A Tesla roadster electric vehicle has a MPGe (Miles per Gallon equivalent) of 102 miles per gallon. A Ford F-150 has a rating of 21 MPG. The weight of the electric battery in the Tesla is 1062 lb. The volume of the gas tank in the F-150 is 83.2791 L. The density of gasoline is 748.90002 kg/m³. Which weighs more, the battery in the Tesla or the gasoline in the F-150.?

The pOH of the 0.001 M NaOH solution is approximately 3.

To determine the pOH of a solution, we need to know the concentration of hydroxide ions (OH-) in the solution.

In the case of a 0.001 M NaOH solution, we can assume that all of the NaOH dissociates completely in water to form Na+ and OH- ions. Therefore, the concentration of hydroxide ions in the solution is also 0.001 M.

The pOH is calculated using the equation:

pOH = -log[OH-]

Substituting the concentration of hydroxide ions, we have:

pOH = -log(0.001)

Using a calculator, we can evaluate the logarithm:

pOH ≈ 3

Therefore, the pOH of the 0.001 M NaOH solution is approximately 3.

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Answer:

3787500 Torr

Explanation:

1 Pascal = 0.0075 Torr

So:

5.05x10^8 Pa --- x

1 Pa --- 0.0075 Torr

x = 5.05x10^8 × 0.0075

x = 3787500 Torr

Answer:

200 g.

Explanation:

What is given?

Initial quantity (N₀) = 400 g.

Half-life of rubidium-87 = 4.8 x 10¹⁰ years.

Step-by-step solution:

Let's see the formula to calculate the quantity remaining:

Where N₀ is the initial quantity, t is the time, and t (1/2) is the half-life of the substance, in this case, Rb-87. Based on this, our formula will be:

If we want to find the amount of Rb-87 after 1 half-life, our t would be equal to 4.8 x 10¹⁰ years, so replacing this value in the formula we obtain:

The answer is that after 1 half-life of a 400 g sample of Rb-87, the remaining quantity is 200 g.

a) To calculate the minimum frequency of electromagnetic radiation required to release electrons from the metal, you can use the following formula:

f = W / h

where f is the minimum frequency of electromagnetic radiation required, W is the work function of the metal in joules, and h is the Planck constant in joules per second.

Plugging in the values for W and h, you get:

f = (5.86 x 10^-19 J) / (6.626 x 10^-34 J/s) = 8.9 x 10^14 Hz

This is the minimum frequency of electromagnetic radiation required to release electrons from the magnesium metal.

b) To calculate the kinetic energy of the ejected electronic light of frequency 2.00 x 10^14 Hz, you can use the following formula:

KE = hf - W

where KE is the kinetic energy of the ejected electron, h is the Planck constant in joules per second, f is the frequency of the electromagnetic radiation in hertz, and W is the work function of the metal in joules.

Plugging in the values for h, f, and W, you get:

KE = (6.626 x 10^-34 J/s) * (2.00 x 10^14 Hz) - (5.86 x 10^-19 J) = 1.32 x 10^-19 J - 5.86 x 10^-19 J = -4.54 x 10^-20 J

This is the kinetic energy of the ejected electron when light of frequency 2.00 x 10^14 Hz is used to irradiate the magnesium metal. Since the kinetic energy is negative, this means that the electron is not released from the metal when irradiated with this frequency. The frequency of the electromagnetic radiation needs to be higher than the minimum frequency required to release the electron in order for the electron to be ejected from the metal.

Answer:

energy was release in creating the bond

Explanation:

According to the VSEPR theory, a molecule or ion of CO2 will have a flat linear shape. Option A

In CO2, the carbon atom forms double bonds with each oxygen atom. The carbon-oxygen double bonds consist of two pairs of electrons, which are arranged linearly, leading to a linear molecular shape.

The VSEPR theory suggests that electron pairs in the valence shell of the central atom repel each other and try to position themselves as far apart as possible, resulting in the linear shape.

The VSEPR theory allows us to predict the molecular geometry based on the arrangement of bonding and non-bonding electron pairs around the central atom. In the case of CO2, there are no lone pairs of electrons on the carbon atom, and the molecule has a symmetrical arrangement, leading to a linear shape. Option A

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Taking into account the reaction stoichiometry, 1 mole of H₂ can be produced by reacting 2 moles of HCI.

