adaptions. 1) Structural 2) Behavioral 3) Physiological

Answer:

2 Na atoms

Explanation:

To determine which compounds are not true organometallic compounds in the eyes of purists, we need to consider the definition of organometallic compounds.

Organometallic compounds are compounds that contain a direct bond between a carbon atom and a metal atom. Based on this definition, we can evaluate each compound provided:

Compound 1: This compound contains a direct bond between a carbon atom and a metal atom (M), so it is a true organometallic compound.

Compound 2: This compound contains a direct bond between a carbon atom and a metal atom (M), so it is a true organometallic compound.

Compound 3: This compound does not contain a direct bond between a carbon atom and a metal atom. Instead, it has a metal atom (M) coordinated to a ligand (L) without a direct carbon-metal bond. Therefore, it is not considered a true organometallic compound in the eyes of purists.

Compound 4: This compound contains a direct bond between a carbon atom and a metal atom (M), so it is a true organometallic compound.

Compound 5: This compound does not contain a direct bond between a carbon atom and a metal atom. It has a metal atom (M) coordinated to a ligand (L) without a direct carbon-metal bond. Therefore, it is not considered a true organometallic compound in the eyes of purists.

Based on the above analysis, the correct answer is:

D. Compound 3 only

Compound 3 is not considered a true organometallic compound since it lacks a direct carbon-metal bond.

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Answer:

In terms of heat transfer,radiation is the emission of thermal energy in the form of infrared waves,

The half life of bromine-74 is 25min. After 75 min. only o.5mg of sample is still active.

Half-life of a radioactive element is time required for the element which undergo disintegration and reduces its initial concentration to half of the concentration.

Therefore, the half-life of  the bromine-74 is 25 minute. So we calculate the number of periods.

Half-life = time / no. of periods

No. of period = Time given / \(t_{1/2}\)

No. of period = 75 / 25 = 3

The number of periods is three and in each period  half of the amount of the initial concentration of the elements will disintegrates.

So, 6mg disintegrates into 4 / 2 and then 4 / 4 and then 4 /8

4mg→ 4 / 2→ 4 / 4→ 4 / 8

The final value will be 0.5 mg.

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The value of x should be 1/9.

The proportion of Californians who are elderly is 0.111.

The probability that a person has received a vaccine shot given that the person is elderly is 70%

The probability that a person has received a vaccine shot given that the person is not elderly is 2%

Probability that a person is elderly given that the person has received a vaccine shot is to be calculated.

Probability that a person is elderly and has received a vaccine shot,

P(E and V)=P(V | E) P(E)P(V | E) = 70%, P(E) = 0.111, soP(E and V) = (0.7) (0.111) = 0.0777

Probability that a person has received a vaccine shot, P(V) = P(E and V) + P(NE and V) P(NE) = (0.7) (0.111) + P(NE and V) P(NE) = 0.0777 + P(NE and V)P(NE and V) = P(V | NE) P(NE)P(V | NE) = 2%, soP(NE and V) = (0.02) (1 - 0.111) = 0.0178P(V) = 0.0777 + 0.0178 = 0.0955

Probability that a person is elderly given that the person has received a vaccine shot, P(E | V) = P(E and V) / P(V) = 0.0777 / 0.0955 = 0.8148(a) P(Bc|A) is the probability of driver’s blood alcohol percentage is not exceeding the legal limit, given that the breath analyzer indicates that legal limit is exceeded.

(b) We know that P(A|B) = P(Ac|Bc) = 0.95 and P(B) = 0.05P(A) = 1 - P(Ac) = 1 - 0.95 = 0.05P(Bc|A) = P(Ac|Bc) P(Bc) / P(A)P(Bc) = 1 - P(B) = 1 - 0.05 = 0.95P(Bc|A) = 0.95 × 0.95 / 0.05 = 18.05(c) P(B|A) = x and P(A) = 0.05P(Ac) = 0.95, P(B|Ac) = 0P(B|A) = P(B and A) / P(A)P(B and A) = P(B|A) P(A) = x (0.05)P(Bc|Ac) = 1 - x = P(Ac|Bc) = P(Bc|Ac) P(Ac) / P(Bc) = (1 - x) (0.95) / 0.95P(B) = P(B and A) + P(B and Ac) = x (0.05) + (1 - x) (0.95) = 0.95 - 0.9 x

Therefore,0.9 x = 0.95 - 0.05x = 1/9

Hence, the value of x should be 1/9.

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Answer:

The answer would be a

Explanation:

That is what goes into the plant and oxygen IS an outcome

A mole of donuts would weigh 3.42 kg, as a dozen donuts weigh 285 g and a mole is 6.022 x 1023 donuts. To calculate this, you need to multiply the weight of a dozen donuts by the number of donuts in a mole.

First, you need to calculate the weight of a single donut. Since there are 12 donuts in a dozen, divide the weight of a dozen (285 g) by 12 to get the weight of a single donut, which is 23.75 g.

Then, you need to multiply the weight of a single donut (23.75 g) by the number of donuts in a mole (6.022 x 1023) to get the weight of a mole of donuts. This is equal to 3.42 kg.

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Answer:

J. J. Thomson

Explanation:

This is called the plum pudding model which was proposed by J. J. Thomson.

Since we have been given the balanced reaction, we can just follow the stoichimetry of the reaction to calculate it.

By the stoichimetry, 1 mol of MnO₂ reacts with 4 moles of HCl. using Rule of three, we have:

1 mol MnO₂ --- 4 mol HCl

4.50 mol MnO₂ --- x

So, 18 moles of HCl will react with 4.5 moles od MnO₂ (assuming complete reaction).

Answer:

✔ octane

CH3CH2CH2CH2CH2CH2CH2CH3

✔ butane

CH3CH2CH2CH3

✔ methane

CH4

✔ decane

CH3CH2CH2CH2CH2CH2CH2CH2CH2CH3

✔ ethane

CH3CH3

Explanation:

An alkane contains only carbon and hydrogen. The following are the accurate names of the compounds;

An alkane is a compound whose only functional group is the carbon - carbon single bond. This compounds contain only carbon and hydrogen.

The correct names of the compounds are;

CH3CH2CH2CH2CH2CH2CH2CH3 - octane

CH3CH2CH2CH3 - butane

CH4 - methane

CH3CH2CH2CH2CH2CH2CH2CH2CH2CH3 - decane

CH3CH3 - ethane

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The change in internal energy of the gas is 123.7 J.

The change in internal energy of a gas can be calculated using the equation: ΔU = Q - W, where ΔU is the change in internal energy, Q is the heat added to or removed from the gas, and W is the work done on or by the gas.

In this case, the work done on the gas can be calculated as W = P * ΔV, where P is the pressure and ΔV is the change in volume. Since the pressure is 1.00 bar and the change in volume is 5.50 L - 1.20 L = 4.30 L, the work done on the gas is W = 1.00 bar * 4.30 L = 4.30 J.

Therefore, the change in internal energy of the gas is ΔU = Q - W = 128 J - 4.30 J = 123.7 J.

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