In first place, the balanced reaction is:

Mg + 2 HCl  → MgCl₂ + H₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

By reaction stoichiometry 2 moles of HCl form 1 mole of H₂.

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The final temperature of the calorimeter, given that it has initial temperature of 23.93 °C is 19.19 °C

We'll begin by obtaining the heat of combustion of 0.531 g of diborane. This is shown below:

1 mole of diborane combust at -1941 KJ

Therefore,

0.0192 mole of diborane will combust at = 0.0192 × -1941 = -37.2672 KJ

Finally, we shall determine the final temperature of the calorimeter. Details below:

H = C(T₂ - T₁)

-37.2672 = 7.854 × (T₂ - 23.93)

Clear bracket

-37.2672 = 7.854T₂ - 187.94622

Collect like terms

-37.2672 + 187.94622 = 7.854T₂

150.67902 = 7.854T₂

Divide both sides by 7.854

T₂ = 150.67902 / 7.854

T₂ = 19.19 °C

Thus, the final temperature is 19.19 °C

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The empirical formula is the smallest comparison of atoms of compound forming elements.  

A molecular formula is a formula that shows the number of atomic elements that make up a compound.  

(empirical formula) n = molecular formula  

The principle of determining empirical formula and molecular formula  

Find mol ratio for every component :

\(\tt \dfrac{17.16}{12}=1.43\)

\(\tt \dfrac{3.17}{1}=3.17\)

\(\tt \dfrac{13.71}{16}=0.857\)

N (r=14 g/mol) :

Mass of Nitrogen :

40.4-(17.16+3.17+13.71)=6.36 g

\(\tt \dfrac{6.36}{14}=0.454\)

C : H : O : N = 1.43 : 3.17 : 0.857 : 0.454 = 3.15 : 7 : 1.89 : 1=3:7:2:1

Empirical formula : C₃H₇O₂N

Molecular mass of protein :

\(\tt \dfrac{40.4}{0.07141}=565.75\)

(C₃H₇O₂N)n=565.75

(12.3+1.7+2.16+14)n=565.75

(89)n=565.75

n=6.4≈6

so the molecular formula : C₁₈H₄₂O₁₂N₆

= 6.022 × 1020

Explanation;

Mole of aluminium oxide (Al2O3) is

⇒ 2 x 27 + 3 x 16

Mole of aluminium oxide = 102 g

i.e., 102 g of Al2O3= 6.022 x 1023 molecules of Al2O3

Then, 0.051 g of Al2O3 contains = 6.022 x 1023 / (102 x 0.051 molecules)

= 3.011 x 1020 molecules of Al2O3

The number of aluminium ions (Al3+) present in one molecule of aluminium oxide is 2.

Therefore, the number of aluminium ions (Al3+) present in 3.11 × 1020 molecules (0.051g) of aluminium oxide (Al2O3)

= 2 × 3.011 × 1020

= 6.022 × 1020

hope it helps_

Hello, this is Bing. I can help you with your question. Based on the information I found on the web, **H2** can be broken down into its two atoms of hydrogen (H) by supplying enough energy to overcome the bond that holds them together⁴. This process is called **dissociation** and requires an energy equal to or greater than the **dissociation energy** of H2, which is about 436 kJ/mol⁴.

One way to break down H2 is by using **electricity** to split water (H2O) into hydrogen (H2) and oxygen (O2) through a process called **electrolysis**¹. In this process, water is decomposed into its elements by passing an electric current through it. The electric current is provided by a battery or another source of electricity and the water needs to have an **electrolyte**, such as salt or acid, added to it to make it conductive¹. Two electrodes, usually made of metal or other conductive material, are inserted into the water and connected to the battery. The electrode connected to the positive terminal of the battery is called the **anode** and the one connected to the negative terminal is called the **cathode**¹. When the electric current flows through the water, hydrogen gas bubbles form at the cathode and oxygen gas bubbles form at the anode¹. The overall chemical reaction for electrolysis of water is:

2 H2O → 2 H2 + O2

Another way to break down H2 is by using **heat** to cause a reaction between hydrogen and oxygen that produces water and releases a large amount of energy. This reaction is called **combustion** or **oxidation** and can be ignited by a spark or a flame³. The reaction is very fast and explosive and can be dangerous if not controlled. The overall chemical reaction for combustion of hydrogen is:

2 H2 + O2 → 2 H2O

I hope this helps you understand how H2 can be broken down and what methods are used to do so.

The expression of the Ksp is Ksp =  [Ca²+] [2OH-]^2

In the balanced chemical equation for the solute's dissolution, Ksp is defined as the product of the ion concentrations in a saturated solution, each concentration being raised to the power of its stoichiometric coefficient.

Ksp is temperature-dependent and varies with different compounds. It is used to predict the maximum amount of a compound that can dissolve in a given solvent under specific conditions.

We know that we can be able to use the expression that has been given in the problem to arrive at the fact that;

Ksp =  [Ca²+] [2OH-]^2

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When the grain size is reduced to 0.160 pm, the strength of mild steel is 1851 MPa.There are a number of variables that can affect mild steel's strength, including the grain size, which is controllable.

We may use the above information to determine the constants in the Hall-Petch equation: The strength of mild steel at grain size d1 = 17.43 pm is 1 = 232.9 MPa. Mild steel has a strength of 2 = 874.2 MPa when the grain size is d2 = 0.80 um (or 800 nm). This is the formula for the Hall-Petch equation: = o + Kd(-1/2). We can use the following equation to determine K: K = (σ2 - σ1)(d2^(1/2) - d1^(1/2))^(-1) (-1) When the values are plugged in, we get the following result: K = (874.2 - 232.9)(800(1/2) - 17.43(1/2))(-1) = 276.3 MPa um(1/2) We can use the following equation to determine o: σo = σ1 - Kd1^(-1/2) Plugging in the numbers yields the following result: o = 232.9 - 276.3(17.43(-1/2)) = 62.28 MPa. The Hall-Petch equation's constants are K = 276.3 MPa um(1/2) and o = 62.28 MPa. Hence, the power of the  yield strength of mild steel at 0.160 pm grain size is 1851 MPa.

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Answer:

41826.05 Calories

Explanation:

1 J = 0.239006 Calories

175 KJ

= 175 x 1000 J

= 175000 J

175000 J to Calories

= 175000 x 0.239006

= 41826.05 Calories

Answer: 41.8

Explanation:

Acellus verified ✅

The number of millimoles of barium chloride added to the flask to 3 significant figures would be 422 mmol.

To calculate the millimoles of barium chloride added to the flask, we need to use the following formula:

moles = concentration x volume

where concentration is in units of mol/L, and volume is in units of L. We are given that the volume is 1.10 L and the concentration is 0.384 mol/L, so:

moles = 0.384 mol/L x 1.10 L

moles = 0.4224 mol

Now, to convert moles to millimoles, we multiply by 1000:

millimoles = 0.4224 mol x 1000

millimoles = 422.4 mmol

Therefore, the millimoles of barium chloride added to the flask is 422 mmol (rounded to 3 significant figures).

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White vinegar typically consists of 93%–96% water and 4–7% acetic acid. It can be used to cooking, bake, cleaning, and get rid of weeds. It can also help you lose weight and lower your blood sugar and cholesterol. Consumption is safe in moderation, but excessive consumption or when combined with certain medications could be harmful.

Apple cider vinegar is widely used in cooking and as a salad dressing because it contains acetic acid and nutrients like vitamins C and B vitamins. But at the same time, it's been utilized customarily as medication. It helps in losing weight.

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The Correct choice is ~ D

Solute is the substance that dissolves into another substance

Answer:

See the answer below.

Explanation:

If an aqueous solution of two salts contains both Na2CO3 and Na2SO4, the following steps will prove the occurrence of both carbonate and sulphate ions:

1. Add a dilute acid (such as HCl) to the solution. The presence of carbonate ion will result in the release of carbon dioxide gas which will be shown by formation of effervescent bubbles. The gas can be proven to be carbon dioxide by channeling it into a lime water which usually turns milky with the presence of the gas.

\(CO^{2-}_3(aq) + 2H^+(aq) ==> H_2O(l) + CO_2(g)\)

2. Add barium chloride to an acidified portion of the aqueous solution. The presence of sulphate ion will be indicated by the formation of white barium sulphate precipitate. Initial acidification is done to disperse off any carbonate ion that might be present in the solution and give a false-positive white precipitate result.

\(Ba^{2+}(aq) + SO^{2-}_4(aq) --> BaSO_4(s)\)

Condensation is a chemical reaction of synthesis. It represents two organic molecules producing one organic molecule and a water molecule.

Condensation reactions are reactions in which two or more substances combine together chemically to produce a larger molecule with the elimination of a small molecule such as water, ammonia, or HCl.

Condensation reactions are important reactions in the formation of polymers.

Polymers are large organic molecules that are composed of smaller repeating units known as monomers.

An example of a condensation reaction is the reaction in which two amino acids are linked together by a peptide bond to form a dipeptide. A water molecule is also eliminated.

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Writing and balancing complex half-reactions in acidic solutions involves a systematic approach. Here are the general steps to follow:

Identify the oxidation and reduction half-reactions: Determine which species is being oxidized (losing electrons) and which is being reduced (gaining electrons).

Balance the atoms: Begin by balancing all atoms except hydrogen and oxygen in each half-reaction.

Balance the charges: Add electrons (e-) to one side of each half-reaction to balance the charges.

Balance the oxygen atoms: Add water (H2O) to the side of the equation that lacks oxygen atoms.

Balance the hydrogen atoms: Add hydrogen ions (H+) to the side of the equation that lacks hydrogen atoms. Keep in mind that the solution is acidic.

Balance the charges: Adjust the number of electrons (e-) on each side of the equation to ensure that the charges are balanced.

Multiply the half-reactions: Multiply each half-reaction by an appropriate factor so that the number of electrons gained and lost are equal.

Combine the half-reactions: Add the two balanced half-reactions together and cancel out common terms on both sides of the equation.

By following these steps, you can effectively write and balance complex half-reactions in acidic solutions, ensuring that the overall reaction is balanced in terms of both atoms and charges.

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Answer:

To calculate the heat released in this reaction, we need to use the formula:

Q = mcΔT

where Q is the heat released, m is the mass of the solution, c is the specific heat capacity of the solution, and ΔT is the change in temperature.

Assuming the density of the solution is 1 g/mL, the mass of the solution is 100 g (50 mL HCl + 50 mL NaOH). The specific heat capacity of the solution can be assumed to be the same as that of water, which is 4.18 J/g°C.

The change in temperature can be calculated as the final temperature minus the initial temperature:

ΔT = 30°C - 22°C = 8°C

Therefore, we have:

Q = (100 g) * (4.18 J/g°C) * (8°C) = 3344 J

The heat released in the reaction is 3344 J.

The value of ΔH for the reaction can be calculated using the formula:

ΔH = -Q/n

where Q is the heat released, and n is the number of moles of limiting reactant used in the reaction. In this case, the limiting reactant is NaOH, and we can calculate the number of moles of NaOH from its concentration and volume:

n(NaOH) = (0.1 L) * (1 mol/L) = 0.1 mol

Therefore, we have:

ΔH = -(3344 J) / (0.1 mol) = -33,440 J/mol

The value of ΔH for the reaction is -33,440 J/mol, which is negative because the reaction is exothermic (heat is released).

3.75M

Molarity is the ratio of the moles of solute to volume of solution. It is measured in moles/Litre

From the given question, the molarity of the cups of juice is given as;

molarity of first solution = 0.75M

molarity of second solution = 2.5M

molarity of third solution = 0.50M

Determine the molarity of the resulting solution

Molarity = 0.75 M + 2.5M + 0.50M

Molarity = 3.75M

Hence the molarity be of the resulting solution is 3.75M

Answer:

8

Explanation:

When you balance the entire equation, you should get:

C5H12 + 8O2 ---> 5CO2 + 6H2O

The Density of metal is 1.32 g/mL.

Given,

volume change observed by chemist when metal is dropped into the cylinder filled with water is 6.1 mL.

weight of metal is 8.1 g

we know that,

Density = mass / Volume

density = 8.1 / 6.1

Density = 1.32 g/mL

Hence, density of metal of mass 8.1 g is 1.32 g/mL

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Answer:

the Molecular formula will be; C10H14O

Explanation:

Given the data in the question;

Chrysanthenone is an unsaturated ketone,

it has M+ = 150 and contains 2 double bond(s) and 2 ring(s).

molecular formula = ?

we know that ketone contain 1 oxygen and mass of oxygen is 16

so mass of the C and H remaining will be;

⇒ 150 - 16 = 134

Now we determine the number of C atoms;

⇒ 134 / 13 = 10

hydrocarbon with 10 hydrogen atom have CnH2n+2 means

⇒ ( 10 × 2 ) +2 = 22 hydrogens

But then we have 3 unsaturation meaning 6 hydrogens less and also we have ring meaning 2 more hydrogens

⇒ 22 - 6 - 2 = 14

Hence the Molecular formula will be; C10H14O

The molar mass of the polystyrene is  41750 g/mol.

We know that the molar mass is the mass of one mole of the substance. We need to obtain the concentration of the solution in order to obtain the molar mass.

Number of moles = 2.05 /M moles

Volume of the solution = 100 mL or 0.1 L

Concentration = 2.05 /M/0.1  or 2.05/0.1 M

π = iCRT

π = Osmotic pressure

i = Van't Hoff factor

C = concentration

R = gas constant

T = temperature

0.012 = 1 *  2.05/0.1 M * 0.082 * 298

0.012 = 50.1/0.1 M

0.012 * 0.1 M = 50.1

M = 50.1/0.012 * 0.1

M = 41750 g/mol

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Answer:

Explanation:

The first process is to draw out the heating curve to have a look at the transition possible which we've shown in the file below.

Now;

To find the energy removed to convert 75g steam → ice then comparing it with 215 kJ.

So conversion of steam at 125 °C → 100 °C

\(\Delta H = (75 \ g) (2.0 \ J/g^0C ) (125 - 100)^0 \ C\)

\(\Delta H = 3750 \ J\)

\(\Delta H = 3.75 \ kJ\)

Since this is lesser than the energy given  (215 kJ), we then have to find the energy removed in the next phase.

For condensation of steam

Find the energy removed to change the steam from 100° C to liquid  at 100° C

\(\Delta H_2 = ( \dfrac{75 \ g}{18.02 \ g/mol}) (40.7 \ kJ/mol)\)

\(\Delta H_2 =1.690* 10^ 2 \ J\)

\(\Delta H_2 =169 \ kJ\)

The total energy that is now removed from the system is:

\(\Delta H_1+ \Delta H_2 = (169 + 3.75) \ kJ\)

\(\Delta H_1+ \Delta H_2 \simeq 173 \ kJ\) which is still lesser than 215 kJ

To the third step; which is the conversion of water at 100° C → water at 0° C

\(\Delta H_3 = ( 75 \ g) (4.2 \ J/g^0 C)(100-0)^0C\)

\(\Delta H_3 = 31500 \ J\)

\(\Delta H_3 = 31.5 \ kJ\)

Thus;

\(\Delta H_1+\Delta H_2+\Delta H_3 = (169 + 3.75 +31.5) \ kJ\)

\(\Delta H_1+\Delta H_2+\Delta H_3 =204 \ kJ\)

To the fourth step;

For freezing of water; we need to find the energy removed to change the water at 0° C → ice at 0° C

\(\Delta H_4 = (\dfrac{75 \ g}{18.02 \ g/mol})(6.02 \ kJ/mol)\)

\(\Delta H_4 = 25.1 \ kJ\)

∴

To change to the solid phase at 0° C; the total energy that is being removed from the steam is  

\(\Delta H_1+\Delta H_2+\Delta H_3 +\Delta H_4 =(169 + 3.75 + 31.5 +25.1) \ kJ\)

\(\Delta H_1+\Delta H_2+\Delta H_3 +\Delta H_4 =229 \ kJ\)

Here, the calculated total energy is more than the given energy 215 kJ.

This implies that the water is not fully converted to ice when 215 kJ of energy removal occurs, Hence the two phases that exist are liquid and solid.

Answer:

a) alternate interior angles are congruent

Explanation:

on edgen

Any time we are working with solutions and its molar concentration we will use the equation:

Where C is the concentration, n is the number of moles of the solute and V is the volume of solution.

We can identify such situations when we are working with molarity, molar concentration, solutions with concentration in "M" or "mol/L" units and other cases.

In this case, we can see that we are working with these three quantities:

- We want the volume in mL os a solution, V.

- We have a molar concentration, C, 0.626 M NaOH.

- We have a number of moles of solute we want to get, n, 0.332 mol of NaOH.

So, we have:

So:

So, the volume we need is approximately 530 mL.

Answer:

No.Kerosene oil and water do not mix with each other and form two separate layers.

Answer:

No

Explanation:

They cannot be mixed together they will form upper and lower layer